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Route Surveying

Hehhe

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Arjie Recarial
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0% found this document useful (0 votes)
58 views3 pages

Route Surveying

Hehhe

Uploaded by

Arjie Recarial
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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ROUTE SURVEYING

SIMPLE CURVE COMPOUND CURVE

Radius: R1=radius of first curve PC(E)


1145.916 R1=radius of second curve PT(E)
𝑅=
𝐷
CT=common tangent
Length of Curve:
I=angle of intersection/central angle of PCE and
𝜋𝑅𝐼 PTE
𝐿=
180
𝐶𝑇 = 𝑇1 + 𝑇2
Tangent distance:
𝐼 = 𝐼1 + 𝐼2
𝐼
𝑇 = 𝑅 tan
2 Length of the chord:
External Distance:
I1 /2 C I2/2
𝐼
𝐸 = 𝑅 [sec − 1] C1 C2
2
Middle distance: PC L PT

𝐼 Use cosine law to solve L


𝑀 = 𝑅 [1 − cos ]
2 𝐿2 = 𝐶12 + 𝐶22 − 𝐶1 𝐶2 𝐶𝑜𝑠 (𝐶°)
Chord distance:
𝐼
𝐶 = 2𝑅𝑠𝑖𝑛 Angle of the first tangent:
2
𝐶2 𝐿
Stationing distance: =
sin 𝜃1 sin 𝐶°
𝑆 = 𝑅𝜃𝑝𝑜𝑖𝑛𝑡 (length of curve)
Angle of the second tangent:
Station of point = 𝑃𝐶 + 𝑆
𝜃2 = 180° − 𝐶° − 𝜃1
𝐶1 𝐿
=
sin 𝜃2 sin 𝐶°

Offset Distance (y):


𝑦 𝑦
𝑡𝑎𝑛 𝜃 = 𝑜𝑟 tan 𝜃 =
𝐵𝑇 𝐹𝑇
𝑅−𝑦
cos 2𝜃 =
𝑅
ROUTE SURVEYING

REVERSE CURVE SPIRAL CURVE

Equal Radii: Considering at any point:


𝑞𝑢𝑎𝑟𝑡𝑒𝑟𝑠
𝐿= (𝐿𝑐 )
4
Spiral angle:

𝐿2 180
𝑠= [ ]
2𝑅𝑐 𝐿𝑐 𝜋
Offset Distance from the tangent at SC:

𝐿3
𝑥=
Let y =parallel tangent 6𝑅𝑐 𝐿𝑐

C=chord length PC to PT Distance along tangent at any point:

Solve I: 𝐿5
𝑦=𝐿−
40𝑅𝑐2 𝐿2𝑐
𝐼 𝑦
sin = Deflection angle:
2 𝐶
𝑠
𝑖=
Radius of reverse curve: 3
𝐶 𝐼
= 2𝑅𝑠𝑖𝑛
2 2
Considering without any point:
Length of tangent in common direction at
Spiral angle:
station PC:
𝐿𝑐 180
𝐼 𝑠𝑐 = [ ]
𝑇 = 2𝑅𝑠𝑖𝑛 2𝑅𝑐 𝜋
2 𝐷𝐶 𝐿𝑐
𝑠𝑐 =
40
Length of tangent in station PRC: Offset Distance from the tangent at SC:
𝐼
𝑇 = 𝑅𝑠𝑖𝑛 𝐿2𝑐
2 𝑥𝑐 =
6𝑅𝑐
Distance along tangent at any point:

𝐿3𝑐
𝑦𝑐 = 𝐿𝑐 −
40𝑅𝑐2
Deflection angle:
𝑠𝑐
𝑖=
3
Length of thrown:
𝑥𝑐
𝑃=
4
ROUTE SURVEYING

Tangent distance for spiral: 𝐿(𝑔1 )


𝑆1 =
𝑔1 − 𝑔2
𝐿𝑐 𝐼
𝑇𝑠 = + [𝑅𝑐 + 𝑃] tan
2 2 𝑦 𝐻
2 =
External Distance for spiral: 𝑆1 𝐿 2
(2)
𝐼
𝐸𝑠 = [𝑅𝑐 + 𝑃] sec − 𝑅𝐶
2
Super elevation when K=velocity in kph: UNSYMMETRICAL PARABOLIC CURVE
𝐿2 (𝑔1 − 𝑔2 )
0.0079(𝐾)2 𝐻=
𝑒= 2(𝐿)
𝑅𝑐
𝐾2 𝐿21 (𝑔1 ) 𝐿1 𝑔1
𝑅= 𝑆1 = , 𝑤ℎ𝑒𝑛 <𝐻
127(𝑒 + 𝑓) 2𝐻 2
Length of spiral: 2𝐻𝐿2
𝐿1 =
𝐿2 (𝑔1 − 𝑔2 ) − 2𝐻
0.036𝐾 3
𝐿𝑐 = 𝑦1 𝐻
𝑅
2 =
𝑆1 𝐿 2
Square of the length T.S ( 21 )

𝑖 𝐿2 𝑦1 𝐻
= 2 2 =
𝑖𝑐 𝐿𝑐 𝑆2 𝐿 2
( 22 )
𝐷 𝐿
=
𝐷𝑐 𝐿𝑐

PARABOLIC CURVE

Change of grade:

g1= when negative

g2= when positive


𝑔2 − 𝑔1
𝑟=
𝑛

Length of curve:

𝐿 = 𝑛(20)
𝐿 = 𝐾(𝑔2 − 𝑔1 )
K=length of curve per 1 degree

Length of the highest point:


𝐿
𝐻 = [𝑔2 − 𝑔1 ]
8

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