Math ch 6
Identities of trigonometry
Here are the proofs for the trigonometric identities:
*Fundamental Identities*
1. Pythagorean Identity: sin^2(x) + cos^2(x) = 1
Proof:
Consider a right-angled triangle with sides of length 1, x, and hypotenuse.
sin(x) = opposite/hypotenuse = x/1 = x
cos(x) = adjacent/hypotenuse = 1/1 = 1
By Pythagoras' theorem:
x^2 + 1^2 = 1^2
x^2 + 1 = 1
sin^2(x) + cos^2(x) = x^2 + 1 = 1
1. Sum of Squares Identity: tan^2(x) + 1 = sec^2(x)
Proof:
tan(x) = sin(x)/cos(x)
sec(x) = 1/cos(x)
tan^2(x) + 1 = (sin^2(x)/cos^2(x)) + 1
= (sin^2(x) + cos^2(x))/cos^2(x)
= 1/cos^2(x)
= sec^2(x)
1. Difference of Squares Identity: 1 + cot^2(x) = csc^2(x)
Proof:
cot(x) = cos(x)/sin(x)
csc(x) = 1/sin(x)
1 + cot^2(x) = 1 + (cos^2(x)/sin^2(x))
= (sin^2(x) + cos^2(x))/sin^2(x)
= 1/sin^2(x)
= csc^2(x)
*Angle Addition and Subtraction Identities*
1. Sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
Proof:
Consider two right-angled triangles with angles a and b.
sin(a + b) = opposite/hypotenuse
= (sin(a)cos(b) + cos(a)sin(b))/1
1. Cos(a + b) = cos(a)cos(b) - sin(a)sin(b)
Proof:
cos(a + b) = adjacent/hypotenuse
= (cos(a)cos(b) - sin(a)sin(b))/1
1. Tan(a + b) = (tan(a) + tan(b)) / (1 - tan(a)tan(b))
Proof:
tan(a + b) = sin(a + b)/cos(a + b)
= (sin(a)cos(b) + cos(a)sin(b))/(cos(a)cos(b) - sin(a)sin(b))
= (tan(a) + tan(b)) / (1 - tan(a)tan(b))
*Double Angle Identities*
1. Sin(2x) = 2sin(x)cos(x)
Proof:
sin(2x) = 2sin(x)cos(x)
= 2(opposite/hypotenuse)(adjacent/hypotenuse)
1. Cos(2x) = cos^2(x) - sin^2(x)
Proof:
cos(2x) = cos^2(x) - sin^2(x)
= (adjacent/hypotenuse)^2 - (opposite/hypotenuse)^2
1. Tan(2x) = 2tan(x) / (1 - tan^2(x))
Proof:
tan(2x) = sin(2x)/cos(2x)
= (2sin(x)cos(x))/(cos^2(x) - sin^2(x))
= 2tan(x) / (1 - tan^2(x))
*Half Angle Identities*
1. Sin(x/2) = ±√((1 - cos(x))/2)
Proof:
sin(x/2) = √((1 - cos(x))/2)
= √(1 - (adjacent/hypotenuse)^2)/2
1. Cos(x/2) = ±√((1 + cos(x))/2)
Proof:
cos(x/2) = √((1 + cos(x))/2)
= √(1 + (adjacent/hypotenuse)^2)/2
1. Tan(x/2) = (1 - cos(x)) / sin(x)
Proof:
tan(x/2) = sin(x/2)/cos(x/2)
= (1 - cos(x))/sin(x)
*Product-to-Sum Identities*
1. Sin(a)cos(b) = (1/2)[cos(a-b) + cos(a+b)]
Proof:
sin(a)cos(b) = (1/2)[cos(a-b) + cos(a+b)]
= (1/2)[(adjacent/hypotenuse) + (adjacent/hypotenuse)]
Here are the rest of the proofs:
_Product-to-Sum Identities (continued)_
1. Cos(a)cos(b) = (1/2)[cos(a-b) + cos(a+b)]
Proof:
cos(a)cos(b) = (1/2)[cos(a-b) + cos(a+b)]
= (1/2)[(adjacent/hypotenuse) + (adjacent/hypotenuse)]
1. Sin(a)sin(b) = (1/2)[cos(a-b) - cos(a+b)]
Proof:
sin(a)sin(b) = (1/2)[cos(a-b) - cos(a+b)]
= (1/2)[(opposite/hypotenuse) - (opposite/hypotenuse)]
_Sum-to-Product Identities_
1. Sin(a) + Sin(b) = 2sin((a+b)/2)cos((a-b)/2)
Proof:
sin(a) + sin(b) = 2sin((a+b)/2)cos((a-b)/2)
= 2(opposite/hypotenuse)(adjacent/hypotenuse)
1. Cos(a) + Cos(b) = 2cos((a+b)/2)cos((a-b)/2)
Proof:
cos(a) + cos(b) = 2cos((a+b)/2)cos((a-b)/2)
= 2(adjacent/hypotenuse)(adjacent/hypotenuse)
1. Sin(a) - Sin(b) = 2cos((a+b)/2)sin((a-b)/2)
Proof:
sin(a) - sin(b) = 2cos((a+b)/2)sin((a-b)/2)
= 2(opposite/hypotenuse)(opposite/hypotenuse)
Formala :
Here are some trigonometry formulas for specific triangles:
*Right Triangle*
1. Pythagorean Theorem: a^2 + b^2 = c^2 (where c is the hypotenuse)
1. Sine: sin(A) = opposite/hypotenuse = a/c
1. Cosine: cos(A) = adjacent/hypotenuse = b/c
1. Tangent: tan(A) = opposite/adjacent = a/b
*Oblique Triangle*
1. Law of Sines: a/sin(A) = b/sin(B) = c/sin(C)
1. Law of Cosines: c^2 = a^2 + b^2 - 2ab*cos(C)
*Equilateral Triangle*
1. All angles are 60°
1. All sides are equal
*Isosceles Triangle*
1. Two sides are equal
1. Two angles are equal
*30-60-90 Triangle*
1. Angles: 30°, 60°, 90°
1. Side ratios: 1:√3:2
*45-45-90 Triangle*
1. Angles: 45°, 45°, 90°
1. Side ratios: 1:1:√2
* Trigonometry Ratio *
1. If sec(x) = 5/3, find tan(x) and sin(x).
Solution:
sec(x) = 5/3
tan(x) = √(sec^2(x) - 1) = √((5/3)^2 - 1) = 4/3
sin(x) = 1/sec(x) = 3/5
1. If cosec(x) = 7/6, find cot(x) and cos(x).
Solution:
cosec(x) = 7/6
cot(x) = √(cosec^2(x) - 1) = √((7/6)^2 - 1) = 6/√7
cos(x) = 1/cosec(x) = 6/7
*Identities and Formulas*
1. Prove: tan(A - B) = (tan(A) - tan(B)) / (1 + tan(A)tan(B))
Solution:
Start with the identity: tan(A - B) = (sin(A)cos(B) - cos(A)sin(B)) / (cos(A)cos(B)
+ sin(A)sin(B))
Divide numerator and denominator by cos(A)cos(B)
Use the definitions of tan(A) and tan(B)
1. Simplify: 2cos^2(x) - 1
Solution:
Use the identity: cos(2x) = 2cos^2(x) - 1
So, 2cos^2(x) - 1 = cos(2x)
*Graphs of Trigonometric Functions*
1. Sketch the graph of y = sin(2x) - 1.
Solution:
Amplitude = 1
Period = π
Phase shift = 0
Vertical shift = -1
1. Find the amplitude and period of y = 2sin(x/2).
Solution:
Amplitude = 2
Period = 4π
*Applications*
1. A Ferris wheel with radius 10 m rotates at 5 rpm. Find the linear speed.
Solution:
Angular speed = 5 rpm = 5(2π)/60 rad/s
Linear speed = radius × angular speed = 10 × 5(2π)/60 = 5.24 m/s
1. A surveyor measures the angle of elevation to the top of a building as 60°. If
the distance to the building is 50 m, find the height.
Solution:
Use the tangent function: tan(60°) = height / 50
Height = 50 × tan(60°) = 50√3 m
*Challenge Questions*
1. Prove: sin(5x) = 16sin^5(x) - 20sin^3(x) + 5sin(x)
Solution:
Use De Moivre's theorem or multiple angle formulas
1. Find the value of cos(15°).
Solution:
Use the identity: cos(15°) = cos(45° - 30°)
= cos(45°)cos(30°) + sin(45°)sin(30°)
= (√2/2)(√3/2) + (√2/2)(1/2)
= (√3 + 1)/2√2
Here are some examples and practice problems for trigonometry:
*Examples*
1. Find sin(x) if cos(x) = 3/5.
Solution: sin(x) = √(1 - cos^2(x)) = √(1 - (3/5)^2) = 4/5
1. Find tan(x) if sin(x) = 2/3.
Solution: tan(x) = sin(x)/cos(x) = (2/3)/√(1 - sin^2(x)) = 2/√5
1. Find cos(2x) if cos(x) = 2/3.
Solution: cos(2x) = cos^2(x) - sin^2(x) = (2/3)^2 - (1 - (2/3)^2) = 1/3
*Practice Problems*
*Basic Trigonometry*
1. Find sin(x) if cos(x) = 2/5.
1. Find tan(x) if sin(x) = 3/4.
1. Find cos(x) if tan(x) = 5/12.
*Trigonometric Identities*
1. Prove: sin(a+b) = sin(a)cos(b) + cos(a)sin(b)
1. Simplify: cos^2(x) + sin^2(x)
1. Prove: tan(2x) = 2tan(x)/(1 - tan^2(x))
*Solving Triangles*
1. In a right triangle, find the length of the hypotenuse if one leg is 3 and the other
leg is 4.
1. In a right triangle, find the measure of an angle if the opposite side is 5 and the
hypotenuse is 13.
1. In an oblique triangle, find the measure of an angle if two sides are 5 and 7.
*Word Problems*
1. A ship sails 20 miles east and then 30 miles north. Find the distance and
direction from the starting point.
1. A plane flies 200 miles at an angle of 30°. Find the horizontal and vertical
components.
1. A force of 50 N acts at an angle of 45°. Find the x and y components.
Last modified: Sep 26, 2024