Frac
Frac
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H.-J. G. Diersch
                                                                                                                                                                N
WASY Institute for Water Resources Planning and Systems Research, Berlin, Germany
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  FEFLOW2 provides 1D and 2D discrete feature ele-
ments which can be mixed with the porous matrix ele-                                                    The conservation of mass, momentum and energy is
ments in two and three dimensions. Different laws of                                                 described by the balance statement2 (symbols are listed
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                 in the Appendix A ’Nomenclature’)
                            --------------
                                  -
                                            +    v  +   j = f           (1-1)
                                  t
                                                                                                                1D channel element
                                                                         river
runoff surface
2D fracture element
fault
aquifer
saturated zone
                    Figure 1.1 Schematization of a subsurface modeling system by combining discrete feature elements with volume dis-
                    cretizations of the total study domain: 1D elements are used to approximate rivers, channels, wells and specific faults,
                    2D feature elements are appropriate for modeling runoff processes, fractured surfaces and faulty zones, and 3D ele-
                    ments represents the basic tessellation of the subsurface domain consisting of an aquifer-aquitard system and involving
                    unsaturated and saturated zones.
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                                                                           NKPKO          cçêãë=çÑ=Ä~ä~åÅÉ=Éèì~íáçåë
         Table 1.1 Used discrete feature elements
                                                                              According to the applications for the discrete fea-
            Fluid motion                                                   ture elements indicated above we are interested in four
 Type                                 Dimension        Application         forms of the governing balance equation (1-1):
                 law
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                 procedures referred to the representative elementary
                                                                                                                     1            non-integrated form
                 volume (REV) composed by fluid and solid phases. It                                            B =            for                                                  (1-8)
                                                                                                                     arbitrary     vertically integrated form
                 results finally to the form C of the basic balance
                 statement3
                                                                                                                                                     interface
                                                                                                                the interface exchange term j                   as
                   -----------------
                         -                                             interface
                                      +    v  +    j  = f + j                            (1-4)
                           t
                                                                                                                   interface      0                   free fluid flow
                                                                                                                  j           =            for                                     (1-9)
                                                                                                                                  0                   porous media flow
                 where an exchange term at the fluid-solid interface nat-
                 urally results
                                                                                                                                                                      top   bottom
                                                                                                                and the top and bottom exchange terms j   j                       as
                    interface       1                           interface
                   j           = ------
                                  S                       n                 j +   w – v   dS   (1-5)
                                                                                                                                       0         non-integrated form
                                                interface                                                         top    bottom
                                           S                                                                    j  j          =       for                             (1-10)
                                                                                                                                       0         vertically integrated form
                 Notice, the balance quantities of the porous medium
                 conservation equation (1-4) are averaged over the REV
                 volume.                                                                                        NKPKP          j~íÜÉã~íáÅ~ä=ÅçåîÉåíáçåë
                    Finally, the porous medium equation (1-4) can also                                             Both Cartesian and cylindrical coordinate systems
                 be vertically integrated over the depth B , which yields                                       will be employed. They are defined as
                 form D of the basic balance statement as
                       ---------------------
                            B -                                                                                         x y z                   3D
                                              +    Bv  +    Bj  =                           (1-6)                                         
                                 t                                                                                          x y                      2D
                                    interface               top       bottom                                            x =                for                                (1-11)
                       Bf + j                     + j – j                                                               x                         1D
                                                                                                                             r  z                   axisymmetry
                                                                                                                                                      
                 It is obvious, the balance statement (1-6) of form D is
                 the most general form which encompasses all other                                              The velocity vector v is accordingly
                 forms when we specify the porosity  as
the depth B as
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                                                                                                                                                                                     NKP=mêÉäáãáå~êáÉë
                                                                                                               2          2          2
                                                                                                 ---------
                                                                                                            - ---------    
                u                                                                                2- + ---------       2
                                                                                                                           + 2-                             3D (x y z) Cartesian
                                               Cartesian coordinates                             x              y         z
                v                                                                                2                  2
                w                                                                                                                                     2D (x y) Cartesian
                                                                                                 ---------
                                                                                                           2
                                                                                                            - + ----------
                                                                                                                        2
    v =                         for                                            (1-12)     2      x              y
                vr                                                                        =                                                                          (1-14)
                                                                                                 2 
               v                              cylindrical coordinates                           ----------                                               1D (x) Cartesian
                                                                                                 x 2
                vz                                                                              
                                                                                                 1    1  2   2 
                                                                                                  --- -----  r ------- + ----2 ---------2- + ---------
                                                                                                                                                        -   cylindrical (r  z)
                                                                                                  r r r                  r                  z
                                                                                                                                                       2
           u v w                                                                     NKPKQ              dê~îáíó=~åÇ=î~êá~ÄäÉë
           ------ + ----- + -------                         3D (x y z) Cartesian
           x y z
           u v                                                                           In the following we assume an exclusive action of
           ------ + -----                                   2D (x y) Cartesian
           x y                                                                        gravity in the form
  v =                                                                    (1-13)
           u
            ------
           x                                               1D (x) Cartesian
                                                                                                                                        gx                    ex
           1   rv r  1 v  v z                                                                g = – ge                  g = gy                   e = ey              (1-15)
           --r- --------------
                      r
                              - + --- --------- + --------
                                  r  z                    cylindrical (r  z)
                                                                                                                                        gz                     ez
                                                         2
and the derivative operation  for the different coor-
                                                                                         As a further useful variable the hydraulic head h
dinate systems is given, for instance, for the variable 
                                                                                         (piezometric head) related to the reference fluid density
as
                                                                                          o is defined
                                                                                                                                   p
                                                                                                                    h =  + z = --------- + z                              (1-16)
                                                                                                                                o g
                                                                                         and
                                                                                                                        p = o g  h – z                                  (1-17)
                                                                                         Thus,
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                                                                          – o
                  p – g = p + ge =  o g   + z + --------------- e         (1-18)
                                                                           o
                                                                                               Table 1.3 Hydraulic radii for different applications
                                              –   
                          =  o g  h + --------------- e =  o g  h + e 
                                                       o
                                               o                                                                Type                                r hydr
                    A phreatic surface represents a macroscopic moving                                   open wide channel (b > 20B)
                 material interface between two fluids, e.g. air and                               D                plane
                 water. A material surface F = F  x t  = 0 is governed                                           B
                                                                                                                                                       B -
                 by the kinematic equation                                                                                                   ---------------------- B
                                                                                                                           b                 1 + 2B  b
                                          F
                                          ------ + w  F = 0                         (1-20)           submerged circular cross-section
                                           t                                                      E
                                                                                                                               R
                                                                                                                                                       2
                                                                                                                                                R -        R
                                                                                                                                                --------- = ---
                                                                                                                                                2R         2
                 The outward unit vector normal to F is defined as
                                                       F                                      and accordingly
                                                 n = ------------                     (1-21)
                                                       F
                                                                                                                           F  t
                                                                                                                 w  n = – ---------------                              (1-22)
                                                                                                                               F
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                                                                                                                                                                                                  NKP=mêÉäáãáå~êáÉë
                                                                                                                            ---------------------
                                                                                                                                 B -                                 h
                                                                                                                                                   = B ------------------ +  ------   (1-26)
where F denotes the magnitude of the vector F .                                                                                     t                      t                 t
For the vertical integration along the thickness B we
can express the geometries of the top and bottom sur-
faces in the forms (Fig. 1.2)                                                                                NKPKT             sáëÅçìë=ëíêÉëëÉë=çå=ëìêÑ~ÅÉë
                top             top                         top
            F              F          x t  = z – b             x y t      = 0                          The viscous stresses on a surface  (note  can
        bottom             bottom                           bottom
                                                                                        (1-23)
    F                 F               x t  = z – b                 x y  t  = 0                      indicate a top and bottom surface as well as a fluid-
                                                                                                             solid interface) result from exchange relationships (1-
                                                                                                             3) and (1-5) if replacing the general flux vector j by
and
                                                                                                             the viscous stress tensor of fluid  (cf. Table 1.2), viz.,
                                          top                      bottom
            B = B  x t  = b                   x y t  – b              x y t              (1-24)                     1                   
                                                                                                                           = ------
                                                                                                                              S           n               + v  w – v   dS       (1-27)
                                                                                                                                               
                                                                                                                                          S
                                                          top
                                                      F         = 0         n
                                                                                                                      
                                                                                                             Here  stands for the stress on the surface  with nor-
                                                                                                                    
                                      B (x,y,t)                                                              mal n . It represents a surface force per unit area
                                                            bottom              h                            depending on the orientation of the surface10. For
                                                        F              = 0                                   instance, let us consider the stress components on a pla-
                                                                                        top                  nar top surface as illustrated in Fig. 1.3. Assuming
z                                          b
                                               bottom
                                                         x y t                  b          x y  t 
         y                                                                                                   additionally a rigid and impermeable surface
        x                                                   datum level
                                                                                                             ( w = v  0 ) with a constant stress property on the unit
                                                                                                             area S the surface stresses are explicitly given by
                                Figure 1.2 Surface conditions.                                                                                     top        top
                                                                                                                                                        n                            (1-28)
                                                                                    top
For a free surface the top elevation z = b  x y t  is                                                    With n
                                                                                                                      top
                                                                                                                               =  0 1 0  the stress components become
identical to the hydraulic head h = h  x y t  . Accord-
ingly, the thickness is given by
                                                                                                                                  = 0 xx + 1 yx + 0 zx =  yx 
                                                                                                                            top
                                                                                                                          x
                                                                                                                                                                  
                                                      bottom                                                                top                                   
                                      B = h–b                                                       (1-25)                y      = 0 xy + 1 yy + 0 zy =  yy                        (1-29)
                                                                                                                                                                  
                                                                                                                                  = 0 xz + 1 yz + 0 zz =  yz 
                                                                                                                            top
                                                                                                                          z
If the bottom geometry is stationary the storage term in
(1-6) becomes
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                                                                                                                    B                     h
                                                                                                                            =   BS o + S s  ------                          (1-32)
                                                          top                                                     t                            t
                                                         y      =  yy
                                                                       0
                                                           n
                                                               top
                                                                     = 1
                                                                                                    where the compressibility S o and storativity S s are
                                                                       0
                                                                                                    introduced as
                                                                            top
                                                                           x     =  yx
                              y                                                                                       S o =  +  1 –   
                                                                                                                                                                              (1-33)
                                          top
                                         z     =  yz                                                                Ss =                 
                                  x
                         z
                    Figure 1.3 Surface forces related to components of                                 Notice, for a free fluid we have to set  = 1 and
                    the viscous stress tensor  .                                                   So =  .
                                                                                                    Neglecting the density effects in the divergence term of
                                                                                                    (1-30) by applying the Boussinesq approximation2 the
                                                                                                    fluid mass balance equation (1-30) yields
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                                                                                                                    h                           
                 NKQKN        cäìáÇ=ã~ëë=ÅçåëÉêî~íáçå                                                             S ------ +    Bv  = BQ  
                                                                                                                     t                                                       (1-34)
                                                                                                                  S =  BS o + S s              
                    The fluid mass conservation is described by speci-                                                                           
                 fying Eq. (1-6) with Table 1.2 as
                               B  +    Bv 
                             t
                                                      = BQ                              (1-30)   NKQKO       cäìáÇ=ãçãÉåíìã=ÅçåëÉêî~íáçå
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                                                                                                                           NKQ=_~ëáÅ=_~ä~åÅÉ=bèì~íáçåë
                                                                                  v
                                                        interface                 ----- 0           v   v  0               (1-40)
    Notice, in Eq. (1-35) the exchange term                                       t
vanishes for free fluid motion and the terms
  top bottom
          are dropped if the equation is not vertically          As the result, one yields a general momentum equation
integrated.                                                         for porous media (we consider the non-integrated form
In the following we assume the Newton’s viscosity law                            top
                                                                    with B  1  = 
                                                                                         bottom
                                                                                                = 0 ) as
(including the Stokes’s assumption10) which is written
in the form                                                                    p – g  = 
                                                                                                     interface
                                                                                                                 +  v
                                                                                                                           2
                                                                                                                                 (1-41)
                                   1
                       ' = 2 d – ---    v I        (1-37)     Furthermore, the drag forces due to fluid viscosity can
                                   3                                                          2
                                                                    usually be dropped  v  0 with respect to the drag
with the strain-rate tensor                                         term of momentum exchange 
                                                                                                      interface
                                                                                                                at interfaces of
                                                                    phases. The interfacial drag term of momentum
                             1                T                                 interface
                         d = ---  v +  v           (1-38)     exchange             can be derived as a linear friction
                             2
                                                                    relationship of the form3
For an incompressible fluid with a divergenceless (so-                                interface            –1
                                                                                                 = – k          v          (1-42)
called solenoidal) velocity   v = 0 the momentum
equation (1-35) leads to the well-known Navier-Stokes
equation                                                            where the permeability k represents an inverse friction
                                                                    tensor due to the viscous drag at the interfaces of fluid-
    v                                             2                solid phases.
B ----- +  Bv   v = – B  p – g  + B v    (1-39)
    t                                                              Finally, the momentum equation (1-41) reduces to the
           interface        top        bottom                       well-known Darcy equation of the form
+ B                 +         –            
                                                                                              k
                                                                                      v = – ------  p – g                   (1-43a)
from where specific forms can be derived as follows.                                        
                                                                    or with (1-18)
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                                                                                  v = – Kf   h + e  
                                                                                                          
   Commonly, in a porous medium the velocity v is                                      k o g             
                                                                                   K = ------------       
sufficiently small, that means the Reynolds number                                        o                                   (1-43b)
based on a typical pore diameter is of order unity or                                                     
                                                                                       o                 
smaller. As the result, the inertial effects in the momen-                        f = -----
                                                                                           -              
                                                                                                         
tum equation (1-39) can be neglected
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                 valid for flow in a porous medium.                                                      dp
                                                                                                                                 2
                                                                                                         ------ – g x =  --------u
                                                                                                                           d
                                                                                                                                                  (1-45)
                                                                                                         dx                dy
                                                                                                                                 2
                 NKQKOKO mä~åÉ=~åÇ=~ñáëóããÉíêáÅ=é~ê~ääÉä=
                 EmçáëÉìáääÉF=Ñäçï                                                Integrating (1-45) with the boundary conditions
                                                                                  u  0  = u  b  = 0 it yields
                     A flow is called parallel when inertial terms of the
                 Navier-Stokes equation (1-39) vanishes. That means, a                                1 dp
                                                                                              u = – ------  ------ – g x y  b – y          (1-46)
                 fluid particle is subjected to zero acceleration, accord-                          2 dx
                 ingly, it moves in pure translation with constant veloc-
                 ity. It follows that pathlines must be straight lines and        and we obtain the average velocity in the aperture b as
                 that the velocity of each particle may depend only on
                 coordinates perpendicular to the direction of flow. Such                              b
                                                                                                                             2
                                                                                               1                       b dp
                 flow fields occur between two parallel plates or in a                     u = ---         u dy = – ---------  ------ – g x   (1-47)
                                                                                               b                     12  dx                 
                 circular tube as depicted in Fig. 1.4.                                              y=0
                  a)                               b)
                        y                                r                        and the discharge Q
                                                                                                                         3
                                                                                                           b dp
                   b
                                                    R                                         Q = ub = – ---------  ------ – g x             (1-48)
                                                                                                         12 dx
                                  u                                 vz      z
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              vr
                                                                                       As seen the Hagen-Poiseuille’s laws of laminar fluid
    v = v                    vz = vz  r                vr = v = 0         (1-50)   motion for 1D and 2D plane flow (1-47) and for axi-
              vz                                                                       symmetric flow (1-53) represent linear relationships
                                                                                       with respect to the pressure gradient and gravity
                                                                                        p – g  . In a generalized form one yields finally
one solves in the z-direction the momentum equation                                    with (1-18)
                      dp                v
                      ------ – g z = --- -----  r --------z                (1-51)   v = – Kf   h + e 
                      dz               r r  r                                                                                                     (1-56)
                                                                                              2
                                                                                           r hydr  o g                 r hydr = b  2 a = 3 for 1D/2D plane
With dv z  dr = 0 at r = 0 and v z  R  = 0 the integra-                             K = -------------------- I with 
                                                                                                 a o                   r hydr = R  2 a = 2 for axisymmetry
tion of (1-51) gives
                          1 dp
                v z = – ------  ------ – g z  R – r 
                                                     2   2
                                                                              (1-52)
                        4 dz                                                          NKQKOKP i~ïë=çÑ=ÑäìáÇ=ãçíáçå=Ñçê=çîÉêä~åÇ=
                                                                                       ~åÇ=ÅÜ~ååÉä=Ñäçï
Then, the average velocity for the Hagen-Poiseuille
flow in a circular tube becomes                                                           Basically, the fluid motion for overland and channel
                                                                                       flow is described by the vertically integrated Navier-
                      2        R
                                                                 2                     Stokes equation (1-39) according to
           1                                        R dp
  v z = ---------2                v z r dr d = – ------  ------ – g z   (1-53)
        R                                          8  dz                                      v
                     =0 r=0                                                                   B ----- +  Bv   v = – B  p – g               (1-57)
                                                                                                  t
                                                                                                        2         top        bottom
                                                                                               + B v + B            –            
and we get for the discharge through the tube
                                                  4
                              R dp                                                    which is a formulation of the well-known De Saint-
               Q = R v z = – ---------  ------ – g z
                     2
                                                                              (1-54)
                                8 dz                                                  Venant equations1. Over a wide range of practical over-
                                                                                       land and channel flow (Fig. 1.5) at low-to-moderate
The relationships (1-53) can be expressed by the                                       velocity/flow regimes the inertial terms in the govern-
hydraulic radius r hydr if replacing the dimension R  2                               ing momentum balance equation (1-35) can be ignored
for the tube flow according to Table 1.3 (type E)                                      compared with the gravitational terms, friction and
                                                                                       pressure effects. Furthermore, the interior viscous
                                      2                                                effects can be neglected over the shear stress effects at
                               r hydr dp
                       v z = – -----------  ------ – g z                 (1-55)   the surfaces1,9. Assuming this,
                                 2 dz
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                        v                                                     2                                      following momentum equation can be derived
                        -----  0         v   v  0                     v  0                          (1-58)
                        t
                                                                                                                                       p – g  +  o gS f = 0 
                                                                                                                                                                 
                 the momentum equation (1-57) reduces to                                                                                         v v-                              (1-62)
                                                                                                                                      S f = ---------------
                                                                                                                                               2                
                                                                                                                                             r hydr             
                                                   top         bottom
                              p – g  –              +                 = 0                              (1-59)
                                                                                                                                                                           v v-
                                                                                                                               Chezy               C           1     -----------------
                                           top                                                                                                                           2
                 The shear effect      at the top (free) surface can be                                                                                             C r hydr
                 caused by wind stress. For the present application we
                 neglect influences caused by wind stress:                                                                                                                  v v-
                                                                                                                        Manning-Strickler          M          43    ------------------
                                                                                                                                                                          2 43
                                                                                                                                                                     M r hydr
                                                  top
                                                       0                                                   (1-60)
                 On the other hand, the shear effect at the bottom can be                                                Instead of using the pressure p as primary variable
                 expressed by a friction slope relationship of the form                                               the hydraulic head h or the local water depth  (cf.
                                                                                                                      Eqs. (1-16) and (1-18)) are alternative formulations of
                                         bottom      o g v v                                                         (1-62), viz.,
                                                  = -------------------
                                                         2 
                                                                                                             (1-61)
                                                        r hydr
                                                                                                                                       o g  h + S f + e  = 0                 (1-63a)
                                                                                                                      and
                 representing friction laws, where v = v  v ,  is a
                 friction factor and   1 is a constant. As the result, the
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                                                                                                                                       2
where fluid density effects are included in the e -                                                                       r hydr
term.                                                                                                    lim v = – lim ------------------- I h = 0               (1-68)
                                                                                                        h  0    h  0 4              2
                                                                                                                              h
   Equation (1-63a) can be used to derive a diffusion-
type flow equation7,9. Since, exemplified for 2D
                                                                                                NKQKP        `çåí~ãáå~åí= ã~ëë= ÅçåëÉêî~J
               v
                   2
                       = u +v =
                                2         2       2 
                                                  r hydr
                                                                   2
                                                                 S fx   +
                                                                              2
                                                                            S fy       (1-64)   íáçå
and with (1-62)
                                                                                                   The balance equation for a contaminant mass results
                                                                                                from Eq. (1-6) and Table 1.2 in form of
                            2        2                                  2      2
                    u + v-                                       u + v-
         S fx = -------------------- u                S fy = -------------------- v    (1-65)
                     2 
                   r hydr
                                                                  2 
                                                                r hydr                              ------------------
                                                                                                          BC 
                                                                                                                         +    BCv  +    Bj c  = Br c   (1-69)
                                                                                                             t
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                                                                                                =  +  1 –    C               
                 The hydrodynamic dispersion tensor D consists of the                                                                
                                                                                                                                              (1-76)
                 molecular diffusion part D d I and the mechanical dis-                        d =  +  1 –   d    C   C  
                 persion part D m . In a porous medium D m is commonly                                           dC                  
                 described by the Scheidegger-Bear dispersion relation-
                 ship as                                                           in which the sorption function   C  can be specified
                                                                                   for Henry, Freundlich or Langmuir isotherms2.
                                                           vv
                          D m =   T v I +   L –  T  ------------   (1-72)
                                                                v
NQ=ö=cbcilt
                                                                                                        NKR=dÉåÉê~äáòÉÇ=jçÇÉä=bèì~íáçåë
j T = –   T                                                  
                                                                
                                                                 (1-79)
 = 
        cond
               +
                       disp         f            s       f f
                              =   +  1 –   I +  c D m           NKRKO     `çåí~ãáå~åí=ã~ëë
                                                                
                                                                               The governing contaminant mass transport equation
one yields the following balance equation for the ther-                    (1-75) can now be specified for the different flow con-
mal energy2                                                                ditions and discrete feature elements. Table 1.6 summa-
                                                                           rizes the different terms and expressions for both
            f f             s s T            f f                          porous media and free fluid conditions.
     B   c +  1 –    c   ------ +  c Bv  T
                                    t
                                     f f
    –    B  T  + B c Q   T – T o                     (1-80)
                                                                           NKRKP     eÉ~í
               f   f                 s     s
    = B   Q T +  1 –   Q T 
                                                                              The specified terms for the governing heat transport
to be solved for the system temperature T .                                equation (1-80) are summarized in Table 1.7 for both
                                                                           porous media and free fluid conditions.
    «aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã                                                                                                  cbcilt=ö=NR
aáëÅêÉíÉ= ÑÉ~íìêÉ= ãçÇÉäáåÖ= çÑ= ÑäçïI= ã~ëë= ~åÇ= ÜÉ~í= íê~åëéçêí= éêçÅÉëëÉë= Äó= ìëáåÖ
cbcilt
                                                                      Table 1.5 Flow model equations
                                                                           h
                                                               L  h  = S ------ –    Kf  B   h + e   – Q = 0
                                                                            t
                                                   S                                                                       Kf  B                                                         Q
Case Darcy Poiseuille Overland Darcy Poiseuille Overland Darcy Poiseuille Overland
                                                                                       k o g                        2                                       2
                                                                                    bB -----------
                                                                                                 - f          hydr  o gI f 
                                                                                                        bB r-----------------------                  r hydr I
         1DPP           b  BS o + S s       b  B + 1          b  B + 1            o                                                     bB ------------------
                                                                                                                                                                     - f    bBQ      bBQ       bBQ 
                                                                                                                   3 o                             4                2
     (1D plane phre-                                                                                                                                       h
                                                                                        
                                                                                        
                                                                                        
                                                                                                             
                                                                                                             
                                                                                                             
                                                                                                             
                                                                                                             
                                                                                            K
                                                                                                                                                     
                                                                                                                                                     
                                                                                                                                                     
                                                                                                                                                     
                                                                                                                                                     
          atic)                                                                                                             K                               K
                                                                                                                     2                                       2
                                                                                                               hydr  o gI f 
                                                                                       k o g           bB r-----------------------                  r hydr I
          1DPN                                                                      bB -----------
                                                                                                 - f                                            bB ------------------
                                                                                                                                                                     - f
                             bBS o               bB                  bB                 o                       3 o                                                      bBQ      bBQ       bBQ 
                                                                                                                                                    4                2
      (1D plane non-                                                                                                                                       h
                                                                                        
                                                                                        
                                                                                        
                                                                                                             
                                                                                                             
                                                                                                             
                                                                                                             
                                                                                                             
                                                                                            K
                                                                                                                                                     
                                                                                                                                                     
                                                                                                                                                     
                                                                                                                                                     
                                                                                                                                                     
         phreatic)                                                                                                          K                               K
                                                                                                                       2                                    2
                                    Ss                                                2 k o g                       r hydr  o gI f               2 r hydr I
                                                       1                    1       R -----------           2
         1DAP           R  S o + ----   R   + ---      R   + ---                - f    R           ----------------------- 
                          2                    2                    2                                                                                                          2          2          2
                                                                                          o                                                    R ------------------
                                                                                                                                                                     - f    R Q     R Q      R Q 
                                     B                 B                    B                                               2 o                    4                2
      (1D axisym-                                                                                                                                          h
                                                                                         
                                                                                         
                                                                                         
                                                                                                                 
                                                                                                                 
                                                                                                                 
                                                                                                                 
                                                                                                                 
                                                                                                K
                                                                                                                                                    
                                                                                                                                                    
                                                                                                                                                    
                                                                                                                                                    
                                                                                                                                                    
     metric phreatic)                                                                                                          K                            K
                                                                                                                       2                                    2
                                                                                      2 k o g f                     r hydr  o gI f               2 r hydr I
          1DAN                   2
                            R S o               R 
                                                       2
                                                                      R 
                                                                            2
                                                                                    R -----------
                                                                                                 -     R
                                                                                                             2
                                                                                                                     -----------------------    R ------------------
                                                                                                                                                                     - f      2
                                                                                                                                                                             R Q 
                                                                                                                                                                                          2
                                                                                                                                                                                        R Q 
                                                                                                                                                                                                     2
                                                                                                                                                                                                   R Q 
                                                                                          o                                2 o                    4                2
       (1D axisym-                                                                                                                                        h
                                                                                         
                                                                                         
                                                                                                                 
                                                                                                                 
                                                                                                                 
                                                                                                                 
                                                                                                                 
                                                                                                                                                    
                                                                                                                                                    
                                                                                                                                                    
                                                                                                                                                    
                                                                                                                                                    
        metric non-                                                                            K                               K                            K
         phreatic)
                                                                                                                 2                                         2
                                                                                       k o g f
                                                                                     B -----------             hydr  o gI f 
                                                                                                         B r-----------------------                 r hydr I
         2DPP              BS o + S s           B + 1               B + 1                      -                                              B ------------------
                                                                                                                                                                    - f      BQ       BQ        BQ 
                                                                                          o                       3 o                            4                2
     (2D plane phre-                                                                                                                                      h
                                                                                       
                                                                                       
                                                                                       
                                                                                                             
                                                                                                             
                                                                                                             
                                                                                                             
                                                                                                             
                                                                                                                                                   
                                                                                                                                                   
                                                                                                                                                   
                                                                                                                                                   
                                                                                                                                                   
          atic)                                                                            K                               K                               K
                                                                                                                 2                                         2
                                                                                       k o g f
                                                                                     B -----------             hydr  o gI f 
                                                                                                         B r-----------------------                 r hydr I
          2DPN                BS o                B                   B                        -                                              B ------------------
                                                                                                                                                                    - f      BQ       BQ        BQ 
                                                                                          o                       3 o                            4                2
      (2D plane non-                                                                                                                                      h
                                                                                       
                                                                                       
                                                                                       
                                                                                                             
                                                                                                             
                                                                                                             
                                                                                                             
                                                                                                             
                                                                                                                                                   
                                                                                                                                                   
                                                                                                                                                   
                                                                                                                                                   
                                                                                                                                                   
         phreatic)                                                                         K                               K                               K
          3DP                                                                                                    2                                       2
       (3D phreatic                                                                    k o g f              r hydr  o gI f                          r hydr I
                               So                                                    ------------         -----------------------                ------------------
                                                                                                                                                                      - f    Q         Q        Q
                                                                                          o                        3 o
      and non-phre-                                                                                                                                  4
                                                                                                                                                            h
                                                                                                                                                                      2
                                                                                      
                                                                                      
                                                                                      
                                                                                                          
                                                                                                          
                                                                                                          
                                                                                                          
                                                                                                          
                                                                                                                                                  
                                                                                                                                                  
                                                                                                                                                  
                                                                                                                                                  
                                                                                                                                                  
          atic)                                                                           K                                K                                 K
NS=ö=cbcilt
                                                                                                               NKR=dÉåÉê~äáòÉÇ=jçÇÉä=bèì~íáçåë
        1DAP              2
                        R  d       R
                                          2       2
                                                R v
                                                              2
                                                            R v
                                                                       2
                                                                    R   D d I + D m 
                                                                                                    2
                                                                                                 R  D d I + D m 
                                                                                                                         2
                                                                                                                      R  Q  +  
                                                                                                                                                2
                                                                                                                                             R  Q  +  
                                                                                                                                                                2
                                                                                                                                                              R Q c
                                                                                                                                                                              2
                                                                                                                                                                            R Q c
   (1D axisymmetric
     phreatic and
     non-phreatic)
         3DP             d           1          v          v          Dd I + Dm                Dd I + Dm           Q  +                Q +          Q c          Qc
   (3D phreatic and
     non-phreatic)
«aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã                                                                                                                                 cbcilt=ö=NT
aáëÅêÉíÉ= ÑÉ~íìêÉ= ãçÇÉäáåÖ= çÑ= ÑäçïI= ã~ëë= ~åÇ= ÜÉ~í= íê~åëéçêí= éêçÅÉëëÉë= Äó= ìëáåÖ
cbcilt
                                                                Table 1.7 Heat transport model equations
                                                                    T
                                                        L  T  = S ------ + q  T –    B  T  +   T – T o  – Q = 0
                                                                     t
                                               S                                  q                                          B                                                                                            Q
                                                                                                                                                                                                                                 free
              Case           porous                free fluid    porous               free fluid       porous                      free fluid               porous          free fluid      porous
                                                                                                                                                                                                                                 fluid
                                   f f                                                                                                            f                                                     f           f
             1DPP         bB   c +                   f f            f f                 f f      bB    +
                                                                                                                     f             bB   I +                    f f            f f      bB   Q T +                                    f           f
                                                    bB c       bB c v              bB c v                                           f f
                                                                                                                                                          bB c Q         bB c Q                                            bB Q T
        (1D plane phre-    1 –   c 
                                        s s                                                                      s
                                                                                                    1 –   I +                      c Dm                                            1 –   Q T 
                                                                                                                                                                                                                s           s
                             2         f f                                                                                              2             f                                     2               f           f
            1DAP          R   c +                                                                  2                 f        R   I +                                             R   Q T +
                                                      2 f f
                                                   R  c
                                                                  2
                                                                R  c v
                                                                            f f          2 f f
                                                                                      R  c v     R    +                                              2     f f
                                                                                                                                                          R  c Q 
                                                                                                                                                                              2 f f
                                                                                                                                                                            R  c Q 
                                                                                                                                                                                                                                  2 f
                                                                                                                                                                                                                                R  Q T
                                                                                                                                                                                                                                                          f
                                                                                                                                        f f
         (1D axisym-       1 –   c 
                                        s s
                                                                                                                 s                      c Dm                                            1 –  
                                                                                                                                                                                                                s    s
                                                                                                                                                                                                                    QT 
                                                                                                    1 –   I +
        metric phreatic                                                                                    f f
             and                                                                                      c D m 
        non-phreatic)
                                  f f                                                                                                         f                                                     f           f
             2DPP          B   c +                   f f            f f                f f        B    +
                                                                                                                 f                 B I +                       f f            f f       B   Q T +                                f           f
                                                     B c       B c v                B c v                                           f f
                                                                                                                                                           B c Q          B c Q                                            B Q T
        (2D plane phre-    1 –   c 
                                        s s                                                                      s
                                                                                                    1 –   I +                      c Dm                                            1 –   Q T 
                                                                                                                                                                                                                s           s
                                 f f                                                                         f                                                                                  f           f
             3DP             c +                     f f            f f                f f            +                       f              f f           f f            f f          Q T +                               f           f
                                                     c           c v                 cv                                        I +  c Dm              c Q            c Q                                               QT
                                                                                                                 s
          (3D phreatic      1 –   c
                                         s s
                                                                                                    1 –   I +                                                                         1 –   Q T
                                                                                                                                                                                                                    s       s
         and non-phre-                                                                                     f f
                                                                                                       c D m
             atic)
NU=ö=cbcilt
                                                                                                                  NKS=cáåáíÉ=bäÉãÉåí=cçêãìä~íáçåë
NKS cáåáíÉ= bäÉãÉåí= cçêãìä~J                                        given. In (1-82) n corresponds to the normal unit vec-
    íáçåë                                                            tor (positive outward),  1 and  2 are prescribed
                                                                     boundary values of  on  1 and  2 , respectively.
NKSKN j~ëíÉê= Éèì~íáçåI= ÄçìåÇ~êó
                                     The finite element formulation is based on the weak
ÅçåÇáíáçåë=~åÇ=ïÉ~â=ëí~íÉãÉåí     form of the basic equation (1-81). Introducing a spatial
                                                                     weighting function w we get
   The governing balance equations as listed in Tables
1.5, 1.6 and 1.7 can be generalized by the following                                      
master equation                                                                   w  S ------
                                                                                           t
                                                                                               - + q   d
                                                                                                                              (1-83)
                                                                                 
              
  L    = S ------- + q   –    D    – Q  = 0
               t
                                                                                  =    w     D    + Q  d
                                                            (1-81)                    
                       Q  = –  + Q
                                                                     Applying partial integration and the divergence theo-
which has to be solved for flow (  = h ), contaminant               rem (Green’s theorem) to the weak statement (1-83)
mass (  = C ) and heat (  = T ) for 1D, 2D and 3D                  and inserting the Robin-type BC (1-82) the following
discrete feature elements.                                           weak form for the finite element method finally results
               D                                                                   
    Let   R and  0 T t  be the spatial and temporal
                                                                           w  S ------- + q   + w   D    d     (1-84)
domain, respectively, where D is the number of space                                t
                                                                        
dimension (1, 2 or 3) and T t is the final time, and let
 =  1   2 denote the boundary of  , where  1
                                                                        +    wa d      =     wQ d +  w  a2 – b  d
                                                                            2                              2
and  2 are two disjoint portions of the total boundary,
 , the following boundary conditions (B.C.’s) have
to be appended to (1-81):
                                                                     NKSKO        pé~íá~ä=ÇáëÅêÉíáò~íáçå
                                 = 1      on   1 
                                                           (1-82)       In the finite element context a spatial semi-discreti-
    – n   D    + a   2 –   = b    on   2                           h
                                                                     zation  of the continuum domain  is achieved by
                                                                                                                            e
                                                                     the union of a set of non-overlapping subdomains  ,
where on  1 we have Dirichlet BC and on  2 it repre-               the finite elements, as
sents a more general form of a Robin type BC in which
more specific Neumann and Cauchy type BC’s are                                                      h
                                                                                                  
                                                                                                                  e
                                                                                                                               (1-85)
involved. If a = 0 a Neumann BC of 2nd kind results,
                                                                                                         e
while for b = 0 a common Cauchy BC of 3rd kind is
    «aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã                                                                                                     cbcilt=ö=NV
aáëÅêÉíÉ= ÑÉ~íìêÉ= ãçÇÉäáåÖ= çÑ= ÑäçïI= ã~ëë= ~åÇ= ÜÉ~í= íê~åëéçêí= éêçÅÉëëÉë= Äó= ìëáåÖ
cbcilt
                                                                  e
                 On any finite-element domain  , the unknown vari-                   polynomials that are piecewise-continuously differen-
                 able  (and dependent coefficients) are replaced by a                tiable and square integrable (but whose second and
                 continuous approximation that assumes the separability               higher derivatives need not to exist).
                 of space and time, thus
                                                                                         Using the Galerkin-based finite element method
                                          h                                           where the test function w becomes identical to the trial
                             x t     x t  = N i  x  i  t      (1-86)
                                                                                      space N , Eq. (1-84) leads to the following global
                                                                                      matrix system of M equations
                 where i = 1  M designates nodal indices, M is the
                 total number of nodes, N i is the nodal basis function,                                  ·
                                                                                                        O+K–F = 0                      (1-87)
                 called the trial space, and x are the spatial coordinates
                 (1-11). Note that the summation convention is used for
                 repeated indices. For the present analysis the basis                 with its components written in indicial notation
                 functions Ni are based on C 0 (continuous) piece-wise
                                                    e                                                                        
                                    O ij =     Oij     =     SNi Nj d                                                    
                                                                                                                             
                                           e         e e
                                                                                                                             
                                                                                                                             
                                               e                                                                             
                                    K ij =  K ij =    N i q  N j + N i   D  N j  + N i N j  d +  aN i N j d 
                                                                                                                                          (1-88)
                                           e         e e                                                       e
                                                                                                               2            
                                                                                                                             
                                                                                                                             
                                              e
                                    F i =  F i =   N i Q d +  N i  a 2 – b  d                                       
                                                                                                                             
                                           e        e e            2
                                                                      e                                                      
                                                                                                                             
                 where the subscripts i j = 1  M denote nodal indi-               cally only solved by numerical schemes. For stability
                 ces. The superposed dot in (1-87) means differentiation              reasons implicit (A-stable) two-step techniques are pre-
                 with respect to time t , viz.,                                       ferred.
OM=ö=cbcilt
                                                                                                                                NKS=cáåáíÉ=bäÉãÉåí=cçêãìä~íáçåë
    «aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã                                                                                                                      cbcilt=ö=ON
aáëÅêÉíÉ= ÑÉ~íìêÉ= ãçÇÉäáåÖ= çÑ= ÑäçïI= ã~ëë= ~åÇ= ÜÉ~í= íê~åëéçêí= éêçÅÉëëÉë= Äó= ìëáåÖ
cbcilt
                 NKSKQ         cáåáíÉJÉäÉãÉåí=Ä~ëáë=çéÉê~íáçåë                                                  alized (local) coordinates (see Fig. 1.6). The coordinate
                                                                                                                transformation (or mapping) that bridges a computa-
                                                                                                                                                                       D
                     A fundamental aspect of the finite-element method                                          tional (transform)  -space and the Euclidean space R
                 is the use of master elements where all element-data                                           is
                 inner products and integrations are performed in gener-
                           1                                                                                                                                 x
                       R
                                                                                 (+1)
                                      (-1)
                                                                         
                                                                                                          e     e
                                                                                                e :   x = x   
                                                                
                                      (-1,1)                                     (1,1)
                                                                                                                                                                 x
                           2                                                                                                                         y
                       R
                                                                             
(-1,-1) (1,-1)
                                                               
                                (-1,-1,1)                           (-1,1,1)
                           3
                       R                                                             (1,1,1)
                                                 (1,-1,1)                                                                                            x
                                                                                 
                               (-1,-1,-1)                                                                                                                       z
                                                             (-1,1,-1)
(1,-1,-1) (1,1,-1) y
                                                                                                                                 D
                                                 Figure 1.6 Finite elements with one-to-one mapping onto R                           ( D = 1,2,3).
OO=ö=cbcilt
                                                                                                                                                NKS=cáåáíÉ=bäÉãÉåí=cçêãìä~íáçåë
                                                        e
                     Ni = Ni  x  =            Ni                          (1-100)
                                                                                               with x =  x 1 x 2 x 3  according to (1-11). To evaluate
                                                e
                                                                                               the flux vector divergence terms in (1-88) the inverse
                                       x = Ni xi                                               Jacobian is required
    x          x          x 3
    -------1-   -------2-   --------
                         
    x
  = -------1-   x 2        x 3
                --------    --------
                         
    x 1        x 2        x 3
    --------    --------    --------
                         
                                           
                                                      J 22 J 33 – J 32 J 23   J 13 J 32 – J 12 J 33   J 12 J 23 – J 13 J 22 
                                                1-                                                                                                  3
                                              ------  J 31 J 23 – J 21 J 33   J 11 J 33 – J 13 J 31   J 21 J 13 – J 23 J 11       in      R
                                                J
                                                      J 21 J 32 – J 31 J 22   J 12 J 31 – J 32 J 11   J 11 J 22 – J 12 J 21 
                         –1              
                     J          = ------ =                                                                                                              (1-103)
                                  x            1 - J 22 – J 12                                                                                     2
                                              ------                                                                                    in      R
                                                J –J J
                                                        21 11
                                           
                                                1-                                                                                                  1
                                              ------                                                                                    in      R
                                                J
    «aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã                                                                                                                                   cbcilt=ö=OP
aáëÅêÉíÉ= ÑÉ~íìêÉ= ãçÇÉäáåÖ= çÑ= ÑäçïI= ã~ëë= ~åÇ= ÜÉ~í= íê~åëéçêí= éêçÅÉëëÉë= Äó= ìëáåÖ
cbcilt
                 with the determinant of J
                                                                                                                                                    3
                                        J 11  J 22 J 33 – J 32 J 23  – J 21  J 12 J 33 – J 13 J 32  + J 31  J 12 J 23 – J 13 J 22    in   R
                                                                                                                                                    2
                                   J =  J J –J J                                                                                           in   R       (1-104)
                                        11 22 21 12
                                        J                                                                                                  in   R
                                                                                                                                                     1
                                        11
                        dx d y d z =    J d d d 
                                                                   D
                        dxdy =          J d d       Cartesian R  D = 1 2 3 
                                                   
                  d =        dx =      J d                                         (1-105)
                       
                       
                       
                        rdrddz        = 2 J r d d axisymmetric
OQ=ö=cbcilt
                                                                                                               NKS=cáåáíÉ=bäÉãÉåí=cçêãìä~íáçåë
               x-    x
               -----  -------
                                    i j k                         J 12 J 23 – J 13 J 22
                      y- d d = det J J J d d =
                y-  ------
               -----                    11 12 13                      J 13 J 21 – J 11 J 23 d d   at    = 1
                    
                                      J 21 J 22 J 23                  J 11 J 22 – J 12 J 21
                z
                ------
                        z
                       -------
            
                    
            
               x        x
               -------   ------
                                          i j k                   J 22 J 33 – J 23 J 32
               y        y
               -------  ------ d d = det J 21 J 22 J 23 d d =    J 23 J 31 – J 21 J 33 d d   at    = 1
                       
                                            J 31 J 32 J 33            J 21 J 32 – J 22 J 31
                z       z-
                -------   -----
                       
            
               x       x
               ------   ------
                                        i j k                     J 12 J 33 – J 13 J 32
            
               y       y                                                                          at    = 1
                ------  ------ d d = det J 11 J 12 J 13 d d =     J 13 J 31 – J 11 J 33 d d
                      
                                           J 31 J 32 J 33             J 11 J 32 – J 12 J 31
       d =    z
                ------
                         z
                         ------
                                                                                                                        (1-106)
                      
            
            
            
               x-
               -----
                d =      J 11
                                    d =
                                             2     2
                                            J 11 + J 12 d      at           = 1
               y           J 12
                ------
               
            
            
               x
                -------
                d =       J 21
                                    d =
                                              2     2
                                            J 21 + J 22 d        at           = 1
               y-           J 22
                ------
               
            
            
            
                     = –1
            
               =1
            
            
«aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã                                                                                                      cbcilt=ö=OR
aáëÅêÉíÉ= ÑÉ~íìêÉ= ãçÇÉäáåÖ= çÑ= ÑäçïI= ã~ëë= ~åÇ= ÜÉ~í= íê~åëéçêí= éêçÅÉëëÉë= Äó= ìëáåÖ
cbcilt
                                                                  2
                 and in cylindrical coordinates of R (meridional) space
                                                    r
                                                    ------
                                                     r d d = 2 J 11 rd = 2 J 2 + J 2 rd                          at         = 1
                                                                                    11    12
                                                     z-             J 12
                                                    -----
                                                    
                                   d =                                                                                                     (1-107)
                                                 r
                                                ------
                                                 r d d = 2 J 21 rd = 2 J 2 + J 2 rd                                at       = 1
                                                 z             J 22
                                                                                 21    22
                                                ------
                                                
                           f  x  d   =     f    d   =       f      d d d   =       wi wj wk f  i j k 
                                             e e                    e –1 –1 –1                          e i=1 j=1k=1
                                                                                                                                             (1-108)
                                                                        1 1                       n Gauss n Gauss
                           g  x  d   =     g    d   =      g     d d   =      wi wj g  i j 
                                             e e                    e –1 –1                   e i=1 j=1
                 where the n Gauss is the number of Gauss points, w i are                       NKSKR ^ëëÉãÄäó= çÑ= íÜÉ= ÇáÑÑÉêÉåí= ÑÉ~J
                 weighting coefficients and the indices  i j k  indicate                    íìêÉ= ÉäÉãÉåíë= íç= íÜÉ= ÖäçÄ~ä= ëóëíÉã
                 the positions of the evaluation points in their local
                                                                                                ã~íêáñ
                 coordinates  . The functions f  .  and g  .  in the inte-
                 grands are marked by an asterisk if the volume and sur-
                 face integrals are expressed in the  -coordinates                             NKSKRKN         kÉÉÇë=Ñçê=ÅççêÇáå~íÉ=íê~åëÑçêã~J
                 according to (1-105), and .
                                                                                                íáçå
                    For 1D elements the integrals of (1-88) can easily
                                                                                                   The global matrix equations (1-87) written in the
                 evaluated in a direct analytical manner so as shown in
                                                                                                form
                 Appendix B for a channel element with a linear basis
                 function N .
OS=ö=cbcilt
                                                                                                NKS=cáåáíÉ=bäÉãÉåí=cçêãìä~íáçåë
                                                                                                                 e   e
                                                                                                  e :   x = x   
                                                                                 3
                                    z                      2D element in the R space
                                                  y                                                                                      
                                                                                                                         (-1,1)                   (1,1)
                                                                            y
                    z                                        x
                                                                                                                                              
                                                                                                                         (-1,-1)                  (1,-1)
                                y
                                                                                     x
                                                                                 3
                                                            1D element in the R space
                                             y
                           z
x
                    z                                                                                                                               (+1)
                                                                                                                           (-1)
                                                                                                                                              
                                                                                          x
                   Figure 1.7 Global x – y – z -coordinate system, rotated elemental x – y – z -coordinate system and local  –    -coor-
                                                                 3
                   dinate system for 2D and 1D elements in the R space.
                 NKSKRKO        dÉåÉê~äáòÉÇ=ÇáëÅêÉíÉ=ëóëíÉã                                                                       
                                                                                                      e                       Te
                                                                                                x = a  x            x=a          x
                    Since the rotation matrix a forms an orthonormal                                                              
                                                                                                 e    e
                                                                                                = T  
                                                                                                             e        e   Te
                                                                                                                      = T  
                                                                                                                                e            (1-112)
                 basis we can transform between the x - and the x -sys-                                                          
                                                                                                                     F = T  F 
                                                                                                 e    e      e        e   Te    e
                 tem according to                                                              F = T  F
OU=ö=cbcilt
                                                                                                                                                     NKS=cáåáíÉ=bäÉãÉåí=cçêãìä~íáçåë
where                                                                                                                      e
                                                                                                                         K = T
                                                                                                                                   Te        e
                                                                                                                                          K  T 
                                                                                                                                                     e
                                                                                                                                                              (1-115b)
                                                                                                                   e           e
                                        a
                                            e
                                                0 0 
                                                                                                          where q and q represent elemental ’flux’ compo-
                            e                       e
                                                                                                          nents for the local and the global coordinate system,
                       T =               0 a 0                                                  (1-113)   respectively. On inserting (1-112), (1-115a) and (1-
                                                            e
                                        0 0 a                                                             115b), using the same transformation rules for the stor-
                                                                                                         age matrix O and assuming that in general the right-
                                                                                                          hand side vector F can also be directionally dependent,
                                                                                                     e    the global matrix system (1-109) yields finally the form
is a diagonal directional cosines matrix built up of a
matrices in a number equal to that of the nodes in the                                                                     ·
                                                                                                                         O+K–F = 0 
element e                                                                                                                                        
                                                                                                                       O =   T   O  T   
                                                                                                                                 Te     e  e
and
                                                                                                                            e                    
                                                                                                                                                 
                                                                                                                                 Te    e   e                  (1-116)
                  Te                                                      e    e       e                               K =   T   K  T   
              a        0        0                                       a 11 a 21 a 31
                           Te                                                                                               e                    
    Te                                                      Te                                                                                   
T        =        0 a           0                       a            = ae ae ae                 (1-114)
                                                                        12 22 32                                                Te   e
                                                                                                                       F =   T  F           
                 0     0 a
                                Te
                                                                          e    e       e                                                         
                                                                         a 13 a 23 a 33                                    e                     
                 
                                                                                                                                                 e
                                                                     e         e
                                                                                                          where the rotation matrix T is evaluated at element
are the transposes of matrices T and a , respectively.                                                                           e
                                                                                                          level e. Practically, T is only required for mapping 2D
                                                                                                                                                     3
                                                                                                          and 1D feature elements in the general R space, while
    We can usually assume that any directional proper-                                                    3D elements need not to rotate to the x -system (the
ties of the discrete system (1-109) are available in the                                                                                       e
                                                                                                          rotation matrix becomes unity T  I ) and can be
local x -coordinates. Then, the local (elemental) sys-                                                   directly mapped onto the local  -space via the Jaco-
                e     e
tem matrix K = K x is transformed into the global                                                       bian J (1-101).
          e
matrix K according to
                                                                                                             However, there are important special cases to be
    e        e         e            e           e           e
q = K   = K   T                                                                                considered here. Firstly, if the material properties of the
                                                                                               (1-115a)                       e           e
    e
q = T
             Te        e
                   q =  T
                                    Te              e            e
                                           K  T     = K  
                                                                          e        e       e              square matrices O and K are independent of the
                                                                                                          coordinate directions (isotropic conditions) then we
                                                                                                          have
with
         «aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã                                                                                                                                   cbcilt=ö=OV
aáëÅêÉíÉ= ÑÉ~íìêÉ= ãçÇÉäáåÖ= çÑ= ÑäçïI= ã~ëë= ~åÇ= ÜÉ~í= íê~åëéçêí= éêçÅÉëëÉë= Äó= ìëáåÖ
cbcilt
                                 T
                                      Te       e    e
                                             O  T   = O
                                                                e             tors u 1 and u 2 (Fig. 1.8), which are parallel to the
                                      Te       e    e           e
                                                                    (1-117)   local  - and  -axes, respectively. They can be found
                                 T          K  T   = K                 by the following shape-derived relationships
                           Te     e
                 because T  T = I due to the condition of orthogo-                        x-
                                         e    e   e    e                                   -----
                 nality and accordingly O = O , K = K .                                          J 11
                                                                                        
                                                                                           y     =        at    = 1
                                                                                           ------   J 12
                     Secondly, if the sink/source and boundary condition                   
                 terms incorporated in the right-hand side vector F rep-                   z-      J 13
                                                                                           -----
                 resent direction-independent quantities so as occurred                    
                 in the balance equations summarized in Tables 1.5, 1.6                 
                                                                                           x
                 and 1.7, the vector F consists of nodal scalars and can                   ------
                 be directly evaluated (no rotation), viz.,                                     J 21
                                                                                           y = J
                                                                                   u1 =    ------   22
                                                                                                            at    = 1      (1-119)
                                                      e                                    
                                       F =      F                 (1-118)             
                                                                                            z
                                                                                            ------
                                                                                                   J 23
                                                e
                                                                                           
                                                                                        
                                                                                           x-
                 NKSKRKP     aÉíÉêãáå~íáçå=çÑ=íÜÉ=ÇáêÉÅíáçå~ä=                             -----
                                                                                                  J 31
                             e                                                          
                 ÅçëáåÉë= a =çÑ=ÉäÉãÉåí=É                                                  y
                                                                                            ------ = J 32   at    = 1
                                                                                           
                                                                                                    J 33
                                                          e
                    The directional cosines a are only required for                        z-
                                                                                            -----
                                                                         3                 
                 mapping 2D and 1D discrete feature elements in the R
                 space. If we commonly assume that the 3D continuum
                 domain  with its boundary  is completely filled
                 by 3D finite elements (e.g., hexahedral or pentahedral
                 isoparametric elements), the 2D fracture and 1D chan-
                 nel elements share the nodal points of the 3D mesh and
                 their geometric extents are aligned to surfaces, edges or
                 diagonals of the 3D matrix elements (Fig. 1.8).
PM=ö=cbcilt
                                                                                                      NKS=cáåáíÉ=bäÉãÉåí=cçêãìä~íáçåë
                                             y                                       y 
                  z 
                               u2
                                                                                                           x 
                                       u1            x 
                                                                                        u2
                                                                                                 u1
z 
z 
u1 u1
y 
Figure 1.8 Exemplified mapping of 2D fracture elements and 1D channel elements aligned to surfaces, edges and diago-
nals, respectively, for a 3D finite matrix element. Local and global coordinates.
   «aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã                                                                                          cbcilt=ö=PN
aáëÅêÉíÉ= ÑÉ~íìêÉ= ãçÇÉäáåÖ= çÑ= ÑäçïI= ã~ëë= ~åÇ= ÜÉ~í= íê~åëéçêí= éêçÅÉëëÉë= Äó= ìëáåÖ
cbcilt
                                                                                                         Notice, for 2D feature elements (fracs) we need
                                       x
                                       ------                                                        only two directional vectors (i = 1,2), the remaining
                                            J 21                                                                         e
                                                                                                      directional cosines a 3j are meaningless.
                                       y = J                      at         = 1
                                       ------   22
                                       
                                              J                                                          Often we can assume that the 2D feature elements
                                         z      23
                                       ------                                                        are perfectly flat, i.e., they represent noncurved 2D
                                       
                                                                                                     geometries which occur for arbitrarily oriented linear
                                       x-                                                           triangles or for vertical linear quadrilaterals in the 3D
                                       -----
                                              J 31                                                 space. Instead of using the above shape-derived expres-
                                       y                                                            sions (1-119) and (1-120), in such cases it is convenient
                          u2 =         ------ = J 32               at         = 1        (1-120)
                                                                                                   to derive the directional vectors u i in a direct manner
                                       z-      J 33                                                 (see Fig. 1.9).
                                       -----
                                       
                                                                                                        We specify the x -axis along the edge nm of the 2D
                                       x-
                                       -----                                                         feature element. The vector u 1 is accordingly given by
                                              J 11
                               
                                       y
                                        ------ = J 12               at         = 1
                                                                                                                                 xn – xm
                                                J 13                                                                    u1 = yn – ym                    (1-123)
                                       z-
                                        -----
                                                                                                                                  zn – zm
= 1
                                1                       0                         0                                                xl – xm
                           e1 = 0                  e2 = 1                    e3 = 0         (1-122)
                                                                                                                         q = yl – ym                    (1-124b)
                                0                       0                         1
                                                                                                                                   zl – zm
PO=ö=cbcilt
                                                                                                                                  NKS=cáåáíÉ=bäÉãÉåí=cçêãìä~íáçåë
                                                                                                                                  k
                z                     l
                                                                   n
                                                                                                     l
                         y
           z                                                               z
                            u2
                                           x                                                                                      n
                                          y
                        m        u1                                              y
                                                                                                                         x
                                                                                                                u1
                                                                                              u2
                                                                                                          m
                                                    x
       Figure 1.9 Directional vectors u i (i = 1,2) for a linear triangular element and a vertically-oriented linear quad-
       rilateral element.
                                 e                                                                         
                                                                                                         xn – xm
and the directional cosines a ij (i = 1,2; j = 1,2,3) can be                                                              x
easily computed by using (1-121).                                                      u1 = yn – ym                     = y
                                                                                                           
                                                                                                                          z                  (1-125a)
                                                                                             zn – zm       
    For 1D channel elements         the same procedure                                                     
                               e
can be applied to determine a ij (for i = 1; j = 1,2,3).                               u 1 = x + y + z 
                                                                                                 2   2   2
                        e
Here, only one row a 1j of the rotation matrix is of
interest. Taking into consideration that 1D feature ele-
                                                                                                                x
                                                                                      a 11 = -------------------------------------------- 
                                                                                        e
ments can be rather arbitrarily placed at mesh nodes
                                                                                                        2               2              2
(which are not necessarily connected in one element                                              x + y + z 
and oriented along edges) the following direct evalua-                                                                                     
                                                                                                                y
                                                                                      a 12 = -------------------------------------------- 
                                                                                        e
                                         e
tion procedure can be used to compute a 1j for a 1D lin-                                                2               2              2
                                                                                                                                               (1-125b)
ear channel element spanning between the two nodes n                                             x + y + z 
                                                                                                                                           
                                                                                                                z
                                                                                      a 13 = -------------------------------------------- 
and m (cf. Fig. 1.8):                                                                   e
                                                                                                        2               2              2
                                                                                                 x + y + z 
    «aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã                                                                                                                       cbcilt=ö=PP
aáëÅêÉíÉ= ÑÉ~íìêÉ= ãçÇÉäáåÖ= çÑ= ÑäçïI= ã~ëë= ~åÇ= ÜÉ~í= íê~åëéçêí= éêçÅÉëëÉë= Äó= ìëáåÖ
cbcilt
                 NKSKRKQ          aÉãçåëíê~íáîÉ=Éñ~ãéäÉ
                                                                                  )                        x        y        z
                                                                             =2                   Node
                                                                        (e                               [unit]   [unit]   [unit]
                                                                   ment
                                                           e   ele
                                                        tur                                   5    1       1.      1.       0.
                                                    frac
                                              2   D
                                                                                                   2      11.      1.       0.
                                                                                          )
                                                                                      =3
                                                                                                   3       7.      11.      0.
                                  4
                                                                                      (e
                                                                                                   4       1.      1.       7.
                                                                                    ent
                                                                                  em
                                      3D matrix element (e = 1)                                    5      11.      1.       9.
                                                                              l el
                                                                             ne
                                                                                                   6       7.      11.      11.
                                                                         han
                                                                     3
                                                                         c
                                                                      1D
                      z
                              y
                                  1                                     2
                                x
                          Figure 1.10 3D prismatic matrix element connected with a 2D fracture element on the top surface and a 1D
                          channel element through a diagonal.
PQ=ö=cbcilt
                                                                                                                                       NKS=cáåáíÉ=bäÉãÉåí=cçêãìä~íáçåë
                   ·
                 O+K–F = 0                                                                          
                                               T1      1   1       T2              2         2                T3          3   3
                                       O =  T   O  T   +  T   O  T   +  T   O  T   
                                                                                                                                               (1-126)
                                              T1      1  1         T2     2   2         T3     3   3
                                       K =  T   K  T   +  T   K  T   +  T   K  T   
                                                                                                        
                                              T1    1      T2      2      T3
                                       F =  T  F  +  T  F  +  T  F 
                                                                                3                       
For the 3D triangular prism (e = 1) it is assumed that                  for coordinate transformation into the x – y – z -coor-
the elemental material properties can be specified in                   dinates. Accordingly,
the global coordinates ( x – y – z ). Here, there is no need
                                         1 00 
                     1        T1         0 10                  1     1                   1                1            1           1
                   T = T           =                        O = O                     K = K                         F = F                    (1-127)
                                         0 01
                                         
                                                                                                   10 
                                                                                                          
                                                                      6 10 4                       0 
                         10             6                   6                                                      10   – 0.5385
                                                                                                     2 
                                                                      ------------------------------------
              u1 =        0        q = 10            u 2 = 10 –                                                      0 =    10                  (1-128)
                                                                                                          
                          2             4                   4                                      10              2    2.6923
                                                                      10 0 2  0 
                                                                                                          
                                                                                                    2 
                                                                   
                                                                   
                                                                   
                                                                   
                                                                   
                                                                   
                                                                   
                                                                   
                                                                   
t = 0.6538
    «aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã                                                                                                                          cbcilt=ö=PR
aáëÅêÉíÉ= ÑÉ~íìêÉ= ãçÇÉäáåÖ= çÑ= ÑäçïI= ã~ëë= ~åÇ= ÜÉ~í= íê~åëéçêí= éêçÅÉëëÉë= Äó= ìëáåÖ
cbcilt
                                                                                          0.9806     0   0.1961 
                                                 0.9806     0   0.1961
                                             2                                  2        – 0.0519 0.9843 0.2596
                                            a = – 0.0519 0.9843 0.2596          T =                                                 (1-129)
                                                                                             .       .      .
                                                    .       .      .
                                                                                            
                                         
                                                                                                                        
                                                                 2      2                                               
                                          0.9806 – 0.0519 .   O xx O xy 0                 0.9806     0   0.1961  
                                                                                                                        
                                              0    0.9843 .        2      2
                                                                O yx O yy 0                 – 0.0519 0.9843 0.2596       if anisotropic
                       T2     2   2      
                     T   O  T   =  0.1961 0.2596 .                                          .       .      .     
                                                                 0      0 0                                             
                                                                                                                      
                                                                                                                       
                                         
                                          O2    if isotropic
                                         
                                                                                                                                    (1-130)
                                   T2        2    2
                 similar for  T          K  T  
                                        
                                                                          2
                                                                         F x
                                         0.9806 – 0.0519 . 
                                            0    0.9843 .                 2
                              T2   2                                    F y         if directional
                            T  F  =  0.1961 0.2596 .
                                                                        0
                                           
                                                                        
                                         2
                                        F      if scalar
                                                                                                         4
                 Taking the u 1 -vector for the 1D channel element                               u 1 = – 10     u 1 = 14.036         (1-131)
                 (e = 3)
                                                                                                         9
PS=ö=cbcilt
                                                                                                    NKS=cáåáíÉ=bäÉãÉåí=cçêãìä~íáçåë
we obtain
                                                                                              
                                             O3 0 0 
                            0.2850  . .      xx
                                                                      0.2850 – 0.7125 0.6412  
                          – 0.7125 . .                                 .       .       .      
       T3     3   3                           0 0 0                                                if anisotropic
     T   O  T   =  0.6412 . .                                   .       .       .      
                                                0 0 0
                                                                                              
                                                                     
                                                                                               
                         
                          3
                         O       if isotropic
                  T3        3    3                                                                                     (1-133)
similar for  T          K  T  
                        
                                                         3
                         0.2850 . .                   F x
                         – 0.7125 . .
              T3   3                                   0      if directional
            T  F  =  0.6412 . .
                                                        0
                        
                                                      
                        
                         3
                        F       if scalar
     «aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã                                                                                             cbcilt=ö=PT
aáëÅêÉíÉ= ÑÉ~íìêÉ= ãçÇÉäáåÖ= çÑ= ÑäçïI= ã~ëë= ~åÇ= ÜÉ~í= íê~åëéçêí= éêçÅÉëëÉë= Äó= ìëáåÖ
cbcilt
                 oÉÑÉêÉåÅÉë                                                              ^ééÉåÇáñ=^
                 1. Chandhry, M. H. & M. E. Barber, Open channel flow. In: The           kçãÉåÅä~íìêÉ
                     handbook of fluid dynamics (ed. by R. W. Johnson), CRC Press/
                     Springer, Chapter 45, 1998.
                 2. Diersch, H.-J. G., FEFLOW - Reference Manual. WASY Ltd.,             In the above the symbols have the following meaning:
                     Berlin, 2002.
                 3. Diersch, H.-J. G., Modeling and numerical simulation of geohy-       Latin symbols
                     drodynamic transport processes (in German). Reprint, WASY
                     Ltd. Berlin, 1991.                                                                                     2
                                                                                           A         =        flow area,  L  ;
                 4. Diersch, H.-J., Finite element modelling of recirculating density-
                     driven saltwater intrusion processes in groundwater, Advances in      a         =        coefficient to specify boundary
                     Water Resources 11 (1988) 1, 25-43.                                                      conditions;
                 5. Diersch, H.-J. G. & O. Kolditz, Coupled groundwater flow and           a         =        rotation matrix;
                     transport: 2. Thermohaline and 3D convection systems, Advances        B         =        thickness or depth,  L  ;
                     in Water Resources 21 (1998) 5, 401-425.
                                                                                           b         =        aperture or surface elevation,  L  ;
                 6. Diersch, H.-J. G. & P. Perrochet, On the primary variable switch-
                     ing technique for simulating unsaturated-saturated flows,             b         =        coefficient to specify boundary
                     Advances in Warer Resources 23 (1999) 3, 271-301.                                        conditions;
                                                                                                                                     –3
                 7. Gottardi, G. & M. Venutelli, LANDFLOW: Computer program                C         =        concentration,  ML  ;
                     for the numerical simulation of two-dimensional overland flow.        C         =        Chezy       roughness       coefficient,
                     Computers & Geosciences 23 (1997)1, 77-89.                                                  1  2 –1
                                                                                                              L T  ;
                 8. Gray, W.G., Derivation of vertically averaged equations describ-        f    s
                     ing multiphase flow in porous media. Water Resources Research         cc       =        specific heat capacity of fluid and
                                                                                                                                        2 –2 –1
                     18 (1982)6, 1705-1712.                                                                   solid, respectively,  L T   ;
                 9. Di Giammarco, P., E. Todini & P. Lamberti, A conservative finite       D         =        space dimension, (1, 2 or 3);
                     elements approach to overland flow: the control volume finite         D         =        tensor of hydrodynamic dispersion,
                     element formulation. Institute for Hydraulic Construction, Univ.                            2 –1
                                                                                                              L T  ;
                     Bologna, Italy.                                                                                                     2 –1
                 10. Panton, R. L., Incompressible flow. 2nd Edition, J. Wiley & Sons,
                                                                                           Dd        =        molecular diffusion,  L T  ;
                     New York, 1996.                                                       Dm        =        tensor of mechanical dispersion,
                                                                                                                 2 –1
                 11. Taylor, G., Dispersion of solute matter in solvent flowing slowly                        L T  ;
                                                                                                                                              –1
                     through a tube. Proc. R. Soc. London A, 219 (1953), 186-203.          d         =        strain-rate tensor of fluid,  T  ;
                                                                                           E         =        internal (thermal) energy density,
                                                                                                                 2 –2
                                                                                                              L T  ;
                                                                                           e         =        gravitational unit vector,  1  ;
                                                                                           ei        =        basis vectors,  1  ;
                                                                                           F         =        material surface;
                                                                                           f         =        specific     rate      of    temporary
                                                                                                              production;
PU=ö=cbcilt
                                                                                            NKS=cáåáíÉ=bäÉãÉåí=cçêãìä~íáçåë
     «aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã                                                                                        cbcilt=ö=PV
aáëÅêÉíÉ= ÑÉ~íìêÉ= ãçÇÉäáåÖ= çÑ= ÑäçïI= ã~ëë= ~åÇ= ÜÉ~í= íê~åëéçêí= éêçÅÉëëÉë= Äó= ìëáåÖ
cbcilt
                   t n            =   time step length at time plane n,                         =   generalized friction factor;
                                       T ;                                                     =   Newton-Taylor              roughness
                                 =   total boundary;                                                coefficient,  1  ;
                                                                         2
                   S              =   projected area of surface,  L  ;                        =   pressure head or local water depth,
                                                                3                                     L ;
                   V              =   volume of REV,  L  ;
                                  =   porosity (= volume fraction of fluid            C       =   sorption function,  1  ;
                                       phase),  1  ;                                           =   balance quantity;
                                  =    – 1    1  , local coordinate,  1  ;               =   domain;
                                  =    – 1    1  , local coordinate,                       =   azimuthal angle,    ;
                                       1 ;                                                                                       –1
                                                                                                 =   Nabla (vector) operator,  L  ;
                                  =   local coordinate vector,  1  ;
                                  =     –  o    o , density ratio or          Subscripts
                                       buoyancy coefficient,  1  ;
                                  =   weighting coefficient,  0    1  ;          corr           corrected;
                                                                   –1
                                  =   chemical decay rate,  T  ;                    e              elemental;
                                  =   coefficient of skeleton compressibi-            n              time plane;
                                                –1
                                       lity,  L  ;
                                                                                       i j k        nodal or spatial indices;
                                  =   tensor of thermal hydrodynamic
                                                             –3 –1                     o              reference value;
                                       dispersion,  MLT   ;
                    f      s
                                =   thermal conductivity for fluid and
                                                                      –3 –1
                                       solid, respectively,  MLT   ;              Superscripts
                     o          =   dynamic viscosity and reference
                                       dynamic          viscosity   of     fluid,                    phase index;
                                                              –1 –1
                                       respectively,  ML T  ;                        D              space dimension;
                                  =    – 1    1  , local coordinate,  1  ;     e              elemental;
                     o          =   fluid density and reference fluid               f              fluid (water) phase;
                                                                       –3
                                       density, respectively,  ML  ;                 n              time plane;
                                  =   viscous stress tensor of fluid,                 s              solid phase;
                                             –1 –2
                                        ML T  ;
                                                                                       T              transpose of a matrix;
                   '              =   deviatory stress tensor of fluid,
                                             –1 –2                                                   surface index;
                                        ML T  ;
                       bottom
                                      shear stress at bottom surface,
                                             –2 –2
                                        ML T  ;
                       interface                                         –2 –2
                                      interfacial shear stress,  ML T  ;
                     top
                                  =   shear stress at top surface,
                                             –2 –2
                                        ML T  ;
QM=ö=cbcilt
                                                                                                                              NKS=cáåáíÉ=bäÉãÉåí=cçêãìä~íáçåë
^ééÉåÇáñ=_
                                                                            Furthermore, we have for the element, cf. (1-100),
^å~äóíáÅ=Éî~äì~íáçå=çÑ=ã~íêáñ= ÉäÉãÉåíë
                                                                                                   x = N1 x 1  + N2 x 2                              (B3)
ENJUUF=Ñçê=~=Na=ÅÜ~ååÉä=ÉäÉãÉåí
We consider the following linear 2-node element e and with and (B4)
                                                                                             x       N 1                N 2                x e
                                                                                  J = J 11 = ------ = --------- x  1  + --------- x  2  = --------   (B4)
        Ni                                                       1                                                                         2
                                                                            and
                        N1                           N2
                                                                                                         –1       1          2
                                                                                                     J        = ------- = --------                       (B5)
                                                                                                                  J       x e
                               N
                               ---------1 = – 1---
                                             2
                                                                     (B2)
                               N 2         1
                               --------- = ---
                                          2
    «aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã                                                                                                                             cbcilt=ö=QN
aáëÅêÉíÉ= ÑÉ~íìêÉ= ãçÇÉäáåÖ= çÑ= ÑäçïI= ã~ëë= ~åÇ= ÜÉ~í= íê~åëéçêí= éêçÅÉëëÉë= Äó= ìëáåÖ
cbcilt
                                                                                              1                                          e
                                                             N1 N1 N1 N2          e             2       2 x            S x e
                                                                         d = -----   1 –    1 –   -------- d = -------------- 2 1
                                 e                   e                        S                                  e
                             O =                S
                                                             N2 N1 N2 N2       4              2            2 2                6 12
                                                                                                                                                        (B8)
                                         e                                         –1  1 –    1 +  
                             e           e               e         e     e
                            K = K1 + K2 + K3 + K4
                                                                                                     1
                                                     N 1 N 1 N 1 N 2    e                             x e              e
                                                              d = ------------  –  1 –    1 –   -------- d = ----- – 1 1
                             e                e                        q                                              q
                            K1   =       q
                                            N 2 N 1 N 2 N 2      2x e –  1 +    1 +   2                       2 –1 1
                                     e                                                             –1
                                                                                                         1
                                                     N 1 N 1 N 1 N 2
                                                                      D
                                                                           e            x e           D
                                                                                                            e
                                                                d = --------2-  1 – 1 -------- d = -------- 1 – 1
                             e                   e
                            K2   =       D
                                            N 2 N 1 N 2 N 2      x e – 1 1 2                     x e – 1 1
                                     e                                                                  –1                                             (B9)
                                                                                              1                                          e
                                                         N1 N1 N1 N2                      e 2       2 x              x e
                                                                          
                                                                     d = ------   1 –    1 –   -------- d = ---------------- 2 1
                             e                   e                                                            e
                            K3 =                       N2 N1 N2 N2        4             2            2  2                 6         1 2
                                     e                                         –1  1 –    1 +  
                                                                          = 1 = – 1
                                                                                              e               2          2
                                              N1 N1 N1 N2                                 a  1 – 1   1 – 1 
                                                                                                                        = a 1 0
                             e        e                                                                                    e
                            K4 = a                                                      = -----
                                              N2 N1 N2 N2                                  4           2              2      0 1
                                                                                                 1 – 2   1 + 2 
                                                                          = 2 = 1
                                 e               e            e
                             F = F1 + F2
                                                                                1                                 e
                                                              N1           e             x e          Q x e
                                                                 d = ------   1 –   -------- d = --------------- 1
                                 e                       e            Q
                             F1 =                Q
                                                              N2        2      1 +  2                     2         1
                                          e                                    –1                                                                     (B10)
                                                                              = 1 = –1
                                                                                                    e         e
                                                                       N1                        a 2 – b  1 – 1
                                                                                                                                    =  a 2 – b  1
                                 e               e                 e                                                                     e      e
                             F2 =  a 2 – b                                                 = ----------------------------
                                                                       N2                                    2               1 + 2                1
                                                                              = 2 = 1
QO=ö=cbcilt
                                                                                                                            NKS=cáåáíÉ=bäÉãÉåí=cçêãìä~íáçåë
                      e                 · e                                 e                            e
                  S x e 2 1   1   q e – 1 1       D
                                                             e            x e 2 1                        
                                                                                                 e 1 0   1
                                                                1  – 1
                -------------
                         6
                               -        +  -----
                                 1 2     e    2
                                         ·   –1 1
                                                     + --------
                                                       x     e –1 1
                                                                       + ----------------
                                                                                6         1 2
                                                                                              +a         –
                                                                                                   0 1   e 
              e
                                        2                                                                2                                   (B11)
                                              e
                                            Q x e                              
                                          – --------------- 1 –  a  2 – b  1  =  0 
                                                                   e       e
                                                   2        1                 1
^ééÉåÇáñ=`
                                                                                            y
aÉêáî~íáçå= çÑ= íÜÉ= çêíÜçÖçå~ä= ÇáêÉÅJ                                                                       l
íáçå~ä=îÉÅíçêë= u i =Ñçê=~=Oa=ÛÑä~íÛ=ÉäÉãÉåí                                                                                       n
                                                                                                                                            x
                                                                                                 u2
                                                                                                          q           q–v      p
                                                                                                                                   u1
   For a linear 2D ’flat’ element we can find the fol-
                                                                             z
lowing vectors for a typical element with the nodes                                    y                          v
mnl  k  :                                                                                           m
                                                                                       x
                   xn – xm               xl – xm
       p  u1 = yn – ym            q = yl – ym               (C1)     the parameter t can be easily found if inserting (C3)
                   zn – zm                zl – zm                     into (C2)
                                                                                             q – tp   p = 0 
Since the vector u 2  q – v is perpendicular to the vec-                                                               
                                                                                                             qp                                 (C4)
tor p  u 1 the dot product yields                                                                       t = ---------- 
                                                                                                             pp
                    q – v  p = 0                          (C2)
                                                                      As a result, we get
Using the parametric description of the vector v as
                                                                                                         qp
                                                                                                  v =  ---------- p                           (C5)
                        v = tp                               (C3)                                        pp
    «aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã                                                                                                                      cbcilt=ö=QP
aáëÅêÉíÉ= ÑÉ~íìêÉ= ãçÇÉäáåÖ= çÑ= ÑäçïI= ã~ëë= ~åÇ= ÜÉ~í= íê~åëéçêí= éêçÅÉëëÉë= Äó= ìëáåÖ
cbcilt
                 and finally (with p  u 1 )                                                              On the other hand, the friction laws for the Hagen-
                                                                                                      Poiseuille flow in form of Eq. (1-56) and for the Man-
                                                    qp                                              ning-Strickler flow in form of Eq. (1-67) (with Table
                               u 2  q – v = q –  ---------- p                                   1.4) are specified by the hydraulic aperture b and the
                                                    pp                     
                                                                                              (C6)   friction parameter M , respectively (cf. Table 1.9).
                                                      q      u
                                         u 2 = q –  ---------------- u 1 
                                                                  1
                                                    u 1  u 1                                              Table 1.9 Frictional input parameter
                                                                            
                                                                                                                 Law                       Parameter
                     In FEFLOW a reduced data set is used to input the                                 Table 1.10 Implemented standard hydraulic radii
                 geometric relationships of the fractures. There is no
                 direct input of the hydraulic radii r hydr for the different                                                           r hydr
                 types of fracture elements applied to both the Hagen-
                 Poiseuille and the Manning-Strickler law of fluid                                        Dimension      expressed by appropriate input
                 motion. Instead, the geometry of the cross-sections is                                   of fracture             parameters
                 input by the flow area A for 1D elements and by the                                       elements
                 thickness/flow depth B for 2D fracture elements (see                                                       Hagen-               Manning-
                 Table 1.8).                                                                                               Poiseuille            Strickler
QQ=ö=cbcilt
                                                                                                                          NKS=cáåáíÉ=bäÉãÉåí=cçêãìä~íáçåë
                                                                                  3              –3                               –3
                                                                        o = 10 kg m ,                o = 1.3  10 Pa s ,    and
                                                                                        –2
    As seen from Table 1.10 the input parameter in form                g = 9.81 ms .           It     results      a   factor  of
                                                                                                    6 –1 –1
of the hydraulic aperture b for the Hagen-Poiseuille                   f o =  o g   o = 7.55  10 m s . A hydraulic radius
law and the geometric input parameter in form of the                   which is different from the standard geometry, and
flow area A or thickness B for the Manning-Strickler                   parameters, which are different from the standard
law are used to express r hydr internally in FEFLOW.                   parameter factor f o , can be derived from the identity
Accordingly, FEFLOW assumes that in the case of
using a Hagen-Poiseuille law a submerged slit geome-                               2                  2
                                                                                  r hydr          b-                                g
try is standard (both in 1D and 2D). In case of the Man-                          ----------- f = ----- f          with         f = ------            (D2)
                                                                                      a           12 o                                
ning-.Strickler law a submerged quadratic cross section
         2
( A = B ) is considered the standard geometry in 1D
                                                                       A corrected hydraulic aperture b corr can be obtained
and a submerged slit plane geometry is standard in 2D.
                                                                       from (D2) as
The question arises how is it possible to differ from the
standard geometry types? For example, instead of a
                                                                                            2 3                     3    for plane geometry
quadratic cross-section for a 1D fracture element, a                   b corr =       ---f- ---------- r hydr   a =                                  (D3)
rectangular plane or an axisymmetric geometry is to be                                fo a                          2    for axisymmetric geometry
used.
                                                                       where r hydr is the actual (true) hydraulic radius, which
    To specify hydraulic radii r hydr which are different              can be taken from Table 1.3, and f is the true parameter
to the embodied standard geometries (Table 1.10) one                   factor, where dynamic viscosity, gravity and density
can input corrections in the hydraulic aperture b for                  can be specified different from the standard settings in
the Hagen-Poiseuille law and in the Manning rough-                     f o . Table 1.11 summarizes the corrected hydraulic
ness coefficient M for the Manning-Strickler law.                      apertures b corr for interesting applications.
These corrected parameters can be derived in the fol-
lowing manner.
                        2
                 r hydr  o g              b o g
                                              2
             K = ----------- --------- I = ------ --------- I   (D1)
                     a o                  12  o
    «aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã                                                                                                                          cbcilt=ö=QR
aáëÅêÉíÉ= ÑÉ~íìêÉ= ãçÇÉäáåÖ= çÑ= ÑäçïI= ã~ëë= ~åÇ= ÜÉ~í= íê~åëéçêí= éêçÅÉëëÉë= Äó= ìëáåÖ
cbcilt
                   Table 1.11 Corrected apertures b corr for different                                       On the other hand, the standard hydraulic conduc-
                  applications in the case of Hagen-Poiseuille law for                                   tivity K for the Manning-Strickler law is according to
                            1D and 2D fracture elements a)                                               Eq. (1-67) with Tables 1.4 and 1.10:
QS=ö=cbcilt
                                                                                                                 NKS=cáåáíÉ=bäÉãÉåí=cçêãìä~íáçåë
   Table 1.12 Corrected Manning roughness                                        Table 1.13 Corrected Manning roughness
coefficient Mcorr for different applications in the                           coefficient M corr for different applications in the
 case of Manning-Strickler law for 1D fracture                                 case of Manning-Strickler law for 2D fracture
                    elements                                                                       elements
«aef=ö=ïïïKãáâÉéçïÉêÉÇÄóÇÜáKÅçã cbcilt=ö=QT