Rates of Reaction
Rates of Reaction
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Explanation:
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Compared to a reaction with a reactant at a low concentration, the graph line for the same reaction but
at a higher concentration/pressure has a steeper gradient at the start and becomes horizontal sooner
This shows that with increased concentration of a solution or increased pressure of a gas, the rate of Your notes
reaction will increase
The effect of surface area
Graph showing the effect of increased surface area on the rate of reaction
Explanation:
Compared to a reaction with lumps of reactant, the graph line for the same reaction but with powdered
reactant has a steeper gradient at the start and becomes horizontal sooner
This shows that with increased surface area of the solid, the rate of reaction will increase
The effect of temperature
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Your notes
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Your notes
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Increasing the number of successful collisions means that a greater proportion of reactant particles
collide to form product molecules
The number of successful collisions depends on: Your notes
The number of particles per unit volume - more particles in a given volume will produce more
frequent successful collisions
The frequency of collisions - a greater number of collisions per second will give a greater number
of successful collisions per second
The kinetic energy of the particles - greater kinetic energy means a greater proportion of
collisions will have an energy that exceeds the activation energy and the more frequent the
collisions will be as the particles are moving quicker, therefore, more collisions will be successful
The activation energy - fewer collisions will have an energy that exceeds higher activation energy
and fewer collisions will be successful
These all have an impact on the rate of reaction which is dependent on the number of successful
collisions per unit of time
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Diagram showing the increased kinetic energy that particles have at higher temperatures
Concentration
Increasing the concentration of a solution will increase the rate of reaction
This is because there will be more reactant particles in a given volume, allowing more frequent and
successful collisions per second, increasing the rate of reaction
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For a gaseous reaction, increasing the pressure has the same effect as the same number of
particles will occupy a smaller space, increasing the concentration
If you double the number of particles you will double the number of collisions per second Your notes
The number of collisions is proportional to the number of particles present
Surface Area
Increasing the surface area of a solid will increase the rate of reaction
This is because more surface area of the particles will be exposed to the other reactant, producing a
higher number of collisions per second
If you double the surface area you will double the number of collisions per second
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Your notes
Catalysts
Catalysts are substances which speed up the rate of a reaction without themselves
being altered or consumed in the reaction
The mass of a catalyst at the beginning and end of a reaction is the same and they do not form part of
the equation
Different processes require different types of catalysts but they all work on the same principle of
providing a different pathway for the reaction to occur that has a lower activation energy
This means a higher proportion of the reactant particles have energy greater than the activation energy
and will result in more successful collisions per second
An important industrial example is iron, which is used to catalyse the Haber Process for the production
of ammonia
Iron beads are used to increase the surface area available for catalysis
Enzymes are biological catalysts, they work best at specific temperature and pH ranges
Normally only small amounts of catalysts are needed to have an effect on a reaction
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Your notes
A catalyst lowers the activation energy of a reaction by providing an alternative reaction pathway
Exam Tip
When answering questions on the effect of concentration on the rate of reaction, you should mention
that there are more particles per unit volume (usually cm3) and this causes an increase in the rate of
collisions.
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Your notes
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Your notes
Diagram showing the process of downwards displacement to investigate the effect of the surface area
of a solid on the rate of reaction
Method:
Add dilute hydrochloric acid into a conical flask
Use a delivery tube to connect this flask to a measuring cylinder upside down in a bucket of water
(downwards displacement)
Add calcium carbonate chips into the conical flask and quickly put the bung back into the flask
Measure the volume of gas produced in a fixed time using the measuring cylinder
Repeat with different sizes of calcium carbonate chips (lumps, crushed and powdered)
Result:
Smaller sizes of chips cause an increase in the surface area of the solid, so the rate of reaction will
increase
This is because more surface area of the particles will be exposed to the other reactant so there will be
more frequent and successful collisions, increasing the rate of reaction
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Your notes
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Your notes
Diagram showing the apparatus needed to investigate the effect of concentration on the rate of
reaction
Method:
Measure 50 cm3 of sodium thiosulfate solution into a flask
Measure 5 cm3 of dilute hydrochloric acid into a measuring cylinder
Draw a cross on a piece of paper and put it underneath the flask
Add the acid into the flask and immediately start the stopwatch
Look down at the cross from above and stop the stopwatch when the cross can no longer be seen
Repeat using different concentrations of sodium thiosulfate solution (mix different volumes of sodium
thiosulfate solution with water to dilute it)
Result:
With an increase in the concentration of a solution, the rate of reaction will increase
This is because there will be more reactant particles in a given volume, allowing more frequent and
successful collisions, increasing the rate of reaction
Effect of temperature on the rate of reaction:
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Your notes
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Your notes
Diagram showing the apparatus needed to investigate the effect of temperature on the rate of reaction
Method:
Dilute hydrochloric acid is heated to a set temperature using a water bath
Add the dilute hydrochloric acid into a conical flask
Add a strip of magnesium and start the stopwatch
Stop the time when the magnesium fully reacts and disappears
Repeat at different temperatures and compare results
Result:
With an increase in the temperature, the rate of reaction will increase
This is because the particles will have more kinetic energy than the required activation energy,
therefore more frequent and successful collisions will occur, increasing the rate of reaction
Effect of a catalyst on the rate of reaction:
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Your notes
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Your notes
Diagram showing the apparatus needed to investigate the effect of a catalyst on the rate of reaction
Method:
Add hydrogen peroxide into a conical flask
Use a delivery tube to connect this flask to a measuring cylinder upside down in a tub of water
(downwards displacement)
Add the catalyst manganese(IV) oxide into the conical flask and quickly place the bung into the flask
Measure the volume of gas produced in a fixed time using the measuring cylinder
Repeat experiment without the catalyst of manganese(IV) oxide and compare results
Result:
Using a catalyst will increase the rate of reaction
The catalyst will provide an alternative pathway requiring lower activation energy so more colliding
particles will have the necessary activation energy to react
This will allow more frequent and successful collisions, increasing the rate of reaction
Monitoring changes in mass
Many reactions involve the production of a gas which will be released during the reaction
The gas can be collected and the volume of gas monitored as per some methods above
Alternatively, the reaction can be performed in an open flask on a balance to measure the loss in mass
of reactant
Cotton wool is usually placed in the mouth of the flask which allows gas out but prevents any materials
from being ejected from the flask (if the reaction is vigorous)
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Your notes
Diagram showing the set-up for measuring the rate of reaction by loss in mass
This method is not suitable for hydrogen and other gases with a small relative formula mass, Mr as the
loss in mass may be too small to measure
Exam Tip
There are many different methods of investigating the rate of reaction. Another method of gas
collection you may see uses a gas syringe.
Those students taking the extended course may be required to devise and evaluate methods of
investigating rates of reaction.
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The steeper the curve, the faster the rate of the reaction
The curve is steepest initially so the rate is quickest at the beginning of the reaction
As the reaction progresses, the concentration of the reactants decreases and the rate decreases Your notes
shown by the curve becoming less steep
When one of the reactants is used up, the reaction stops, the rate becomes zero and the curve levels
off to a horizontal line
The amount of product formed in a reaction is determined by the limiting reactant:
If the amount of limiting reactant increases, the amount of product formed increases
If the amount of the reactant in excess increases, the amount of product remains the same
Drawing a tangent to the slope allows you to show the gradient at any point on the curve
The steeper the slope, the quicker the rate of reaction
The volume of a gaseous product would increase to a maximum over time, so the line levels out
indicating the reaction is over
Since the volume and mass would be proportional, this could also be a graph of the mass of product
versus time
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Worked example
Your notes
0.2 g of manganese(IV) oxide was added to 25 cm3 of 0.1 mol/dm3 hydrogen peroxide solution. The
volume of oxygen produced every minute was recorded and the results are shown on the graph.
The experiment was repeated using the same mass of manganese(IV) oxide and at the same
temperature but using 25 cm3 of 0.2 mol/dm3 of hydrogen peroxide solution.
Sketch the curve for the results of this experiment on the same grid.
Answer
Step 1 - Deduce how the initial gradient will be different from the original graph
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The hydrogen peroxide solution is twice as concentrated so the rate of reaction will be greater and
the initial gradient will be steeper
Your notes
Step 2 - Deduce how much product will be formed compared to the original experiment
The amount of hydrogen peroxide determines the amount of oxygen produced. In the 2nd
experiment, there are twice as many hydrogen peroxide molecules in the same volume so the
amount of oxygen gas produced will be doubled
Step 3 - Sketch the graph
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Worked example
Your notes
Iodine and methanoic acid react in aqueous solution.
I2 (aq) + HCOOH (aq) → 2I− (aq) + 2H+ (aq) + CO2 (g)
The rate of reaction can be found by measuring the volume of carbon dioxide produced per unit time
and plotting a graph as shown:
Answer:
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Your notes
Exam Tip
If the amount of reactant used up is being monitored, then the graph will fall with the steepest gradient
at the start, becoming less steep until it levels off to a horizontal line.
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