Alternating Current 60Q
Alternating Current 60Q
Topics Covered :
Section A:
Alternating Current
Section A
1. The primary and secondary coils of an ideal 4. A pure inductor of 50.0 mH is connected to
transformer have 100 and 500 turns an ac source of 220 V. If the frequency of the
respectively. The magnetic flux linking the source is 50 Hz. Then r.m.s current in the
primary coil is given by ϕ = 40t + 5. The circuit is nearly
output voltage across the secondary coil is (A) 28 A
(all the quantities are in SI units)
(B) 14 A
(A) 2000 V
(C) 12 A
(B) 400 V
(D) 24 A
(C) 200 V
(D) 100 V
5. In a series L-C-R circuit, voltage across
resistor, capacitor and inductor is 20 V each.
2. The average value of the current in given I-t If capacitor is short circuited the voltage
graph, between 0 to T, is across inductor is
(A) 10√– 2V
–
(B) 20√2V
–
(C) 5√2V
(D) 5
V
√2
(C) 500 Hz
6
, then the value of inductive reactance will
be 15. The power factor of the circuit shown in
(A) R figure is
2
(B) R
(C) 2R
(D) R
√3
π
10. In series AC circuit, if V = V0 sin(ωt + ) and
6
2π
I = I0 sin(ωt + ) then (A) 0.2
3
T
24. A transformer is used on a 2000 V input line
to deliver 20 A at 120 V at the secondary
(D) I0
2T
coil. If the power efficiency of the transformer
is 80% then the current drawn from the input
line is
20. In pure inductive circuit, current (a.c. circuit) (A) 3 A
(A) Lags behind emf by π rad
2 (B) 2 A
(B) Leads the emf by π
rad (C) 1.5 A
2
(B) 1
s (B) –
√2
50
(C) 1
s
(C) 1
100 √2
(D) 1
s (D) 1
600 2
√2
(D) All of these
(D) V0
(D) 1 : 2
32. The rms value of current is 1 A. The rms
value of potential difference between P and
Q is 36. 200
An inductance of (
π
) mH , a
−3
10
capacitance of (
π
)F and a resistance
of 10 Ω are connected in series with an ac
source 220 V, 50 Hz, The phase angle of the
circuit is
(A) π
(A) 5V 6
(B) 7V (B) π
(C) 3V (C) π
3
(D) 4V
(D) π
√
circuit? 2
√2
−−−−−−
(C) 2
b
√a2 +
2
(D) √a2 +b
2
(B)
2
(B) √5R
–1 1
, tan ( )
2 2
–
(C) √5XC , tan
–1
(2)
–
(D) √2R, tan
–1
(3)
(C)
46. If the power factor in an AC circuit changes
1 1
from 2
to 4
then by what percent
impedance will change (approximately) if
resistance remains constant?
(A) Increase by 200 %
(D) (B) Decrease by 200 %
(C) Increase by 100 %
(D) Decrease by 100 %
−
−−−
(B) 7 √–
2 V
(D) 1 2LC
√
R 3
(C) 10 V
(D) 10 √–2 V
56. A : Energy is produced when a transformer 59. The primary and secondary windings of a
steps up voltage. transformer have self inductances L1 = 6.0
R : A step-up transformer can be used as an H, L2 = 0.06 H respectively and a coefficient
amplifier. of coupling K = 0.8. If primary current
(A) Both Assertion & Reason are true and increases at the rate of 103 A/s then emf
the reason is the correct explanation of
induced in primary and secondary windings
the assertion
respectively are (there is no load connected
(B) Both Assertion & Reason are true but across the secondary)
the reason is not the correct (A) 6000 V, 60 V
explanation of the assertion
(B) 6000 V, 360 V
(C) Assertion is true statement but Reason
is false (C) 6000 V, 480 V
(D) Both Assertion and Reason are false (D) 6000 V, 48 V
statements
60. In a parallel L - C circuit as shown in the
57. A : Loads are generally inductive in AC figure
circuit in our home.
R : Capacitor can be used to improve power
factor in a circuit containing inductor and
resistor.
(A) Both Assertion & Reason are true and
the reason is the correct explanation of
the assertion
(B) Both Assertion & Reason are true but (A) Current through source i must be
the reason is not the correct greater than iL
explanation of the assertion
(B) Current through source i must be less
(C) Assertion is true statement but Reason
than iC
is false
(D) Both Assertion and Reason are false (C) iL may be greater than i
statements (D) iL must be equal to i