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Lec 1-Part-2

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0% found this document useful (0 votes)
17 views11 pages

Lec 1-Part-2

Uploaded by

Peter Safwat
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
You are on page 1/ 11

02/10/2024

BANDWIDTH DEFINITION

 Bandwidth, in general, represents a range of


frequencies

Bandwidth is 400 MHz

300 MHz 700 MHz

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USAGE OF THE TERM BANDWIDTH

To specify the • A medium such as a


communication coaxial cable is associated
capacity with a bandwidth

To indicate the • Voice grade circuits have


bandwidth of a a bandwidth of 4 KHz (0-
technology 4000 Hz)

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02/10/2024

MODULE 3:
Analog And Digital Systems
Case Study: Telephone Channel

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Analog or Digital Systems


Specify whether a system is digital or analog
by reference to the possible amplitudes of
voltage (and/or current) waveforms.

Analog Information Source produces values


defined on a continuum e.g., human voice.

Digital Information Source produces a finite


set of possible symbols e.g., computer
keyboard

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AREAS OF APPLICATION (ANALOG)

 Old telephone networks


 Most analog television broadcasting systems are turning into
digital ones.
 Radio broadcasting

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ANALOG TO DIGITAL CONVERSION

1 0 1 1 0 1 0 0

A to D Converters, Digital
Signal Processors (DSP) etc.

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DATA TRANSMISSION USING ANALOG TECHNOLOGY

Computer Modem
Digital Analog
0s and 1s 0s and 1s

Digital-to-Analog Modulation
and vice versa
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Case Study: Telephone Channel

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Telephone Transmission
A baseband voice signal where the frequency
range optimized for voice signals
300Hz 3400 Hz

Direct transmission of digital data not possible


Long sequences of 1's or 0's look like a signal with zero Frequency.
Frequency for 9600bps sequences of alternating 0's and 1's > 3400Hz.

Modulate an audio-frequency carrier signal with digital data


Carrier always above low cutoff. To get high data rates at <3400Hz,
squeeze multiple bits into a signal element.

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Baud Rate
Each signal element is a “baud” (after its inventor Baudot (1845-1903)
Number of signal elements /s is called the baud rate.

Theoretical Limitations on Transmission Rate, Nyquist Theorem:


Max Bit Rate = 2 x carrier bandwidth x log2(possible values/signal element)

no of bits encoded by a signaling element

e.g., for an 8 levels for signal element (i.e., 3 bit/signal element) in a voice
channel;
Max bit rate = 2 x 3000 x log2(8) = 18000bps

Fixed by legacy for voice grade lines and 8


technology possible values per baud

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Shannon-Hartley Law
This law takes noise into account;

Max bit rate = bandwidth x log2(1 + S/N)


Where S/N is the signal to noise ratio.
S/N for analogue PSTN with multiple exchanges is ~1000
(It depends on complexity of connection)

Max bit rate = 3000 x log2(1000) = 30000bps


33.3kbps modems reached this limit
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Why Use The Narrowest Bandwidth?


 Narrower signal bandwidth permits “packing” more
individual channels into a fixed total bandwidth.
 Engineers are usually required to build the most
economical system which meets quality requirements.
 Systems with higher quality requirements use
greater audio bandwidth:
 AM Broadcasting: 5 kHz (4.5 kHz in some countries)*
 FM Broadcasting: at least 15 kHz audio bandwidth
 Hi-Fi audio: 20 Hz lows and 20 kHz highs (Compact Disks)

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Module 4
Frequency and Time Division Multiplexing
With Case Study: DSL

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Examples Of Multiplexing Schemes:


Frequency Division Multiplexing Using Analog Carrier Systems
The standard telephony voice channel [300 – 3400 Hz] is
stacked on high frequency carriers by single sideband
amplitude modulation. This is the most bandwidth efficient
scheme possible.

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The analog voice channels are pre-grouped into threes and


heterodyned on carriers at 12, 16, and 20 kHz. The
resulting upper sidebands of four such pre-groups are then
heterodyned on carriers at 84, 96, 108, and 120 kHz to
form a 12-channel group.

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Time Division Multiplexing


Nyquist Sampling Theorem

 A band-limited waveform can be accurately reconstructed if


sampled at a rate greater than twice its bandwidth.
 Example: a 4 kHz bandwidth signal must be sampled slightly more than
8000 samples per second
 Exactly 8000 samples/sec would sample each 4000 Hz sine wave
component exactly twice per cycle.

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Digital Multiplexer Processes


 Measure the voice waveform voltage to obtain 8000 samples
per second
 Digitally encode this voltage into a binary code value of 8 bits
 Serially transmit 8 bits consecutively for each such coded
sample
 Insert extra” bit(s) in the transmitted bit stream for
synchronizing purposes
 De-multiplexer operations are substantially the reverse of
those listed here

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Example Of TDM , The E-1 Frame


125 s or 1/8000 second

0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31
32 8-bit time slots per frame,
normally 30 used for subscriber
PCM, two for synch and signals one time slot

Slot zero contains Slot 16 contains


synchronizing common channel
bit label: 1 2 3 4 5 6 7 8

bit pattern and some signaling, either 3.9 s/slot


trouble-shooting channel associated
bit patterns. condition bits, or
CCS7
8000 frames/s
256 bits/frame
2.048 Mbit/s bit rate
0.488 µs/bit

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Digital Multiplexing Hierarchy


In the European system, the E1 signal constitutes the first level
of a hierarchy of signals that are each formed by successively
carrying out the TDM multiplexing of 4 lower level signals.
This way we obtain signals with the following formats:
E2 (8.448 Mbit/s),
E3 (34.368 Mbit/s) and
E4 (139.264 Mbit/s).
A fifth level, E5 (565.148 Mbit/s) was also defined but in the
end was not standardized.
This digital multiplexing hierarchy is the European version of
what is known as Plesiochronous Digital Hierarchy or PDH.

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E1 Multiplexing Scheme

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Worldwide Plesiochronous Digital


Hierarchy (PDH)

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