Question: 1
Rajeev buys goods worth Rs. 6650. He gets a rebate of 6% on it. After getting the rebate, he pays
sales tax @ 10%. Find the amount he will have to pay for the goods
(A) Rs. 6654
(B) Rs. 6876.10
(C) Rs. 6999.20
(D) Rs. 7000
Ans: B
Rajeev got 6% rebate as Rs. 6650
∴ Net price = 6650 × 0.94 = Rs. 6251
Tax on net price @ 10% = 10100×6251 = Rs. 625.10
∴ Total price = 6251 + 625.10 = Rs. 6876.10.
Question: 2
Fresh fruits contain 68% water and dry fruits contain 20% water. How much dry fruits can be
obtained from 100 kg of fresh fruits?
(A) 32 kg
(B) 42 kg
(C) 50 kg
(D) 52 kg
Ans: D
Fresh fruit contains = 68% water
Dry fruit contains = 20% water
From 100 kg of fresh fruit = 100 (1−48100)
= 52 kg dry fruits can be obtained
Question: 3
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent
increase of population per year is
(A) 5%
(B) 6%
(C) 7%
(D) 8.75%
Ans: A
Average percentage increase of population/year
= 262500–175000175000×10×100
= 87500175000×10010 = 5%.
Question: 5
In an examination, 52% of the candidates failed in English and 42% failed in Mathematics. If
17% failed in both the subjects, then the percentage of candidates, who passed in both the
subjects, was
(A) 21
(B) 22
(C) 23
(D) 25
Ans: C
Percentage of candidates who failed in
one or two or both subjects = 52 + 42 – 17 = 77
∴ Percentage of passed candidates = 100 - 73 = 23.
Question: 1
A student scores 55% marks in 8 papers of 100 marks each. He scores 15% of his total marks in
English. How much does he score in English?
(A) 44
(B) 45
(C) 66
(D) 77
Ans: C
Total marks obtained by the student = 55% of 800
= (55100×800) = 440.
∴ Marks scored in English = 15% of 440 = (15100×440) = 66.
Question: 3
In a college election between two candidates, one candidate got 55% of the total valid votes.
15% of the votes were invalid. If the total votes were 15200, what is the number of valid votes
the other candidate got?
(A) 5814
(B) 6840
(C) 7106
(D) 8360
Ans: A
Number of valid votes
= (100 – 15)% of 15200 = 85% of 15200
= (85100×15200) = 12920.
Valid votes polled by other candidate
= (100 – 55)% of 12920 = (45100×12920) = 5814.
Question: 4
A can complete a piece of work in 12 days. A and B together can complete the same piece of
work in 4 days. In how many can B alone complete the same piece of work?
(A) 2 days
(B) 6 days
(C) 10 days
(D) 12 days
Ans: B
Suppose the work consists of making 12 pillars. Since A can complete the work in 12 days, this
implies that A can make one pillar in a day. Similarly, we get that A and B together can make
three pillars in a day. Hence we can conclude that ‘B’ can make two pillars in a day. Hence, the
total work (12 pillars) can be completed by B in (12 &divde; 2) = 6 days.
Question: 1
A alone can complete a piece of work in 8 days. Work done by B alone in one day is half of the
work done by A alone in one day. In how many days can the work be completed if A and B work
together?
(A) 512
(B) 513
(C) 612
(D) 613
Ans: B
A does the work in 8 days.
B does the work in 16 days.
∴ A + B do the work in 8×168+16 = 163 = 513 days.
Question: 2
A can complete a piece of work in 12 days. A and B together can complete the same piece of
work in 8 days. In how many days can B alone complete the same piece of work?
(A) 15 days
(B) 16 days
(C) 18 days
(D) 24 days
Question: 3
15 men can do a piece of work in 6 days. How many men would be required to do the same work
in 7.5 days?
(A) 10
(B) 12
(C) 16
(D) 18
Ans: B
Required men = 15(67.5) = 12.
Question: 5
A and B can together finish a work in 30 days. They worked together for 20 days and then B left.
After another 20 days A finished the remaining work. In how many days can A alone finish the
job?
(A) 50 days
(B) 60 days
(C) 70 days
(D) 80 days
Ans: B
A and B together do 2030 = 23 part of the work in 20 days.
Remaining work = 1−23 = 13
∴ A alone can do the work in 20 × 3 = 60 days.
Question: 2
Fresh fruits contain 68% water and dry fruits contain 20% water. How much dry fruits can be
obtained from 100 kg of fresh fruits?
(A) 32 kg
(B) 42 kg
(C) 50 kg
(D) 52 kg
Ans: D
Fresh fruit contains = 68% water
Dry fruit contains = 20% water
From 100 kg of fresh fruit = 100 (1−48100)
= 52 kg dry fruits can be obtained
Question: 3
The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent
increase of population per year is
(A) 5%
(B) 6%
(C) 7%
(D) 8.75%
Ans: A
Average percentage increase of population/year
= 262500–175000175000×10×100
= 87500175000×10010 = 5%.
