Compulsory Three Five: Use of Graph Paper Is Allowed
Compulsory Three Five: Use of Graph Paper Is Allowed
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Paper / Subject Code: 32621 / Mechanical Measurements & Controls
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1T01435 - T.E.(Mechanical) Engineering)(SEM-V)(Choice Base Credit Grading System ) ((R- 19) (C
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Scheme) / 32621 - Mechanical Measurements & Controls
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QP CODE: 10028692 DATE: 23/05/2023.
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Time: 3 Hours Total Marks: 80
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2) Attempt any THREE questions out of remaining FIVE questions.
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4) Use of Graph paper is allowed.
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1. Answer of the following questions(any Four). 20
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i) Define wavelength standard and state the significance of using it.
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ii) Explain different types of fits with suitable examples and sketches
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iii) Differentiate between roughness and waviness.
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v) Briefly explain the construction and working of a strain gauge load cell.
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vi) Using Routh’s criterion examine the stability of a control system whose characteristic
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(B) Reduce the given block diagram to a it’s canonical form and hence obtain equivalent 10
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3. (A) Explain generalized measurement system elements with block diagram. Describe 10
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b. If it is desired to have steady state error to be 0.4, find corresponding value of “K”
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c. Find steady state error if input is changed to 2+6t, and value of K to 10.
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28692 Page 1 of 2
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Wear allowance 10% of gauge design
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absolute optical encoder. Give examples of their use.
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4. (A) Explain principle, construction and working of Parkinson Gear Tester
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Paper / Subject Code: 32621 / Mechanical Measurements & Controls
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5. (A) What are encoders? With a neat sketch, explain the working of an incremental and
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(B) Design a general type of Go and No Go plug gauge for inspecting a hole 25 d8. Given 10
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(B) Draw the root locus and comment on the stability of the control system having open loop 10
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Paper / Subject Code: 32621 / Mechanical Measurements & Controls
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1T01435 - T.E.(Mechanical) Engineering)(SEM-V)(Choice Base Credit Grading System ) ((R-20-21) (C Scheme) / 32621 -
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Mechanical Measurements & Controls Time: 3 Hours Total Marks: 80
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QP CODE: 10013250 DATE: 22/11/2022
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N.B: 1) Question No. 1 is compulsory.
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2) Attempt any THREE questions out of remaining FIVE questions
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3) Assume suitable data wherever necessary.
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4) Use of Graph paper is allowed.
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5) Figures to the right indicate full marks
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1. Answer the following questions.
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i) Distinguish between Line, End and Wavelength Standard.
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ii) Distinguish between open loop and closed loop control system with suitable
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While measuring the speed of steam turbine with stroboscope, stationary image was
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observed for three consecutive stroboscope settings of 3000, 4000 and 5250 flashes
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2. (A) Reduce the following block diagram and find the transfer function. 10
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(B) What is Taylors principle, explains in detail? Write note on Hole Basis System and 10
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Sketch the Bode Plot, Find 𝜔𝑔𝑐 , 𝜔𝑝𝑐 , GM and PM. Comment on stability.
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13250 Page 1 of 2
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interferometer.
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5. (A) Draw the Root-Locus of the system having
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Paper / Subject Code: 32621 / Mechanical Measurements & Controls
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suggest method to minimize the effect of Modifying & Interfering inputs.
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4. (A) Explain principle of interference. How flatness can be checked with help of optical
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principle. State one major advantage and disadvantage of this instrument over
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6. (A) What are the different elastic transducers used for pressure measurement? Illustrate 10
(B) Draw neat labelled diagram of Taylor Hobson Talysurf and briefly explain working 10
(B) What are desired, Modifying, Interfering input? Explain with example of each. Also 10
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QP CODE: 10013250
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pressure measurement.
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4. Figures/sketches carry weightage.
3. Assume suitable data, if necessary.
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stability criterion , determine the range of “k” for stability.
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B8 1F0 F2 A7 4E 13 01 7E0 89 57 472 FC B8 1F F2 A 4E 13 201 7E
1F F2 6A 4E 513 20 7E 89 C5 47 FC 8B 1F 0F2 6A 74E 51 20 7E 089
0F 6A 74 51 20 17E 08 C5 747 2F 8B 81 0F 6A 74 51 32 17 08 C
26 74 E5 32 17 0 9C 74 2F C8 81 F0 26 7 E5 32 017 E0 9C 574
A7 E 13 01 E0 89 57 72 C B8 F F2 A7 4E 13 01 E 89 57 72
c) Explain the following terms with respect to the measuring system:
01 E0 9C 57 72 C B8 F0 F2 A7 E 13 01 E0 89 57 72 C B8 1F
7E 89 5 47 FC 8B 1F F 6A 4E 51 20 7E 89 C5 47 FC 8B 1F 0F
b) Differentiate between open loop and closed loop system with examples.
9C 74 2F C8 8 F0 26 7 E5 32 17 E0 9C 57 72 C8 B8 F0 26 A7
What is the error if the exact formula is used for measurement of pressure?
57 72 C B8 1F0 F2 A7 4E 13 01 E0 89 57 472 FC B8 1F F2 A 4E
Paper / Subject Code: 32602 / Mechanical Measurements & Control
47 FC 8B 1F F2 6A 4E 51 20 7E 89 C5 47 FC 8B 1F 0F 6A 74 51
Explain the construction and working of a Nozzle Flapper with a neat sketch
2F 8B 81 0F 6A 74 51 32 17 08 C 74 2F 8 81 0F 26 74 E5 3
C8 8 F0 26 7 E5 32 01 E0 9C 57 72 C8 B8 F0 26 A7 E5 13
B8 1F0 F2 A7 4E 13 01 7E0 89 57 472 FC B8 1F F2 A 4E 13 2 Illustrate the constructional features and working of LVDT with a neat sketch
1F F2 6A 4E 513 20 7E 89 C5 47 FC 8B 1F 0F2 6A 74E 51 20
Consider the characteristic equation s4 +2s3+(4+k)s2+9s+25=0 , using the Hurwitz
A7 E 13 01 E0 89 57 72 C B8 F F2 A7 4E 13 01
4E 513 201 7E 89 C57 47 FC 8B 1F 0F2 6A 4E 513 20 7E
51 20 7E 08 C5 47 2FC 8B 81F 0F 6A 74 51 20 17E
32 17 08 9C 74 2F 8 81 0 26 74 E5 32 17 0
05
06
06
08
04
08
08
06
06
08
08
07
01 E0 9C 57 72 C B8 F0 F2 A7 E 13 01 E0 8
7E 89 5 47 FC 8B 1F F 6A 4E 51 20 7E 89
08 C5 747 2F 8B 81 0F 26A 74 51 320 17 08
9C 74 2F C8 8 F0 26 7 E5 32 17 E0 9C
57 72 C B8 1F0 F2 A7 4E 13 01 E0 89
19-Nov-2019 1T01425 - T.E (Mechanical Engineering) (SEM-V)(Choice Base) / 32602 - Mechanical Measurements &
47 FC 8B 1F F2 6A 4E 51 20 7E 89 C5
2F 8B 81 0F 6A 74 51 32 17 08 C 7
C8 8 F0 26 7 E5 32 01 E0 9C 57
B8 1F0 F2 A7 4E 13 01 7E0 89 57 4
1F F 6A 4 51 20 7E 8 C5 47
2F 8B 81 0F 6A 74 51 2 17 08
0 E
FC C8B 81F F0F2 26A 74E E513 320 17E 089 9C5
8 8 0 6 7 5 1 7
C8 B8 1F0 F26 A7 4E5 132 201 7E0 089C C57 472
B8 1F0 F2 A7 4E 13 01 7E0 89 57 472 FC
8B 1F F 6A 4E 51 20 7E 8 C5 47 F 8B
81 0 26 7 5 32 17 0 9C 74 2 C8 8
81 F0F F26AA74 4E51 132 017 E08 89C 574 72F FC8 B81 1F0F
F 0 E 5 7 B
Q.5
1F 0F2 26A 74E E513 320 17E 089 9C5 747 2FC C8B 81F F0F2 26A
7 1 7 2
Q6)
0 0 8
F0 F26 6A7 4E5 5132 201 7E0 89C C57 472 FC8 8B8 1F0 0F26 6A7 74E5
F 4 7 8 4 F 1
77512
0F 26AA74 E51 1320 017E E08 9C5 5747 72F C8B B81 F0F F26AA74 4E51 132
a)
b)
a)
26 74 E5 32 17 0 9C 74 2F C8 81 F0 26 7 E5 32 017
26 A74 E5 132 017 E0 89C 574 72F C8 B81 F0 F26 A7 4E5 132 017 E0
A 1 8 F 4 8
6A 74E E51 320 017E E08 9C5 5747 72FC C8B B81F F0F 26AA74 E51 1320 017E E08 9C5
7 4 5 3 2 17 0 9C 7 4 2 F 8 8 0 2 6 7 E 5 32 1 7 0 9
8 1
A7 E 13 01 E0 9 57 72 C B8 F F2 A7 4E 13 01 E 89 C57 7472
4E 513 201 7E 89 C57 47 FC 8B 1F 0F2 6A 4E 513 20 7E 089 C5 47 FC
51 20 7E 08 C5 47 2FC 8B 81F 0F 6A 74 51 20 17E 08 C5 747 2F 8B
32 17 08 9C 74 2F 8 81 0 26 74 E5 32 17 0 9C 74 2F C8 8
equation
01 E0 9C 57 72 C B8 F0 F2 A7 E 13 01 E0 89 57 72 C B8 1F
7E 89 5 47 FC 8B 1F F 6A 4E 51 20 7E 89 C5 47 FC 8B 1F 0F
08 C5 747 2F 8B 81 0F 26A 74 51 320 17 08 C 74 2F 8 81 0F 26
9C 74 2F C8 8 F0 26 7 E5 32 17 E0 9C 57 72 C8 B8 F0 26 A7
57 72 C B8 1F0 F2 A7 4E 13 01 E0 89 57 472 FC B8 1F F2 A 4E
47 FC 8B 1F F2 6A 4E 51 20 7E 89 C5 47 FC 8B 1F 0F 6A 74 51
2F 8B 81 0F 6A 74 51 32 17 08 C 74 2F 8 81 0F 26 74 E5 32
C8 8 F0 26 7 E5 32 01 E0 9C 57 72 C8 B8 F0 26 A7 E5 13 01
B8 1F0 F2 A7 4E 13 01 7E0 89 57 472 FC B8 1F F2 A 4E 13 201 7E of magnitude “5”.
1F F2 6A 4E 513 20 7E 89 C5 47 FC 8B 1F 0F2 6A 74E 51 20 7E 089
0F 6A 74 51 20 17E 08 C5 747 2F 8B 81 0F 6A 74 51 32 17 08 C
26 74 E5 32 17 0 9C 74 2F C8 81 F0 26 7 E5 32 017 E0 9C 574
A7 E 13 01 E0 89 57 72 C B8 F F2 A7 4E 13 01 E 89 57 72
4E 513 201 7E 89 C57 47 FC 8B 1F 0F2 6A 4E 513 20 7E 089 C5 47 FC
51 20 7E 08 C5 47 2FC 8B 81F 0F 6A 74 51 20 17E 08 C5 747 2F 8B
32 17 08 9C 74 2F 8 81 0 26 74 E5 32 17 0 9C 74 2F C8 8
01 E0 9C 57 72 C B8 F0 F2 A7 E 13 01 E0 89 57 72 C B8 1F
7E 89 5 47 FC 8B 1F F 6A 4E 51 20 7E 89 C5 47 FC 8B 1F 0F
08 C5 747 2F 8B 81 0F 26A 74 51 320 17 08 C 74 2F 8 81 0F 26
9C 74 2F C8 8 F0 26 7 E5 32 17 E0 9C 57 72 C8 B8 F0 26 A7
57 72 C B8 1F0 F2 A7 4E 13 01 E0 89 57 472 FC B8 1F F2 A 4E
47 FC 8B 1F F2 6A 4E 51 20 7E 89 C5 47 FC 8B 1F 0F 6A 74 51
2F 8B 81 0F 6A 74 51 32 17 08 C 74 2F 8 81 0F 26 74 E5 32
C8 8 F0 26 7 E5 32 01 E0 9C 57 72 C8 B8 F0 26 A7 E5 13 01
B8 1F0 F2 A7 4E 13 01 7E0 89 57 472 FC B8 1F F2 A 4E 13 201 7E
1F F2 6A 4E 513 20 7E 89 C5 47 FC 8B 1F 0F2 6A 74E 51 20 7E 089
0F 6A 74 51 20 17E 08 C5 747 2F 8B 81 0F 6A 74 51 32 17 08 C
26 74 E5 32 17 0 9C 74 2F C8 81 F0 26 7 E5 32 017 E0 9C 574
Page 2 of 2
A7 E 13 01 E0 89 57 72 C B8 F F2 A7 4E 13 01 E 89 57 72
4E 513 201 7E 89 C57 47 FC 8B 1F 0F2 6A 4E 513 20 7E 089 C5 47 FC
51 20 7E 08 C5 47 2FC 8B 81F 0F 6A 74 51 20 17E 08 C5 747 2F 8B
***************
32 17 08 9C 74 2F 8 81 0 26 74 E5 32 17 0 9C 74 2F C8 8
For a system with unity feedback having , G(s) =
01 E0 9C 57 72 C B8 F0 F2 A7 E 13 01 E0 89 57 72 C B8 1F
7E 89 5 47 FC 8B 1F F 6A 4E 51 20 7E 89 C5 47 FC 8B 1F 0F
08 C5 747 2F 8B 81 0F 26A 74 51 320 17 08 C 74 2F 8 81 0F 26
9C 74 2F C8 8 F0 26 7 E5 32 17 E0 9C 57 72 C8 B8 F0 26 A7
𝑠2
57 72 C B8 1F0 F2 A7 4E 13 01 E0 89 57 472 FC B8 1F F2 A 4E
47 FC 8B 1F F2 6A 4E 51 20 7E 89 C5 47 FC 8B 1F 0F 6A 74 51
2F 8B 81 0F 6A 74 51 32 17 08 C 74 2F 8 81 0F 26 74 E5 32
2FC8B81F0F26A74E5132017E089C5747
C8 8 F0 26 7 E5 32 01 E0 9C 57 72 C8 B8 F0 26 A7 E5 13 01
B8 1F0 F2 A7 4E 13 01 7E0 89 57 472 FC B8 1F F2 A 4E 13 201 7E
1F F2 6A 4E 513 20 7E 89 C5 47 FC 8B 1F 0F2 6A 74E 51 20 7E 089
0F 6A 74 51 20 17E 08 C5 747 2F 8B 81 0F 6A 74 51 32 17 08 C
26 74 E5 32 17 0 9C 74 2F C8 81 F0 26 7 E5 32 017 E0 9C 574
800 (𝑠+2)
A7 E 13 01 E0 89 57 72 C B8 F F2 A7 4E 13 01 E 89 57 72
equivalent transfer function, for the block diagram shown below.
32 17 08 9C 74 2F 8 81 0 26 74 E5 32 17 0 9C 74 2F C8 8
01 E0 9C 57 72 C B8 F0 F2 A7 E 13 01 E0 89 57 72 C B8 1F
7E 89 5 47 FC 8B 1F F 6A 4E 51 20 7E 89 C5 47 FC 8B 1F 0F
20 (S+3)
57 72 C B8 1F0 F2 A7 4E 13 01 E0 89 57 472 FC B8 1F F2 A 4E
Paper / Subject Code: 32602 / Mechanical Measurements & Control
47 FC 8B 1F F2 6A 4E 51 20 7E 89 C5 47 FC 8B 1F 0F 6A 74 51
2F 8B 81 0F 6A 74 51 32 17 08 C 74 2F 8 81 0F 26 74 E5 3
C8 8 F0 26 7 E5 32 01 E0 9C 57 72 C8 B8 F0 26 A7 E5 13
b) Obtain the state-space equation and output equation for the system defined by the
0F 6A 74 51 20 17E 08 C5 747 2F 8B 81 0F 6A 74 51 32 1
26 74 E5 32 17 0 9C 74 2F C8 81 F0 26 7 E5 32 017
A7 E 13 01 E0 89 57 72 C B8 F F2 A7 4E 13 01
4E 513 201 7E 89 C57 47 FC 8B 1F 0F2 6A 4E 513 20 7E
51 20 7E 08 C5 47 2FC 8B 81F 0F 6A 74 51 20 17E
32 17 08 9C 74 2F 8 81 0 26 74 E5 32 17 0
10
10
10
10
01 E0 9C 57 72 C B8 F0 F2 A7 E 13 01 E0 8
7E 89 5 47 FC 8B 1F F 6A 4E 51 20 7E 89
08 C5 747 2F 8B 81 0F 26A 74 51 320 17 08
9C 74 2F C8 8 F0 26 7 E5 32 17 E0 9C
57 72 C B8 1F0 F2 A7 4E 13 01 E0 89
47 FC 8B 1F F2 6A 4E 51 20 7E 89 C5
2F 8B 81 0F 6A 74 51 32 17 08 C 7
C8 8 F0 26 7 E5 32 01 E0 9C 57
B8 1F0 F2 A7 4E 13 01 7E0 89 57 4
1F F 6A 4 51 20 7E 8 C5 47
7 16 9 A 8E 2 6C C9 B 43
7C C16 092 2A7 78E 12F F6C C9 1B1 143 A7
1 09 A 8E 12 6C C9 1B 4 A7 DA
16 6092 2A7 78E 12F F6C C9 1B 143 3A7 DA 96
1 1 1 D 1
60 092A A78 8E1 2F6 6CC C91 B1 43A A7D A9 961 B77
92 7 E1 2F C 91 B1 43 7D A 61 B7 C
92 A7 8E1 2F 6C C91 B1 43 A7D A 961 B7 7C 160
8 C A 9 1
2A A78 E12 2F6 6CC 91B B14 43A 7D A9 61B B77 7C1 609 92A
Q4)
Q3)
Q1)
78 E12 F6 CC 91 14 3A 7D A9 61B 77 C1 609 2A 78E
58679
78 E12 F6 CC 91 B14 3A 7D A9 61B 77 C1 609 2A 78E 12
B 6
T
8E E12F F6C CC9 91B 143 3A7 7DA A96 61B 77C C16 092 2A7 78E 12F F6C
1 1 1 D 1 7 0 1
a)
a)
a)
C A 1
E1 2F 6CC 91 B1 43A 7D A9 961 B7 7C1 60 92A A78 8E1 2F6 6CC C91
2F 6C 91 B1 43 7D A 61 B7 7C 60 92 78 E1 2F CC 91 B1
2F 6C C91 B1 43 A7D A 961 B7 7C 160 92 A78 E1 2F 6CC 91 B1 43A
C A 9 1 A 6 4
F6 6CC 91B B14 43A 7D A9 61B B77 7C1 609 92A 78E E12 2F6 CC 91B B14 3A 7DA
CC 91 1 3A 7D A9 61 77 C1 60 2A 78 12 F6 CC 91B 14 3A 7D 9
Where;
91 B1 43A 7D A9 61 B77 C1 609 92A 78 E12 F6 CC 91B 14 3A 7D A9 61B
B1 43 7D A 61 B7 C 60 2A 78 E1 F CC 91 1 3A 7D A9 61 77
equation:
43 A7 A 961 B7 7C 160 92 7 E1 2F 6C 91 B1 43A 7D A 61 B7 C1
A7 DA 96 B 7C 16 92 A7 8E 2F 6C C9 B 43 7 A 96 B7 7C 60
W= 1500N.
instruments:
dm = Wl2
DA 96 1B 77C 16 092 A7 8E 12F 6C C9 1B 143 A7 DA 96 1B7 7C 16 92
and examples
4Ebd3
96 1B 77C 16 092 A7 8E 12F 6C C9 1B1 143 A7 DA 961 1B7 7C 160 092 A7
Instructions:
1B 77 16 09 A 8E 12 6C C9 1B 43 A7 DA 96 B 7C 16 92 A7 8E
77 C1 09 2A 78E 12 F6C C 1B 14 A DA 96 1B 77C 16 09 A7 8E 12F
dm = 2.622 ± 2.25%
d = 5.25 ± 0.25 cm ;
60 92A 78 E1 2F6 CC 91 B1 3A 7D A9 61 77 C1 609 2A 78 12 F6 CC
in various quantities.
92 7 E1 2F C 91 B1 43 7D A 61 B7 C 60 2A 78 E1 F6 CC 91
b = 4.942 ± 0.42 cm ;
A7 8E 2F 6C C9 B 43 A7 A 96 B7 7C 16 92 7 E1 2F C 9 B1
Y(t) = [1 0 0 ] x(t)
43 A7 A 961 B7 7C 160 92 7 E1 2F 6C 91 B1 43A 7D A 61 B7 C1
A7 DA 96 B 7C 16 92 A7 8E 2F 6C C9 B 43 7 A 96 B7 7C 60
DA 96 1B 77C 16 092 A7 8E 12F 6C C9 1B 143 A7 DA 96 1B7 7C 16 92
96 1B 77C 16 092 A7 8E 12F 6C C9 1B1 143 A7 DA 961 1B7 7C 160 092 A7
1B 77 16 09 A 8E 12 6C C9 1B 43 A7 DA 96 B 7C 16 92 A7 8E
(3 Hours)
C1 60 2A 78 1 F6 C 91 14 3A 7D 9 1B 77 1 09 2A 8E 12 6
+ 1 +2
92 7 E1 2F C 91 B1 43 7D A 61 B7 C 60 2A 78 E1 F6 CC 91
+
A7 8E 2F 6C C9 B 43 A7 A 96 B7 7C 16 92 7 E1 2F C 9 B1
8E 12F 6C C9 1B 143 A7 DA 96 1B 7C 16 092 A7 8E 2F 6C C9 1B1 43
12 6C C9 1B 14 A7 DA 96 1B 77C 16 09 A7 8E 12F 6C C9 1B 43 A7
d) Explain the principle of LVDT with a neat sketch
F6 C 1B 14 3A D 9 1B 77 1 09 2A 8E 12 6 C 1B 14 A DA
CC 91 1 3A 7D A9 61 77 C1 60 2A 78 12 F6 CC 91B 14 3A 7D 9
91 B1 43A 7D A9 61 B77 C1 609 92A 78 E12 F6 CC 91B 14 3A 7D A9 61B
u(t)
B1 43 7D A 61 B7 C 60 2A 78 E1 F CC 91 1 3A 7D A9 61 77
43 A7 A 961 B7 7C 160 92 7 E1 2F 6C 91 B1 43A 7D A 61 B7 C1
A7 DA 96 B 7C 16 92 A7 8E 2F 6C C9 B 43 7 A 96 B7 7C 60
DA 96 1B 77C 16 092 A7 8E 12F 6C C9 1B 143 A7 DA 96 1B7 7C 16 92
DA961B77C16092A78E12F6CC91B143A7
96 1B 77C 16 092 A7 8E 12F 6C C9 1B1 143 A7 DA 961 1B7 7C 160 092 A7
C1 60 2A 78 1 F6 C 91 14 3A 7D 9 1B 77 1 09 2A 8E 12 6
60 92A 78 E1 2F6 CC 91 B1 3A 7D A9 61 77 C1 609 2A 78 12 F6 CC
92 7 E1 2F C 91 B1 43 7D A 61 B7 C 60 2A 78 E1 F6 CC 91
A7 8E 2F 6C C9 B 43 A7 A 96 B7 7C 16 92 7 E1 2F C 9 B1
Determine (i) Type and order of the system (ii) All error coefficients
2. Attempt any three questions from the remaining five questions.
1B 77 16 09 A 8E 12 6C C9 1B 43 A7 DA 96 B 7C 16 92
77 C1 09 2A 78E 12 F6C C 1B 14 A DA 96 1B 77C 16 09
C1 60 2A 78 1 F6 C 91 14 3A 7D 9 1B 77 1 09 2A
60 92A 78 E1 2F6 CC 91 B1 3A 7D A9 61 77 C1 609 2A 7
92 7 E1 2F C 91 B1 43 7D A 61 B7 C 60 2A 78
A rectangular steel rod of width ‘b’ and depth‘d’ is supported at its end and is loaded at its
b) Enumerate the types of pressure measurement devices w.r.t. to pressure levels. Explain the
A7 8E 2F 6C C9 B 43 A7 A 96 B7 7C 16 92 7
b) Differentiate between open and closed loop systems with their respective block diagrams
c) Explain the following terms with respect to static characteristics of the measuring
F6 C 1B 14 3A D 9 1B 77 1 09 2A 8E 12
TURN OVER
CC 91 1 3A 7D A9 61 77 C1 60 2A 78 12
10
10
08
12
10
10
05
05
05
05
Q6)
Q5)
58679
78 E12 F6 CC 91 14 3A 7D A9 61B 77 C1 609 2A 78E
78 E12 F6 CC 91 B14 3A 7D A9 61B 77 C1 609 2A 78E 12
B 6
8E E12F F6C CC9 91B 143 3A7 7DA A96 61B 77C C16 092 2A7 78E 12F F6C
1 1 1 D 1 7 0 1
a)
C A 1
E1 2F 6CC 91 B1 43A 7D A9 961 B7 7C1 60 92A A78 8E1 2F6 6CC C91
2F 6C 91 B1 43 7D A 61 B7 7C 60 92 78 E1 2F CC 91 B1
2F 6C C91 B1 43 A7D A 961 B7 7C 160 92 A78 E1 2F 6CC 91 B1 43A
C A 9 1 A 6 4
F6 6CC 91B B14 43A 7D A9 61B B77 7C1 609 92A 78E E12 2F6 CC 91B B14 3A 7DA
CC 91 1 3A 7D A9 61 77 C1 60 2A 78 12 F6 CC 91B 14 3A 7D 9
91 B1 43A 7D A9 61 B77 C1 609 92A 78 E12 F6 CC 91B 14 3A 7D A9 61B
B1 43 7D A 61 B7 C 60 2A 78 E1 F CC 91 1 3A 7D A9 61 77
43 A7 A 961 B7 7C 160 92 7 E1 2F 6C 91 B1 43A 7D A 61 B7 C1
A7 DA 96 B 7C 16 92 A7 8E 2F 6C C9 B 43 7 A 96 B7 7C 60
DA 96 1B 77C 16 092 A7 8E 12F 6C C9 1B 143 A7 DA 96 1B7 7C 16 92
96 1B 77C 16 092 A7 8E 12F 6C C9 1B1 143 A7 DA 961 1B7 7C 160 092 A7
1B 77 16 09 A 8E 12 6C C9 1B 43 A7 DA 96 B 7C 16 92 A7 8E
77 C1 09 2A 78E 12 F6C C 1B 14 A DA 96 1B 77C 16 09 A7 8E 12F
A7 DA 96 B 7C 16 92 A7 8E 2F 6C C9 B 43 7 A 96 B7 7C 60
DA 96 1B 77C 16 092 A7 8E 12F 6C C9 1B 143 A7 DA 96 1B7 7C 16 92
DA961B77C16092A78E12F6CC91B143A7
96 1B 77C 16 092 A7 8E 12F 6C C9 1B1 143 A7 DA 961 1B7 7C 160 092 A7
1B 77 16 09 A 8E 12 6C C9 1B 43 A7 DA 96 B 7C 16 92 A7 8E
77 C1 09 2A 78E 12 F6C C 1B 14 A DA 96 1B 77C 16 09 A7 8E 12F
C1 60 2A 78 1 F6 C 91 14 3A 7D 9 1B 77 1 09 2A 8E 12 6
60 92A 78 E1 2F6 CC 91 B1 3A 7D A9 61 77 C1 609 2A 78 12 F6 CC
92 7 E1 2F C 91 B1 43 7D A 61 B7 C 60 2A 78 E1 F6 CC 91
A7 8E 2F 6C C9 B 43 A7 A 96 B7 7C 16 92 7 E1 2F C 9 B1
8E 12F 6C C9 1B 143 A7 DA 96 1B 7C 16 092 A7 8E 2F 6C C9 1B1 43
12 6C C9 1B 14 A7 DA 96 1B 77C 16 09 A7 8E 12F 6C C9 1B 43 A7
F6 C 1B 14 3A D 9 1B 77 1 09 2A 8E 12 6 C 1B 14 A DA
CC 91 1 3A 7D A9 61 77 C1 60 2A 78 12 F6 CC 91B 14 3A 7D 9
91 B1 43A 7D A9 61 B77 C1 609 92A 78 E12 F6 CC 91B 14 3A 7D A9 61B
Obtain transfer function C(s) / R(s) using block diagram reduction technique.
B1 43 7D A 61 B7 C 60 2A 78 E1 F CC 91 1 3A 7D A9 61 77
Paper / Subject Code: 32602 / Mechanical Measurements & Control
92 7 E1 2F C 91 B1 43 7D A 61 B7 C 60 2A 78
A7 8E 2F 6C C9 B 43 A7 A 96 B7 7C 16 92 7
8E 12F 6C C9 1B 143 A7 DA 96 1B 7C 16 092 A7 8E
12 6C C9 1B 14 A7 DA 96 1B 77C 16 09 A7 8E 1
F6 C 1B 14 3A D 9 1B 77 1 09 2A 8E 12
CC 91 1 3A 7D A9 61 77 C1 60 2A 78 12
10
10
10
10