DC 1
DC 1
Example 20: A resistor R in series Resistivity of Some Inferred Absolute Zero Temperature
X and Y? with an 8-Ω resistor and absorbs 100W Common Materials Material T (oC)
Example 11: Calculate the energy in when the two are connected across a 60- Resistivity ρ
V line. Find the unknown resistance? Material Aluminum 228
joules converted in 24 hours by a 100-W W-m W-CM/ft Annealed Copper 234.5
lamp. Example 21:Two lamps are connected in Aluminum 2.83◌ּ10-8 17.02 Hard-Drawn Copper 241.5
Example 12: The average electric-flat- series across a voltage source of 220- Copper 1.724◌ּ10-8 10.371 Iron 180
iron is rated 550W at 220V. How many volts. Lamp A has a rating 100-watts, Gold 2.44◌ּ10-8 14.676 Silver 243
disk revolutions will a watt-hour meter 110-volts, while lamp B has a rating of Iron 98◌ּ10-8 589.4
make after using it for 90 minutes 50-W, 110-volts. If the resistances of the Silver 1.629◌ּ10-8 9.805
assuming the disk makes 12rev/kWh? lamps are taken as constants, determine XIII. OHM’S LAW:
the voltage drop across lamp A. In an electrical circuit, the current is
Example 13: An electric heater draws 25 XII. EFFECT OF TEMPERATURE ON RESISTANCE
kcal in 10 minutes at 220 volts. Calculate Example 22:A resistor having a rating of OF CONDUCTORS: directly proportional to voltage and is
the current. 220-volts, 75-watts is to be connected to inversely proportional to resistance.
a 110-volts source. Calculate the power it
Example 14:An electric heater rated will draw if this resistor is connected to a
110-volts, takes 1000-watts to boil 1 liter R2 R I= I =V◌ּG
voltage source of 110-volts. R1
of water. Calculate the time in minutes
required to raise the temperature of the Example 23:Two batteries in parallel
water from 20oC to boiling. The heater supply a common load of 2 Ω. Batteries A I – current in amperes
t
has an over-all efficiency of 95%. and B have open-circuit voltages and t1 V – voltage in volts
internal resistances of 10 V, 2 Ω; and 8 t2
Example 15: If a resistor rated at 2-watts V, 2 Ω respectively. Determine the load
T R – resistance in ohms,W
and 6-volts is connected across a battery Figure G – conductance in Siemens
current.
with an open circuit voltage of 6-volts,
what is the internal resistance of the Example 24:A 30 ohms resistor is
connected in series with the parallel XIV.KIRCHHOFF’S VOLTAGE LAW (KVL)
battery if the resulting current is 0.3
ampere? combination of 150 ohms resistor and a The algebraic sum of all voltages in a
load resistor RL. The combination is circuit taken around a closed path is
Example 16: A storage battery has an connected across a voltage source of
open-circuit voltage E of 12 volts and has zero.
120-volts. Calculate the value of RL that
an internal resistance RB of 0.1Ω. will result in maximum power transferred Convention:
Calculate the terminal voltage VT if the to it. Also determine the maximum power R2 = R1 [1 + a1 (t2 - t1)]
load current IL is 20 A. (Ans. _______ ) transferred. a Path b-a:
Example 17: A 12-Ω resistor is Example 25:A series combination of two Potential Rise = +V
connected in parallel with a series V Path a-b:
resistors 1kΩ and 4 kΩ is connected to a
combination of resistors of 8 and 16 Ω. If voltage source of 100 volts. A voltmeter Potential Drop = -V
the drop across the 8-Ω resistor is 48V, b
having an internal resistance of 12 kΩ is
determine the total impressed emf. placed across the 4 kΩ resistor. What is Figure
Example 18: When two resistors are the reading of the voltmeter?
connected in series, the total resistance
R2– resistance at temperature t2 a Path b-a:
is 108Ω; when connected in parallel, the
equivalent resistance is 24Ω. What is the R1– resistance at temperature t1 R Potential Rise = +Vr
+ Path a-b:
value of each unit? T – inferred absolute zero temperature Vr Potential Drop = -Vr
Example 19: A parallel combination of 5- a1- temperature coefficient of
ohm and 20-ohm resistors is connected I
resistance at temperature t1
in series with a variable resistor and to a b
50volt source. To what ohmic value will Figure
the variable resistor be set when the
power in the 5-ohm resistor is 20 watts?
6 3
CERTC-EE Review Guide Series Review Guide Series ELECTRICAL ENGINEERING DC Circuits 1
XV. KIRCHHOFF’S CURRENT LAW (KCL) V = V1 + V2 + … Vn Example 1: How much current flows
through a wire if 7.488x1019 electrons
Ø The algebraic sum of all currents RT = pass a given point every minute?
entering and leaving a node is zero. The source voltage V is the summation of R1 R2 Example 2:The current in a conductor
the voltages across each resistor.
Convention: varies as follows: during the first 8 sec
Figure there is a linear change from zero to 4
RT = R1 + R2+ ..Rn amp; during the next 15 sec the current is
Current entering a constant at 4 amp; during a third period
I2 XX. SERIES-PARALLEL CIRCUIT:
I3 node: + sign of 20 sec the current decreases linearly
Current leaving a The total resistance RT is the sum of the to 3 amp. Determine the average current.
node node: - sign R1
individual resistances. RT = R1 + Example 3: How much voltage is
I1
I4 R2 R3 required to cause a current of 500mA to
flow for 2 minutes if the work done to
Figure RT = = + +.. Figure move the electron is 3kJ?
Example 4: The resistivity of a certain
conductor in SI is 0.46µΩ-m. Determine
I1 - I2 - I3 + I4 = 0 XXI. PARALLEL-SERIES CIRCUIT: its resistivity in Ω·c-mil/ft.
XVIII. RESISTANCES IN PARALLEL: Example 5:Calculate the resistance of
R2 1km long cable composed of 19 strands
IT RT= of similar copper conductors each strand
XVI. ELECTRICAL POWER: R1
Rn R3 being 1.32mm in diameter. Allow 5%
R1 R2
increase in length of the twist of each
2
P=I ◌ּR (watts) P = V◌ּI (watts) V
I1 I2 In strand in complete cable. Resistivity of
Figure copper may be taken as 1.72x10-8W-m.
Figure Example 6: A 2 meter wire of has a
P= (watts) diameter of 3 cm is stretched until its
XXII. CURRENT DIVIDER: resistance is 50 times the initial
I1 = ; I2= ; In = resistance. Calculate the new resistance
IT
I1 = Example 7: The resistance of 120
XVII. RESISTANCES IN SERIES:
meters of wire is 20-W. What is its
The same voltage V exists across each R1 R2
conductance?
V1 V2 Vn resistor. I1 I2 I2 = Example 8:A 100-m conductor has a
cross-sectional area of 2 mm2 and having
R1 R2 Rn IT = I1 + I2+ .. In Figure a resistance of 15-Ω. Calculate its
V conductivity.
I
The total current IT is the sum of XXIII. VOLTAGE DIVIDER: Example 9: The resistance of a wire is
Figure individual current passing through each 126.46 ohms at 100°C and 100 ohms at
resistor. 30°C. Determine the coefficient of the
R1 V2 = wire at 0°C.
V
I= = = GT = = + +… R2 V2
Figure
4 5
The same current I exist on each resistor XIX. TWO RESISTANCES IN PARALLEL: SAMPLE PROBLEMS: