1999paper II
1999paper II
S-(OBJ) 1999 1 of 14
ELECTRICAL ENGINEERING
PAPER–II
1. A thermal generating station has an d. 0.1 pu
installed capacity of 15 MW and supplies a 5. A short transmission line has a total
daily load of 10 MW for 12 hours and 5 resistance of 2Ω, reactance of 3Ω, current
MW for remaining 12 hours. The plant of 125 A and pf of 0.8. Regulation in
capacity factor for this station is percentage is equal to
a. 1 a. 1.9
b. 0.75 b. 0.38
c. 0.67 c. 3.8
d. 0.5 d. 0.19
2. Power output (in kW) of a hydro power 6. A star-connected 3-phase 11 kV. 25 MVA
station is equal to (Q = discharge in m3/s, q alternators with its neutral grounded
overall. efficiency of the plant, h = head in through a 0.033 Pu reactance (based on the
m, ω = density of water) alternator rating) has positive negative and
75 Qω h zero-sequence reactance’s of 0.2 pu, 0.1 pu
a.
0.736 η and 0.1 pu respectively. A single line to
ground fault on one of its terminals would
0.736
b. Qω hη result in a fault current of
75 a. 150 MVA
750 Qθη b. 125 MVA
c.
0.736 h c. 100 MVA
0.736 Qhη d. 50 MVA
d.
750 ω 7. Compared to Gauss-Seidel method,
3. Consider following moderators used in Newton-Raphson method takes
nuclear reactors: a. less number of iterations and more
1. Graphite time per iteration
2. Beryllium b. less number of iterations and less time
3. Heavy water per. iteration
Their correct sequence in increasing order c. more number of iterations and more
of their neutron absorption cross-sections time per iteration
is d. more number of iterations and less
a. 1, 3, 2 time per iteration
b. 2, 1, 3 8. An infinite bus of 1 Pu is fed from a
c. 3, 1, 2 synchronous machine having E = 1.1 Pu.
If the transfer reactance between them is
d. 3, 2, 1
0.5 pu, the steady stat? power limit will be
4. 3-phase alternator rated at 50 MVA, 22 kV
a. 1.1 pu
has a synchronous reactance per phase of 5
Pu on its thermal rating. The pu value of b. 0.5 pu
this reactance on a base of 100 MVA and c. 2.2 Pu
220 kV is d. 1 pu
a. 25 pu 9. The positive sequence current for a L - L
b. 12.5 Pu fault of a 2 kV system is 1400 A, and
c. 1 pu corresponding current for a L - L - G fault
2 of 14
is 2220 A. The zero sequence impedance
of the system is
a. 62.75 Ω
b. 4.5275 Ω
c. 5.275 Ω
d. 0.5275 Ω
10. The inertia constant of a 100 MVA, 50 Hz,
4-pole generator is 10 MJ/MVA. If the
The equivalent capacitor arrangement of a
mechanical input to the machine is
two-string insulator is shown in the above
suddenly raised from 50 MW to 75 MW
figure. The maximum voltage that each
the rotor acceleration will be equal to
unit can withstand should not exceed 17.5
a. 225 electrical degree/s2 kV. The line-voltage of the complete string
b. 22.5 electrical degree/s2 is
c. 125 electrical degree/s2 a. 17.5 kV
d. 12.5 electrical degree/s2 b. 33 kV
11. A surge of 260 kV traveling in a line of c. 35 kV
natural impedance of 500Ω arrives at a d. 37.3 kV
junction with two lines of natural
16. Consider the following statements:
impedances of 250Ω and 50Ω
1. By using bundle conductors in an
respectively. The voltage transmitted in
overhead line, the corona loss is
the branch lines is
reduced.
a. 400kV
2. By using bundle conductors, the
b. 260 kV inductance of transmission line
c. 80 kV increases and capacitance reduces;
d. 40 kV 3. Corona loss causes interference in
12. Insulation coordination of UHV lines adjoining communication lines.
(above 500 kV) is, done based on Which of these statements are correct?
a. lightning surges a. 1 and 2
b. lightning surges and switches surges b. 2 and 3
c. switching surges c. 1 and 3
d. None of the above d. 1, 2 and 3
13. The number of discs in a string of 17. Which one of the following sequences of
insulators for 400 kV ac overhead operations represents the rated operating
transmission line lies in the range of duty cycle of a circuit breaker?
a. 32 to 33 (O - open; C - close; t = 3 sec.; T = 3 mm.)
b. 22 to 23 a. O – t - C0 – T - CO
c. 15 to 16 b. O – CO – t – CO – T – C
d. 9 to 10 c. O – C – T – OC – T
14. The insulation resistance of a single-core d. O – CO – T – CO – T - C
cable is 200 MΩ/km. The insulation 18.
resistance for 5 km length is
a. 40 MΩ
b. 1000 MΩ
c. 200MΩ
d. 8 MΩ
15.
3 of 14
With the usual notation, the impedance
matrix for the system shown in the above
figure is
⎡3 1 ⎤
a. ⎢ ⎥
⎣1 3⎦
⎡ 3 / 8 −1/ 8⎤ The distribution system shown in the
b. ⎢ ⎥ above figure is to be protected by over-
⎣ −1/ 8 3 / 8 ⎦ current system of protection. For proper
⎡ 6 / 5 4 / 5⎤ fault discrimination, directional over-
c. ⎢ ⎥
⎣ 4 / 5 6 / 5⎦ current relays will be required at locations
a. 1 and 4
⎡5 4⎤
d. ⎢ ⎥ b. 2 and 3
⎣4 5⎦ c. 1, 4 and 5
19. A 3-phase circuit breaker is rated at 2000 d. 2, 3 and 5
MVA, 33 kV; its making current will be
23. If the fault current is 2 kA, the relay
a. 35 kA setting is 50% arid the CT ratio is 400/5,
b. 49 kA then plug setting multiplier will be
c. 70 kA a. 25
d. 89 kA b. 15
20. Line trap at coupling capacitors are used c. 50
for carrier current protection in which d. 12.5
a. line trap has high impedance to 50 Hz 24. A three-phase 11/66 kV, delta/star
signal but low impedance to carrier transformer, protected by Merz-price
current signal whereas a coupling scheme has CT ratio of 400/5 on L.T. side.
capacitor has low impedance to 50 Hz Ratio of C.T. on H.T. side will be equal to
signal but high impedance to carrier
a. 1 : 23
signal
b. 23 : 1
b. line trap has low impedance to 50Hz
signal but high impedance to carrier c. 23 : 3
current signal, whereas a coupling d. 3 : 23
capacitor has high impedance to 50 Hz
signal but low impedance to carrier 25. Which one of the following statements in
signal respect of HVDC transmission line is not
correct?
c. both line trap and coupling capacitor
have low impedance to 50 Hz signal a. the power transmission capability of
but high impedance to carrier current bipolar line is almost the same as that
signal of single circuit ac line
d. both line trap and coupling capacitor b. HVDC link line can operate between
have high impedance to 50 Hz signal two ac systems whose frequencies
but low impedance to carrier current need not be equal
signal c. There is no distance limitation for
21. Four alternators, each rated at 5 MVA, 11 HVDC transmission by UG cable
kV with 20% reactance are working in d. Corona loss is much higher in HVDC
parallel. The short-circuit level at bus bars transmission line
is 26. In a 3-phase converter used in HVDC
a. 6.25 MVA transmission, the three anodes conduct
b. 20 MVA sequentially. Due to overlap caused by the
circuit inductance, two anodes conduct
c. 25 MVA simultaneously during the overlap period
d. 100 MVA The output voltage waveform during this
22. period is the
4 of 14
a. voltage of the 1st anode, because the firing angle α min = φ where
2nd anode has not completely taken
φ = tan −1 (ω L / R ) .
over
b. mean of the two anode voltages, as Reason (R): In an ac voltage regulator
they conduct together feeding R — L load, control is lost if
c. voltage of the 2nd anode, because the α min < φ .
voltage of this anode is greater than a. Both A and Rare true and R is the
that of the 1st correct explanation of A
d. sum of the 1st and the 2nd anode b. Both A and R are true but R is NOT
voltages, because both the anodes are the correct explanation of A
conducting c. A is true but R is false
27. If, for a given alternator in economic d. A is false but R is true
operation mode, the incremental cost is 32. Assertion (A): A 64 input MUX can be
given by (0.012P +8) Rs./mwh, dPL / dP = built by using eight 8 input multiplexers
0.2 and plant λ = 25, then the power
Reason (R): Any six variable functions can
generation is
always be implemented by a multiplexer
a. 1000 MW with six address lines.
b. 1250 MW a. Both A and Rare true and R is the
c. 750 MW correct explanation of A
d. 1500 MW b. Both A and R are true but R is NOT
28. Load frequency control uses the correct explanation of A
a. proportional controllers alone c. A is true but R is false
b. integral controllers alone d. A is false but R is true
c. both proportional and integral 33. Assertion (A): The input resistance of a
controllers silicon JFET is of the order of tens or
d. either proportional or integral huntlreds of megaohms.
controllers Reason (R): The gate-source junction of
29. Two generators rated at 200 MW and 400 JFET is a reverse biased silicon diode and
MW are operating in parallel. Both the hence only a very small leakage current
governors have a drop of 4%, when the flows through the gate.
total load is 300 MW They share the load a. Both A and Rare true and R is the
as (suffix ‘1’ is used for generator 200 correct explanation of A
MW and suffix ‘2’ is used for generator b. Both A and R are true but R is NOT
400 MW) the correct explanation of A
a. P1 = 100 MW and P2 = 200MW c. A is true but R is false
b. P1 = 150 MW and P2 = 150 MW d. A is false but R is true
c. P1 = 200 MW and P2 = 100 MW 34. Assertion (A): The per unit impedance of a
d. P1 = 200 MW and P2 = 400 MW synchronous machine is the reciprocal of
30. Assertion (A): dc series motors are used short-circuit ratio of the machine
to drive electric locomotives. Reason (R): For the computation of the
Reason (R): dc series motor develop high short-circuit ratio, the field excitation to
torque at high speed. generate rated voltage on open-circuit
a. Both A and Rare true and R is the should be read from the open-circuit
correct explanation of A characteristic of the machine.
b. Both A and R are true but R is NOT a. Both A and Rare true and R is the
the correct explanation of A correct explanation of A
c. A is true but R is false b. Both A and R are true but R is NOT
the correct explanation of A
d. A is false but R is true
c. A is true but R is false
31. Assertion (A): If an ac-voltage regulator is
feeding and R — L ked, the minimum d. A is false but R is true
5 of 14
35. Assertion (A): The switching function F = b. 22.22 mA, 8.61 mA and 12.3mA
Σ(0 - 3, 12 - 15) does not have a unique c. 28.33 mA, 14.61 mA and 13.33 mA
minimal sum of product form. d. 40 mA, 20 mA and 25 mA
Reason (R) The switching function F = 39. The transition capacitance of a diode is 1
Σ(0 - 3, 7, 12 - 15) has cyclic prime nF and it can withstand reverse potential of
implicants. 400 V.A capacitance of 2 nF which can
a. Both A and Rare true and R is the withstand a reverse potential of 1 kV is
correct explanation of A obtained by connecting
b. Both A and R are true but R is NOT a. two 1 nF diodes in parallel
the correct explanation of A b. six parallel branches with each branch
c. A is true but R is false comprising three 1 nF diodes in series
d. A is false but R is true c. two 1 nF diodes in series
36. Assertion (A): The maximum possible d. three parallel branches with each
output frequency of the basic series branch comprising six 1 nF diodes in
inverter, using SCR’s T1 and T2 is limited series
to the resonant frequency. 40.
Reason (R): Thyristor T2 can only be fired
when thyristor T1 is OFF and vice-versa,
otherwise a dead short-circuit will take
place across the dc supply.
a. Both A and Rare true and R is the
correct explanation of A
b. Both A and R are true but R is NOT
the correct explanation of A The circuit of a class B push-pull amplifier
c. A is true but R is false shown in the above figure. If the peak
d. A is false but R is true output voltage VO is 16 V, the power
37. drawn from the dc source would be
a. 10 W
b. 16 W
c. 20 W
d. 32 W
41. An FET source follower circuit has gm of
2 m band rd of 50 k . If the source
resistance RS is 1 kΩ, the output resistance
of the amplifier will be
A 5 V reference is drawn from the circuit a. 330 Ω
shown in the above figure. If the zener b. 450 Ω
diode is of 5 mV and 5 V, then RZ will be
c. 500 Ω
a. 50 Ω
d. 1 k Ω
b. 500 Ω
42. If the counters of INTEL 8253
c. 5000 Ω (programmable interval timer) are loaded
d. 50000 Ω with a hew value while counting, then
38. A voltage of 200 cos 100 t is applied to a a. the counter will stop counting
half-wave rectifier with a load resistance b. the counter will ignore the new. loaded
of 5 kΩ. The rectifier is represented by an value d continue to count as per
ideal diode in series with a resistance of 1 previous loaded value
kΩ. The maximum value of current, dc c. the counter will start counting
component of current and rms value of backwards
current will be respectively d. counting will restart from the new
a. 33.33 mA, 10.61 mA and 16.67 mA value of count which has been loaded
6 of 14
43.