Chemistry of Alcohols
Chemistry of Alcohols
INTRODUCTION:
Alcohols are organic compounds in which one or more hydrogen atoms from hydrocarbon have
been replaced by hydroxyl (-OH) group. They are some of the most common and useful
compounds in nature, in industry, and around the house. The general formula for a simple acyclic
alcohol is CnH2n+1OH, where n=1, 2, 3, etc. The saturated carbon chain is often designated by the
symbol R, so that ROH can represent any alcohol in the homologous series. Alcohols can be
viewed as organic analogues of water in which one hydrogen atom is replaced by an alkyl group.
The simplest and most commonly used alcohols are methanol and ethanol. They occur widely in
nature and have many industrial and pharmaceutical applications.
Aromatic compounds, which contain a hydroxy group on a side chain, behave like alcohols are
                                                                             3
called aromatic alcohol. In these alcohols, the —OH group is attached to a sp hybridised carbon
atom next to an aromatic ring.
                          CH2OH               CH CH OH             CH CH CH OH
                                                 2   2               2   2   2
                                                                    OH
CH2    CH OH        CH2     CH CH2 OH
vinylic alcohol      allylic alcohol
                                                          phenol
CLASSIFICATION OF ALCOHOLS: Alcohols are classified into following types on
the basis of number of –OH groups present in the molecule and nature of carbon attached with –OH
group as follow:
(a) Monohydric Alcohols: These compounds contain only one –OH group.
CH3CH2OH CH3CH2CH2OH
   On the basis of nature of carbon atom attached with -OH group the mnohydric
   Alcohols can be further classified as primary (1°), secondary (2°), or tertiary (3°)
   depending on the number of carbon atoms bound to the hydroxyl-bearing carbon.
   (a) Primary alcohol (1° alcohol): A primary alcohol has one alkyl group attached to
      the carbon bound to the –OH, i.e., a compound in which the hydroxyl group is
      bounded to a primary carbon. Primary alcohols have the group –CH 2OH, where
      the carbon atom with the alcoholic hydroxyl group has at least two additional
      hydrogen attached to that carbon. Primary alcohol has –OH gr oup bonded to a
      carbon which is bonded to one other carbon:
H H
H C C OH
H H
   (b) Secondary alcohol (2° alcohol): A secondary alcohol has two alkyl group attached
      to the carbon bound to the –OH, i.e., the hydroxyl group is bounded to a secondary
      carbon. Secondary alcohols have the group –CHOH, where the carbon atom with the
      alcoholic hydroxyl group has only one additional H atom attached to it. There are two
      R groups (R stands for any other organic chain or group), and the alcoholic hydroxyl
      group is attached to a secondary carbon. Secondary alcohol has –OH group bonded to
      a carbon which is bonded to two other carbon:
H OH H
HC C C H
H H H
   (c) Tertiary alcohol (3° alcohol): A tertiary alcohol has three alkyl group attached to
      the carbon bound to the –OH, i.e., the hydroxyl gro up is bounded to a tertiary carbon.
        Tertiary alcohols have the group –COH, wher e the carbon atom with the alcoholic
        hydroxyl group has no additional H atoms attached to it.
H CH3 H
                  H        C     C        C   H
                    H    OH   H
    If we replace hydrogen with a –OH group we get the following groups for three
    alcohols:
CH2OH CH OH C OH
                                      OH
                                                                OH                               OH
                      OH                                                                         C    CH3
                                                  CH3    CH2     CH        CH3   CH3      CH2
     primary alcohol                                                                               CH3
                               secondary alcohol         secondary alcohol             tertiary alcohol
NOMENCLATURE OF ALCOHOLS
    Step 1. Name the longest continuous chain to which the hydroxyl (—OH) group is
    attached. Count the number of carbon atoms and identify the corresponding alkane.
    The name for this chain is obtained by dropping the final -e from the name of the
    hydrocarbon parent name and adding the ending -ol.
    Step 2. Number the longest chain to give the lowest possible number to the carbon
    bearing the hydroxyl group.
    Step 3. Locate the position of the hydroxyl group by the number of the carbon to which
    it is attached.
    Step 4. Number the any other substituents according to their position on the chain.
    Step 5. Combine the name and location for other groups, the hydroxyl group location,
    and the longest chain into the final name.
    Step 6. If there are more than one –OH group do not remove the –e from the suffix,
    but add a di- or tri- prefix to the –ol suffix.
    Step 7. Identify and locate the other branches on the chain so that they are named
    alphabetically and their carbon number is hyphenated onto the front of the name.
Other examples:
               OH                                 CH3                             OH
CH3             CH CH2          CH3     CH3       CH    CH2 CH2                   CH     CH3
                                                                                                                     OH
                2                                 5                  2
                    - butanol                         methyl             hexanol                   cyclopentanol
OH             OH         OH                                                                       OH
  CH2           CH                                               2
                          CH2                                                                              CH   CH3
 1              2          3                                                 OH          CH3       CH
, ,        -                                           3                 1
                                                                                                           NH2
1 2 3          trihydroxy propane        3-                -1-                            3
                                              cyclopentyl propanol                            --amino 2-   butanol
                                                                                                     OH
                                                OH
CH2 CH CH OH CH3
                         CH3
3                   2                                      CH3                                              CH3
    - butene - - ol                                                                .
                                      3 - meyhylcyclohexanol                      2 3 - dimethylcyclooctanol
METHOD OF PREPARATION OF ALCOHOLS
H2O
                RX+OH                      ROH    +   X
                                                 H2O
               CH3CH2CH2Br       +   NaOH(aq)             CH3CH2CH2OH       +   NaCl
                                                                             +        –
          3. From hydration of alkenes: Hydration i.e.s addition of H and OH across a C=C
              double bond to give alc ohols. This is an electrophilic addition of H2O to the alkene.
              Alcohols can be prepa red by adding water to an alkene in the presen ce of a strong
              acid such as co. H2SOO4. Because these reactions follow Markovnikov's rule, the
                                                                       º     º
              product of the reaction is often a highly substituted 2 or 3 alcohol.
                 Ease of preparation is tert. > sec. > prim alcohol; ease of dehydr ation follows
                 same sequence.
(a) By reaction with aldehydes & ketones: The reaction of Grignard reagents with
formaldehyde produces a primary alcohol, with other aldehydes, secon dary alcohols
and with ketones, tertiary alcohols. In this method alcohol is prepa red with the
formation of new carbon-carbon bonds.
                                   0
All other aldehydes yield 2 alcohols on reaction with Grignard reagents.
                                                            OH
                           CH3           i ether
         CH CH MgBr                                CH3CH2 CHCH3
                                                                 +
                   32                       C O         ii H O
                                        H                            3
                 CH3 H                                                             CH3
    CH3   CH C           O
                               +
                                       CH3MgI           H+               CH3       CH CH OH
                                                  0
With ketones, Grignard rea gents give 3 alcohols.                                                  CH3
                                                                               CH3
                         CH3                  i ether
                                                                               C              OH
  CH3CH2MgBr                       C O              + CH3CH2
                                              ii H3O
                         CH3                                                   CH3
(b) By reaction with esters: Produces tertiary alcohols in which two of the
substituents on the hydroxyyl- bearing carbon are derived from the Grignardd reagent.
               O
                                      MgBr
               C    OCH2CH3
                                               NH +
                                                    4                C    OH
          (c) By reaction with epoxxides: Grignard reagents react with epoxide to yield primary
          alcohols containing two or more carbon atoms.
The reaction is much slower than the reaction of water with sodium. Alcohols tend to
be slightly less acidic (pKa = 15) compared to water (pKa = 14). The higher the pKa
value the lower is the acid strength. The reaction of alcohol with sodium can be used
to deposite the excess sodium in the laboratory. Even alcohols are neutral to litmus
and do not reacts with alkali like NaOH but contain active hydrogen atom so reacts
with Na or K metal.
    ++              NaOH                          H2SO4                 +
H        CH3 ONa                 CH3 OH                       CH3     OH2
          Sod.      Strong       Methanol        Strong       Protonated
          methoxide base                         acid         methanol
(i) The lower alcohols are colourless liquids with a characteristic smell and a burning
taste. The higher members (with more than 12 carbons) are colourless wax like solids.
(ii) Because of hydrogen bonding, alcohols tend to have higher boiling points than
comparable hydrocarbons and ethers of similar molecular weight. Alcohols exists
associated molecules due to the association of molecules in the liquid phase through
strong intermolecular hydrogen bond between hydrogen atom of one molecule and
oxygen atom of another molecule. The oxygen-hydrogen bond is polar because
oxygen is much more electronegative than hydrogen. The lowers members have low
boiling points. With the increase in molecular weight, the boiling points keep on
increasing gradually. For example, the boiling point of butyl alcohol is 118°C whereas
the boiling point of the isomeric diethyl ether is 36°C.
(iii) Solubility: The general rule in solubility is “like dissolves like.” The hydroxyl group
generally makes the alcohol molecule polar and therefore more likely to be soluble in
water. Hydrogen bonding also has an effect on water solubility. The OH groups of an
alcohol can hydrogen bond with water, and so this portion of the alcohol is hydrophilic.
On the other hand, the alkyl chain in an alcohol is similar to hydrophobic molecules like
hydrocarbon that do not mix with water. Compounds like alcohols that have hydrophilic
and hydrophobic regions are called ambiphilic (or amphiphilic). The water solubility of a
given alcohol depends on whether the hydrophilic OH or the
hydrophobic             alkyl         chain            dominates.         Alcohols      with    shorter         carbon   chains
(CH3OH,CH3CH2OH, CH3CH2CH2OH) are usually more soluble than those with longer
carbon chains because the increasing size of the nonpolar chain disrupts the hydrogen
bonding network. Formation of hydrogen bonds with water will increase their solubility.
That is why alcohols are much more soluble in water than their corresponding alkanes,
aromatic hydrocarbons, alkyl halides or aryl halides. Amongst isomeric alcohols, the
solubility increases with branching.
(iv)The B.P. and M.P. will also increase with carbon chain length. The longer the
alcohols carbon chain, the better the chance that the alcohol will be a solid at room
temperature. Alcohols show higher boiling points than alkane and ethers of similar
mass due to hydrogen bonding. Since there is not any possibility of hydrogen bonding
in ether, the forces between the ether molecules are much weaker and can be much
more easily vaporized.
                                                                        CH3CH2CH2CH2CH2CH2CH2CH2OH
    CH3CH2OH
                                                                                       Insoluble in water
      Soluble in water                             O
                                       H                 H
          O
                                  O
  H             H
                            H3C       H
                                           R                   R
                            R                  O
                                                                    ..... O       H
                                  O        H ..... OH          H
                                          H
(v) The viscosity of small alcohols is much higher than the viscosity of alkanes.
(vi) Generally alcohols are lighter than water, i.e., less dense than water. Density of
      alcohols increases with molecular mass.
CHEMICAL REACTIONS OF ALCOHOLS:
     Alcohols acts both as nucleophiles as well as electrophiles. The bond between O-H is
     broken when alcohols react as nucleophiles and the bond between C-O is broken when
     they react as electrophiles. The chemical properties of any given aliphatic alcohol depend
     on the nature of the alkyl group and on the properties of the hydroxyl group. Based on the
     cleavage of O-H and C-OH bonds, the reactions of alcohols may be divided into two
     groups:
                                                  +
       ROH + CH3COCl                 ROCOCH3          HCl
     (B) Reaction involving fission of R—OH bond (cleavage of C—O bon                 d): The
     reactions involving R – OH bond with cleavage of C – O bond are as follow
     For primary alcohols, the conditions required are conc. sulphuric acid and temperature
           0
     of 170 C.
                     +
                    H
                                                              +
     ROH                      ROH                         R              +        alkene
                                        2
                                                +
                                                                    -   H
                                            H
     CH3CH2CH2CH2OH                                   CH CH         CHCH
                                                          3                       3
                CH3                           +
                                            H
              C      CH2OH                          CH3       C    CH           CH3
     CH3
              CH3                                             CH3
                                                          +
                                                    CH2OH2
                CH2OH          H+
In smaller ring always ring expansion takes place due to molecular strain and they
tend to convert to high stability with large ring.
OH
                             H3PO4
                                                                    +    H2O
                                    _         0
                             160        170     C
           C H3                20   %         H2SO4
                                                                  H3 C      C             C H2
 H3C C              OH
           CH                                                               CH        3
                3
The main function of the acid is to transform the poor leaving group — OH into the very
good leaving group —OH 2 . The order of the relative ease of dehydration of alcohols is:
 0   0    0
3 >2 >1
Tertiary carbocations are most stable and therefore are easier to form than secondary and
primary carbocations; tertiary alcohols are the easiest to dehydrate.
        CH3                   CH3                   H                   H
CH3 C                  CH3     C             CH3    C             H C
        CH3                   H                     H                   H
Dehydration of secondary and tertiary alcohols containing more than three carbon atoms
will give a mixture of alkenes, the major product can be deteermined from Satzeff’s
Rule:
Mechanism:
(b)
                                                              0
When the dehydration is carried out at a temperature of 140 C with an excess of alcohol
ether will be formed. Thiss reaction removes a molecule of water from two alcohol
molecules, causing the two ―R‖ groups to become att ached to an oxygen a tom,
forming an ether functional group:
  2                  Con.H 2SO4
      CH3CH2OH                                                    +
                                        CH3CH2         O CH2CH3       HO
                                                                       2
(a) Reaction with hydrogen halides: Respective alkyl halides are formed by reacting
with the appropriate hydro gen halide, HCl for chlorination, HBr for bromination, and HI
for iodination. The rea ction involves the initial protonation of the hydroxyl group of the
alcohol. This improves the leaving group ability of the hydroxyl group.
                      HCl
                                 R Cl        +        H2O
                      HBr
      R OH                   R          Br       +   H2 O
                      HI
                                 R I         +       H2 O
Mechanism:
Step1: Protonation of the alcohols: The alcohol acts as a weak base an d accepts the
proton donated by the hydrogen halide.
                     3                                                              3
                      ROH +              PBr3                                           RBr      +   H PO
                                                                                                      3     3
                     3                                                              3
                         ROH +            PI                                            RI       +   HPO
                                               3                                                      3     3
            ROH          +           +                              +
                                 H                      R       O           H
                                                                H
Step 2: Removal of a water molecule and formation of halide through SN2 mechanism/
SN1 mechanism as:
                                 +
                                                                        R-CH 2-X
X           RCH2O H
                  H
                                                                R
                                                                        +
                 +
     R3C O                                                      C
                     H
                                                        R                       R
             H
                                                                            R
                         R
                             +                                              C
     X                   C                                                               R
                 R               R                          X                   R
                                               0    0           0
(iii) Rate of the reaction for 1 , 2 and 3
The rate can be shown by the turbidity in the aqueous layer since the chloroalkane
formed is immiscible with water.
(b) Reaction with thionyl chloride, SOCl2: Alcohols will react with thionyl chloride
to produce alkyl halides. The reaction involves a nucleophilic attack of the alcohol on
a SOCl2 molecule displacing one of the chlorides. Then the chloride will act as the
nucleophile in a second step and displace the oxygen from the carbinol carbon.
    R OH     +       SOCl
                                 2                 R Cl     +   SO2             +       HCl
(c) Reaction with phosphorus halides
The mechanism is very similar to the thionyl chloride reaction. The alcohol acts as the
nucleophile and displaces a halide ion from the PX3 or the PX5.
   R-OH         +       P C l5                     R-Cl+           H C l + P O C l3
3. Esterification: Alcohol reacts with carboxylic acids, acid chlorides and acid
anhydrides to form esters. The reaction with carboxylic acid and acid anhydride is
reversible, and therefore, water is removed as soon as it is formed. Esterification takes
place much faster in the presence of a catalyst such as conc. H2SO4.
Example :
                                                                              O
                                     Con.H2SO4
CH3CH2COOH              + CH3CH2OH                              CH3CH2        C OCH2CH3     +   H2O
                                                    Reflux
Alcohols can also react with acid chlorides and acid anhydrides to form esters. The
introduction of acetyl (CH3CO) group in alcohols or phenols is known as acetylation.
Example:
                         O                                                            O
                                 +                                                       +            HCl
     CH3CH2         C    Cl           CH3CH2OH                            CH3CH2 C OCH2CH3
            O
                                                                          O
CH3CH2      C                                    Con.H SO
                                                      2     4
                O+CH             3
                                     CH OH
                                        2
                                                                 CH3CH2   C OCH2CH3   +   CH3CH2COOH
 CH3CH2     C
            O
          3. Oxidation: Alcohols can be oxidized by various oxidizing agents to aldehyde, ketones
          or carboxylic acids. Oxidation is the gain of oxygens and /or the loss of
                                                                           hydrogens.
                       OH
                                                                   O
                                          [O]
                       C                                  C
                                    oxidising agent
                       H
               0
          (a) 1 alcohol oxidizes readily, first to an aldehyde, then to a carboxylic acid. These two
          oxidation steps make sense because the primary alcohol functional group has two C-H
          bonds that can be broken. Primary or secondary alcohols can be oxidized to produce
          compounds containing the carbonyl group (a carbon-oxygen double bond, C=O). Strong
          oxidizing agents such as hot alkaline KMnO4 or CrO3 in H2SO4 will oxidize primary
          alcohols right past the aldehyde to the salt of the carboxylic acid in which the acid may be
          precipitated by acidification. The alcohol, aldehyde and acid retain the same number of
          carbon atoms.
                                                              O
                                  [O]
              RCH2OH                                  R       C H+H2O
                             oxidising agent
                                                               O
                                    [O]
              CH3CH2OH                            CH3         C H+H2O
                              oxidising agent
                                                                          O
                                           [O]
                           CH2OH                                         C H
                                     oxidising agent
    0
b. 2 alcohol has only one C-H bond that can be broken, so it can only oxidize once, to a ketone,
which cannot be oxidized any further:
                    H
                                                             R
          R         C    OH
                                    _2   H                       C O
                    R'                                   R'
               0
           3 alcohol                               Ketone
                     OH                                          O                                       O
                                         [O]                                          [O]
         CH3        CH    CH3                       CH           C CH                              CH3   C   OH+HO
                                                         3                       3                              2
                          OH                                             O
                                     [O]
                                                                             +       H2O
               0
         c. 3 alcohol has no C-H bonds that can be broken, so it is not oxidized, no matter how
         strong the oxidizing agent because it would involve the breakage of the high energy
         C—C bonds in the alcohol molecule.
                         CH3
                                          [O]
               CH3       C OH                      No oxidation product
                         CH3
                                     0
         In acidic solutions, 3 alcohols can he oxidized to give a mixture of ketone and acid,
         both with fewer carbon atoms than the alcohol.
                          CH3                                        O
                                             [O]
                                                                                        +
                   CH3    C    OH                     CH3            C       CH3            CH COOH
                                                                                               3
CH2CH3
DIHYDRIC ALCOHOLS:
      These compounds contain two hydroxyl      (–OH) groups in a molecule. These are
      dihydroxy components of alkanes. Their general formula is CnH2n+2O2. The simplest
         and most important dihydric alcohol is ethylene glycol. They are classified as α, β,γ.....
glycols, according to the relative position of two hydroxyl groups. α is 1, 2 glycol, β is
1, 3 glycol.
                                          CH2 OH
         CH2 OH
                                          CH2
         CH2 OH
                                          CH2 OH
    Nomenclature: For naming polyhydric alcohols, the name of the alkane is retained and
    the ending -e is not dropped but add a di- or tri- prefix to the –ol suf fix. Thus dihydric
    alcohols are named as alkane diols and trihydric alcohols are named as alkene triols.
                                                              OH
        CH2        OH
                                                                                   OH               OH
         CH2       OH                                                       CH3     CH        CH2   CH      CH3
                                                          OH
          eth - 1,2 - diol                  trans - 1,2 - cyclobutanediol             ,   -   pentadienol
                                                                                     24
                                                        OH
                               2             4
                    HO                                   6        7
                           1            3           5
                     ,              -
                    3 3 - diethyl       1,6 -     heptanediol
METHODS OF PREPARATION
From ethylene: (a) through icy dilute alkaline solution of Bayer's reagent.
                                                                                   CH2                       Ag 200
                                            (i)
                                                  dil.KMnO4
                                                                                  (c) With HOCl followed by
                                            (ii) OH                               hydrolysis:
               C    C
RCOOH
       CH2           -              catalyst
                      1
                   + 2    O2
                                                    _         0
                                                        400   C
    C C
    OH OH
syn hydroxilation                                                                                                             H2O             CH2       OH
                                                                                                                              dil.HCl         CH2       OH
                                                             OH                                    O
                         OH/H
                                                       C C
       O                                               OH
                                                           anti hydroxilation
                  CH2                                                     CH2       OH
                             +       HOCl                                                      NaHCO3                   CH2         OH
                                                                                                                                          +
                  CH2                                                         CH2   Cl                                  CH2         OH        NaCl + CO2
            CH2         Br           +                                                   CH2       OH
                                            Na2CO3           +   HO                                              2
                                                                                                                               + CO
            CH2         Br                                        2
                                                                                                             +
                                                                                                                     NaBr            2
                                                                                         CH2       OH
(ii) It is miscible in water and ethanol in all proportions but is insoluble in ether.
                                                                              0
     1. Action of Sodium: It reacts with Na at 50 c to form to form mono and dialkoxide
        at elevated temperature.
                                                  0                                          +
          CH2         OH                     50         C               CH 2 ONa                              1
                             +    Na                                                                  +       2
                                                                                                                      H
                                                                                                                           2
CH2 OH CH2 OH
                        +                         0                                          +
          CH2 ONa
                             +    Na
                                        160             C               CH 2 ONa                              1
                                                                                                      +               H
         CH2          OH                                                CH2            ONa        +           2                2
              CH2                                        0                   CH2
                       OH+             HCl         160       C                         Cl
                CH2    OH                                                     CH   2    OH
                                                                                                          +H           2
                                                                                                                           O
              CH2 Cl                              200
                                                            0   C
                                                                         CH 2 Cl
                                  + HCl                                                                   +
              CH2      OH                                                CH2           Cl                     H2 O
              CH2 OH                                                        CH 2        Br
          3                       +    PBr   3
                                                                        3                                         2
                                                                                                              +
                                                                                                                      H3PO4
           CH2        OH                                                    CH2              Br
PI3 produce ethylene diodide which is unstable and split into I2= and ethylene
+ I2
4. Reaction with carboxylic acid: Gives diester depending upon the amount of glycol
   and acid taken:
  CH2      OH
                      +       CH3COOH                              CH2           OCOCH3
                                                                                                           +   H2O
  CH2      OH                                                      CH2    OH
                                                                  glycol monoacetate
 CH2 OCOCH3
                          +       CH3COOH H2SO4                             CH2 OCOCH3
 CH2       OH                         in excess                             CH2 OCOCH3
                                                                                glycol diacetate
       With dibasic acid it form polymer:
                                                            CH2 OH                                 O                        O
     HOOC                                 HO
                                       COOH           + n
                                                                                       C                        C OCH CH O H
                              n H2O                                                                                         2   2   n
                                                                   OH
                                                  n         CH2
                                                                                                               terylene
              trephthalic acid
5. Reaction with aldehyde and ketones: Glycol reacts with aldehyde and ketones in
   presence of p- toluene sulphonic acid to give cyclic acetals/ketals which further
   may give ketone/aldehyde while treating with HIO4. This reaction thus can be
   useful to protect carbonyl group.
                                                 R
        CH2      OH               +    O     C                                         O               R
        CH2      OH                              H                                             C               +H2O
                                                                                       O               H
                                                 R
       CH2      OH            +        O    C                                      O           R
                                                                                           C               +
                                                                                                                H2O
       CH2       OH                              R                                 O           R
                O             R                                                                R
                                            HIO4             2
                      C                                          CHCO   +          O       C
                O             R                                                                R
6. (i) The oxidation of ethylene glycol with HNO3 to yields anumber of substance as
   follow:
                                          CHO
                                           CHO
                                          glyoxal        CHO
                                                                            COOH
    CH2 OH                 CHO
                                                         COOH
    CH2      OH             CH2     OH                            COOH
    glycol              glucollic
                        aldehyde                    glyoxylic acid oxalic   acid
                                         COOH
                                     CH2 OH
                                     glycollic acid
   (ii) Oxidation with KMnO4 or K2Cr2O7 to form formic acid:
        CH2                                     O
                 OH    KMnO4
        CH2      OH or K Cr O
                                          2   H C OH
                          2     2   7
        glycol
   (iii) Oxidation with Pb (OCOCH3)4 or HIO4 glycol gives formaldehyde.
           CH2     OH                                         O
                               Pb(OCOCH3)4
        CH2          OH                             2H       C     H
        glycol                  or HIO4
     CH2     OH
                              ZnCl2
     CH2      OH                                         CH3CHO    +   HO
                                                                       2
     glycol
                             0
(ii) When heated alone at 500 C, it gives ethylene oxide.
     CH2 OH
                               heat                  O
     CH2         OH                                               +    HO
                                                                           2
      glycol
(iii) Dioxane is obtained when glycol is heated with conc. H2SO4.
    HO CH2            CH2 OH
                                                             CH2        CH2
                                        H2SO4                                   +2
                 +                                       O                     O H2O
    HO CH2            CH2 OH                                 CH2        CH2
2. Due it has a high viscosity, so it is used in the hydrolic break , printing ink ball,
   pen inks, organic solvents .
TRIHYDRIC ALCOHOL
     It is a triol. The introduction of third –OH group in diol molecule raises the b.p. about
        0
     100 C, increase viscosity and make the alcohol more sweet. Viz; glycerol
                                    CH2OH
CHOH
CH2OH
METHODS OF PREPARATION
     1. From fats and oil: On hydrolysis of fats and oils, glycerol and higher fatty acids are
        formed.
            CH2OOCR                                CH2OH
                                +
            CHOOCR                  3HO                    +    3
                                     2             CHOH          RCOOH
            CH2OOCR                                CH2OH
     2. By fermentation of sugars: Alcoholic fermentation of sugar in the presence of
        sodium sulphite gives good yield of glycerol.
                                           CH2OH
                         yeat               CHOH
         CH O                                      + CH3CHO +   CO2
            6   12   6
CHEMICAL REACTIONS
                                                                 0                                   0
     Glycerol molecule contains two 1 – OH groups and one 2 – OH group. Thus, it
     shows characteristics of both primary and secondary alcohols.
                                    0                                                     0
     In general, 1 – OH groups are more reactive than 2 – OH group.
     1. Reaction with sodium: Only primary alcoholic groups are attacked one by one and
          secondary alcoholic group is not attacked, Sodium forms monosodium glycerolate
          at room temperature and disodium glycerolate at higher temperature.
            CH OH                                           CHONa                         CH2ONa
                       2                  Na                 2            Na
            CHOH                                            CHOH                            CHOH
                                         Room tem.                     High tem.
                 CH OH                                       CHOH                             CH2ONa
                       2                                     2
            CH2OH                                                CH2          Cl
                                                                                      +
            CH2OH               +   PCl5                         CH       Cl              3 POCl          3
                                                                                                3    +        HCl
         CH2OH                      CH2 Cl
     3. Reaction with HCI or HBr: When HCI is passed into glycerol at 110°C, both , α or
          β glycerol monochlorohydrins are formed. If the HCI gas is passed for sufficient
          time, glycerol α, α’ dichlorohydrin and glycerol, α,β- dichlorohydrin are formed.
    CH2    OH                           0           CH2          Cl                      CH2    OH
                                  110    C
    CH    OH +          HCl                         CH       OH                 +         CH    Cl
   CH2    Cl                       CH2        Cl
   CH     OH            +          CH        Cl                   Excess of HCl
                                                                            0
  CH2 Cl              CH2 OH                                          110    C
 Same reactions occur with HBr.
   formed. First tri iodide is formed but due to large size of iodine atom I2 comes out
   from product.
 (b) When glycerol is heated with a large amount of HI, the allyl iodide first formed is
     reduced to propene, which in presence of excess of HI forms iso-propyl iodide.
    CH2                                      CH3                       CH3                            CH3
   CH          +   HI                        CHI     _
                                                         I
                                                                                CH +HI                CHI
   CH2I                                                      2
                                            CH2I                      CH2                            CH3
5. Reaction with HNO3: When one part of glycerol in a thin stream is added to three
   times conc. HNO3 and five parts of concentrated sulphuric acid, nitro-glycerine
   (glyceryl trinitrate) is formed.
6. Reaction with acetic acid, acetic anhydride or acetyl chloride: Mono-, di- and tri-
   esters are formed.
    CH2OH                                 CH2OCOCH3                                      CH OCOCH
                     CH3COOH                                       CH3COOH                 2              3
    CHOH                                  CHOH                                           CHOH
                   or CH3COCl                                     or CH3COCl
    CH2OH                             CH2OH                                              CH OCOCH
                                                                                           2              3
                                   CH2OCOCH3
                                   CHOCOCH3
                                   CH2OCOCH3
7. Reaction with oxalic acid: Different products are formed under different
   conditions.
               0
   (a) At 100 C and with excess of oxalic acid, formic acid is formed
                                                                            O
     CH2OH                                                               CH2O C
                                                                                                CH OOCH
                                                                                                      2
                                          _
                                      100 110 0
                                                      C
                                                                     CH2OH                     H2 O
                                                                    CHOH
                                                HCOOH         +
                                                                    CH2OH
               0
   (b) At 260 C allyl alcohol is formed
   CH2OH                                                          CH2OOC                       CH2
    CHOH+ HOOC                 COOH                               CHOOC_
                                              _2H O                          2CO2               CH
                                                  2
   CH2OH
                                            CH2OH                   CH2OH
8. Dehydration: Glycerol when heated alone or with dehydrating agents such as
   potassium hydrogen sulphate or phosphorus penta oxide or conc. sulphuric acid,
   acrolein or acrylaldehyde is formed which has a characteristic bad smell. This
   reaction can be used as a test of glycerol.
   CH2OH                                        CH2
                                                              2
    CHOH              KHSO4 or                  CH        +        HO
                                                                     2
                       P2O5 heat
   CH2OH                                        CHO
   9. Oxidation: Glycerol gives different oxidation products depending on the nature of
         oxidizing agent. The following products may be obtained during oxidation of
         glycerol.
(b) Conc. HNO3 oxidises glycerol into glyceric acid and tartronic acid.
   10. Formation of resin: Glycerol reacts with phthalic anhydride forming polyesters
         known as glyptals. Each of the three –OH groups in glycerol forms an ester
         linkage with the anhydride, giving a thermosetting polymer (plastic) used for
         making synthetic fibers.
                              O
                              C                                             CH       CH2   OH
         n                                       O+HO          CH2
                                                                            OH
                              C
                                                           g ly c e r o l
                               O
             p h th a lic a n h y d r id e
               O                       O
                                                                                       O
              C                       C
                                                           CH            CH2     O     C
                                             O    CH2
                                                           O
                                                                                       O   C
                                                           C         O
                                                                                               O
                                                               C     O
                                                               O
                                                 glyptal
          CH2OH
                      CrO3
                      H2SO4
OH PBr3
1. Satuzaff’s rule
2. Glyptal
4. Synthesis of glycerol
2. Glycerol is a:
A.H2SO4                                    B.Al2O3
C.H3PO4                                          D. All.
A. Butan-2-ol B.Ethane
C.Butane D.Pentane
                                           H2, Pt
A.Cyclohexanol                                       B.Cyclohexane
C. Cyclohexene D. 1,2-cyclohexanediol
        O                   (i) L iA lH 4
                                                 ?
                              (ii) H 2 O
OH O
A. B.
        OH
 C.                               D.
9. What is the product in following reaction?.
                    O
                                                 NaBH4
                                                         ?
                          H
                                     CH3CH2OH
A. OH B.
C. OH D.
OH
hexanol D. 2,2-dimethyl-5-pentanol
hydroxyethyl)octane D. 6-methyl-3-propyl-2-heptanol
compound? CH3
                    OH
A. cis-3-methylcyclohexanol                           B. cis-5-methylcyclohexanol
C. trans-3-methylcyclohexanol D. trans-5-methylcyclohexanol
                                                  OH
A.                             B.
            OH
                                                          OH
                 OH   OH
                                D.
 C.
        OH
14. What is the hybridization of the oxygen atom in alcohols?
                                                  2
A. sp                                     B. sp
        3                                     3
C. sp                                     D. sp d
A. CH3OH B. CH3CH2OH
C. CH3CH2CH2OH D. CH3CH2CH2CH2OH
16. Which of these five-carbon alcohols would you expect to be most water soluble?
                                                             OH
     A.
                           OH        B.               C
                                     D.                     OH
      C.                OH
                         O
 A.                      C OH          B.           CH2OH
                         O
                         C H           D.           CH2OH
  C.
                     O                                                     +
                                                 Ether                HO
                                   +                                   3
C CH3 CH3MgBr
                     OH                                          OH
 A.                                      B.
                     C                                   CH2          CH CH3
                             CH3
                     CH3
                                                         OH
 C.                  CH
                                            D.           CH       CH2CH3
                              CH2OH
                     CH3
19. Arrange the compounds in order of increasing solubility in water (least first).
             O                          OH
                                                                                       O
CH3CH2CH2C       H           CH3CH2CH2CH2        CH3CH2CH2CH2CH3               CH3CH2CH2CH3
      I                           II                       III                         IV
1.17 ANSWERS(MCQs):
1.18 REFERENCES
                                                     th
1. Jerry march, Advanced Organic Chemistry, 4 edition, Wiley India,                2010.
                                                               nd
2. P.S. Kalsi, Organic Reactions and their Mechanisms, 2            edition, New
  age International Publishers. 2017
3.S.M. Mukherji and S.P. Singh, Reaction Mechanism in Organic Chemistry.
  Trinity Press, 2016