Mensuration for Bank Exam – Question Bank Set 1 (Eng)
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               Mensuration for Bank Exam – Question Bank Set 1 (Eng)
1) The circumference of a circle is one-third of the
perimeter of a rectangle. The area of the circle is                    4) A wire is looped in the form of rectangle whose
2464 m2. What is the area of the rectangle, if the                     area is 96 cm2 and the ratio of the length to
breadth of the rectangle is 120 m?                                     breadth of the rectangle is 3:2. If the same wire is
A.18560 m2                                                             looped in the form of circle, what is the area of
B.17280 m2                                                             the circle?
C.16720 m2                                                             A.1400/11 cm2
D.19340 m2                                                             B.1300/11 cm2
E. None of these                                                       C.1500/11 cm2
                                                                       D.1200/11 cm2
2) The area of the circle is 1386 cm2 and the ratio                    E. None of these
of the breadth of the rectangle to radius of the
circle is 4:3. If the circumference of the circle is                   5) The ratio of the radius and height of a right
equal to the perimeter of the rectangle, then what                     circular cone is 3: 4. If the curved surface area of
is the area of the rectangle?                                          the cone is 135π m2, find the total surface area of
A.1032 cm2                                                             the cone.
B.1048 cm2                                                             A.116 π m2
C.1056 cm2                                                             B. 216 π m2
D.1064 cm2                                                             C.210 π m2
E. None of these                                                       D.110 π m2
                                                                       E.196 π m2
3) If the ratio of the height to radius of the cylinder
is 3:2 and the curved surface area of the cylinder                     6) Length and breadth of a rectangle is x cm and
is 1848 cm2. If the radius of the cylinder is equal                    (x – 8) cm respectively. If the area of the square
to the radius of the cone and the height of the                        is 324 cm2 and the perimeter of the square is 8
cone is 9 cm, then what is the volume of the                           cm more than that of rectangle, then find the area
cone?                                                                  of the rectangle?
A.1448 cm3                                                             A.300 cm2
B.1648 cm3                                                             B.320 cm2
C.1948 cm3                                                             C.280 cm2
D.1848 cm3                                                             D.240 cm2
E. None of these                                                       E. None of these
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               Mensuration for Bank Exam – Question Bank Set 1 (Eng)
7) The circumference of two circles is 132 metres                       9) If the ratio of the radius of the circle to the
and 176 metres respectively. What is the                                cylinder is 1: 2 and the height of the cylinder is 8
difference between the area of the larger circle                        cm more than the radius of the cylinder. If the
and the smaller circle?                                                 circumference of the circle is 22 cm, then what is
A.1078 m2                                                               the volume of the cylinder?
B.1152 m2                                                               A.2110 cm3
C.986 m2                                                                B.2210 cm3
D.854 m2                                                                C.2310 cm3
E. None of these                                                        D.2410 cm3
                                                                        E. None of these
8) The perimeter of a rectangular field is twice the
perimeter of a square field. If one of the sides of                     10) The ratio of the radius to height of the cylinder
the square field is 20 m and breadth of the                             is 7: 8 and the radius of the cylinder to side of the
rectangular field is 30m, then find the area of the                     square is 2: 3. If the volume of the cylinder is
rectangular field?                                                      9856 cm3, then find the perimeter of the square?
A.1250 m2                                                               A.72 cm
B.1300 m2                                                               B.76 cm
C.1350 m2                                                               C.80 cm
D.1500 m2                                                               D.84 cm
E. None of these                                                        E. None of these
                                              ANSWER WITH EXPLANATION
1. Answer: B                                                            528 = 2*(l + 120)
Area of a circle = πr2                                                  264 = l + 120
2464 = 22r2/7                                                           l = 264 - 120
2464*(7/22) = r2                                                        l = 144
r2 = 784                                                                Area of the rectangle = 144*120 = 17280 m2
r = 28 m
Circumference of a circle = 2πr = 2*(22/7)*28 =                         2. Answer: D
176 m                                                                   Area of the circle=∏ * r * r
Perimeter of the rectangle = 3*176 = 528 m                              1386=22/7 * r * r
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                Mensuration for Bank Exam – Question Bank Set 1 (Eng)
Radius of the circle=21 cm                                             70/11 =r
Circumference of the circle=2 * ∏ * r                                  Area of the circle=22/7 * 70/11 * 70/11
=2 * 22/7 * 21                                                         =1400/11 cm2
=132 cm
Breadth of the rectangle=4/3 * 21=28 cm                                5. Answer: B
Perimeter of the rectangle=2 * (l + b)                                 The ratio of the radius and height of a right
132=2 * (l + 28)                                                       circular cone = 3: 4 (3x, 4x)
Length of the rectangle=38 cm                                          Slanting height of the cone = √ (32 + 42) = 5 (5x)
Area of the rectangle=l * b=38 * 28=1064 cm2                           The curved surface area of the cone = πrl
                                                                       => 135π = π * 3x * 5x
3. Answer: D                                                           => x= 3
Curved surface area of the cylinder= 2πrh = 2 *                        Radius of the cone = 3 * 3 = 9 m
22/7 * r * h                                                           Height of the cone = 4 * 3 = 12 m
1848 = 2 * 22/7 * 2x * 3x                                              Slanting height of the cone = 5 * 3 = 15 m
x = 7 cm                                                               The total surface area of the cone = πr (l + r)
Radius of the cylinder = 7 * 2 = 14 cm                                 => π * 9 * (15 + 9) = 216π m2
Radius of the cone = 14 cm
Volume of the cone = 1/3πr2h = 1/3 * 22/7 * r2 * h                     6. Answer: D
=1/3 * 22/7 * 14 * 14 * 9                                              Side of the square = (324)1/2 = 18 cm
=1848 cm3                                                              Perimeter of the square = 18 * 4 = 72 cm
                                                                       2 * (x + x – 8) = 72 – 8
4. Answer: A                                                           2x – 8 = 32
Perimeter of the rectangle = circumference of the                      x = 20
circle                                                                 Area of the rectangle = 20 * (20 – 8) = 240 cm2
Area of the rectangle=l * b
96=3x * 2x                                                             7. Answer: A
x =4 cm                                                                Circumference of circle1 = 132
Perimeter of the rectangle=2 * (l + b)                                 2πr1 = 132
=2 * (12 + 8)                                                          2*(22/7)*r1 = 132
=40 cm                                                                 r1 = 132*(7/44)
Perimeter of the circle = 2πr                                          r1 = 21
=>40=2 * 22/7 * r                                                      Circumference of circle2 = 176
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               Mensuration for Bank Exam – Question Bank Set 1 (Eng)
2πr2 = 176                                                             9. Answer: C
2*(22/7)*r2 = 176                                                      Circumference of the circle = 2 * 22/7 * r
r2 = 176*(7/44)                                                        2 * 22/7 * r = 22
r2 = 28                                                                Radius of the circle = 3.5 cm
Required answer = πr22 – πr12 = π*(r22 – r12)                          Radius of the cylinder = 2 * 3.5 = 7 cm
= > (22/7)*(282 – 212)                                                 Height of the cylinder = 7 + 8 = 15 cm
= > (22/7)*(28+21) (28 – 21)                                           Volume of the cylinder = 22/7 * r * r * h
= > (22/7)*(49)*(7)                                                    = 22/7 * 7 * 7 * 15
= > 1078 m2.                                                           = 2310 cm3
8. Answer: D                                                           10. Answer: D
Perimeter of square field= 20*4= 80m                                   Volume of the cylinder = 22/7 * r * r * h
Perimeter of the rectangular field= 160m                               9856 = 22/7 * 7x * 7x * 8x
Let the length of the rectangular field be x                           x = 2 cm
160= 2(x+30)                                                           Radius of the cylinder = 2 * 7 = 14 cm
160- 60= 2x                                                            Side of the square = 3/2 * 14 = 21 cm
x= 50 m                                                                Perimeter of the square = 4a = 21 * 4 = 84 cm
Area of the rectangular field= 50*30= 1500 m2
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