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of pyramid as 4, for which the pyramid structure will look like:
R
he pyramid is 36. Hence, 36 is returned as the outputV Neants ae Branham
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Question | EL rerwattaer | MVAIT 7 Commpter java
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AS a means of fevning Bruce's mental
ability, Andrew now presents
Broce with the values 21,22. and 25 ‘Cyr task ts to help Bruce find
ing the ong mal integer
1D Use Custom Input
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‘Qualifying Score
There «sa competition ina school The cutett to take part this
competition n having a qualifying score of 35 marks or more
There are M subjects Haught in a clas Marks obtained in each subject
anv semesters | and 2 are qrven i the form of am array S¥ and $2
respectively. The qualifying score #4 calculatect in the following way
© Step 1 Subtract marks abtamed in i® aubject m Semester 1
from marks obtained an i" subject en Seoesipe 2. S2 + STHL
where = O12
© Step 2 Add the maiks. cf upto P subjects with the mavimum
scores obtained after subtraction in Step 1. This wall gree a
studtents quaktying score, The ain #8 to get a score equal to or
greater than 35
Ut the quatying score is greater than or equal to 34 then the students
1s Qualihed to appear in the competition, else they are Disqualified
Your tack 1s to hd and retum a string value; representing the result
that 1s Qualified or Disqualified followed by the score achieved
(separated by a space)
Attempted O72
' JAYANT > Compiler
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. Public String d
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Input Specification «
Input © An integer value, representing the number . publle int #inaatine
inpunz : An intege ing the umb ead only ree
input : An inte nat the th *
write code he
new Unipg
Ovipst Specification
Example 1
inputt :
imputz
inpuss,( )
@ : uy |
findX(cls, input1, input2, input3):
x1 etal i) tf 2
es Oty iw 1) sf 2
(input3 >is ae
ent a)
((x3 & (1 << i)) I= @):
cnt += (1 << i)
fanaaExpected return type i
# Read only region end
w rite code here:
a= inputa
n= len(a)
s-0
for 1 in range(2°*(n-3)):
ans = @
ss = a[0]
for J dn range(n-t)e
if{i>>§)
ansreint(ss)
ss» afjel}
else:
sst~ aljel]
if foane2:
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f nest:
return strCa)
else:
| return ste(s)© The length of sing S is ciwoys ever. CO Use
Met! Online Assesement © ayNeed Help?
= (Please aid country
2021-2031
¥ ms
5 “code while dialing:Here in this «
perform the ss v trne f naney
way:
- pra {eof type 1. we convert
® The second of tye 1 we convert
» wie! Otani vert
awl string Obtained after dertorming jal
Henté, CERMER isee eee cee creep meee nee eee
Fal Pesve-iiar nacelles alia Geneniacionantel es
. Meer ri’ iri
inputs : (1.2.1)
| Output = BADC
Explanation:
Herein thes example. on the string “ACD” we can
Perform the sequence of operations on the following
* The t ation mw oltype 1, we convert
' | “ABCD te “DECA™
i
(@ The second operation is of type 2. we convert
) DECA* to “CADE
third Operation is of type 1. we convert
“CADE” ta “BADC™.
Therefore the final string obtained after performing all
the operations 1s BADC™.
hein? Cortact us (Plesse
r
rode while dialingrhe Sample cases
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eee he sre eu sea G same ul is)
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n = input2
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res = typel(res)
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1. Hands on Programm + o
Qualifying Score
There ws a competition inaschcol The cut-off to take part in thin
competion mn having @ qualtying score of 15 marks of more.
There are N subjects taught ina class Marks obtamed in each gubpect
wnvvemesters Vand 2 are qweninthe form of an aray $0 and $2
respectively The qualifying wore es calculated i the following wiry
© Step 1 Subtract marks obtamed ini sulyect in Semester 1
from marks obtained ina!” subject in Semester 2 be, $2[i] - S1fu),
8 where ie O12 w
® Step 2 Add the marks, cf upto P subjects weth the macinum
stores, obtined after subtraction in Step 1. This will quae a
student's quakfeng score. The air i to get.a score equal to or
greater than 35
If the qualifying score rs qreater than or equal to 25 then the students
1s Qualitied to appear in Lhe competition, ele they are Diquathed
Your tavk is to fm and return asteng value, representing the result
that + Qualified or Disqualified follawed by the score achieved
separated by a space,
ant Pm at Sentlan
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Note lavAt? + Compiler java 4
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iv
Input Specification
input | An integer value, representing the mumber 21 . publie Lit finge( lat
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input
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‘Output Specification:
Example 1
inputt
input?
inputs(cls, input1, input2, input3, input4):
eC ie eera oc o8|
eres ule
(res[:input2))}
(res{ :input2})}Question | (1 Revisit Later
How to Attempt?
Solve the Lquation
Give an iiteset ND your Lack 6 fo find andl return the number of vets of 1 porutive
yeadc thet satnty the following equation:
wethecrabebora N
integers a
Mote: ab and ¢ arn penitiwe intenpers, are thea wuss can the the arr
Input Specification:
“Jnput : An integer value N.
Output Specification:
Return an integer value, representing the mumber of sets of three polfive integers
that satisty the equation given above.
Example 1:
input 6
‘Output : 1
Explanation:
for N — 6, there is only one set of 3 integers that satisfies the equation a? + b? «
ab + be + ca = N
tester
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15 | return count
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3 class UserMainCode (object):
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7 input ; string
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14 for i in inputa:
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1 SELECT * From train_details tbl
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he query window on the right-hand side of the seraen,
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ow Question 1
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How to Attempt?
Write an SQL query to display.
The last name of
29 Instructor WHO is the colle,
Whose fast name ts ‘Bette and are IN the same
Your output Should ©ontain 4 Column yn, the Delo,
Order
“Mentioned
* View Schema tab
A the ty
9select o.last_name
from instructor o
Join department
e on o.dept_id= e.dept_id
where e.dept_id= (select dept_id
LCMV Cece) g
where last_name = 'Bette’)
and o.last_name<> ‘Bette’
Order by o.last_name;