Mini Lab Project Report
Voltage Divider and Selector Circuit
Department: Computer Science and Engineering (CSE)
Semester: Fall 2023
Course Code: CSE209
Course Title: Electrical Circuits
Submitted by:
Group Number: 02
Name: Student ID:
Afia Ayub Samirah 2022-3-60-012
Rebeka Sultana Dina 2022-3-60-027
Kha. Mo. Syeed Asif 2022-3-60-030
Sadia Reza 2022-3-60-073
Wasifa Motahara Raisa 2022-3-60-103
Submitted to:
Dr. Sarwar Jahan
Associate Professor
Department of CSE
East West University
Date of submission: 14-12-2023
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Problem Discussion
A 10V DC supply is available. In practice we need to use 10V, 5V, and 3V
as supply voltage of a low current electrical circuit. We have to design a
voltage divider circuit so that the desired voltage can be selected at the
output.
Voltage +
+ Divider
10V Output (10V, 5V or 3V)
- and
Selector
Circuit -
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Circuit Design
Figure: 01
Figure:2
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Figure:3
Figure: 4
We have used a 10V battery to power the circuit. Assuming the currents
i1 = 3 mA, i2 = 10 mA, and i3 = 10 mA in Figures 2, 3, and 4, we can
determine the resistor's value. We found a resistor that is equivalent to
those circuits. Demonstrate how to connect them to the circuits.
Here, R1=1000Ω
R2=1000 Ω
R3=1000 Ω
R4=1000 Ω
R5=1000Ω
R6=1000 Ω
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For figure 2, Applying Voltage Divider Rule, we get,
Req1= R1+ R2+ R3
→Req1=1000Ω+1000Ω+1000Ω
→ Req1=3000 Ω
𝑬
i1=
𝐑𝐞𝐪𝟏
𝟏𝟎
→i1=
𝟑𝟎𝟎𝟎
→i1=3mA.
Now, V1=i1×R3
→V1=0.003A ×1000 Ω
→V1=3V.
So, 3V will be across R3 resistor.
In figure 3, Applying voltage divider rule, we get,
Req2= R4+ R5
→Req2=1000Ω+1000Ω
→, Req2=2000 Ω
𝑬
i2=
𝐑𝐞𝐪𝟐
𝟏𝟎
→i2=
𝟐𝟎𝟎𝟎
→i2=5mA.
Now, V2=i2×R5
→V2=0.005A ×1000 Ω
→V2=5V.
So, 5V will be across R5 resistor.
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For Figure 4, there is only one resistor. So 10V will be across R6 resistor.
Experimental Results:
We have used PSpice to verify the experimental and theoretical value.
To get 3V, we have to turn on switch 1. From Figure 1, we can see that
the 3V is across R3 Resistor.
To get 5V, we have to turn on switch 2. From Figure 2, we can see that
the 5V is across R5 Resistor.
Similarly, if we turn on switch 3, we can find 10V is across R6 Resistor.
Measured value of Measured Value Measured Value Measured Value
E (v) of v1 (V) of v2 (V) of v3 (V)
10 3.3 5 10
Name Theoretically Measured Difference
Values Values
E 10 10 0.0
V1 3 3.3 0.3
V2 5 5 0.0
V3 10 10 0.0
Discussion: From this project we have measured the value of V1, V2
and V3 using PSpice, where we can see the Measured value of V1 is
difference from the theoretically value. This difference can be
negotiated.
Conclusion: In this experiment project, we had used a 10V battery.
Sometimes because of continuously using the battery, the voltage of the
battery could be fallen. By using the adopter source instead of the
battery, we can achieve better accuracy results.
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