Coordination Chemistry Basics
Coordination Chemistry Basics
Coordination Compounds
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(d and f block elements)
The molecules or ions that surround the central metal atom or ion
in a coordination compound are called Ligands or donor groups.
Example:
1. Cisplatin, [Pt(NH3)2Cl2] two NH3 molecules and two Cl- ions are ligands
2. K4[Fe(CN)6] six cyanide ions are the Ligands.
The atoms of ligand that are attached directly to the metal are called ligand
donor atoms.
Example: In cisplatin ‘N’ and ‘Cl’ are ligand donor atoms. Each ligand donor
atom contributes the share of one electron pair to form coordinate bond with
metal ion , as shown in cisplatin.
Types of Ligands:
Ligands are classified as monodentate and polydentate ligands depending upon the
number of donor atoms they have.
1.Monodentate ligands:
A monodentate ligand is the one where a single ligand donor atom shares an
electron pair to form a coordinate bond with the central metal ion.
Example:
The ligands Cl -, OH -or CN- attached to metal have electron pair on Cl, O and N,
respectively which are donor atoms :
NH3 molecule has only one donor atom i.e. nitrogen atom.
Hence it can be linked to the metal of complex only through ‘N’ atom.
2.Polydentate ligands:
A polydentate ligand has two or more ligand donor atoms linked to the central
metal ion.
Polydentate Ligands are further classified into bi,tri…………..hexa dentate depending
upon the number of ligand donor groups linked with the ligand.
i.Ethylenediamine binds to metal using electron pair on each of its two nitrogens.
It is a bidentate ligand
Similarly oxalate ion (C2O4)2- is also bidentate ligand. It bonds to metal ion using
electron pair of two ‘O’ donor atoms.
ii. Ethylenediaminetetraacetate ion (EDTA)4- binds to metal ion by electron pairs of
four oxygen and two nitrogen atoms. It is a hexadentate ligand.
A ligand that has two donor atoms but uses the electron pair of only
one donor atom to bond with central metal ion to form a coordinate bond is
called ambidentate ligand.
Example:
1.NO2- group has donor atoms(N and O) out of the two only one donor atom is
linked to the metal as M-ONO or M-NO2.
2.SCN- ions has two donor atoms (S and N) but only one can be linked to the
metal such as M ← SCN or M← NCS.
Terms used in coordination chemistry:
Coordination sphere :
The central metal ion and the ligands attached to it are always enclosed in a square
bracket. This is called a coordination sphere, which is a discrete structural unit.
When the coordination sphere comprising central metal ion and the surrounding
ligands together carry a net charge, it is called the complex ion.
The ionisable groups shown outside the square bracket are the counter ions.
The net charge residing on the complex ion is its charge number. It is algebraic sum
of the charges carried by the metal ion and the ligands. The charge carried by the metal
ion is its oxidation state (O.S.).
Double salt : A double salt dissociates in water completely into simple ions.
For example (i)Mohr's salt, FeSO4(NH4)2SO4.6H2O dissociates as :
Imp.1 Mark
ii. Carnalite KCl.MgCl2.6H2O dissociates as:
Postulate (i) Metal in a complex has two types of valencies: primary (ionizable)
valency and secondary (nonionizable) valency.
Postulate (ii) Primary valencies are ionizable and are satisfied by anions.In modern
terms,it is called oxidation state of metal
Postulate (iii) Secondary valencies are nonionizable and are satisfied by neutral
molecules or negative ions.In modern terms,we call it coordinatation number of metal.
Postulate (iv) Primary valencies are non rigid and non directional.Secondoray valencies
have directional properties therefore its number and positon determines geometry of the
complex
Postulate (v) In a complex, there are two types of spheres.
i) Coordination or inner sphere: In this sphere the groups present cannot be easily
separated as they are firmly attached to meta
ii) Ionisation sphere or outer sphere : The groups present in this sphere are loosely
bound and can be easily separated.
Experimental Observations:
1) a. Werner treated 1 mole of a purple coloured complex CoCl3 5NH3 with excess of
AgNO3 produces 3 moles AgCl Precipitate. This shows that 3 Cl- ions present in
ionization sphere.
b. When complex was heated with HCl, ammonia is not removed. This shows that it is
strongly bound to cobalt in coordination sphere. Therefore formula of the complex
is [Co(NH3)5 ]Cl3.
Problem: 1 mole of a green coloured complex of CoCl3 4NH3 on treatment with excess
of AgNO3 produces 1 mole of AgCl.What is the formula of the complex.
[Co(NH3)4Cl2]Cl
Classification of complexes:
Complexes in which a metal ion is attached to only one type of ligands are
homoleptic
Example: [Co(NH3)6]3+ .Here only one type(ammonia) of ligands are
attached to Co3+ ion
Heteroleptic complexes: Imp.1 Mark
Complexes in which a metal is bound to more than one type ligands are
heteroleptic.
Example: [Co(NH3)4Cl2]+
There are two types of ligands 4 ammonia and two Cl- are attached to CO3+ ion
Classification on the basis of charge on the complex
A coordination complex does not possess cationic or anionic sphere are called neutral
sphere complexes.
Example:[Pt(NH3)2Cl2] or [Ni(CO)4] have neither cation nor anion but are neutral
sphere complexes.
9.5 IUPAC nomenclature of coordination compounds :
4. After the name of the metal, write its oxidation state in Roman number which
appears in parentheses without any space between metal name and parentheses.
5. If complex has more than one ligand of the same type, the number is indicated with
prefixes, di-, tri-, tetra-, penta-, hexa- and so on.
6. For the complex having more than one type of ligands, they are written in an
alphabetical order. Suppose two ligands with prefixes are tetraqua and dichloro.While in
alphabetical order,tetraqua is first and then dicholro.
7. If the name of ligand itself contains numerical prefix then display number by prefixes
with bis for 2, tris for 3,tetrakis for 4 and so forth. Put the ligand name in parentheses.
For example,(ethylenediamine)3 or (en3) would appear as tris (ethylenediamine) or
tris (ethane-1,2-diamine).
8. The metal in cationic or neutral complex is specified by its usual name while in the
anionic complex the name of metal ends with 'ate'.
IUPAC names of anionic and neutral ligands
IUPAC names of metals in anionic complexes
IUPAC names of some complexes
It is the total number of electrons around the central metal ion
present in a complex
Calculated as the sum of the electrons on the metal ion and the number of
electrons donated by the ligands.
It can be calculated using the formula.
EAN= Z-X+Y
Where
Z= Atomic number of the metal
X= Number of electrons lost during the formation of the metal
ion from its atom.
Y= number of electrons donated by the ligands.
EAN Rule: Imp.1 Mark
“A metal ion continues to accept electron pairs from ligands till the total
number electrons present around the metal ion in the complex becomes
equal to the atomic number of the next noble gas atom.”
Thus if the EAN is equal to 18 (Ar),36 (Kr),54 (Xe), or 86 (Rn) then the EAN rule is obeyed.
2. Consider [Fe(CN)6]4-
3. Consider [Zn(NH3)4]2+
Isomers
STRUCTURAL
STEREO ISOMERS ISOMERS
COORDINATION SOLVATE
Isomers have the same connections among constituent atoms but a different
arrangements of the atoms in space are called stereoisomers
There are two kinds of stereoisomers in coordination compounds:
(a) geometric isomers or distereoisomers and (b) enantiomers or optical isomers.
These are non mirror image stereoisomers. These are possible in heteroleptic
complexes. In these isomers, there are cis and trans types of arrangements of ligands.
Cis and trans isomers have different properties. Cis and trans isomerism is
observed in square planar and octahedral complexes.
i.Cis and trans isomers in square planar complexes :
The square planar complexes of MA2B2and MA2BC type exist as cis and trans isomers,
where A, B and C are monodentate ligands, M is metal.
Example :[Pt(NH3)2Cl2],(MA2B2type) [Pt(NH3)(H2O)Cl2] (MA2BC type)
Here the cis isomer is more soluble in water than the trans isomer. The cis isomer
named cisplatin is an anticancer drug while the trans isomer is physiologically
inactive. The cis isomer is polar with non-zero dipole moment. The trans isomer
has zero dipole moment as a result of the two opposite Pt – Cl and two Pt-NH3 bond
moments, which cancel each other.
ii. Cis and trans isomers in octahedral complexes :
The octahedral complexes of the type MA4B2, MA4BC and M(AA)2B2 exist as cis and
trans isomers. (AA) is a bidentate ligand. [Co(NH3)4Cl2]⊕,(MA4B2 type)
b. Optical isomers (Enantiomers) :
The complex molecules or ions that are non superimposable mirror images of each
other are enantiomers. The non superimposable mirror images are chiral.
Enantiomers have identical properties however differ in their response to the plane-
polarized light. The enantiomer that rotates the plane of plane-polarized light to right
(clockwise) is called the dextro (d) isomer, while the other that rotates the plane to
left (anticlockwise) is called laevo (l) isomer.
Square planar complexes do not show enantiomers since they have mirror
plane and axis of symmetry.
Structural isomers (Constitutional isomers) :
Structural isomers possess different linkages among their constituent atoms but they
have same chemical formulae.
They can be classified as linkage isomers, ionization isomers, coordination
isomers and solvate isomers.
Imp.1 Mark
a.Linkage isomers :
These isomers are formed when the ligand has two different donor atoms.
It coordinates to the metal via different donor atoms.
Thus the nitrite ion NO2- having two donor atoms show isomers as :
Example:
where a, x, [a⊕ + nx- ] denote the charge on the metal, ligand and the complex,
respectively. Now, the equilibrium constant K is given by
Stability of the complex can be explained in terms of K.
Higher the value of K larger is the thermodynamic stability of the complex.
The equilibria for the complex formation with the corresponding K values are given
below.
From the above data, [Co(NH3)6]3⊕ is more stable than [Ag(CN)2]- and [Cu(CN)4]2- .
Factors which govern stability of the complex :
Stability of a complex is governed by
(a) charge to size ratio of the metal ion and (b) nature of the ligand.
a. charge to size ratio of the metal ion
Higher the ratio greater is the stability. For the divalent metal ion complexes their
stability shows the trend : Cu2⊕ > Ni2⊕ > Co2⊕ > Fe2⊕ > Mn2⊕ > Cd2⊕.
The above stability order is called Irving-William order.
In the above list both Cu and Cd have the charge +2, however, the ionic radius of Cu2⊕ is
69 pm and that of Cd2⊕ is 97 pm.
The charge to size ratio of Cu2⊕ is greater than that of Cd2⊕ . Therefore the Cu2⊕ forms
stable complexes than Cd2⊕.
b. Nature of the ligand.
A second factor that governs stability of the complexes is related to how easily the
ligand can donate its lone pair of electrons to the central metal ion that is, the basicity
of the ligand. The ligands those are stronger bases tend to form more stable complexes.
Example: CN- ion is more basic than NH3.Hence cyano complexes are more stable
than ammine complexes.
Valence bond theory (VBT) Assumptions of VBT
i. Central metal ion provides vacant d orbitals for formation of coordinate bonds with
ligands.
ii. The vacant d orbitals along with s and p orbitals of the metal ion take part in
hybridisation.
iii. The number of vacant hybrid orbitals formed is equal to the number of ligand
donor atoms surrounding the metal ion which equals the coordination number of metal.
iv. Overlap between the vacant hybrid orbitals of the metal and filled orbitals of
the ligand leads to formation of the metal- ligand coordinate bonds.
v. The hybrid orbitals used by the metal ion, point in the direction of the ligand.
vi. The (n-1)d or nd orbitals used in hybridisation allow the complexes to be
classified as (a) outer orbital and (b) inner orbital complexes.
Number of Orbitals and Types of Hybridisation
iv. From the number of ligands find the number of metal ion orbitals required for
bonding.
v. Identify the orbitals of metal ion available for hybridisation and the type of
hybridisation involved.
vi. Write the electronic configuration after hybridisation.
vii Show filling of orbitals after complex formation.
viii. Determine the number of unpaired electrons and predict magnetic
behaviour of the complex.
Octahedral complexes Imp.3 Mark
a. [Co(NH3)6]3⊕ [low spin or Inner orbital or spin paired complex]
i.Oxidation state of central metal Cobalt(Z=27 4s23d7) is +3
ii.Valence shell electronic configuration of Co3⊕ is represented in box diagram as
shown below :
iii. Number of ammine ligands is 6, number of vacant metal ion orbitals required for
bonding with ligands must be six.
iv. Complex is low spin, so pairing of electrons will take place prior to
hybridisation.
v. Electronic configuration after pairing would be
vi. Six orbitals available for hybridisation are two 3d, one 4s, three 4p orbitals
The orbitals for hybridization are decided from the number of ammine ligands which
is six. Here (n-1)d orbitals participate in hybridization since it is the low spin complex.
iii. Six fluoride F- ligands, thus the number of vacant metal ion orbitals required for
bonding with ligands would be six.
iv. Complex is high spin, that means pairing of electrons will not take place
prior to hybridisation. Electronic configuration would remain the same as in the free
state shown above.
v. Six orbitals available for the hybridisation. Those are one 4s, three 4p, two of 4d
orbitals
Six metal orbitals after bonding with six F- ligands led to the sp3d2 hybridization. The d
orbitals participating in hybridisation for this complex are nd.
vi. Six vacant sp3d2 hybrid orbital of Co3+ overlap with six orbitals of fluoride forming
Co - F coordinate bonds.
vii. Configuration after complex formation.
viii. The complex is octahedral and has four unpaired electrons and hence, is
paramagnetic.
Tetrahedral complex
[Ni(Cl)4]2-
i. Oxidation state of nickel is (Z=28 4s23d8)+2
ii. Valence shell electronic configuration of Ni2+
iii. number of Cl ligands is 4. Therefore number of vacant metal ion orbitals required for
bonding with ligands must be four.
iv. Four orbitals on metal available for hybridisation are one 4s, three 4p. The complex is
tetrahedral.
The four metal ion orbitals for bonding with Cl ligands are derived from the sp3
hybridization.
vi. Four vacant sp3 hybrid orbital of Ni2⊕overlap with four orbitals of Cl- ions.
vii. Configuration after complex formation would be.
viii.The complex has two unpaired electrons and hence, paramagnetic.
Square planar complex
[Ni(CN)4]2-
i. Oxidation state of nickel is(Z=27 4s23d8) +2
ii. Valence shell electronic configuration of Ni2+
iii. Number of CN ligands is 4, so number of vacant metal ion orbitals required for
bonding with ligands would be four.
iv. Complex is square planar so Ni2⊕ ion uses dsp2 hybrid orbitals.
v. 3d electrons are paired prior to the hybridisation and electronic configuration of Ni2⊕
becomes :
vi. Orbitals available for hybridisation are one 3d, one 4s and two 4p which give dsp2
hybridization.
vii. Four vacant dsp2 hybrid orbitals of Ni2⊕ overlap with four orbitals of CN ions to
form Ni - CN coordinate bonds.
vii. Configuration after the complex formation becomes.
1. CFT assumes that metal-ligand bonding is entirely ionic .It arises from electrostatic
attraction between positively charged metal ion and negatively charged ligands
2. Five d orbitals, dxy,dyz,dxz,dz2 and dx2-y2 in an isolated gaseous ion or atom are
degenerate that is they have the same energy.
3. When ligands approach metal ion, their electrons are repelled by electrons of metal
ion.As a result of this repulsion,d orbitals of metal ion raised in energy and split
into two groups, designated as t2g and eg. This splitting is called crystal field
splitting. The energy separation between two groups is Δo.
4. The axial orbitals, dz2 and dx2-y2 experience more repulsion and are raised eg level
of higher energy
The orbitals dxy,dyz,dzx that lie between the axes suffer lesser repulsion. They
are ,therefore lowered in energy relative to average energy. They are placed in t2g level
5. Strong field and weak field ligands
i. Strong field ligands:
In these ligands donor atoms are carbon, nitrogen or phosphorus .These ligands
produce relatively large value of Δo. Therefore, Δo > P where P is the pairing energy of
electrons. Thus it is easier to pair up electrons than to place them in either dz2 or dx2-y2
orbitals. This results in low spin complex (Octahedral)
ii. Weak field ligands:
In these ligands donor atoms are halogens, oxygen or sulphur. These ligands produce
relatively small value of Δo.Therefore for metal complex with weak field ligands Δo <P.
It is then easier with weak field ligands Δo <P. It is then easier to place an electron in
either dz2 or dx2-y2 than to pair up electrons. This gives rise to high spin complex
(Octahedral).
6. A choice between high spin and low spin electronic configuration arises only for
d4 - d7 octahedral complexes.
In d1 to d3 complexes, all electrons occupy lower energy d orbitals independent of Δo.
In d8 to d10 complexes, dxy,dyz and dxz orbitals each contain two electrons. dz2 and
dx2-y2 orbitals contain two,three or four electrons,which is again independent of Δo.
7. Spectrochemical series
The arragnement of ligands in order of their increasing field strength is called
spectrochemial series
I- < Br- < Cl- < S2- < F- < OH- < C2O42-<H2O<NCS <EDTA< NH3,<en< CN- < CO.
d orbital diagrams for high spin and low spin d4-d7complexes
Applications of coordination compounds Imp.2 Mark
2.To estimate hardness of water: Hardness of water is due to the presence of Ca2+
and Mg2+ ions in it. The ligand EDTA forms stable complexes with Ca2+ and Mg2+ ions .
The selective estimation of these ions can be done due to difference in
the stability constants of calcium and magnesium complexes.
3.Extraction processes of some metals, like those of silver and gold, make use of
complex formation. Gold, for example, combines with cyanide in the presence of oxygen
and water to form the coordination entity [Au(CN)2]– in aqueous solution. Gold can be
separated in metallic form from this solution by the addition of zinc .
4.Purification of metals can be achieved through formation and subsequent
decomposition of their coordination compounds.
For example, impure nickel is converted to [Ni(CO)4], which is decomposed to yield pure
nickel.
5. In biological systems. The pigment responsible for photosynthesis, chlorophyll, is
a coordination compound of magnesium. Haemoglobin, the red pigment of blood which
acts as oxygen carrier is a coordination
compound of iron.
6. Catalysts for many industrial processes. Examples include rhodium complex,
[(Ph3P)3RhCl], a Wilkinson catalyst, is used for the hydrogenation of alkenes.