Surface Development
Surface Development
SURFACES
18ME2ICEED
It is also called a pattern where the plane may show the true size of each area of the
object. When the pattern is cut, it can be rolled or folded back into the original object
Cylinder Cone
4-May-20 4
DEPARTMENT OF MECHANICAL ENGINEERING, BMSCE, BANGALORE-19
METHODS OF DEVELOPMENT
Zones
Section views are very important to reveal interior features of parts which are not
otherwise not visible. Section of solids are based on the use of Imaginary cutting
plane .
Trace of a section plane is a line in which the section plane meets the reference
plane. The projection of the section on the reference plane to which the section
plane is perpendicular will be straight line coinciding with the trace of the section
plane on it.
DEPARTMENT OF MECHANICAL
4-May-20 7
ENGINEERING, BMSCE, BANGALORE-19
• Vertical trace (V.T.) – V.T. of a section plane is a line in
which the section plane meets the V.P.
• Horizontal trace (H.T) – H.T. of a section plane is a line in
which the section plane meets the H.P
• Section plane intersection points are denoted with
numbers
• Types of Section plane :These cutting planes can be
1. Vertical Section Plane cutting plane parallel to vertical
plane(HT)
Frustrum
Fig 1B
Fig 1A
Fig 2
4-May-20 DEPARTMENT OF MECHANICAL ENGINEERING, BMSCE, BANGALORE-19 14
Example 2.A pentagonal prism of base sides 20mm and height 40mm is resting with its base on HP and base
edge parallel to the VP. The prism is cut as shown in the following front view. Draw the section plane and
identify section points
Fig 1B
Fig 2
Note:When two section planes intersect,
Two section points ,one at front and another at back
Will be formed.In this problem section points 2 and 5
Fig 1A
(8')
11 11 (6')
a' 2' b' 4' c' A 2 B 4 C 6 8 A
Fig 1B 15
1' 1
3' (7') 5' 1 3 5 7
60
DEVELOPMENT
VP
X Y
HP p' q' r' P Q R P
120
(p) a 1 8 7 6 5 c (r)
Fig 2
2 4
40
3
Fig 1A b (q)
Fig 1B
3' 3
60
(4') 4
2' 2
20
1' 1 1
D A
20°
c
Fig 2
b
Fig 1A
Fig 2
Fig 1B
Fig 1A
Fig 1B
Fig 2
Fig 1A
Fig 1B
Fig 2
Note:Development should be started about cc1 and not
AA1,else It will not be a single piece development
Fig 1A
Fig 1B
Fig 2
Fig 1A
Fig 2
Fig 1A
Fig 1B
Fig 2
Fig 1A
Fig 1B
Fig 2
Fig 1A
Fig 2
Fig 1A
Fig 1B
Fig 2
Fig 1A
Fig 1B
Fig 2
Fig 1A
Fig 1B
Fig 2
Fig 1A
Fig 1B
Fig 2
Fig 1A
Fig 1B
Fig 2
Fig 1A
0
R2
Fig 1B
R
20
60
4'(12') 12
3' (13') 5' (11') 11 13
(14') (10') 4 5 10 14
6'(9') 3 15
(15')2'
2 6 9
a' 1'(16')(e') b' (d') 7' c' A 1 B 7 C 8 D E 16 A
5 (8')
R 20
e 5,28 13,82
d 13,82
8,59
22,49
22,49
17,64
13,82
30
5,2 a 150
c
8
8,5
9 Fig 2
17,6 b
4
Fig 1A
30
Fig 1B R
20
R
20
10' 10
1' 1 1
65
9' 9 9
2' 8' 2 8 2
3' 7' 3 7
4' 6' 4 6
5' 5
R 20
R 20
f e
O
10 5
40
30 15
180
a d
Fig 2
30
c
10
5
b
5
Fig 1A 15
Fig 1B
Fig 2
Fig 1A
Fig 1B
Fig 2
Fig 1B
Fig 2
Fig 1A
4-May-20 DEPARTMENT OF MECHANICAL ENGINEERING, BMSCE, BANGALORE-19 35
21) A square pyramid of side of base45mm, altitude 70mm is resting with its base on HP with two sides of the
base parallel to VP. The pyramid is cut by a section plane which is perpendicular to the VP and inclined at 400
to the HP. The cutting plane bisects the axis of the pyramid. Obtain the development of the lateral surfaces the
truncated pyramid
Fig 1B
Fig 2
Fig 1A
Fig 2
Fig 1A
30,2
45
8
52,6
D
5
C
76,8
(3') 2'
40°
9
DEVELOPMENT
70
A
(4') 1' 4 B
35
1
3
(d') a' (o 1') (c') b' b1 '
52
30,28
,65 2
d c
4 A
O
3
Fig 2 76,89
1
(o1 ) b1
o
2
1
a b
q 45 Fig 1A
Fig 1B
Fig 2
Fig 1A
4-May-20 DEPARTMENT OF MECHANICAL ENGINEERING, BMSCE, BANGALORE-19 39
25) A square pyramid of 25mm base edge and 50mm height rests with its base on HP with all of its base
edges equally inclined to VP. It is cut by a plane perpendicular to VP and inclined to HP at 600, passing
through the extreme right corner of base. Draw the development of the lateral surface of the pyramid.
Fig 1B
Fig 2
Note:Development should be started about Oc
and not OA,else It will not be a single piece
development
Fig 1A
Fig 1B
o'
15,2
19,9
2
8
4 D
27,6
4' C
55,2
(5') (5T')
60°
40
8
1' 2' 3'
50
(6') A
DEVELOPMENT
25
6 B
5
c' c ' 1 3 2
15,22
1
25
a' 4
30°
19,98
d 1
O A
6 27,64
5
a o c 1 55,28
1 (o1 ) 4 c
2 Fig 2
25
3
40
b
Note:When two section planes intersect,
Fig 1A Two section points ,one at front and another at
back Will be formed(3,6)
4-May-20 DEPARTMENT OF MECHANICAL ENGINEERING, BMSCE, BANGALORE-19 41
27) A frustum of a pentagonal pyramid, smaller base sides 16mm and bigger top face sides 32mm and height
40mm, is resting on the HP on its smaller base, with one of its base sides parallel to the VP. Draw the
projections of the frustum and develop the lateral surface it.
Fig 1B
Fig 2
Fig 1A
Fig 1B 30
P D
DEVELOPMENT
122,68 T
92,01
S C
22,5
B
d Q Fig 2
30
e
s
t
92,01 P A
22,5
30
o (o ) r c
1 122,68
p
q
a
Fig 1A b
Fig 1B
Fig 2
Fig 1A
4-May-20 DEPARTMENT OF MECHANICAL ENGINEERING, BMSCE, BANGALORE-19 44
30) A pentagonal pyramid, 30mm sides, with a side of base perpendicular to VP. Draw the development of the
lateral surfaces of the retained portion of the pyramid shown by the dark lines in the following figure.
Fig 1B
Fig 2
Note:When two section planes intersect,
Two section points ,one at front and another at
back Will be formed(2,6)
Fig 1A
(o ')
Note:When
30,3
38,5
26,3 A
60,6
2 ,63
8
6
Fig 1B 60 two section
3
3'
1
(4')
planes
55
45°
o 5 Two section
4
e' (o ')b' (d') c' c ' points ,one at
38,58
a' 1
1
26
,36
3
d D
front and
e
5 4 O 1 2
another at
6
o
back
c
a
(o1 ) 1
C Will be
1 3 c
A B formed(2,5)
Fig 1A 30
2
30 Fig 2
b
Fig 1B
Fig 2
Fig 1A
Fig 1B
Fig 2
Fig 1A
Fig 1B
Fig 2
Fig 1A
Fig 1B
Fig 2
Note:Development should be started about OD and not
OA,preferably
Fig 1A
Fig 1B
Fig 2
Note:When two section planes intersect,
Two section points ,one at front and another at
back Will be formed(1,5)
Fig 1A
Fig 1B
Fig 2
Fig 1B
Fig 2B
2A
D=3.14x45=141.36mm
Fig 1A
Fig 1B 5 5
DEVELOPMENT
(11')
45
(12') 5' 5 11
4' 6' (10') 6 10 12
4
7 9
3' 120° 8
7' 8' 3 13
1' 2' (13') (9') 2 14
(14')
18 1 1
188.4
k 11
l j
P= X D=188.4
m h
Fig 2B
a g
2A
b f
D=3.14x54=161.67 mm
c e
d 5 5
Fig 1A O 60
Fig 1B
Fig 2B
2A
D=3.14x50=157mm
Fig 1A
Fig 1B
Fig 2B
2A
D=3.14x40=125.6mm
Fig 1A
Fig 1B
Fig 2B
2A
D=3.14x40=125.6mm
Fig 1A
Fig 1B
Fig 2B
2A
D=3.14x40=125.6mm
Fig 1A
Fig 1B
Fig 2B
2A
D=3.14x40=125.6mm
Fig 1A
Fig 1B
Fig 2B
Note:Development should be started about EE1 and not
AA1,else It will not be a single piece development
Fig 1A 2A
D=3.14x40=125.6mm
4-May-20 DEPARTMENT OF MECHANICAL ENGINEERING, BMSCE, BANGALORE-19 60
46) A pipe made of using a half tubular (circular) with a half square in shape is cut as shown in the following
figure. Draw the development of the lateral surface of the object.
Fig 1B
Fig 2B
Fig 2B
Fig 1B
Fig 1A 2A :
= 3600 *r / R
= 3600 * 30/76.16=141.80
Fig 2B
Fig 1B
Fig 1A 2A
= 3600 *r / R
= 3600 * 30/76.16=141.80
4-May-20 DEPARTMENT OF MECHANICAL ENGINEERING, BMSCE, BANGALORE-19 63
49) A right cone of 55mm diameter of base and 75mm height stands on its base on HP. It is cut to the shape of
a truncated cone with its truncated surface inclined at 450 to the axis lying at a distance of 40mm from the
apex of the cone. Obtain the development of the lateral surface of the truncated cone.
Fig 2
Fig 1B
= 3600 *r / R
= 3600 * 27.5/79.88=135.20
Fig 1A
Fig 1B
Fig 2B
2A
= 3600 *r / R
Fig 1A = 103.440
4-May-20 DEPARTMENT OF MECHANICAL ENGINEERING, BMSCE, BANGALORE-19 65
51. A frustum of a cone 80mm bottom diameter and 40mm top diameter, and 70mm high
rest on base on HP. It is cut through by a semicircular hole of diameter 40mm as in fig. 9 Draw
the development.
Fig 1B Fig 2B
72,8
A
126,88
124,8
K
145,6
O 40 9).
,6
145
I
125
70
R2
127
0
3' 4'
G
72,8
2'
1' 5'
a' b' c' d' e' f' g' F
O 80
j
99°
k i 5
E
4
l h N
4°
3
D
2 M
8°
a g
Fig 2A 1 C
Fig 1A b f
=(r/R)*360=98.90
B
=(40/145.6) X 360=98.90
e
c m n
d
A
4-May-20 DEPARTMENT OF MECHANICAL ENGINEERING, BMSCE, BANGALORE-19 66
52) Draw the development of the lateral surface of the cone, whose front view is as shown in the following
figure.
Fig 1B
Fig 2B
2A
= 3600 *r / R
= 3600 * 25/65=138.460
Fig 1A
4-May-20 DEPARTMENT OF MECHANICAL ENGINEERING, BMSCE, BANGALORE-19 67
53 A frustum of a cone 80mm bottom diameter and 40mm top diameter, and 70mm high
rest on base on HP. It is cut through by a semicircular hole of diameter 40mm as in fig. Draw
the development.
Fig 2B
Fig 1B
72,8
A
126,88
124,8
K
145,6
O 40 9).
,6
145
I
125
70
R2
7
0
12
3' 4'
G
72,8
2'
1' 5'
a' b' c' d' e' f' g' F
O 80
j
99°
k i 5
E
4
l h N
4°
3
D
2 M
8°
a g
Fig 2A 1 C
b f
=(r/R)*360=98.90
B
=(40/145.6) X 360=98.90
e
c m n
d
A
Fig 1A
21,54
17,32
32,31
43,08
K
16,16
,31
R 16,16
32
15
R
5
6
4
J
7
°
3
134
50
I This is a curve
8
,08
2 43
R
9
1
H
10
G
Fig 2B
k j F
i
l E
h D
B C
A
g
a R 20
f
Fig 2A
b
3,0 e =(r/R)*360=133.70
3 c d
=(20/53.85) X 360=133.70
Fig 1A
Fig 1B A
85 Fig 2B
53, L
K
16,16
15
32,31
16
43,0
16,
53,8
J
R
8
°
134
50
8 I This is a curve
3,0
,31
4
R 32
R
H
10
k j F
i
l E
h D
B C
A
g
a R 20
16
b
f Fig 2A
e =(r/R)*360=133.70
c d
3,03 =(20/53.85) X 360=133.70
Fig 1A
Fig 2B
Fig 1B
Fig 2A
= 3600 *r / R
= 3600 * 25/65=138.460
Fig 1A
4-May-20 DEPARTMENT OF MECHANICAL ENGINEERING, BMSCE, BANGALORE-19 71
58) Draw the developments of the lateral surface of a funnel consisting of a cylinder and a frustum of a cone.
The diameter of the cylinder is 20mm and top face diameter of the funnel is 80mm. The height of frustum and
cylinder are equal to 60mm and 40mm respectively.
3A
Fig 1B
= 3600 *r / R
= 3600 * 40/89.44=1610
Fig 2B
2A Fig 3B
D=3.14x20=62.83mm
Fig 1A
Fig 1B
Fig 2B
Fig 2A
= 3600 *r / R
= 3600 * 25/65=138.460
Fig 1A
2A 3A
= 3600 *r / R = 3600 *r / R
= 3600 * 20/44.72=1610 = 3600 * 10/ 80.62=44.650
Fig 1B
Fig 2B
Fig 3B
Fig 1A
Fig 2B
3A
D=3.14x30=94.25 mm
Fig 1A