Session: 2023-24

Time : 19:13:00 CHEMISTRY

Marks : 4612
9.COORDINATION COMPOUNDS

Single Correct Answer Type

1. The IUPAC name of Na3 [Co(ONO)6 ] is:

a) Sodium cobaltinitrite
b) Sodium hexanitritocobaltate(III)
c) Sodium hexanitrocobalt(III)
d) Sodium hexanitritocobaltate(II)
2. CuSO4 decolourises on addition of KCN, the product is:
a) Cu(CN)2−4 b) [Cu(CN)4 ]3− c) Cu(CN)2 d) CuCN
3. Exchange of coordination group by a water molecule in complex molecule results in:
a) Ionization isomerism
b) Ligand isomerism
c) Hydration isomerism
d) Geometrical isomerism
4. The type of isomerism found in urea molecule is
a) Chain
b) Position
c) Tautomerism
d) None of these
5.
The IUPAC name of the compound is
a) Butane-2-aldehyde b) 2-methyl butanal c) 2-ethyl propanal d) None of the above
6. Anisol is a product obtained from phenol by the reaction known as:
a) Coupling b) Etherification c) Oxidation d) Esterification
7. Which of the following is diamagnetic in nature?
a) [Fe(CN)6 ]3− b) [NiCl4 ]2− c) [Ni(CO)4 ] d) [MnCl4 ]2−
8. Which is the strongest field ligand?
a) CN− b) NO−2 c) NH3 d) en
9. Nitrobenzene on reduction with Zn and 𝑎𝑞. NH4 Cl gives:
a) Aniline
b) Nitrosobenzene
c) 𝑁-phenyl hydroxylamine
d) Hydrazobenzene
10. The IUPAC name of [Co(NH3 )5 ONO]2+ ion is
a) Pentaammine nitrito cobalt (IV) ion b) Pentaammine nitro cobalt (III) ion
c) Pentaammine nitrito cobalt (III) ion d) Pentaammine nitro cobalt (IV) ion
11. The compound which does not show paramagnetism is
a) NO2 b) NO c) [Ag(NH3 )2 ]Cl d) [Cu(NH3 )4 Cl2 ]
12. Which of the following is expected to undergo nitration more easily and readily to furnish the
corresponding nitro derivatives employing the usual nitrating mixture?
a) C6 H6 b) C6 H5 NO2 c) C6 H5 CH3 d) C6 H5 ∙ CCl3
13. 3+ 3−
The number of unpaired electrons calculated in [Co(NH3 )6 ] and [Co(F6 )] are
a) 4 and 4 b) 0 and 2 c) 2 and 4 d) 0 and 4
14. The IUPAC name of

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 a) 4-hydroxy amino benzene carboxylic acid b) 4-(N-hydroxy) imino benzene carboxylic acid
c) 4-hydroxy imino cyclohexanoic acid d) 4-(N-hydroxy) imino cyclohexane-1
-carboxylic acid
15. The IUPAC name of the coordination compound K 2 [Zn OH)4 ] is
(
a) Potassium tetrahydroxozine (II) b) Dipotassium tetrahydroxo(II)
c) Potassium tetrahydroxozincate (II) d) Potassium tetrahydroxozincate (III)
16. Arrange in order of decreasing trend towards S𝐸 reactions,
Chlorobenzene, Benzene, Anilium chloride, Toluene:
I. (II) (III) (IV)
a) II > I > III > IV b) III > I > II > IV c) IV > II < I > III d) I > II > III > IV
17. Toluene is nitrated and the resulting product is reduced with tin and hydrochloric acid. The product so
obtained is diazotised and then heated with cuprous bromide. The reaction mixture so formed contains:
a) Mixture of 𝑜- and 𝑚-bromotoluenes
b) Mixture of 𝑜- and 𝑝-bromotoluenes
c) Mixture of 𝑜- and 𝑝-dibromobenzenes
d) Mixture of 𝑜- and 𝑝-bromoanilines
18. A positive carbylamine test is given by:
a) 𝑁, 𝑁-dimethylaniline
b) 2,4-dimethylaniline
c) 𝑁-methyl-𝑜-methylaniline
d) 𝑝-methyl benzylamine
19. CN− is strong field ligand. This is due to the fact that
a) It carries negative charge
b) It is a pseudohalide
c) It can accept electrons from metal species
d) It forms high spin complexes with metal species.
20. Which of the following is not true for ligand metal complex?
a) Highly charged ligand forms strong bond
b) Greater the ionization potential of central metal, the stronger is the bond
c) Larger the permanent dipole moment of ligand, the more stable is the bond
d) Larger the ligand, the more stable is the metal-ligand bond
21. The nitration of nitrobenzene with fuming HNO3 will give:
a) TNB b) 1,3-dinitrobenzene c) Picric acid d) 1,4-dinitrobenzene
22. A ligand can also be regarded as
a) Lewis acid b) Bronsted base c) Lewis base d) Bronsted acid
23. The correct statement with respect to the complexes Ni(CO)4 and [Ni (CN)4 ]2− is
a) Nickel is in the same oxidation state in both
b) Both have terahedral geometry
c) Both have square planar geometry
d) Have tetrahedral and square planar geometry respectively
24. Which one of the following has lowest value of paramagnetic behaviour?
a) [Cr(CN6 )4 ]3− b) [Mn(CN)6 ]3− c) [Fe(CN)6 ]3− d) [Co(CN)6 ]3−
25. In the reaction;

the products are:

a)

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 b)

c)

d)

26. An octahedral complex is formed when central metal atom undergoes hybridization amongst
the….orbitals.
a) 𝑠𝑝3 b) 𝑑𝑠𝑝2 c) 𝑠𝑝3 𝑑 d) 𝑠𝑝3 𝑑2
27.

a)

b)

c)

d)

28. Biological oxidation of C6 H6 taking place in body of dog, gives:

a) Benzoic acid b) Toluic acid c) Maleic acid d) Muconic acid
29. Ammonia forms the complex ion [Cu(NH3 )4 ]2+ with copper ions in the alkaline solutions but not in acidic
solutions .What is the reason for it?
a) In acidic solutions hydration protects copper ions
In acidic solutions protons coordinate with ammonia molecules forming NH4+ ions and NH3 molecules
b)
are not available
c) In alkaline solutions insoluble Cu(OH)2 is precipitated which is soluble in excess of any alkali
d) Copper hydroxide is an amphoteric substance
30. Which of the following has the highest molar conductivity in solution?
a) [Pt(NH3 )6 ]Cl4 b) [Pt(NH3 )5 Cl]Cl3 c) [Pt(NH3 )4 Cl2 ]Cl2 d) [Pt(NH3 )3 Cl3 ]Cl
31. Which of the following is not 𝑚𝑒𝑡𝑎 directing group?
a) —SO3 H b) —NO2 c) —CN d) —NH2
32. Which of the following is an organometallic compound?
a) Lithium methoxide b) Lithium acetate
c) Lithium dimethylamine d) Methyl lithium
33. Which among the following is very strong 𝑜-, 𝑝-directing group?
a) —Cl b) —O𝑅 c) —NH2 d) —NH𝑅
34. The type of hybridisation in tetrahedral complexes of metal atom is
a) 𝑑𝑠𝑝 2 b) 𝑑2 𝑠𝑝 c) 𝑠𝑝3 d) 𝑠𝑝2
35. Chlorobenzene on heating with NaOH at 300 ͦC under pressure gives:
a) Phenol b) Benzaldehyde c) Chlorophenol d) None of these

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36. The coordination number of Fe in [Fe(CN)6 ]4− [Fe(CN)6 ]3− and [FeCl4 ]− are respectively.
a) 2, 3, 3 b) 6, 6, 4 c) 6, 3, 3 d) 6, 4, 6
37. Consider the following statements
I. Chain and position isomerism are not possible together between two isomers
II. Tautomerism is a chemical phenomenon which is catalysed by acid as well as base
III. Tautomers are always metamers
IV. Tautomers are always functional isomers
Select the correct answer by using the codes given below
a) Only III is correct b) III and IV are correct
c) I, II and III are correct d) I, II and IV are correct
38. What is the EAN of nickel in [Ni(CN)4 ] ?
2−

a) 32 b) 35 c) 34 d) 36
39. Which of the following alcohols is dehydrated most readily with conc. H2 SO4 ?
a) 𝑝-O2 NC6 H4 CH(OH)CH3
b) 𝑝-ClC6 H4 CH(OH)CH3
c) 𝑝-CH3 OC6 H4 CH(OH)CH3
d) C6 H5 CH(OH)CH3
40. The compound having tetrahedral geometry is
a) [Ni(CN)4 ]2− b) [Pd(CN4 )]2− c) [PdCl4 ]2− d) [NiCl4 ]2−
41. Identify ‘𝑍’ in the change;

a) b) c) d)

42. Which of the following is most acidic?

a) 𝑝-cresol b) 𝑝-chlorophenol c) 𝑝-nitrophenol d) 𝑝-aminophenol
43. Benzoylacetonato beryllium exhibit isomerism of the type
a) Structural b) Geometrical c) Optical d) Conformational
44. Which one of the following has a square planar geometry?
(At. No. Fe=26, Co=27, Ni=28, Pt=78)
a) [CoCl4 ]2− b) [FeCl4 ]2− c) [NiCl4 ]2− d) [PtCl4 ]2−
45. The number of ions formed on dissolving one molecule of FeSO4 (NH4 )2 SO4 ∙ 6H2 O in water is:
a) 4 b) 5 c) 3 d) 6
46. A solution of potassium ferrocyanide would contains-ions
a) 2 b) 3 c) 4 d) 5
47. Which of the following is not considerd as an organometallic compound?
a) Grignard reagent b) 𝑐𝑖𝑠-platin c) Zeise’s salt d) Ferrocene
48. When phenol is reacted with CHCl3 and NaOH followed by acidification, salicylaldehyde is obtained. Which
of the following species are involved in the above mentioned reaction as intermediates?
d) Both (a) and (b)

a) b) c)

49. Number of geometrical isomers for the molecule

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 a) 2 b) 3 c) 6 d) 5
50. Which statement about coordination number of a cation is true?
a) Most metal ions exhibit only a single characteristic coordination number
b) The coordination number is equal to the number of ligands bonded to the metal atom
c) The coordination number is determined solely by the tendency to surround the metal atom with the
same number of electrons as one of the rare gases
d) For most cations, the coordination number depends on the size, structure and charge of the ligands
51. Among the following, the strongest base is:
a) C6 H5 NH2 b) 𝑝-NO2—C6 H4 NH2 c) 𝑚-NO2—C6 H4 NH2 d) C6 H5 CH2 NH2
52. General formula for arenes is:
a) C𝑛 H2𝑛+6 b) C𝑛 H2𝑛+6𝑦 c) C𝑛 H2𝑛 d) C𝑛 H2𝑛−6𝑦
53. Which of the following doesn’t have a metal-carbon bond?
a) Al(OC2 H5 )3 b) C2 H5 MgBr c) K[Pt(C2 H4 )Cl3 ] d) Ni(CO)4
54. How many isomers are possible in [Co(en)2 Cl2 ]?
a) 2 b) 4 c) 6 d) 1
55. How many carbon atoms in the molecule HOOC − (CHOH)2 − COOH are asymmetric?
a) 1 b) 2 c) 3 d) None of these
56. In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei.
a) 2 b) 3 c) 6 d) 4
57. Which can be used to distinguish C6 H5 NH2 and C6 H5 CH2 NH2?
a) Diazotisation followed with coupling with phenol
b) Carbylamine reaction
c) Reimer-Tiemann reaction
d) None of the above
58. When RCOCl and AlCl3 are used in Friedel-Craft’s reaction, the electrophile is:
a) 𝐶𝑙 + b) 𝑅COCl c) d) 𝑅 +
59. Thiophene is separated from benzene by:
a) Chlorination of thiophene
b) Sulphonation of thiophene
c) Nitration of thiophene
d) Oxidation of thiophene
60. A complex compound of CO3+ with molecular formula COCl𝑥 . yNH3 gives a total of 3 ions when dissolved in
water. How many Cl− ions satisfy both primary and secondary valencies in this complex?
a) 3 b) 1 c) 4 d) Zero
61. The correct IUPAC name of alcohol [(CH3 )2 CH]3 COH is
a) Tri isopropyl carbinol b) 2, 4-dimethyl-3-isopropyl pentan-3-ol
c) 2,4-dimethyl-3-(1-methyl) ethyl pentan-3-ol d) None of the above
62. Colour of transition metal complexes can be explained by:
a) Completely filled 𝑑-orbitals
b) Vacant 𝑑-orbitals
c) 𝑑 − 𝑑 transition
d) None of the above
63. Which is most reactive towards electrophilic reagents:

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 a) b) c) d)

64. Pick a poor electrolytic conductor complex in solution:

a) K 2 [PtCl6 ] b) [Co(NH3 )3 ](NO2 )3 c) K 4 [Fe(CN)6 ] d) [Co(NH3 )4 ]SO4
65. Benzene reacts with sulphuric acid only when the acid is:
a) Dilute and cold b) Dilute and hot c) Hot and concentrated d) Mixed with HNO3
66. In the following reaction the catalyst used is:

a) Cr2 O3 b) Al2 O3 c) Zn dust d) Cr2 O3 and Al2 O3

67. The alkane which has only primary hydrogen atom is
a) Pentane b) 𝑖𝑠𝑜pentane
c) 𝑛𝑒𝑜pentane d) 2, 2-dimethyl butane
68. The correct IUPAC name of the complex;

a) Dichlorodimethylglyoximato cobalt(II)
b) 𝐵𝑖𝑠(dimethylglyoxime) dichloro cobalt(II)
c) Dimethylglyoxime cobalt(II) chloride
d) Dichlorodimethylglyoxime-N,N-cobalt(II)
69. Which of the following nitroalkane will not show tautomerism?
CH3 − CH − CH2 NO2
a) CH3 CH2 CH2 CH2 NO2 b) |
CH3
CH3 CH − CH2 CH3
c) | d)
NO2
70. Which is low spin complex?
a) [Fe(CN)6 ]3− b) [Co(NO2 )6 ]3− c) [Mn(CN)6 ]3− d) All of these
71. The probable formula for Prussian blue is:
a) Fe3 [Fe(CN)6 ]2 b) Fe2 [Fe(CN)6 ]3 c) Fe4 [Fe(CN)6 ]3 d) Fe3 [Fe(CN)6 ]4
72. Which represents Reimer-Tiemann reaction?

a)

b)

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 c)

d)

73. The complex ion which has no ‘𝑑’-electron in the central metal atom is :
a) [MnO4 ]− b) [Co(NH3 )6 ]3+ c) [Fe(CN)6 ]3− d) [Cr(H2 O)6 ]3+
74. The shape of cobalt hexaammine cation, which has its central cobalt atom surrounded by six ammonia
molecules is:
a) Tetrahedral b) Octahedral c) Square planar d) Trigonal
75. Which ligand is capable of forming low spin as well as high spin complexes?
a) CO b) NO−2 c) CN− d) NH3
76.

The IUPAC name of is

a) 7-ethyl-2, 4, 5, 6-tetramethyl-deca-1, 9-diene b) 7-ethyl-2, 4, 5, 6-tetramethyl-deca-1, 8-diene
c) 4-ethyl-4, 5, 6, 7-tetramethyl-deca-1, 9-diene d) 7-(1-propenyl)-2, 3, 4, 5-tetramethyl-non-1-ene
77. IUPAC name of [Pt NH3 3 Br(NO2 )Cl]Cl is
( )
a) Triamminechlorobromonitro platinum (IV) chloride
b) Triamminebromonitrochloro platinum (IV) chloride
c) Triamminebromochloronitro platinum (IV) chloride
d) Triamminenitrochlorobromo platinum (IV) chloride
78. An aromatic ether is not cleaved by HI even at 525 K. The compound is:

a) C6 H5 OCH3 b) C6 H5 OC6 H5 c) C6 H5 OC3 H7 d)

79. Phenol does not react with:

a) Na2 CO3 b) NaOH c) NaHCO3 d) KOH
80. [EDTA] is a
4−

a) Monodentate ligand b) Bidentate ligand

c) Quadridentate ligand d) Hexadentate ligand
81. [Pt(NH3 )4 Cl2 ]Br2 and [Pt(NH3 )4 Br2 ]Cl2 are related to
a) Optical isomer b) Linkage isomers c) Coordinate isomers d) Ionization isomers
82. Ferrocene is an example of
a) Sand-wiched complex
b) Pi-bonded complex
c) A complex in which all the five carbon atoms of cyclopentadiene anion are bonded to the metal
d) All of the above
83. Which compound is zero valent metal complex?
a) [Cu(NH3 )4 ]SO4 b) [Pt(NH3 )2 Cl2 ] c) [Ni(CO)4 ] d) K 3 [Fe(CN)6 ]
84. Which of the following compounds is 2, 2, 3-trimethyl hexane?
a) (CH3 )3 CCH(CH3 )CH2 CH3 b) (CH3 )3 CCH2 (CH3 )2
c) (CH3 )2 CHCH2 CH2 C(CH3 )3 d) (CH3 )3 CCH(CH3 )CH2 CH2 CH3
85. The formula of phenoxy benzene is:
a) C6 H5 C6 H5 b) C6 H5 —O—C6 H5 c) C6 H5 —O— C6 H6 d) None of these

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86. Ziegler-Natta catalyst is an organometallic compound containing
a) Iron b) Titanium c) Rhodium d) Zirconium
87. Ziegler-Natta catalyst is
a) (Ph3 P)3 RhCl b) K[PtCl3 (C2 H4 )] c) [Al2 (C2 H6 )6 + TiCl4 ] d) [Fe(C2 H5 )2 ]
88. The tendency to show complex formation is maximum in ….elements.
a) 𝑠-block b) 𝑝-block c) 𝑑-block d) 𝑓-block
89. EDTA has coordination number
a) 3 b) 4 c) 5 d) 6
90. Which of the following is used in Friedel-Craft’s acylation reaction?

a) b) CH3 CH2 Cl c) CH3 COOCH3 d) CH3 Cl

91. The correct IUPAC name of Mn3 (CO)12 is

a) Dodacacarbonyl maganate (0) b) Dodacacarbonyl maganate (II)
c) Didacacarbonyl trimaganese (0) d) Manganic dodecacarbanyl (0)
92. The π −bonded organometallic compound which has ethene as one of its component is
a) Zeise’s salt b) Ferrocene c) Dibenzene chromium d) Tetraethyl tin
93. IUPAC name of the compound

a) Ethyl-2-methyl-2-(𝑚-nitro) phenyl propanoate b) Ethyl-2-methyl-2-(𝑜-nitro) phenyl propanoate

c) Ethyl-2-methyl-2-(3-nitro) phenyl propanoate d) Ethyl-2-methyl-2-(3-nitro) phenyl propanoic acid
94. What is the product obtained in the following reaction:

a) b) c) d)

95. [Co(NH3 )6 ]Cl3 is called:

a) Hexaammine cobalt (III) chloride
b) Amino cobalt chloride (III)
c) Cobalt chloride hexaammine
d) Hexaammine tricobalt chloride
96. The complexes [PtCl2 (NH3 )4 ]Br2 and [PtBr2 (NH3 )4 ]Cl2 are example for isomerism
a) Geometrical b) Optical c) Ionization d) Linkage
97. Geometrical shapes of the complexes formed by the reaction of Ni with Cl , CN − and H2 O , respectively,
2+ −

are
a) Octahedral, tetrahedral and square planar b) Tetrahedral ,square planar and octahedral
c) Square planar ,tetrahedral and octahedral d) Octahedral , square planar and octahedral
98. Identify the correct order of reactivity in electrophilic substitution reactions of the following compounds:

a) 1 > 2 > 3 > 4 b) 4 > 3 > 2 > 1 c) 2 > 1 > 3 > 4 d) 2 > 3 > 1 > 4
99. The centric formula for benzene was proposed by:
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 a) Dewar
b) Armstrong and Baeyer
c) Ladenberg
d) Kekule
100. Which is the correct statement?
a) Benzyl alcohol is more acidic than phenol
b) Ethanol is a powerful oxidizing agent
c) Phenol is more acidic than propanol
d) Ethane has high boiling point than ethanol
101. Phenol on sulphonation gives:
a) o-phenol sulphonic acid
b) 𝑝-phenol sulphonic acid
c) 𝑚-phenol sulphonic acid
d) Mixture of 𝑜-and 𝑝-phenol sulphonic acids
102. Which of the following organometallic compound is 𝜎 and 𝜋 bonded?
a) Fe(CH3 )3 b) [Co(CO)5 NH3 ]2+ c) [Fe(η5 − C5 H5 )2 ] d) K[PtCl3 (η2 − C2 H4 )]
103. The number of double bonds in BHC (gammexane) is:
a) 1 b) 2 c) 3 d) Zero
104. Given the molecular formula of the hexa coordinated complexes (𝐴) CoCl3 ∙ 6NH3 (𝐵)CoCl3 ∙ 5NH3
(𝐶) CoCl3 ∙ 4NH3 . If the number of coordinated NH3 molecules in 𝐴, 𝐵 and 𝐶 respectively are 6, 5 and 4,
primary valency in (𝐴), (𝐵) and (𝐶) are
a) 0, 1, 2 b) 3, 2, 1 c) 6, 5, 4 d) 3, 3, 3
105. Type of isomerism shown by [Cr(NH3 )5 NO2 ]Cl2 is
a) Optical b) Ionisation c) Geometrical d) Linkage
106. [Sc(H2 O)6 ] ion is
3+

a) Colourless and diamagnetic b) Coloured and octahedral

c) Colourless and paramagnetic d) Coloured and paramagnetic
107. Which one of the following octahedral complexes will not show geometrical isomerism? ( A and B are
monodentate ligands)
a) [𝑀𝐴4 𝐵2 ] b) [𝑀𝐴5 𝐵] c) [𝑀𝐴2 𝐵4 ] d) [𝑀𝐴3 𝐵3 ]
108. The IUPAC name of the following compound is

a) 3-amino-2-hydroxy propanoic acid b) 2-aminopropan-3-ol-1-oic acid

c) 2-amion-3-hydroxy propanoic acid d) Aminohydroxy propanoic acid
109. Which of the following complex ion is not expected to absorb visible light?
a) [Ni(CN)4 ]2−
b) [Cr(NH3 )6 ]3+
c) [Fe(H2 O)6 ]2+
d) [Ni(H2 O)6 ]2+
110. The correct sequence of activating power of a group in benzene is:
a) −NH2 > −NHCOCH3 > −CH3
b) −NH2 < −NHCOCH3 < −CH3
c) −NH2 > −NHCOCH3 < −CH3
d) −NH2 < −NHCOCH3 > −CH3
111. The pair of compounds having metals in their highest oxidation state is
a) MnO2 , FeCl3 b) [MnO4 ]− , CrO2 Cl2
c) [Fe(CN)6 ]3− , [Co(CN)3 ] d) [NiCl4 ]2− , [CoCl4 ]−
112. Total number of geometrical isomers for the complex [RhCl(CO)(PPh3 )(NH2 )] is
a) 1 b) 2 c) 3 d) 4

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113. The reaction of chloroform with alc. KOH and 𝑝-toluidine forms:

a)

b)

c)

d)

114. Which order is correct in spectrochemical series of ligands?

a) Cl− < F − < [C2 O4 ]2− < NO− 2 < CN
−

b) CN < [C2 O4 ] < Cl > NO2 < F −

− 2− − −

c) [C2 O4 ]2− < F − < Cl− > NO− 2 < CN

−

d) F − < Cl− < NO− −

2 < CN < [C2 O4 ]
2−

115. The IUPAC name of compound K 3 [Fe(CN)5 NO] is

a) Pentacyano nitrosyl potassium ferrate(II) b) Potassium cyano pentanitrosyl ferrate(II)
c) Potassium pentacyanonitrosyl ferrate (III) d) Potassium pentacyanonitrosyl ferrate (II)
116. The colour of [Ti(H2 O)6 ] is due to:
3+

a) Transfer of an electron from one Ti to another

b) Presence of water molecule
c) Excitation of electrons from 𝑑 − 𝑑
d) Intramolecular vibration
117. The oxidation number of Fe in K 4 [Fe(CN)6 ]is
a) +3 b) +4 c) +2 d) −2
118. Correct structures of [E][S]-5-bromo-2,7-dimetyl, non-4-ene is

a) b)

c) d)

119. Name the metal 𝑀 which is extracted on the basis of following reactions,
4𝑀 + 8CN − + 2H2 O + O2 ⟶ 4[𝑀(CN)2 ]− + 4OH −
2[𝑀 (CN)2 ]− + Zn ⟶ [Zn(CN)4 ]2− + 2𝑀:
a) Nickel b) Silver c) Copper d) Mercury
120. EAN of Cr in [Cr(NH3 )6 ]Cl3 is:
a) 32 b) 33 c) 34 d) 35
121. The complex [Pt(NH3 )6 ]Cl4 furnishes:
a) 5 ions b) 6 ions c) 4 ions d) 2 ions
122. Ammoniacal solution of Ni(CN)2 reacts with C6 H6 to produce a light violet coloured crystalline compound
of the formula:
a) Ni(CN)2 ∙ C6 H5 b) C6 H5 CH3 c) Ni(CN)2 C6 H6 d) Ni(CN)2 NH3 ∙ C6 H6
123. Ammonia forms the complex ion [Cu(NH3 )4 ] with copper ions in alkaline solution but not in acidic
2+

solution. What is the reason for it?

a) In acidic solutions, hydration protects copper ions
b) In alkaline solution, insoluble Ci(OH)2 is precipited which in excess of any alkali

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 c) Copper hydroxide is an amphoteric substance
In acidic solutions, protons coordinate with ammonia molecules forming NH4+ ions and NH3 molecules
d)
are not available
124. Which of the following shows geometrical isomerism?
a) 1, 2-dicholoroethane b) 1, 2-dimethylcyclopropane
d) All of the above
c)

125. The shape of the complex [Ag(NH3 )2 ]+ is:

a) Octahedral b) Square planar c) Tetrahedral d) Linear
126. The 𝜋-bounded organometallic compound which has ethane as one of its component is
a) Dibenzene chromium b) Zeise salt c) Ferrocene d) Tetraethyl tin
127. The major product of the following reaction is:

a)

b)

c)

d)

128. Which is true in the case of Ni(CO)4 complex?

a) Hybridization of Ni is 𝑠𝑝3
b) Tetrahedral shape of the molecule
c) Diamagnetic
d) All are correct
129. The reaction, C H N Cl Cu→
2 Cl2 /HCl
C6 H5 Cl + N2 is called:
6 5 2
a) Etard’s reaction b) Sandmeyer’s reaction c) Wurtz-Fittig reaction d) Perkin’s reaction

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130. Which of the following does not show optical isomerism?
a) [Co(en)3 ]3+ b) [Co(en)2 Cl2 ]+ c) [Co(NH3 )3 Cl3 ]0 d) [Co(en)Cl2 (NH3 )2 ]+
131.

Having the IUPAC name as

a) 1, 2-dimethyl cyclobutane b) 2, 3-dimethyl cyclobutene
c) 2, 3-dimethyl butane d) 1, 2-dimethyl cyclobut-1-ene
132. Which of the following ions is produced when we prepare nitrating mixture by mixing together
concentrated HNO3 and concentrated H2 SO4 ?
a) NO− 2 b) NO+ 2 c) NO− 3 d) SO+
3H
133. The correct IUPAC name of

a) 1-brmo-2-chloro-6-fluoro-4-iodobenzene b) 1-bromo-6-chloro-2-fluoro-4-iodobenzene
c) 2-bromo-1-chloro-3-floro-5-iodobenzene d) 2-bromo-3-chloro-1-floro-5-odobenzene
134. [Co NH3 4 NO2 2 ]Cl exhibits:
( ) ( )
a) Ionization isomerism, geometrical isomerism and optical isomerism
b) Linkage isomerism, geometrical isomerism and optical isomerism
c) Linkage isomerism, ionization isomerism and optical isomerism
d) Linkage isomerism, ionization isomerism and geometrical isomerism
135. Which of the following complexes are not correctly matched with hybridisation of their central metal ion?
1. [Ni(CO)4 ] 𝑠𝑝3
2. [Ni(CO)4 ]2− 𝑠𝑝3
3−
3. [CoF6 ] 𝑑2 𝑠𝑝3
4. [Fe(CN)6 ]3− 𝑠𝑝3 𝑑2
Select the correct answer using the codes given below
a) 1 and 2 b) 1 and 3 c) 2 and 4 d) 2, 3 and 4
136. Which of the following is an explosive?
a) PCl5 b) HNO3 c) C6 H5 OH d) 2,4,6-trinitrophenol
137. The coordination number of Cr in [Cr(NH3 )3 (H2 O)3 ]Cl3 is:
a) 3 b) 4 c) 6 d) 2
138. The major product obtained when 3-phenyl-1, 2-propane-diol is heated with H2 SO4 is:
a) C6 H5 —CH2—CO—CH3
b) C6 H5 —CH2—CH2—CHO
c) C6 H5 —CH2—CH = CH2
d)

139. Rate of substitution in phenol is:

a) Slower than as in benzene
b) Faster than as in benzene
c) Equal to that as in benzene
d) None of the above
140. Magnetic moment of [Ag(CN)2 ]− is zero. How many unpaired electrons are there?
a) Zero b) 4 c) 3 d) 1
141. Chlorophyll is a coordination compound having central atom of:
a) Ca b) Mg c) Na d) K

P a g e | 12
142. Which of the following statements is incorrect?
a) In K 3 [Fe(CN)6 ], the ligand has satisfied only the secondary valency of ferric ion.
b) In K 3 [Fe(CN)6 ], the ligand has satisfied both primary and secondary valencies of ferric ion.
c) In K 4 [Fe(CN)6 ], the ligand has satisfied both primary and secondary valencies of ferrous ion.
d) In[Cu(NH3 )4 ]SO4, the ligand has satisfied only the secondary valenecy of copper.
143. Maximum number of open chain isomers that an alkene can have with the molecular formula C4 H8 is
a) 5 b) 4 c) 3 d) 2
144. Which one is the wrong statement?
a) Open chain compounds are called aliphatic
b) Unsaturated compounds contain multiple bonds in them
c) Saturated hydrocarbons are called alkene
d) Aromatic compounds possess a characteristic aroma
145. According to postulates of Werner’s theory for coordination compounds, which of the following is true?
a) Primary valencies are ionizable b) Secondary valencies are ionizable
c) Only primary valencies are non-ionizable d) Primary and secondary valencies are non-
ionizable
146. Atomic numbers of Cr and Fe are respectively 24 and 26. Which of the following is paramagnetic with the
spin of the electron?
a) [Cr(CO)6 ] b) [Fe(CO)5 ] c) [Fe(CN)6 ]4− d) [Cr(NH3 )6 ]3+
147. Which of the following structures correspond to the product expected, when excess of C6 H6 reacts with
CH2 Cl2 in presence of anhy. AlCl3 ?

a) b) c) d)

148. Which of the following will give a pair of enantiomorphs?

a) [Co(en)2 Cl2 ]Cl b) [Cr(NH3 )6 ][Co(CN)6 ]
c) [Pt(NH )
3 4 ][PtCl6] d) [Co(NH3 )4 Cl2 ]NO2
149. The crystal field splitting energy for octahedral(∆0 ) and tetrahedral (∆𝑡 ) complexes is related to
4 1 4
a) ∆𝑡 = ∆0 b) ∆𝑡 = ∆0 c) ∆0 = 2∆𝑡 d) ∆0 = ∆𝑡
9 2 9
150. The correct name of the compound [Cu(NH3 )4 ](NO3 )2 , according to IUPAC system is:
a) Cuprammonium nitrate
b) Tetraamminecopper(II) dinitrate
c) Tetraamminecopper(II) nitrate
d) Tetraamminecopper(I) dinitrate
151. Which among the following will not show chain isomerism?
a) C3 H8 b) C4 H10 c) C5 H12 O d) C5 H10 O
152. Phenol (1 mole) reacts with bromine to give s-tribromophenol. How much bromine is needed?
a) 1.5 mole b) 3.0 mole c) 4.5 mole d) 6.0 mole
153. Dimethyl glyoxime forms a coloured complex with
a) Ag b) Ni c) Cr d) Zn
154. Which has regular tetrahedral geometry?
a) [Ni(CN)4 ]2+ b) SF4 c) [BF4 ]− d) XeF4
155. In haemoglobin the iron shows oxidation state:
a) +2 b) +3 c) +1 d) +4
156. For the given complex [CoCl2 (en)(NH3 )2 ]+ , the number of geometrical isomers, the number of optical
isomers and total number of isomers of all type possible respectively are
a) 2, 2 and 4 b) 2, 2 and 3 c) 2, 0 and 2 d) 0, 2 and 2
157. Which can show aromatic character?

P a g e | 13
 a) Furan b) Pyrrol c) Benzene d) All of these
158. Of the following complexes, the one with the largest value of the crystal field splitting is:
a) [Fe(H2 O)6 ]3+ b) [Ru(CN)6 ]3− c) [Fe(H2 O)6 ]2+ d) [Fe(NH3 )6 ]3+
159. The specific rotation of a pure enantiomer is + 16°. Its observed rotation if it is isolated from a reaction
with 25% recemisation and 75% retention is
a) −12° b) +12° c) +16° d) −16°
160. Lithium tetrahydridoaluminate is correctly represented as:
a) Al[LiH4 ] b) Al2 [LiH4 ]3 c) Li[AlH4 ] d) Li[AlH4 ]2
161. Which of the following compounds is generally used for hydrogenation of alkenes?
a) Ni(CO)4 b) [(C6 H5 )3 P]3 RhCl c) (CH3 )3 Al d) (C5 H5 )2 Fe
162. The end product of the reaction,
Sunlight
C6 H6 + Cl2 → is:
a) C6 H5 Cl b) 𝑜-C6 H4 Cl2 c) C6 H6 Cl6 d) 𝑝-C6 H4 Cl2
163. [Pt(NH3 )6 ]Cl4 complex gives
a) 4 ions b) 3 ions c) 2 ions d) 5 ions
164. Which does not obey EAN rule?
a) [Cu(NH3 )4 ]2+ b) [Zn(OH)4 ]2− c) [HgI4 ]2− d) Fe(CO)5
165. Oxidation number of Fe in K 3 [Fe(CN)6 ] is:
a) +3 b) +2 c) +10 d) 1
166. Which of the following is not an organometallic compound?
a) NaOC2 H5 b) (CH3 )3 Al c) (C2 H5 )4 Pb d) 𝑅Mg𝑋
167. Considering H2 O as weak field ligand, the number of unpaired electrons in
[Mn(H2 O)6 ]2+ will be (Atomic no. of Mn=25)
a) Three b) Five c) Two d) Four
168. The value of ‘spin only’ magnetic moment for one of the following configuration is 2.84 BM the correct one
a) 𝑑4 (in weak ligand field) b) 𝑑 4 (in strong ligand field)
c) 𝑑3 (in weak as well as in strong field) d) 𝑑 5 (in weak ligand field)
169. Fluorobenzene (C6 H5 F) can be synthesized in the laboratory:
a) By heating phenol with HF and KF
b) From aniline by diazotisation followed by heating the diazonium salt with HBF4
c) By direct fluorination of benzene with F2 gas
d) By reacting bromobenzene with NaF solution
170. Which compound burns with a sooty flame?
a) C6 H5 CH2 OH
b) C6 H5 COOH
c) CH3 OH
d) CH3 COC2 H5
171. How many EDTA (ethylenediaminetetraacetic acid) molecules are required to make an octahedral
complex with a Ca2+ ion?
a) Six b) Three c) One d) Two
172. Intramolecular rearrangement of phenyl esters to give 𝑜-and 𝑝-derivatives in presence of AlCl3 is known
as:
a) Friedel-Craft’s reaction
b) Fries rearrangement
c) Esterification
d) Coupling
173. Which reaction can produce R—CO—Ar species?
AlCl3 AlCl3
a) ArCOCl + H—Ar → b) COCl + RMgX ⟶ c) 𝑅COCl + H—Ar → d) 𝑅 + CrO3 ⟶
174. Acidic character of phenol is due to:
a) Resonance of phenoxide ion
P a g e | 14
 b) Tautomerism occurring in phenol
c) The fact that the electronegativity of oxygen is more than that of hydrogen
d) None of the above
175. In triethylenediamine cobalt(III) chloride the coordination number of cobalt is:
a) 3 b) 4 c) 6 d) 7
176. Mark the unidentical compound

a) b) c) d)

177. A complex compound in which the oxidation number of a metal is zero, is

a) K 4 [Fe(CN)6 ] b) K 3 [Fe(CN)6 ] c) [Ni(CO)4 ] d) [Pt(NH3 )4 ]Cl2
178. In the halogenation of aromatic nucleus, the halogen carrier, used to generate the species is:
a) Cl b) Cl+ c) Cl− d) Cl
179. Among [Ni(CN)4 ] , [NiCl4 ] and [Ni(CO)4 ]:
2− 2−

a) [Ni(CN)4 ]2− is square planar and , [NiCl4 ]2− , Ni(CO)4 are tetrahedral
b) [NiCl4 ]2− is square planar and [NiCN4 ]2− , Ni(CO)4 are tetrahedral
c) Ni(CO)4 is square planar and [Ni(CN)4 ]2− , [NiCl4 ]2− are tetrahedral
d) None of the above
180. Benzene is obtained by:
a) Condensation of three C2 H2 molecules
b) Polymerization of three C2 H2 molecules
c) Addition of three C2 H2 molecules
d) Substitution of three acetylene molecules
181. IUPAC name of 𝑡-butyl chloride is
a) 2-chloro butane b) 1-chloro-2-methylpropane
c) 2-chloro-2-methylpropane d) None of the above
182. The 𝑑-electronic configuration of Cr , Mn , Fe , Ni2+ are 3d4 , 3d5 , 3d6 and 3d8 respectively. Which of
2+ 2+ 2+

the following complex will show minimum paramagnetic behaviour?

a) [Fe(H2 O)6 ]2+ b) [Ni(H2 O)6 ]2+ c) [Cr(H2 O)6 ]2+ d) [Mn(H2 O)6 ]2+
183. Phenol is more acidic than cyclohexanol because:
a) Benzene ring exists in resonance
b) Cyclohexane ring shows resonance
c) Phenol is poor in hydrogen
d) Cyclohexanol is rich in hydrogen
184. Total possible structural isomers (not stereo) of C4 H6 are
a) 4 b) 6 c) 9 d) 12
185. In the reaction of 𝑝-chlorotoluene with KNH2 in liq. NH3 the major product is:
a) 𝑜-toluidine b) 𝑚-toluidine c) 𝑝-toluidine d) 𝑝-chloroaniline
186. The type of isomerism in the molecule of compounds CH3 CH2 COCH2 CH3 and CH3 CHC(OH)CH2 CH3 is
referred as:
a) Metamerism
b) Chain isomerism
c) Functional isomerism
d) Tautomerism
187. Phenol is less soluble in water. It is due to:
a) Non-polar nature of phenol
b) Acidic nature of−OH group
c) Non-polar hydrocarbons part in it
d) None of the above

P a g e | 15
188. When phenol is treated with excess bromine water, it gives:
a) 𝑚-bromophenol
b) 𝑜-and 𝑝-bromophenol
c) 2,4-dibromophenol
d) 2,4,6-tribromophenol
189. Which have octahedral shape (𝑑 2 𝑠𝑝3 ) hybridization of central atom?
a) [Cr(NH3 )6 ]2+ b) [Fe(CN)6 ]3− c) [Cu(NH3 )6 ]+ d) All are correct
190. Which of the following molecules/species are aromatic in character?

a) 2 b) 3 c) 4 d) 1
191. Among the following compounds ;

the order of basicity is :

a) IV > III > II > I b) II > I > III > IV c) III > IV > II > I d) I > III > IV > II
192.

a) Tri-μ-carbonyl 𝑏𝑖𝑠-(tricarbonyl)iron (0)

b) Hexacarbonyl iron (III) μ-tricarbonyl ferrate(0)
c) Tricarbonyl iron(0) μ-tricarbonyl iron(0) tricarbonyl
d) Nonacarbonyl iron
193. Which is high spin complex?
a) [CoCl6 ]3− b) [FeF6 ]3− c) [Co(NH3 )6 ]2+ d) All are correct
194. The correct IUPAC name of tartaric acid is
a) 1, 4-dicarboxy-2, 3-dihydroxy ethane b) α, α′-dihydroxy butane-1,4-dioic acid
c) 1, 4-dihydroxybutane-2, 3-dioic acid d) 2, 3-dihydroxybutane-1, 4-dioic acid
195. What is the overall formation equilibrium constant for the ion[𝑀𝐿4 ]2− ion, given that β4 for this complex is
2.5 ⨯ 1013 ?
a) 2.5 ⨯ 1013 b) 5 ⨯ 10−13 c) 2.5 ⨯ 10−14 d) 4.0 ⨯ 10−13
196. The oxidation state of Cr in [Cr(NH3 )4 Cl2 ]+ is
a) 0 b) +1 c) +2 d) +3
197. Which of the following compounds has the most acidic nature?

a) b) c) d)

198. The oxidation state of Mo in its oxo-complex species [Mo2 O4 (C2 H4 )2 (H2 O)2 ]2− is:
a) +2 b) +3 c) +4 d) +5
199. CH3 MgI is an organometallic compound due to
a) Mg —I bond b) C —I bond c) C—Mg bond d) C —H bond
200. The effective atomic number of Cr (At. No.=24)in [Cr(NH3 )6 ]Cl3 is
a) 35 b) 27 c) 33 d) 36
201. When aniline is heated with benzaldehyde, the product is:
a) Benzoin b) Schiff ’s base c) Unsaturated acid d) Azoxy benzene

P a g e | 16
202. Slow heating of salicylic acid gives:
a) Benzoic acid b) Phenol c) Benzaldehyde d) None of these
203. According to Hückel, monocyclic compounds will show aromaticity when:
a) It has 4π-electrons
b) It has no π-electron
c) It has 4π+2 electrons
d) It has (4𝑛 + 2)π-electrons
204. When phenol is distilled with zinc dust, it gives:
a) Benzene b) Toluene c) C6 H5 CHO d) None of these
205. The IUPAC name of the given structure

is
a) N-chloro-N-bromoethanamide b) N-bromo-N-chloroethanamide
c) N-bromo-N-chloroacetamide d) N-chloro-N-bromoacetamide
206. Acetophenone when reacted with a base C2 H5 ONa, yields a stable compound which has the structure:

a)

b)

c)

d)

207. Which of the following has maximum resonance energy?

a) Diphenyl b) Benzene c) Naphthalene d) Phenanthrene
208. Benzene sulphonic acid on treating with P2 O5 gives:
a) Salicylic acid b) Benzoic acid c) Acid anhydride d) Sodium benzoate
209. Compounds with following formula will show
Cl
|
(i) CH3 CH2 CHCH2 CH3 and (ii) CH3 CH2 C − CH3
| |
Cl CH3
a) Position and functional isomerism
b) Chain and positional isomerism
c) Chain and functional isomerism
d) None of the above combinations
210. Which of the following statements is correct?
a) In K 3 [Fe(CN)6 , the ligand has satisfied both primary and secondary valencies of ferric ion
b) In (Cu(NH3 )4 SO4 , the ligand has satisfied only the secondary valency of copper
c) In K 3 [Fe(CN)6 , the ligand has satisfied only the secondary valency of ferric ion
d) Both (b) and (c)
211. Which statement is not correct?
a) Fe(CO)5 reacts with Br2 Cl4
P a g e | 17
 b) Carbonyl complexes are usually formed with transition metals
c) All transition metals form monometallic carbonyls
d) The decomposition of Ni(CO)4 to give Ni is used in the extraction of Ni by Mond’s process
212. The complex showing a spin-only magnetic moment of 2.82 BM is
a) Ni(CO)4 b) [NiCl4 ]2− c) Ni(PPh3 )4 d) [Ni(CN)4 ]2−
213. The IUPAC name of [CoCl(NO2 )(en)2 ]Cl is:
a) Chloronitro-𝑏𝑖𝑠(ethylenediamine) cobaltic(III) chloride
b) Chloronitro-𝑏𝑖𝑠(ethylenediamine)cobalt(II) chloride
c) Chloro-𝑏𝑖𝑠(ethylenediamine)nitrocobalt(III) chloride
d) 𝐵𝑖𝑠-(ethylenediamine)chloronitrocobalt(III) chloride
214. The product of acid catalysed hydration of 2-phenyl propene is:
a) 3-phenyl-2-propanol
b) 1-phenyl-2-propanol
c) 2-phenyl-2-propanol
d) 2-phenyl-1-propanol
215. Carbolic acid is the name used for:
a) Opium b) Phenol c) Chloroform d) H2 CO3
216. The major product of the following reaction

a)

b)

c)

P a g e | 18
 d)

217. The oxidation number of cobalt in K[Co(CO)4 ] is

a) −1 b) +3 c) +1 d) −3
218. Formaldehyde-phenol resin is:
a) Orlon b) Nylon c) Teflon d) Bakelite
219. Among the ligands NH3 ,en, CN and CO , the correct order of their increasing field strength, is
−

a) CO < NH3 <en < CN − b) NH3 < en < CN − < CO

c) CN < NH3 < CO < en
−
d) en < CN − < NH3 < CO
220. Cyclopentadienyl anion is aromatic due to the presence of:
a) 6π-electrons b) 10 π-electrons c) 4 π-electrons d) 12 π-electrons
221. The IUPAC name of K 4 [Fe(CN)6 ] is
a) Potassium ferrocyanide b) Potassium hexa cyanoferrate (I)
c) Tetra potassium hexa cyanoferrate (II) d) Potassium hexa cyanoferrate (II)
222. Which xylene is most easily sulphonated?
a) 𝑂𝑟𝑡ℎ𝑜 b) 𝑃𝑎𝑟𝑎 c) 𝑀𝑒𝑡𝑎 d) All at the same rate
223. The IUPAC name of following polyfunctional compound is

a) 2,4-dioxo cyclohexanoic acid b) 2,4-dioxo cycloheptanoic acid

c) 4-formyl-2-oxo cyclohexane-1-carboxylic acid d) 2,4-dioxo cyclohexane-1-carboxylic acid
224. Alkyl groups are 𝑜- and 𝑝-directing because of:
a) Resonance effect
b) Inductive effect
c) Resonance effect through hyperconjugation
d) All of the above
225. Racemic modification can be resolved by
a) The use of enzymes b) Fractional crystallisation
c) Fractional distillation d) None of the above
226. Which of the following structure contain 1 primary and 7 secondary hydrogen atoms?
CH3 − CH − CH2 − CH2
| |
a) CH3 CH − CH3
|
CH3
CH3
|
b) CH3 − CH2 − CH2 − CH
|
CH2 − CH3
CH3
c) |
CH3 − CH2 − CH − CH2 − CH3
d) CH3 − CH2 − CH2 − CH2
P a g e | 19
 |
CH2 − CH3
227. Which of the following compounds does not dissolve in conc. H2 SO4 even on warning?
a) Ethylene b) Benzene c) Hexane d) Aniline
228. In the complex Fe(CO)x , the value of 𝑥 is and it is:
a) 3, octahedral b) 4, tetrahedral c) 5, trigonal pyramidal d) 6, square pyramidal
229. The empirical formula of naphthalene is:
a) CH2 b) C5 H4 c) C2 H d) C𝑛 H2𝑛
230. The chemical formula of diammine silver (I) chloride is
a) [Ag(NH3 )Cl] b) [Ag(NH3 )3 ]Cl c) [Ag(NH4 )2 ]Cl d) [Ag(NH3 )2 ]Cl
231. For the square planar complex [M (a)(b)(c)(d)] (where , M=central metal and a, b, c, and d are
monodentate ligands), the number of possible geometrical isomers are
a) 1 b) 2 c) 3 d) 4
232. Which group is 𝑚𝑒𝑡𝑎 directing?
a) −CCl3 b) −OH c) −NH2 d) −CH3
233. The IUPAC name of the compound [Cu(NH3 )4 (NO3 )2 ] is:
a) Cuprammonium nitrate
b) Dinitratotetraamminecopper(II)
c) Tetraamminecopper(II) dinitrite
d) Tetraamminecopper(III) dinitrite
234. Coordination number of Fe in the complexes [Fe(CN)6 ]4− , [Fe(CN)6 ]3− and [FeCl4 ]− would be respectively
a) 6, 4, 6 b) 6, 6, 4 c) 6, 3, 3 d) 2, 3, 3
235. Which statement is true for cyclohexane?
a) It has two possible isomers
b) It has three conformations
c) Boat conformation is most stable
d) Chair and boat conformations differ in energy by 44 kJ/mol
236. Ligands in a complex salt are:
a) Anions linked by coordinate bonds to a central metal atom or ion
b) Cations linked by coordinate bonds to a central metal atom or ion
c) Molecules linked by coordinate bonds to a central metal atom or ion
d) Ions or molecules linked by coordinate bonds to a central metal atom or ion
237. The IUPAC name of CH3 COCH2 COOC2 H5 is
a) Ethyl butanoate b) Ethyl-(3-oxo)butanoate
c) Ethyl butan-1-oate-2-one d) Ethyl butan-4-oate-2-one
238. When benzene is treated with CO and HCl in presence of anhydrous aluminium chloride, benzaldehyde is
formed. This reaction is known as:
a) Friedel-Craft’s reaction
b) Rosenmund’s reaction
c) Stephen’s reaction
d) Gattermann-Koch’s reaction
239. [Cr(NH3 )6 ]3+ ion is:
a) Paramagnetic b) Diamagnetic c) Square planar d) None of these
240. The following compound can exhibits

a) Tautomerism b) Optical isomerism

c) Geometrical isomerism d) Geometrical and optical isomerism
241. Which complex is diamagnetic?

P a g e | 20
 a) [Fe(CN)6 ]4− b) [Cu(NH3 )4 ]3+ c) [Ti(H2 O)6 ]3+ d) None of these
242. 𝑀𝑒𝑠𝑜-tartaric acid is optically inactive due to the presence of
a) Molecular symmetry b) Molecular asymmetry
c) External compensation d) Two asymmetric C-atoms
243. Complex forming tendency increases with:
a) Increase in size of cation
b) Decrease in size of cation
c) Increase in size of anion
d) None of the above
244. Ziegler-Natta catalyst is
a) (Ph3 P)3 RhCl b) Al2 (C2 H6 )6 + TiCl4
c) Fe(C2 H5 )2 d) K[PtCl3 (C2 H4 )]
245. Among the following compounds the one that is most reactive towards electrophilic nitration is:
a) Toluene b) Benzene c) Benzoic acid d) Nitrobenzene
246. Phenol on oxidation gives chloranil. The oxidant used is:
a) K 2 S2 O8 b) KMnO4 c) KClO3 + HCl d) None of these
247. The IUPAC name of the compound

is
a) 3-sec-butyl-5-ethyl-3-methyloctane b) 4-sec-butyl-5-ethyl-3-methyloctane
c) 5-sec-butyl-4-ethyl-3-methyloctane d) 4-sec-butyl-3-ethyl-5-methyloctane
248. All the common 𝑚-directing groups……the benzene ring towards electrophilic substitution reactions.
a) Deactivate b) Activate c) Both (a) and (b) d) None of these
249. Among the following, the coloured compound is :
a) CuCl b) K 3 C4 (CN)4 c) CuF2 d) [Cu(CH3 CN)4 ]BF3
250. The existence of two different coloured complexes with the composition of [Co(NH3 )4 Cl2 ]+ is due to:
a) Linkage isomerism
b) Geometrical isomerism
c) Coordination isomerism
d) Ionisation isomersim
251. [Co(NH3 )4 Cl2 ] possesses:
a) Square planar geometry
b) Tetrahedral geometry
c) Tetrahedral nature
d) Octahedral geometry
252. Which one does not belong to ligand?
a) PH3 b) NO+ c) BF3 d) Cl−
253. Product formed in the reaction;

a) b) c) d)

254. Which one of the following has square planar structure?

a) [Ni(CN)4 ]2− b) [Ni(CO)4 ] c) [NiCl4 ]2− d) All of these

P a g e | 21
255. 4-methyl benzene sulphonic acid reacts with sodium acetate to give:

a) b) c) d)

256. Phthalein test is characteristics of ….and is given by it.

a) Alcohols b) Phenols c) Aldehydes d) Ketones
257. Which of the following compounds would exhibit coordination isomerism?
a) [Cr(H2 O)6 ]Cl2 b) [Cr(NH3 )6 ][Co(CN)6 ] c) [Cr(en)2 ]NO2 d) [Ni(NH3 )6 ][BF4 ]2
258. In a reaction of aniline a coloured product C was obtained.

The structure of 𝐶 would be:

a)

b)

c)

d)

259. The carboxyl functional group (−COOH) is present in:

a) Picric acid
b) Barbituric acid
c) Ascorbic acid
d) Aspirin
260. Which of the following is an example of electrophilic substitution reaction?
a) Acylation b) Alkylation c) Benzoylation d) All of these
261. The number of ions given by [Co(NH )
3 4 ]Cl3 in aqueous solution is:
a) 2 b) 3 c) 1 d) 4
262. Which of the following is an organometallic compound?
a) Ti(OC6 H5 )4 b) Ti(OCOCH3 )4 c) Ti(OC2 H5 )4 d) Ti(C2 H5 )4
263. A solution of CuCl in NH4 OH is used to measure the amount of which gas is a sample by simply measuring
change in volume?
a) CO2 b) H2 c) CO d) All of these
264. On passing benzene vapour through a tube at 700-800C or through molten lead we get:
a) Diphenyl b) Phenol c) Toluene d) Benzaldehyde
265. Picric acid is a yellow coloured compound. Its chemical name is:
a) 𝑚-nitrobenzoic acid b) 2,4,6-trinitrophenol c) Trinitrotoluene d) Trinitroaniline
266. The ideal starting material for the synthesis of 𝑚-chloronitro benzene is:

P a g e | 22
 a) Benzene b) Chlorobenzene c) Toluene d) Nitrobenzene
267. In a reaction involving ring substitution of C6 H5 𝑌, the major product is 𝑚𝑒𝑡𝑎-isomer. The group 𝑌 can be:
a) —NH2 b) —COOH c) —CH3 d) —Cl
268. When ammonia is added to green aqueous solution of nickel(II) sulphate, the colour of the solution
changes to blue violet. This is caused by:
a) Nickel undergoing a change in oxidation state
b) Ammonia molecules replacing water molecules surrounding nickel
c) Change in coordination number of nickel
d) Change in pH value of the solution
269. The compound, whose stereo chemical formula is written below, exhibits 𝑥-geometrical isomers and 𝑦-
optical isomers. The value of 𝑥 and 𝑦 are

a) 4 and 4 b) 2 and 2 c) 2 and 4 d) 4 and 2

270. Among the following-phenol, benzoic acid, nitrobenzene and toluene, the compound that undergoes
nitration readily is:
a) Benzoic acid b) Toluene c) Phenol d) Nitrobenzene
271. Which one is organometalllic compound?
a) Lithium acetate b) Lithium methoxide
c) Lithium dimethyl amide d) Methyl lithium
272. What are the products formed when an equimolar mixture of benzaldehyde and formaldehyde is heated
with concentrated NaOH?
a) C6 H5 —CH2—OH and H—COONa
b) C6 H5 —COONa and CH3—OH
c) C6 H5 —CH2—COONa
d) C6 H5 —COOH and CH3—ONa
273. Gammexane (a 𝛾-isomer of) is:
a) BHC
b) Benzene hexachloride
c) Lindane
d) All of these
274. Number of electrons gained by Pd in [PdCl4 ]2−:
a) 4 b) 8 c) 10 d) 0
275. Which of the following is considered to be an anticancer species?

a) b)

c) d)

276. For benzaldehyde which of the following is incorrect?

a) It is an aromatic aldehyde

P a g e | 23
 b) It is used in perfumery
c) On oxidation it yields benzoic acid
d) On reduction it yields phenol
277. The main source of aromatic compounds is:
a) Wood b) Petroleum c) Coal d) Both (b) and (c)
278. Phenol on hydrogenation in presence of a nickel catalyst at 160C gives:
a) Benzene b) Cyclohexane c) Cyclohexanol d) 𝑛-hexanol
279. The IUPAC name of compound

is
a) Hexane-1, 2, 5-tricarbonitrile b) Hexane-1, 3, 6-tricarbonitrile
c) Butane-1, 2, 4-tricarbonitrile d) Butane-1, 3, 4-tircarbonitrile
280. Fac-mer isomerism is associated with which one of the following complexes? (M=central metal)
a) [𝑀(𝐴𝐴)2 ] b) [𝑀𝐴3 𝐵3 ] c) [𝑀(𝐴𝐴)3 ] d) [𝑀𝐴𝐵𝐶𝐷]
281. Which of the following is the correct order of stability of the following four distinct conformation of 𝑛
butane?
a) Staggered > Gauche > Partially eclipsed > Fully eclipsed
b) Gauche > Staggered > partially eclipsed > Fully eclipsed
c) Staggered > Partially eclipsed > Gauche > Fully eclipsed
d) Fully eclipsed > Staggered > Partially eclipsed > Gauche
282. 𝑜-nitrophenol can form hydrogen bonds within the molecule. It thus, has:
a) Very high m.p. b) Very high viscosity c) Low m.p. d) none of these
283. The element which does not form mononuclear carbonyl is:
a) Fe b) Mn c) Ni d) W
284. Which of the following is hexadentate ligand?
a) Ethylene diamine b) Ethylene diamine tetra acetic acid
c) 1,10-phenanthroline d) Acetyl acetonato
285. The molecular formula of a saturated compound is C2 H4 Cl2 . The formula permits the existence of two
a) Functional isomers b) Position isomers c) Optical isomers d) 𝑐𝑖𝑠 − 𝑡𝑟𝑎𝑛𝑠 isomers
286. An octahedral complex is formed when hybrid orbitals of the following type are involved
a) 𝑠𝑝3 b) 𝑑𝑠𝑝2 c) 𝑑 2 𝑠𝑝3 d) 𝑠𝑝2 𝑑2
287. The IUPAC name of the given compound CH3 − CH = CH − COOC2 H5 is
a) Ethyl propenoate b) Ethyl-2-butenoate
c) Ethyl-1-butenoate d) Propene ethyl methanoate
288. Which product is not obtained by heating wood or coal in the absence of air?
a) Coal-tar b) Naphthalene c) Benzene d) Wax
289. Dry distillation of calcium benzoate with calcium formate gives:
a) Acetaldehyde b) Benzoic acid c) Benzaldehyde d) Benzoic anhydride
290. Which will give Fe ions in solution?
3+

a) [Fe(CN)6 ]3−
b) Fe2 (SO4 )3
c) [Fe(CN)6 ]4−
d) NH4 (SO4 )2 ∙ FeSO4 ∙ 6H2 O
291. Each metal possesses:
a) Primary valencies satisfied by anions only
b) Secondary valencies satisfied by donor molecules
c) Coordination number
d) All of the above
292. Aspirin is:
a) Antibiotic b) Antipyretic c) Sedative d) Psychedelic

P a g e | 24
293. Hybridisation, shape and magnetic moment of K 3 [Co(CO3 )3 ] is
a) 𝑑2 𝑠𝑝 3 , octahedral, 4.9 BM b) 𝑠𝑝 3 𝑑2 , octahedral, 4.9 BM
c) 𝑑𝑠𝑝 2 , square planer, 4.9 BM d) 𝑠𝑝 3 , tetrahedral, 4.9BM
294. Among the following complexes (K-P),
K 3 [Fe(CN)6 ](𝐾) , [Co(NH3 )6 ]Cl3 (𝐿),
Na3 [Co(ox)3 ](𝑀)
[Ni(H2 O)6 ]Cl2 (𝑁) , and
[Zn(H2 O)6 ](NO3 )2 (𝑃) the diamagnetic complexes
a) K, L, M, N b) K, M, O, P c) L, M, O, P d) L, M, N, O
295. Aniline when diazotised in cold and then treated with dimethyl aniline gives a coloured product. It
structure would be:

a)

b)

c)

d)

296. Pyridine possesses:

a) Aromatic nature
b) Unsaturated aliphatic nature
c) Alicyclic nature
d) Aliphatic nature
297. A reagent used for identifying nickel ion is:
a) Potassium ferrocyanide
b) Phenolphthalein
c) Dimethyl glyoxime
d) EDTA
298. Aniline was diazotised and subsequently reduced with stannous chloride and hydrochloric acid to yield:
a) Phenyl aniline b) Phenyl hydrazine c) 𝑝-amino azobenzene d) Diazoamino benzene
299. The reaction of toluene with Cl2 in presence of FeCl3 gives predominantly:
a) 𝑚-chlorobenzene
b) Benzoylchloride
c) Benzyl chloride
d) 𝑜- and 𝑝-chlorobenzene
300. Which statement is not correct in the case of [Co(NH3 )6 ]3+ complex?
a) It is octahedral in shape
b) It involves 𝑑2 𝑠𝑝2 -hybridization
c) It has diamagnetic nature
d) None of the above
301. Pick out the complex compound in which the central metal atom obeys EAN rule strictly
a) K 4 [Fe(CN)6 ] b) K 3 [Fe(CN)6 ] c) [Cr(H2 O)6 ]Cl3 d) [Cu(NH3 )4 ]SO4
302. Amongst the following, the compound that can be most readily sulphonated is:
a) Benzene b) Methoxy benzene c) Toluene d) Chlorobenzene
303. 𝑝-chloroaniline and anilium hydrochloride can be distinguished by:
a) P2 O5 b) AgNO3 c) Carbylamine test d) Sandmeyer’s reaction
304. Pyrogallol is….. trihydroxy benzene.

P a g e | 25
 a) 1, 2, 4 b) 1, 2, 3 c) 1, 3, 5 d) None of these
305. Phenol is weakly acidic but does not react withNaHCO3 like carboxylic acids hence:
a) Phenol is weaker than carbonic acid
b) Phenol is stronger than acid
c) Phenol is stronger than carboxylic acid
d) None of the above
306. 𝑝-cresol reacts with chloroform in alkaline medium to give compound (𝐴) which adds hydrogen cyanide to
form compound (𝐵). The latter on acidic hydrolysis gives chiral carboxylic acid. The acid is:

a) b) c) d)

307. The number of isomeric xylenes is:

a) 2 b) 3 c) 4 d) 1
308. The IUPAC name of [Cr(H2 O)4 Cl2 ]Cl is:
a) Tetrahydrodichlorochromium(III) chloride
b) Tetraaquodichlorochromium(III) chloride
c) Tetraaquodichlorochromium(I) chloride
d) None of the above
309. Among the following metal carbonyls, C— O bond order is lowest in
a) [Mn(CO)6 ]+ b) [Fe(CO)5 ] c) [Cr(CO)6 ] d) [V(CO)6 ]−
310.

a) 3-propyl-1,3-pentadiene b) 3,3-dipropyl-1,3-pentadiene
c) 3,3-diethenyl penta-1,4-diene d) 4,4-diethenyl penta,1,2-diene
311. Which of the following shell, form an outer octahedral complex?
a) 𝑑4 b) 𝑑8 c) 𝑑 6 d) None of these
312. Friedel-Craft’s reaction of bromobenzene with methyl iodide gives:
a) 𝑜-bromotoluene
b) 𝑝-bromotoluene
c) 𝑜-and 𝑝-bromotoluene
d) 𝑚-bromotoluene
313. An organic compound C7 H8 O is neither soluble in NaOH nor gives blue colour with FeCl3 , is:
d) None of these
a) C6 H5 ∙ CH2 OH b) c) C6 H5 ∙ OCH3

314. Which exist as a pair of mirror image isomers?

a) b) c) d)

315. Benzene double bonds are not so reactive as those of hexatriene because:
a) The three double bonds are caged in a ring
b) Benzene is aromatic and has six π-resonating electrons
c) Benzene has no double bond

P a g e | 26
 d) Benzene is non-polar
316. The most stable ion is
a) [Fe(OH)5 ]3− b) [FeCl6 ]3− c) [Fe(CN)6 ]3− d) [Fe(H2 O)6 ]3+
317. Which of the following is/are threo isomers?

a) Only (i) b) Only (ii)

c) Only (iii) d) All (i), (ii) and (iii)
318. In the coal-tar distillation of middle oil, the aromatic compounds present are:
a) Benzene, naphthalene, anthracene
b) Naphthalene, pyridine, phenol
c) Naphthalene, pyridine
d) None of the above
319. The correct order of increasing reactivity of C—𝑋 bond towards nucleophilic in the following compound
is:

a) I<II<IV<III b) II<III<I<IV c) IV<III<I<II d) III<II<I<IV

320. Which of the following system is most stable for a chelate?
a) Two fused cyclic system b) Three fused cyclic system
c) Four fused cyclic system d) Five fused cyclic system
321. Which of the following reaction take place when a mixture of concentrated HNO3 and H2 SO4 reacts on
benzene at 300 K?
a) Sulphonation b) Nitration c) Hydrogenation d) Dehydration
322. Consider the following reaction:

a) Benzene b) Toluene c) Benzaldehyde d) Benzoic acid

323. The shortest C—O bond order exists in:
a) [Mn(CO)6 ]+ b) [Fe(CO)5 ] c) [Cr(CO)6 ] d) [V(CO)6 ]−
324. Between 𝑝-nitrophenol and salicyladehyde, solubility in base is:
a) Almost nil in both cases
b) Higher in 𝑝-nitrophenol
c) Higher for salicyladehyde
d) Equal in nature
325. (+) and (-) forms of optically active compounds are different in
a) Boiling points b) Melting points c) Specific gravity d) Specific rotation
326. Benzene on treatment with dry HCN and HCl in presence of anhy. AlCl3 followed by hydrolysis forms:
a) Chlorobenzene b) Benzoic acid c) Benzaldehyde d) Cyanobenzene
327. In which of the following compounds does the central atom obey EAN rule?
a) K 3 Fe(CN)6 b) K 4 Fe(CN)6 c) Cu(NH3 )4 SO4 d) All of these
328. Pick the correct name of [Co(NH )
3 5 Cl]Cl2
a) Chloropentammine cobalt (III) chloride b) Chloropentammine cobalt (III)
c) Chloropentammine cobalt (II) chloride d) Pentammine chloro cobalt(III) chloride
P a g e | 27
329. The geometry of Ni(CO)4 and Ni(PPh3 )2 Cl2 are
a) Square planar and terrahedral respectively b) Both tetrahedral
c) Tetrahedral and square planer respectively d) Both square planar
330. Select pair of chain isomers from the following

a) I and II b) II and III c) I and IV d) II and III

331. Which ligand produces a high crystal field splitting (a strong ligand field)?
a) CO b) NO− 2 c) CN− d) All are correct
332. Benzene reacts with 𝑛-propyl chloride in the presence of anhydrous AlCl3 to give predominantly:
a) Isopropyl benzene
b) No reaction
c) 𝑛-propylbenzene
d) 3-propyl-1-chlorobenzene
333. Which of the following coordination compounds would exhibit optical isomerism?
a) Pentaamminenitrocobalt (III) iodide b) Diamminedinitroplatinum (II)
c) trans-dicyanobis (ethylenediamine) d) Tris-(ethylenediamine) cobalt(III) bromide
334. What is the magnetic moment of K 3 [FeF6 ]?
a) 3.87 BM b) 4.89 BM c) 5.91 BM d) 6.92 BM
335. The EAN of Cr in [Cr(SCN)6 ] is:
3−

a) 35 b) 33 c) 34 d) 37
336. Which has maximum paramagnetic character?
a) [Fe(CN)6 ]4− b) [Cu(H2 O)4 ]2+ c) [Cu(NH3 )4 ]2+ d) [Mn(H2 O)6 ]2+
337. Phenol, when it first reacts with concentrated sulphuric acid and then with concentrated nitric acid, gives:
a) Nitrobenzene
b) 2, 4, 6-trinitrobenzene
c) 𝑜-nitrophenol
d) 𝑝-nitrophenol
338. Activation of benzene ring by —NH2 in aniline can be reduced by treating with:
a) Dil. HCl b) Ethyl alcohol c) Acetic acid d) Acetyl chloride
339. Sulphonation of benzoic acid produces mainly:
a) 𝑜-sulphobenzoic acid
b) 𝑚-sulphobenzoic acid
c) 𝑝-sulphobenzoic acid
d) 𝑜-𝑝-disulphobenzoic acid
340. The IUPAC name for the complex [Co(NO2 )(NH3 )5 ]Cl2 is
a) Nitrito -N- pentamminecobalt (III) chloride b) Nitrito -N- pentamminecobalt (II) chloride
c) Pentammine nitrito-N- cobalt (II) chloride d) Pentaammine nitrito-N- cobalt (III) chloride
341. The ionisation isomer of [Cr(H2 O)4 Cl(NO2 )C] is
a) [Cr(H2 O)4 (O2 N)]Cl2 b) [Cr(H2 O)4 Cl2 ](NO2 )
c) [Cr(H2 O)4 Cl (ONO)] Cl d) [Cr(H2 O)4 Cl2 (NO2 )]. H2 O
342. Salicylic acid, aspirin, nylon, plastics and picric acid have a common raw material, namely:
a) Methane b) Formic acid c) Phenol d) Alcohol
343. Ulmann’s reaction is used for the preparation of:
a) Diphenyl b) Iodobenzene c) Toluene d) Naphthalene
344. Which of the following statements is/are incorrect for 𝐷 − (+) −glyceradehyde?
a) The symbol 𝐷 not indicates the dextrorotatory nature of the compound

P a g e | 28
 b) The sign (+) indicates the dextrorotatory nature of the compound
The symbol 𝐷 indicates that hydrogen atom lies left to the chiral centre in the Fischer projection
c)
diagram
The symbol 𝐷 indicates that hydrogen atom lies right to the chiral centre in the Fischer projection
d)
diagram
345. Complexes with CN− ligands are usually:
a) High spin complexes b) Low spin complexes c) Both (a) and (b) d) None of these
346. The IUPAC of

is
a) 2-cyclopentyl propane b) 1, 1-dimethyl-1-cyclopentyl methane
c) 1-(1-methyl) ethyl cyclopentane d) None of the above
347. Which ion is paramagnetic?
a) [Ni(H2 O)6 ]2+ b) [Fe(CN)6 ]4− c) [Ni(CO)4 ] d) [Ni(CN)4 ]2−
348.

Configuration of are
a) 𝑅, 𝑅 b) 𝑅, 𝑆 c) 𝑆, 𝑆 d) 𝑆, 𝑅
349. Dow process is used for the conversion of chlorobenzene to:
a) Benzene b) Nitrobenzene c) Phenol d) Gammexane
350. Phenolphthalein is produced on heating phthalic anhydride and conc. sulphuric acid with:
a) Salicylic acid b) Phenol c) Phenacetin d) Phenanthrene
351. Benzene is converted to toluene by:
a) Friedel-Crafts reaction
b) Grignard reaction
c) Wurtz reaction
d) Perkin’s reaction
352. The number of ions formed when hexamine copper (II) sulphate is dissolved in water is?
a) 1 b) 2 c) 4 d) 6
353. In a set of reactions 𝑚-bromobenzoic acid gave a product 𝐷, Identify the product 𝐷:

a) b) c) d)

354. In [Cr(C2 O4 )3 ]3− , the isomerism shown is:

a) Ligand b) Optical c) Geometrical d) Ionization
355. The hybridization of Fe in K 4 [Fe(CN)6 ] complex is:
a) 𝑑2 𝑠𝑝2 b) 𝑑2 𝑠𝑝3 c) 𝑑𝑠𝑝2 d) 𝑠𝑝3
356.
The correct name of is

a) Hex-3-yn-5-ene b) Hex-5-en-3-yne c) Hex-3-yn-1-ene d) Hex-1-en-3-yne

357. Nickel metal is in highest oxidation state in:

P a g e | 29
 a) Ni(CO)4 b) K 2 NiF6 c) [Ni(NH3 )6 ](BF4 )2 d) K 4 [Ni(CN)6 ]
358. Which of the following complexes show six coordination number?
a) [Zn(CN)4 ]2− b) [Ni(NH3 )4 ]2+ c) [Cu(CN)4 ]2− d) [Cr(H2 O)6 ]3+
359. Which of the following statements is wrong?
a) The IUPAC name of alkenes ends with suffix-ene
b) The IUPAC name of alkynes ends with suffix-yne
c) The IUPAC name of acid amide is alkanamide
d) The substituents get lower number in comparison to principal functional group
360. The possible number of isomers for the complex [MCl2 Br2 ]SO4 is:
a) 1 b) 2 c) 4 d) 5
361. K 3 [(Al)(C2 O4 3 ] is called
)
a) Potassium aliminium (III) oxalate b) Potassium alumino oxalate
c) Potassium trioxalato aluminate (VI) d) Potassium trioxalato aluminate (III)
362. In Fe(CO)5 , the Fe — C bond possesses
a) π −Character only b) Both σ and π −characters
c) Ionic characters d) σ −Character only
363. The reaction, [Fe(CNS)6 ] ⟶ [FeF6 ] taken place with
3− 3−

a) Decrease in magnetic moment b) Increase in magnetic moment

c) Decrease in coordination number d) Increase in coordination number
364. Which chloro derivative of benzene among the following would undergo hydrolysis most readily with
aqueous NaOH to furnish the corresponding hydroxyl derivative?

a)

b)

c)

d) C6 H5 Cl
365. Some salts although containing two different metallic elements give test for only one of them in solution.
Such salts are:
a) Complex salts b) Double salts c) Normal salts d) None of these
366. Mixture 𝑋 = 0.02 mole of [Co(NH3 )5 SO4 ]Br and 0.02 mole of [Co(NH3 )5 Br]SO4 was prepared in 2 litre of
solution.
1 litre of mixture X +excess AgNO3 ⟶ 𝑌.
1 litre of mixture X + excess BaCl2 ⟶ 𝑍.
No. of moles of 𝑌 and 𝑍 are.
a) 0.01, 0.01 b) 0.02, 0.01 c) 0.01, 0.02 d) 0.02, 0.02
367. The hybridization of central metal ion and shape of Wilkinson’s catalyst is
a) 𝑠𝑝3 𝑑, trigonal bipyramidal b) 𝑠𝑝3 ,tetrahedral
c) 𝑑𝑠𝑝 2 ,squre planar d) 𝑑 2 𝑠𝑝2 , octahedral
368. The 𝑑-electron configurations of Cr 2+ , Mn2+ , Fe2+ and Co2+ are 𝑑4 , 𝑑5 , 𝑑6 𝑎𝑛𝑑 𝑑7 respectively. Which one
of the following will exhibit minimum paramagnetic behaviour?
a) [Cr(H2 O)6 ]2+
b) [Mn(H2 O)6 ]2+
c) [Fe(H2 O)6 ]2+
[Co(H2 O)6 ]2+
d)
(At. Nos. Cr = 24, Mn = 25, Fe = 26, Co = 27)

P a g e | 30
369. An enantiomerically pure acid is treated with racemic mixture of an alcohol having one chiral carbon. The
ester formed will be
a) Optically active mixture b) Pure enantiomer
c) 𝑚𝑒𝑠𝑜 compound d) Racemic mixture
370. Which of the following ring is most strained?
a) Cyclohexane b) Cyclopentane c) Cyclobutane d) Cyclopropane
371. Formylchloride has not been prepared so far. Which can function as formylchloride in formylation?
a) HCHO + HCl b) HCOOCH3 + HCl c) CO + HCl d) HCONH2 + HCl
372. In hexacyanomanganate (II) ion the Mn-atom assumes 𝑑 𝑠𝑝 -hybrid state. The number of unpaired
2 3

electrons in the complex is:

a) 1 b) 2 c) 3 d) 0
373. Which one of the following does not give a white precipitate with silver nitrate solution?
a) [Co(NH3 )6 ]Cl3 b) [Co(NH3 )5 Cl]Cl2 c) [Co(NH3 )4 Cl2 ]Cl d) [Co(NH3 )3 Cl3 ]
374. In a set of reactions, ethyl benzene yielded a product 𝐷.

a) b) c) d)

375. The oxidation number of Pt in [Pt(C2 H4 )Cl3 ] is

a) +1 b) +2 c) +3 d) +4
376. Among [Fe(H2 O)6 ] , [Fe(CN)6 ] , [Fe(Cl)6 ] species, the hybridization state of the Fe atom are,
3+ 3− 3−

respectively
a) 𝑑2 𝑠𝑝3 , 𝑑2 𝑠𝑝3 , 𝑠𝑝 3 𝑑2 b) 𝑠𝑝 3 𝑑2 , 𝑑2 𝑠𝑝3 , 𝑑 2 𝑠𝑝3 c) 𝑠𝑝3 𝑑2 , 𝑑2 𝑠𝑝3 , 𝑠𝑝3 𝑑2 d) None of these
377. Of the following complex ions, which is diamagnetic in nature?
a) [CoF6 ]3− b) [NiCl4 ]2− c) [Ni(CN)4 ]2− d) [CuCl4 ]2−
378. The IUPAC name of compound

a) 2-methoxycarbonylbenzoic acid b) Methyl-2-carboxy benzoate

c) 2-carboxy phenyl ethanoate d) 𝑜-carboxyphenyl acetate
379. Which of the following are produced from coal-tar?
a) Synthetic dyes b) Drugs c) Perfumes d) All of these
380. Chlorine is least reactive in:
a) CH3 Cl b) CH2=CHCl c) C6 H5 Cl d) C2 H5 Cl
381. Correct IUPAC name of compound
(CH3 )2 C(CH2 CH3 )CH2 CH(Cl)CH3 is
a) 5-chloro-3,3-dimethylhexane b) 3-chloro-2-ethyl-2-methylpentane
c) 2-chloro-4-ethyl-4-methylpentane d) None of the above

P a g e | 31
382.

In the above reaction ‘X’ stands for:

a) NH2 b) Cl c) SnCl2 d)
383. Which follows EAN rule?
a) Fe(CO)5 b) Ni(CO)4 c) K 4 [Fe(CN)6 ] d) All are correct
384. Which one is bidentate ligand?
a) C2 O2−
4 b) NH2 ∙ CH2 ∙ CH2 ∙ NH2 c) Both (a) and (b) d) None of these
385. The reagent used for conversion of benzene diazonium chloride to benzene is:
a) H3 PO2 + H2 O b) Na2 SnO2 + NaOH c) C2 H5 OH d) All of these
386. Which will not give the usual test for iron?
a) K 2 Fe2 (SO4 )4 ∙ 24H2 O
b) (NH4 )2 Fe(SO4 )2 ∙ 6H2 O
c) K 3 [Fe(CN)6 ]
d) Fe2 (SO4 )3
387. [Co(NH3 )5 SO4 ]Br and [Co(NH3 )5 Br]SO4 are a pair of …… isomers.
a) Ionisation b) Ligand c) Coordination d) Hydrate
388. The first organic compound prepared in the laboratory was
a) Acetic acid b) Acetylene c) Urea d) Methane
389. Aniline on heating with conc. H2 SO4 at 460 K gives:
a) Aniline sulphate
b) Benzene sulphonic acid
c) Sulphanilic acid
d) None of the above
390. Which of the following statements regarding phenols is not correct?
a) Phenols are stronger acid than water and alcohols
b) Phenols are weaker acids than carboxylic acids
c) Phenols are soluble in both aqueous NaOH and aqueous NaHCO3
d) Phenoxide ions are more stable than the corresponding phenols
391. Which would decolourise cold, 𝑎𝑞. potassium permanganate solution?
a) Benzoic acid b) Cinnamic acid c) 𝑝-toluic acid d) 𝑚-toluic acid
392. The magnetic moment of K 3 [Fe(CN)6 ] is found to be 1.7 BM. How many unpaired electron (s) is/are
present per molecule?
a) 1 b) 2 c) 3 d) 4
393. The IUPAC name of the compound

a) Bicyclo [2,5,0] nonane b) Bicyclo [5,0,2] nonane

c) Bicyclo [5,2,0] nonane d) Bicyclo [0,2,5] nonane
394. The IUPAC name of the compound

a) 2-oxocyclohexane-1-carboxylic acid b) Cyclohexane-2-oxo-1-carboxylic acid

c) 6-oxocyclohexane-1-carboxylic acid d) None of the above
395. The IUPAC name of
P a g e | 32
 is
a) Spiro [3.2.1] octane b) Bicyclo [3.2.2] octane c) Bicyclo [3.2.1] octane d) None of these
396. Which of the following deactivates benzene substitution?
a) −NH𝑅 b) −OH c) −O𝑅 d) −COO𝑅
397. Aniline, chloroform and alc. KOH on heating give:
a) Phenyl isocyanide b) Phenyl cyanide c) Chlorobenzene d) Phenol
398. In the chemical reactions,

the compounds ′′𝐴′′ and ′′𝐵′′ respectively are :

a) Nitrobenzene and chlorobenzene
b) Nitrobenzene and fluorobenzene
c) Phenol and benzene
d) Benzenediazonium chloride and fluorobenzene
399. The incorrect statement for IUPAC system of nomenclature is
a) In an organic compound, the longest carbon chain is always selected for assigning the root word
b) There is no compound with the name 3-ethyl pentane
c) Out of – NH2 and – OH groups present in an organic compound, −NH2 is treated as substituent
d) Different alkyl groups are written alphabetically while, writing the IUPAC name
400. When sodium benzene sulphonate is fused with sodium hydroxide (solid), followed by hydrolysis the
product formed is:
a) Benzene b) Sod. phenoxide c) Benzene thiophenol d) Phenol
401. The correct order of stability of conformations of cyclohexane is
a) Chair > twist boat > boat b) Twist boat > chair > boat
c) Boat > chair > twist boat d) Boat > twist boat > chair
402. Phenol with dilute HNO3 gives:
a) 𝑚𝑒𝑡𝑎 and 𝑝𝑎𝑟𝑎 nitrophenol
b) 𝑜𝑟𝑡ℎ𝑜 and 𝑝𝑎𝑟𝑎 nitrophenol
c) Trinitrophenol
d) 𝑜𝑟𝑡ℎ𝑜 and 𝑚𝑒𝑡𝑎 nitrophenol
403. The increasing order of boiling points of compounds given below is:
(I) 1,2-dihydroxy benzene
(II) 1,3-dihydroxy benzene
(III) 1,4-dihydroxy benzene
(IV) Hydroxyl benzene
a) I < II < III < IV b) I < II < IV < III c) IV < I < II < III d) IV < II < I < III
404. The pair of the compounds in which both the metals are in the higher possible oxidation state is
a) CrO2 Cl2 , MnO−4 b) [Co(CN)6 ]3− , MnO3
c) TiO3 , MnO2 d) [Fe(CN)6 ]3− , [Co(CN)6 ]3−
405. The number of ions given by K 2 [PtCl6 ] in aqueous solution is:
a) 2 b) 3 c) 4 d) Zero
406. Which of the following are functional isomers?
a) CH3 CH2 Cl and CH3 CH2 Br b) CH3 CHBr2 and CH2 Br2 ∙ CH2 Br

c) C2 H5 OC2 H5 and CH3 OC3 H7 d)

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407. Phenol is:
a) Strongly acidic b) Weakly acidic c) Strongly basic d) Weakly basic
408. The correct IUPAC name of KAl(SO4 )2 ∙ 12H2 O is:
a) Aluminium potassium sulphate-12-water
b) Potassium aluminium(III) sulphate-12-water
c) Potassium aluminate(III) sulphatehydrate
d) Aluminium(III) potassium sulphate hydrate-12
409. A complex shown below can exhibit:

a) Optical isomerism only

b) Geometrical isomerism only
c) Both optical and geometrical isomerism
d) None of the above
410. The IUPAC name of the complex [Co(NH3 )4 Cl2 ]Cl is
a) Dichloro tetraammine cobalt (III) chloride b) Tetraammine dichloro cobalt(III) chloride
c) Tetraammine dichloro cobalt (II) chloride d) Tetraammine dichloro cobalt (IV) chloride
411. The correct decreasing order of their reactivity towards hydrolysis is:
(i) C6 H5 COCl

a) (i)>(ii)>(iii)>(iv) b) (iv)>(ii)>(i)>(iii) c) (ii)>(iv)>(i)>(iii) d) (ii)>(iv)>(iii)>(i)

412. Nitrobenzene is generally used for:
a) Preparing shoe polish b) Preparing floor polish c) Preparing aniline d) All of these
413. In the coordination compound, K 4 [Ni(CN)4 ], the oxidation state of nickel is
a) -1 b) 0 c) +1 d) +2
414. Salicylic acid as compared to benzoic acid:
a) Is more acidic b) Has same acidity c) Has less acidity d) None of these
415. Which ligand is expected to be bidentate?
a) C2 O2−
4 b) CH3 C ≡ N c) Br − d) CH3 NH2
416. Which one of the following is most reactive towards aqueous NaOH?
a) C6 H5 Cl b) C6 H5 CH2 Cl c) C6 H5 Br d) BrC6 H4 Br
417. Which is not an aromatic compound?
a) Pyridine b) Naphthalene c) Xylene d) Cyclohexane
418. Which one of the following is wrongly matched?
a) [Cu(NH3 )4 ]2+ − Square planar b) [Ni(CO)4 ] − Neutral ligand
c) [Fe(CN6 )] 3−
− 3
𝑠𝑝 𝑑 2
d) [Co(en)3 ]3+ − Follows EAN rule
419. Stereoisomers have different
a) Molecular formula b) Structural formula
c) Configuration d) Molecular mass

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420. Which of the following will show optical isomerism?
a) [Cu(NH3 )4 ]2+
b) [ZnCl4 ]2−
c) [Cr(C2 O4 )3 ]3−
d) [Co(CN)6 ]3−
421. A complex of cobalt has five ammonia molecules, one nitro group and two chlorine atoms for each cobalt
atom. One mole of this compound produces three mole ions in aqueous solution which on treating with
excess of AgNO3 give two mole of AgCl. The formula of the compound is:
a) [Co(NH3 )4 NO2 Cl][(NH3 )Cl]
b) [Co(NH3 )5 Cl][ClNO2 ] c) [Co(NH3 )5 NO2 ]Cl2 d) [Co(NH3 )5 ][(NO2 )2 Cl2 ]
422. Which one group is trivalent in nature?
a) Benzo b) Benzal c) Benzyl d) All of these
423. Benzene contains double bonds but does not give addition reactions because:
a) Double bonds in benzene are strong
b) Double bonds change their position rapidly
c) Resonance lowers the energy of benzene molecule and leads to greater stabilization
d) None of the above
424. Low spin complex of 𝑑6 -cation in an octahedral field will have the following energy:
−12
a) ∆ +𝑃
5 0
−12
b) ∆ + 3𝑃
5 0
−2
c) ∆ + 2𝑃
5 0
−2
∆ +𝑃
d) 5 0
(∆0 = Crystal field splitting energy in an octahedral field, 𝑃=Electron pairing energy)
425. C7 H8 O show how many isomers?
a) 2 b) 3 c) 4 d) 5
426.

The above structural formula refers to:

a) BHC b) DNA c) DDT d) RNA
427. The compound

Have its IUPAC name as

a) Octa dec-9-enoic acid b) Oleic acid
c) Ethyl hexadic-9-enoic acid d) All of these
428. The type of isomerism present in nitropentaammine-chromium (III) chloride is :
a) Optical b) Linkage c) Ionization d) polymerization
429. Which complex compound possesses 𝑠𝑝 𝑑 hybridisation?
3 2

a) [Fe(NH3 )6 ]3+ b) [Fe(CN)6 ]4− c) [Fe(CN)6 ]3− d) [Fe(Cl)6 ]3−

430. Amongst the following carboxylic acids the strongest acid is:
a) Benzoic acid
b) 𝑜-methoxybenzoic acid
c) 𝑚-nitrobenzoic acid
d) 𝑝-nitrobenzoic acid

P a g e | 35
431. When EDTA solution is added to Mg2+ ion solution, then which of the following statements is not true?
Four coordinate sites of Mg2+ are occupied by EDTA and remaining two sites are occupied by water
a)
molecules.
b) All six coordinate sites of Mg 2+ are occupied.
c) PH of the solution is decreased.
d) Colourless [Mg − EDTA]2− chelate is formed.
432. The energy difference between chair and the boat conformation of cyclohexane is
a) 29.7 kJ b) 44 kJ c) 151 kJ d) 36 kJ
433. Compounds having the same molecular formula but different properties are called
a) Isotopes b) Isobars c) Isomers d) Isomorphs
434. CH3 OCH2 CH2 CH2 OCH2 CH3 is
a) Ethylmethylpropyl diether b) Ethylmethoxypropyl ether
c) 3-ethoxy-1-methoxy propane d) 1-ethoxy-3-methoxy propane
435. The benzene molecule contains:
a) Six 𝑠𝑝2 -hybridized carbons
b) Three 𝑠𝑝2 -hybridized carbons
c) Six 𝑠𝑝3 -hybridized carbons
d) Three 𝑠𝑝3 -hybridized carbons
436. The correct order of stability of conformations of NH2 − CH2 − CH2 − OH is
a) Gauche > eclipsed > anti b) Gauche > anti > eclipsed
c) Eclipsed > gauche > anti d) Anti > eclipsed > gauche
437. The solubility of AgCN increases by the addition of KCN because of:
a) Complex formation b) Redox change c) Salt formation d) None of these
438. Alicyclic compounds are
a) Aromatic cyclic compounds b) Aliphatic cyclic compounds
c) Both (a) and (b) d) None of the above
439. Which of the following compounds reacts slower than benzene in electrophilic bromination?
a) C6 H5 — NO2 b) C6 H5 — NH2 c) C6 H5 — OH d) C6 H6 — CH3
440. The fraction of chlorine precipitated by AgNO3 solution from [Cu(NH3 )5 Cl]Cl2 is:
a) 1/2 b) 2/3 c) 1/3 d) 1/4
441. Number of possible optical isomers in[Co(en)2 Cl2 ]+ is
a) 2 b) 3 c) 4 d) 6
442. Dimethyl glyoxime gives a red precipitate with Ni which is used for its detection. To get this precipitate
2+

readily, the best pH range is

a) < 1 b) 3 − 4 c) 9 − 11 d) 2 − 3
443. Predict the product:

a)

b)

P a g e | 36
 c)

d)

444. Replacement of Cl of chlorobenzene to give phenol requires drastic conditions but chlorine of 2, 4-
dinitrochlorobenzene is readily replaced because:
a) NO2 makes the electron rich ring at 𝑜𝑟𝑡ℎ𝑜 and 𝑝𝑎𝑟𝑎 positions
b) NO2 withdraws electrons at 𝑚𝑒𝑡𝑎 position
c) NO2 donate electrons at 𝑚𝑒𝑡𝑎-position
d) NO2 withdraws electrons at 𝑜𝑟𝑡ℎ𝑜 and 𝑝𝑎𝑟𝑎 positions
445. Salicylic acid on heating with soda lime forms:
a) Phenol b) Benzyl alcohol c) Benzene d) Benzoic acid
446. Which of the following is an organometallic compound?
a) Ti(C2 H5 )4 b) Ti(OC2 H5 )4 c) Ti(OCOCH3 )4 d) Ti(OC6 H5 )4
447. Which kind of isomerism is exhibited by octahedral Co NH3 4 Br2 Cl ?
( )
a) Geometrical and ionisation b) Geometrical and optical
c) Optical and ionisation d) Geometrical only
448. Which of the following is the strongest base?

a) b) c) d)

449. Which of the following will be aromatic?

a) b) c) d)

450. The correct symbol relating the two Kekule structure of benzene is:
a) ⟶ b) ⇌ c) ↔ d) ⇄
451. Benzaldehyde can be obtained by the hydrolysis of:
a) Benzyl chloride b) Benzal chloride c) Benzonitrile d) Benzoic acid
452. Which of the following has an optical isomer?
a) [Co(en)(NH3 )2 ]2+ b) [Co(H2 O)4 (en)]3+ c) [Co(en)2 (NH3 )2 ]3+ d) [Co(NH3 )3 Cl]+
453. Chromium carbonyl is:
a) Cr(CO)4 b) Cr(CO)5 c) Cr(CO)6 d) None of these
454. Which of the following reagents may be used to distinguish between phenol and benzoic acid?
a) Aqueous NaOH b) Tollen’s reagent c) Molisch reagent d) Neutral FeCl3
455. Which of the following complex species do not involve 𝑑2 𝑠𝑝3-hybridization?
a) [CoF6 ]3− b) [Co(NH3 )6 ]3+ c) [Fe(CN)6 ]3− d) [Cr(NH3 )6 ]3+
456. Which one of the following shows maximum value of paramagnetic behaviour?

P a g e | 37
 a) [Sc(CN)6 ]3− b) [Co(CN)6 ]3− c) [Ni(CN)4 ]2− d) [Cr(CN)6 ]3−
457. The IUPAC name of
HOOC − CH2 − CH2 − CH2 − CH − CH2 − COOH
|
CH2 COOH
is
a) 3-(carboxymethyl) heptane-1,7-dioic acid
b) 5-(carboxymethyl) heptane-1,7-dioic acid
c) 2-(carboxymethyl) pentane dicarboxylic acid
d) 4-(carboxymethyl) pentane dicarboxylic acid
458. Which of the following species will be diamagnetic?
a) [Fe(CN)6 ]4− b) [FeF6 ]3− c) [Co(C2 O4 )3 ]3− d) [CoF6 ]3−
459. Which one of the following is an outer orbital complex and exhibits paramagnetic behaviour?
a) [Cr(NH3 )6 ]3+ b) [Co(NH3 )6 ]3+ c) [Ni(NH3 )6 ]2+ d) [Zn(NH3 )6 ]2+
460. Moth balls contain:
a) Camphor b) Benzoic acid c) Naphthalene d) Cinnamic acid
461. The number of unidentate ligands in the complex ion is called
a) Oxidation number b) Primary valency
c) Coordination number d) EAN
462. According to Hückel rule, the number of π-electrons in anthracene is:
a) 12 b) 14 c) 10 d) 20
463. In ethane and cyclohexane which one of the following pairs of conformations are more stable?
a) Eclipsed and chair conformations b) Staggered and chair conformations
c) Staggered and boat conformations d) Eclipsed and boat conformations
464. Among the following which is not π-bonded organometallic compound?
a) K[PtCl3 (2 − C2 H4 )] b) Fe(5 − C5 H5 )2 c) Cr(6 − C6 H6 )2 d) (CH3 )4 Sn
465. 𝑜, 𝑝-directing groups are generally:
a) Activating groups b) Deactivating groups c) Neutral groups d) None of these
466. Aryl halides are less reactive towards nucleophilic substitution reaction as compared to alkyl due halides
to:
a) The formation of less stable carbonium ion
b) Resonance stabilization
c) Longer carbon-halogen bond
d) The inductive effect
467. Which would be least reactive towards bromine?
a) Nitrobenze b) Anisole c) Phenol d) Chlorobenzene
468. Which has a smell of oil of winter green?
a) Benzaldehyde b) Benzoic acid c) Ethyl salicylate d) Methyl salicylate
469. The coordination number of Pt in [Pt(NH3 )4 Cl2 ] ion is
2+

a) 2 b) 4 c) 6 d) 8
470. C6 H5 Cl on treating with NaOH at 300 ͦC gives phenol. However the yield is poor because of side reaction
producing:
a) C6 H5 Na b) C6 H5 OCH3 c) C6 H5 OC6 H5 d) None of these
471. In Cr(NH3 )4 Cl2 ]Cl the ligands are:
a) NH3 only b) Cl− only c) Both NH3 and Cl− d) Cr, NH3 , Cl−
472. Which statement is not correct regarding aniline?
a) It is less basic than ethyl amine
b) It can be steam distilled
c) It reacts with sodium to give hydrogen
d) It is soluble in water

P a g e | 38
473. Among the following, identify the species with an atom of +6 oxidation state:
a) [MnO4 ]− b) [Cr(CN)6 ]3− c) [NiF6 ]2− d) CrO2 Cl2
474. Which of the following alkanes contain primary, secondary, tertiary and quaternary carbon atom together?
a) (CH3 )3 CH b) (C2 H5 )3 CH c) (CH3 )3 CCH2 CH(CH3 )2 d) (CH3 )4 C
475. The hardness of water is estimated by:
a) Conductivity method b) EDTA method c) Titrimetric method d) Distillation method
476. I2 is stirred in between two liquids, C6 H6 and water. It:
a) Dissolves more in C6 H6
b) Dissolves more in H2 O
c) Dissolve equally
d) Dissolves in neither C6 H6 nor water
477. The number of tertiary C-atoms in 2,2,4,4-tetra methyl pentane is
a) 1 b) 2 c) 3 d) 4
478. Hydrogenation of benzoyl chloride in the presence of Pd on BaSO4 gives:
a) Benzyl alcohol b) Benzaldehyde c) Benzoic acid d) Phenol
479. The Clemmensen reduction of benzaldehyde gives:
a) C6 H5 NH2 b) C6 H5 OH c) C6 H5 CH3 d) C6 H5 COOH
480. Which of the following ligand has lowest Δ𝑜 value?
a) CN− b) CO c) F − d) NH3
481. Which one of the following has an optical isomer?
(en=ethylenediamine)
a) [Zn(en)(NH3 )2 ]2+ b) [Co(en)3 ]3+ c) [CO(H2 O)4 (en)]3+ d) [Zn(en)2 ]2+
482. Trichloroacetaldehyde, CCl3 CHO reacts with chlorobenzene in presence of sulphuric acid and produces:

a)

b)

c)

d)

483. Which fraction of coal-tar is rich in arene?

a) Light oil b) Heavy oil c) Green oil d) Middle oil
484. The coordination number and oxidation number of X in the following compound [𝑋 (SO4 )(NH3 )5 ]Cl will be
a) 10 and 3 b) 2 and 6 c) 6 and 3 d) 6 and 4
485. Benzyl chloride is formed by treating toluene with Cl2 in:
a) Presence of light
b) Absence of light
c) Treating benzene with anhy. AlCl3

P a g e | 39
 d) Treating benzene with As2 S3
486. Which complex cannot ionize in solution?
a) [CoCl3 (NH3 )3 ] b) K 4 (Fe(CN)6 ] c) K 2 [Pt(F6 )] d) [Pt(NH3 )6 ]Cl4
487. [Ni CN 4 ] , [MnBr4 ] and [CoF6 ] , geometry, hybridisation and magnetic moment of the ions
( ) 2− 2− 3−

respectively, are
Tetrahedral, square planar, octahedral :
a) 3
𝑠𝑝 , 𝑑𝑠𝑝2 , 𝑠𝑝3 𝑑2 : 5.9, 0, 4.9
Tetrahedral, square planar, octahedral :
b)
𝑑𝑠𝑝 2 , 𝑠𝑝3 , 𝑠𝑝3 𝑑2 : 0, 5.9, 4.9
Square planar, tetrahedral, octahedral :
c)
𝑑𝑠𝑝 2 , 𝑠𝑝3 , 𝑑2 𝑠𝑝3: 5.9,4.9,0
Square planar, tetrahedral, octahedral :
d)
𝑑𝑠𝑝 2 , 𝑠𝑝3 , 𝑠𝑝3 𝑑2 : 0, 5.9, 4.9
488. Ozonolysis of benzene gives:
a) 1 molecule of glyoxal
b) 2 molecules of glyoxal
c) 3 molecules of glyoxal
d) None of these
489. In benzene, C—C bond length is 1.39 Å; the C—H bond length is:
a) 1.39 b) 1.08 c) 1.54 d) 1.46
490. The IUPAC name of following compound is

a) N,N-dimethyl, 3-methyl pentan-3-amine b) 3-N,N-dimethyl, 3-methyl pentanamine

c) 3-methyl-3-N, N-dimethyl pentane d) 3-methyl-3-N, N-dimethyl butane
491. Which of the following may be used as food preservative?
a) Benzene
b) Ethylene
c) Sodium benzoate
d) Sodium metaaluminate
492. Which compound is formed when sodium phenoxide is heated with ethyl iodide?
a) Phenetole b) Ethyl phenyl alcohol c) Phenol d) None of these
493. In metal carbonyl (organometallic)complexes, the 𝑀— C bond is
a) Ionic b) Covalent with ionic character
c) Covalent d) Coordinate covalent
494. Octahedral complex

a) cis b) trans c) mer d) fac

495. The correct order of magnetic moments (spin only values in BM) among the following is
(Atomic no. Mn=25, Fe=26, Co=27)
a) [MnCl4 ]2− > [CoCl4 ]2− > [Fe(CN)6 ]4− b) [MnCl4 ]2− > [Fe(CN)6 ]4− > [CoCl4 ]2−
c) [Fe(CN)6 ]4− > [MnCl4 ]2− > [CoCl4 ]2− d) [Fe(CN)6 ]4− > [CoCl4 ]2− > [MnCl4 ]2−
496. Aniline and methyl amine can be differentiated by:
a) Diazotisation followed by coupling with phenol
b) Reaction with chloroform and aqueous solution of KOH
c) Reaction with HNO2

P a g e | 40
 d) None of the above
497. The functional group present in cresols is:
a) Alcoholic (— OH) b) Aldehydic (— CHO) c) Phenolic (— OH) d) Carboxylic (— COOH)
498. In the reaction;

the structure of the product T is:

a)

b)

c)

d)

499. Which one of the following compounds is most acidic?

a) b) c) d)

500. The most unstable configuration of cyclohexane is

a) Boat b) Chair c) Twist boat d) Half chair
501. In which compound synergic effect is present?
a) [Ni(CO)4 ] b) [NiCl4 ]2− c) [CuCl4 ]2− d) [Mn(H2 O)6 ]2+
502. The IUPAC name of the compound

is
a) 4-amino-2-ethyl pent-1-ene b) 2-ethyl pentan-4-amine
c) Amino-4-pentene d) 4-ethyl pent-4-en-2-amine
503. Aqua regia reacts with Pt to yield:
a) Pt(NO3 )4 b) H2 [PtCl6 ] c) PtCl4 d) PtCl2
504. K 3 [Al(C2 O4 )3 ] is called:
a) Potassium aluminooxalate
b) Potassium alumino(III) oxalate
c) Potassium trioxalatoaluminate
d) Potassium trioxalatoaluminate(III)

P a g e | 41
505. The IUPAC name of

a) 6-oxo-1,2,2-tri methyl bicycle [2.2.1] heptane b) 1,7,7-trimethyl bicyclo [2.2.1] heptan-2-one

c) 1,5,5-trimethyl bicyclo [2.1.1] hexane-2-one d) 1,7,7-trimethyl bicyclo [2.1.2] heptan-2-one
506. Nitration of toluene takes place at:
a) 𝑜𝑟𝑡ℎ𝑜 position
b) 𝑚𝑒𝑡𝑎 position
c) 𝑝𝑎𝑟𝑎 position
d) Both 𝑜𝑟𝑡ℎ𝑜 and 𝑝𝑎𝑟𝑎 position
507. Estimation of calcium and magnesium is done by
a) EDTA b) Oxalate c) Phosphate d) None of these
508. How many enantiomer pairs are obtained by monochlorination of 2, 3-dimethyl butane?
a) Four b) Two c) Three d) One
509. Common reactions of benzene and its derivatives are:
a) Electrophilic addition reactions
b) Electrophilic substitution reactions
c) Nucleophilic substitution reactions
d) Nucleophilic addition reactions
510. The IUPAC name of the compound
is
a) 1, 3, 5-triheptene b) 2, 4, 6-triheptene
c) 2, 4, 6-heptatriene d) Hepta-1, 3, 5-triene
511. Name of compound

a) 1, 2, 3-triformylpentane b) Propane-1, 2, 3-tricarbaldehyde

c) 3-formylpentane-1, 5-dial d) Propane-1, 2, 3-trial
512. The attacking species in aromatic sulphonation is:
a) SO3 b) H3 SO+
4 c) HSO4 d) SO+2
513. Which one of the following compound does not react with bromine?
a) Ethyl amine b) Propene c) Phenol d) Chloroform
514. The magnetic moment (spin only) of [Ni Cl4 ] is
2−

a) 1.82 BM b) 5.46 BM c) 2.82 BM d) 1.41 BM

515.

a) At position-2 b) At position-3 c) At position-4 d) At positions-2 and 4

516. Ionization of K[Ag(CN)2 ] will give:
a) K + and [Ag(CN)2 ]− ion
b) KCN and AgCN
c) K + , Ag + , CN−
d) None of the above
517. The coordination number and oxidation state of Cr in K 3 [Cr(C2 O4 )3 ] are respectively
a) +6 and +3 b) 3 and 0 c) 4 and +2 d) 3 and +3
P a g e | 42
518. A complex of platinum, ammonia and chlorine produces four ions per molecule in the solution. The
structure consistent with the observation is:
a) [Pt(NH3 )4 ]Cl4 b) [Pt(NH3 )2 Cl4 ] c) [Pt(NH3 )5 Cl]Cl3 d) [Pt(NH3 )4 Cl2 ]Cl2
519. The type of magnetism exhibited by [Mn(H2 O] ] ion is
2+

a) Paramagnetism b) Diamagnetism c) Both (a) and (b) d) None of these

520. According to effective atomic number rule the central metal acquires:
a) Inert gas configuration
b) Duplet
c) Octet
d) Quartet
521. K 3 CoF6 is high spin complex. What is the hybrid state of Co-atom in this complex?
a) 𝑠𝑝3 𝑑 b) 𝑠𝑝 3 𝑑2 c) 𝑑 2 𝑠𝑝3 d) 𝑑𝑠𝑝2
522. The correct structure of ethylenediaminetetraacetic acid (EDTA) is

a) b)

c) d)

523. [Co(NH3 )5 Br]SO4 and [Co(NH3 )5 SO4 ]Br are examples of which type of isomerism?
a) Linkage b) Optical c) Geometrical d) Ionisation
524. The coordination number of a central metal atom in a complex is determined by
a) The number of ligands around a metal ion bonded by σ − bonds
b) The number of ligands around a metal ion bonded by π −bonds
c) The number of ligands around a metal ion bonded by σ –and π − bonds both
d) The number of only anionic ligands bonded to the metal ion
525. Action of benzoic acid with hydrazoic acid in presence of N3 H gives:
a) Aniline b) Benzamide c) Phenyl cyanide d) All of these
526. Which ion shows usually the coordination number 6?
a) Cr 3+ b) Fe3+ c) Fe2+ d) All of these
527. Which of the following represents hexadentate ligand?
a) 2, 2-bipyridyl b) DMG c) Ethylenediamine d) None of these
528. Nitrobenzene can be prepared from benzene by using a mixture of conc. HNO3 and conc. H2 SO4 .In the
mixture, nitric acid acts as a/an:
a) Catalyst b) Reducing agent c) Acid d) Base
529. The value of the ‘spin only’ magnetic moment for one of the following configurations is 2.84 BM. The
correct one is
a) 𝑑5 (in strong ligand field) b) 𝑑 3 (in weak as well as strong ligand fields)
c) 𝑑4 (in weak ligand field) d) 𝑑 4 (in strong ligand field)
530. The IUPAC name of the compound

a) 6-(3-oxobutyl) cyclohexan-1-one b) 6-(2-oxobutyl) cyclohexan-1-one

c) 2-(3-oxobutyl) cyclohexan-1-one d) 2-(2-oxobutyl) cyclohexan-1-one
531. Hybridisation, shape and magnetic moment of [Ni(CN)4 ]2− ion

P a g e | 43
 a) 𝑑𝑠𝑝 2, square planar, zero b) 𝑑𝑠𝑝2, square planar, 1.73
c) 𝑠𝑝2 𝑑2 , octahedral, zero d) 𝑑 2 𝑠𝑝3 , octahedral, 1.73
532. Choose the IUPAC name of
a) Dicyclobutane b) Bicyclo [2.2.0] hexane
c) Bicyclo [2.2.1] hexane d) None of these
533. Which of the following is a heterocyclic compound?
a) Phenanthrene b) Thiophene c) Phenol d) Aniline
534. [Sc(H2 O 6 ] ion is
) 3+

a) Colourless and diamagnetic b) Coloured and octahedral

c) Colourless and paramagnetic d) Coloured and paramagnetic
535. Benzene reacts with CH3 Cl in the presence of anhydrous AlCl3 to form:
a) Xylene b) Toluene c) Chlorobenzene d) Benzylchloride
536. The magnetic moment of [Co(NH3 )6 ]Cl3 is
a) 1.73 b) 2.83 c) 6.6 d) Zero
537. The correct order of reactivity towards electrophilic substitution is:
a) Phenol >Benzene>Chlorobenzene>Benzoic acid
b) Benzoic acid>Chlorobenzene>Benzene>Phenol
c) Phenol >Chlorobenzene>Benzene>Benzoic acid
d) Benzoic acid>Phenol>Benzene>Chlorobenzene
538. The product formed by the reaction of C6 H5 CN and CH2 N2 is:
d) None of these
a) b) c)

539. Increasing order of expected enol content

a) CH3 COCH2 CHO > CH3 COCH3 > CH3 CHO > CH3 COCH2 COCH3
b) CH3 COCH2 COCH3 > CH3 COCH2 CHO > CH3 COCH3 > CH3 CHO
c) CH3 CHO > CH3 COCH3 > CH3 COCH2 CHO > CH3 COCH2 COCH3
d) CH3 COCH3 > CH3 COCH2 COCH3 > CH3 CHO > CH3 COCH2 CHO
540. Out of the following the metal which forms polynuclear carbonyl is:
a) Na b) Mg c) Mn d) All of these
541. Picric acid and benzoic acid can be distinguished by:
a) Aqueous NaHCO3 b) Aqueous NaOH c) Aqueous FeCl3 d) Aqueous Na2 CO3
542. The compound having the lowest oxidation state of iron is
a) K 4 Fe(CN)6 b) K 2 FeO4 c) Fe2 O3 d) Fe(CO)5
543. The name of [Pt(NH3 )4 Cl2 ] , [PtCl4 ] is
2+ 2−

a) Tetramminedichloroplatinum(IV) tetrachloro platinate(II)

b) Dichloroplatinum (IV) tetrachloroplatinate
c) Tetrachloroplatinum (II) tetrammineplatinate
d) Tetrachloroplatinum (II) dichlorotetraammine platinate
544. 𝑚-dihydroxybenzene is also called:
a) Catechol b) Resorcinol c) Quinol d) Pyrogallol
545. The ion which exhibits green colour
a) Cu2+ b) Mn2+ c) Co2+ d) Ni2+
546. 𝑋 → 2 Benzotrichloride →
Cl Hydrolysis
𝑌
𝑋 and 𝑌 respectively are:
a) Benzene, benzaldehyde
b) Toluene, benzaldehyde
c) Toluene, benzoic acid
d) Benzene, benzoic acid

P a g e | 44
547. Geometrical isomerism is found in coordination compounds having coordination number:
a) 2 b) 3 c) 4 (tetrahedral) d) 6
548. Which one of the following complexes is not expected to exhibit isomerism?
a) [Ni(NH3 )4 (H2 O)2 ]2+ b) [Pt(NH3 )2 Cl2 ] c) [Ni(NH3 )2 Cl2 ] d) [Ni(en)3 ]2+
549. The correct acidity order of the following is:

a) (III) > (IV) > (II) > (I)

b) (IV) > (III) > (I) > (II)
c) (III) > (II) > (I) > (IV)
d) (II) > (III) > (IV) > (I)
550. Identify ‘𝑍’ in the reaction;

a)

b)

c)

d)

551. Pure aniline is a:

a) Brown coloured liquid
b) Colourless liquid
c) Brown coloured solid
d) Colourless solid
552. Aromatic compounds undergo most easily:
a) Nucleophilic substitution
b) Electrophilic substitution
c) Nucleophilic addition
d) Electrophilic addition

P a g e | 45
553. The colour of CoCl3 ∙ 5NH3 ∙ H2 O is:
a) Orange yellow b) Orange c) Green d) Pink
554. The value of 𝑥 on the [Ni(CN)4 ]𝑥 is:
a) +2 b) −2 c) Zero d) +4
555. Complexes with halide ligands are generally:
a) High spin complexes b) Low spin complexes c) Both (a) and (b) d) None of these
556. The hybridization involved in [CoF6 ]3− is:
a) 𝑑2 𝑠𝑝3 b) 𝑑3 𝑠𝑝2 c) 𝑑𝑠𝑝3 d) 𝑠𝑝3 𝑑2
557.

Will have the name

a) N-ethyl-N-methylethanamine b) N,N-diethylmethanamine
c) N,N-diethylethanamide d) None of the above
558. The oxidation state of Fe in the brown ring complex [Fe(H2 O)5 NO]SO4 is
a) +3 b) 0 c) +2 d) +1
559. The metal ion in complex A has EAN identical to the atomic number of krypton . A is
(At. no. of Cr=24, Fe=26, Pd=46)
a) [Pd(NH3 )6 ]Cl4 b) [Cr(NH3 )5 Cl]SO4 c) Na4 [Fe(CN)6 ] d) K 3 [Fe(CN)6 ]
560. Which one of the following is expected to exhibit optical isomerism [en =ethylenediamine]?
a) 𝑡𝑟𝑎𝑛𝑠 − [Co(en)2 Cl2 ] b) 𝑐𝑖𝑠 − [pt(NH3 )2 Cl2 ]
c) 𝑐𝑖𝑠 − [Co9en)2 Cl2 ] d) 𝑇𝑟𝑎𝑛𝑠 − [pt(NH3 )2 Cl2
561. What is the magnetic moment of K 3 [FeF6 ]?
a) 5.91 BM b) 4.89 BM c) 3.87 BM d) 6.92 BM
562. Identify ‘𝑌’ in the change;

a) b) c) d)

563. Among the following statements on the nitration of aromatic compounds, the false one is:
a) The rate of nitration of benzene is almost the same as that of hexadeuterobenzene
b) The rate of nitration of toluene is greater than that of benzene
c) The rate of nitration of benzene is greater than that of hexadeuterobenzene
d) Nitration is an electrophilic substitution reaction
564. The bond length of C—O bond in carbon monoxide is 1.128Å. The C— O bond in Fe(CO)5 is:
a) 1.15 Å b) 1.128 Å c) 1.72 Å d) 1.118 Å
565. Which one is not correct for homologous series?
a) All members are represented by same general formula
b) All members have same chemical properties
c) All members have same physical properties
d) All members have same functional group
566.

is named in IUPAC as
a) 2, 3-dimethyl bicyclo [2.2.1] hept-5-ene b) 1, 2-dimethyl bicyclo [2.2.1] hept-4-ene
c) 5, 6-dimethyl bicyclo [2.2.1] hept-2-ene d) 4, 5-dimethyl bicyclo [2.2.1] hept-1-ene
567. Ferric ion forms a prussian blue coloured solution due to the formation of:

P a g e | 46
 a) K 4 [Fe(CN)6 ] b) Fe(CNS)3 c) Fe4 [Fe(CN)6 ]3 d) K 3 [Fe(CN)6 ]
568. What is the magnetic moment of [FeF6 ] ? 3−

a) 5.92 b) 5.49 c) 2.34 d) 4

569. Which of the following can exhibit geometrical isomerism?
a) [MnBr4 ]2− b) [Pt(NH3 )3 Cl]+ c) [PtCl2 . P(C2 H5 )3 ]2 d) [Fe(H2 O)5 NO]2+
570. A compound contains 2 dissimilar asymmetric C-atoms. The number of optical isomers are
a) 2 b) 3 c) 4 d) 5
571. Coordination number of Ni in [Ni(C2 O4 3 ] is:
) 4−

a) 3 b) 6 c) 4 d) 5
572. Which compound exhibits optical isomerism?
a) Pentaamminenitrocobalt (III) iodide
b) Diamminedichloroplatinum (II)
c) 𝑇𝑟𝑎𝑛𝑠-dicyano-bis-(ethylenediamine) chromium (III) chloride
d) Tris-(ethylenediamine)cobalt (III) bromide
573. Ruthenium carbonyl is:
a) Ru(CO)4 b) Ru(CO)5 c) Ru(CO)8 d) Ru(CO)6
574. Oxidation state of nitrogen is incorrectly given for
Compound Oxidation state
a) [Co(NH3 )5 Cl]Cl2 0 b) NH2 OH −1
c) (N2 H5 )2 SO4 +2 d) Mg 3 N2 −3
575. Which of the following can participate in linkage isomerism?
a) NH3 b) H2 O c) H2 NCH2 CH2 NH2 d) NO− 2
576. 𝑂𝑟𝑡ℎ𝑜-nitrophenol is less soluble in water than 𝑝-and 𝑚-nitrophenols because:
a) 𝑜-nitrophenol shows intramolecular H-bonding
b) 𝑜-nitrophenol shows intermolecular H-bonding
c) Melting point of 𝑜-nitrophenol is lower than those of 𝑚-and 𝑝-isomers
d) 𝑜-nitrophenol is more volatile in steam than those of 𝑚-and 𝑝-isomers
577. Among the following most basic compound is:
a) Benzyl amine b) Aniline c) Acetanilide d) 𝑝-nitro aniline
578. The EAN of platinum in potassium hexachloroplatinate (IV) is:
a) 46 b) 86 c) 36 d) 84
579. The number of ions formed when copper ammonium sulphate is dissolved in water is:
a) 1 b) 2 c) 4 d) Zero
580. Which of the following cannot show linkage isomerism?
a) NO− 2 b) NH3 c) CN− d) SCN−
581. Xylenes on oxidation with acidic KMnO4 gives:
a) Phthalic acid b) Isophthalic acid c) Terephthalic acid d) All of these
582. The ratio of σ-and π-bonds in benzene is:
a) 2 b) 4 c) 6 d) 8
583. The order of decreasing reactivity towards 𝑆𝐸 reaction for the given compound is:
(i)C6 H6
(ii)C6 H5 CH3
(iii)C6 H5 Cl
(iv)C6 H5 OH
a) (ii)>(iv)>(i)>(iii) b) (iv)>(iii)>(ii)>(i) c) (iv)>(ii)>(i)>(iii) d) (i)>(ii)>(iii)>(iv)
584. Which of the following compounds is not optically active?

a) b) c) d)

P a g e | 47
585. The number of geometrical isomers of [Co(NH3 )3 (NO2 )3 ] are:
a) Zero b) 2 c) 3 d) 4
586. Phenol is less acidic than:
a) Water b) 𝑝-methoxyphenol c) 𝑝-nitrophenol d) Ethanol
587. In the reaction,

s
a) C6 H5 OH b) C6 H6 c) C6 H5 COONa d) C6 H5 ONa
588. Incorrect statement is
a) Ethane can have an infinite number of conformations
b) Cyclopropane molecule has considerable angle strain
c) Eclipsed form of ethane is less stable then staggered conformation
d) Staggered conformation possess maximum energy
589. The complex [Co(NH3 )5 Br]SO4 will give white ppt. with:
a) PbCl2 b) AgNO3 c) KI d) None of these
590. Which of the following complexes exhibits the highest paramagnetic behaviour?
a) [Fe(en)(bpy)(NH3 )2 ]2+
b) [Co(OX)2 (OH)2 ]−
c) [Ti(NH3 )6 ]3+
[V(gly)2 (OH)2 (NH3 )2 ]+
d) Where, gly = glycine, en = ethylenediamine and bpy = bipyridylmoities
(At. No. Ti=22, V=23, Fe=26, Co=27)
591. The coordination number in a/an ……… complex may increase to 8.
a) Cobalt b) Osmium c) Nickel d) Iron
592. Compound used for covering wounds caused by bite of mad dog is:
a) Benzoic acid b) Aniline c) Phenol d) Salicylic acid
593. Cinnamic acid on decarboxylation gives:
a) Benzene b) Toluene c) Styrene d) Benzaldehyde
594. In which of the following pairs both the complex show optical isomerism?
a) 𝐶𝑖𝑠-[Cr(C2 O4 )2 Cl2 ]3− ; 𝑐𝑖𝑠-[Co(NH3 )4 Cl2 ] b) [PtCl(dien)]Cl, [NiCl2 Br2 ]2−
c) [Co(NO3 )3 (NH3 )3 ], 𝑐𝑖𝑠-[Pt(en)2 Cl2 ] d) [Co(en)3 ]Cl3 , 𝑐𝑖𝑠-[Co(en)2 Cl2 ]Cl
595. The name of the ring structure complex compound formed between metal ion and polydentate ligand is
a) Simple complex b) Chelate complex c) Polynuclear complex d) None of the above
596. IUPAC name of
Cl2 CH − CH − CH − CCl3 is
| |
C2 H 5 C2 H 5
a) 1,1,1,4,4-pentachloro-2,3-diethyl-butane
b) 3-(dichloromethyl)-4-(trichloromethyl)-hexane
c) 3-(trichloromethyl)-4-(dichloromethyl)-hexane
d) 1,1,4,4,4-pentachloro-2,3-diethyl butane
597. Which statement is wrong with regard to acetaldehyde and benzaldehyde?
a) Both react with hydroxylamine to form oximes
b) Both react with HCN to form cyanohydrin
c) Both react with NaOH to form polymers
d) Both react with hydrazine to form hydrazones
598. The coordination number of Cu in complex [Cu(H2 O)4 ]2+ is
a) 4 b) 3 c) 2 d) 1
599. Which reaction sequence would be best to prepare 3-chloroaniline from benzene?
a) Chlorination, nitration, reduction
b) Nitration, chlorination, reduction
P a g e | 48
 c) Nitration, reduction, chlorination
d) Nitration, reduction, acetylation, chlorination, hydrolysis
600. The complexes (Co(NH3 )6 )][Cr(C2 O4 )3 ] and [Cr(NH3 )6 ][Co(C2 O4 )3 ]
a) Geometrical isomerism b) Ionization energy
c) Coordination isomerism d) Linkage isomerism
601. The reaction,
B2 /Fe
C6 H5 NHCOCH3 → BrC6 H4 NHCOCH3
is an example of:
a) Substitution reaction
b) Addition reaction
c) Condensation reaction
d) Elimination reaction
602. Given the molecular formula of the hexa coordinated complexes is
(A) CoCl3 .6NH3
(B) CoCl3 .5NH3
(C) CoCl3 .4NH3
If the number of coordinated NH3 molecules in A, B and C respectively are 6, 5 and 4 the primary valency
in (A),(B) and (C) are
a) 6, 5, 4 b) 3, 2, 1 c) 0, 1, 2 d) 3, 3, 3
603. C6 H14 has two tertiary carbons. The IUPAC name is
a) 𝑛-hexane b) 2-methylpentane c) 3-methylpentane d) 2,3-dimethylbutane
604. The compound [Co(NO2 )(NH3 )5 ]Cl2 and [Co(ONO)(NH3 )5 ]Cl2 are examples of:
a) Geometrical isomers b) Linkage isomers c) Ligand isomers d) Ionization isomers
605. Which is not a π-bonded complex?
a) Zeise salt b) Ferrocene c) Dibenzene chromium d) Tetraethyl lead
606. When phenol is treated with PCl5 , the yield of chlorobenzene is generally poor because of the formation of:
a) Benzoyl chloride b) 𝑝-chlorophenol c) 𝑜-chlorophenol d) Tertiary phosphate
607. Which will show tautomerism?

a) b)

c) d)

608. The IUPAC name of compound

a) N-phenylaminoethanone b) N-phenylethanamide
c) N-phenylmethanamide d) N-phenylaminomethane
609. Which one of the following is most reactive towards electrophilic reagent?

P a g e | 49
 a) b) c) d)

610. Which of the following shows 𝑑𝑠𝑝2 hybridisation?

a) NiCl2−
4 b) SCl4 c) NH4+ d) PtCl2−
4
611. Which one of the following is not an explosive?
a) Trinitroglycerine b) o-aminotoluene c) Dynamite d) TNT
612. Spin only magnetic moment of the compound Hg[Co SCN 4 ]is
( )
a) √3 b) √15 c) √24 d) √8
613. When phenol is treated with NH3 and ZnCl2 , it changes to:
a) Aniline b) Salicylic acid c) Cyclohexanol d) None of these
614. In which complex is the transition metal in zero oxidation state?
a) [Co(NH3 )6 ]Cl2 b) [Fe(H2 O)6 SO4 ] c) [Ni(CO)4 ] d) [Fe(H2 O)3 ](OH)2
615. The species having tetrahedral shape is
a) [NiCl4 ]2− b) [Ni(CN)4 ]2− c) [PdCl4 ]2− d) [Pd(CN)4 ]2−
616. An imperfect complex of a complex compound is 100% ionized; the compound is called:
a) Double salt b) Complex salt c) Acid salt d) Normal salt
617. For which transition metal ions are low spin complexes impossible?
a) Zn2+ b) Zr 2+ c) Ag + d) All are correct
618. (A) K 4 [Fe(CN)6 ]
(B)K 3 [Cr(CN)6 ]
(C)K 3 [Co(CN)6 ]
(D)K 2 [Ni(CN)6 ]
Select the complexes which are diamagnetic.
a) (A), (B) and (C) b) (B), (C) and (D) c) (A), (C) and (D) d) (A), (B) and (D)
619. Wilkinson’s catalyst, (Ph3 P)3 RhCl is used for
a) Hydrogenation of oils b) Hydrogenation of alkynes
c) Hydrogenation of alkenes d) Polymerization of alkenes
620. Among the following compounds, the most acidic is:
a) 𝑝-nitrophenol
b) 𝑝-hydroxybenzoic acid
c) 𝑜-hydroxybenzoic acid
d) 𝑝-toluic acid
621. An aromatic primary amine with cold nitrous acid leads to the formation of:
a) Alcohol b) Nitrite c) Diazonium salt d) Benzene
622. Chlorobenzene gives DDT when it reacts with:
a) Phenol b) Naphthalene c) Chloral d) Acetaldehyde
623. Under suitable conditions C6 H5 CH2 OH 𝐴 , C6 H5 OH(𝐵) and C6 H5 COOH(𝐶) can act as acids. The increasing
( )
order of their acidic strengths is:
a) 𝐴 < 𝐵 < 𝐶 b) 𝐴 < 𝐶 < 𝐵 c) 𝐵 < 𝐴 < 𝐶 d) 𝐶 < 𝐵 < 𝐴
624. Which is considered to be an anticancer species?

a) b) c) d)

625. The compound required for the formation of thermosetting polymer with methanal is:
a) Phenol b) Benzene c) Benzaldehyde d) All of these
626. Which one of the following has highest number of isomers?

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 a) [Co(NH3 )5 Cl]2+ b) [Co(en)2 Cl2 ]+ c) [Ru(NH3 )4 Cl− ] d) [In(PP3 )2 H(CO)]2+
627. Which group is 𝑜- and 𝑝-directing?
a) —NO2 b) —SO3 H c) —COOH d) —NHCOCH3
628. When benzyl chloride is boiled with aqueous solution of lead nitrate in current of carbon dioxide, the main
product is:
a) Benzoic acid b) Benzyl alcohol c) Benzaldehyde d) Nitrobenzene
629. Ligands in complex compounds
a) Donates electron pair b) Accept electron pair
c) Neither accept electron pair nor donate d) All of the above
630. Aniline is separated by:
a) Fractional crystallisation
b) Fractional distillation
c) Steam distillation
d) Vacuum distillation
631. In which of the following octahedral complexes of Co (at. No. 27), will be magnitude of ∆0 be the highest?
a) [Co(CN)6 ]3− b) [Co(C2 O4 )3 ]3− c) [Co(H2 O)6 ]3+ d) [Co(NH3 )6 ]3+
632. The IUPAC name of K 2 [PtCl6 ] is
a) Hexachloroplatinate potassium b) Potassium hexachloroplatinate (IV)
c) Potassium hexachloroplatinate d) Potassium hexachloroplatinum(IV)
633. Aqueous solution of nickel sulphate on treating with pyridine and then adding a solution of sodium nitrite
gives dark blue crystals of:
a) [Ni(py)4 ]SO4 b) [Ni(py)2 (NO2 )2 ] c) [Ni(py)4 (NO2 )2 ] d) [Ni(py)3 (NO2 )]2 SO4
634. Benzyl alcohol is obtained from benzaldehyde by:
a) Fittig’s reaction b) Cannizzaro’s reaction c) Kolbe’s reaction d) Wurtz’s reaction
635. The structure of the compound that gives a tribromo derivative on treatment with bromine water is:

a) b) c) d)

636. The coordination number and the oxidation state of the element ‘E’ in the complex [E(en)2 (C2 O4 )]NO2
(where (en) is ethylene diamine) are, respectively :
a) 6 and 3 b) 6 and 2 c) 4 and 2 d) 4 and 3
637. Benzaldehyde reacts with PCl5 to give:
a) Benzyl chloride b) Benzo trichloride c) Benzal chloride d) Chlorobenzene
638. Which one of the following complex ions has geometrical isomers?
a) [Co(en)3 ]3+ b) [Ni(NH3 )5 Br]+ c) [Co(NH3 )2 (en)2 ]3+ d) [Cr(NH3 )4 (en)]3+
639. The strongest acid among the following aromatic compounds is:
a) 𝑂𝑟𝑡ℎ𝑜-nitrophenol b) 𝑝𝑎𝑟𝑎-chlorophenol c) 𝑝𝑎𝑟𝑎-nitrophenol d) 𝑚𝑒𝑡𝑎-nitrophenol
640. The isomers observed in alkanes is
a) Metamerism b) Chain isomerism
c) Position isomerism d) Geometrical isomerism
641. The two compounds pentaamminesulphatocobalt (III) bromide and pentaamminesulphatocobalt(III)
chloride represent:
a) Linkage isomerism
b) Ionization isomerism
c) Coordination isomerism
d) No isomerism

P a g e | 51
642. Both [Ni(CO)4 ] and [Ni(CN)4 ]2− are diamagnetic. The hybridisation of nickel in the compounds
respectively are :
a) 𝑠𝑝3 , 𝑠𝑝3 b) 𝑠𝑝 3 , 𝑑𝑠𝑝2 c) 𝑑𝑠𝑝2 , 𝑠𝑝3 d) 𝑑𝑠𝑝3 , 𝑑𝑠𝑝2
643. The following compounds on hydrolysis in aqueous acetone will give:

a) Mixture of (K) and (L) b) Mixture of (K) and (M) c) Only (M) d) Only (K)
644. The number of π-electrons in cyclo hepta trienyl anion is:
a) 2 b) 3 c) 8 d) 5
645. In the Grignard reaction, which metal forms an organometallic bond?
a) Sodium b) Titanium c) Magnesium d) Palladium
646. Aromatic hydrocarbons are the derivatives of:
a) Benzene
b) Methane
c) Normal series of paraffins
d) None of the above
647. Benzene easily shows:
a) Ring fission reactions since it is unstable
b) Addition reactions since it is unsaturated
c) Electrophilic substitution reactions due to stable ring and high π-electron density
d) Nucleophilic substitution reactions due to stable ring and minimum electron density
648. The IUPAC name of the compound

is
a) Tetra phenyl methane b) 1,1,1,1-tetraphenyl methane
c) 1,1,1,1-tetracyclohexyl methane d) Methyno-1,1,1-1-tetracyclohexane
649.

having the IUPAC name as

a) 2,4,4-trimethyl pentanal b) 4,4,2-trimethyl pentanal
c) 1,3,3-trimethyl butanal d) 3,3,1-trimethyl butanal
650. When benzoic acid is heated with soda lime, we get:
a) Phenol b) Benzyl alcohol c) Benzene d) Benzaldehyde
651. If a compound absorbs violet colour from the sunlight, then the observed colour is:
a) Yellow b) Orange c) Blue d) Green
652. Sulphonic acid is used in the manufacture of:
a) Antipyretics b) Antitoxine c) Antibiotics d) Dyes
653. In the silver plating of Cu, K[Ag(CN)2 ] is used instead of AgNO3 . The reason is:
a) A thin layer of Ag is formed on Cu

P a g e | 52
 b) More heat is required
c) 𝐴g + ions are completely removed from solution
d) Less availability of Ag + ion as Cu cannot displace Ag from Ag(CN)2
654. The strongest 𝑜-, 𝑝-directing group among the following is:
a) —OH b) —Cl c) —C6 H5 d) —Br
655. Out of TiF6 , CoF6 , Cu2 Cl2 and NiCl4 (Z of Ti = 22, Co = 27, Cu = 29, Ni = 28) the colourless species are:
2− 3− 2−

a) CoF63− and NiCl2−

4 b) TiF62− and CoF63− c) Cu2 Cl2 and NiCl2−
4 d) TiF62− and Cu2 Cl2
656. Which is true in the case of [Fe(CN)6 ]3− complex?
a) 𝑑2 𝑠𝑝3 -hybridization of Fe
b) Paramagnetic
c) One unpaired electron
d) All of the above are correct
657. The IUPAC name of [Ni(PPh3 )2 Cl2 ]2+ is
a) Bis-dichloro (triphenylphosphine)nickel(II) b) Dichloro bis (triphenylphosphine)nickel(II)
c) Dichloro triphenylphosphine nickel(II) d) Triphenyl phosphine nickel (II) dichloride
658. The complex [Co(NH )
3 3 Cl3 ]is:
a) Neutral b) Cationic c) Anionic d) None of these
659. From the stability constant (hypothetical values) given below, predict which is the strongest ligand?
a) Cu2+ + 4NH3 ⇌ [Cu(NH3 )4 ]2+ ; (𝐾 = 4.5 × 1011 )
b) Cu2 + 4CN ⇌ [Cu(CN)4 ]2− ; (𝐾 = 2.0 × 1027 )
c) Cu2+ + 2en ⇌ [Cu(en)2 ]2+ ; (𝐾 = 3.0 × 1015 )
d) Cu2+ + 4H2 O ⇌ [Cu(H2 O)4 ]2+ ; (𝐾 = 9.5 × 108 )
660. Which has highest m.p.?
a) 𝑜-bromophenol b) 𝑚-bromophenol c) 𝑝-bromophenol d) 𝑚-chlorophenol
661. Hexafluorocobaltate(III) ion is found to be high spin complex, the probable hybrid state of cobalt in it is:
a) 𝑑2 𝑠𝑝3 b) 𝑠𝑝 3 c) 𝑠𝑝3 𝑑 d) 𝑠𝑝3 𝑑2
662. Which isomeric dibromotoluene is most difficult to make from toluene?
a) 2,3 b) 2,4 c) 3,5 d) 2,6
663. Which one of the following forms with an excess of CN (cyanide) a complex?
−

a) Cu+ b) Ag + c) Ni2+ d) Fe2+

664. Nitration of salicylic acid gives:
a) 2,4,6-trinitrosalicylic acid
b) 2,4,6-trinitrophenol
c) 2,4,6-trinitrobenzoic acid
d) None of the above
665. The IUPAC name of the compound

is
a) N-hydroxy-3-amino pentane b) N-hydroxyamino pentane
c) N-hydroxy-3-imino pentane d) None of the above
666. Which is not true of the coordination compound [Co en)2 Cl2 ]Cl?
(
a) Exhibits geometrical isomerism b) Exhibits optical isomerism
c) Exhibits ionisation isomerism d) Is an octahedral complex
667. The IUPAC name of

is
a) 3-(bromomethyl)-2-methyl butanoyl chloride b) 3-(bromomethyl)-2-methyl propanoyl chloride
c) 2-(bromomethyl)-3-methyl butanoyl chloride d) None of the above

P a g e | 53
668. Aniline is reacted with bromine water and the resulting product is treated with an aqueous solution of
sodium nitrite in the presence of dilute HCl. The compound so formed is treated with fluoroboric acid
which is subsequently heated dry. The final product is:
a) 𝑝-bromofluorobenzene
b) 𝑝-bromoaniline
c) 2,4,6-tribromofluorobenzene
d) 1,3,5-tribromobenzene
669. Which of the following is a common donor atom in ligands?
a) Nitrogen b) Oxygen c) Arsenic d) Both (b) and (c)
670. The reaction of aniline with acetyl chloride in presence of NaOH gives:
a) Acetanilide b) Aniline hydrochloride c) 𝑝-chloroaniline d) A red dye
671. In the reaction, the compound ′′𝑋′′ is:

a) CH3 COOH
b) Br ∙ CH2 COOH
c) (CH3 CO)2 O
d) CHO ∙ COOH
672. Which of the following will exhibit maximum ionic conductivity?
a) K 4 [Fe(CN)6 ] b) [Co(NH3 )6 ]Cl3 c) [Cu(NH3 )4 ]Cl2 d) [Ni(CO)4 ]
673. Dipole moment of 𝑝-nitroaniline, when compared to nitrobenzene (𝑋) and aniline (𝑌) will be:
a) Greater than (𝑋) and (𝑌)
b) Smaller than (𝑋) and (𝑌)
c) Greater than (𝑋) but smaller than (𝑌)
d) Equal to zero
674. The structure of iron pentacarbonyl is:
a) Square planar b) Trigonal bipyramidal c) Triangular d) None of these
675. Turnbull’s blue is:
a) Ferricyanide b) Ferrous ferricyanide c) Ferrous cyanide d) Ferri ferrocyanide
676. The correct IUPAC name of

is
a) 2-hydroxypropane-1, 2, 3-tricarboxylic acid b) 3-carboxy-3-hydroxy-pentane-1, 5-dioic acid
c) 2 carboxy-4 hydroxy-pentane-1, 5-dioic acid d) 3-carboxy-3-hydroxy-hexane-1, 6-dioic acid
677. The trivial name among the following is
a) Acetone b) Acetylene c) Uric acid d) None of these
678. The IUPAC name of [Pt(NH3 )4 (NO2 )Cl]SO4 is
a) Chloronitro tetrammine platinum (IV) sulphate
b) Tetrammine chloronitro platinum (II) sulphate
c) Tetrammine chloronitro platinum (IV) sulphate
d) Chlorotetrammine nitroplatinum (IV) sulphate
679. The overlapping in benzene is in carbon-carbon orbitals of the type:
a) 𝑝 − 𝑝 b) 𝑠𝑝 − 𝑠𝑝 c) 𝑠𝑝2 − 𝑠𝑝2 d) 𝑠𝑝3 − 𝑠𝑝3
680. Change in composition of coordination sphere yields which type of isomer?
a) Geometrical b) Ionization c) Optical d) None of these
681. The IUPAC name of K 2 [Ni(CN)4 ] is
a) Potassium tetracyanonickelate (II) b) Potassium tetracyanatonickelate (III)

P a g e | 54
 c) Potassium tetracyanatonickel (II) d) Potassium tetracyanonickel (III)
682. Aniline in a set of the following reactions yielded a coloured compound 𝑌:

a)

b)

c)

d)

683. The effective atomic number rule is less likely to apply if the metal-ligand bond:
a) Is extremely weak
b) Has a covalent character
c) Has a large amount of ionic character
d) None is correct
684. Potassium ferrocyanide is an example of
a) Tetrahedral b) Octahedral c) Square planar d) Linear
685. 1-phenyl, 2-chloropropane on treatment with aqueous KOH gives mainly:
a) 1-phenylpropane b) 3-phenylpropane c) 1-phenylpropan-2-ol d) 1-phenylpropan-3-ol
686. Which class of compounds can exhibit geometrical isomerism?
a) C6 H5 CH = NOH b) CH3 CH = CHCH3
c) d) All of the above

687. The product of oxidation of aniline with K 2 Cr2 O7 and conc. H2 SO4 will be:
a) p-amino phenol
b) p-benzoquinone
c) Aniline black dye
d) Phenyl hydroxylamine
688. Among the following the Newmann projections of 𝑚𝑒𝑠𝑜-2, 3-butanediol are

a) 𝑃, 𝑄 b) 𝑃, 𝑅 c) 𝑅, 𝑆 d) 𝑄, 𝑆
689. A new carbon-carbon bond is formed in:
a) Cannizzaro’s reaction

P a g e | 55
 b) Friedel-Crafts reaction
c) Clemmensen reduction
d) None of the above
690. Which of the following compounds can exhibit tautomerism?
CH3 − CH − CH3
a) b) c) d) |
NH2
691. The most basic compound among the following is:
a) Benzylamine b) Aniline c) Acetanilide d) 𝑝-nitroaniline
692. Which of the following has least oxidation state of Fe?
a) K 3 [Fe(OH)6 ] b) K 2 [FeO4 ]
c) FeSO4 (NH4 )2 SO4 .6H2 O d) [Fe(CN)6 ]3−
693. The spin only magnetic moment value (in Bohr magneton units) of Cr(CO)6 is
a) 0 b) 2.84 c) 4.90 d) 5.92
694. Which is an excellent antiseptic?
a) Phenol b) Benzyl alcohol c) Benzaldehyde d) Acetic acid
695. Scientist who explained the structures and isomerism in the complex compound was:
a) Sidgwick b) Pauling c) Powell d) Werner
696. The cation that does not form an ammine complex with excess of ammonia is:
a) Al3+ b) Ag + c) Cu2+ d) Cd2+
697. The complex ion which has the highest magnetic moment among the following is
a) [CoF6 ]3− b) [Co(NH3 )6 ]3+ c) [Ni(NH3 )4 ]2+ d) [Ni(CN)4 ]2−
698. For square planar complex of platinum (II), [Pt(NH3 )(Br)(Cl)Py]2+ , how many isomeric forms are
possible?
a) Two b) Three c) Four d) Six
699. Which of the following has highest boiling point?
a) Benzene b) Phenol c) Toluene d) Ethyl benzene
700. A nitrogen containing organic compound on heating with chloroform and alcoholic KOH evolved very
unpleasant smelling vapours. The compound could be:
a) Nitrobenzene b) Benzamide c) 𝑁, 𝑁-dimethyl amine d) Aniline
701. Which of the following 0.1 M complex compound solutions will have the minimum electrical conductivity?
a) Hexammine platinum (IV) chloride b) Chloropenta ammine platinum (IV) chloride
c) Dichloro tetrammine platinum (IV) chloride d) Trichloro triammine platinum (IV) chloride
702. False statement is
a) Aprotic solvents increase the enol content in tautomerism
b) Any deviation from the normal bond angles introduces angle strain in molecule
c) Diastereomers have identical physical properties
d) Chain isomers can also be position isomers
703. The correct IUPAC name of the compound is
CH3 − CH − CH − CH − CH2 − CH3
| | |
Cl Br I
a) 4-bromo-5-chloro-3-iodo hexane b) 3-bromo-2-chloro-4-iodo hexane
c) 3-bromo-4-iodo -2-chloro hexane d) 2-bromo-3-bromo-4-iodo hexane
704. Benzyl chloride (C6 H5 CH2 Cl) can be prepared from toluene by chlorination with:
a) SO2 Cl2 b) SOCl2 c) S2 Cl2 d) NaOCl
705. The compound 2,2’-bipyridine has the structure

a) b)

P a g e | 56
 c) d)

706. The IUPAC name of

a) 4-formyl-6-oxocyclohexane-1-carboxylic acid b) 2-oxo-4-formyl cyclohexane-1-carboxylic acid

c) 6-oxo-4-formyl cyclohexane-1-carboxylic acid d) 4-formyl-2-oxo cyclohexane-1-carboxylic acid
707.

a) HCl/CuCl b) HNO2 /Cu c) C2 H5 OH/Cu d) SnCl2 /HCl

708. Diethylenetriammine is:
a) Chelating agent b) Polydentate ligand c) Tridentate ligand d) All of these
709. The no. of ions given by [Pt(NH3 )4 Cl2 ]Cl2 in aqueous solution is:
a) 2 b) 3 c) 4 d) 5
710. Aniline reacts with excess of bromine to give:
a) Benzyl bromide and hydrobromic acid
b) 2,4,6-tribromoaniline
c) 2-bromotoluene and hydrobromic acid
d) 2-bromophenol and hydrobromic acid
711. The coordination compounds,
[Co(NH3 )6 ]3+ [Cr(CN)6 ]3−
and [Cr(NH3 )6 ]3+ [Co(CN)6 ]3− are example of
a) Linkage isomerism b) Coordination isomerism
c) Ionisation isomerism d) Geometrical isomerism
712. Both Co3+ and Pt 4+ have a coordination number of six. Which of the following pairs of complexes will show
approximately the same electrical conductance for their 0.001 M. aqueous solutions?
a) CoCl3 .4NH3 and PtCl4 . 4NH3 b) CoCl3 .3NH3 and PtCl4 . 5NH3
c) CoCl3 .6NH3 and PtCl4 . 5NH3 d) CoCl3 .6NH3 and PtCl4 . 3NH3
713. In SCN ligand if N is attached to central atom, the name of ligand is:
a) Thiocyanato-N b) Cyanato-N c) Thiocyanato-S d) Cyanato-S
714.

a)

P a g e | 57
 b)

c)

d)

715. Oxidation of ethyl benzene by KMnO4 gives:

a) Benzyl alcohol b) Benzophenone c) Acetophenone d) Benzoic acid
716. One of the following statements regarding Reimer-Tiemann reaction is false:
a) Reaction of phenol with CHCl3 and KOH
b) CCl2 acts as a nucleophile
c) Reaction of phenol with CCl4 and NaOH
d) Reaction of phenol with formaldehyde to form bakelite
717. The structure representing a heterocyclic compound is

a) b)

c) d)

718. Phenol reacts with Br2 in CCl4 at low temperature to give:

a) 𝑚-bromophenol
b) 𝑜-and 𝑝-bromophenol
c) 𝑝-bromophenol
d) 2,4,6-tribromophenol
719. The correct name of the compound [Cu(NH3 )4 ](NO3 )2 , according to IUPAC system is
a) Cuprammonium nitrate b) Tetrammine copper (II) dinitrate
c) Tetrammine copper (II) nitrate d) Tetrammine copper (II) dinitrite
720. Nitroethane can exhibit one of the following kind of isomerism
a) Metamerism b) Optical activity c) Tautomerism d) Position isomerism
721. What would be the correct IUPAC name of

a) 3,3-dimethyl-3-cyclopentyl propanal
b) 3-methyl-3-cyclopentyl butan-1-al
c) 1-(1-methyl-1-formyl) methylethyl cyclopropane
d) None of above
722. The number of unpaired electrons in the square planar [Pt(CN)4 ]2− ion is
a) 2 b) 1 c) 0 d) 3
723. The oxidation number of cobalt in K[Co(CO)4 ]is
P a g e | 58
 a) +1 b) +3 c) −1 d) −3
724. IUPAC name of Na3 [Co(NO2 )6 ] is
a) Sodium hexanitrito cobaltate (II) b) Sodium hexanitro cobaltate (III)
c) Sodium hexanitrito cobaltate (III) d) Sodium cobaltinitrite(II)
725. The total number of possible isomers for the complex compound [Cu(NH3 )4 ][PtCl4 ]
a) 6 b) 5 c) 4 d) 3
726. Benzaldehyde reacts with excess of anhydrous ethyl alcohol in the presence of HCl, gives:
a) C6 H5 COCl b) C6 H5 COOC2 H5 c) C6 H5 CH(OC2 H5 )2 d) C6 H5 CH2 Cl
727. Which pair of isomerism is not possible together?
a) Chain and position b) Functional and position
c) Tautomerism and functional d) All of the above
728. Which type of conformation is shown by I and II?

a) I is eclipsed, II is staggered b) II is eclipsed, I is staggered

c) Both are eclipsed d) Both are staggered
729. Which will give chiral molecule?
CH3 MgBr
LiAlH4 C2 H5 CHO → +
a) CH3 COCl → b) H /H2 O

Cu
c) (CH3 )2 CHC2 H5 → d)

730. The neutral ligand is:

a) Chloro b) Hydroxo c) Ammine d) Oxalato
731. The effective atomic number of cobalt in the complex [Co(NH )
3 6 ]3+
is
a) 36 b) 24 c) 33 d) 30
732. K 4 [Fe(CN)6 ] is used to detect the presence of:
a) Metallic ion b) Ferrous ion c) Ferric ion d) None of these
733. 𝑝-nitro benzldehyde reacts with concentrated NaOH solution at room temperature to give:
a) 𝑝-nitrobenzamide
b) 𝑝-nitro benzyl alcohol and sod. 𝑝-nitrobenzoate
c) Benzaldehyde
d) 𝑝-nitrotoluene
734. But-1-ene and cyclobutane exhibit
a) Ring chain isomerism
b) Position isomerism
c) Tautomerism
d) Functional
isomerism
735. The groups satisfying the secondary valencies of a cation in a complex are called:
a) Ligands b) Radicals c) Primary valencies d) None of these
736. Benzene was dicovered by:
a) Cavendish b) Faraday c) Berzelius d) Wöhler
737. The number of structural and configurational isomers of a bromo compound C5 H9 Br obatined by the
addition of HBr on 2-pentyne respectively are
a) 1, 2 b) 2, 4 c) 4, 2 d) 2, 1

P a g e | 59
738. The primary valency of Fe in K 3 [Fe(CN)6 ] is:
a) 3 b) 2 c) 1 d) Zero
739. Which complex compound obeys 18-electron rule?
a) [V(CO)5 ] b) [Fe(NH3 )6 ]2+ c) [Ni(CO)6 ] d) [Mn(H2 O)6 ]2+
740. Two isomers X and Y with the formula Cr(H2 O)5 ClBr2 were taken for experiment on depression in
freezing point. It was found that one mole of X gave depression corresponding to 2 moles of particles and
one mole of Y gave depression due to 3 moles of particles. The structural formula of X and Y respectively,
are
a) [Cr(H2 O)5 Cl]Br2 ; [Cr(H2 O)4 Br2 ]Cl. H2 O b) [Cr(H2 O)5 Cl]Br2 ; [Cr(H2 O)3 ClBr2 ].2H2 O]
c) [Cr(H2 O)5 Br]BrCl; [Cr(H2 O)4 ClBr]Br. H2 O d) [Cr(H2 O)4 Br2 ]ClH2 O; [Cr(H2 O)5 Cl]Br2
741. The IUPAC name of

is
a) 1-formyl-3-oxo-pentanoic acid b) 5-formyl-3-oxo pentanoic acid
c) 3-oxo-5-formyl pentanoic acid d) 3-oxo-1-formyl pentanoic acid
742. The two complexes given below are:

a) Geometrical isomers b) Position isomers c) Optical isomers d) Identical

743. Which of the following statements is not correct?
a) In oxyhaemoglobin Fe2+ is paramagnetic
b) During respiration the size of Fe2+ increases when it changes from diamagnetic to paramagnetic state
c) Four haeme groups are present in haemoglobin
d) Haeme is the prosthetic group and it is non-protein part
744. Chlorination of toluene in the presence of light and heat followed by treatment with aqueous NaOH gives:
a) 𝑜-cresol b) 𝑝-cresol c) 2,4-dihydroxytoluene d) Benzoic acid
745. Which of the following has maximum probability of showing tautomerism?

a) b) c) d)

746. The halide which undergoes nucleophilic substitution most readily is:
a) 𝑝-H3 CC6 H4 Cl b) 𝑜-H3 COC6 H4 Cl c) 𝑝-ClC6 H4 Cl d) 𝑝-O2 NC6 H4 Cl
747. The major product (70% to 80%) of the reaction between 𝑚-dinitrobenzene with (NH4 )2 Sx is:

a) b) c) d)

748. The ′𝐸′-isomer is

P a g e | 60
 a) b)

d) None of the above

c)

749. The Baeyer angle strain is minimum in

a) Cyclopropane b) Cyclobutane c) Cyclopentane d) Cyclohexane
750. Among the following ions, which one has the highest unpaired electrons?
a) [Cr(H2 O)6 ]3+ b) [Zn(H2 O)6 ]2+ c) [Fe(H2 O)6 ]2+ d) [Cr(H2 O)6 ]3+
751. Which will give a white precipitate with AgNO3 in aqueous solution?
a) [Co(NH3 )5 Cl](NO2 )2 b) [Pt(NH3 )6 ]Cl4 c) [Pt(en)Cl2 ] d) [Cu(NH3 )4 ]SO4
752. The organic product formed in the reaction;

a) C6 H5 CH2 OH and CH3 OH

b) C6 H5 COOH and CH4
c) C6 H5 CH3 and CH3 OH
d) C6 H5 CH3 and CH4
753. Complexes with bidentate ligands are called:
a) Ligands b) Chelates c) Complexes d) None of these
754. Excited state configuration of Mn2+ is
4 3 2 4 2 5 0
a) 𝑡2𝑔 b) 𝑡2𝑔 𝑒𝑔 c) 𝑡2𝑔 𝑒𝑔 d) 𝑡2𝑔 𝑒𝑔
755. The IUPAC name of

is
a) Ethyl acetylate b) Ethyl methyl butenoate
c) Ethyl acetoethanoate d) Ethyl (3-methyl) but-2-enoate
756. The compound which result from the coordination of carbon monoxide are known as
a) Carbon permono b) Electronic c) Carbonyls d) None of these
757. The correct IUPAC name of AlCl3 (EtOH)4 is:
a) Aluminium(II) chloride-4-ethanol
b) Aluminium(III)chloride-4-ethanol
c) Aluminium(IV)chloride-4-hydroxy ethane
d) Aluminium chloride-4-ethanol
758. The IUPAC name of [Co(NH3 )6 ][Cr(C2 O4 )3 ]is
a) Hexaamine cobalt (III) tris (oxalato ) chromium
b) Hexaamine cobalt (III) tris (oxalato ) chromate(III)
c) Hexaamine cobalt tris (oxalato ) chromium(III)
d) Hexaamine cobalt (III) chromium (III) oxalate
759. The insecticide, germicide gammexane is a formulation for:
a) DDT
b) Benzene hexachloride
c) Hexachlorobenzene
d) Chloral
760. Among [Ni(CO)4 ]2− , [Ni(CN)4 ]2− , [NiCl4 ]2− species, the hybridisation states of the Ni atom are,
respectively (Atomic no. of Ni=28)
a) 𝑠𝑝3 , 𝑑𝑠𝑝2 , 𝑑𝑠𝑝2 b) 𝑠𝑝 3 , 𝑑𝑠𝑝2 , 𝑠𝑝3 c) 𝑠𝑝3 , 𝑠𝑝3 , 𝑑𝑠𝑝2 d) 𝑑𝑠𝑝2 , 𝑠𝑝3 , 𝑠𝑝
761. Which of the following complex ions is expected to absorb visible light?

P a g e | 61
 a) [Zn(NH3 )6 ]2+
b) [Sc(H2 O)3 (NH3 )3 ]3+
c) [Ti(en)2 (NH3 )2 ]4+
[Cr(NH3 )6 ]3+
d)
[At. no. Zn = 30, Sc = 21, Ti = 22, Cr = 24]
762. Chain isomers of CH3 CH2 CH2 CH2 OH is/are
a) 2 b) 3 c) 4 d) 5
763. Although chlorobenzene does not give Ulmann’s reaction. However, presence of…group in chlorobenzene
at 𝑜-, 𝑝-position enables it to give Ulmann’s reaction.
a) NO2 b) NH2 c) OH d) SO3 H
764. Which statement is true?
a) A compound with 𝑅 configuration is the (+) enantiomer
b) If configuration changes from + to −, that essentially means inversion of configuration take place
c) An achiral molecule reacts to give a chiral molecule, always racemic forms
d) By breaking two bonds on the chiral centre configuration changes
765. Which can be used for carrying out electrophilic aromatic substitution?
a) Water b) Liquid NH3 c) Oleum d) Hydride ion
766. Which of the following can participate in linkage isomerism?
a) NO− b) c) H2O d)
2

767. Aniline in a set of reactions yielded a product 𝐷.

The structure of the product 𝐷 would be:

a) C6 H5 NHCH2 CH3 b) C6 H5 CH2 OH c) C6 H5 CH2 NH2 d) C6 H5 NHOH
768. The number of ions formed when cuprammonium sulphate is dissolved in water is
a) Zero b) 1 c) 2 d) 4
769. Tautomerism is not exhibited by :

a) C6 H5 − CH = CH − OH b) c) d)

770. Benzaldehyde reacts with NH3 to give:

a) Aniline b) Benzamide c) Phenylcyanide d) Hydrobenzamide
771. In coal-tar fraction of heavy oil, the aromatic compound present is:
a) Cresol
b) Pyridine
c) Benzene
d) Anthracene
772. Optical isomerism is shown by octahedral complexes
a) Having all monodentate ligands b) Having all the three bidentate ligands
c) Having two 𝑡𝑟𝑎𝑛𝑠 bidentate ligands d) Having two 𝑡𝑟𝑎𝑛𝑠 monodentate ligands
773. Which can be hydrolysed most easily?
a) (C6 H5 )3 CCl b) C6 H5 CH2 Cl c) (C6 H5 )2 CHCl d) C6 H5 Cl
774. The most stable configuration of 𝑛 butane will be
a) Skew boat b) Eclipsed c) Gauche d) Staggered-anti
775. Anhydrous aluminium chloride is used in Friedel-Craft’s reaction because it is:
a) Electron rich
b) Soluble in ether
c) Ionizable to chloride and aluminium ions
P a g e | 62
 d) Electron deficient molecule
776. The two isomers given below are
(i) COOH
|
H − C − OH
|
HO − C − H
|
COOH
(ii) HOOC
|
H − C − OH
H − C − OH
|
HOOC

a) Enantiomers b) Diastereomers c) Measomers d) Position isomers

777. Which of the following has lowest boiling point?
a) Phenol b) 𝑜-nitrophenol c) 𝑚-nitrophenol d) 𝑝-nitrophenol
778. The IUPAC name of [Ni(NH3 )4 ][NiCl4 ] is
a) Tetrachloro nickel (II) – tetraammine nickel (II)
b) Tetraammine nickel (II) –tetrachloro nickel(II)
c) Tetraammine nickel (II) –tetrachloro nickelate(II)
d) Tetrachloro nickel (II) –tetraammine nickelate(0)
779. All ligands are:
a) Lewis acid b) Lewis base c) Neutral d) None of these
780. Aspirin is known as:
a) Phenyl salicylate b) Acetyl salicylate c) Methyl salicylic acid d) Acetyl salicylic acid
781. Which of the following has on optical isomer?
a) [Co(NH3 )3 Cl]+ b) [Co(en)(NH3 )2 ]2+ c) [Co(H2 O)4 (en)]3+ d) [Co(en)2 (NH3 )2 ]3+
782. The IUPAC name of the compound

a) 1,1,1-trichloro-2,2-diphenyl ethane b) 2,4,5-trichloro hexanol

c) 2,2,2-trichloro bicyclo [4.4.0] nenone d) 2,2,2-trichloro-1,1-diphenyl ethane
783. The property by virtue of which a compound can rotate the plane of polarised light is known as
a) Polarisability b) Phosphorescence c) Optical activity d) Polarization

784. The molecules represented by the following two structures are

a) Epimers b) Diastereomers c) Enantiomers d) Identical

785. The IUPAC name of the coordination compound K 3 [Fe(CN)6 ] is
a) Tripotassium hexacyanoiron (II) b) Potassium hexacyanoiron(II)
c) Potassium hexacyanoferrate (III) d) Potassium hexacyanoferrate (II)
786. Which one of the following is an inner orbital complex as well as diamagnetic in nature?
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 a) [Cr(NH3 )6 ]3+ b) [Co(NH3 )6 ]3+ c) [Ni(NH3 )6 ]2+ d) [Zn(NH3 )6 ]2+
787. How many unpaired electrons are present in the central metal ion of [CoCl4 ] ? 2−

a) 3 b) 4 c) 5 d) 2
788. Show the coordination number of the metal ion, its oxidation number, the number of electrons in d-
orbitals and the number of unpaired electrons d-orbitals respectively in complex [Co(H2 O)4 SO3 ]Cl.
a) 6, 3, 6, 4 b) 6, 3, 6, 0 c) 5, 3, 6, 4 d) 5, 3, 6, 0
789. Benzene reacts with…..to give acetophenone.
a) Acetyl chloride
b) Acetyl chloride in presence of anhy. AlCl3
c) Anhy. AlCl3
d) None of the above
790. Which group would you introduce into a drug or a dye to make it water soluble?
a) —NO2 b) —Cl c) —SO3 H d) —OH
791. In the coordination compound, K 4 [Ni(CN)4 ],oxidation state of nickel is
a) −1 b) +1 c) 0 d) +2
792. The IUPAC name of [Cr(NH3 )4 Cl2 ]NO3 is:
a) Tetraaminodichlorochromium (I) nitrate
b) Tetraaminodichlorochromium (III) nitrate
c) Dichlorotetraamminechromium (III) nitrate
d) Tetraaminodichlorochromium (II) nitrate
793. Vanillin, used as a flavouring agent is:
a) An aliphatic alcohol b) An aromatic aldehyde c) A hydrocarbon d) A carbohydrate
794. Which of the following will exhibit optical isomerism?
a) [Cr(en)(H2 O)4 ]3+ b) [Cr(en)3 ]3+ c) 𝑡𝑟𝑎𝑛𝑠-[Cr(en)2 Cl2 ]+ d) [Cr(NH3 )6 ]3+
795. Which one is a mixed ketone?
a) Benzophenone b) Benzenone c) Acetophenone d) Dibenzyl ketone
796. Transition metals can form complexes in:
a) Zero oxidation state b) Cation form c) Anion form d) All of these
797. Toluene on oxidation with air in presence of V2 O5 yields:
a) Phenol b) Benzoic acid c) Benzaldehyde d) Benzyl alcohol
798. [Pt((NH3 )4 ]Cl2 is
a) Pyramidal b) Pentagonal c) Tetrahedral d) Square planar
799. In Fe(CO)5 , the FE—C bond possess:
a) π-character only
b) Both σ and π-characters
c) Ionic character
d) σ-character only
800. Which molecule has tetrahedral geometry?
a) [Co(NH3 )6 ]3+ b) [Ni(CN)4 ]2+ c) Fe(CO)5 d) [NiCl4 ]2−
801. [Co(NH3 )5 Br]SO4 and [Co(NH3 )5 SO4 ]Br are the examples of:
a) Linkage isomerism
b) Geometrical isomerism
c) Ionization isomerism
d) Optical isomerism
802. The compounds 𝑅 − NO2 and 𝑅 − ONO are
a) Geometrical isomers b) Functional isomers
c) Metamers d) Optical isomers
803. Which of the following Fischer projection formula is same as D-glyceraldehyde?

P a g e | 64
 a) b) c) d)

804. [Fe(NO2 )3 Cl3 and [Fe(O— NO)3 Cl3 ] shows

a) Linkage isomerism b) Geometrical isomerism
c) Optical isomerism d) None of the above
805.

The IUPAC name of the compound is

a) 2-ethenyl-3-methyl cyclohexa-1, 3-diene b) 2, 5-dimethyl hepta-2, 6-dienoic acid
c) 2, 6-dimethyl hepta-2, 5dienoic acid d) 2, 3-dimethyl epoxyethane
806. When benzene sulphonic acid and 𝑝-nitrophenol are treated with NaHCO3 , the gases released respectively
are:
a) SO2 , NO2 b) SO2 , NO c) SO2 , CO2 d) NO2 , CO2
807. Which of the following is non-ionizable?
a) [Co(NH3 )3 Cl3 ] b) [Co(NH3 )4 Cl2 ]Cl c) [Co(NH3 )5 Cl]Cl2 d) [Co(NH3 )6 ]Cl2
808. Increasing order of expected keto content
a) CH3 COC2 H5 > CH3 CHO > CH3 COCH3 > CH3 COCH2 COCH3
b) CH3 COCH3 > CH3 CHO > CH3 COC2 H5 > CH3 COCH2 COCH3
c) CH3 CHO > CH3 COC2 H5 > CH3 COCH3 > CH3 COCH2 COCH3
d) CH3 COCH2 COCH3 > CH3 CHO > CH3 COCH3 > CH3 COC2 H5
809. Which is colourless complex?
a) Cu2 (CH3 COO)4 ∙ H2 O
b) Cu2 Cl2
c) CuSO4 ∙ 5H2 O
d) [Cu(NH3 )4 ]SO4 ∙ SO4 ∙ 4H2 O
810. Which is not a reasonable structure for dimethyl benzene?

a) b) c) d)

811.

The IUPAC name of the compound is

a) Propionic anhydride b) Dipropanoic anhydride
c) Ethoxy propanoic acid d) Propanoic anhydride
812. A mixture of benzene and aniline can be separated by:
a) Alcohol b) Dil. HCl c) Dil. NaOH d) Hot water
813. The correct IUPAC name of the complex Fe C5 H5 2 is
( )
a) Cyclopentadienyl iron (II) b) Bis (Cyclopentadienyl)iron (II)
c) Dicyclo pentadienyl ferrate (II) d) Ferrocane
814.

The electrophile involved in the above reaction is:

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 a)
b) Dichlorocarbene (: CCl2 )
c)
d)

815. Benzoyl Chloride is prepared from benzoic acid by:

a) Cl2 , ℎ𝑣 b) SO2 Cl2 c) SOCl2 d) Cl2 , H2 O
816. Which of the following ions forms most stable complex compound?
a) Fe3+ b) Mn2+ c) Ni2+ d) Cu2+
817. Which one of the following cyano complexes would exhibit the lowest value of paramagnetic behaviour?
(Atomic no. Cr=24, Mn=25, Fe=26, Co=27)
a) [Co(CN)6 ]3− b) [Fe(CN)6 ]3− c) [Mn(CN)6 ]3− d) [Cr(CN)6 ]3−
818. Which of the following statements is not correct?
a) The complexes [NiCl4 ]2− and [Ni(CN)4 ]2− differ in the state of hybridisation of nickel.
b) The complexes [NiCl4 ]2− and [Ni(CN)4 ]2− differ in the magnetic properties.
c) The complexes [NiCl4 ]2− and [Ni(CN)4 ]2− differ in geometry.
d) The complexes [NiCl4 ]2− and [Ni(CN)4 ]2− differ in primary valencies of nickel.
819. In the complexes [Fe(H2 O)6 ]3+ , [Fe(CN)6 ]3− , [Fe(C2 O4 )3 ]3− and [FeCl6 ]3− , more stability is shown by:
a) [Fe(H2 O)6 ]3+ b) [Fe(CN)6 ]3− c) [Fe(C2 O4 )3 ]3− d) [FeCl6 ]3−
820. In the reaction,

the intermediate ‘X’ is:

a) Phthalic anhydride b) Phthalic acid c) 𝑜-xylene d) Benzoic acid
821. Which of the following is π complex?
a) Trimethyl aluminium b) Ferrocene c) Diethyl zinc d) Nickel carbonyl

822. When phenol is reacted with chloroform and an alkali like NaOH, the compound formed is salicyladehyde.
If we use pyrene in place of chloroform the product obtained is:
a) Salicyladehyde b) Phenolphthalein c) Salicylic acid d) Cyclohexanol
823. Among the properties (a) reducing (b) oxidizing (c) complexing, the set of properties shown by CN− ion
towards metal species is
a) B, c b) A, b, c c) C, a d) A, b
824. Which of the following is most powerful 𝑚𝑒𝑡𝑎 directing group?
a) —NO2 b) —SO3 H c) —CHO d) —COOH
825. Which among the following compounds will show metamerism?
a) CH3 COC3 H7 b) CH3 OC2 H5 c) CH3 SC2 H5 d) CH3 OCH3
826. The hybridization of [PtCl6 ] ion is:
2−

a) 𝑑2 𝑠𝑝3 b) 𝑠𝑝 2 𝑑3 c) 𝑠𝑝3 𝑑 d) 𝑠𝑝3 𝑑2

827. The correct name of [Pt(NH3 )4 Cl2 ][PtCl4 ] is
a) Tetrachloro platinum (II) dichloro tetrammine platinate
b) Dichloro tetremmine platinum (IV) tetrachloro platinate(II)
c) Tetrammine dichloro platinum (IV) tetrachloro platinate (II)
d) Tetrachloro platinum (II) tetrammine platinate (IV)
828. The oxidation state of iron in K 4 [Fe(CN)6 ]is
a) 1 b) 4 c) 3 d) 2
829. Formation of complex compound can be detected by:
a) Change in colour b) Change in solubility c) Change in pH d) All are correct
830. The complex that violates the EAN:
P a g e | 66
 a) Potassium ferrocyanide
b) Potassium ferricyanide
c) Nickel carbonyl
d) Cobalt(III) hexaammine chloride
831. Chlorobenzene on heating with aqueous NH3 under pressure in presence of Cu2 Cl2 gives:
a) Aniline b) Benzamide c) 𝑜-dichlorobenzene d) Chloroaminobenzene
832. The complex, [Pt(Py)(NH3 )BrCl] will have how many geometrical isomers?
a) 2
b) 3
c) 4
d) 0
833. Which one doesn’t have π −bond?
a) Grignard reagent b) Dibenzene chromium
c) Zeise’s salt d) Ferrocene
834. The IUPAC name of the compound CH2 − CH − COOH is
| |
NH2 OH
a) 1-hydroxy-2-aminopropanoic acid b) 2-hydroxy-3-aminopropanoic acid
c) 3-amino-2-hydroxypropanoic acid d) 2-hydroxy-1-aminopropanoic acid
835. EDTA is a…..ligand.
a) Monodentate
b) Hexadentate
c) Bidentate
d) Tridentate
836. Thymol, a phenol derivative is mainly used as:
a) Germicide
b) Insecticide
c) Antibiotic
d) Fragrance compound and antiseptic
837. Which of the following complex has zero magnetic moment (spin only)?
a) [Ni(NH3 )6 ]Cl2 b) Na3 [FeF6 ] c) [Cr(H2 O)6 ]SO4 d) K 4 [Fe(CN)6 ]
838. Which compound is zero valent metal complex?
a) [Ni(CO )4 ] b) K 3 [Fe(CN)6 ] c) [Pt(NH3 )2 Cl2 ] d) [Cu(NH3 )4 SO4 ]
839.
The IUPAC name of is
a) Bicyclo [5.5.0] nonane b) Biphenyl
c) Cyclopropyl cyclohexane d) Spiro [3.5] nonane
840. The tetrahedral crystal field splitting is only…..of the octahedral splitting.
a) 1/9 b) 2/9 c) 4/9 d) 5/9
841. IUPAC name of [Co(ONO)(NH3 )5 ]Cl2 is
a) Pentammine nitrocobalt (II) chloride b) Pentammine nitrosocobalt (III) chloride
c) Pentammine nitritocobalt (III) chloride d) Pentammine oxo-nitrocobalt (III) chloride
842. Point out the central ion ligand in the complex K 2 [Cd(CN)4 ] ;
a) Cd+ , CN1− b) Cd2+ , CN1− c) Cd2+ , CN4− d) Cd2+ , CN2−
843. Number of chiral centres in

a) 1 b) 2 c) 3 d) 4

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844. From the equation, 3C2 H2 ⟶ C6 H6, find the volume of acetylene (NTP) for the manufacture of 3 mole of
benzene:
a) 67.2 litre b) 134.4 litre c) 201.6 litre d) 33.8 litre
845. According to IUPAC nomenclature sodium nitroprusside is named as
a) Sodium pentacyanonitrosyl ferrate(II) b) Sodium pentacyanonitrosyl ferrate(III)
c) Sodium nitroferricyanide d) Sodium nitroferrocyanide
846. Among [Ni(CO)4 ], [Ni(CN)4 ] and [NiCl4 ] species the hybridisation states of Ni atom are respectively:
2− 2−

a) 𝑠𝑝3 , 𝑑𝑠𝑝2 , 𝑑𝑠𝑝2 b) 𝑠𝑝 3 , 𝑑𝑠𝑝2 , 𝑠𝑝3 c) 𝑠𝑝3 , 𝑠𝑝3 , 𝑑𝑠𝑝2 d) 𝑑𝑠𝑝2 , 𝑠𝑝3 , 𝑠𝑝 3
847. The chemical name of DDT is:
a) Dichloro dinitro toluene
b) Dichloro dimethyl toluene
c) 𝑝, 𝑝′-dichloro diphenyl trichloroethane
d) None of the above
848. The stability of complexes of Cu2+ , Ni2+ , Co2+ and Fe2+ varies in the order
a) Cu2+ > Ni2+ > Co2+ > Fe2+ b) Cu2+ > Fe2+ > Ni2+ > Co2+
c) Ni > Co > Fe > Cu
2+ 2+ 2+ 2+ d) Cu2+ < Ni2+ < Co2+ < Fe2+
849. The number of unpaired electrons in Ni(CO)4 is
a) 0 b) 1 c) 3 d) 4
850. In sodium tetrafluorooxochromate(….), Na3 [Cr O F4 ] the left out place should be filled with which of the
( )
following roman numerals?
a) VI b) III c) IV d) None of these
851. The IUPAC name of compound
CN − CH2 − CH − CH2 − COOCH3 is
|
OCH3
a) 3-methoxy-4-cyano methyl butanoate b) Methyl-4-cyano-3-methoxy butanoate
c) 4-cyano-3-methoxy methyl butanoate d) Methyl-3-methoxy-4-cyano butanoate
852. Cumene is:
a) 𝑜-methyl phenol b) 𝑝-cresol c) Isopropyl benzene d) Phenyl 𝑛-propane
853. In Etard’s reaction toluene is oxidised to benzaldehyde using:
a) H2 O2
b) Cl2
c) Chromium trioxide or CrO2 Cl2
d) KMnO4
854. Which of the following will exhibit geometrical isomerism?
a) Propene b) Butene-2
c) Butene-1 d) 1, 1-dichloro butane
855. Ferrocene is:
a) Fe(5 − C5 H5 )2 b) Fe(2 − C5 H5 )2 c) Cr(5 − C5 H5 )5 d) Os(5 − C5 H5 )2
856. Which one is an outer orbital complex?
a) [Ni(NH3 )6 ]2+ b) [Mn(CN)6 ]4− c) [Co(NH3 )6 ]3+ d) [Fe(CN)6 ]4−
857. The pair of [Co(SO4 )(NH3 )5 ]Cl and [CoCl(NH3 )5 ]SO4 constitutes
a) Optical isomers b) Linkage isomers c) Coordination isomers d) Ionisation isomers
858. The IUPAC name of K 2 [Cr(CN)2 O2 (O)2 (NH3 )]is
a) Potassiumammine dicyanodioxoperoxochromate (VI)
b) Potassiumammine cyanoperoxodioxochrometic (IV)
c) Potassiumammine dicyanodioxoperoxochromium (IV)
d) Potassiumammine dicyanodioxoperoxochromium (IV)
859. In spectrochemical series chlorine is above than water i.e., Cl > H2 O, this is due to
a) Good π-acceptor properties of Cl

P a g e | 68
 b) Strong σ −donor and good π-acceptor properties of Cl
c) Good π −donor properties of Cl
d) Larger size of Cl than H2 O
860. The type of isomerism shown by [Co(en)2 (NCS)2 ]Cl and [Co(en)2 (NCS)Cl]NCS is:
a) Coordination b) Ionization c) Linkage d) All of these
861. Which ion shows only the coordination number 4 in complexes?
a) Pt 2+ b) Cr 3+ c) Fe3+ d) Pt 4+
862. The spin magnetic moment of cobalt in Hg[Co(SCN)4] is :
a) √3 b) √8 c) √15 d) √24
863. Which of the following is not an isomer of but-1-yne?
a) But-2-yne
b) Buta-1-3-diene
c) Methyl cyclopropene
d) But-2-ene
864. How many unpaired electrons are present in the central metal ion of [CoCl4 ]2− ?
a) 2 b) 3 c) 4 d) 5
865. The brown ring complex compound is formulated as [Fe(H )
2 O 5 NO]SO4 . The oxidation state of Fe is:
a) +1 b) +2 c) +3 d) Zero
866. Correct IUPAC name of

a) Gammexane b) Dichloro diphenyl trichloroethane

c) Diparachlorophenyl trichloroethane d) 1,1,1-tirchloro-2,2-bis (4-chlorophenyl) ethane
867. IUPAC name of

a) Cumene b) 2-phenyl propane

c) Phenyl propane d) 1-(2-propyl) benzene
868. Which of the following gives violet colour with an alcoholic solution of FeCl3 ?
a) Benzoic acid b) Toluene c) Salicylic acid d) Nitrobenzene
869. Which of the following is wrong statements?
a) Ni(CO)4 , has zero oxidation number for Ni b) Ni(CO)4 , has oxidation number +4 for Ni
c) Ni is metal d) CO is gas
870. Which of the following represents a chelating ligand?
a) H2 O b) Cl− c) OH − d) DMG
871. The correct order of reactivity of PhMgBr with;

a) I > II > III

b) III > I > II
c) II > III > I
d) II > I > III
872. Which of the following will give maximum number of isomers?
a) [Co(NH3 )4 Cl2 ] b) [Ni(en)(NH3 )4 ]2+ c) [Ni(C2 O4 )(en)2 ] d) [Cr(SCN)2 (NH3 )4 ]+
873. CuCl reacts with KCN solution forming a complex. Coordination number of copper in the complex is:

P a g e | 69
 a) 2 b) 3 c) 4 d) 6
874. The terms stereoisomers, enantionmers and diastereomers will refer
a) Only to configurational isomers including geometric isomers
b) Only to configurational isomers
c) To both configurational as well as conformational isomers
d) To neither configuration nor conformational isomers
875. Aniline was acetylated. The product on nitration followed by alkaline hydrolysis gave:
a) 𝑜-nitroacetanilide b) 𝑜-and 𝑝-nitroaniline c) 𝑚-nitroaniline d) Acetanilide
876. The IUPAC name of the compound [CuCl2 (CH3 NH2 )2 is
a) Dichloro bis (dimethyl amine) copper(II) b) Dichloro bis (methyl amine) copper(II)
c) Dimethyl amine copper (II) chloride d) Bis (dimethyl amine ) copper (II) chloride
877. Which is the structure of compound 2-(1-cyclobutenyl)-1-hexene?

a) b)

c) d)

878. On explosion TNT gives:

a) CO + N2 + H2 + CH4 + CO2
b) CO + N2 + H2
c) CO2 + N2 + H2 O
d) CO + N2 + H2 O
879. Hexafluoroferrate(III) ion is an outer orbital complex. The number of unpaired electrons present in it is:
a) 1 b) 5 c) 4 d) Unpredictable
880. The EAN of Fe in K 3 [Fe(CN)6 ] is:
a) 36 b) 37 c) 38 d) 35
881. The IUPAC name of the compound

is
a) 4-methyl cyclopent-1-en-3-ol b) 5-methyl cyclopent-2-en-1-ol
c) 2-methyl cyclopent-4-en-1-ol d) 3-methyl cyclopent-1-en-2-ol
882. Which one amongst the following, exhibit geometrical isomerism?
a) [CoIII (NH3 )5 Br]SO4 b) CoIII [EDTA]1− c) [Cr III (SCN)6 ]3− d) [Pt II (NH3 )2 Cl2 ]
883. Chiral molecules are those which are
a) Superimposable on their mirror images b) Non-superimposable on their mirror images
c) Unstable molecules d) Capable of showing geometrical isomerism
884. At room temperature the eclipsed and the staggered forms of ethane cannot be isolated because
a) Both the conformers are equally stable b) They interconvent rapidly
There is a large energy barrier of rotation about d) The energy difference between the
c)
the 𝜎-bond conformers is large
885. A group of atoms can function as a ligand only when
a) It is a small molecule b) It has an unshared electron pair
c) It is a negatively charged ion d) It is a positively charged ion
886. The IUPAC name of Ni(CO)4 is:
a) Tetracarbonyl nickelate(0)

P a g e | 70
 b) Tetracarbonyl nickelate(II)
c) Tetracarbonyl nickel(0)
d) Tetracarbonyl nickel(II)
887. 2-methyl phenol is:
a) 𝑜-cresol b) Catechol c) 𝑝-cresol d) 𝑚-cresol
888. NH2 ∙ NH2 serves as:
a) Monodentate ligand b) Chelating ligand c) Bridging ligand d) Both (a) and (c)
889. For blasting purpose TNT is mixed with:
a) NH4 Cl b) NH4 NO3 c) NH4 NO2 d) (NH4 )2 SO4
890. During the debromination of 𝑚𝑒𝑠𝑜-dibromobutane, the major compound formed will be
a) 𝑐𝑖𝑠-2-butene b) 1-butene c) 𝑛-butane d) 𝑡𝑟𝑎𝑛𝑠-2-butene
891. The IUPAC name of K 2 [Cr(CN)2 O2 (O)2 (NH3 )] is
a) Potassium ammine dicyano dioxoperoxochromate b) Potassium ammine cyano
(VI) peroxodioxochromium(VI)
c) Potassium ammine cyano d) Potassium ammine cyano peroxodioxochromatic
peroxodioxochromium(V) (IV)
892. Benzene on reaction with a mixture of HNO3 and H2 SO4 followed by reaction of Cl2 /FeCl3 gives:
a) 3-chloro-1-nitrobenzene
b) 2-chloro-1-nitrobenzene
c) 4-chloro-1-nitrobenzene
d) A mixture of 2-chloro and 4-chloro-1-nitrobenzene
893. The number of isomeric forms in which [Co(NH3 )4 Cl2 ]+ ion can occur is:
a) 2 b) 3 c) 4 d) 1
894. Nitration of benzene is:
a) Nucleophilic substitution
b) Electrophilic substitution
c) Electrophilic addition
d) Nucleophilic addition
895. Reimer-Tiemann reaction involves a:
a) Carbonium ion intermediate
b) Carbene intermediate
c) Carbanion intermediate
d) Free radical intermediate
896. Which does not have a carboxyl group?
a) Picric acid b) Ethanoic acid c) Aspirin d) Benzoic acid
897. In Cannizaro’s reaction given below:

the slowest step is:

a) The transfer of hydride to the carbonyl group
b) The abstraction of proton from the carboxylic group
c) The deprotonation of PhCH2 OH
d)

898. The oxidation state of Ag in Tollens’ reagent is:

a) Zero b) +1 c) +2 d) +1.5
899. Hybridization of Fe in [K 3 Fe(CN)6 ] is
a) 𝑠𝑝3 b) 𝑑2 𝑠𝑝3 c) 𝑠𝑝3 𝑑2 d) 𝑑𝑠𝑝3
900. Which of the following is not isomeric with diethyl ether?
a) Methyl 𝑛-propyl ether b) Butan-1-ol
c) 2-methyl propan-2-ol d) Butan-2-one

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901. In the given conformation C2 is rotated about C2 − C3 bond anticlockwise by an angle of 120° then the
conformation obtained is

a) Fully eclipsed conformation b) Partially eclipsed conformation

c) Gauche conformation d) Staggered conformation
902. Crystal field stabilization energy for high spin 𝑑 octahedral complex is:
4

a) −1.8 ∆0 b) −1.6 ∆0 + 𝑃 c) −1.2 ∆0 d) −0.6 ∆0

903. Which kind of isomerism is exhibited by octahedral [Co NH3 4 Br2 ]Cl?
( )
a) Geometrical and ionisation
b) Geometrical and optical
c) Optical and ionisation
d) Geometrical only
904. The IUPAC name of the following compound is

a) 5-cyclopropyl pent-2-en-1-oic acid b) 6-cyclopropyl pent-2-en-1-oic acid

c) 5-cyclopropyl pent-1-en carboxylic acid d) 6-cyclopropyl pent-1-en carboxylic acid
905. Which of the following compounds will show a negative test with phenyl hydrazine?
a) Glucose b) Ethyl alcohol c) A cetaldehyde d) Benzophenone
906. Friedel-Craft’s reaction is not possible in:
a) C6 H5 OH b) C6 H5 C2 H5 c) C6 H5 NO2 d) C6 H5 CH3
907. The geometry of Ni(CO)4 and Ni(PPh3 )2 Cl2 are
a) Both square planar b) Tetrahedral and square planar respectively
c) Both tetrahedral d) Square planar and tetrahedral respectively
908. The number of isomers possible for square planar complex K 2 [PdClBr2 SCN] is:
a) 2 b) 3 c) 4 d) 6
909. The correct order for the wavelength of absorption in the visible region is
a) [Ni(NO2 )6 ]4− < [Ni(NH3 )6 ]2+ < [Ni(H2 O)6 ]2+ b) [Ni(NH3 )6 ]2+ < [Ni(H2 O)6 ]2+ < [Ni(NO2 )6 ]4−
c) [Ni(H2 O)6 ]2+ < [Ni(NH3 )6 ]2+ < [Ni(NO2 )6 ]4− d) [Ni(NO2 )6 ]4− < [Ni(H2 O)6 ]2+ < [Ni(NH3 )6 ]2+
910. The IUPAC name of CCl3 CH2 CHO is
a) Chloral b) 1,1,1-trichloropropanol
c) 2,2,2-trichloropropanol d) 3,3,3-trichloropropanol
911. The coordination number of Cu in [Cu(H2 O)4 ]2+ complex is
a) 2 b) 1 c) 3 d) 4
912. Among the following, the correct statement is
a) Prefixes are written before the name of compound
b) Suffixes are written after the name of compound
c) The IUPAC name is always written as a single word
d) All of the above
913. In which of the following 𝑝-electrons of the halogens are not involved in delocalisation?
a) Chlorobenzene b) Bromobenzene c) Allyl chloride d) Vinyl chloride
914. Which of the following does not have optical isomer?
a) [Co(en)(NH3 )2 Cl2 ]Cl b) [Co(en)2 Cl2 ]Cl c) [Co(NH3 )3 Cl] d) [Co(en)3 ]Cl3
915. Ethylene diamine is an example of

P a g e | 72
 a) Monodentate ligand b) Bidentate ligand c) Tridentate ligand d) Polydentate ligand
916. In chlorobenzene, the —Cl group:
a) Activates the benzene ring more via resonance effect than deactivating it via inductive effect
b) Deactivates the benzene ring more via inductive effect than activating it via resonance effect
c) Activates the benzene ring via resonance effect and deactivates it via inductive effect. Both these effects
are more evenly matched
d) None of the above
917. The 𝑅-isomer among the following are

a) (i) and (ii) b) (ii) and (iii) c) (iii) and (iv) d) (i) and (iii)
918. Which possesses tetrahedral shape (𝑠𝑝3 -hybridization of central atom)?
a) [Zn(NH3 )4 ]2+ b) [Ni(CO)4 ] c) [Cd(NH3 )4 ]2+ d) All are correct
919. The reaction,
Dil.NaOH
C6 H5 CHO + CH3 CHO → C6 H5 CH=CHCHO is called:
a) Benzoin condensation
b) Claisen condensation
c) Perkin’s reaction
d) Cannizaro’s reaction
920. Complexation is shown by:
a) Ag b) Au c) Cu d) All of these
921. AgO in Ag(II) complex which is:
a) Diamagnetic b) Paramagnetic c) Ferromagnetic d) Neutral
922. Acylation of benzene to produce aliphatic aromatic ketones is called:
a) Benzoin condensation
b) Hydroformylation
c) Friedel-Crafts reaction
d) None of these
923. The structure of the major product formed in the given reaction

a)

P a g e | 73
 b)

c)

d)

924. Chlorobenzene is prepared commercially by:

a) Grignard reaction b) Raschig process c) Wurtz - Fittig reaction d) Friedel-Crafts reaction
925. An aqueous solution of CoCl2 on addition of excess of concentrated HCl turns blue to formation of
a) [CoCl4 ]2− b) [Co(H2 O)2 Cl4 ]2− c) [Co(H2 O)2 2Cl4 ]2− d) [Co(H2 O)4 Cl2 ]
926. Which one of the following will not show geometrical isomerism?
a) [Cr(NH3 )4 Cl2 ]Cl b) [Co(en)2 Cl2 ]Cl c) [Co(NH3 )5 NO2 ]Cl2 d) [Pt(NH3 )2 Cl2 ]
927. When ethyl benzoate is hydrolysed with aqueous alkali, the products present in the medium are:
a) C6 H5 COOH, C2 H5 O− b) C6 H5 COO− , C6 H5 OH c) C2 H5 OH, C6 H5 COOH d) C6 H5 COO− , C2 H5 O−
928. The IUPAC name of

a) 2-carbamoyl hexanal b) 2-carbamoyl hex-3-en-1-al

c) 6-keto-2-methylhexanamide d) 5-formyl-2-methylpent-3-en-1-amide
929. Which of the following is more basic than aniline?
a) 𝑝-Nitroaniline b) Benzylamine c) Diphenylamine d) Triphenylamine
930. Name of some compounds are given below. Which one is not in IUPAC system?
CH3 − CH − CH − CH3
| | CH − C ≡ C − CH(CH3 )2
a) b) 3
OH CH3 4 methyl-2-pentyne
4-methyl-2-butanol
CH3
|
CH − CH2 − CH2 − CH − CH − CH2 CH3
c) d) 3
|
CH2 CH3
3-methyl-4-ethyl heptane
931. For which transition metal ions are low spin complexes possible?
a) Rh3+ b) Mn3+ c) Ru2+ d) All are correct
932. Which one is monodentate ligand?
a) F − b) NO−2 c) H2 O d) All are correct
933. Cyclic hydrocarbon molecule A has all the carbons and hydrogens in a single plane. All the carbon-carbon
bonds are of same length and less than 1.54 Å and more than 1.34 Å. The C— C—C bond angle will be:
a) 120 ͦ b) 180 ͦ c) 100 ͦ d) 109 ͦ28
934. Chlorine reacts with benzaldehyde to give:

P a g e | 74
 a) Benzyl chloride b) Benzal chloride c) Benzoyl chloride d) Chlorobenzene
935. Phenol is:
a) A base weaker than NH3
b) An acid stronger than carbonic acid
c) An acid weaker than carbonic acid
d) Neutral
936. Which one is example of octahedral complex?
a) Cu(NH3 )2+4 b) FeF63− c) Zn(NH3 )2+4 d) Ni(CN)2−
4
937. Which one of the following statement is correct?
a) Ferric ions give a deep green precipitate on adding potassium ferrocyanide solution.
b) On boiling a solution having K + , Ca2+ and HCO−
3 ions, we get a precipitate of K 2 Ca(CO3 )2
c) Manganese salt give a violet vortex test in reducing flame
d) From a mixed precipitate of AgCl and AgI, ammonia solution dissolves only AgCl
938. Which of the following fractions obtained in fractional distillation of coal-tar contains benzene and
toluene?
a) Light oil
b) Heavy oil
c) Middle oil
d) Green oil
939. The tetrahedral complexes have coordination number
a) 3 b) 6 c) 4 d) 8
940. The C—C bond length in benzene is ……than C—C bond length in alkenes.
a) Less b) More c) Equal d) None of these
941. Which are generally used for preparing derivative of aldehydes and ketones?
a) Hydroxylamine hydrochloride
b) 2,4-dinitrophenylhydrazine
c) Phenylhydrazinehydrochloride
d) All of the above
942. In the reaction,

The compounds (𝐴), (𝐵) and (𝐶) are the following:

a) Benzene, nitrobenzene and aniline
b) Benzene, dinitrobenzene and 𝑚-nitroaniline
c) Toluene, 𝑚-nitrobenzene and 𝑚-toluidine
d) Benzene, nitrobenzene and hydrazobenzene
943. En is an example of a:
a) Monodentate ligand b) Bidentate ligand c) Tridentate ligand d) Hexadentate ligand
944. The major product obtained when Br2 /Fe is treated with

a)

P a g e | 75
 b)

c)

d)

945. Phenol on treatment with dil. HNO3 at room temperature gives:

a)

b)

c)

d)

946. In an octahedral structure, the pair of d-orbitals involved in 𝑑2 𝑠𝑝3 hybridisation is

a) 𝑑𝑥 2−𝑦2 , 𝑑𝑧 2 b) 𝑑𝑥𝑧 , 𝑑𝑥 2−𝑦2 c) 𝑑𝑧 2 , 𝑑𝑥𝑧 d) 𝑑𝑥𝑦 , 𝑑𝑦𝑧
947. In which of the following ions has the metal atom EAN as 36?
a) [Fe(CN)6 ]4− b) [Fe(CN)6 ]3− c) [PbCl4 ]2− d) [Pd(CN)6 ]2−
948. The number of ions given by K[Pt(NH3 )5 Cl5 ] in aqueous solution is:
a) 2 b) 3 c) 4 d) 1
949. CuCl is sparingly soluble in H2 O but it dissolves in KCl solution due to the formation of:
a) K 2 (CuCl4 ) b) K 3 (CuCl4 ) c) K(CuCl2 ) d) None of these
950. A characteristics group test for phenolic gp. is:
a) Libermann’s nitroso reaction
b) Coupling with diazonium salt
c) 𝑎𝑞. FeCl3
d) All of the above
P a g e | 76
951. Write the IUPAC name of the compound

a) 5, 6-dimethyl bicyclo [2,2,1] heptane b) 2, 3-dimethyl bicyclo [2,2,1] heptane

c) 2, 3-dimethyl bicyclo [1,2,2] heptane d) 3, 4-dimethyl bicyclo [2,1,2] heptane
952. Choose the correct statement from the ones given below for two anilium in:

a) II is not an acceptable canonical structure because carbonium ions are less stable than ammonium ions
b) II is not an acceptable canonical structure because it is non-aromatic
c) II is not an acceptable canonical structure because the nitrogen has 10 valence electrons
d) II is an acceptable canonical structure
953. Which of the following statements is/are incorrect?
a) Metamerism belongs to the category of structural isomerism
b) Tautomeric structures are the resonating structures of a molecule
c) The violet colouration produce by a molecule with neutral ferric chloride solution indicates the
presence of enolic group in the molecule
d) Geometrical isomerism is not shown by alkenes
954. Gives are (i) cyclohexanol; (ii) acetic acid; (iii) 2, 4, 6-trinitrophenol; and (iv) phenol. In these the order of
decreasing acidic character will be:
a) (iii)>(ii)>(iv)>(i) b) (ii)>(iii)>(i)>(iv) c) (ii)>(iii)>(iv)>(i) d) (iii)>(iv)>(ii)>(i)
955. Phenol and benzoic acid can be distinguished by:
a) Aqueous NaHCO3 b) Aqueous NaNO3 c) Aqueous NaOH d) Conc. H2 SO4
956. The functional groups – OH, −COOH, −CHO, −OCH3 attached to a chiral carbon is in the preference order
a) OH > COOH > CHO > OCH3 b) OCH3 > OH > CHO > COOH
c) OCH3 > OH > COOH > CHO d) OCH3 > COOH > CHO > OH
957. The hypothetical complex chloro diaquatriammine cobalt(II) chloride can be represented as:
a) [CoCl(NH3 )3 (H2 O)2 ]Cl2 b) [Co(NH3 )3 (H2 O)Cl3 ] c) [Co(NH3 )3 (H2 O)2 Cl] d) [Co(NH3 )3 (H2 O)3 ]Cl3
958. Which is expected to be paramagnetic?
a) [Ni(H2 O)6 ]2+ b) [Ni(CO4 )] c) [Zn(NH3 )4 ]2+ d) [Co(NH3 )6 ]3+
959. The molecular formula of diphenyl methane

How many structural isomers are possible when one of the hydrogen is replaced by a chlorine atom?
a) 8 b) 7 c) 6 d) 4
960. Among the properties (A)reducing, (B) oxidising (C) complexing , the set of properties shown by CN− ion
towards metal species is
a) A, B b) B, C c) C, A d) A, B, C
961.

In the double bonds are

a) 𝑐𝑖𝑠, 𝑐𝑖𝑠 b) 𝑐𝑖𝑠, 𝑡𝑟𝑎𝑛𝑠
c) 𝑡𝑟𝑎𝑛𝑠, 𝑐𝑖𝑠 d) 𝑡𝑟𝑎𝑛𝑠, 𝑡𝑟𝑎𝑛𝑠

P a g e | 77
962. The reaction of toluene with Cl2 in presence of FeCl3 gives ‘𝑋’ and the reaction in presence of light gives
‘𝑌’.Thus, ‘𝑋’ and ′𝑌′ are:
a) 𝑋=benzal chloride; 𝑌 = 𝑜-chlorotoluene
b) 𝑋 = 𝑚-chlorotoluene; 𝑌 = 𝑝-chlorotoluene
c) 𝑋 = 𝑜-and 𝑝-chlorotouene; 𝑌=trichloro methyl benzene
d) 𝑋 =benzal chloride; 𝑌 = 𝑚-chlorotoluene
963. Among the following four compounds:
a) Phenol b) Methyl phenol c) 𝑚𝑒𝑡𝑎-nitrophenol d) 𝑝𝑎𝑟𝑎-nitrophenol
964. Which gives phthalic anhydride on reaction with hot, conc. H2 SO4 in presence of Hg?
a) Naphthalene b) Phenol c) 𝑝-xylene d) 𝑚-xylene
965. Cis-trans-isomerism is found in square planar complexes of the molecular formula: (𝑎 and 𝑏 are
monodentate ligands)
a) 𝑀𝑎4 b) 𝑀𝑎3 𝑏 c) 𝑀𝑎2 𝑏2 d) 𝑀𝑎𝑏3
966. Which ion produces a small crystal field splitting (a weak ligand field)?
a) I− b) Cl− c) F − d) All of these
967. Benzene undergoes substitution reaction more easily than addition because:
a) It has a cyclic structure
b) It has three double bonds
c) It has six hydrogen atoms
d) Of resonance
968. Isomers have essentially identical
a) Structural formula b) Chemical properties
c) Physical properties d) Molecular formula
969. Which of the following pair is not correctly matched?
a) Absorption peak for [Cr III (NH3 )6 ]3+ = 21680 cm−1
b) Effective atomic no. of Pt in [PtCl6 ]2− = 84
c) Crystal field stabilization energy of 𝑑2 in weak ligand field = (−)0.8 ∆0
d) Example of weak ligand field for 𝑑5 configuration = [MnII F6 ]4−
970. Aspirin (or acetyl salicylic acid) is obtained by action of CH3 COCl with:
a) Salicylic acid b) Phenol c) Benzaldehyde d) Aniline
971. CuCl dissolves in ammonia forming a complex. The coordination number of copper in the complex is:
a) 1 b) 2 c) 4 d) 6
972. IUPAC name of the following cycloalkane is

a) 8-methyl bicyclo [4,3,0] nonane b) 1-methyl bicyclo [4,3,0] nonane

c) 3-methyl bicyclo [4,3,0] nonane d) 4-methyl bicyclo [4,3,0] nonane
973. Schiff’s bases are formed when aniline is condensed with:
a) Phenols b) Aromatic aldehydes c) Aryl chlorides d) Aliphatic alcohols
974. Which of the following is not an organometallic compound?
a) Zeise’ s salt b) TEL c) Sodium ethoxide d) Ferrocene
975. Molecular formula C5 H12 O will show
a) Position
b) Optical isomerism
c) Functional isomerism
d) All of these
976. Both Co3+ and Pt 4+have a coordination number of six. Which of the following pairs of complexes will show
approximately the same electrical conductance for their 0.001 M aqueous solutions?
a) CoCl2 . 4NH3 and PtCl4 .4NH3 b) CoCl3 . 3NH3 and PtCl4 .5NH3
c) CoCl3 . 6NH3 and PtCl4 .5NH3 d) CoCl3 . 6NH3 and PtCl4 .3NH3

P a g e | 78
977. Which of the following is not an organometallic compound?
a) Sodium ethoxide b) Trimethyl aluminium
c) Tetraethyl lead d) Ethyl magnesium bromide
978. The number of water molecule(s) directly bonded to the metal centre in CuSO4 .5H2 O is
a) 1 b) 2 c) 3 d) 4
979. The formula of sodium nitroprusside is:
a) Na4 [Fe(CN)5 NO2 ] b) Na2 [Fe(CN)5 NO] c) NaFe[Fe(CN)6 ] d) Na2 [Fe(CN)6 NO2 ]
980. The IUPAC name of the compound
H2 N − CH − CH2 OH is
|
COOH
a) 2-amino-2-carboxy pentanol b) 1-amino-2-hydroxy propanoic acid
c) 1-hydroxy-2-amino-3-propanoic acid d) 2-amino-3-hydroxy propanoic acid
981. Which of the following complex species does not involve inner orbital hybridisation?
a) [CoF6 ]3− b) [Co(NH3 )6 ]3+ c) [Fe(CN)6 ]3− d) [Cr(NH3 )6 ]3+
982. The EAN of nickel in K 2 [Ni(CN)4 ] is:
a) 35 b) 34 c) 36 d) 38
983. The type of isomerism shown by, 6,6’-disitrodiphenic acid is
a) Conformational b) Optical c) Geometrical d) Functional
984. Which one of the following compounds forms benzoic acid on oxidation?
a) Chlorophenol b) Benzylchloride c) Chlorobenzene d) Chlorotoluene
985. Glycinato ligand is:

a)

b) Bidentate ligand
c) Two donor sites N and O−
d) All of the above
986. Which one is the most likely structure of CrCl3 ∙ 6H2 O, if 1/3 of total chlorine of the compound is
precipitated by adding AgNO3 to its aqueous solution?
a) CrCl3 ∙ 6H2 O
b) [Cr(H2 O)3 Cl3 ] ∙ (H2 O)3
c) [CrCl2 (H2 O)4 ] ∙ Cl ∙ 2H2 O
d) [CrCl(H2 O)5 ]Cl2 ∙ H2 O
987. Carbon in benzene undergoes 𝑠𝑝 2 -hybridization and the bond angle is 120 ͦ. The shape of benzene
molecule is:
a) Linear b) Planar c) Pyramidal d) Planar hexagonal
988. The example of coordination isomerism is
[Co (NH3 )6 ] [Cr(CN)6 ] and
a) b) [Co(NH3 )5 Br]SO4 and [Co(NH3 )5 SO4 ]Br
[Cr(NH3 )6 ] [Co(CN)6 ]
c) Co(NH3 )5 NO3 ]SO4 and [Co(NH3 )5 SO4 ]NO3 d) [Pt(NH3 )4 Cl2 ]Br2 and [Pt(NH3 )4 Br2 ]Cl2
989. Coordination compounds have great importance in biological systems. In this context which of the
following statement is incorrect?
a) Haemoglobin is the red pigment of blood and contains iron
b) Cyanocobalamin is B12 and contains cobalt
c) Chlorophylls are green pigments in plants and contains calcium
d) Carbocypeptidase-A an enzyme and contains zinc

P a g e | 79
990.

The IUPAC name of the given structure 𝐻 is

a) Diisohexane b) Isohexane c) 2, 2-dimethylbutane d) 2, 3-dimethylbutane
991. Aniline on treating with phosgene gives:
a) Phenyl isocyanate b) A secondary base c) A neutral substance d) A tertiary base
992. On boiling with conc. hydrobromic acid, phenylethylether will yield:
a) Phenol and ethyl bromide
b) Bromobenzene and ethanol
c) Phenol and ethane
d) Bromobenzene and ethane
993. Ammonia gas does not evolve from the complex FeCl3 . 4NH3 but is gives white precipitate with aqueous
solution of AgNO3 . Coordination number of central metal ion in above complex is six. Give IUPAC name of
the complex.
a) Ammonium trichloro triammine ferrum(III) b) Tetra ammine ferrum (III) chloride
c) Dichloro tetraammine ferrate (II) chloride d) Dichloro tetraammine ferrum (III) chloride
994. Nickel (Z=28) combines with a uninegative monodentate ligand 𝑋 − to form a paramagnetic
complex[Ni𝑋4 ]2− . The number of unpaired electron (s) in the nickel and geometry of this complex ion are
respectively
a) One , tetrahedral b) Two , tetrahedral c) One , square planar d) Two, square planar
995. Amongst the compounds given, the one that would form a brilliant coloured dye on treatment with NaNO2
in dil. HCl followed by addition to an alkaline solution of 𝛽-naphthol is:

a)

b)

c)

d)

996. Identify ‘𝑍’ in the reaction given below;

a) b) c) d)

997. A solution containing 2.675 g of CoCl3 .6NH3 (molar mass =267.5 g mol-1) is passed through a cation
exchanger. The chloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 g of AgCl
(molar mass=143.5 g mol−1 ). The formula of the complex is
(Atomic mass of Ag=108 u)

P a g e | 80
 a) [Co(NH3 )6 ]Cl3 b) [CoCl2 (NH3 )4 ]Cl c) [CoCl3 (NH3 )3 ] d) [CoCl(NH3 )5 ]Cl2
998. [Cr(H2 O)6 ] ion has 𝑑-electrons equal to:
3+

a) 2 b) 3 c) 4 d) 5
999. Enol form is more stable in
a) CH3 CHO b) CH3 COCH3
c) CH3 COCH2 COOC2 H5 d) Cyclohexanone
100 The coordination number of cobalt in [Co(en)2 Br2 ]Cl2 is:
0.
a) 2 b) 4 c) 6 d) 8
100 Which one readily accepts a proton?
1.
a) Acetylene b) Nitrobenzene c) Aniline d) Phenol
100 Identify ‘𝑍’ in the reaction;
2.

a)

b)

c)

d)

100 The number of σ and π-bonds in a molecule of benzene is:

3.
a) 6σ and 9π b) 9σ and 3π c) 12σ and 3π d) 6σ and 6π
100 The phenomenon of optical activity will be shown by:
4.

a) b) c) d)

P a g e | 81
100
5.

The correct name of the compound is

a) 1,3,4-trimethyldecaline b) 1,3,9-trimethyldecaline
c) 1,8,10-trimethyldecaline d) 1,3,10-trimethyldecaline
100 If NH4 OH is added to the (PtCl4 ) ion, the complex formed represents:
2−

6.
a) Zero dipole b) Finite dipole c) Infinite dipole d) All of these
100 Which one of the following will be able to show 𝑐𝑖𝑠-𝑡𝑟𝑎𝑛𝑠-isomerism?
7.
a) 𝑀 𝐴3 𝐵
b) 𝑀(𝐴𝐴′ ) 2

c) 𝑀𝐴2 𝐵𝐶𝐷
𝑀𝐴
d) 4
(𝐴𝐴′ is unsymmetrical bidentate ligand, 𝐴𝐵𝐶𝐷 are unidentate ligands.)
100 The coordination number of a metal in coordination compound is
8.
a) Same as primary valency b) Sum of primary and secondary valencies
c) Same as secomdary valency d) None of the above
100 The IUPAC name of K 4 [Ni(CN)4 ] is
9.
a) Tetrapotassium tetracyanonickelate (II) b) Potassium tetracyanonickel (II)
c) Potassium tetracyanonickelate (0) d) Potassium tetracyanonickelate (II)
101 Which of the following compounds shows optical isomerism?
0.
a) [Co(CN)6 ]3− b) [Cr(C2 O4 )3 ]3− c) [ZnCl4 ]2− d) [Cu(NH3 )4 ]2+
101 [C6 H5 ]2 Pd(SCN)2 ] and [(C6 H5 )2 Pd(NCS)2 ] are:
1.
a) Linkage isomers b) Coordination isomers c) Ionization isomers d) Geometrical isomers
101 Mark the correct statement
2.
a) Ethane has two conformations of which staggered conformation is more stable than the eclipsed
conformation
b) Ethane has an infinite number of conformations of which eclipsed conformation is more stable than the
staggered conformation
c) Ethane has an infinite number of conformation of which staggered conformation has the maximum
energy
d) Ethane has an infinite number of conformation of which the staggered conformation is possessed by
majority of the molecules at room temperature
101
3.

Of the following on heating with alkali followed with

acid hydrolysis?

P a g e | 82
 a)

b)

c)

d)

101 Which among the following will be named as dibromidobis (ethylene diamine) chromium (III) bromide?
4.
a) [Cr(en)2 Br2 ]Br b) [Cr(en)Br4 ]− c) [Cr(en)Br2 ]Br d) [Cr(en)3 ]Br3
101 Which one of the following complex is an outer orbital complex?
5. (Atomic no. Mn=25, Fe=24, Co=27, Ni=28)
a) [Fe(CN)6 ]4− b) [Mn(CN)6 ]4− c) [Co(NH3 )6 ]3+ d) [Ni(NH3 )6 ]2+
101 Benzene can be directly obtained from:
6.
a) CH≡CH
b) CH2=CH2 and butadiene
c) Chlorobenzene
d) All of the above
101 Chlorobenzene on treatment with Raney nickel or Al in presence of alkali gives:
7.
a) Benzene b) Chlorophenol c) Phenol d) None of these
101 The compound that undergoes decarboxylation most readily under mild condition is:
8.

a) b) c) d)

101 Which ion is paramagnetic?

9.
a) [Ni(NH3 )4 ]2+ b) [Ni(CO)4 ] c) [Co(NH3 )6 ]3+ d) [Ni(CN)4 ]2−
102 Which kind of isomerism is exhibited by octahedral [Co(NH3 )4 Br2 Cl]?
0.
a) Geometrical and ionization b) Geometrical only
c) Geometrical and optical d) Optical and ionisation
102 Resorcinol and conc. H2 SO4 in presence of phthalic anhydride produce a compound which is:
1.
a) A dye b) An antiseptic c) An indicator d) A detergent
102 Which of the following compounds shows optical isomerism?
2.

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 a) [Cr(C2 O4 )3 ]3− b) [Cu(NH3 )4 ]2+ c) [Co(CN)6 ]3− d) [ZnCl4 ]2−
102 The IUPAC name of [Co(NH3 )6 ]Cl3 is
3.
a) Hexamine cobalt (II) chloride b) Triammine cobalt (III) trichloride
c) Hexamine cobalt (III) chloride d) None of the above
102 In the following compounds, the order of acidity is:
4.

a) III > IV > I > II b) I > IV > III > II c) II > I > III > IV d) IV > III > I > II
102 Consider the following structure and choose the correct statements
5.

a) I and II have 𝑅-configuration b) I and III have 𝑅-configuration

c) Only III has 𝑆-configuration d) Both (a) and (c) are correct
102 Benzaldehyde, when heated with concentrated KOH solution, gives:
6.
a) C6 H5 CH2 OH
b) C6 H5 COOH
c) C6 H5 COOK
d) Mixture of C6 H5 COOK and C6 H5 CH2 OH
102 Write the IUPAC name of the compound
7.

a) Bicyclo-[2.2.2] octane-2,6-dione b) Bicyclo-[2.2.2] octane-3,5-dione

c) Bicyclo –[2.2] octane 2,6-dione d) Bicyclo [2,2] octane-3,5-dione
102 3-chloro-4-methyl benzene sulphonic acid on steam distillation gives:
8.
a) Toluene 𝑚-chloro benzene 𝑝-methyl benzene
b) c) d) 𝑜-chloro toluene
sulphonic acid sulphonic acid
102 The oxidation number of platinum in [Pt(NH3 )5 Cl]Cl3 is
9.
a) 2 b) 3 c) 4 d) 6
103 Which of the following is not an organometallic compound?
0.
a) C2 H5 ONa b) CH3 Mgl c) Tetraethyl tin d) KC4 H9
103 Which of the following pairs of compounds are enantiomers?
1.

a) b)

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 c) d)

103 Which complex has square planar shape 𝑑𝑠𝑝 2-hybridization?

2.
a) [Ni(CN)4 ]2− b) [Cu(NH3 )4 ]2− c) [PtCl4 ]2− d) All of these
103 The complex used as an anticancer agent is
3.
a) 𝑐𝑖𝑠-[PtCl2 (NH3 )2 ] b) Na2 CO3
c) 𝑡𝑟𝑎𝑛𝑠-[Co(NH3 )3 Cl3 ] d) 𝑐𝑖𝑠-K 2 [PtCl2 Br2 ]
103 Dyes are formed when diazonium salts react with:
4.
a) Phenols
b) Aldehydes
c) Ketones
d) Alcohols
103 Potassium ferrocyanide is a
5.
a) Complex salt b) Double salt c) Normal salt d) Mixed salt
103 The primary and secondary valencies of chromium in the complex ion, dichlorodioxalatochromium (III) ,
6. are respectively.
a) 3,4 b) 4,3 c) 3,6 d) 6,3
103
7.

a) Friedel-Craft’s reaction
b) Kolbe’s synthesis
c) Wurtz’s reaction
d) Grignard synthesis
103 The correct statement related to IUPAC nomenclature is
8.
a) If 2 or more chains of equal length are seen in the compound then the chain with minimum number of
side chains will be preferred
b) If double and triple bonds are at symmetrical positions in a compound then triple bond gets lower
preference
c) Correct IUPAC name of CH3 COC2 H5 is ethyl methyl ketone
d) As far as possible, the IUPAC name of a compound is written as a single word
103 Which of the following isomerism is shown by ethyl acetoacetate?
9.
a) Geometrical isomerism b) Keto-enol tautomerism
c) Enantiomerism d) Diastereoisomerism
104 The number of moles of ions given on complete ionisation of one mole of [Co(NH3 )6 ]Cl3 is/are
0.
a) 4 b) 3 c) 2 d) 1
104 The major products (𝑃, 𝑄) in the given reaction are:
1.

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 a)

b)

c)

d)

104 𝑝-nitrophenol is stronger acid than phenol because nitro group is:
2.
a) Electron withdrawing b) Electron donating c) Basic d) Acidic
104 Among the following group, which deactivates benzene ring for electrophilic substitution:
3.
a) Methyl b) Amino c) Hydroxyl d) Chlorine
104 Iron has lowest oxidation state in:
4.
a) Fe(CO)5
b) Fe2 O3
c) K 2 feO4
d) FeSO4 ∙ (NH4 )2 SO4 ∙ 6H2 O
104 The dihedral angle between the two methyl groups in Gauch conformation of 𝑛 butane is
5.
a) 120° b) 180° c) 45° d) 60°
104 Increasing order of acid strength among 𝑝-methoxyphenol, 𝑝-methylphenol and 𝑝-nitrophenol is:
6.
a) 𝑝-methylphenol < 𝑝-methoxyphenol < 𝑝-nitrophenol
b) 𝑝-methoxyphenol < 𝑝-methylphenol < 𝑝-nitrophenol
c) 𝑝-nitrophenol < 𝑝-methoxyphenol < 𝑝-methylphenol
d) 𝑝-nitrophenol < 𝑝-methylphenol < 𝑝-methoxyphenol
104 Total number of isomeric alcohols with formula C4 H10 O are
7.
a) 1 b) 2 c) 3 d) 4
104 What is the IUPAC name of Na2 [Fe(CN)5 NO]?
8.
a) Pentacyanonitroso sodium ferrate b) Pentacyanonitroso sodium ferrate(II)
c) Sodium pentacyanonitroso ferrate(II) d) Sodium pentacyanonitroso ferrate
104 Which of the following cations does not form an ammine complex with excess of ammonia?
9.
a) Ag + b) Cu2+ c) Cd2+ d) Na+

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105 In the complex K 2 [Fe(CN)6 ]
0.
a) The complex is high spin complex b) Both Fe atoms are in the same oxidation state
c) The coordination number of iron is 4 d) Both Fe atoms are in different oxidation state
105 The number of chiral carbon atoms present in the molecule
1.

a) 3 b) 4 c) 2 d) 1
105 The complex that doesn’t give a precipitate with AgNO3 solution
2.
a) [Co(NH3 )3 3Cl3 ] b) [Co(NH3 )6 ]Cl3 c) [Ag(NH3 )2 ]Cl d) [Cr(NH3 )4 Cl2 ]Cl
105 The IUPAC name of the given compound [Co(NH )
3 5 Cl]Cl2 is
3.
a) Penta amino cobalt chloride chlorate b) Cobalt penta ammine chloro chloride
c) Pentamine chloro cobalt (III) chloride. d) Penta amino cobalt (III) chlorate
105 Amongst Ni(CO)4 , [Ni(CN)4 ]2− and [NiCl4 ]2−
4.
a) Ni(CO)4 is diamagnetic,[NiCl4 ]2− and [Ni(CN)4 ]2− are paramagnetic
b) Ni(CO)4 and [NiCl4 ]2− are diamagnetic and [Ni(CN)4 ]2− is paramagnetic
c) Ni(CO)4 and [Ni(CN)4 ]2− are diamagnetic and [NiCl4 ]2− is paramagnetic
d) [NiCl4 ]2− and [Ni(CN)4 ]2− are diamagnetic and Ni(CO)4 is paramagnetic
105 Which aromatic acid among the following is weaker than simple benzoic acid?
5.

a) b) c) d)

105 Which statement is incorrect?

6.
a) Ni(CO)4 -tetrahedral, paramagnetic
b) [Ni(CN)4 ]2− -square planar, diamagnetic
c) Ni(CO)4 -tetrahedral, diamagnetic
d) [NiCl4 ]2− -tetrahedral, paramagnetic
105 Which of the following has asymmetric C-atom?
7.
Cl Br H Cl H Cl H D
| | | | | | | |
a) H − C − C − H b) H − C − C − Cl c) H − C − C − H d) CH3 − C − C − CH3
| | | | | | | |
H H H H H H Br OH
105 The IUPAC name of
8.

a) 1-phenyl-3-propanol b) 3-phenyl-1-propanol
c) 1-hydroxy-3-phenyl-propane d) None of the above

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105 The complexes [Co(NH3 )6 ][Cr(CN)6 ] and [Cr(NH3 )6 ][Co(CN)6 ] are the examples of which type of
9. isomerism?
a) Geometrical isomerism
b) Linkage isomerism
c) Ionization isomerism
d) Coordination isomerism
106 Racemic tartaric acid is optically inactive due to
0.
a) External compensation b) Internal compensation
c) Presence of plane of symmetry d) All of the above
106 Nitration of aniline is done in:
1.
a) Acidic medium
b) Alkaline medium
c) Neutral medium
d) In acidic medium by first converting it into acetanilide before nitration
106 A bridging ligand possesses:
2.
a) Polydentate or monodentate nature
b) Two or more donor centres
c) The tendency to get itself attached to two metal ions
d) All of the above
106 What is the neutralization equivalent of benzoic acid?
3.
a) 122 b) 61 c) 244 d) 488
106 𝑚-chlorobenzaldehyde on reaction with conc. KOH at room temperature gives:
4.
a) Potassium 𝑚-chlorobenzoate and 𝑚-hydroxy benzaldehyde
b) 𝑚-hydroxybenzaldehyde and 𝑚-chlorobenzylalcohol
c) 𝑚-chlorobenzylalcohol and 𝑚-hydroxy benzylalcohol
d) Potassium 𝑚-chlorobenzoate and 𝑚-chlorobenzyl alcohol
106 The oxidation number of Fe in brown ring [Fe(H2 O)5 NO]2+ is
5.
a) 0 b) +1 c) +2 d) +3
106 [Cr(H 2O 6 ) ]Cl3 (at. No. of Cr=24) has a magnetic moment of 3.83 BM. The correct distribution of 3𝑑-
6. electrons in the chromium of the complex:
a) 3𝑑1𝑥𝑦 , 3𝑑1𝑦𝑧 , 3𝑑1𝑥𝑧 b) 3𝑑1𝑥𝑦 , 3𝑑1𝑦𝑧 , 3𝑑1𝑧 2 c) (3𝑑1𝑥 2 −𝑦2 ), 3𝑑1𝑧 2 , 3𝑑1𝑥𝑧 d) 3𝑑1𝑥𝑦 , (3𝑑1𝑥 2−𝑦2 ), 3𝑑1𝑦𝑧
106 Excess of silver nitrate solution is added to 100 mL of 0.01 M pentaaqua chloro chromium (III) chloride
7. solution. The mass of silver chloride obtained in grams is [Atomic mass of silver is 108].
a) 287 ⨯ 10−3 b) 143.5 ⨯ 10−3 c) 143.5 ⨯ 10−2 d) 287 ⨯ 10−2
106 The total number of possible structural isomers of the compound [CuII (NH3 )4 ][Pt II Cl4 ] are:
8.
a) 3 b) 5 c) 4 d) 6
106 A similarity between optical and geometrical isomerism is that :
9.
a) Each gives equal number of isomers for a given compound
b) If in a compound one is present then so is the other
c) Both are included in stereoisomerism
d) They have no similarity

P a g e | 88
107 In [Ni(NH3 )4 ]SO4 , the valency and coordination number of Ni will be respectively
0.
a) 3 and 6 b) 4 and 4 c) 4 and 2 d) 2 and 4
107 C6 H5 CHO is different from aliphatic aldehyde in its reaction towards:
1.
a) Tollen’s reagent b) Schiff’s reagent c) NaHSO3 d) Fehling’s solution
107 Oxidation of naphthalene by acidic KMnO4 gives:
2.
a) Toluene b) Benzaldehyde c) Phthalic acid d) Benzoic acid
107 The number of possible theoretical conformations of 𝑛-butane are
3.
a) Two b) Three c) Four d) Infinite
107 Which is correct order for acidic nature of following acids?
4. (I) PhCOOH (II) o - NO2 C6 H4 COOH
(III) 𝑝 - NO2 C6 H4 COOH (IV) 𝑚- NO2 C6 H4 COOH
a) II > III > IV > I b) II > IV > III > I c) II > IV > I > III d) I > II > III > IV
107 Salicylic acid when treated with zinc dust gives:
5.
a) Phenol b) Salicyladehyde c) Benzene d) Benzoic acid
107 Action of PCl5 on salicylic acid produces:
6.
a) 𝑜-chlorobenzoyl
b) 𝑜-hydroxybenzoyl chloride
c) 𝑜-chlorobenzoic acid
d) None of the above
107 Which of the following species is most stable?
7.

a)

b)

c)
d)

107 Give the IUPAC name of the following

8.

a) 5-ethyl-4, 4-dimethyloctane b) 4-ethyl-5, 5-dimetyloctane

c) 3-ethyl-2-methyl-2-propyl hexane d) 4-ethyl-5-methyl, 5-propyl hexane
107 Which of the following reacts with KCN to form benzoin?
9.
a) C6 H5 CHO b) C6 H5 Cl c) C2 H5 Cl d) C6 H5 CH3
108 Which one is an organometallic compound in the following?
0.
a) C2 H5 ONa b) C2 H5 — S— S— C2 H5
c) Al2 (CH3 )6 d) Al(C6 H5 S)3
108 The formula of picramide is:
1.

P a g e | 89
 a) b) c) d)

108 An alkane forms isomers if minimum number of C-atom is:

2.
a) 1 b) 2 c) 3 d) 4
108 Which will form geometrical isomers?
3.
d) All of these
a) b) CH3 CH = NOH c)

108 Choose the option which show correct preferential order of groups among the following
4.
a) −COOH, −CHO, −OH, −NH2 b) −NH2 , −OH, CHO, −COOH
c) −COOH, −OH, −NH2 , −CHO d) −COOH, −NH2 , −CHO, −OH
108 The number of precipitable halide ions in [Pt(NH3 )Cl2 Br]Cl is:
5.
a) 2 b) 3 c) 4 d) 1
108 Which of the following is polycyclic compound?
6.
a) Xylene b) Cumene c) Styrene d) Naphthalene
108 Among acetic acid, phenol and 𝑛-hexanol, which of the compound(s) will react with NaHCO3 solution to
7. give sodium salt and CO2 ?
a) Acetic acid and phenol
b) Acetic acid
c) Phenol
d) 𝑛-hexanol
108 Nitrosobenzene can be isolated from nitrobenzene under:
8.
a) Metal and acid
b) Zn dust and NH4 Cl
c) Alkaline sodium arsenite
d) None of the above
108 Which of the following complexes is an outer orbital complex?
9.
a) [Fe(CN)6 ]4− b) [Co(NH3 )6 ]3+ c) [Ni(NH3 )6 ]2+ d) None of these
109 In which of the following complex ion, the central metal ion is in a state of 𝑠𝑝 𝑑 hybridisation?
3 2

0.
a) [Co(F6 )]3− b) [Co(NH3 )6 ]3+ c) [Fe(CN)6 ]3− d) [Cr(NH3 )6 ]3+
109 Give name of the complex, name should specify the position of ligands
1.

a) Bistransphosphinecarbonylchloroiridium [II] b) Carbonylchlorobistransphosphineiridium[III]

c) Carbonylchlorobistransphosphineiridium[I] d) Chlorocarbonylbistransphosphineiridium [I]

P a g e | 90
109 The function of anhydrous aluminium chloride in the Friedel-Crafts reaction is:
2.
a) To absorb water
b) To absorb hydrochloric acid
c) To produce an electrophile
d) To produce nucleophile
109 Coordination isomerism is caused by interchange of ligands between the
3.
a) Complex cation and complex anion b) Inner sphere and outer sphere
c) Low oxidation and higher oxidation states d) 𝑐𝑖𝑠 and 𝑡𝑟𝑎𝑛𝑠 structure
109 Which aldehyde is used in the manufacture of perfumes?
4.
a) Cinnamaldehyde b) Salicyladehyde c) Benzaldehyde d) None of these
109 Which of the following statements is not correct?
5.
a) A 𝑚𝑒𝑠𝑜 compound has chiral centres but exhibits no optical activity
b) A 𝑚𝑒𝑠𝑜 compound has no chiral centres and thus are optically inactive
A 𝑚𝑒𝑠𝑜 compound has molecules in which one half of molecule is superimposable on the other even
c)
through chiral centre is present in them
A 𝑚𝑒𝑠𝑜 compound is optically inactive because the rotation caused by one half of molecule is cancelled
d)
by the rotation produced by another half
109 The volume (in mL) of 0.1 M AgNO3 required for complete precipitation of chloride ions present in 30 mL
6. of 0.01 M solution of [Cr(H2 O)5 Cl]Cl2 , as silver chloride is close to
a) 3 b) 4 c) 5 d) 6
109 Benzene is a resonance hybrid mainly of two Kekule structures. Hence:
7.
a) Half of the molecules correspond to one structure, and half to the second structure
b) At low temperatures benzene can be separated into two structures
c) Two structures make equal contribution to resonance hybrid
d) An individual benzene molecule changes back and forth between two structures
109 Keto form is more stable in
8.
a) CH3 COCH2 COOC2 H5 b) CH3 COCH2 COCH3 c) CH3 COCH3 d) CH3 COCH2 COC2 H5
109 The oxidation state and effective atomic number(EAN) of cobalt (CoF6 ) are respectively
2−

9.
a) 3 and 36 b) 4 and 35 c) 4 and 37 d) 2 and 35
110 Benzamide on reaction with POCl3 gives:
0.
a) Aniline b) Chlorobenzene c) Benzylamine d) Benzonitrile
110 Which pair of carbon skeleton is an example of isomerism?
1.
C C
| |
a) C − C − C − C and C − C − C
|
C
C C
| |
b) C − C − C and C − C − C
| |
C C
P a g e | 91
 c)

C
|
d) C − C − C − C − C and C − C − C
|
C
110 Electrolytic reduction of nitrobenzene in weak acidic medium gives:
2.
a) Aniline
b) 𝑝-hydroxy aniline
c) Nitrobenzene
d) 𝑁-phenyl hydroxyl amine
110 In complexes, metal atom acts as:
3.
a) Lewis base b) Bronsted acid c) Bronsted base d) Lewis acid
110 When benzene is treated with concentrated HNO3 at room temperature it will give:
4.
a) CO2 and H2 O b) Nitrochlorobenzene c) Dark red colour d) Dinitrobenzene
110 Which of the following compounds exhibit linkage isomerism?
5.
a) [Co(en)3 ]Cl3 b) [Co(NH3 )6 ][Cr(CN)6 ] c) [Co(en)2 NO2 Cl]Br d) [Co(NH3 )5 Cl]Br2
110 The compound
6.

have IUPAC name as

a) Tricyclopropyl b) Tricyclopropane
c) 1,1’, 2’, 1’’-tercyclo propane d) None of the above
110 The most stable conformation of chlorohydrin at room temperature is
7.
a) Fully eclipsed b) Partially eclipsed c) Gauche d) Staggered
110 Among Ni(CO)4 , [Ni(CN)4 ] and [Ni(Cl)4 ] :
2− 2−

8.
a) [Ni(CO)4 ], [NiCl4 ]2− are diamagnetic and [Ni(CN)4 ]2− is paramagnetic
b) [NiCl4 ]2− , [Ni(CN)4 ]2− are diamagnetic and [Ni(CO)4 ] is paramagnetic
c) [Ni(CO)4 ], [Ni(CN)4 ]2− are diamagnetic and [NiCl4 ]2− is paramagnetic
d) [Ni(CO)4 ] is diamagnetic and [NiCl4 ]2− , [Ni(CN)4 ]2− are paramagnetic
110 The complex Hg[Co(CNS)4 ] is correctly named as:
9.
a) Mercury tetrathiocyanatocobaltate(II)
b) Mercury cobalt tetrasulphocyano(II)
c) Mercury tetrasulphocyanidecobaltate(II)
d) Mercury sulphocyanatocobalt(II)
111 Which of the following compounds is not coloured?
0.
a) Na2 [CuCl4 ] b) Na2 [CdCl4 ] c) K 4 [Fe(CN)6 ] d) K 3 [Fe(CN)6 ]

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111 Which one has square planar geometry?
1.
a) [CoCl4 ]2− b) [FeCl4 ]2− c) [NiCl4 ]2− d) [PtCl4 ]2−
111 Which exhibits highest molar conductivity?
2.
a) [Co(NH3 )6 ]Cl3 b) [Co(NH3 )5 Cl]Cl2 c) [Co(NH3 )4 Cl2 ]Cl d) [Co(NH3 )3 Cl3 ]
111 Coordination compounds have great importance in biological systems. In this context which of the
3. following statement is incorrect?
a) Chlorophyll is green pigment in plants and contain calcium.
b) Haemoglobin is the red pigment of blood and contains iron.
c) Cyanocobalamin is vitamin B12 and contains cobalt.
d) Carboxypeptidase-A is an enzyme and contains zinc.
111 Complex salt can be made by the combination of [CoIII (NH3 )5 Cl]𝑥 with
4.
a) Cl− b) 2Cl− c) PO3−
4 d) 2K +
111 Which of the following pairs represents linkage isomers?
5.
a) [Cu(NH3 )4 ][PtCl4 ] and [Pt (NH3 )4 ][CuCl4 ] b) [Pd(PPh3 )2 (NCS)2 ] and [Pd(PPh3 )2 (SCN)2 ]
c) [Co(NH3 )5 ]NO3 SO4 and [Co(NH3 )5 SO4 ]NO3 d) [PtCl2 (NH3 )4 ]Br2 and [PtBr2 (NH3 )4 ]Cl2
111 The reaction products of C H OCH + HI → is: ∆
6 5 3
6.
a) C6 H5 OH + CH3 I b) C6 H5 I + CH3 OH c) C6 H5 CH3 + HOI d) C6 H6 + CH3 OI
111 An aromatic amine (A) was treated with alcoholic potash and another compound (𝑌) when a foul smeling
7. gas was formed with formula C6 H5 NC. (𝑌) was formed by reacting a compound (𝑍) with Cl2 in the
presence of slaked lime. Compound (𝑍) is:
a) C6 H5 NH2 b) CH3 OH c) CH3 COCH3 d) CHCl3
111 Chlorine is most reactive in:
8.
a) CH3 Cl b) CH2=CHCl c) C6 H5 Cl d) C6 H5 CH2 Cl
111 The C—C bond order in benzene is close to:
9.
a) 1.5 b) 2.5 c) 3.0 d) 6.0
112 Mixture 𝑋 = 0.02 mole of [Co(NH3 )5 SO4 ]Br and 0.02 mole of [Co(NH3 )5 Br]SO4 was prepared in 2 L of
0. solution
1 L of mixture 𝑋 + excess AgNO3 ⟶ 𝑌
1 L of mixture 𝑋 + excess BaCl2 ⟶ 𝑍
Number of moles of 𝑌 and 𝑍 are
a) 0.01, 0.01 b) 0.01,0.02 c) 0.02, 0.01 d) 0.02, 0.02
112 Phenol can be converted into salicylic acid by:
1.
a) Etard’s reaction
b) Kolbe’s reaction
c) Reimer-Tiemann reaction
d) Both (b) and (c)
112 Fe2 (CO)9 is diamagnetic. Which of the following reasons is correct?
2.
a) Presence of one CO as bridge group
b) Presence of monodentate ligand
c) Metal-metal (Fe-Fe) bond in molecule
d) Resonance hybridization of CO

P a g e | 93
112 The formula of dichlorobis (urea) copper(II) is:
3.
a) [CuO = C(NH2 )2 ]Cl2
b) [CuCl2 {O = C(NH2 )}]
c) [Cu{O = C(NH2 )2 }Cl]Cl
d) [CuCl2 ][O = C(NH2 )2 ]H2
112 Which of the following facts about the complex [Cr(NH3 )6 ]Cl3 is wrong?
4.
The complex involves 𝑑2 𝑠𝑝3 hybridisation and isb) The complex is paramagnetic.
a)
octahedral in shape.
c) The complex is an outer orbital complex. d) The complex gives white precipitate with silver
nitrate solution.
112 The compounds P, Q and S were separately subjected to nitration using HNO3 /H2 SO4 mixture. The major
5. product formed in each case respectively, is:

a)

b)

c)

d)

112 Aromaticity of benzene is due to:

6.
a) Ring
b) Three double bonds

P a g e | 94
 c) Delocalisation of π-electrons
d) None of the above
112
7.
The IUPAC name of is
a) 2, 2, 4, 4-tetramethyl pentane b) 2, 2-dimethyl propane
c) 4-ethyl-3-methyl hex-3-ene d) Ethyl isopropyl ethene
112 Phenol is heated with a solution of mixture of KBr and KBrO3 . The major product obtained in the above
8. reaction is:
a) 2-bromophenol b) 3-bromophenol c) 4-bromophenol d) 2,4,6-tribromophenol
112 The coordination number of a central metal atom in a complex is determined by
9.
a) The number around a metal ion bonded by pi-bonds
b) The number of only anionic ligands bonded to the metal ion
c) The number of ligands around a metal ion bounded by sigma and pi-bonds both
d) The number of ligands around a metal ion bonded by sigma bonds
113 The true statement about benzene is:
0.
a) Because of d) Monosubstitution of
There are two types of There is a cyclic
unsaturation benzene benzene gives three
b) C—C bonds in benzene c) delocalisation of π-
easily undergoes isomeric products
molecule electrons in benzene
additions
113
1.
a) C6 H5 OH b) C6 H5 CH2 OH c) C6 H5 MgBr d) C6 H5 Cl
113 Which has highest paramagnetism?
2.
a) [Cr(H2 O)6 ]3+ b) [Fe(H2 O)6 ]2+ c) [Cu(H2 O)6 ]2+ d) [Zn(H2 O)6 ]2+
113 Which is not true ligands metal complex?
3.
a) Larger the ligand, the more stable is the metal-ligand complex
b) Highly charged ligand forms stronger bonds
c) Larger the permanent dipole moment of ligand, the more stable is the bond
d) Greater the ionization potential of central metal, the stronger the bond
113 [Co(NH3 )4 Cl2 ]NO2 and [Co(NH3 )4 Cl ∙ NO2 ]Cl] are
4.
a) Optical isomers b) Geometrical isomers c) Ionization isomers d) Linkage isomers
113 Acetophenone on oxidation by perbenzoic acid gives phenyl acetate. The reaction is named as:
5.
a) Baeyer-Villiger oxidation
b) Perkin’s reaction
c) Claisen condensation
d) Reformatsky reaction
113 Friedel-Craft’s reaction does not occur in case of:
6.
a) Toluene b) Benzene c) Naphthalene d) pyridine
113 One mode of a complex compound Co NH3 5 Cl3 gives three moles of ions on dissolution in water. One of
( )
7. the same complex reacts with two moles of AgNO3 solution to yield two moles of AgCl(𝑠). The structure of
the complex is
a) [Co(NH3 )3 Cl3 ] ∙ 2NH3 b) [Co(NH3 )4 Cl2 ] ∙ Cl ∙ NH3

P a g e | 95
 c) [Co(NH3 )4 Cl]Cl2 ∙ NH3 d) [Co(NH3 )5 Cl]Cl2
113 C6 H6 is a very good industrial solvent for:
8.
a) Oil b) Fat c) Rubber d) All of these
113 Salol is used as:
9.
a) Antiseptic b) Antipyretic c) Both (a) and (b) d) None of these
114 Presence of nitro gp. in benzene ring:
0.
a) Deactivates the ring for S𝐸 reaction
b) Activates the ring for S𝐸 reactions
c) Renders the ring basic
d) Deactivates the ring for SN reaction
114 Which of the following complexes will show geometrical as well as optical isomerism? (en =ethylene
1. diamine)
a) [Pt(NH3 )2 Cl2 ] b) [Pt(NH3 )2 Cl4 ] c) [Pt(en)3 ]4+ d) [Pt(en)2 Cl2 ]
114 The huge number of organic compounds is due to the fact that
2.
a) Tetravalency of carbon b) Carbon possesses property of catenation
c) Carbon compounds exhibits polymerisation d) Both (b) and ( c )
114 When nitrobenzene is treated with Br2 in presence of FeBr3 , the major product formed is 𝑚-
3. bromonitrobenzene. Statements which are related to obtain the 𝑚-isomer are:
a) The relative electron density on 𝑚𝑒𝑡𝑎 carbon is more than that of 𝑜𝑟𝑡ℎ𝑜 and 𝑝𝑎𝑟𝑎 positions
b) Loss of aromaticity when Br + attacks at the 𝑜𝑟𝑡ℎ𝑜 and 𝑝𝑎𝑟𝑎 positions and not at 𝑚𝑒𝑡𝑎 position
c) Easier loss of H + to regain aromaticity from the meta position than from 𝑜𝑟𝑡ℎ𝑜 and 𝑝𝑎𝑟𝑎 positions
d) None of the above
114 Which one of the following compounds when dissolved in water, gives a solution with pH more than 7?
4.
a) C6 H5 NH2 b) C6 H5 OH c) C2 H5 OH d) CH3 COCH3
114 Formula of ferrocene is:
5.
a) [Fe(CN)6 ]4− b) [Fe(CN)6 ]3+ c) [Fe(CO)5 ] d) [(C6 H5 )2 Fe]
114 What is the EAN of nickel in Ni(CO)4 ?
6.
a) 38 b) 30 c) 36 d) 32
114 One mole of the complex compound Co(NH3 )5Cl3 , gives 3 moles of ions on dissolution in water . One mole
7. of the same complex reacts with two moles of AgNO3 solution to yield two moles of AgCl(s). The structure
of the complex is
a) [Co(NH3 )5 Cl]Cl2 b) [Co(NH3 )3 Cl2 ]. 2NH3
c) [Co(NH3 )4 Cl2 ]Cl. NH3 d) [Co(NH3 )4 Cl]Cl2 . NH3
114 Which one of the following has largest number of isomers?
8. (R=alkyl group, en=ethylenediamine)
a) [Ru(NH3 )4 Cl2 ]+ b) [Co(NH3 )5 Cl]2+ c) [Ir(PR 3 )2 H(CO)]2+ d) [CO(en)2 Cl2 ]+
114 Which complex is likely to show optical activity?
9.
a) 𝑇𝑟𝑎𝑛𝑠-[Co(NH3 )4 Cl2 ]+ .
b) [Cr(H2 O)6 ]3+
c) 𝐶𝑖𝑠-[Co(NH3 )2 (en)2 ]3+
d) 𝑇𝑟𝑎𝑛𝑠-[Co(NH3 )2 (en)2 ]3+

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115 A square planar complex is formed by hybridization of which atomic orbitals?
0.
a) 𝑠, 𝑝𝑥 , 𝑝𝑦 , 𝑑𝑦𝑧 b) 𝑠, 𝑝𝑥 , 𝑝𝑦 , 𝑑𝑥 2−𝑦2 c) 𝑠, 𝑝𝑥 , 𝑝𝑦 , 𝑑𝑧 2 d) 𝑠, 𝑝𝑥 , 𝑝𝑦 , 𝑑𝑥𝑦
115 The IUPAC name of the compound
1. CH2 − CH − CH − CH2 COCl is
| | |
COCl COCl COCl
a) 1, 2, 3, 4-butanetetrachlorocarbonyl b) 1, 2, 3, 4-butanetetrachloroformyl
c) 1, 2, 4-butanetricarboxylic acid d) None of the above
115 Nitrobenzene can be prepared from benzene by using a mixture of conc. HNO3 and conc. H2 SO4 . In the
2. nitrating mixture HNO3 acts as a:
a) Base b) Acid c) Reducing agent d) Catalyst
115 In the compound lithium tetrahydroaluminate, the ligand is
3.
a) H b) H + c) H − d) None of these

P a g e | 97
Session: 2023-24
Time : 19:13:00 CHEMISTRY
Marks : 4612
9.COORDINATION COMPOUNDS

: ANSWER KEY :
1) b 2) b 3) c 4) c 173) c 174) a 175) c 176) c
5) b 6) b 7) c 8) a 177) c 178) b 179) a 180) b
9) c 10) b 11) c 12) c 181) c 182) b 183) a 184) b
13) d 14) d 15) c 16) c 185) b 186) d 187) c 188) d
17) b 18) d 19) b 20) b 189) d 190) b 191) b 192) a
21) a 22) c 23) d 24) d 193) d 194) d 195) a 196) d
25) d 26) d 27) d 28) d 197) b 198) b 199) c 200) c
29) b 30) a 31) d 32) d 201) b 202) b 203) d 204) a
33) d 34) c 35) a 36) b 205) b 206) d 207) d 208) c
37) d 38) c 39) c 40) d 209) b 210) c 211) c 212) b
41) a 42) c 43) c 44) d 213) c 214) c 215) b 216) a
45) b 46) d 47) b 48) d 217) a 218) d 219) b 220) a
49) b 50) d 51) d 52) d 221) d 222) c 223) c 224) d
53) a 54) b 55) b 56) c 225) a 226) b 227) c 228) c
57) a 58) c 59) a 60) b 229) b 230) d 231) c 232) a
61) c 62) c 63) a 64) d 233) b 234) b 235) d 236) d
65) c 66) d 67) c 68) a 237) b 238) d 239) a 240) b
69) d 70) d 71) c 72) a 241) a 242) a 243) b 244) b
73) a 74) b 75) d 76) b 245) a 246) c 247) b 248) a
77) c 78) b 79) c 80) d 249) c 250) d 251) d 252) c
81) d 82) d 83) c 84) d 253) c 254) a 255) a 256) b
85) b 86) b 87) c 88) c 257) b 258) c 259) d 260) d
89) d 90) a 91) c 92) a 261) d 262) d 263) c 264) a
93) c 94) b 95) a 96) c 265) b 266) d 267) b 268) b
97) b 98) c 99) b 100) c 269) b 270) c 271) d 272) a
101) d 102) c 103) d 104) b 273) d 274) b 275) c 276) d
105) d 106) a 107) b 108) c 277) d 278) c 279) c 280) b
109) a 110) a 111) b 112) c 281) a 282) c 283) b 284) b
113) b 114) a 115) d 116) c 285) b 286) c 287) b 288) d
117) c 118) a 119) b 120) b 289) c 290) b 291) d 292) b
121) a 122) d 123) d 124) d 293) b 294) c 295) c 296) a
125) d 126) b 127) a 128) d 297) c 298) b 299) d 300) b
129) b 130) c 131) d 132) b 301) a 302) b 303) b 304) b
133) c 134) d 135) d 136) d 305) a 306) b 307) b 308) b
137) c 138) d 139) b 140) a 309) b 310) c 311) b 312) c
141) b 142) a 143) a 144) c 313) c 314) a 315) a 316) c
145) a 146) d 147) d 148) a 317) b 318) b 319) d 320) d
149) a 150) c 151) a 152) b 321) b 322) d 323) d 324) b
153) b 154) c 155) a 156) b 325) d 326) c 327) b 328) d
157) d 158) b 159) b 160) c 329) b 330) d 331) d 332) a
161) b 162) c 163) d 164) a 333) d 334) c 335) b 336) d
165) a 166) a 167) b 168) b 337) d 338) d 339) b 340) d
169) b 170) b 171) c 172) b 341) b 342) c 343) a 344) c

P a g e | 98
345) b 346) c 347) a 348) b 549) a 550) b 551) b 552) b
349) c 350) b 351) a 352) b 553) d 554) b 555) a 556) d
353) d 354) b 355) b 356) d 557) a 558) d 559) c 560) c
357) b 358) d 359) d 360) d 561) a 562) b 563) c 564) a
361) d 362) b 363) b 364) a 565) c 566) c 567) c 568) a
365) a 366) a 367) c 368) d 569) c 570) c 571) b 572) d
369) a 370) d 371) c 372) a 573) b 574) c 575) d 576) a
373) d 374) d 375) c 376) c 577) a 578) b 579) b 580) b
377) c 378) a 379) d 380) c 581) d 582) b 583) c 584) d
381) d 382) a 383) d 384) c 585) b 586) c 587) b 588) d
385) d 386) c 387) a 388) c 589) a 590) c 591) b 592) c
389) c 390) c 391) b 392) a 593) c 594) d 595) b 596) b
393) c 394) a 395) c 396) d 597) c 598) a 599) b 600) c
397) a 398) d 399) b 400) d 601) a 602) b 603) d 604) b
401) a 402) b 403) c 404) a 605) d 606) d 607) d 608) b
405) b 406) d 407) b 408) b 609) c 610) d 611) b 612) b
409) a 410) b 411) c 412) d 613) a 614) c 615) a 616) a
413) b 414) a 415) a 416) b 617) d 618) c 619) c 620) c
417) d 418) c 419) c 420) c 621) c 622) c 623) a 624) c
421) c 422) a 423) c 424) b 625) a 626) b 627) d 628) c
425) d 426) c 427) a 428) b 629) a 630) c 631) a 632) b
429) d 430) d 431) a 432) a 633) c 634) b 635) a 636) a
433) c 434) c 435) a 436) b 637) c 638) c 639) c 640) b
437) a 438) b 439) a 440) b 641) d 642) b 643) a 644) c
441) b 442) c 443) b 444) d 645) c 646) a 647) c 648) d
445) a 446) a 447) a 448) a 649) a 650) c 651) a 652) d
449) b 450) d 451) b 452) c 653) d 654) a 655) d 656) d
453) c 454) d 455) a 456) d 657) b 658) a 659) b 660) c
457) a 458) a 459) c 460) c 661) d 662) c 663) b 664) b
461) c 462) b 463) b 464) d 665) c 666) c 667) c 668) c
465) a 466) b 467) a 468) d 669) d 670) a 671) c 672) a
469) c 470) c 471) c 472) d 673) a 674) b 675) b 676) a
473) d 474) c 475) b 476) a 677) c 678) c 679) c 680) b
477) b 478) b 479) c 480) c 681) a 682) a 683) c 684) b
481) b 482) a 483) a 484) c 685) c 686) d 687) b 688) b
485) a 486) a 487) d 488) c 689) b 690) b 691) a 692) c
489) b 490) a 491) c 492) a 693) a 694) a 695) d 696) a
493) d 494) d 495) a 496) a 697) a 698) b 699) b 700) d
497) c 498) c 499) a 500) d 701) d 702) c 703) b 704) a
501) a 502) d 503) b 504) d 705) d 706) d 707) c 708) d
505) b 506) d 507) a 508) d 709) b 710) b 711) b 712) c
509) b 510) d 511) b 512) a 713) a 714) b 715) d 716) d
513) d 514) c 515) b 516) a 717) c 718) b 719) c 720) c
517) a 518) c 519) a 520) a 721) b 722) c 723) c 724) b
521) b 522) c 523) d 524) a 725) a 726) c 727) c 728) b
525) a 526) d 527) d 528) d 729) b 730) c 731) a 732) c
529) d 530) c 531) a 532) b 733) b 734) a 735) a 736) b
533) b 534) a 535) b 536) d 737) b 738) a 739) b 740) d
537) a 538) a 539) b 540) c 741) b 742) d 743) a 744) d
541) c 542) d 543) a 544) b 745) d 746) d 747) b 748) c
545) d 546) c 547) d 548) c 749) c 750) c 751) b 752) a
P a g e | 99
753) b 754) b 755) d 756) c 957) a 958) a 959) d 960) c
757) b 758) b 759) b 760) b 961) c 962) c 963) a 964) a
761) d 762) b 763) a 764) d 965) c 966) d 967) d 968) d
765) c 766) a 767) b 768) c 969) b 970) a 971) b 972) a
769) b 770) d 771) a 772) b 973) b 974) c 975) d 976) c
773) a 774) d 775) d 776) b 977) a 978) d 979) b 980) d
777) b 778) c 779) b 780) d 981) a 982) b 983) b 984) b
781) d 782) a 783) c 784) d 985) d 986) c 987) d 988) a
785) c 786) b 787) a 788) c 989) c 990) d 991) a 992) a
789) b 790) c 791) c 792) c 993) d 994) b 995) c 996) c
793) b 794) b 795) c 796) d 997) a 998) b 999) c 1000) c
797) b 798) d 799) b 800) d 1001) c 1002) c 1003) c 1004) b
801) c 802) b 803) c 804) a 1005) b 1006) b 1007) c 1008) c
805) c 806) d 807) a 808) c 1009) c 1010) b 1011) a 1012) d
809) b 810) d 811) d 812) b 1013) b 1014) a 1015) d 1016) d
813) b 814) b 815) c 816) b 1017) a 1018) b 1019) a 1020) a
817) a 818) d 819) c 820) a 1021) a 1022) a 1023) c 1024) d
821) b 822) c 823) c 824) a 1025) a 1026) d 1027) a 1028) d
825) a 826) d 827) c 828) d 1029) c 1030) a 1031) b 1032) d
829) d 830) b 831) a 832) b 1033) a 1034) a 1035) a 1036) c
833) a 834) c 835) b 836) d 1037) a 1038) d 1039) b 1040) a
837) d 838) a 839) d 840) c 1041) c 1042) a 1043) d 1044) a
841) c 842) b 843) b 844) c 1045) d 1046) b 1047) d 1048) c
845) b 846) b 847) a 848) d 1049) d 1050) b 1051) c 1052) a
849) a 850) b 851) b 852) c 1053) c 1054) c 1055) b 1056) a
853) c 854) b 855) a 856) a 1057) d 1058) b 1059) d 1060) a
857) d 858) a 859) b 860) b 1061) d 1062) d 1063) a 1064) d
861) a 862) c 863) d 864) b 1065) b 1066) a 1067) a 1068) c
865) a 866) d 867) d 868) c 1069) c 1070) d 1071) d 1072) c
869) b 870) d 871) c 872) d 1073) d 1074) a 1075) d 1076) a
873) c 874) a 875) b 876) b 1077) d 1078) a 1079) a 1080) c
877) b 878) a 879) b 880) d 1081) c 1082) d 1083) d 1084) a
881) a 882) d 883) b 884) b 1085) d 1086) d 1087) b 1088) d
885) b 886) c 887) a 888) d 1089) c 1090) a 1091) c 1092) c
889) b 890) d 891) a 892) a 1093) a 1094) c 1095) b 1096) d
893) a 894) b 895) b 896) a 1097) c 1098) c 1099) b 1100) d
897) a 898) b 899) b 900) d 1101) a 1102) a 1103) d 1104) c
901) c 902) d 903) a 904) a 1105) c 1106) c 1107) c 1108) c
905) b 906) c 907) c 908) c 1109) a 1110) b 1111) d 1112) a
909) a 910) d 911) d 912) c 1113) a 1114) b 1115) b 1116) a
913) c 914) c 915) b 916) b 1117) c 1118) d 1119) a 1120) a
917) a 918) d 919) b 920) d 1121) d 1122) c 1123) b 1124) c
921) a 922) c 923) d 924) b 1125) c 1126) c 1127) c 1128) d
925) a 926) c 927) b 928) d 1129) d 1130) c 1131) c 1132) b
929) b 930) d 931) d 932) d 1133) a 1134) c 1135) a 1136) d
933) a 934) c 935) c 936) b 1137) d 1138) d 1139) a 1140) a
937) d 938) a 939) c 940) b 1141) d 1142) d 1143) a 1144) a
941) d 942) d 943) b 944) c 1145) d 1146) c 1147) a 1148) d
945) b 946) a 947) a 948) a 1149) c 1150) b 1151) a 1152) a
949) b 950) d 951) b 952) c 1153) c
953) b 954) a 955) a 956) c
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Session: 2023-24
Time : 19:13:00 CHEMISTRY
Marks : 4612
9.COORDINATION COMPOUNDS

: HINTS AND SOLUTIONS :

1 (b)
Follow IUPAC rules.
2 (b)
2CuSO4 + 10KCN
⟶ 2K 3 Cu(CN)4 + (CN)2
+ 2K 2 SO4 It has no unpaired electron and is diamagnetic
3 (c)
Follow definition of hydration isomerism. 4. [MnCl4 ]2− Oxidation state of Mn = +2
4 (c)
Urea, NH2 − C − NH2
||
O
shows tautomerism as
∴ It is paramagnetic as it has five unpaired
NH2 − C = NH
electrons.
|
8 (a)
OH
CN− is strongest field ligand. The spectrochemical
6 (b)
series order is:
C6 H5 ONa + 𝑅𝑋 ⟶ C6 H5 OR (Anisole)
I− < Br − < Cl− < F − < [C2 O4 ]2− < H2 O < py <
7 (c)
NH3 < en < NO2− < CN − < CO.
Diamagnetic substances have all paired electron.
10 (b)
1. [Fe(CN)6 ]3− Oxidation state of Fe=+3
[Co(NH3 )5 ONO]2+
Fe3+ 3𝑑 4𝑠 4𝑝
Penta ammine nitrito cobalt (III) ion.
↿ ↿ ↿ ↿ ↿
11 (c)
In [Ag(NH3 )2 ]Cl, Ag + contains 𝑑10 configuration.
As others contain unpaired electrons
12 (c)
CH3 gp., an 𝑜-and 𝑝-directing group attached in
nucleus activates the ring for S𝐸 reactions.
It has one unpaired electron and is paramagnetic. The presence of 𝑚-directing groups in benzene
nucleous simply decreases electron density at 𝑜-
2. [NiCl4 ]2− Oxidation state of Ni=+2 and 𝑝-, whereas no change in electron density at
𝑚-position is noticed.

It has two unpaired electrons and is paramagnetic

3. Ni(CO)4 Oxidation state of Ni=0 On the contrary 𝑜-and 𝑝-directing groups in

Ni (G.S.) 3𝑑 4𝑠 4𝑝 nucleus increases the electron density at 𝑜- and 𝑝-
⥮ ⥮ ⥮ ↿ ↿ position.
Thus, presence of 𝑜- and 𝑝-directing groups
provide seats for S𝐸 reactions or activates the ring,
whereas presence of 𝑚-directing groups does not
P a g e | 101
 activate the ring and thus, deactivate the ring for In Ni(CO)4 , Ni is in zero oxidation state. It has
S𝐸 reactions tetrahedral geometry but is diamagnetic. In
[Ni (CN)4 ]2− , Ni is in +2 oxidation state. It is 𝑑𝑠𝑝2
hybridised and have square planar shape. The
compound is diamagnetic.
24 (d)
[Co(CN)6 ]3− has 𝑑2 𝑠𝑝3-hybridisation and six 𝑑-
electrons are paired due to strong field ligand.
13 (d)
Thus no unpaired electron.
In both [Co(NH3 )6 ]3+ and [CoF6 ]3+ , Co is present
25 (d)
as Co3+ .
HBr ⟶ H + + Br −
Thus, the electronic configuration of Co is
7 2
27Co=[Ar] 3𝑑 , 4𝑠
6 0
27Co3+=[Ar]3𝑑 , 4𝑠

In case of [Co(NH3 )6 ]3+ , NH3 is a strong field

ligand, so pairing of electrons in 3d-orbital takes
place.
6 0
27Co3+=[Ar]3𝑑 , 4𝑠

Ether reacts with acid to give protonated ether.

]3+
In [CoF6 , F is a weak field ligand, thus doesn’t The next step involves nucleophilic attack by
cause pairing. Hence, halide ion with the displacement of weakly basic
6 0
27Co3+=[Ar]3𝑑 , 4𝑠 alcohol molecule.
26 (d)
Octahedral complex should have six hybridized
orbitals.
18 (d) 27 (d)
It is a test for primary amines. No doubt 2,4-
dimethylaniline is also primary amine but it does
not give test due to steric hindrance.
19 (b)
CN− is strong field ligand because it is an example Kolbe-Schmidt’s reaction.
of pseudohalide. Pseudohalide ions are stronger 29 (b)
coordinating ligands and they have the ability to The pair of electron present with nitrogen will not
form σ bond and π-bond. be available to be donated as H + will consume
20 (b) that one.
Higher the charge and smaller the size of ligand, 30 (a)
more stable is the complex formed It provides maximum number of ions (five) on
21 (a) ionization.
Trinitrobenzene is an explosive compound 31 (d)
formed during nitration of C6 H6 with fuming Follow Vorlander’s rule.
HNO3 . 32 (d)
22 (c) Organometallic compounds are those in which
A ligand is a species that is capable of donating an metal is linked directly with carbon. CH3 Li,
electron pair(s) to the central metal ion. The methyl lithium due to the presence of metal-
substances which are capable of donating an carbon bond, is an organometallic compound.
electron pair are called Lewis base, so a ligand is 33 (d)
also a Lewis base. The directive influence order is:
23 (d) O− > N𝑅2 > NH𝑅 > NH2 > OH > OCH3
≈ NHCOCH3 > CH3 > 𝑋

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34 (c)
Hybridisation Shape
𝑑𝑠𝑝2 Square planar
𝑠𝑝3 Tetrahedral
𝑠𝑝2 Trigonal planar

Hence, in tetrahedral complexes metal atom is 𝑠𝑝3

hybridised.
36 (b)
The number of ligands attached to the central
metal ion is called the coordination number.
So, coordination numbers of Fe in
[Fe (CN)6 ]4− , [Fe(CN)6 ]3− and [FeCl4 ]− are 6, 6
and 4 respectively. bis (benzoylacetonato) beryllium (II) complex
37 (d) 44 (d)
Tautomers may or may not be metamers Cl− is a weak ligand but Cl− cause the pairing of
38 (c) electron with large Pt 2+ and consequently give
EAN=(Atomic number – O. S + 2 × C. N. ) 𝑑𝑠𝑝2 hybridisation and square planar geometry.
Hence, EAN of Ni in [Ni(CN)4 ]2− = (28 − 2 + 45 (b)
2 × 4) = 34 It is a double salt;
39 (c) FeSO4 ∙ (NH4 )2 SO4 ∙ 6H2 O
Electron repelling nature of methoxy gp. facilitate ⟶ Fe2+ + 2SO2− 4 + 2NH4
+

the protonation of alcohol. 46 (d)

40 (d) Potassium ferrocyanide K 4 [Fe(CN)6 ] will ionize
[Ni(Cl)4 ]2− oxidation state of Ni is +2 as
So, configuration of 𝑁𝑖 2+ = K 4 [Fe(CN)6 ] ⇌ 4K + + [Fe(CN)6 ]4−
1𝑠 2 , 2𝑠 2 2𝑝6 , 3𝑠 2 3𝑝 6 3𝑑8 So, it will give five ions in solution
In Ni2+ 3𝑑 4𝑠 4𝑝 47 (b)
𝑐𝑖𝑠-platin is not a organimetallic compound
⥮ ⥮ ⥮ ↿ ↿
because it has no carbon- metal bonding
48 (d)
Follow mechanism of Reimer-Tiemann reaction.
49 (b)
Thus, due to 𝑠𝑝3 -hybridisation of Ni2+ in When 𝑛 =even number then for two identical
[NiCl4 ]2− , the shape of [NiCl4 ]2− is tetrahedral. ends, number of geometrical isomers
41 (a) = 2𝑛−1 + 2𝑛/2−1
This is Sandmeyer’s reaction. = 21 + 20
42 (c) =3
𝑝-nitrophenols are more acidic. 50 (d)
43 (c) The characteristics of coordination number.
Benzoylacetonato beryllium exhibit optical 51 (d)
isomerism as follows Aliphatic amines are more basic than aromatic
amines as the later are more stablised due to
resonance.
52 (d)
Aromatic hydrocarbons are called arenes with
general formula C𝑛 H2𝑛−6𝑦 , where 𝑛 ≮ 6 and y is
no. of cyclic rings. Benzene has one ring and 𝑛 =
6, 𝑖. 𝑒., no. of carbon atoms. Thus, general formula
is C6 H6 . All other aromatic hydrocarbons are
derivative of benzene.

P a g e | 103
53 (a) distillation because thiophene and C6 H6 both
Al(OC2 H5 )3 doesn’t have metal-carbon bond.(i.e., have nearly same b.p.
it is not an example of organometallic compound). 60 (b)
As cobalt is present as CO3+ and coordination
number of cobalt is 6, the molecular formula of
compound should be CoCl3 . 𝑦NH3 . Now, as it
gives a total of three ions when dissolved in
water, its structural formula must be
[CoCl(NH3 )5 ]Cl2
[CoCl(NH3 )5 ]Cl2 ⇌ [CoCl(NH3 )5 ]2+ + 2Cl−
Thus, only one Cl− ion is satisfying both primary
54 (b) and secondary valency of Co3+ in this compound.
In [Co(en)2 Cl2 ], four isomers are possible, two 61 (c)
The structure of alcohol is
geometrical isomers and two optical isomers.

Now, cis-isomer also show optical isomerism. Cis

isomer exists in enantiomeric form as it is
unsymmetrical. 62 (c)
Plane mirror The transition metal cations during complex
formation show 𝑑-𝑑 transition to give coloured
ions.
63 (a)
—CH3 gp. Shows +ve inductive effect and —OH
gp. shows resonance effect which increases the
electron density on C6 H6 ring.
64 (d)
It produces least number of ions in solution.
55 (b)
66 (d)
A carbon atom which is attached by four different
The process is known as aromatisation or
group is called an asymmetric carbon atom or
cyclization.
chiral centre
67 (c)
HOOC(CHOH)2 COOH has two asymmetric carbon
CH3
atom
|
CH3 − C − CH3
|
56 (c) CH3
Each π-electron is delocalised on each C-atom. 𝑛𝑒𝑜-pentane
57 (a) The structure shows that all the hydrogen atoms
An orange-red dye is formed with C6 H5 NH2. are attached to primary C-atoms hence these are
59 (a) primary hydrogens
Thiophene reacts more readily with H2 SO4 than 68 (a)
C6 H6 giving thiophene sulphonic acid which is Follow IUPAC rules.
water soluble and thus, can be separated from 69 (d)
C6 H6 . This can not be made by fractional

P a g e | 104
 x −2=0
x =+2
has no α-hydrogen. Hence, it will O.N of Cu=+2
not show tautomerism O.N of pt in [Pt(NH3 )2 Cl2 ]
70 (d) x +2 × 0 + 2 × −1 = 0
−
Both CN − and NO2 are strong field ligands. x −2=0
71 (c) x =+2
Prussian blue is O.N of Ni in [Ni (CO )4]
FeIII II I III II
4 [Fe (CN)6 ]3 or M Fe [Fe (CN)6 ], where M
I x +4⨯0=0
is Na, K, Rb, Li, Cs. x =0
73 (a) O.N of Fe in K 3 [Fe CN)6 ]
(
Co3+ , Fe3+ and Cr 3+ have 6𝑑-electrons, 5𝑑- 3⨯(+1)+ x +6⨯−1=0
electrons and 3𝑑-electrons respectively. Mn7+ has 3+ x −6=0
no 𝑑-electron. x =+3
74 (b) ∴ [Ni (CO )4 ] is zero valent compound.
All complexes of Co(III) have six ligands or 84 (d)
coordination number of six and thus, are The compounds given have following structures
octahedral in shape.
75 (d)
NH3 is weak as well as strong field ligand.
77 (c)
[Pt(NH3 )3 Br(NO2 )Cl]Cl
Triamminebromochloronitro platinum (IV)
chloride.
78 (b)
Both the carbon attached to O are part of aromatic
system.
79 (c)
Phenol is weak acid.
80 (d)
[EDTA]4− is a hexadentate ligand because it
donates six pairs of electrons to central metal
atom in a complex.
82 (d)
Ferrocene of bi-(cyclopentadienyl) iron is an
orange-crystalline solid. It is Fe(η5 – C5 H5 )2. The Out of these the (a) and (b) contain 5 C-atoms in
structure of ferrocene is regarded as sandwiche their longest possible chains hence, these could not
structure, in which the iron atom is sandwiched be the correct options for 2, 2, 3-trimethylhexane.
between two C5 H5 organic rings. The planes of Out of (c) and (d), the (c) is 2, 2, 5-trimethyl
the rings are parallel so that all the carbon atoms hexane and (d) is 2, 3, 3-trimethyl hexane
are at the same distance from the iron atom. 85 (b)
It is a π-bonded complex. Its structure is as Phenoxy benzene is diphenyl ether.
86 (b)
Ziegler-Natta catalyst is an organometallic
compound containing titanium. It is TiCl4 and
(C2 H5 )3 Al. It is used in the preparation of
83 (c) polyethylene.
[Cu(NH3 )4 ]SO4 330−350 K,1−2 atm
𝑛CH2 = CH2 → (−CH2 − CH2 −)𝑛
Oxidation number of TiCl4 +(C2 H5)3 Al
Cu ⇒ x +4 × 0 − 2 = 0 polyethylene

P a g e | 105
87 (c)
Al2 (C2 H5 )6 + TiCl4 is Zeigler Natta catalyst.
88 (c)
Transition metals have empty or half filled 𝑑-
orbitals to accept electron pairs. 𝑑 8 -configuration in strong ligand field gives 𝑑𝑠𝑝2
89 (d) hybridisation, hence square planar geometry.
The number of atom of the ligand that are directly
bound to the central metal atom or ion by Ni2+ + 4Cl− → [NiCl4 ]2−
coordinate bonds is known as the coordinate Here Ni2+ has 𝑑8 -configuration with CN− as weak
number of the metal or ion. It is actually the ligand.
number of chemical bonds which the ligand form
with the central metal atom or ion

𝑑 8 -configuration in weak ligand field gives

𝑠𝑝3 hybridisation, hence tetrahedral geometry.
Ni2+ with H2 O forms [Ni(H2 O)6 ]2+ complex and
H2 O is a weak ligand.
3d
⥮ ⥮ ⥮ ↿ ↿
90 (a)
Acyl chlorides or acid amhydrides are used in
acylation.
92 (a)
Zeise’s salt, K[PtCl3 (C2 H4 ) ]is a π-bonded
Therefore, [Ni(H2 O)6 ]2+ has octahedral geometry.
organometallic compound. Its structure is as
98 (c)
Benzene ring is activates for 𝑆𝐸 reaction by the
+𝐼effect as well as hyperconjugation of CH3 group
−Cl deactivates as −𝐼 effect predominates over
+𝑀 effect. −NO2 group deactivates ring by −𝐼
effect and −𝑀 effect.
100 (c)
Alcohols are neutral.
101 (d)
95 (a) —OH is 𝑜-and 𝑝-directing gp.
Follow IUPAC rules. 102 (c)
96 (c) [Fe(η5 − C2 H5 )2 ] is the organometallic compound
Since the complexes which has 𝜎 and 𝜋 bonds present
[PtCl2 (NH3 )4 ]Br2 and [PtBr2 (NH3 )4Cl2 have the 103 (d)
same molecular formula but on ionisation they BHC is C6 H6 Cl6 a saturated cyclic molecule.
give different ions, they exhibit ionisation 104 (b)
isomerism. The complexes can be written as follows
[PtCl2 (NH3 )4 ]Br2 ⇌ [PtCl2 (NH3 )4 ]2+ + 2Br − [Co(NH3 )6 ]Cl3 , [Co(NH3 )5 Cl]Cl2 , [Co(NH3 )4 Cl4 ]Cl
[PtBr2 (NH3 )4 ]Cl2 ⇌ [PtBr2 (NH3 )4 ]2+ + 2Cl− Hence, no. of primary valencies are 3, 2 and 1
97 (b) respectively
Ni2+ + 4CN − → [Ni(CN)4 ]2− 105 (d)
[Cr(NH3 )5 NO2 ]Cl2 compound shows linkage
Here Ni2+ has 𝑑8 -configuration with CN− as
isomerism because it has NO2 group which is
strong ligand.
ambidentate ligand.
It can be linked via N atom (— NO2 ) or via O atom
(—ONO) to form two different isomers.

P a g e | 106
106 (a)
In [𝑆𝑐(𝐻2 𝑂)6 ]3+ ,
Oxidation state of Sc is +3.
Sc (ground state)
3d 4s 4p 113 (b)
This is carbylamines reaction.
↿ ⥮

Sc 3+

∵ Sc 3+ has no unpaired electron.

∴ [Sc(H2 O)6 ]3+ is diamagnetic and colourless.
107 (b)
[𝑀𝐴5 𝐵] due to absence of symmetry of ‘B ’ ligand 114 (a)
cannot exist in the form of cis-trans isomer. An experimental fact depending upon the ability
108 (c) of the ligand to cause crystal field splitting (𝑖. 𝑒.,
Out of the 3 functional groups attached strength of ligand).
115 (d)
K 3 [Fe(CN)5 NO]
group
Potassium pentacyanonitrosyl ferrate (II).
will be the principal functional group and rest as
116 (c)
the substituents
The 𝑑-𝑑 excitation is responsible for colour of
Ti(H2 O)3+6 which has one unpaired electron.
117 (c)
The oxidation number of Fe in K 4 [Fe(CN)6 ]is +2.
119 (b)
109 (a) Both Ag and Au are extracted by complex
A transition metal complex absorbs visible light formation method.
only when it has unpaired electron. Ni2+ in 120 (b)
EAN = 24 − 3 + 2 × (6) = 33.
121 (a)
According to Werner’s theory, only those ions are
110 (a) precipitated which are attached to the metal
The directive influence order and tendency to atoms with ionic bonds and are present outside
release electron for 𝑜-and 𝑝-directing group is, the coordination sphere.
O−2 > N𝑅2 > NH𝑅 > NH2 > OH > OCH3 [Pt(NH3 )6 ]Cl4 ⇌ Pt(NH3 )4+6 + 4Cl
−

≈ NHCOCH3 > CH3 > 𝑋 122 (d)

111 (b) It is a fact.
(a) In MnO2 , FeCl3 oxidation states of Mn and Fe 123 (d)
are +4 and +3 respectively. In acidic solution, proton coordinate with
(b) In (MnO4 )− , CrO2 Cl2 oxidation states of Mn ammonia to form NH4+ . NH4+ does not act as ligand
and Cr are +7 and +6 respectively. because nitrogen atom has no lone pair of
(c) In [Fe(CN)6 ]3− , [Co(CN)3 ] oxidation states of electrons which it can donate to metal atom
Fe and Co are +3 and +3 respectively. 124 (d)
2− −
(d) [NiCl4 ] , [CoCl4 ] oxidation states of Ni and Disubstituted cyclic compounds and disubstituted
Co are +2 and +3 respectively. alkenes show geometrical isomerism
112 (c) 125 (d)
[M (abcd)] complex is square planar so will have Ag(NH3 )+ 2 has 𝑠𝑝-hybridization and linear
three geometrical isomers. complex.

P a g e | 107
127 (a)
The replacement of Cl is due to the formation of stable benzyl carbocation. Alternatively Cl is present in
side chain and thus replaced whereas Br is attached in benzene nucleus.

128 (d) 129 (b)

The electronic configuration of Ni in Replacement of N2 Cl by halogen atom of Cu𝑋 −
[Ni(CN)4 ]2− , [Ni(Cl)4 ]2− and Ni(CO)4 are: H𝑋 from benzene diazonium chloride is called
Ni2+ in [Ni(CN)4 ]2− : Sandmeyer’s reaction.
130 (c)
Optical isomerism is shown by the type
[𝑀(𝐴𝐴)𝑋2 𝑌2 ], [𝑀(𝐴𝐴)3 ], [𝑀(𝐴𝐴)2 𝑋2 ]
131 (d)
Ni2+ in [Ni(Cl4 ) ]2− :

Ni in [Ni(CO)4 ]: 1,2-dimethyl cyclobut-1-ene

132 (b)
HNO3 + 2H2 SO4 ⟶ NO+ − +
2 + 2HSO4 + H3 O .

134 (d)
(i) −NO2 can show linkage

P a g e | 108
 (iii) Also [Co(NH3 )4 (NO2 )2 ]Cl has its ionisation isomer as [Co(NH3 )4 NO2 Cl]NO2 .

135 (d)
Complex Hybridization
[Ni(CO)4 ] 𝑠𝑝3
[Ni(CO)4 ]2− 𝑑𝑠𝑝2
[CoF6 ]3− 𝑠𝑝3 𝑑2
[Fe(CN)6 ]3− 𝑑2 𝑠𝑝3
140 (a)
If magnetic moment is zero the species should not
136 (d) have unpaired electrons.
2, 4, 6-trinitrophenol is known as picric acid, an 141 (b)
explosive. Chlorophyll is a complex having Mg-atom.
137 (c) 142 (a)
It is a fact. Primary valency of metal is satisfied only by the
139 (b) anion. It is simply ionic valency. While secondary
OH gp., an 𝑜- and 𝑝-directing group activates ring valency is satisfied by ligands (which can give a
for reactions. The presence of 𝑚-directing groups lone pair of electron). The ligands satisfying
in benzene nucleous simply decreases electron secondary valency, are always written in
density at 𝑜- and 𝑝-, whereas no change in coordination sphere. This concept was given by
electron density at 𝑚-position is noticed. Werner.
In K 3 [Fe(CN)6 ], the CN − ions satisfy both the
primary as well as secondary valency of Fe3+ ion.
143 (a)
The following isomers the alkene have
(i) CH3 − CH2 − CH = CH2
On the contrary 𝑜-and 𝑝-directing groups in (ii) CH3 − CH = CH − CH3
nucleus increases the electron density at 𝑜- and 𝑝-
position.
Thus, presence of 𝑜- and 𝑝-directing groups
provide seats for S𝐸 reactions or activates the ring,
whereas presence of 𝑚-directing groups does not
activate the ring and thus, deactivate the ring for
S𝐸 reactions
CH3
|
(v) CH3 − C = CH2
145 (a)

P a g e | 109
 According to postulates of Werner’s theory for 153 (b)
coordination compounds, metal atoms exhibit two Diamethyl glyoxime forms a colour complex with
types of valencies i.e., primary valency and nickel
secondary valency. The primary valency is 154 (c)
ionisable whereas the secondary valency is non- BF4− has 𝑠𝑝3 -hybridisation and tetrahedral.
ionisable. 155 (a)
146 (d) Oxidation state of iron in haemoglobin is +2.
[Fe(CN)6 ]4− is diamagnetic (Fe2+ has 3𝑑6 156 (b)
configuration and the 6 electron pairs up in three 5. Geometrical isomers have same structural
𝑑-orbitals followed by 𝑑2 𝑠𝑝3 -hybridisation). formula but differ in spatial arrangement
[Cr(NH3 )6 ]3+ is paramagnetic (Cr 3+ has 3𝑑3 of groups.
configuration. Hybridisation is 𝑑 2 𝑠𝑝3 . Due to 3
6. Different arrangement of atoms or groups
unpaired electrons it is paramagnetic)
[Cr(CO)6 : Cr(Z = in three dimensional space results in two
optical isomers which are image of each
25): [Ar] 4𝑠 , 3𝑑5 .
18 1
other.
The one 4𝑠-electron pairs up with five 3𝑑-
electrons in three 𝑑-orbitals. This is followed by
𝑑2 𝑠𝑝3 -hybridisation to give octahedral complex.
No unpaired electron and hence complex is
diamagnetic.
Fe(CO)5 ∶ Fe(Z =
26): [Ar] 4𝑠 , 3𝑑6 .
18 2

The six electrons in 𝑑-subshell pairs up in three 𝑑-

orbitals. This is followed by 𝑑2 𝑠𝑝3 -hybridisation
to give octahedral geometry with one vacant
hybridised orbital. The resulting shape of the
complex is square based pyramid. As there is no
unpaired electron, the complex is diamagnetic.
147 (d)
A modified or extended Friedel-Crafts reaction.
148 (a)
cis[Co(en)2 Cl2 ]Cl is optically active hence, it will
give a pair
Therefore, number of geometrical isomers, optical
isomers and total number of isomers are 2, 2 and
3 respectively.

157 (d)
149 (a) Hetero aromatics show aromatic nature due to
∆𝑡 is roughly 4/9 times to ∆0. 4𝑛 + 2π electrons.
150 (c) 158 (b)
Follow IUPAC rules. CN− ligand has strong ligand field because of
151 (a) higher value of ∆.
Alkanes having less than four carbon atoms in 159 (b)
basic chain will not show chain isomerism % Enantiomeric excess
observed specific rotation
152 (b) = × 100
specific rotation of pure enantiomer
3/4
Observed specific rotation = 100 × (+16°) × 100
= +12°
160 (c)
3 mole of Br2 are needed.
P a g e | 110
 Follow IUPAC rules. It is Friedel-Crafts reaction.
161 (b) 174 (a)
[(C6 H5 )3 P)3 RhCl] or [(Ph3 P)3 RhCl] is a Resonance in phenoxide ion makes it more stable.
Wilkinson’s catalyst, the most widely used of all More stable is ion less stable is phenol or more is
catalysts for homogeneous hydrogenation. acidic nature.
162 (c) 175 (c)
Halogens attack double bond of C6 H6 in presence Triethylenediamine cobalt(III) chloride is
of light. In absence of light as well as in presence [Co(NH2 CH2 CH2 NH2 )3 ]Cl3 ; NH2 CH2 CH2 NH2 is
of only AlCl3 , SE reactions are noticed. bidentate ligand and thus, coordination no. =
163 (d) 3 × 2 = 6.
[Pt(NH3 )6 ]Cl4 complex gives five ions in the 177 (c)
solution. CO is a neutral ligand, so the oxidation state of
[Pt(NH3 )6 ]Cl4 ⇌ [Pt(NH3 )6 ]4+ + 4Cl− metal in metal carbonyls is always zero.
164 (a) [Ni(CO)4 ]
The EAN for Cu in [Cu(NH3 )4 ]2+ is 35 and not 36, x+(0×4)=0
the next inert gas at. No. x =0
165 (a) 178 (b)
1 × 3 + a + 6 × (−1) = 0, 𝑎 = +3 FeCl3 + Cl2 ⟶ FeCl− 4 + Cl
+

166 (a) 179 (a)

In NaOC2 H5 , Na is attached to O-atom. [Ni(CN)4 ]2− has 𝑑𝑠𝑝2-hybridization while
167 (b) [Ni(Cl4 )2− ] and [Ni(CO4 )] have 𝑠𝑝3 -hybridization.
In [Mn(H2 O)6 ]2+ , Mn is present as Mn2+or Mn 180 (b)
(II), so its electronic configuration ∆
3C2 H2 → C6 H6
182 (b)
=1𝑠 2 , 2𝑠 2 2𝑝6 , 3𝑠 2 3𝑝6 3𝑑5 Cr 2+ , Mn2+ , Fe2+ and Ni2+ have 4, 5, 4 and 2
3𝑑 4𝑠 4𝑝 unpaired electrons respectively.
↿ ↿ ↿ ↿ ↿ 183 (a)
4𝑑
It is a reason for the fact.
186 (d)
In [Mn(H2 O)6 ]2+ , the coordination number of Mn
O
is six, but in presence of weak field ligand, there
||
will be no pairing of electrons in 3𝑑. So, it will
CH3 CH2 − C − CH2 CH3 ↔
form high spin complex due to presence of five
(keto form)
unpaired electron.
OH
In [Mn(H2 O)6 ]2+
|
CH3 − CH = C − CH2 CH3
(enol form)
187 (c)
170 (b) Non-polr part C6 H5 —shows more hydrophobic
Due to aromatic nature; C6 H5 CH2 OH is exception nature.
and does not burn with sooty flame. 189 (d)
171 (c) All involve 𝑑2 𝑠𝑝3-hybridization.
EDTA (Ethylenediaminetetraacetic acid) 191 (b)
Aromatic amines are less basic than aliphatic
amines. Also presence of electron attracting group
decreases the basic character of aromatic amines.
It is
192 (a)
hexadentate (6 electron pairs)
Follow IUPAC rules.
that’s why for octahedral complex only one EDTA
193 (d)
is required.
173 (c)
P a g e | 111
 All are weak field ligands and thus, give high spin N-bromo-N-chloro ethanamide
complex. 206 (d)
194 (d) It is condensation reaction.
Tartaric acid is

195 (a)
β4 for [ML4 ]2− can be written as
[𝑀𝐿 ]2−
4 13
β4=[𝑀2+][𝐿− ]4 = 2.5 ⨯ 10

The overall formation equilibrium constant can be

written as
[𝑀𝐿 ]2−
4
k=[𝑀2+ ][𝐿−1 ]4

k= β4 = 2.5 ⨯ 1013
196 (d)
[Cr(NH3 )4 Cl2 ]+
Let oxidation state of Cr =x
NH3=0
207 (d)
Cl=−1
Due to more canonical forms.
Net charge =+1
208 (c)
∴ [Cr(NH3 )4 Cl2 ]+ P2O5
x +4×0+2(−1)=+1 2C6 H5 SO2 . OH → (C6 H5 SO2 )2 O
∴ x =+3 209 (b)
197 (b) Isomeric substances that differ only in the
Phenols are acidic; alcohols are neutral. arrangement of carbon atoms forming the base
198 (b) chain are known as chain isomers
2 × 𝑎 + 4 × (−2) + 2 × 0 + 2 × 0 = −2, ∴𝑎 CH3 CH2 CHCH2 CH3
= +3 |
199 (c) Cl
CH3 MgI (Grignard reagent) is an organometallic and
compound due to C— Mg bond. Cl
200 (c) |
Effective atomic number =electrons in Cr 3+ CH3 − CH2 − C − CH3
+electrons form 6NH3 ligands. |
=21+6×2=33 CH3
203 (d) If the compound with the same molecular formula
Hückel rule for aromaticity suggests that an differ in the position of the same functional group
aromatic compound must possess (4𝑛 + 2)π- on the identical base chain the compounds are
electrons, where 𝑛 = 0, 1,2…, etc., as well as π- called position isomers
electrons cloud should embrace all the carbon 210 (c)
atoms of the cyclic systems. In K 3 [Fe(CN)6 ], the ligands are negative which is
204 (a) present in coordination spheres shows a dual
C6 H5 OH + Zn dust ⟶ C6 H6 . behavior. It may satisfied both primary and
205 (b) secondary valencies while, neutral ligand satisfied
only secondary valencies
211 (c)

P a g e | 112
 A number of transition metals form polymetallic All these are used to explain 𝑜-, 𝑝- directing
carbonyls. nature of —CH3 gp.
212 (b) 225 (a)
𝑁𝑖 ∶ 3𝑑 8 4𝑠 2 𝑁𝑖 2+ ∶ 3𝑑8 The separation of racemic mixture back into 𝑑
Since, Cl is a weak field ligand, it doesn’t cause and 𝑙 isomers is known as resolution. It can be
paring of electron. done by
(I) mechanical method
⥮ ⥮ ⥮ ↿ ↿ (II) bio-chemical method using enzymes
(III) chemical method (salt formation)
3𝑑 8 4𝑠 4𝑝 227 (c)
Number of unpaired electrons, n=2 Alkanes are not dissolved in H2 SO4 .
μ = √𝑛(𝑛 + 2) = √2(2 + 2)BM = √8 BM = 228 (c)
2.82 BM Monomeric form of iron carbonyl is Fe(CO)5 .
213 (c) 229 (b)
Follow IUPAC rules. Molecular formula of naphthalene is C10 H8 .
214 (c) 230 (d)
The reaction occurs via., electrophilic addition It is clear from the chemical formulae that Ag is
following Markownikoff’s rule,. central metal atom and ligands are 2 ammonia
molecule
Hence, compound is [Ag(NH3 )2 ]Cl
231 (c)
For [M abcd ]square planar complex, the number
of possible geometrical isomers is three which is
215 (b) obtained by fixing the position of one of the
C6 H5 OH is also called carbolic acid. ligands say a while the other ligands b, c and d
216 (a) are placed trans to it.
232 (a)
Follow exceptions of Vorlander’s rule.
233 (b)
Follow IUPAC rules.
234 (b)
Coordination number is equal to total number of
ligands in a complex
It is easier to do nucleophilic substitution on alkyl 235 (d)
halides than on aryl halides. Chair and boat conformations of cyclohexane
217 (a) differ in energy by 44 kJ/mol
Oxidation state of Co in K [Co(CO)4 ]is
+1 + 𝑥 + 4 × 0 = 0
𝑥 = −1(For co)
218 (d)
Bakelite is formed as a result of condensation of 236 (d)
HCHO and phenol. Ligands form coordinate bond with central atom
219 (b) or ion and donate electron pair.
Based on spectrochemical series , ligands 238 (d)
arranged in increasing order of crystal field
strength are as
NH3 < 𝑒𝑛 < CN − < 𝐶O
222 (c) This is Gattermann-Koch reaction -CHO gp. in
Follow mechanism of sulphonation on xylene. C6 H6 nucleus.
224 (d) 239 (a)

P a g e | 113
 [Cr(NH3 )6 ]3+ has three unpaired electrons. The compound is substituted octane, it has
Electronic configuration of Cr 3+ in Cr(NH3 )6 is: branches at carbon-3, carbon-4, carbon-5. The
name is
4-sec-butyl-5-ethyl-3-metyl octane
248 (a)
The presence of 𝑚-directing groups in benzene
×× Electron pair donated by NH3 .
nucleous simply decreases electron density at 𝑜-
240 (b)
and 𝑝-, whereas no change in electron density at
𝑚-position is noticed.

The above compound has chiral centre

Hence, it can exhibit optical isomerism while
geometrical isomerism is not possible due to
presence of identical groups on double bonded On the contrary 𝑜-and 𝑝-directing groups in
carbon atom nucleus increases the electron density at 𝑜- and 𝑝-
241 (a) position.
It has no unpaired electron. Thus, presence of 𝑜- and 𝑝-directing groups
242 (a) provide seats for S𝐸 reactions or activates the ring,
COOH whereas presence of 𝑚-directing groups does not
| activate the ring and thus, deactivate the ring for
H − C − OH S𝐸 reactions
| plane of symmetry
H − C − OH
|
COOH
𝑀𝑒𝑠𝑜 tartaric acid is optically inactive due to the
presence of molecular symmetry. It I optically 249 (c)
inactive due to internal compensation, 𝑖𝑒, the CuF2 is blue coloured crystalline solid.
effect of one half of the molecule is neutralized by 250 (d)
other Different ionization gives different colour.
243 (b) 251 (d)
Smaller is cation, more is effective nuclear charge, The complex has coordination number of six
more is the tendency to attract electron pair from which is found in octahedral complex.
ligands. 252 (c)
245 (a) BF3 has incomplete octet and is Lewis acid; it
Presence of 𝑜-, 𝑝-directing gp. facilitates the SE cannot donate electron pair.
reactions. 253 (c)
246 (c) Methyl thiomethyl group is inserted at 𝑜𝑟𝑡ℎ𝑜
K 2 S2 O8 gives quinol; KMnO4 gives mesotartaric position by heating phenol with dimethyl
acid. sulphoxide and pyridine −SO3 /(CH3 CO)2 O .
254 (a)
Ni(CN)2−4
Ni(G. S.) 3𝑑 4𝑠 4𝑝
⥮ ⥮ ⥮ ↿ ↿ ⥮
247 (b)

Ni2+ 3𝑑 4𝑠 4𝑝
⥮ ⥮ ⥮ ↿ ↿

P a g e | 114
 ⥮ ⥮ ⥮ ↿ ↿ ⥮

Ni(CN)2−4
Ni is in +2 oxidation state.
255 (a)
4-methyl benzene sulphonic acid is stronger than
acetic acid thus it will release acid from sodium
acetate.
256 (b)
Phthalein test is characteristics of phenols.
257 (b)
[Cr(NH3 )6 ][Co(CN)6 ] is isomer to
Ni(CO)4
[Cr(CN)6 ][Co(NH3 )6 ], i.e., ligands are partially
Oxidation state of Ni is zero
changes in complex anion and complex cation.
Ni(0) 3𝑑 4𝑠 4𝑝
259 (d)
Aspirin is acetyl salicylic acid.

Thus, only aspirin has carboxylic group.

260 (d) 269 (b)

Replacement of H-atom of ring usually takes place
following S𝐸 reaction mechanism.
261 (d)
[Co(NH3 )4 ]Cl3 ⇌ [Co(NH3 )4 ]3+ + 3Cl−
262 (d) Compound has one chiral carbon
Because there is direct bonding of metal ion with atom thus, it has two geometrical (𝑐𝑖𝑠 and 𝑡𝑟𝑎𝑛𝑠)
carbon and two optical isomers
263 (c) 270 (c)
CuCl in NH4 OH absorbs CO. The directive influence order and tendency to
265 (b) release electron for 𝑜-and 𝑝-directing group is,
It is a fact. O−2 > N𝑅2 > NH𝑅 > NH2 > OH > OCH3
267 (b) ≈ NHCOCH3 > CH3 > 𝑋
−COOH gp. is 𝑚𝑒𝑡𝑎 directing gp. 271 (d)
268 (b)
[Ni(H2 O)4 ]SO4 + NH4 OH → [Ni(NH3 )4 ]SO4

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 In organometallic compound, carbon atom is
directly bonded to metal atom. Methyl lithium
(CH3 Li) is an organometallic compound.
272 (a)
This is crossed Cannizzaro’s reaction in which 285 (b)
HCHO is oxidized. H H
NaOH
C6 H5 CHO + HCHO → C6 H5 CH2 OH + HCOONa . | |
273 (d) (i) − H − C − C − Cl 1,1-dichloro ethane
Gammexane is C6 H6 Cl6 . | |
274 (b) H Cl
Each ligand donates one electron pair. (ii) H H
275 (c) | |
7. is isomer of [Pt(NH3 )2 Cl2 ] which is used H − C − C − H 1,2-dichloro ethane
as an anticancer drug for treating several | |
types of malignant tumours. Cl Cl
Both are position isomers
286 (c)
Hybridisatio Geometry of
n complex
3 Tetrahedral
𝑠𝑝
𝑑𝑠𝑝2 Square planar
276 (d) 𝑑2 𝑠𝑝3 Octahedral
Reduction 2 2
C6 H5 CHO → C6 H5 CH2 OH. 𝑠𝑝 𝑑 Not possible
Benzyl alcohol.
277 (d)
Petroleum and coal are main sources of aromatic 287 (b)
compounds. CH3 − CH = CH − COOC2 H5 is
279 (c) Ethyl-2-butenoate
1 2 3 4
288 (d)
CH2 − CH − CH2 − CH2
Waxes are not obtained obtained by destructive
| | |
distillation of wood or coal.
CN CN CN
289 (c)
Butane-1,2,4-tricarbonitrile
Formaldehyde and benzophenone are also
280 (b)
obtained.
Fac-mer isomerism is associated with [𝑀𝐴3 𝐵3 ]
290 (b)
type complexes.
It ionizes to Fe3+ and SO2− 4 .
291 (d)
These are the concepts of Werner’s theory.
293 (b)
In K 3 [Co(CO3 )3 ], cobalt shows the +3 oxidation
state i.e., (𝑑6 ) ion. Hence, Co (+3) has four
282 (c) unpaired electrons so, it is paramagnetic.
Intramolecular H-bonding gives rises to lower The magnetic moment of Co(+3)
m.p. In K 3 [Co(CO3 )3 ] = √𝑛 (𝑛 + 2) BM
283 (b) = √4(4 + 2) BM=4.9 BM
Mn does not form mononuclear carbonyl. Where, n=number of unpaired electrons
284 (b) CO2− 2−
3 is a weak field bidentate ligand, so 3CO3
Ethylenediamine tetraacetic acid is a hexadentate ligands occupy six orbitals, thus it shows 𝑠𝑝3 𝑑2
ligand because it has six donor centres. hybridisation and octahedral in shape.
296 (a)

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 Some heterocyclic compounds (hetero aromatics) 9. Fe0 =
possess aromatic nature. Follow Hückel rule. 3𝑑6 , 4𝑠 2 . In presence of CO effective configuration
297 (c) 3𝑑8 .
Nickel reacts with dimethylglyoxime to give red
ppt. of nickel-dimethyl glyoxime complex. Four lone pair for back bonding with CO.

10. Cr 0 = 3𝑑4 , 4𝑠 2 . Effective configuration =

3𝑑6 .

Three lone pair for back bonding with CO.

298 (b)
NaNO2 +HCl
C6 H5 NH2 → C6 H5 N2 Cl
SnCl2 +HCl 11. V − = 3𝑑4 , 4𝑠 2 . Effective configuration =
→ C6 H5 NHNH2
3𝑑6 .
299 (d)
−CH3 gp. is 𝑜-and 𝑝-directing FeCl3 is halogen Three lone pair for back bonding with CO.
carrier.
300 (b) Maximum back bonding in Fe(CO)5 , therefore CO
It has coordination number of six and thus, should bond order is lowest here.
have six hybridized orbitals, 𝑖. 𝑒., 𝑑2 𝑠𝑝3-
311 (b)
hybridization.
𝑑 4 : Forms outer complex in high spin and forms
301 (a)
inner complex in low spin. It cannot form
For K 4 [Fe(CN)6 ], the EAN of Fe2+ ion
octahedral complex.
=(26−2+12) =36 .
𝑑6 : In low spin it forms inner octahedral complex
Hence it follows EAN rule, as its EAN is equal to
and in high spin forms outer octahedral complex.
number of electrons of Kr (inert gas), i.e., 36.
𝑑 8 : Forms only outer spin octahedral complex.
302 (b)
312 (c)
OCH3 gp. an 𝑜 – and 𝑝 –directing group activates
Bromo group, 𝑜- and 𝑝-directing.
ring for 𝑆𝐸 reactions.
313 (c)
303 (b)
The given statement represents only ether.
Anilium hydrochloride gives white ppt. with
314 (a)
AgNO3 .
Due to asymmetric carbon atom.
305 (a)
315 (a)
This is a fact for given statement.
This is a fact for the given statement.
307 (b)
316 (c)
𝑂𝑟𝑡ℎ𝑜, 𝑚𝑒𝑡𝑎 and 𝑝𝑎𝑟𝑎.
CN− and OH − are strong nucleophiles.
308 (b)
[Fe(OH)5 ]3− is not formed.
Follow IUPAC rules.
317 (b)
309 (b)
The prefixes erythro and threo are used in
8. Mn+ =
systems containing two asymmetric carbons
3𝑑5 , 4𝑠1 . In presence of CO effective configuration =
when two of the groups are the same and the
3𝑑6 , 4𝑠 0 .
third is different. The erythro-isomer has identical
Three lone pair of back bonding with vacant groups as the same side when a drawn in Fischer
orbital of C in CO. projection and threo-isomer has them on opposite
side
318 (b)
Main fractions of coal-tar and the compounds
present there in are:

P a g e | 117
 Main fraction Temp. Chief Due to rearrangement because 2 carbon is more
range constituents stable than 1 carbon.
1. Light oil or 80- Benzene, 333 (d)
crude 170C toluene, xylenes, Tris –(ethylenediamine) cobalt(III) bromide
2. naphtha etc. ([Co(en)3 ]Br3 )exhibits optical isomerism.
Middle oil or 170- Phenol,
3. carbolic acid 230C naphthalene,
Heavy oil or pyridine, etc.
4. creosote oil 230- Cresols,
Green oil or 270C naphthalene
5. anthracene quinolone, etc.
oil 270- Anthracene, 334 (c)
Pitch 360C phenanthrene, 𝐾3 [𝐹𝑒𝐹6 ]
etc. Fe3+ = [Ar] 3𝑑5 4𝑠 0
Resid 90-94% of
ue carbon
319 (d) Number of unpaired electrons=5
The order of reactivity depends on the stability of Magnetic moment =√𝑛(𝑛 + 2) = √𝑠(𝑠 + 2)
intermediate carbocation formed due to = √35 = 5.91 BM
heterolytic cleavage of C—𝑋 bond. 335 (b)
320 (d) EAN of Cr = 24 − 3 + 6 × 2 = 33.
Greater is the number of chelate rings, greater is 336 (d)
stability of the chelate. Hence, five fused cyclic Paramagnetic character ∝ number of unpaired
system is most stable for a chelate. electrons.
321 (b) 25Mn2+ ion has maximum unpaired (five unpaired
HNO3 + H2 SO4 acts as nitration mixture. electrons)
323 (d) electrons. So, [Mn(H2 O)6 ]2+ is most
The negative charge density on V-atom favours paramagnetic.
easy electron pair donation. 337 (d)
324 (b)
Due to acidic nature.
325 (d)
If a substance rotates the plane polarised light in
clockwise direction it is dextrorotatory (+). If it
rotates the plane polarised light in anticlockwise
direction then it is laevorotatory (−) Note : The reaction gives 2, 4, 6-trinitrophenol.
326 (c) Choice is not given. Only option left is 𝑜-
HCN+HCl HOH nitrophenol, which is not formed in this course of
C6 H 6 → C6 H5 CH=NH → C6 H5 CHO
reaction.
327 (b)
338 (d)
EAN of Fe in K 4 Fe(CN)6 = 26 – 2 + 2 × 6 = 36;
NH2 in aniline is highly susceptible to oxidant and
the at. no. of next inert gas.
therefore nitration of aniline is carried out by
329 (b)
protecting it against oxidation by acetyl chloride.
Both Ni (CO)4 and Ni(PPh3 )2 Cl2 have 𝑠𝑝3 -
hybridisation
331 (d)
All are examples of strong ligand field, because all
339 (b)
have greater value of ∆; ∆ represents the strength
—COOH is 𝑚𝑒𝑡𝑎-directing group.
of ligand field.
340 (d)
332 (a)
[Co(NO2 )(NH3 )5 ]Cl2

P a g e | 118
 Pentaammine nitrito –N- cobalt (III) chloride.
341 (b)
The ionisation isomer of
[Cr(H2 O)4 Cl (NO2 )]Cl is [Cr(H2 O)4 Cl2 ](NO2 )
×× Electron pair donated by CN − .
because of exchanging of ligand and counter ions.
356 (d)
342 (c)
CH3 − CH2 − C ≡ C − CH = CH2
All can be prepared from phenol. 6 5 4 3 2 1
343 (a) hex-1-en-3-yne
Only iodobenzene gives Ulmann’s reaction, 357 (b)
Cu
2C6 H5 I → C6 H5 — C6 H5 Oxidation state of Ni in K 2 NiF6 is +4; the highest
344 (c) among all.
Fischer projection can be manipulated by rotating 359 (d)
a group of any three ligands in clockwise (D) or Substituents always get higher number than the
anticlockwise (L) direction, the fourth ligand does principal functional group while, numbering the
not change its position longest possible chain
345 (b) 360 (d)
A strong filed ligand produces low spin Draw different isomers.
complexes. 362 (b)
347 (a) Metal carbonyl organometallic compounds
2+ possess both σ-and π-characters.
Ni in [Ni(H2 O)6 ] has two unpaired electrons in
it. 363 (b)
348 (b) F − is a weak field ligand and [FeF6 ]3− is an outer-
Compounds in which a chiral centre is part of a orbital complex
ring are handed in a analogous fashion

[FeF6 ]3− shows 𝑠𝑝3 𝑑2 hybridisation and Fe3+ has

five unpaired electrons.
In [Fe(CNS)6 ]3− , CNS− is a strong field ligand and
is inner orbital complex.
351 (a) [Fe(CNS)6 ]3−
AlCl3 anhy.
C6 H6 + CH3 Cl → C6 H5 CH3
352 (b)
The formula of hexamine copper (II) sulphate
is[Cu(NH3 )6 ]SO4. It dissolve in water as

[Fe(CNS)6 ]3− shows 𝑑2 𝑠𝑝 3 hybridisation and has

one unpaired electron.
354 (b) Hence, the reaction.
Complex of type [M(AA)3 ] show optical [Fe(CNS)6 ]3− → [FeF6 ]3−
isomerism. takes place with increase in magnetic moment.
355 (b) 364 (a)
Electronic configuration of Fe2+ in K 4 Fe(CN)6 is: Presence of three —NO2gp. in chlorobenzene
activates Cl atom to show SN reactions.
365 (a)

P a g e | 119
 Complex compounds or complex salts containing 377 (c)
two different metallic elements give tests for only Ni2+ has two unpaired (3𝑑 8 ) electrons. CN − is
one element. For example, potassium strong field ligand and thus all the eight electrons
( )
hexacyanoferrate (II), K 4 [Fe CN 6 ] gives tests are paired giving 𝑑𝑠𝑝2 -hybridisation.
+ 2+
only for K ions and not for Fe ions. 379 (d)
+ 4−
K 4 [Fe(CN)6 ] ⇌ 4K + [Fe(CN)6 ] Coal-tar is source of all these.
366 (a) 380 (c)
Only primary valencies are ionized. Halogen attached to benzene nucleus is stabilized
BaCl2 due to resonance.
[Co(NH3 )5 Br]SO4 → [Co(NH3 )5 Br]2+ + BaSO4
AgNO 3 382 (a)
[Co(NH3 )5 SO4 ]Br → [Co(NH3 )5 SO4 ] + AgBr −NO2 group is reduced to −NH2 by Sn/HCl.
0.01 mole of each by 0.01 mole of reactants. 383 (d)
367 (c) Each central atom attains the EAN equal to at. No.
Wilkinson’s catalyst, (Ph3 P)3 RhCl of next inert gas Kr, 𝑖. 𝑒., 36.
RH + = [Kr] 4𝑑8 𝑠 0 384 (c)
𝑖𝑒, 𝑑𝑠𝑝 2 hybridisation A bidentate ligand has two donor sites available
Rh atom in Wilkinson’s catalyst is 𝑑𝑠𝑝2 hybridised for coordination, 𝑒. g.,
giving a square planar shape to the molecule
368 (d)
H2 O is weak field ligand, thus Co2+ has only 3
unpaired electrons. 385 (d)
369 (a) −N2 Cl is reduced to H by either of these reducing
If an enantiomerically pure acid is treated with agents.
racemic mixture of an alcohol having a chiral 386 (c)
carbon, the product formed will be optically active Fe is present in the form of complex ion, 𝑖. 𝑒.,
mixture [Fe(CN)6 ]3− which is not ionized to Fe3+ and CN− .
370 (d) 387 (a)
Cyclopropane is most strained since it has a [Co(NH3 )5 SO4 ]Br ⇌ [Co(NH3 )5 SO4 ]+ + Br −
maximum angle strain of 24° − 44′ [Co(NH3 )5 Br]SO4 ⇌ [Co(NH3 )5 Br]2+ + SO2− 4
371 (c) The molecular formula of both of the above
compounds is same but on ionisation they give
different ions in solution, so they are called
ionization isomers.
390 (c)
Phenols are weak acids and do not react with
this is Gattermann-Koch reaction to introduce NaHCO3 (a weak base).
−CHO gp. in C6 H6 nucleus. 391 (b)
372 (a) C6 H5 CH = CHCOOH is cinnamic acid; it has
Mn in Mn(CN)4− 6 has configuration: unsaturation.
392 (a)
Magnetic moment of
K 3 [Fe(CN)6 ]=1.7 BM
373 (d) Magnetic moment=√𝑛(𝑛 + 2)
It does not ionize to give Cl− ions and thus, white 𝑛 =number of unpaired electrons present in
ppt. of AgCl will not be obtained. molecule
375 (c) 1.7=√𝑛 (𝑛 + 2)
[Pt(C2 H4 )Cl3 ] −𝑛2 + 2𝑛 − 2.89 = 0 then 𝑛 = 0.97 or 1
𝑥 + 0 + (−1) × 3 = 0 393 (c)
𝑥 + (−3) = 0
𝑥 = +3

P a g e | 120
 409 (a)
Compounds having coordination number six and
following the general formula show geometrical
and optical isomerism.
This compound contains 9 carbon atoms and
𝑀𝐴4 𝐵2 , 𝑀𝐴4𝐵𝐶 , 𝑀𝐴3𝐵3 𝑎𝑛𝑑 𝑀(𝐴𝐴)2 𝐵2 show
corresponding alkane is nonane. Three bridges
geometrical isomerism and
contain 5, 2 and 0 carbon atoms. Therefore, the
𝑀𝐴2 𝑋2𝑌2 , 𝑀𝐴2𝑋2 𝑌𝑍 , 𝑀𝐴2 𝑋𝑌𝑍𝐿
name of the compound is bicyclo [5.2.0] nonane
𝑀𝐴𝐵𝑋𝑌𝑍𝐿 , 𝑀(𝐴𝐴)3 , 𝑀(𝐴𝐴)2 𝑋2 show optical
395 (c)
The compound have structure as written below isomerism. (𝐴𝐴) is bidentate ligand.
410 (b)
[Co(NH3 )4 Cl2 ]Cl , Its IUPAC name is tetraammine
dichloro cobalt III chloride.
411 (c)
The ease of hydrolysis depends upon the
magnitude of the +ve charge on the carbonyl
group.
396 (d) 412 (d)
It is 𝑚-directing gp. All are the common uses of nitrobenzene.
397 (a) 413 (b)
Carbylamines reaction. K 4 [Ni(CN)4 ] ⟶ 4K + + [Ni(CN)4 ]4−
400 (d) x +(4× −1)= −4
C6 H5 SO3 Na + NaOH ⟶ C6 H5 ONa + NaHSO3 x − 4=−4
x =0
414 (a)
401 (a) Presence of —OH gp. in C6 H6 nucleus increases
The stability order of conformations of acidic nature.
cyclohexane is 416 (b)
Chair > twist boat > boat > half chair Halogen attached on side chain behaves as in
402 (b) aliphatic molecule.
Phenolic group is susceptible for oxidation and 417 (d)
thus, to obtain 𝑜- and 𝑝-nitrophenol dil. HNO3 is Cyclohexane is an aliphatic cyclic compound.
used in place of conc. HNO3 + H2 SO4. 418 (c)
403 (c) 12. In [Cu(NH3 )4 ]2+ , Cu is present as Cu2+
Lower is mol. Wt. lower is b.p., also 1, 2-dihydroxy
benzene show chelation and thus have lower b.p. Cu2+ = [Ar]3𝑑9 4𝑠 0
than 1,3 and 1,4-derivatives.
Phenol 1,2-dihydroxyb 1,3-dihyroxyb [Cu(NH3 )4 ]2+ = [Ar]
1,4-dihydroxyb
enzene enzene
enzene
m.p. 43C < 105C <110C
<170C (NH3 being a strong field ligand shifts one
b. p. < < electron from 3d-orbital to 4p-orbital.)
<
405 (b) 13. In [Ni(CO)4 ], CO is a neutral ligand
K 2 [PtCl6 ] ⇌ 2K + + [PtCl6 ]−
14. In [Fe(CN)6 ]3− , Fe is present as Fe3+ .
407 (b)
Phenols are weakly acidic due to resonance. Fe3+ = [Ar]3𝑑5 4𝑠 0
408 (b)
Follow IUPAC rules. [Fe(CN)6 ]3− = [Ar]

P a g e | 121
 [Fe(Cl)6 ]3− = [Ar]
↿ ↿ ↿ ↿ ↿

Thus, its hybridization is 𝑑2 𝑠𝑝3 not 𝑠𝑝3 𝑑2 , i.e., it is

an inner orbital complex.

15. [Co(en)3 ]3+ contains total 36 electrons, 𝑖. 𝑒., 430 (d)

follows EAN rule. p 𝐾a for (a), (b), (c) and (d) are 4.17, 4.09, 3.49
and 3.43 respectively.
420 (c)
431 (a)
Optical isomerism is very common in octahedral
[H2 EDTA]2− + Mg 2+ → [MgEDTA]2+ + 2H +
complexes having general formula
𝑛− 𝑛− 16. In this complex, four donor sites are
[𝑀𝐴2 𝐵2 𝐶2 ] , [𝑀𝐴𝐵𝐶𝐷𝐸 ]𝑛− , [𝑀(𝐴𝐴)3 ] , occupied by oxygen and two donor sites
𝑛− 𝑛− 𝑛−
[𝑀(𝐴𝐴)3𝐵2 ] [𝑀(𝐴𝐴)3 𝐵𝐶 ] and [𝑀(𝐴𝐵)3 ] are occupied by nitrogen.

17. This complex is six coordinated.

is unsymmetrical bidentate ligand. 18. Complex [MgEDTA]2− is colourless.

421 (c)
19. Increase in [H + ]decreases pH of the
[Co(NH3 )5 NO2 ]Cl2 ⇌ [Co(NH3 )5 NO2 ]2+ + 2Cl−
solution.
2Cl− + Ag + (excess) ⟶ 2AgCl ↓
422 (a) 433 (c)
C6 H5 C is benzo gp. Different compounds having the same molecular
423 (c) formula but different properties are called
It is the reason for given fact. isomers
424 (b) 434 (c)
𝑑6 -cation with low spin has electronic In the compound
6 0
configuration 𝑡2g 𝑒g .
Total energy= (−0.4 ∆0 per 𝑒 − × 6) + (𝑒 − pairing
energy of 3 pairs)
= −2.4 ∆0 + 3P
12
=− ∆0 + 3P
5
426 (c) Numbering will be done from this end because
It is DDT, 𝑖. 𝑒., 𝑝, 𝑝′ -dichloro diphenyl both are side chains and – OCH3 is smaller than
trichloroethane. – OC2 H5
428 (b) 3-ethoxy-1-methoxy-propane
[Cr(NO2 )(NH3 )5 ] Cl show linkage isomerism. 435 (a)
Each carbon in benzene is 𝑠𝑝2 -hybridized.
436 (b)

429 (d)
Cl, being a weak field ligand, does not cause
pairing of d-electrons of the metal atom and thus,
forms outer orbital complex as.
In [Fe(Cl)6 ]3− , Fe is present as Fe3+
Fe3+ = [Ar]3𝑑5 4𝑠 0 4𝑝0 So, gauche form stabilized by intermolecular
hydrogen bonding hence, gauche is more stable
than anti
↿ ↿ ↿ ↿ ↿
437 (a)
P a g e | 122
 AgCN + KCN ⟶ K[Ag(CN)2 ]. II
438 (b) In geometrical isomerism, coordination number
Carbocyclic compounds which resemble aliphatic of central atom (cobalt) is six and shape is
compounds in their properties are called alicylic octahedral, so it shows following geometrical
compounds isomers.
439 (a)
—NO2 gp. is deactivating gp.
440 (b)
The molecule contains three chlorine atoms out of
which only two are ionized.
441 (b)
[Co(en)2 Cl2 ]+ have three optical isomers which
are given below.

448 (a)
Aliphatic amines are stronger base than aromatic
amines.
449 (b)
Follow Hückel rule.
450 (d)
⇄ sign represents oscillating structures (Kekule)
for C6 H6 ;

451 (b)
HOH
C6 H5 CHCl2 → C6 H5 CHO.
453 (c)
Cr has coordination no. 6 in its carbonyl and other
complexes.
442 (c) 454 (d)
The reaction carried out in alkaline pH, 𝑖𝑒, 9 − 11 Neutral FeCl3 (𝑎𝑞. ) gives violet coloured complex
444 (d) with phenol.
NO2 gp. withdraws electrons from 𝑜 –and 𝑝- 455 (a)
position and thus, deactivates the ring. This [CoF6 ]3− is an outer complex having 𝑠𝑝 3 𝑑2 -
deactivation stabilises the negatively charged hybridization.
intermediates formed during reaction and thus, 456 (d)
replacement of−Cl becomes easier. [Sc(CN)6 ]3−
446 (a) Sc=21=1𝑠 2 , 2𝑠 2 , 2𝑝6 , 3𝑠 2 , 3𝑝6 , 4𝑠 2 , 3𝑑1
Ti(C2 H5 )4 is an organometallic compound because
there is direct bonding of metal ion with carbon. 3𝑑 4𝑠 4𝑑
447 (a)
Octahedral Co(NH3 )4 Br2 Cl shows ionisation and Sc 3+ =
geometrical isomerism. No unpaired electron
In ionisation isomerism ligands show different
coordination sphere and the anions present Ni(CN)2−4
outside the coordination sphere. Ni(G. S.) 3𝑑 4𝑠 4𝑝
These are exchanged with each other as follows ⥮ ⥮ ⥮ ↿ ↿ ⥮
Co(NH3 )4 Br2 Cl ⇌ [Co(NH3 )4 Br2 ]+ + Cl−
I
[Co(NH3 )4 BrCl]Br ⇌ [Co(NH3 )4 Br Cl]+ + Br −
P a g e | 123
 Ni2+ 3𝑑 4𝑠 4𝑝 28 Ni
2+
in [Ni(NH3 )6 ]2+ has
⥮ ⥮ ⥮ ↿ ↿ 1𝑠 , 2𝑠 2𝑝6 , 3𝑠 2 3𝑝6 3𝑑8 configuration. It uses 4th
2 2

orbital to show 𝑠𝑝3 𝑑2 hybridisation to form outer

complex with 2 unpaired electrons in 3𝑑-orbital.
460 (c)
Moth repellent due to insecticide nature.
461 (c)
The number of unidentate ligand in the complex
It has no unpaired electron hence, diamagnetic. ion is called coordination number.
[Co(CN)6 ]3− 462 (b)
Co (G.S.) 3𝑑 4𝑠 4𝑝
⥮ ⥮ ↿ ↿ ↿ ⥮

Co3+ 3𝑑 4𝑠 4𝑝
7double bonds and thus, 14 π- electrons.
⥮ ↿ ↿ ↿ ↿
463 (b)
Co3+ 3𝑑 4𝑠 4𝑝 In ethane and cyclohexane, staggered and chair
forms are more stable respectively
⥮ ⥮ ⥮

(Pairing
due to CN − )

[Cr(CN)6 ]3−
464 (d)
Cr (G.S.) 3𝑑 4𝑠 4𝑝 (CH3 )4 Sn has no π-bond.
↿ ↿ ↿ ↿ ↿ ↿ 465 (a)
Halogens however 𝑜- and 𝑝-directing group but
deactivate ring for S𝐸 reactions due to electron
Cr 3+ 3𝑑 4𝑠 4𝑝 withdrawing nature.
↿ ↿ ↿ ↿ 466 (b)
It is the reason for the fact.
Cr 3+ 3𝑑 4𝑠 4𝑝 467 (a)
⥮ ↿ −NO2 gp. is deactivating gp.
470 (c)
(due to CN − ) The side reaction produces diphenyl ether. The
It has one unpaired electron so, paramagnetic. yield may be increased by adding little diphenyl
458 (a) ether with C6 H5 Cl + NaOH.
[Fe(CN)6 ]4− → Fe2+ → 471 (c)
(Strong field) Atoms or groups donating electron pair to metal
1𝑠 2 , 2𝑠 2 2𝑝6 , 3𝑠 2 3𝑝6 3𝑑6 are ligands.
472 (d)
Aniline is insoluble in water.
473 (d)
CrO2 Cl2 has + 6 oxidation state of Cr.
CN− is strong field ligand, it cause pairing while 475 (b)
C2 O2− −
4 and F are weak field ligands and don’t It is a method to estimate hardness of water.
causes pairing. 476 (a)
Hence, [Fe(CN)6 ]4− due to the absence of Both are non-polar; like gets dissolved in like.
unpaired electrons is diamagnetic. 477 (b)
459 (c)

P a g e | 124
 In [Ni(CN)4 ]2−
Ni2+ =

There are two carbon atoms, 𝑖𝑒, C-2 and C-4 are
tertiary C-atoms
478 (b)
Rosenmund’s reaction.
𝑑𝑠𝑝2 hybridisation, i.e., square planar geometry,
479 (c)
Zn−Hg/HCl zero unpaired electron, i.e., zero magnetic
C6 H5 CHO → C6 H5 CH3 moment
480 (c) For [MnBr4 ]2− , oxidation state of Mn is +2.
F − has lowest ∆𝑜 value depending upon the Br − = weak field ligand
splitting power of 𝑑-orbitals Mn2+ (in ground state)
481 (b) 3𝑑 4𝑠
Complex [Co(en)3 ]3+ has no plane of symmetry ↿ ↿ ↿ ↿ ↿
and centre of symmetry that’s why it is optically
active. In [MnBr4 ]2− ,
Mn2+ =

482 (a)
It is preparation of DDT.
483 (a) 𝑠𝑝3 hybrisation, i.e., tetrahedral geometry, five
Light oil mainly contains C6 H6 , C7 H8 , C8 H10 , etc. unpaired electrons, i.e., magnetic moment=5.9
484 (c) Co3+ in ground state=
Coordination number is the number of ligand σ-
bonded to metal-atom. Hence, coordination
number of X in [𝑋(SO4 )(NH3 )5 ]Cl is 6. Let 3𝑑 4𝑠 0 4𝑝
oxidation state of X in the complex be ‘y’ then ⥮ ↿ ↿ ↿ ↿
y +(−2)+5(0)+( −1)=0
y −2−1=0 For [CoF6 ]3− , oxidation state of Co is +3.
y =+3 F − =weak field ligand
485 (a) In [CoF6 ]3−

In presence of light substitution occurs is side

chain.
486 (a)
[CoCl3 (NH3 )3 ] cannot ionize in solution because
three chloride ions satisfy primary and secondary
valencies. It will not be precipitated by the
addition ofAgNO3 . 𝑠𝑝3 𝑑2 hybridisation i.e., octahedral geometry
487 (d) four unpaired electrons i.e., magnetic moment is
2−
For [Ni(CN)4 ] , oxidation state of Ni is +2. 4.91 BM.
CN− =strong field ligand 489 (b)
Ni2+ (ground state)= An experimental value.
3𝑑 8 4𝑠 0 491 (c)
⥮ ⥮ ⥮ ↿ ↿ A commonly used food preservative.
P a g e | 125
492 (a) 503 (b)
C6 H5 ONa + C2 H5 I ⟶ C6 H5 OC2 H5 + NaI Aqua regia ∆
Phenetole Pt → H2 [PtCl6 ] → PtCl4 + 2HCl
504 (d)
493 (d) Follow IUPAC rules.
Metal carbonyl are regarded as the coordination 505 (b)
compounds formed by the donation of lone pair of The structure of the compound is
electron of CO into the suitable empty orbital of
zero valent transition metals such as Ni, Fe etc.
Therefore, the 𝑀— C bond is coordinate covalent.
494 (d)
When the three ligands (with same donor atoms)
are on the same triangular face of the octahedron,
the isomer is called facial or fac isomer.
The octahedral complex is facial or fac isomer.

506 (d)
−CH3 gp. is 𝑜𝑟𝑡ℎ𝑜 and 𝑝𝑎𝑟𝑎 directing.
507 (a)
Estimation of calcium and magnesium is done by
EDTA.
508 (d)

In this complex, the three ligands are on the same

triangular face of the octahedron.
495 (a) Due to the presence of chiral centre it shows the
Number of unpaired electrons in [Fe(CN)6 ]4− is optical activity and its mirror image are non
zero. superimposable hence it shows one enantiomer
Thus, magnetic moment pair
=√𝑛(𝑛 + 2)=0 BM
(n=unpaired electrons)
n in [MnCl4 ]2− =5, √35 BM 509 (b)
n in [CoCl4 ]2− =3, √15 BM C6 H6 and other aromatic compounds show
496 (a) characteristics S𝐸 reactions.
Orange-red dye is formed with aniline. 510 (d)
499 (a) CH2 = CH − CH = CH − CH = CH − CH3
It is a fact. Follow 𝑜𝑟𝑡ℎ𝑜 effect. 1 2 3 4 5 6 7

500 (d) Hepta-1,3,5-triene

Half chair is transition state conformation 511 (b)
1 2 3
between the chair and boat conformation. The
CH2 − CH − CH2
energy difference between the chair and half chair
| | |
conformation being 44 kJ mol−1 . Hence it is most
CHO CHO CHO
unstable
Propane-1, 2, 3-tricarbaldehyde
501 (a)
512 (a)
The M—C π-bond in metal carbonyl which is
The attacking species in sulphonation is SO3 .
formed by the donation of an electron pair from a
H2 SO4 ⟶ H3 O+ + SO3 + HSO− 4
filled 𝑑-orbital of metal into the vacant
513 (d)
antibonding π-orbital of CO, strengthens the M—
CHCl3 has no reaction with Br2 .
C σ— bond. This is called synergic effect and is
514 (c)
usually observed in metal carbonyls. Thus
[NiCl4 ]2− ; oxidation number of Ni,
[Ni(CO)4 ] exhibits synergic effect.
x−4=−2
P a g e | 126
 ∴ x=+2 521 (b)
Ni(28) = [Ar]3𝑑8 , 4𝑠 2 It is outer complex having 𝑠𝑝3 𝑑2 [CoF6 ]3− ion.
3𝑑8 Electronic configuration of Co3+ in [CoF6 ]3− is:
⥮ ⥮ ⥮ ↿ ↿

×× Electron pair donated by F −

523 (d)
The two given compound have same composition
but in solution both will give different ions. The
isomerism is known as ionisation isomerism
Ni2+ [Ar]
524 (a)
Coordination number is the maximum covalency
⥮ ⥮ ⥮ ↿ ↿
shown by a metal or metal ion. It is the maximum
[NiCl4 ]2−
number of ligands attached to metal by sigma
bonds or coordinate bonds.
525 (a)
C6 H5 COOH + N3 H ⟶ C6 H5 NH2 + CO2 + N2 ; this
𝒔𝒑𝟑 -hydrid orbitals, tetrahedral is Schmidt’s reaction.
Cl− is a weak ligand and thus unpaired electrons 526 (d)
are not paired. Lone pairs from 4Cl− are Each possess the tendency to have coordination
accommodated in four 𝑠𝑝3 hybrid orbitals. number equal to six.
N=unpaired electron=2, paramagnetic 527 (d)
Magnetic moment (spin only) Hexadentate ligand donates six pair of electrons
= √𝑁(𝑁 + 2) BM = √8 = to central atom.
2.828 BM (a) 2, 2-dipyridyl-bidentate ligand
515 (b)
Pyridine shows SE reactions at position-3
preferentially and at 2,4-positions under specific
conditions.
516 (a)
(b) DMG-bidentate ligand
K[Ag(CN)2 ] ⇌ K + + [Ag(CN)2 ]1−
CH3 − C = N − O →
517 (a)
|
Its coordination number will be 6 because it is
CH3 − C = N →
bonded with three bidentate ligands
|
𝑥 + 3(−2) + 3(+1) = 0 ⇒ 𝑥 = +3
OH
518 (c)
(c) Ethylenediamine-pentadentate ligand
The four ions on ionisation are possible only
∴ None of the given ligand is hexadentate ligand.
when three Cl− are outside the coordination
528 (d)
sphere.
HNO3 + H2 SO4 ⟶ NO+ +
2 + H3 O + HSO4
−
[Pt(NH3 )5 Cl]Cl3 ⇌ [Pt(NH3 )5 Cl]3+ + 3Cl− Base Acid
519 (a) 529 (d)
In presence of H2 O which is a weak ligand no 20. 𝑑5 in strong field
pairing occurs which results in unpaired electrons
𝑛 =unpaired electron=1
left in the compound, due to which it shows
paramagnetism

520 (a)
This is a fact.
P a g e | 127
 1
Magnetic moment=√𝑛(𝑛 + 2)𝐵𝑀 21Sc=[Ar]3𝑑 4𝑠 2
Sc = [Ar]3𝑑 0 4𝑠 0 no unpaired electrons in 𝑑-
3+

= √3 BM=1.73 BM subshell, so it is diamagnetic and colourless.

536 (d)
21. 𝑑3 in strong/weak field In [Co(NH3 )6 ]3+ the oxidation state of Co is +3.

[Co(NH3 )6 ]3+ does not contain unpaired electron

hence, its magnetic moment is zero.
𝑛=3
537 (a)
Magnetic moment=√15 =3.87 BM Presence of 𝑜-, 𝑝-directing groups in benzene
nucleus activates ring for S𝐸 reaction. Presence of
22. 𝑑4 in weak field 𝑚-directing deactivates ring for S𝐸 reaction. Also
halogens deactivating gp. Due to –𝐼𝐸 inspite of 𝑜-
and 𝑝-directing nature. The presence of 𝑚-
directing groups in benzene nucleous simply
decreases electron density at 𝑜- and 𝑝-, whereas
no change in electron density at 𝑚-position is
noticed.
𝑛=4

Magnetic moment=√24 =4.90 BM

23. 𝑑4 in strong field

On the contrary 𝑜-and 𝑝-directing groups in

nucleus increases the electron density at 𝑜- and 𝑝-
position.
Thus, presence of 𝑜- and 𝑝-directing groups
provide seats for S𝐸 reactions or activates the ring,
𝑛=2 whereas presence of 𝑚-directing groups does not
activate the ring and thus, deactivate the ring for
Magnetic moment=√8 =2.83 BM S𝐸 reactions
531 (a)
[Ni(CN)4 ]2− ion has 𝑑𝑠𝑝2 hybridisation, zero
magnetic moment and square planar structure.
3𝑑 4𝑠 4𝑝
Ni-atom
⥮ ⥮ ⥮ ↿ ↿ ⥮
539 (b)
Ni ⥮ ⥮ ⥮ ↿ ↿ The percentage of enolic contents of some
(II) common compounds in decreasing order will be

>
C6 H5 COCH2 COCH3 > 𝐶H3 COCH2 COCH3
It has no unpaired electrons hence, its magnetic > 𝐶H3 COCH2 COOC2 H5 > 𝐶H3 COCH2 CHO
moment is zero. > 𝐶H3 COCH3
534 (a)

P a g e | 128
 The compounds of nickel are green coloured due
to 𝑑 − 𝑑 transition in presence of ligand in Ni2+
cations.
546 (c)
> 𝐶H3 CHO > Cl2 HOH
C6 H5 CH3 → C6 H5 CCl3 → C6 H5 COOH
540 (c)
547 (d)
Mn forms Mn2 (CO)10 carbonyl.
Geometrical isomerism is found in compounds
541 (c)
having coordination no. 4 (square planar and not
Picric acid has phenolic gp.
tetrahedral shape) as well as coordination no. 6.
542 (d)
Coordination no. 4 (square planar)
(i) The sum of oxidation states of all atoms in a
𝑀𝐴2 𝐵𝐶 , 𝑀𝐴2𝐵2
compound is zero.
Showing geometrical isomerism 𝑀𝐴𝐵𝐶𝐷
(ii) Oxidation state of metal in carbonyl is zero. Coordination no. 6 (octahedral)
𝑀𝐴4 𝐵2 , 𝑀𝐴4𝐵𝐶
(a) K 4 Fe(CN)6 Showing geometrical isomerism.
𝑀𝐴3 𝐵3 , 𝑀(𝐴𝐴)2𝐵2
Let, oxidation state of Fe in K 4 Fe(CN)6 = x
548 (c)
∴ +4+ x +(−1×6)=0 Follow text.
549 (a)
∴ x =+2 Presence of electron repelling gp. decreases the
(b) K 2 FeO4 acidic strength.
C6 H5 COOH 𝑝-methyl benzoic 𝑝-chloro
Let, oxidation state of Fe in K 2 FeO4 = x phenol phenol
acid
∴ +1×2+ x +(−2×4)=0 𝐾𝑎 6.76 × 10 −5
1.26 × 10−5 4.16 ×
10 −10
∴ x =+6 10 1.05 × 10
551 (b)
(c) Fe2 2O3 It becomes brown (due to oxidation) on standing
in air.
Let, oxidation state of Fe in Fe2 O3 = x 552 (b)
∴ 2x +(−2×3)=0 It is characteristics of aromatic compounds.
553 (d)
or 2x =6 The colour of the complex COCl3 ∙ 5NH3 ∙ H2 O is
pink.
6
∴ x =2=+3 554 (b)
2 + 4 × (−1) = 𝑥, 𝑥 = −2
(d) Fe(CO)5 555 (a)
Halide ligands have low values of ∆.
Oxidation state of Fe in Fe(CO)5 =0
556 (d)
∴ Oxidation state of Fe is least in Fe(CO)5 . Electronic configuration of Co3+ in [CoF6 ]3− is:

543 (a)
The name of [Pt(NH3 )4 Cl2 ]2+ , [PtCl4 ]2− is
tetraamminedichloroplatinum (IV)
tetrachloroplatinate (II). Since, positive ion is ×× Electron pair donated by F −
written first and negative ion later. 558 (d)
544 (b) Let the oxidation state of Fe in
Resorcinol is 𝑚𝑒𝑡𝑎 hydroxyphenol. [Fe(H2 O)5 NO]SO4 is x.
545 (d) [Fe(H2 O)5 NO]2+
⇒ x+0+1=2

P a g e | 129
 ∴ x =+1 =√35=5.92 BM.
Here, NO exists as nitrosyl ion (NO+). 569 (c)
559 (c) [PtCl2 . P(C2 H5 )3 ]2 can exhibit geometrical
EAN=Z−(ON)+2 (C.N.) isomerism, the geometrical isomers are
where, O.N.=oxidation number
C.N.=coordination number
Z = atomic number
[Fe(CN)6 ]4− :
EAN=26− (2)+2(6)
=26-2+12=36
561 (a)
In the complex K 3 [FeF6 ], Fe is present in +3
oxidation state.
6 2
26Fe=[Ar]3𝑑 4𝑠

Fe3+ = [Ar]3𝑑5
570 (c)
↿ ↿ ↿ ↿ ↿
Hence, number of unpaired electrons is five as F is The minimum possible isomers of compound will
weak ligand. be

Magnetic moment=√𝑛(𝑛 + 2)
= √5(5 + 2)
=5.91 BM
563 (c)
No doubt C— D bond cleavage is slower than 571 (b)
C— H bond due to isotopic effect but rate of C2 O2−
4 is a bidentate group. As the complex
overall substitution is determined by the slow contains three bidentate groups, the central metal
attachment of electrophile to carbocation ion has a coordination number of 6.
(Morrison-Boyd 15.14P-532). 572 (d)
564 (a) [Co(en)3 ]3+ has 𝑑 and 𝑙 forms as
Due to synergic bond formation, bond order
decreases and bond length increases a little.
566 (c)
It is a bicyclic compound having two common
carbon atoms and three bridges. So, the IUPAC
name is

573 (b)
5, 6-dimethyl bicyclo [2.2.1] hept-2-ene Ru forms two carbonyls with zero oxidation
567 (c) number. Mononuclear Ru(CO)5 and trinuclear
Ru3 (CO)12 .
Fe3+ + [Fe(CN)6 ]4− ⟶ Fe4 [Fe(CN)6 ]3
Prussian blue 574 (c)
568 (a) Oxidation state of nitrogen in (N2 H5 )2 SO4 is
The effective magnetic moment of a paramagnetic 4𝑥 + 10 − 2 = 0
substance is given by the relation 𝑥 = −2
𝜇 = √𝑛(𝑛 + 2) BM. 575 (d)
where, 𝑛=number of unpaired electrons. Linkage isomerism is exhibited by ambidentate
3− 3+ ligands (ligands having two coordination sites).
In [FeF6 ] , Fe has five unpaired electrons.
3−
μ of [FeF6 ] = √𝑛(𝑛 + 2) e.g., NO−2 .
= √5(5 + 2)

P a g e | 130
 If the bonding is through N, the ligand is named as Os (Z=76) : [Xe] 4𝑓14 , 5𝑑6 , 6𝑠 2
nitro and if it is through O, it is named as nitrito. Hence, the coordination number in an osmium
NO− 2 → nitro —N complex may increase to 8.
ONO− →nitrito —O 592 (c)
577 (a) Phenol has antiseptic property.
Due to resonance of electron pair in aniline, 593 (c)
nitroaniline and acetanilide, these are weaker NaOH+CaO
C6 H5 CH = CHCOOH → C6 H5 CH = CH2
than C6 H5 CH2 which does not involve lone pair of (Styrene)
N in resonance. The basic order is: Benzyl amine 594 (d)
>Aniline > Acetanilide > Nitroaniline. [Co(en)3 Cl3 𝑖𝑒, [Co(en)3 ]3+
578 (b)
Effective atomic no. (EAN) = at. No. of central
atom –oxidation state +2 × (no. of ligands)=
28 − 0 + 2 × 4 = 36
EAN = 78 − 4 + 2 × 6 = 86.
579 (b)
[Cu(NH3 )4 ]SO3 ⇌ [Cu(NH3 )4 ]2+ + SO2− 4 𝑐𝑖𝑠[Co(en)2 Cl2 ]Cl 𝑖𝑒, 𝑐𝑖𝑠 [Co(en)2 Cl2 ]+
580 (b)
Ammonia is not an ambident legand so it can
donate electron only by N-atom
582 (b)
12σ and 3π.
583 (c)
−OH gp. is activating whereas Cl— is deactivating.
—CH3 gp. is less activating than OH.
584 (d) 595 (b)
The compound in which ligands form ring with
the metal are called chelate complex.
597 (c)
Benzaldehyde undergoes Cannizzaro’s reaction.
The compound is symmetrical with
600 (c)
respect to centre of the molecule
Coordination isomerism is possible when both
585 (b)
positive and negative ions of a salt are complex
Two 𝑐𝑖𝑠 and 𝑡𝑟𝑎𝑛𝑠 forms.
ions and the two isomers differ in distribution of
586 (c)
ligands in the cation and the anion
𝑝-nitrophenol is more stronger acid than phenol.
601 (a)
587 (b)
[O] NaOH
This is bromination of acetanilide, a SE reaction.
C6 H5 CH3 → C6 H5 COOH → C6 H5 COONa 602 (b)
CaO+NaOH
→ C6 H 6 The primary valency is ionizable valency. It
588 (d) corresponds to oxidation state of metal. The
Staggered conformation is most stable due to its primary valency is always satisfied by anion.
minimum energy [Co(NH3 )6 ]Cl3 ⟶ [Co(NH3 )6 ] + 3Cl−
589 (a) (A)
[Co(NH3 )5 Br]SO4 ⇌ [Co(NH3 )5 Br]2+ + SO4 2− ∴ Number of primary valency is 3
Pb2+ + SO2− [Co(NH3 )5 Cl]Cl2 ⟶ [Co(NH3 )5 Cl] +
4 ⟶ PbSO4 ↓
−
White insoluble 2Cl
590 (c) (B)
Fe2+ , Co5+ , Ti3+ , and V 3+ have 4, 4, 1, 2 unpaired ∴ Number of primary valency is 2
electron respectively. The pairing leads Fe2+ with [Co(NH3 )4 Cl2 ]Cl ⟶ [Co(NH3 )4 ] + Cl−
no unpaired electron. ∴ Number of primary valency is 1.
591 (b) 603 (d)
P a g e | 131
 The carbon atom which is attached to three It is a differentiating point in between complex
carbon atoms is called tertiary carbon atom. and double salt.
C6 H14 has two tertiary carbons hence, its 617 (d)
structure is as All possess lesser number of unpaired electrons.
618 (c)
Structures K 4 [Fe(CN)6 ], K 3 [Co(CN)6 ],
K 2 [Ni(CN)4 ] are diamagnetic.
619 (c)
Wilkinson’s catalyst is used for hydrogenation of
alkenes
604 (b)
620 (c)
The ligand NO2 has two types of linkage with
Due to 𝑜𝑟𝑡ℎ𝑜 effect; 𝑜𝑟𝑡ℎ𝑜 benzoic acid is most
central atom. In NO2 , it is the N-atom which is
acidic because its anion is highly stabilized due to
donor and in O—NO it is the O atom which
strong intramolecular H-bonding.
donates electron pair.
605 (d)
Tetraethyl lead is organometallic compound.
606 (d)
C6 H5 OH + PCl5 ⟶ (C6 H5 )3 PO4 is main product.
609 (c)
Directive influence order
—OH > —OCH3 > —CH3 > —NHCOCH3 > —
CH2 OH of 𝑜-, 𝑝- gps. This is due to effect of +𝑅 𝐾a : 1.0 × 10−3 2.9 × 10−5 1.26 × 10−5
directing influence of gp. 6.9 × 10−8
610 (d) 623 (a)
[PtCl4 ]2− shows 𝑑𝑠𝑝2 hybridization because C6 H5 COOH is acid; phenol also as acid.
internal 𝑑-orbitals participate in its hybridization. 624 (c)
611 (b) 𝐶𝑖𝑠-isomer of [Pt(NH3 )2 Cl2 ] is used as anticancer
Dynamite, TNT, TNB, trinitroglycerine are drug.
explosive. 626 (b)
612 (b) [Co(en)2 Cl2 ]+ shows geometrical as well as
In Hg[Co(SCN)4 ], Co is present as Co2+ . The optical isomerism
configuration of Co2+ is given as following 628 (c)
[Ar]3𝑑 7 4𝑠 0 Lab method for preparation of benzaldehyde.
629 (a)
The ligand at least consist one donor atom having
a lone pair of electrons which it can donate to
metal atom or ion
630 (c)
Aniline is steam volatile.
∴ Magnetic moment (𝜇)=√𝑛(𝑛 + 2) 631 (a)
CFSE (crystal field splitting energy) for octahedral
√3(3 + 2) = √15 BM
complex, ∆0 depends on the strength of negative
614 (c)
ligand. Spectrochemically it has been found that
In metal carbonyls CO has ox. no. equal to zero.
the strength of splitting is as follows
615 (a)
CO > CN− > 𝑁O− 2 > 𝑒𝑛 > NH3 > 𝑝𝑦 >
[NiCl4 ]2− has tetrahedral shape. In this complex,
Ni is in the +2 oxidation state and Ni2+ ion always NCS− > H2 O > O2− > 𝑂X 2− > 𝑂H − > F − >
forms tetrahedral complexes Cl− > 𝑆𝐶N− > S2− > 𝐵r − > I−
616 (a) Therefore, magnitude of ∆0 will be highest in case
of [Co(CN)6 ]3− .
632 (b)
P a g e | 132
 K 2 [PtCl6 ] methoxy group stabilizes the carbocation
Potassium hexachloroplatinate (IV). intermediate of product(𝐿).
633 (c) 645 (c)
The complex formed by the reaction of NiSO4 , In the Grignard reaction magnesium metal forms
pyridine and NaNO2 gives [Ni(py)4 ](NO2 )2 a an organometallic bond
blue-coloured salt. Dry ether
𝑅𝑋 + Mg → 𝑅— Mg— 𝑋
634 (b) Grignard reagent
KOH(𝑎𝑞.)
C6 H5 CHO → C6 H5 COOH + C6 H5 CH2 OH 646 (a)
635 (a) Aromatic hydrocarbons are called arenes with
Only m-cresols give tribromo derivatives on general formula C𝑛 H2𝑛−6𝑦 , where 𝑛 ≮ 6 and y is
treatment with Br2 water. no. of cyclic rings. Benzene has one ring and 𝑛 =
636 (a) 6, 𝑖. 𝑒., no. of carbon atoms. Thus, general formula
[E(en)2 C2 O4 ]NO2 is C6 H6 . All other aromatic hydrocarbons are
∴ Coordination number of 𝐸 = 6 derivative of benzene.
∴ Oxidation number of 𝐸 = 3[𝐸 3+ + 0 + (−2) + 647 (c)
(−1) = 0] It is a fact.
637 (c) 648 (d)
PCl5
C6 H5 CHO → C6 H5 CHCl2 Tri and tetravalent bridges derived from methane
638 are given the prefix methyno and methyno
Complex Isomerism shown respectively
(a) [Co(en)]3+ Optical only
(b) [Ni(NH3 )5 Br]+ No geometrical
isomer
(c) 3+
[Co(NH3 )2 (en)2 ] Cis and trans
(d) [Cr(NH3 )4 (en)]3+ No geometrical
isomer
(c)
639 (c)
Presence of —NO2 at 𝑝-position increases acidic 649 (a)
character. The structure of the compound is
640 (b)
Alkanes are saturated hydrocarbons without any
functional group, hence can show chain
isomerism only
641 (d)
Both have different molecular formulae. 650 (c)
642 (b) NaOH+CaO
C6 H5 COONa → C6 H 6 .
Ni in [Ni(CO)4 ] : .....3𝑠 2 , 3𝑝 6 , 3𝑑8 , 4𝑠 2 651 (a)
Complementary colours of absorbed light are
seen.
652 (d)
Ni in [Ni(CN)4 ]2− : .....3𝑠 2 , 3𝑝6 , 3𝑑8 , 4𝑠 2 Presence of —SO3 H gp. increases solubility of
drug or dyes.
653 (d)
It is a fact.
643 (a) 654 (a)
The product (𝐾) is formed through simple The directive influence order is:
nucleophilic substitution while major product (𝐿) O− > N𝑅2 > NH𝑅 > NH2 > OH > OCH3
is formed through ~H − shift 𝑣𝑖𝑎 𝑆𝑁 1 reaction and ≈ NHCOCH3 > CH3 > 𝑋
655 (d)

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 Ti4+ : 3d0 and Cu+ ∶ 3d10 can not show 𝑑-𝑑-
transition and thus colourless.
656 (d)
Fe3+ in [Fe(CN)6 ]3− is:

657 (b)
The IUPAC name of [Ni(PPh3 )2 Cl2 ]2+ is dichloro
bis (triphenylphosphine) nickel (II).
658 (a) This is Perkin’s reaction.
It is neutral complex as it does not ionize in 672 (a)
solution state. K 4 [Fe(CN)6 ](𝑎𝑞) ⇌ 4K + (𝑎𝑞) + [Fe(CN)]4− (𝑎𝑞)
659 (b) It gives five ions in solution.
Higher is the stability constant of ligand, lesser is [Co(NH3 )6 ]Cl3 (𝑎𝑞)
its dissociation, more is its stability. ⇌ [Co(NH3 )6 ](𝑎𝑞) + 3Cl− (𝑎𝑞)
660 (c) It gives four ions in solution.
It is a fact. [Cu(NH3 )4 ]Cl2 (𝑎𝑞)
661 (d)
⇌ [Cu(NH3 )4 ]2+ (𝑎𝑞) + 2Cl− (𝑎𝑞)
Electronic configuration of Co3+ in [CoF6 ]3− is: It gives three ions in solution.
673 (a)

×× Electron pair donated by F −

662 (c)
CH3 is 𝑜–and 𝑝–directing gp.
663 (b)
Ag + has two coordination number forms complex μ1 and μ2 both for NO2 (electron withdrawing)
with excess of CN− , 𝑖𝑒 Ag(CN)2 and NH2 (electron releasing) gp. act in some
665 (c) direction.
| | 674 (b)
−C − N group is called amino Electronic configuration of Fe in Fe(CO)5 is:
| |
while – C = N group is called imino
| |

×× Electron pair donated by CO.

675 (b)
Turnbull’s blue is KFeII [FeIII (CN)6 ].
679 (c)
666 (c) Each carbon in C6 H6 is 𝑠𝑝2 -hybridized and thus,
The coordination compound [Co(en)2 Cl2 ]Cl C—C bond is 𝑠𝑝2 -𝑠𝑝2 .
doesn’t show ionization isomerism. 680 (b)
669 (d)
Change in composition of coordination sphere
Nitrogen and oxygen are common donor atoms in yield ionisation isomers
ligands 681 (a)
670 (a) The IUPAC name of K 2 [Ni(CN)4 ] is Potassium
NaOH
C6 H5 NH2 + CH3 COCl → C6 H5 NHCOCH3 tetracyanonickelate (II).
671 (c) 683 (c)
It is a characteristic fact.
684 (b)
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 K 4 [Fe(CN)6 ]4K + + [Fe(CN)6 ]4− Let oxidation state of Fe in K 2 [FeO4 ]=x
The oxidation number of Fe in [Fe(CN)6 ]4− is +2. (+1×2)+x +(4× −2)=0
Fe2+ : 1𝑠 2 , 2𝑠 2 2𝑝6 , 3𝑠 2 3𝑝6 3𝑑6 , 4𝑠 0 4𝑝 x =+6
3𝑑6 4𝑠 4𝑝 ( )
FeSO4 . NH4 2 SO4 .6H2 O
⥮ ⥮ ⥮ × × × × × × Let oxidation state of Fe in
CN CN CN CN CN CN FeSO4 . (NH4 )2 SO4 .6H2 O=x
∴ x +(−2)+2+(−2)=0
x =+2
Since, CN − is a strong field ligand, pairing occurs (d) [Fe(CN)6 ] 3−

and the hybridisation of [Fe(CN)6 ]4− is 𝑑2 𝑠𝑝 3 and Let oxidation state of Fe in

structure is octahedral. [Fe(CN)6 ]3− =x
685 (c) ∴ x +(6× −1)= −3
KOH(𝑎𝑞.) ∴ x =+3
CH3 CHClCH2 C6 H5 → CH3 CHOHCH2 C6 H5 .
1−phenyl propan−2−ol FeSO4 . (NH4 )2 SO4 has Fe in lowest oxidation
686 (d) state.
All the compounds in which there should be 693 (a)
restricted rotation about a bond in the molecule, CO is a strong ligand, all the six electrons of the
show geometrical isomerism. Oximes of the type valence shell of Cr is paired and spin only
CH3 − CH = N − OH, C6 H5 − CH = N − OH, magnetic moment=0
C6 H5 − C = N − OH and cyclic 694 (a)
| Phenol is used in carbolic soaps.
CH3 695 (d)
Werner proposed theory for complex compounds
Compound like show
to explain the structure and isomerism in them.
geometrical isomerism
696 (a)
687 (b)
It is p-block element and thus, has no tendency to
The oxidation of aniline by K 2 Cr2 O7 + H2 SO4
form complex.
(conc.) gives 𝑝-benzoquinone.
697 (a)
688 (b)
In
[CoF6 ]3− complex ion Co3+ is 𝑠𝑝3 𝑑2 hybridized. F −
is weak ligand and cannot pair up the d -electrons
so, complex is high spin. Due to four unpaired
electrons it is highly paramagnetic.
698 (b)
[Mabcd] type complexes exist in three isomeric
forms.

Here, 𝑃 and 𝑅 represent 𝑚𝑒𝑠𝑜-compound

689 (b)
Friedel-Crafts reaction involves new C— C bond.
691 (a)
Rest all show less tendency to donate electron
pair due to resonance.
692 (c)
(a) K 3 [Fe(OH)6 ] 699 (b)
Let oxidation state of Fe in Due to H-bonding.
K 3 [Fe(OH)6 ] =x 700 (d)
(+1×3)+ x +(−1×6)=0 A characteristics reaction of primary amine. This
∴ x =+3 is carbylamines reaction.
(b) K 2 [FeO4 ] 701 (d)

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 The formula of given complex are as follows: [Co(NH3 )6 ][Cr(CN)6 ] and [Cr(NH3 )6 ][Co(CN)6 ] re
(a) Hexammineplatinum (IV) chloride presents coordination isomerism.
[Pt(NH3 )6 ]Cl4 712 (c)
(b) Chloropentammine platinum (IV) chloride Co3+ and Pt 4+ = 6 coordination number
[Pt(NH3 )5 Cl]Cl3 CoCl3 .6NH3 and PtCl4 .5NH3
(c) Dichhlorotetrammine platinum (IV) chloride In solution
[Co(NH3 )6 ]Cl3 → [Co(NH3 )6 ]3+ + 3Cl−
[Pt(NH3 )4 Cl2 ]Cl2 In solution
(d) Trichlorotriammine platinum (IV) chloride [PtCl(NH3 )5 ]Cl3 → [PtCl(NH3 )5 ]3+ + 3Cl−
[Pt(NH3 )3 Cl3 ]Cl Number of ionic species are same in the solution
In aqueous solution the complex ionise is of both complexes, therefore their equimolar
[Pt(NH3 )3 Cl3 ]Cl ⇌ [Pt(NH3 Cl3 ]+ + Cl solutions will show same conductance.
Trichlorotriammine platinum (IV) 2 ions chloride 713 (a)
gives the minimum number of ions in the solution. Thiocyanato-N is the name when ligand SCN has
Hence, it has the minimum electrical conductivity. electron pair donated by N-atom to metal.
702 (c) 715 (d)
Diasteromers have different physical properties Any side chain is oxidised to −COOH.
such as m. pt, b. pt solubilities 716 (d)
703 (b) This is another reaction.
The decreasing order of priority of prefix in 717 (c)
numbering the carbon chain of an organic
compound is
Bromo > 𝐶ℎ𝑙𝑜𝑟𝑜 > 𝐼𝑜𝑑𝑜
is heterocyclic compound
719 (c)
[Cu(NH3 )4 ](NO3 )2
tetrammine copper (II) nitrate.
705 (d) 720 (c)
The structure of the compound 2, 2’-bipyridine is Nitorethane exhibits tautomerism

706 (d)
722 (c)
The electronic configuration Pt=[Xe]
4 𝑓14 , 5𝑑9 , 6𝑠1
∴ Pt 2+ = [Xe]4𝑓 14 , 5𝑑8 , 6𝑠 0
[Pt(CN)4 ]2− = [Xe]4𝑓14
Note : If a compound contains two or more
substituents then numbering is done in such a
way that the sum of the locants is the lowest
707 (c)
−N2 Cl gp. Is reduced to −H by reducing agent
∴ No unpaired electron is present in [Pt(CN)4 ]2−
C2 H5 OH/Cu.
ion.
708 (d)
723 (c)
All are the required facts for diethyl triamine.
Let the oxidation number of cobalt is x in K
709 (b)
[Pt(NH3 )4 Cl2 ]Cl2 ⇌ [Pt(NH3 )4 Cl2 ]2+ + 2Cl− . [Co(CO)4 ].
1+x+0=0
711 (b)
x =−1
When ligands are exchanged between metal
724 (b)
atoms, coordination isomerism results. Hence,

P a g e | 136
 The IUPAC name of Na3 [Co(NO2 )6 ] is sodium The number of valence electrons
hexanitrocobaltate (III). = 5+(2×5)
725 (a) = 15 𝑒 −
1.[Cu(NH3 )4 ][PtCl4 ] (b) In[Fe(NH3 )6 ]2+ ,
2.[Cu(NH3 )3 Cl] ∙ [PtCl3 (NH3 )] The number of valence electrons
3.[Cu(NH3 )2 ] ∙ [PtCl2 (NH3 )2 ] 𝑐𝑖𝑠 =6+(6×2)=6+12=18 𝑒 −
4.[Cu(NH3 )2 Cl2 ][PtCl2 (NH3 )2 ] 𝑡𝑟𝑎𝑛𝑠 (c) In [Ni(CO)6 ],
5.[Cu(NH3 )Cl3 ] ∙ [Pt(Cl)(NH3 )3 ] The number of valence electrons=10+(2× 6)=22
6.[Pt(NH3 )4 ] ∙ [CuCl4 ] 𝑒−
727 (c) (d) In [Mn(H2 O)6 ]2+ ,
Tautomerism and functional isomerism is not The number of valence electrons=5+(6×2)=17
possible together 𝑒−
732 (c) Thus, only [Fe(NH3 )6 ]2+ follows 18-electron rule.
Fe3+ + K 4 Fe(CN)6 ⟶ KFe[Fe(CN)6 ] + 3K + 740 (d)
Prussian blue
One mole of X gave depression corresponding to 2
733 (b)
moles of particles, i.e., on ionisation X gives 2
This is Cannizzaro’s reaction.
moles of ions , thus it contains only 1 ion outside
the coordination sphere and its structural formula
is [Cr(H2 O)4 Br2 ]Cl. H2 O while Y gives 3 moles of
ions, thus it contains two ions outside the
coordination sphere and its structural formula is
[Cr(H2 O)5 Cl]Br2 2
734 (a) 742 (d)
CH3 − CH2 − CH = CH3 and Both represent only one molecule and no
CH2 − CH2 isomerism.
| | 743 (a)
CH2 − CH2 Haemoglobin is porphyrin complex of ferrous iron
exhibit ring chain isomerism being coordinated to four nitrogen atoms and
735 (a) additionally coordinated to a water reversible by
Follow Werner’s theory. a molecule. The water molecule appears to be
736 (b) replaceable reversible by a molecule of oxygen to
Faraday for the first time isolated C6 H6 from coal- give oxyhaemoglobin. Fe2+ is diamagnetic due to
tar. strong field ligands.
737 (b) 746 (d)

—CN and —COOH gp. at 𝑝-position facilitate

replacement of Cl gp. by SN reactions to show
Structural isomers (position) = 2 normal SN reactions.
Stereo isomers = 4 747 (b)
738 (a) (NH4 )2 S𝑥 brings in selective reduction of one of
According to Werner’s theory, the primary the two —NO2 group at 𝑚-position.
valency of a metal is equal to the no. of charge on 748 (c)
complex ion, 𝑖. 𝑒., 3 on [Fe(CN)6 ]3− If the highest priority groups on two carbon
739 (b) atoms of the double bond are on the opposite
The complex which contains 18 valence electrons, side, the configuration is 𝐸. (Entgegen)
follows 18-electron rule.
(a) In [V(CO)5 ]

P a g e | 137
 1.In Ni(CO)4 , nickel is 𝑠𝑝3 -hybridised because in
it oxidation state of NI is zero. So, configuration of
2 2 6 2 6 8 2
28Ni=1𝑠 2𝑠 2𝑝 , 3𝑠 3𝑝 3𝑑 , 4𝑠

3𝑑8 4𝑠 2 4𝑝
749 (c) ⥮ ⥮ ⥮ ↿ ↿ ⥮
Cyclopentane possess 0°44′ angle strain which is
minimum
750 (c) 24.
[Fe(H2 O)6 ]2+ has four unpaired electrons 2.In [Ni(CN)4 ]2− , nickel is present as Ni2+, so its
configuration=1𝑠 2 , 2𝑠 2 2𝑝 6 , 3𝑠 2 3𝑝6 3𝑑8
751 (b)
3𝑑 4𝑠 4𝑝
[Pt(NH3 )6 ]Cl4 ⇌ Pt(NH3 )6 + 4Cl−
⥮ ⥮ ⥮ ↿ ↿
Ag + + Cl− ⟶ AgCl ↓
White ppt.
752 (a)

CH3 ⎯ C≡CH + Amm ∙ AgNO3 ⟶ CH3 C≡C ∙ Ag +

HNO3
∆
CH3 ∙ CH2 COOCH3 + NaOH → CH3 CH2 COONa
CN −
+ CH3 OH
is strong field ligand, hence it makes Ni2+
electrons to be paired up.

25. In [NiCl4 ]2− species, nickel is present as

Ni2+ , so its
configuration=1𝑠 2 , 2𝑠 2 2𝑝6 , 3𝑠 2 3𝑝6 3𝑑8
3𝑑 4𝑠 4𝑝
754 (b)
⥮ ⥮ ⥮ ↿ ↿
Configuration of Mn2+ is
[Ar]3𝑑 5
According to CFSE (crystal field stabilisation
energy), in excited state of Mn2+ ion, three
electrons go in 𝑡2𝑔 level (𝑑𝑥𝑦 , 𝑑𝑦𝑧 and 𝑑𝑧𝑥 ) and
two electrons go in 𝑒𝑔 level (𝑑𝑧 2 and 𝐷𝑥 2 −𝑦2 ). Cl−
755 (d)
CH3 is weak field ligand, hence Ni2+ electrons are not
| paired.
CH2 = C − CH2 − COOC2 H5 761 (d)
4 3 2 1 Ti4+ ∶ 3𝑑0
ethyl (3-methyl) but-2-enoate Cr 3+ ∶ 3𝑑3 Completely filled or empty 𝑑-
756 (c) orbitals are colourless.
𝑒g, Fe(CO)5 , Ni(CO)4 ,etc., Zn2+ ∶ 3𝑑10
757 (b) Sc 3+ ∶ 3𝑑0
Follow IUPAC rules. 762 (b)
758 (b) Possible isomers are as follows :
[Co(NH3 )6 ][Cr(C2 O4 )]3 its IUPAC name is hexa CH3
amine cobalt (III) tris (oxalato) chromate (III). |
759 (b) CH3 CH2 CH2 CH2 OH CH3 CHCH2 OH,
Gammexane is C6 H6 Cl6 . (I) (II)
760 (b)
CH3

P a g e | 138
 | Main fractions of coal-tar and the compounds
CH3 − C − OH present there in are:
| Main fraction Temp. Chief
CH3 range constituents
(III) 1. Light oil or 80- Benzene,
crude 170C toluene, xylenes,
CH3 − CH − CH2 − CH3 2. naphtha etc.
| Middle oil or 170- Phenol,
OH 3. carbolic acid 230C naphthalene,
(IV) Heavy oil or pyridine, etc.
Here, only (I), (II) and (III) are chain isomers 4. creosote oil 230- Cresols,
763 (a) Green oil or 270C naphthalene
2,2-dinitrodiphenyl or 4,4-dinitrodiphenyl is 5. anthracene quinolone, etc.
formed. oil 270- Anthracene,
764 (d) Pitch 360C phenanthrene,
We have that by breaking two bond on the chiral etc.
centre configuration changes Resid 90-94% of
765 (c) ue carbon
Use of oleum (H2 SO4 + SO3 ) produces inclusion 772 (b)
of −SO3 H gp. in C6 H6 ring. Octahedral complexes containing three bidentate
766 (a) ligands shows optical isomerism If 𝐴 is a
NO− 2 can participate in linkage isomerism because bidentate ligand then complex of type 𝑀𝐴3 show
it may be bonded to metal through nitrogen or optical isomerism
through oxygen.
[(NH3 )5 CoNO2 ]Cl2 and [(NH3 )5 CoONO]Cl2
Pentaamminenitro pentaamminenitro
cobalt (III) chloride cobalt (III) chloride
768 (c)
Cuprammonium salt, [Cu(NH3 )4 ]SO4
[Cu(NH3 )4 ]SO4 ⇌ [Cu(NH3 )4 ]2+ + SO2− 4 773 (a)
So, it will give two ions in water Cl atom attached in side chain behaves as
769 (b) aliphatic in nature.
(a) Shows tautomerism since aldehydes are more 775 (d)
stable than vinyl alcohols Due to electron deficient molecule it accepts lone
C6 H5 − CH = CHOH ↔ C6 H5 CH2 − CH2 − CH2 pair of electron to produce electrophile.
=0 AlCl3 + Cl2 ⟶ AlCl− 4 + Cl
+

(b) Does not show tautomerism because it does 777 (b)

not have hydrogens at α-positions 𝑜 –nitrophenol has intramolecular H-bonding.
( c ) Shows tautomerism because enol form is 778 (c)
stabilized by H-bonding IUPAC name is tetraammine nickel (II) –
tetrachloronickelate (II).
779 (b)
Ligands are electron pair donor.
(d) Shows tautomerism because enol form is 781 (d)
stabilized by aromatic character Cis- form of [Co(en)2 (NH3 )2 ]3+ is optically active.

771 (a)

P a g e | 139
 AlCl3
C6 H6 + CH3 COCl → C6 H5 COOCH3
790 (c)
—SO3 H is water soluble.
791 (c)
+1 × 4 + 𝑥 − 1 × 4 = 0
4 + 𝑥 − 4 = 0 ⇒ 𝑥 = 0 for Ni
792 (c)
784 (d) Follow IUPAC nomenclature.
After two interchanges at each of the two chiral 793 (b)
carbon atoms in second structure in such a way Due to bitter almond smell. It is
that CH3 group is held vertically upward and C2 H5 CH3 O(OH)C6 H3 CHO.
group vertically downward, we get first structure 795 (c)
C6 H5 COCH3 acetophenone is a mixed ketone
having one alkyl and other phenyl gp. attached

Thus, the two structures are identical

785 (c) 796 (d)
K 3 [Fe(CN)6 ] These are the facts about transition metal atoms
cation anion to act as central atom.
Oxidation state of Fe in anion =+3 798 (d)
Thus, it is potassium hexacyanoferrate (III). Since, hybridization is 𝑑𝑠𝑝 2 so, it is square planar
786 (b) 799 (b)
In [Zn(NH3 )6 ]3+ , Zn exists as Zn2+ Metal-carbon bond in metal carbonyls has σ as
10
30 Zn: 3d , 4s
2 well as π characters.
Zn2+ : 3d10 ; Thus, no unpaired electron but it is 800 (d)
outer orbital complex. The electronic configuration of Ni in
In [Co(NH3 )6 ]3+ , Co exists as Co3+ [Ni(CN)4 ]2− , [Ni(Cl)4 ]2− and Ni(CO)4 are:
7
27 Co: 3d , 4s
2 Ni2+ in [Ni(CN)4 ]2− :
Co3+ : 3d6 ; It is 𝑑2 𝑠𝑝 3 inner orbital complex with 3
electron paired in 3𝑑.
787 (a)
In [CoCl4 ]2− ion, central metal atom i.e., cobalt is Ni2+ in [Ni(Cl4 ) ]2− :
in +2 oxidation state. Hence,
7 2
27Co=[Ar]3𝑑 4𝑠
7
∴ 27Co2+=[Ar]3𝑑
⥮ ⥮ ↿ ↿ ↿
Hence, number of unpaired electrons is three as Cl Ni in [Ni(CO)4 ]:
is weak ligand.
788 (c)
Coordination number is the number of ligands in
the coordination sphere. Hence, the coordination 801 (c)
number of cobalt ion in [Co(H2 O)4 SO3 ]Cl is 5. Both produce different ions in solution state:
Let the oxidation number of Co is x. [Co(NH3 )5 Br]SO4 ⇌ [Co(NH3 )5 Br]2+ + SO2− 4
x +4(0)+(−2)+(−1)=0 [Co(NH3 )5 SO4 ]Br ⇌ [Co(NH3 )5 SO4 ]1+ + Br −
x +0−2 − 1 = 0 803 (c)
x =3 The configuration in which – OH group is on right
Number of unpaired electrons in d-orbital are 4 side, H-atom is on left side, −CHO group is on
because H2 O is a weak ligand and therefore, upper side and CH2 OH is on lower side found in
pairing of d-electrons is not possible. Fischer projection known as D-configuration
789 (b)

P a g e | 140
 816 (b)
Mn2+will have half filled more stable 𝑑 5
configuration and without distributing it an outer
orbital complex can be formed
817 (a)

Hybridi Unpair Magneti

zation ed c
electro momen
ns t
1.[Co(CN)6 ]3− 𝑑2 𝑠𝑝3 0 0
2.[Fe(CN)6 ]3− 𝑑2 𝑠𝑝3 1 √3 BM
804 (a)
3. 𝑑2 𝑠𝑝3 2 √8 BM
Linkage isomerism is shown by those complexes
[Mn(CN)6 ]3−
which have an ambidentate ligand such as 4.[Cr(CN)6 ]3− 𝑑2 𝑠𝑝3 3 √15 BM
NO− 2 , CN −
and ̅
SCN etc. In [Fe (NO ) Cl
2 3 3 ], N is donor atom while in [Fe( ONO)3 Cl3 ], O is
donor atom. Thus, least paramagnetism is in (a).
805 (c) 818 (d)
The primary valencies of Ni, in the complexes
[Ni(Cl4 )]2− and [Ni(CN)4 ]2− is same i.e., (+II).
Primary valencies are those valencies which a
metal exhibits in the formation of its simple salt,
these are non-directional. It is also referred as
2,6-dimethyl hepta-2, 5-dienoic acid oxidation state of central metal atom.
806 (d) 819 (c)
NaHCO3 reacts with acids to give CO2 from HCO− The central metal ion is Fe3+ and C2 O2−4 is
3
ion. negative bi-dentate ligand which forms more
H + + HCO− 3 ⟶H2 O + CO2 ↑ stable complex than neutral or mono-dentate
807 (a) ligand.
The species within the coordination sphere does 821 (b)
not ionize. In π-complex, organic ligands use their π system
808 (c) to bond with metal, 𝑒.g., ferrocene.
The reverse of enolic contents of compound is 823 (c)
ketonic contents. Thus, the correct order of CN− ions act both as reducing agent as well as
ketonic contents are good complexing agent
CH3 CHO > CH3 COC2 H5 > CH3 COCH3 824 (a)
> CH3 COCH2 COCH3 The order of 𝑚𝑒𝑡𝑎 directing, gp. is:
809 (b) Me3 N + > NO2 > CN > SO3 H > CHO > COCH3
The anhydrous complexes of Cu2+ 2 do not involve > COOH
𝑑-𝑑 transition and are thus, colourless. 825 (a)
810 (d) CH3 COC3 H7 can exhibit metamerism
The valence of C-atom of ring is 5 at two methyl O O CH3
gp. attachment. || || |
812 (b) CH3 − C − CH2 CH2 CH3 , CH3 − C − CH − CH3
Aniline is basic and thus, reacts with acid. and O
814 (b) ||
The Riemer-Tiemann reaction is followed by CH3 CH2 − C − CH2 CH3
dichloro carbene mechanism. 826 (d)
815 (c) It has coordination no. six and thus, octahedral or
SOCl2
C6 H5 COOH → C6 H5 COCl + SO2 + HCl ; −OH 𝑠𝑝3 𝑑2 -hybridization.
group is replaced by PCl5 , PCl3 or SOCl2 . 828 (d)

P a g e | 141
 Let the oxidation state of iron in K 4 [Fe(CN)6 ]is x.
4(+1)+x+6(-1)=0
4+x-6=0
x=+2 In compound two chiral carbon
829 (d) atoms are present
These are the methods to test complex formation. 844 (c)
830 (b) 9 mole or 9 × 22.4 litre of C2 H2 are needed.
EAN of Fe in K 3 Fe(CN)6 is: 26 − 3 + 2 × 6 = 35, 845 (b)
𝑖. 𝑒., not 36 the next inert gas. IUPAC name of sodium nitroprusside
833 (a) Na2 [Fe(CN)5 NO] is sodium pentacyanonitrosyl
Grignard reagent is a σ-bonded organometallic ferrate (III) because in it NO is neutral ligand and
compound because all the bonds present in the the oxidation number of Fe is III, which is
reagent are single bonds. calculated as
835 (b) 2×ON of Na+ ON of Fe +5×ON of CN
+1×ON of NO=0
2×(+1)+ON of Fe +5× (-1) +1×0=0
ON of Fe =5-2=+3
846 (b)
six electron pairs) available for attachment at
The electronic configuration of Ni in
central metal atom.
[Ni(CN)4 ]2− , [Ni(Cl)4 ]2− and Ni(CO)4 are :
836 (d)
Ni2+ in [Ni(CN)4 ]2− ∶
Thymol is 3-hydroxy-l-isopropyl-4-methyl
benzene (C10 H14 O), a white crystalline phenol
derivative, has smell of thyme, occurs in many
essential oils used as fragrant material as well as
mild antiseptic. Ni2+ in [Ni(Cl)4 ]2− ∶
837 (d)
Ferrocyanide ion [Fe(CN)6 ]4− is diamagnetic in
nature hence K 4 [Fe(CN)6 ] complex has zero
magnetic moment.
Ni2+ in [Ni(CO)4 ] ∶
Fe-atom 3𝑑 4𝑠 4𝑝
⥮ ↿ ↿ ↿ ↿ ⥮
Fe(II)
⥮ ↿ ↿ ↿ ↿
848 (d)
2 3 When cations have same charge but number of 𝑑-
𝑑 𝑠𝑝 hybridisation
electrons are different then the stability (or CFSE)
decreases with increase in the number of 𝑑-
electrons. Therefore, the correct order is
Fe2+ > 𝐶o2+ > 𝑁i2+ > 𝐶u2+
849 (a)
838 (a)
Oxidation state of Ni in Ni(CO)4 is zero.
CO ligand has zero oxidation state, that is why
3𝑑 4𝑠 4𝑝
[Ni(CO)4 ] is a zero valent metal complex
840 (c) ⥮ ⥮ ⥮ ↿ ↿ ⥮
A characteristic; follow ligand field theory.
842 (b)
Central ion is Cd2+ and ligand is CN − .
843 (b)

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 CO is a strong ligand. It causes pairing of SCN− a strong field ligand provides four electron
electrons. Hence, there is no unpaired electrons in to pair to show 𝑠𝑝3-hybridisation in [Co(SCN)4 ]2−
Ni(CO)4 . and thus three unpaired electrons exists on CO2+ .
850 (b) ∴ Magnetic moment = √𝑛(𝑛 + 2) = √3(3 + 2) =
Ox. no. of Cr is calculated as:
√15
3 × 1 + 𝑎 + 1 × (−2) + 4 × (−1) = 0; 𝑎 = +3 863 (d)
853 (c) But-2-ene and but-1-yne do not have same
CrO3 or CrO2 Cl2 and a mixture of K 2 Cr2 O7 + molecular formula, thus are not isomers
H2 SO4 + NaCl can also be used. CH3 − CH = CH − CH3 CH3 − CH2 − C ≡ CH
854 (b) But-2-ene but-1-yne
Butane-2 exhibit geometrical (𝑐𝑖𝑠, 𝑡𝑟𝑎𝑛𝑠) (C4 H8 ) (C4 H6 )
isomerism 864 (b)
7 2
27 Co ⟶ [Ar]3𝑑 4𝑠
Co2+ ⟶ 3𝑑7 4𝑠 0

Number of unpaired electrons = 3

865 (a)
NO in iron complexes has ox. no. equal to one.
𝑎 + 5 × 0 + 1 − 2 = 0, 𝑎 = +1
855 (a)
868 (c)
Ferrocene is a π complex Fe(5 − C5 H5 )2 .
Due to the presence of phenolic gp.
856 (a)
869 (b)
Ni in [Ni(NH3 )6 ]2+ has 𝑠𝑝3 𝑑2 (outer complex)
Ni(CO)4 has a O.N. zero for Ni
having octahedral geometry.
870 (d)
857 (d)
Because it is a polydentate ligand which binds the
These examples are ionisation isomers because of
central atom nickel forming a ring structure
chloride and sulphate ions.
871 (c)
859 (b)
Carbonyl compounds react with Grignard reagent
When ligands are arranged in ascending order of
following nucleophilic addition. More +ve is
crystal field splitting energy, ∆, they produce a
charge on C+ centre of carbonyl gp., easier is
spectrochemical series.
nucleophile attack.
In comparison to H2 O, Cl is strong σ-donor and
good π-acceptor, therefore it is a strong ligand
than H2 O. Hence, in the spectrochemical series Cl
is above than water.
860 (b)
(Positive charge on C+ is dispersed due to + 𝐼. 𝐸.
On ionization different species are formed to
of CH3 gp.)
show ionization isomerism:
[Co(en)2 (NCS)2 ]Cl ⇌ [Co(en)2 (NCS)2 ] + Cl−
[Co(en)2 (NCS)Cl]NCS
⇌ [Co(en)2 (NCS)Cl] + NCS−
861 (a) (Positive charge on C+ is dispersed more due to
Pt 2+ has square planar complexes with +𝐼. 𝐸. of two CH3 𝑔𝑝.)
coordination number four.
862 (c)
In Hg[Co(SCN)4 ], Co exists as Co2+
27 Co ∶ 3𝑑7 , 4𝑠 2
2+ (Positive charge on C+ is intensified due to −𝐼. 𝐸.
27 Co ∶ 3𝑑7
of C6 H5 gps.)

P a g e | 143
 888 (d)
system NH2 ∙ NH2 serves as monodentate as well as
of benzene nucleus following resonance bridging ligand because a 3-membered ring will
deactivates C+ centre to attack by nucleophile. be too strained to be stable.
Resonance effect overpowers over −𝐼. 𝐸. of 889 (b)
C6 H5 gp. TNT mixed with NH4 NO3 gives explosive material.
872 (d) 890 (d)
[Cr(SCN)2 (NH3 )4 ]+ shows geometrical (or 𝑐𝑖𝑠- During debromination, 𝑚𝑒𝑠𝑜-dibromobutane
𝑡𝑟𝑎𝑛𝑠) and linkage isomerism. form 𝑡𝑟𝑎𝑛-2-butene
873 (c)
CuCl + 4KCN ⟶ K 3 [Cu(CN)4 ] + KCl.
Thus, coordination no. of Cu is four.
876 (b)
The IUPAC name of the compound
[CuCl2 (CH3 NH2 )2 ] is dichloro bis-(methyl amine)
copper (II).
891 (a)
877 (b)
The IUPAC name of compound is
K 2 [Cr(CN)2 O2 (O)2 (NH3 )is
Potassium ammine dicyano dioxoperoxo

chromate (VI)
2-(1-cyclobutenyl)-1-hexane 893 (a)
879 (b) It can show ionization isomerism: [Co(NH3 )4 Cl2 ]+
Electronic configuration of [FeF6 ]3− is: and [Co(NH3 )4 Cl]2+ Cl .
894 (b)
Replacement of H-atom of ring usually takes place
following S𝐸 reaction mechanism.
×× Electron pair donated by F − 895 (b)
880 (d) Follow mechanism of Reimer-Tiemann reaction.
Effective atomic no. (EAN) = at. No. of central 896 (a)
atom –oxidation state +2 × (no. of ligands)= It is 2,4,6-trinitrophenol.
28 − 0 + 2 × 4 = 36 897 (a)
EAN = 26 − 3 + 2 × (6) = 35 Follow mechanism of cannizzaro’s reaction.
882 (d) 898 (b)
[Pt II (NH3 )2 Cl2 ] shows geometrical isomerism. Ag in Tollens’ reagent exists as Ag 2 O
2 × 𝑎 + 1 × (−2) = 0
𝑎 = +1
899 (b)
K 3 [Fe(CN)6 ]
Electronic configuration of Fe = [Ar]3𝑑 6 4𝑠 2
884 (b)
Electronic configuration of Fe3+ = [Ar]3𝑑5
Staggered and eclipsed conformers cannot be
Number of ligand (Coordination number)=6
physically separated because the energy
Nature of ligand in strong field
difference between them is so small that they
most readily interconvent at room temperature
885 (b)
A species or group of atoms can act as ligand only
when it carries an unshared pair, i.e., lone pair of
electrons.
Hybridisation of Fe is 𝑑2 𝑠𝑝 3
886 (c)
900 (d)
Follow IUPAC rules.

P a g e | 144
 Butan-2-one O The IUPAC name of a compound is written as
|| single word
CH3 − C − CH2 − CH3 is not isomeric with 913 (c)
diethyl ether CH3 CH2 − O − CH2 − CH3 . Because CH2=CH— CH2 Cl ↔ ClCH2 — CH=CH2.
both are differing in molecular formula 914 (c)
902 (d) [Co(NH3 )3 Cl3 ] does not have optical isomers
because it is of formula 𝑀𝐴3 𝐵3 which does not
show optical isomerism
915 (b)
Ethylenediamine is a bidentate ligand.

916 (b)
CFSE = 3𝛌(−0.4)∆0 + 0.6(∆0 ) = 0.6 ∆0 Electron withdrawing nature or –𝐼𝐸 increases the
905 (b) activation of ring more effectively, however
Only carbonyl compounds show this test. resonance opposes inductive effect for
906 (c) attachment at 𝑜-and 𝑝-position and hence, makes
Presence of 𝑚𝑒𝑡𝑎 directing gp. Deactivates ring less deactivation for 𝑜-and 𝑝-positions.
for Friedel-Crafts reaction. 918 (d)
907 (c) All involves 𝑠𝑝3 -hybridization.
Ni(CO)4 and Ni(PPh3 )2 Cl2 are tetrahedral in
919 (b)
geometrical shape, because coordination number Chaisen condensation involves condensation of
of Ni is four in both cases.
benzaldehyde with aliphatic aldehydes or ketones
908 (c) having two α-H-atoms, 𝑒. g.,
Geometrical isomers (𝑐𝑖𝑠 and 𝑡𝑟𝑎𝑛𝑠) and linkage
isomers (−SCN and − CNS).
909 (a)
The absorption of energy of the observation of
920 (d)
colour in a complex transition compounds
All are transition elements with 𝑑-orbitals not
depends on the charge of the metal ion and the
filled to capacity.
nature of the ligands attached. The same metal ion
921 (a)
with different ligands shows different absorption
Ag(II) has a 𝑑 9 -configuration and must contain
depending upon the type of ligand. The presence
unpaired electron but AgOis diamagnetic because
of weak field ligands make the central metal ion to
AgO does not contain Ag(II) but is a mixed oxide
absorb low energies 𝑖𝑒, of higher wavelength. The
of Ag I AgIII O2.
field strength of ligands can be obtained from
922 (c)
spectrochemical series, 𝑖𝑒,
Friedel-Crafts reaction involves alkylation or
(weak field) I − < Br − < S2− < Cl− < NO− 3 <
− −
acylation in benzene nucleus using alkylating or
F < OH
acylation reagents in presence of anhy. AlCl3 .
< H2 O < NH3 < NO2 < CN − < CO (strong field)
924 (b)
911 (d)
2C6 H6 + 2HCl + O2 → 2C6 H5 Cl + H2 O
The total number of monodentate ligands
925 (a)
attached to the central metal is known as
CoCl2 is a weak Lewis acid, reacting with chloride
coordination number. Hence, in [Cu(H2 O)4 ]2+
ions to produce salt containing the terrahedral
coordination number of Cu atoms is 4.
[CoCl4 ]2− ion. CoCl2 is blue when anhydrous, and a
912 (c)
deep magenta colour when hydrated, for this
Prefixes and suffixes are written before and after
reason it is widely used as an indicator for water
the root word respectively and not before and
926 (c)
after the compound

P a g e | 145
 Octahedral complexes of the type 𝑀𝐴5 𝐵 do not 1. Light oil or 80- Benzene,
show geometrical isomerism. crude 170C toluene, xylenes,
927 (b) 2. naphtha etc.
NaOH
C6 H5 COOC2 H5 → C6 H5 COONa + C2 H5 OH Middle oil or 170- Phenol,
928 (d) 3. carbolic acid 230C naphthalene,
Heavy oil or pyridine, etc.
4. creosote oil 230- Cresols,
In this compound is principal
Green oil or 270C naphthalene
functional group
5. anthracene quinolone, etc.
While – CHO is substituent group, hence
oil 270- Anthracene,
Pitch 360C phenanthrene,
etc.
Resid 90-94% of
ue carbon
939 (c)
929 (b)
The coordination number (C.N.) of a metal atom
C6 H5 CH2 NH2 has least negative inductive effect
in a complex is the total number of bonds formed
and thus shows more basic nature.
by metal with ligands.
930 (d)
In case of tetrahedral complexes the number of
bonds formed between metal and ligand is four.
So, coordination number is also four.
940 (b)
Due to resonance bond length become identical
Note : The prefix in a compound should be and is 1.40 Å. Whereas in alkane C—C bond is
arranged in alphabetical order 1.54 Å and in alkene it is 1.34 Å.
931 (d) 941 (d)
All possess lesser number of unpaired electrons. C=O + H2 NNHC6 H5 ⟶ C=NNHC6 H5
932 (d) All reagents do so.
A monodentate ligand has one donor site 944 (c)
available for coordination. Electrophilic substitution occurs at electron rich
933 (a) centres usually at 𝑜- and 𝑝-positions. The ring
It is benzene. attached with −NH will develop more electron
934 (c) density at 𝑜- and 𝑝-positions. Since 𝑜-position is
Cl2 blocked, thus electrophile will attach at 𝑝-
C6 H5 CHO → C6 H5 COCl
935 (c) position.
Phenol is weak acid. 945 (b)
936 (b) Follow text.
The coordination number in [FeF6 ]3− is 6, hence it 946 (a)
is a octahedral complex In the formation of 𝑑2 𝑠𝑝3 hybrid orbitals, two
937 (d) (𝑛 −1)𝑑 orbitals of 𝑒𝑔 set i.e., (𝑛 − 1) 𝑑𝑧 2 and (𝑛 −
AgCl + 2NH ⟶ [Ag(NH ) ]Cl 1)𝑑𝑥 2 −𝑦2 orbitals, one
3 3 2
Soluble
𝑛𝑠 and three 𝑛𝑝(𝑛𝑝𝑥 , 𝑛𝑝𝑦 and 𝑛𝑝𝑧 ) orbitals
938 (a)
combine together and form six 𝑑2 𝑠𝑝3 hybrid
Main fractions of coal-tar and the compounds
orbitals.
present there in are:
947 (a)
Main fraction Temp. Chief
EAN of Fe = 26 − 2 + 6 × 2 = 36.
range constituents
948 (a)
K[Pt(NH3 )5 Cl5 ] ⇌ K + + [Pt(NH3 )5 Cl5 ]−
949 (b)
3KCl + CuCl ⟶ K 3 [CuCl4 ]; this is soluble in water.

P a g e | 146
950 (d) (CN− reduces Cu2+ to Cu+ )
All are characteristics tastes for phenol. 961 (c)
952 (c)
N cannot have more than 8 elements in its valence
shell. In the double bonds are 𝑡𝑟𝑎𝑛𝑠 and
953 (b) 𝑐𝑖𝑠. The first and third bonds are identical
Tautomeric structures of a molecule are not the 963 (a)
resonating structures of the molecule 𝑝 –nitrophenol is most acidic (among these) as it
954 (a) has electron withdrawing −NO2 gp.
2, 4, 6-trinitrophenol is strong acid than acetic 965 (c)
acid but phenol is less acidic than acetic acid. Geometrical isomerism is found in compounds
955 (a) having coordination no. 4 (square planar and not
Phenol being weak acid does not react with aq. tetrahedral shape) as well as coordination no. 6.
NaHCO3 . Coordination no. 4 (square planar)
956 (c) 𝑀𝐴2 𝐵𝐶 , 𝑀𝐴2𝐵2
If two atoms directly attached to the double bond Showing geometrical isomerism 𝑀𝐴𝐵𝐶𝐷
have the same atomic number, then the elative Coordination no. 6 (octahedral)
priority of the groups is determined by a similar 𝑀𝐴4 𝐵2 , 𝑀𝐴4𝐵𝐶
comparison of the atomic numbers of the next Showing geometrical isomerism.
elements in the groups. Thus, the preference 𝑀𝐴3 𝐵3 , 𝑀(𝐴𝐴)2𝐵2
order of given group is 966 (d)
OCH3 > OH > COOH > CHO Follow crystal field theory.
957 (a) 967 (d)
Follow IUPAC name. Due to resonance C6 H6 is stabilized and normal
958 (a) addition reactions (except addition of H2 , Cl2 and
It possesses 𝑑8 configuration of Ni2+. ozonolysis) are not observed in C6 H6 .
959 (d) 969 (b)
There are four structural isomers possible for EAN of Pt in [PtCl6 ]2− = 86
diphenyl methane when one H-atom is replaced 971 (b)
by a Cl-atom CuCl + NH3 ⟶ [Cu(NH3 )2 ]Cl. The coordination
no. = No. of ligands attached.
972 (a)

Longest system : 1,2,3,4,5,6

Next longest system : 6,7,8,1
Shortest system : 1,6
The IUPAC name of compound is
8-methyl bicyclo [4,3,0] nonane
973 (b)
Aniline on condensation with aromatic aldehyde
960 (c)
gives Schiff’s base.
CN− is a better complexing agent (C) as well as a
974 (c)
reducing agent(A)
Organometallic compounds are those compounds
Thus, properties (A) and (C) are shown.
in which metal is directly attached to the carbon
Property (C ):Ni2+ + 4CN − ⟶ [Ni(CN)4 ]2−
atom. In sodium ethoxide, sodium attached to
Property(A):
oxygen atom, hence it is not an organometallic
II I
1 compound.
CuCl2 + 5KCN ⟶ K 3 [Cu(CN)4 ] + (CN)2 + 2KCl
2 975 (d)
P a g e | 147
 (i) CH3 CH2 CH2 CH2 CH2 OH Effective atomic no. (EAN) = at. No. of central
and atom –oxidation state +2 × (no. of ligands)=
CH3 CH2 CH2 − CH − CH3 28 − 0 + 2 × 4 = 36
| EAN = 28 − 2 + 2 × 4 = 34.
OH 983 (b)
are Position isomers Due to restricted rotation about the carbon-
carbon single bond joining the two phenyl groups,
the molecule as a whole is chiral and thus shows
optical isomerism
984 (b)
Due the presence of asymmetry, optical Any side chain is oxidised to COOH gp.
isomerism is possible 985 (d)
(iii) CH3 CH2 CH2 CH2 CH2 OH and These are facts about glycinato ligand.
CH3 CH2 OCH2 CH2 CH3 are functional isomerism 986 (c)
976 (c) According to Werner’s theory, only those ions are
Co3+ and Pt 4+ have 6 coordination number. precipitated which are attached to the metal
CoCl3 . 6NH3 and PtCl4 . 5NH3 atoms with ionic bonds and are present outside
In solution
[Co(NH3 )6 Cl3 → [Co(NH3 )6 ]3+ + 3Cl− the coordination sphere.
In solution 987 (d)
[PtCl(NH3 )5 Cl3 → [PtCl(NH3 )5 ]3+ + 3Cl−
𝑠𝑝2 -hybridization leads to planar hexagonal
Number of ionic species are same in the solution
shape.
of both complexes, therefore their equimolar
988 (a)
solutions will show same conductance.
Coordination isomerism is caused by interchange
977 (a)
of ligands with the metal atoms.
Organometallic compounds are those compounds
989 (c)
in which carbon atom is directly linked to metal.
Chlorophyll are green pigment in plant and
But in sodium ethoxide as oxygen is attached to
contain magnesium instead of caleium
attached to sodium metal so, it is not a
991 (a)
organometallic compound
C6 H5 NH2 + Cl2 OC ⟶ C6 H5 N=C=O + 2HCl
978 (d)
992 (a)
[Cu(H2 O4 )]SO4 . H2 O coordination number of Cu is HBr
4. C6 H5 OC2 H5 → C6 H5 OH + C2 H5 Br
979 (b) 993 (d)
Sodium nitroprusside is Na2 [Fe(CN)5 NO]. [Fe(NH3 )4 . Cl2 ]Cl
980 (d) Tetraammine dichloro ferrum III chloride.
2 3 994 (b)
NH2 − CH − CH2 OH 2 6
28Ni=[Ar] 3𝑠 3𝑝 4𝑠 3𝑑
2 8

| 2+ 2
Ni = [Ar] 3𝑠 3𝑝 3𝑑 6 8

COOH
1
2-amino-3-hydroxy propanoic acid
981 (a)
[CoF6 ]3− is an outer orbital complex ion. It
involves outer orbital hybridisation. It has 𝑠𝑝 3 𝑑2- Nickel has two unpaired electrons and geometry
hybridisation because F − is a weak ligand. is tetrahedral due to 𝑠𝑝3 hybridisation.
995 (c)
It is a test for −NH2 gp attached on benzene
nucleus following diazotisation and coupling
reaction.

982 (b)

P a g e | 148
 100 (c)
1 Aniline is base.
100 (c)
2 Two COOH on vicinal carbon atom lose H2 O on
heating.

100 (c)
3 Benzene has 6 C—C, 6 C—H σ-bonds and 3C=Cπ-
bonds.
100 (b)
4 Rest all have plane of symmetry.
100 (b)
6 The number of unpaired electrons in complex
[Pt(NH3 )2 ]Cl2 are two.
100 (c)
7 Geometrical isomerism is found in compounds
997 (a) having coordination no. 4 (square planar and not
2.675
Mole of CoCl3 . 6NH3 = =0.01 tetrahedral shape) as well as coordination no. 6.
267.5
AgNO3 (𝑎𝑞) + Cl− (𝑎𝑞) ⟶ AgCl ↓ (white) Coordination no. 4 (square planar)
4.78 𝑀𝐴2 𝐵𝐶 , 𝑀𝐴2𝐵2
Moles of AgCl= =0.03.
143.5 Showing geometrical isomerism 𝑀𝐴𝐵𝐶𝐷
1. mole CoCl3 . 6NH3 gives =0.03 mol
Coordination no. 6 (octahedral)
AgCl
𝑀𝐴4 𝐵2 , 𝑀𝐴4𝐵𝐶
∴ 1 mole CoCl3 . 6NH3 ionizes to gives =3 mol Cl− Showing geometrical isomerism.
𝑀𝐴3 𝐵3 , 𝑀(𝐴𝐴)2𝐵2
Hence, the formula of compound is 100 (c)
[Co(NH3 )6 ]Cl3 . 8 According to the modern view primary valency of
complex compound it its oxidation number while
998 (b)
secondary valency is the coordination number
Electronic configuration of Cr in [Cr(H2 O)6 ]3+ is :
100 (c)
1𝑠 2 , 2𝑠 2 2𝑝6 , 3𝑠 2 3𝑝 6 3𝑑3 .
9 The IUPAC name of K 4 [Ni(CN)4 ] is potassium
tetracyanonickelate (0).
101 (b)
0
×× Electron pair donated by H2 O
999 (c)
The stabilishing effect of enolic form is the
intramolecular hydrogen bond present in enols.
This provides another source of increasing
bonding and hence, increased stabilization.
Thus,

Mirror image
is more stable
is not superimposable hence, optical isomerism is
100 (c)
possible.
0 Each en has two coordinate bonds; each Br has
101 (a)
one coordinate bond.
1

P a g e | 149
 S-atom is donor in SCN and N-atom is donor in
NCS. The linkage isomerism arises when Iigand
has two possibilities to attach on central atom.,
101 (d)
2 Ethane has an infinite number of conformation
but staggered and eclipsed are preferred. Ethane 101 (a)
molecule would exist in the staggered 9 Ni in [Ni(H2 O)6 ]2+has two unpaired electrons in
conformation due to its minimum energy and it.
maximum stability 102 (d)
101 (a) 4 An electron attracting group (−NO2 ) disperses
4 Follow IUPAC rules the negative charge on phenoxide ion and thus,
101 (d) makes it more stable or increases the acidic
5 The complex in which nd orbitals are used in character of phenol. The substitution is more
hybridisation, are called outer orbital complex. effective at 𝑝-position than in the 𝑚-position as
26. [Fe(CN)6 ]4− = the former involves a resonating structure
bearing negative charge on the carbon attached to
the electron withdrawing group. Also presence of
electron repelling gp. (−CH3 ) intensifies the
negative charge on phenoxide ion and thus, makes
27. phenol less acidic.
102 (d)
[Mn(CN)6 ]4− = 6 NaOH
2C H CHO →
6 5 C H COOH + C H CH OH
6 5 6 5 2
Oxidised Reduced
102 (c)
9 Let the ON of Pt in[Pt(NH3 )5 Cl]Cl3 is x.
x +5×(0)−1 −3=0
28. x −4=0
x=+4
[Co(NH3 )6 ]3+ = 103 (a)
0 Organometallic compounds have carbon-metal
bond, hence CH3 Mgl, tetraethyl tin and KC4 H9 are
organometallic compounds while C2 H5 ONa is not
an organometallic compound due to absence of
29. carbon-metal bond.
[Ni(NH3 )6 ]2+ = 103 (b)
1 Optical isomers of a compound which are non-
superimposable but related to each other as an
object and its mirror are called enantiomers

101 (d)
6 In each case aromatisation leads to formation of
C6 H 6 . 103 (d)
101 (a) 2 All involve 𝑑𝑠𝑝2-hybridization.
7 C H Cl →
H2 −Ni or Al/NaOH
C H ; 103 (a)
6 5 6 6
101 (b) 3 𝐶𝑖𝑠- isomer of [Pt(NH3 )2 Cl2 ] is used as an
8 𝛽-keto acids undergo decarboxylation most easily anticancer drugs for treating several type of
on heating. malignant tumours when it is inject into the blood
stream the more reaction Cl groups are lost so,
the Pt atom bonds to a N-atom in guanosine (a

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 part of DNA). This molecule can bond to two [Co(NH3 )6 ]Cl3 gives four mole of ions on
different guanosine units and by bridging complete ionisation.
between them it upsets the normal reproduction [Co(NH3 )6 ]Cl3 ⇌ [Co(NH3 )6 ]3+ + 3Cl−
of DNA 104 (a)
103 (a) 2 It is a reason for the fact.
4 104 (d)
3 Halogens no doubt 𝑜-and 𝑝-directing gp. but they
deactivate the ring.
104 (a)
4 In metal carbonyls CO has ox. no. equal to zero.
104 (d)
5 The dihedral angle is 60°
104 (b)
6 𝑝 𝐾𝑎 are 10.21, 10.14 and 7.15 respectively.
These are coupling reactions.
104 (d)
103 (a)
7 (i) CH3 CH2 CH2 CH2 OH (ii) CH3 CH2 − CH − CH3
5 In K 4 Fe(CN)6 , the species retains its identity in
|
solid as well as solution state
OH
103 (c)
CH3 CH3
6 The formula of dichlorodioxalatochromium (III) is
| |
[Cr(Cl2 )(ox)2 ]3−
(iii) CH3 − CH − CH2 OH (iv) CH3 − C − OH
Primary valency of a metal (Cr)in the complex
|
≡ oxidation number of that
CH3
metal
104 (c)
= +3
8 Na2 [Fe(CN)5 NO]
Secondary valency of chromium in complex
Sodium pentacyanonitroso ferrate (II).
=coordination number
104 (d)
=+6
9 Na+ does not possess the tendency to form
(∵ Coordination number is the number of ligands
complex ion because of non-availability of 𝑑-
attached to the central metal ion and oxalate ion
orbitals.
is a bidentate ligand i.e., can coordinate at two
105 (b)
positions)
0 In the complex K 2 Fe[Fe(CN)6 ] both the iron
103 (a)
atoms are present in same oxidation state
7 Friedel-Crafts reaction involves alkylation or
105 (c)
acylation in benzene nucleus using alkylating or
1 Carbon bonded with four different groups is
acylating reagents in presence of anhy. AlCl3 .
known as chiral carbon atom. In case of given
103 (d)
compound
8 According to IUPAC system, the IUPAC name of a
compound is written as single word as far as
possible
103 (b)
9 O O
|| || The number of chiral carbon atoms are two
CH3 − C − CH2 − C − OC2 H5 ⇌ 105 (a)
(keto) 2 [Co(NH3 )3 Cl3 ] does not give a precipitate with
OH O AgNO3 solution because all the chloride ions are
| || non-ionizable.
CH3 − C = CH − C − OC2 H5 [Co(NH3 )3 Cl3 ] ⇌does not ionise
(enol) 105 (c)
104 (a) 3
0

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 The IUPAC name of the compound forms. This form of tartaric acid is optically
[Co(NH3 )5 Cl]Cl2 is pentaammine chloro cobalt inactive due to external compensation
(III) chloride. 106 (d)
105 (c) 1 −NH2 gp. is highly susceptible to oxidant (HNO3 )
4 The electronic configuration of and thus, first protected by acetylation.
Ni in [Ni(CN)4 ]2− , [NiCl4 ]2− and Ni(CO)4 are as 106 (d)
following 2 All are the required facts for bridging ligands.
Ni in [Ni(CN)4 ]2− 106 (a)
3 C6 H5 COOH is monobasic acid;
Mol. wt. = Eq. wt.
106 (d)
4 Cannizzaro’s reaction.
Ni2+ in [NiCl4 ]2−
106 (b)
5 NO is in NO+ form.
Let the oxidation state of Fe is x
x +0⨯5+(+1)=+2
Ni in [Ni(CO)4 ] x =2−1
x =+1
Hence, the oxidation number of Fe in brown ring
[Fe(H2 O)5 NO]2+ is +1.
106 (a)
CO and CN − are strong ligands so, they induces 6 Cr 3+ : 1𝑠 2 , 2𝑠 2 2𝑝6 , 3𝑠 2 3𝑝6 3𝑑3 . 𝑇ℎ𝑒 3𝑑1𝑥𝑦 , 3𝑑1𝑥𝑧 , 3𝑑1𝑦𝑧
pairing of electrons so, their complexes are has lower energy.
diamagnetic which, Cl− is a weak ligand so, it does 106 (a)
not induce the pairing of electrons so, its complex 7 Number of moles of pentaaqua chloro chromium
is paramagnetic III chloride in the solution.
105 (b) 0.01×100
𝑛= =0.001
5 Presence of CH3 gp. (an electron repelling group) 1000

decreases acidic character in benzoic acid. 1 mole of [Cr(H2 O)5 Cl]Cl2 gives 2 moles of
Presence of electron withdrawing gps. chloride ions.
(NO2 , Cl, SO3 H) increases the acidic nature. Moles of chloride ions =0.001 ×2=0.002
105 (a) Mass of AgCl produced =0.002 ×143.5
6 Ni(CO)4 is a tetrahedral complex and is =287.0× 10−3 g
diamagnetic due to the absence of unpaired 106 (c)
electron. 8 The four isomers are:
105 (d) [Cu(NH3 )4 ][PtCl4 ], [Cu(NH3 )4 Cl]
7 Such a carbon atom to which four different atoms [PtCl3 (NH3 )]; [Pt(NH3 )3 Cl][CuCl3 (NH3 )], [Pt(NH3
or groups are attached is called asymmetric .
carbon 106 (c)
H D 9 Both optical isomerism and geometrical
| | isomerism are examples of stereoisomerism.
CH3 − C − C − CH3 107 (d)
|* |* 0 [Ni(NH3 )4 ]SO4
Br OH 𝑥 0 −2
105 (d) 𝑥 + 0 + (−2) = 0 ⇒ 𝑥 = +2 is valency and 4 is
9 Coordination sphere is interchanged. C.N. of Ni
106 (a) 107 (d)
0 Racemic tartaric acid is optically inactive due to 1 C6 H5 CHO does not reduce Fehling’s solution.
external compensation. Racemic tartaric acid is an 107 (d)
equimolar mixture of optically active 𝑑- and 𝑙- 3 𝑛-butane can exist in an infinite number of
conformations

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107 (a)
4 This is correct order of acidic nature of
nitrobenzoic acids. Also follow ortho effect. [CoF6 ]3− ion 3𝑑
107 (d) ⥮ ↿ ↿ ↿ ↿
7

is dispersed due to electron releasing nature of

methoxy group.
108 (c)
0 An organometallic compound is considered as a
substance contains a carbon-metal bond e.g.,
Al2 (CH3 )6 . F − is a weak ligand. It cannot pair up electrons
108 (c) with d-subshell and forms outer orbital
1 Picramide is 2, 4, 6-trinitroaniline. octahedral complex.
108 (d)
(b) [Co(NH3 )6 ]3+ ion
2 Except alkynes, chain isomerism is observed
when the number of carbon atoms is four or more
than four
108 (d)
3 The isomerism which arises due to restricted
rotation about a bond in a molecule is known as
geometrical isomerism 4𝑑

All of these form geometrical isomers

(c) [Fe(CN)6 ]3+ ion
108 (a)
4 The choice of principal functional group is made
on the basis of the following order
Carboxylic acid > sulphonic acid > anhydride >
esters > acid halide > acid amide > nitrile >
aldehyde > ketone > alcohol > amine
108 (d)
5 [Pt(NH3 )Cl2 Br]Cl ⇌ [Pt(NH3 )Cl2 Br]+ + Cl−
Cl− + Ag + ⟶ AgCl 4𝑑
108 (b)
7 −COOH gp. reacts with NaHCO3 to give
effervescence.
108 (d) (d) [Cr(NH3 )6 ]3+ ion
8 Fe/H2O2 (𝑣)
C6 H5 NO2 → C6 H5 NO
108 (c)
9 Complex ion Hybridisation of central atom
[Fe(CN)6 ]4− 𝑑 2 𝑠𝑝3 (inner)
[Mn(CN)6 ]4− 𝑑 2 𝑠𝑝3 (inner)
[Co(NH3 )6 ]3+ 𝑑 2 𝑠𝑝3 (inner)
4𝑑
[Ni(NH3 )6 ]2+ 𝑠𝑝3 𝑑2 (outer)
109 (a)
0 Electronic configuration of 𝐶𝑜 2+ ion NH3 and CN− are strong ligands. So, they form
(a) their inner orbital complex.
3𝑑 4𝑠 0 3𝑝 109 (c)
⥮ ↿ ↿ ↿ ↿ 1 The name of complex is
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 Carbonylchlorobistransphosphineiridium (I). 110 (c)
109 (a) 6 The compound will be numbered as and can be
3 Coordination isomerism is caused by the named as unbranched assembles containing 3 or
interchange of ligands between complex cation more identical cycles
and complex anion
109 (c)
4 Due to bitter almond smell.
109 (b)
5 Compounds which do not show optical activity
inspite of the presence of chiral carbon atoms are
called 𝑚𝑒𝑠𝑜-compounds
110 (c)
109 (d)
7
6 mmol of complex =30×0.01 =0.3 Also, 1 mole of
complex [Cr(H2 O)5 Cl]Cl2 gives only two moles of
chloride ion when dissolved in solution.
[Cr(H2 O)5 Cl]Cl2 ⟶ [Cr(H2 O)5 Cl]2+ + 2 Cl−
⇒mmol of Cl− ion produced from its 0.3 mmol The gauch conformation is most stable due to
=0.6 presence of H-bonding between H atom of OH and
Hence, 0.6 mmol of Ag + would be required for Cl
precipitation. 110 (c)
⇒ 0.60 mmol of Ag +=0.1 M ×V (in mL) 8 The electronic configuration of Ni in
⇒ V=6 mL [Ni(CN)4 ]2− , [Ni(Cl)4 ]2− and Ni(CO)4 are :
109 (c) Ni2+ in [Ni(CN)4 ]2− ∶
7 This is Kekule’s view for C6 H6 structure.
109 (c)
8 C = O double bond of a carbonyl group is a
stronger bond (> C = O, 364 kJ/mol) than the C =
C bond strength 250 kJ/mol) of the enol. Thus, Ni2+ in [Ni(Cl)4 ]2− ∶
CH3 COCH3 is more stable
109 (b)
9 Effective atomic number (EAN) =Atomic no. of
metal Ni2+ in [Ni(CO)4 ] ∶
-Oxidation no.+ Coordination no.×2
For[CoF6 ]2− , the oxidation state of cobalt is 4.
EAN=(27-4)+6×2
=23+12=35
110 (d) 110 (a)
3 Metal atom or cation acts as Lewis acid or 9 Follow IUPAC rules.
electron pair acceptor. 111 (b)
110 (c) 0 Cd has no unpaired electron in [CdCl4 ]2− ion.
4 The nitration of C6 H6 does not occur at room 111 (d)
temperature. The solution becomes dark red due 1 It is a fact.
to absorption of NO2 given out by HNO3 . 111 (a)
110 (c) 2 On ionization it gives maximum number of (four)
5 [Co(en)2 NO2 Cl]Br exhibits linkage isomerism ions.
because the NO2 group can exist as nitrito (— 111 (a)
ONO) and nitro (—NO2 ) group. The linkage 3 Chlorophyll contains Mg, hence (a) is incorrect
isomers of [Co(en)2 NO2 Cl]Br are as statement.
[Co(en)2 NO2 Cl]Br and [Co(en)2 ONOCl]Br. 111 (b)
4 [Co(NH3 )5 Cl]2+ + 2Cl− ⟶ [Co(NH3 )5 Cl]Cl2

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111 (b) 31. There are three unpaired electrons, hence
5 Linkage isomerism is caused due to presence of paramagnetic, thus correct.
ambidentate ligands. 32. 𝑑2 𝑠𝑝3 -inner orbital complex, thus
[Pd(PPh3 )2 (NCS)2 ]and [Pd(PPh3 )2 (SCN)2 ] are incorrect
33. Due to ionisable Cl− ions, white precipitate
linkage isomers due to SCN, ambidentate ligand. with AgNO3 , thus correct.
111 (a) Therefore, (c) is wrong.
6 HI
C H OCH → C H OH + CH I 112 (c)
6 5 3 6 5 3
111 (c) 5 NO+ 2 attacks at 𝑜𝑟𝑡ℎ𝑜-𝑝𝑎𝑟𝑎 for (P) w. r. t. OH
7 C6 H5 NH2 + KOH + (𝑌) ⟶ C6 H5 NC ;(𝑌) is CHCl3 ; NO+ 2 attacks at 𝑜𝑟𝑡ℎ𝑜-𝑝𝑎𝑟𝑎 for (Q) w. r. t. CH3 and
(𝑌) is formed from (𝑍) + Cl2 + Ca(OH)2 and OCH3 both
thus,(𝑍) is CH3 COCH3 . NO+ 2 attacks at 𝑜𝑟𝑡ℎ𝑜-𝑝𝑎𝑟𝑎 for (S) with respect to
111 (d) −OCOC6 H5
8 Halogen attached on side chain behaves as in 112 (c)
aliphatic molecule. 6 Follow molecular orbital theory for C6 H6 .
111 (a) 112 (d)
9 MO theory reveals bond order in C6 H6 lies in 8 5KBr(𝑎𝑞. ) + KBrO3 (𝑎𝑞. ) ⟶ 3Br2 (𝑎𝑞. )
between 1 and 2. or 5Br − + Br 5+ ⟶ 3Br20
112 (a)
0 [Co(NH3 )5 SO4 ]Br + AgNO3 ⟶ [Co(NH3 )5 ∙
SO4 ] + AgBr
0.02mol (Y)
[Co(NH3 )5 Br]SO4 + BaCl2
⟶ [Co(NH3 )5 Br]Cl2 + BaSO4
0.02mol (Z)
On using one liter solution we will get 0.01 mole 𝑌 112 (d)
and 0.01 mole 𝑍 9 The number of atoms of the ligand that are
112 (c) directly bounded to the central metal atom or ion
2 Metal-metal (Fe-Fe) bond pairs up the unpaired by coordinated bond is known as the coordination
electrons. number of the metal atom or ion. Coordination
112 (b) number of metal =number of 𝜎 bonds formed by
3 Follow IUPAC rules. metal with ligand
112 (c) 113 (c)
4 [𝐶𝑟(𝑁𝐻3 )6 ] 𝐶𝑙3 ⇌ 0 Follow MO diagram for C6 H6 .
Coordinate sphere Ionisable 113 (b)
AgNO3 2 [Fe(H2 O)6 ]2+ has four unpaired electrons;
[Cr(NH3 )6 ]3+ + 3Cl− → AgCl ↓
[Cr(H2 O)6 ]3+ , [Cu(H2 O)6 ]2+ and [Zn(H2 O)6 ]2+
white precipitate
have 3, 1, 0 unpaired electrons, respectively.
Cr(24)[Ar]3𝑑5 4𝑠1
113 (a)
Cr 3+ [Ar]3𝑑3 4𝑠 0
3 Larger is the ligand, less stable is metal-ligand
3d 4s 4p
3+ bond.
Cr [Ar] ↿ ↿ ↿
113 (c)
4 Both produces different ions in solution state
[Cr(NH3 )6 ]3+ [Ar]
[Co(NH3 )4 Cl2 ]NO2 ⇌ [Co(NH3 )4 Cl2 ]+ NO− 2
[Co(NH3 )4 Cl ∙ NO2 ]Cl
⇌ [Co(NH3 )4 Cl ∙ NO2 ]+ + Cl−
113 (a)
5 The name of reaction is Baeyer-Villiger oxidation.

× Indicates lone-pair of NH3 donated to Cr

30. 𝑑2 𝑠𝑝3 hybridisation, octahedral, thus, 113 (d)
correct. 6
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 Pyridine undergoes S𝐸 reactions at 3-position but On the contrary 𝑜- and 𝑝-directing groups in
under vigorous conditions, nitration, nucleus increase the electron density at 𝑜- and 𝑝-
sulphonation and halogenation occurs only at position.
300C. Friedel-Crafts reaction is not observed in
pyridine because electron pair on N-atom (Lewis
base) form complex with AlCl3 (Lewis acid) and
a+ve charge on N-atom so produced decreases
the activity of pyridine for S𝐸 reaction.
113 (d)
7 2Cl− ions are inisable Thus, presence of 𝑜- and 𝑝-directing groups
∴ [Co(NH3 )5 Cl]Cl2 ⇌ ⏟[Co(NH3 )5 Cl]2+ + 2Cl− provide seats for SE reactions or activates the
3 ions ring, whereas presence of 𝑚-directing groups
2Cl− + 2AgNO3 ⟶ 2AgCl + 2NO− 3 does not activate the ring and thus, deactivate the
113 (d) ring for SE reactions.
8 Benzene is very good solvent. 114 (a)
113 (a) 4 Aniline is basic.
9 Salol is phenyl salicylate and is used as antiseptic. 114 (d)
114 (a) 5 Ferrocene is diphenyl iron complex.
0 −NO2 gp. is deactivating gp. for SE reaction. 114 (c)
114 (d) 6 Effective atomic number (EAN)
1 Geometrical isomerism is found in compounds = Atomic no. –O.S. +2 × C.N.
having coordination no. 4 (square planar and not = 28-0+2×4
tetrahedral shape) as well as coordination no.6. = 28+8
Coordination no. 4 (square planar) = 36
𝑀𝐴2 𝐵𝐶 , 𝑀𝐴2𝐵2 ., 114 (d)
Showing geometrical isomerism 𝑀𝐴𝐵𝐶𝐷 . 8 [CO(en)2 Cl2 ] forms optical and geometrical
Coordination no. 6 (octahedral) isomers.
𝑀𝐴4 𝐵2 , 𝑀𝐴4𝐵𝐶 , 114 (c)
Showing geometrical isomerism. 9 Only 𝑐𝑖𝑠-octahedral compounds show optical
𝑀𝐴3 𝐵3 , 𝑀(𝐴𝐴)2𝐵2 activity.
114 (a) 115 (b)
3 The presence of 𝑚-directing groups in benzene 0 A square planar complex results from 𝑑𝑠𝑝2-
nucleus simply decreases electron density at 𝑜- hybridisation involving
and 𝑝- whereas no change in electron density at (𝑛-1) 𝑑𝑥 2−𝑦2 , 𝑛𝑠, 𝑛𝑝𝑥 and 𝑛𝑝𝑦 atomic orbitals.
𝑚-position is noticed. 115 (a)
2 HNO3 accepts a proton from H2 SO4 .
H2 SO4 ⇌ H + + HSO−4
HNO3 + H + ⟶ H2 O + NO+ 2
115 (c)
3 Lithium tetrahydroaluminate is Li[Al(H)4 ]

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