Solution
Solution
6201CMD30334124SRG004 MD
PHYSICS
SECTION - A
For calculating centre of mass of combination of bodies we can assume whole mass of each of
(1)
the bodies to be concentrated at centre of mass.
For calculating torque of gravitational force on a body we can assume whole mass to be
(2)
concentrated at centre of mass in uniform gravitational field.
For calculating moment of inertia of a body about some axis we can assume whole mass to be
(3)
concentrated at centre of mass.
For a system we can write for momentum as Msystem where Msystem is mass of system and
(4) is velocity of system even though velocities of bodies in system can be different from velocity of
centre of mass of system.
2) A uniform rod of mass m and length ℓ is connected with two ideal strings from ends of rod as
shown in figure, if tensions in strings are T1 & T2 respectively then :-
(1)
T1 >
(2)
T2 >
(3)
T1 <
(4)
T1 = T2 =
3) For the wheel-and-axle system shown, which of the following expresses the condition required for
the system to be in static equilibrium?
(1) m1 = m2
(2) am1 = bm2
(3) am2 = bm1
2 2
(4) a m1 = b m2
4) Four Ts are made from two identical rods of equal mass and length. If I represents the moment of
inertia about the axis shown in figure.
5) A ball of mass M and radius R has a moment of inertia of I = 2/5 MR2. The ball is released from
rest and rolls down the ramp with no frictional loss of energy. The ball gets projected vertically
upward of a ramp as shown in the diagram, reaching a maximum height ymax above the point where it
leaves the ramp. Determine the maximum height of the projectile ymax in terms of h. (Assume no
collision anywhere)
(1) h
(2)
(3)
(4)
6) A wheel rolls without sliding along a horizontal road as shown. The velocity of the center of the
wheel is represented by → . Point P is painted on the rim of the wheel. The instantaneous
(1) represented by →
(2) represented by ←
(3) represented by
(4) zero
7) Two uniform semicircular discs, each of radius R are stuck together to form a disc. Masses of the
two semicircular parts are M and 3M. The moment of inertia of the circular disc about an axis
perpendicular to its plane and passing through the centre of the formed disc. (Point 'O' in figure)
(1) 2MR2
(2)
(3)
(4)
8) A uniform disc of mass m0 rotates freely about a fixed horizontal axis passing through its centre. A
thin cotton pad is fixed to its rim, which can absorb water. The mass of water dripping onto the pad
per unit time is μ. After what time will the angular velocity of the disc get reduced to half its initial
value?
(1)
(2)
(3)
(4)
9) A body attains a height equal to the radius of the Earth when projected from Earth' surface. The
velocity of the body with which it was projected is :–
(1)
(2)
(3)
(4)
10)
Calculate energy needed for moving a mass of 4kg from the centre of the earth to its surface. If
radius of the earth is 6400 km and acceleration due to gravity at the surface of the earth is g = 10
m/sec2
11) Time taken by the planet to cover path ABC is t1 & time taken by the planet to cover path C D A
is t2 :-
(1) t1 = t2
(2) t2 > t1
(3) t1 > t2
(4) cannot be determined
12)
The gravitational field due to a mass distribution is E = K/x3 in the x-direction. (K is a constant).
Taking the gravitational potential to be zero at infinity, its value at a distance x is
(1) K/x
(2) K/2x
(3) K/x2
(4) K/2x2
13) Five point masses m each are placed at five corners of a regular pentagon. Distance of any
corner from center is r. Match the following two columns.
Column I Column II
14) The rotation of the Earth having radius R about its axis speeds upto a value such that a man at
0
latitude angle 60 feels weightless. The duration of the day in such case will be
(1)
(2)
(3)
(4)
(1) F1>F2>F3> F4
(2) F1 = F2< F3< F4
(3) F1 = F2 < F4 < F3
(4) F1 < F2 < F3 < F4
16) Two vessels A and B of different shapes have the same base area and are filled with water up to
the same height h (see figure). The force exerted by water on the base is FA for vessel A and FB for
vessel B. The respective weights of the water filled in vessels are WA and WB. Then
17) Two soap bubbles of radii and equal to 4 cm and 5 cm are touching each other over a
common surface S1S2 (shown in figure). Its radius of curvature will be
(1) 4 cm
(2) 20 cm
(3) 5 cm
(4) 4.5 cm
18) A liquid drop of diameter D breaks into 27 tiny drops. The resultant change in energy is :–
(1) 2π TD2
(2) 4π TD2
(3) π TD2
(4) None of these
19) Two capillary tubes of same diameter are put vertically one each in two liquids whose relative
densities are 0.8 and 0.6 and surface tensions are 60 dyne/cm and 50 dyne/cm respectively. Ratio of
(1)
(2)
(3)
(4)
20) In a capillary tube experiment, a vertical 30 cm long capillary tube is dipped in water. The water
rises up to a height of 10 cm due to capillary action. If this experiment is conducted in a freely
falling elevator, the length of the water column becomes :–
(1) 10 cm
(2) 20 cm
(3) 30 cm
(4) zero
21) A vessel, whose bottom has round holes with diameter of 0.1 mm, is filled with water. The
maximum height to which the water can be filled without leakage is :– (S.T. of water = 75 dyne/cm, g
= 1000 cm/s2)
(1) 100 cm
(2) 75 cm
(3) 50 cm
(4) 30 cm
22) The velocity of falling rain drop attain limited value because of :–
Column I Column II
Temperature of the
(B) (q) decrease
bubble will
24) This question has Statement-1 and Statement-2 of the four choices given after the Statements,
choose the one that best describes the two Statements.
Statement 1 : A capillary is dipped in a liquid and liquid rises to a height h in it. As the temperature
of the liquid is raised, the height h increases (if the density of the liquid and the angle of contact
remain the same)
Statement 2 : Surface tension of a liquid decreases with the rise in its temperature.
(1) Statement-1 is false and Statement-2 is true
Statement-1 is true, Statement-2 is true. Statement-2 is not the correct explanation for
(2)
Statement-1
(3) Statement-1 is true and Statement-2 is false
Statement-1 and Statement-2 both are true, But Statement-2 is the correct explanation for
(4)
Statement-1
25) Wax is coated on the inner wall of a capillary tube and the tube is then dipped in water. Then,
compared to the unwaxed capillary, the angle of contact θ and the height h upto which water rises
change. These changes are :
26) The maximum load a wire can withstand without breaking, when its length is reduced to half of
its original length, will
(1) be double.
(2) be half.
(3) be four times.
(4) remain same.
27) A sample of metal weights 210 grams in air, 180 grams in water and 120 grams in an unknown
liquid. Then:–
28) A wooden block with a coin placed on its top, floats in water as shown in Fig. The distance and
h are illustrated.
29) A Cylindrical tank has a cross-sectional area S = 1000 cm2, stands motionless on a horizontal
surface (figure). In its wall there is a hole, cross-sectional area of which S1 = 10 cm2, located at a
distance h1 = 80 cm from the surface of water in the tank and h2 = 180 cm from the bottom. Find
cross-sectional area S2 of the jet emanating from the hole at the place of its falling on a horizontal
surface.
(3)
(4)
30) Water flows in a horizontal tube (see figure). The pressure of water changes by 700 Nm–2
between A and B where the area of cross section are 40 cm2 and 20 cm2, respectively. Find the rate
of flow of water through the tube, (density of water = 1000 kgm–3)
31) If the ratio of lengths, radii and Young’s moduli of steel and brass wires in the figure are a,b and
(1) 2a2c/b
(2) 3a/2b2c
(3) 2ac/b2
(4) 3c/2ab2
32) A rope of diameter 2cm breaks if tension in it exceeds 500 N. The maximum tension that may be
given to similar rope of diameter 4cm is :-
(1) 500 N
(2) 250 N
(3) 1000 N
(4) 2000 N
33) The length of a metal wire is ℓ1 when the tension in it is T1 and is ℓ2 when the tension is T2. The
natural length of the wire is :-
(1)
(2)
(3)
(4)
34) If S is stress and Y is Young's modulus of material of a wire, the energy stored in the wire per
unit volume is :-
(1) 2S2Y
(2)
(3)
(4)
35) The graph shown is the extension of wire of length 1m suspended from the top of a roof at one
end and with a load W connected to the other end. If the cross sectional area of the wire is 1 mm2,
(3)
× 1011 Nm–2
(4) None of these
SECTION - B
1) Two bodies of masses 2kg and 3kg are connected by a metal wire of cross section 0.04 mm2.
Breaking stress of metal wire is 2.5 GPa. The maximum force F that can be applied to 3kg block so
(1) 100 N
(2) 150 N
(3) 200 N
(4) 250 N
2) Assertion (A):- If line of action of the force passes through the axis of rotation, then the body will
rotate even with the application of a small force.
Reason (R):- If line of action of force passes through the axis of rotation, then torque is zero.
3) Assertion : For a body, pure rolling down a rough inclined surface, work done by friction is
negative.
Reason : In pure rolling on a fixed surface, velocity of contact point of the body is zero.
(1) Both Assertion and Reason are true but Reason is NOT the correct explanation of Assertion.
(2) Assertion is true but Reason is false.
(3) Assertion is false but Reason is true.
(4) Both Assertion and Reason are true and Reason is the correct explanation of Assertion.
4) Assertion: A ladder is more apt to slip, when you are high up on it than when you just begin
to climb.
Reason: At the high up on a ladder, the torque is large and it is small when one just begins to climb.
(1) Both assertion and reason are true and the reason is the correct explanation of the assertion.
(2) Both assertion and reason or true but reason is not the correct explanation of the assertion.
(3) Assertion is true but reason is false.
(4) Both assertion and reason are false.
5) Two particles of combined mass M, placed in space with certain separation, are released.
Interaction between the particles is only of gravitational in nature and there is no external force
present. Acceleration of one particle with respect to the other when separation between them is R,
has a magnitude :
(1)
(2)
(3)
6) Suppose the gravitational force varies inversely as the nth power of the distance. Then, the time
period of a planet in circular orbit of radius R around the sun will be proportional to :
(1) Rn
(2) R(n+1)/2
(3) R(n–1)/2
(4) R–n
7) In the given figure there is a hollow sphere. Then on which points, gravitational potential due to
(1) O, A, B, C
(2) O, A, B
(3) O, B
(4) No where
8) Two artificial satellites P and Q are revolving round the earth in circular orbits. If the ratio of
their orbital radius is 1 : 4 and ratio of their masses is 3 : 1 then the ratio of their orbital speeds is :-
(1) 1 : 2
(2) 2 : 1
(3) 1 : 4
(4) 4 : 1
10) The poisson's ratio of a material is 0.5. If a force is applied to a wire of this material, there is a
decrease in the cross-sectional area by 4%. The percentage increase in the length is :-
(1) 1%
(2) 2%
(3) 2.5%
(4) 4%
11) Compressibility per unit atm. pressure of water is 'σ' and if due to pressure P (in atm) there is
decrement in volume, find change is volume (V - volume)
(1) σ P / V
(2) σ PV
(3) σ / PV
(4) σ V / P
12) When a metal wire elongates by hanging a load Mg on it, the gravitational potential energy of
mass M decreases by Mgl. This energy appears:-
13)
A vertical U-tube of uniform inner cross section contains mercury in both sides of its arms.
A glycerin (density = 1.3g/cm3) column of length 10 cm is introduced in to one of its arms. Oil of
density 0.8 gm/cm3 is poured into the other arm until the upper surfaces of the oil and glycerine are
in the same horizontal level. Find the length of the oil column, (density of mercury = 13.6 gm/cm3) :-
(1) 10.4 cm
(2) 8.2 cm
(3) 7.2 cm
(4) 9.6 cm
14) An incompressible liquid flows through a horizontal tube as shown in the figure. Then, the
(1) 4Q
(2) Q
(3)
(4)
CHEMISTRY
SECTION - A
1) Standard entropy of X2, Y2 and XY3 are 60, 40 and 50 JK–1 mol–1, respectively. For the reaction,
X2 + Y2 → XY3, ΔH = – 30 kJ,
to be at equilibrium, the temperature will be:
(1) 1250 K
(2) 500 K
(3) 750 K
(4) 1000 K
2)
Column I Column II
Free expansion at
A P
ΔV = 0 q = -w = nRT ln
Isothermal
B Q ΔU = wad
irreversible change
Isothermal
C R ΔU = qv
reversible change
For adiabatic
D S q = -w= Pex(Vf - Vi)
changes
(1) A-S, B-P, C-R, D-Q
(2) A-R, B-Q, C-P, D-S
(3) A-R, B-S, C-P, D-Q
(4) A-Q, B-E, C-S, D-P
(1) Suppressed
(2) Not altered
(3) Increased
(4) Doubled
4) Considering entropy (S) as a thermodynamic parameter, the criterion for the spontaneity of any
process is
5) For the process H2O(l) (1 bar, 373 K) → H2O(g) (1 bar, 373 K), the correct set of thermodynamic
parameters is :
(1) ΔG = 0, ΔS = –ve
(2) ΔG = 0, ΔS = +ve
(3) ΔG = –ve, ΔS = +ve
(4) ΔG = +ve, ΔS = 0
7) The standard reaction Gibbs energy for a chemical reaction at an absolute temperature T is given
by ΔrG° = A – BT
Where A and B are non-zero constants. Which of the following is TRUE about this reaction?
(1) K = e–ΔG°/RT
(2)
=–T
In isothermal process,
(3)
Wreversible = – nRT ln
lnK =
(4)
9) What can be concluded about the values of ΔH and ΔS from this graph?
(1) Standard Gibbs free energy is equal to zero for a reversible reaction at equilibrium
Gibb's function of the system attains its maximum value when a reversible reaction reaches
(2)
equilibrium.
For H2O(s) H2O(l), at its melting point and 1 atm pressure, 1 mole of H2O(s) has same Gibbs
(3)
energy as 1 mole of H2O(ℓ)
(4) If ΔH < O, the process will always be spontaneous.
11) KP will be greater to KC under which of the following conditions for the reaction at 300K
temperature
aA + bB ⇌ cC + dD
12) An ideal gas is taken around the cycle ABCDA as shown in figure. The net work done during the
cycle is equal to :-
(1) Zero
(2) Positive
(3) Negative
(4) We cannot predict
13) If for a given substance, TB is the m.pt. and TA is the freezing point, then correct variation of
entropy by graph between entropy change and temp. is
(1)
(2)
(3)
(4)
(1)
(2)
(3)
(4)
15)
Column-I Column-II
16) What is the net work done (w) when 1 mole of monoatomic ideal gas undergoes in a process
described by 1, 2, 3, 4 in given V–T graph
Use : R = 2cal/mole K
ln 2 = 0.7
(1) –600 cal
(2) – 660 cal
(3) + 660 cal
(4) + 600 cal
17) An ideal gas is allowed to expand both reversibly and irreversibly in an isolated system. If Ti is
the initial temperature and Tf is the final temperature, which of the following statements is correct?
18) Correctly match the number of sigma and Pi bond in the given compounds :
1) Furan (a) σ = 7; π = 1
2) Pyridine (b) σ = 9; π = 2
3) Urea (c) s = 11; π = 3
20) Number of olefinic, acetylinic, double bond and triple bond is present in the given compound:
(1)
(2)
(3)
(4)
(1)
(4)
(1) 3
(2) 1
(3) 2
(4) 4
(a) (b)
(c) (d)
Correct code is :
24)
(1) 6
(2) 5
(3) 3
(4) 7
(1) 2-Bromo-6-chlorocyclohex-1-ene
(2) 6-Bromo-2-chlorocyclohexene
(3) 3-Bromo-1-chlorocyclohexene
(4) 1-Bromo-3-chlorocyclohexene
32) Number of C-atoms in first higher homologue of first member of ester family is
(1) 5
(2) 4
(3) 3
(4) 2
35) Amino group (–NH2) of Primary amine is attached to which type of carbon :
SECTION - B
(1) 12
(2) 8
(3) 16
(4) 14
(1) Two
(2) Three
(3) Four
(4) One
4) How many structural isomers are possible for molecular formula C4H10O ?
(1) 4
(2) 2
(3) 9
(4) 7
(1) 2
(2) 3
(3) 4
(4) 5
(II)
(III)
(IV)
(1)
(2)
(3)
(4)
(1)
(2)
(3)
(4)
(1)
(2)
(3)
(4)
12) The successive ionisation energies (in eV/atom) of an element 'X' are 5.98, 18.82, 28.45, 119.99,
153.82, 190.49 and 241.76 respectively. The element 'X' is likely to be :
(1) Be
(2) Li
(3) Na
(4) Al
(1) 7
(2) 4
(3) 5
(4) 9
14) The chemistry of lithium is very similar to that of magnesium even though they are placed in
different groups. Its reason is :-
(1) Nobel gases have a different number of outermost electrons than their group number.
(2) In the sixth period the orbitals being filled are 6s, 4f, 5d, 6p.
(3) The second transition series contains the elements from Y to Cd.
(4) O–2 has the same no. of electrons in its outermost as well as penultimate shell.
BOTANY
SECTION - A
2) Assertion : In majority of dicotyledonous plants, the direct elongation of the radicle leads to the
formation of primary root.
Reason : The primary root and it's branches constitute the tap root system.
(1) Both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
(2) Both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
(3) Assertion is True but the Reason is False.
(4) Both Assertion & Reason are False.
3)
Identify the number of correct statements w.r.t., phloem fibres:
(I) Phloem fibres (bast fibres) are made up of sclerenchymatous cells.
(II) These are generally absent in the primary phloem but are found in the secondary phloem.
(III) These are much elongated, unbranched and have pointed, needle like apices. The cell wall of
phloem fibres is quite thin.
(IV) Before maturity, these fibres lose their protoplasm and become dead.
(1) 1
(2) 3
(3) 2
(4) 4
(1) Potato
(2) Ginger
(3) Colocasia
(4) All of these
(1) Both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
(2) Both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
(3) Assertion is True but the Reason is False.
(4) Both Assertion & Reason are False.
6)
7) Assertion : When a leaf Lamina is entire or incised, but incisions don't reach upto midrib, then it
is said to be simple.
Reason : Lamina is the green, expanded part of leaf with vein and veinlets.
(1) Assertion is correct and reason is correctly explaining the statement of assertion.
(2) Assertion is correct, reason is also correct but doesn't explain the statement of assertion.
(3) Assertion is correct, reason is incorrect.
(4) Assertion is incorrect, reason is also incorrect.
8)
9) The given figure shows some types of phyllotaxy. Select the option that correctly match them :-
a b c
10) Consider the following four statements (a-d) and select the option which includes all the correct
ones :-
(a) In all leguminous plants, the leaf base many become swollen, which is known as pulvinus.
(b) Long thin flexible petioles allow leaf blades to flutter in wind there by cooling the leaf and
bringing fresh air to leaf surface.
(c) A single leaf arises at each node in mustard and chinarose.
(d) Leaves originate from shoot apical meristem and arranged in basipetal manner.
(1) b and c
(2) b, c and d
(3) a and b
(4) c and d
11) The aestivation in petals of lady finger and Calotropis plants are respectively :-
(1) A & D
(2) B & A
(3) D & A
(4) D & B
12) Match the Column-I, Column-II and Column-III & select the correct option :
13)
14) Depending on whether the apex gets converted into a flower or continues to grow, how many
major type of inflorescences are defined :-
(1) Two
(2) Four
(3) Seven
(4) Five
15) In how many of the following plant underground stem works as organ of perennation?
Turnip, Ginger, Colocasia, Opuntia, Jasmine, Pistia.
(1) Three
(2) Two
(3) Four
(4) Five
16) How many example of plants in the list given below have axile placentation.
Mustard, Sesbania, Trifolium, Belladonna, Tobacco, Petunia, Onion, Datura, Makoi, Chilli.
(1) 5
(2) 7
(3) 8
(4) 6
17)
Consider the following 4 statements a-d and select the option which includes all the correct ones :-
(a) When stamens are united into bunches/bunch it is called adelphy.
(b) When anthers are united and filaments are free, then it is syngenesious condition.
(c) When anthers as well as filaments are united then it is called synandrous condition.
(d) In tetradynamous condition inner 4 stamens are short while outer 2 stamens are long.
(1) Statement a, b, c
(2) Statement b, c, d
(3) Statement b, d
(4) Statement c, d
18) In the list given below how many genera consists of monocarpellary and tricarpellary ovary
respectively?
Moong, Lupin, Gloriosa, Turnip, Aloe, Barseem, Colchicum, Tulip, Indigofera, Datura, Ladyfinger,
Lily.
Maturation Permanent
i A
zone cells
Protect the
iv D Root cap
tender apex
(1) Only ii and iv
(2) i, ii, iii and iv
(3) Only iii and iv
(4) Only ii, iii and iv
20) Which of the following is/are correct combinations with respect to their special condition of
stamens and types of placentation :-
(A) Cotton - Monoadelphous, axile
(B) Lemon - Polyadelphous, axile
(C) Sunflower - Syngenesious, basal
(D) Gram - Diadelphous, marginal
21)
22) Which of the following statements are true for pea plant :-
A. In stem vascular bundles are arranged in ring.
B. Conjoint collateral vascular bundle in leaf
C. Vexillary aestivation of petals
D. Reticulate venation in leaf
E. Good quantity of endosperm is present in mature seed
F. Multicellular trichomes are present in stem epidermis
(1) A, B, C, D & F
(2) A, B, C, D, E & F
(3) C, D & E
(4) B, C, D, E, F
24)
Soyabean, Tomato, Potato, Solanum, Sesbania, Muliathi, Aloe, Gloriosa, Sem, Lupin, Tulips, Petunia,
Sunhemp, Ashwagandha, Asparagus, Tobacco, Belladona and Trifolium.
25)
27) Which of the following option gives the correct categorisation of the tissue systems found
in plants :-
A C
B Ground
Epidermal Vascular
tissue
tissue tissue
system
system system
Bulliform Primary
(1) Cambium
cells xylem
Madullary
(2) Stomata Pericycle
Rays
Vascular
(3) Trichomes Hypodermis
Bundles
28) Find out the correct match from the following table :-
(1) i only
(2) i and ii
(3) iii only
(4) ii and iii
29) How many are formed by the process of dedifferentiation and re-differentiation, respectively ?
Phellogen, phellem, wood, phelloderm, secondary phloem, pith, interfascicular cambium
30) Observe the given diagram carefully and how many statements are true about given diagram:
(1) Two
(2) Three
(3) Four
(4) One
31) How many of the following are part of cortex in dicot root ?
Pericycle, Pith, Hypodermis, General cortex, Endodermis, Xylem
(1) Three
(2) Two
(3) Four
(4) Five
32) In the given diagram, different parts are indicated by alphabets. Choose the answer in which
these alphabets correctly matches with parts they indicate :-
(1) A - Cork B - Secondary cortex C - Complimentary cells D - Cork cambium
(2) A - Cork B - Complimentary cells C - Secondary Cortex D - Cork cambium
A - Epidermis B - Complimentary cells
(3)
C - Cork cambium D - Secondary cortex
A - Epidermis B - Cork cambium
(4)
C - Secondary cortex D - Complimentary cells
34) Given diagram represents T.S. of woody dicot stem passing through lenticel. Which of the
following statement is true about labelleld parts A, B & D.
35)
SECTION - B
(1) Axile
(2) Parietal
(3) Free central
(4) Both 1 & 3
(1) I & IV
(2) IV & III
(3) III & I
(4) V only
(1) One
(2) Two
(3) Three
(4) Four
4) In the T.S. of Zea mays stem, which sequence is correct in a vascular bundle, from periphery to
centre.
5)
6)
(1) Three
(2) Four
(3) One
(4) Two
(1) A & B
(2) B & C
(3) C, D & E
(4) A & D
9)
How do bulliform cells help plants during drought conditions?
10) Find out the correct match from the following table ?
12) Study the given statements carefully and give the answer.
(A) Bark is a nontechnical term that refers to all tissues exterior to the cork cambium only
(B) Phellem, phellogen and phelloderm are collectively called pericarp.
(C) In the dicot stem vascular cambium is completely secondary in origin.
(D) In dicot stem endodermis cells are rich in starch grains and the layer is also called starch sheath.
13) How many of the following are observed in tomato : Exstipulate leaf, compound leaves,
underground tuber, reticulate venation, non endospermic seed, complete flower, conjoint
bicolleteral open vascular bundle in stem, swoollen placenta, multicellur trichome, isobilateral leaf.
(1) Six
(2) Seven
(3) Five
(4) None
(1) Two
(2) Three
(3) Four
(4) One
15)
Consider the following statement a-d and select the option which includes all the correct ones :-
(a) Midrib is called principle vein.
(b) A leaf is said to be compound when the incision of lamina reach up to the midrib breaking into
number of leaflets.
(c) When the veins runs parallel to each other within lamina. The venation is parallel.
(d) Leaves in all dicotyledons plant posses parallel venation.
(1) Statement a, b, c
(2) Statement b, c, d
(3) Statement c, d
(4) Statement a, c, d
ZOOLOGY
SECTION - A
1) Lungs do not collapse between breaths and some airways remains in the lungs which can never
be expelled because ?
(1) 1
(2) 2
(3) 3
(4) 4
4) The given diagram represent the CO2 transportation. Identify the A, B, C and phenomena D in this
5)
Partial pressure (in mm Hg) of Oxygen and Carbon dioxide at Different parts Involved in Diffusion is
given in table then identify the A, B, C and D :-
A 104 40
Blood (Deoxygenated) 40 B
Blood (Oxygenated) C 40
Tissues 40 D
(1) A - Pulmonary artery, B-45, C-95, D-45
(2) A - Pulmonary vein, B-45, C-104, D-40
(3) A - Alveoli, B-45, C-95, D-45
(4) A - Alveoli, B-40, C-104, D-45
6) Which one of the following is the incorrect statement for respiration in humans ?
(1) Workers in grinding and stone-breaking industries may suffer, from lung fibrosis
(2) About 20-25% of carbon dioxide (CO2) is carried by haemoglobin as carbomino-haemoglobin
(3) Cigarette smoking may cause emphysema
Neural signals from pneumotoxic centre in pons region of brain can increase the duration of
(4)
inspiration
7)
Tidal volume
(i) (EC – ERV) 500 ml
(TV)
Expiratory
(ii) reserve volume (VC – IRV – TV) 3000 ml
(ERV)
Vital capacity
(iii) IRV + ERV + RV 4500 ml
(VC)
Residual
(iv) FRC – ERV 1200 ml
volume (RV)
(1) (i) and (ii)
(2) (i), (iii) and (iv)
(3) (i), (ii) and (iii)
(4) (i) and (iv)
Column I Column II
(A) Gills (i) Prawn
(B) Moist skin (ii) Rabbit
(C) Lung (iii) Earthworm
(D) Body surface (iv) Frog
(v) Cockroach
(vi) octopus
(vii) Flatworms
(viii) sponges
(ix) snakes
(x) Shark
A → (i), (vi), (x); B → (iii), (v), (viii) ;
(1)
C → (ii), (ix); D → (iv), (vii)
A → (i), (vi), (x); B → (iii), (iv);
(2)
C → (ii), (ix); D → (viii), (vii)
A → (vi), (vii), (iv); B → (i), (iii), (v);
(3)
C → (ii), (ix), (x); D → (viii)
A → (i), (vi), (x); B → (iii), (iv) ;
(4)
C → (ii), (ix), (x); D → (vii), (v)
11) Assertion : The amount of CO2 that can diffuse through the diffusion membrane per unit
difference in partial pressure is much higher than O2.
Reason : The solubility of CO2 is 20-25 time higher than that of oxygen.
(1) Both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
(2) Both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
(3) Assertion is True but the Reason is False.
(4) Both Assertion & Reason are False.
12)
13) In the diagram the section of human heart given here, certain parts have been represented by
alphabets. Choose the correct option in which an alphabet has been not correctly matched with the
part they indicate and their function.
15) Pneumotaxic centre is present in the A . Chemosensitive area situated adjacent to Rhythm
centre Recognize B concentration in C Blood. Find A, B, C
A B C
(1) 2
(2) 1
(3) 3
(4) 4
18) Match the disorders given in column I with symptoms under column II. Choose the answer which
gives the correct combination of alphabets with numbers :
Column I Column II
(1) P-wave
(2) Q-wave
(3) QRS-wave
(4) T-wave
(1) 6
(2) 3
(3) 2
(4) 4
22) Assertion (A) :- Respiratory rhythum centre can moderated the function of pneumotaxic centre,
located in the medulla region in brain.
Reason (R) :- Pneumotaxic centre controls the swtich "ON" point of inspiration.
(1)
(2)
(3)
(4) 1 and 3 both
25)
(1) Three
(2) Four
(3) One
(4) Two
Column-I Column-II
27)
Consider the following four statements (a-d) and select the option which includes all correct ones:-
(a) Coronary Artery disease, (CAD), often result due to Atherosclerosis
(b) Heart failure occurs when the heart muscle is suddenly damaged by an inadequate blood supply
(c) High blood pressure leads to heart diseases and also affects vital organs like brain and kidney
(d) Angina occurs due to conditions that affect the blood flow to myocardium.
(1) Statements (b), (c) and (d)
(2) Statements (a), (b) only
(3) Statements (c), (d) only
(4) Statement (a), (c) and (d)
28) Assertion : The formation of Bicarbonate 70% takes place in the RBC not in the plasma.
Reason : RBCs contain very high concentration of the enzyme carbonic anyhydrase.
(1) Both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
(2) Both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
(3) Assertion are True but Reason is not correct.
(4) Assertion is false but Reason is true.
29)
(1) AB–
(2) O–
(3) AB+
(4) All of these
32) The typical Lubb-Dup sounds heard in the heart beat of a healthy person are due to :-
33) Statement-I: Lower invertebrates like sponges, coelenterates, flatworms, etc., exchange O2 with
CO2 by simple diffusion over their entire body surface.
Statement-II: Among vertebrates, fishes use gills whereas amphibians, reptiles, birds and mammals
respire through lungs.
(1) 60–65%
(2) 0.5–1%
(3) 2–3%
(4) 6–8%
SECTION - B
1) Blood from intestine to the liver is carried by :-
3) Given below is the flow chart of Human respiratory system. A, B, C are denoted as :-
4) Carbon monoxide can kill a person because of it's extremely high affinity for :-
(1) haemoglobin
(2) phytochrome
(3) cytochrome
(4) None of these
6)
(1) SAN
(2) AVN
(3) AV bundle
(4) Bundle of His
7) Assertion: Person with 'AB' group can accept blood from persons with AB as well as the other
groups of blood.
Reason: Persons with AB groups have antigen A and antigen B on its RBCs and no antibodies in
their plasma.
(1) Both Assertion & Reason are True & the Reason is a correct explanation of the Assertion.
(2) Both Assertion & Reason are True but Reason is not a correct explanation of the Assertion.
(3) Assertion is True but the Reason is False.
(4) Both Assertion & Reason are False.
9) When heart muscles are suddenly damaged by an inadequate blood supply, this condition called
as :
(1) Both Assertion and Reason are true but Reason is NOT the correct explanation of Assertion.
(2) Assertion is true but Reason is false.
(3) Assertion is false but Reason is true.
(4) Both Assertion and Reason are true and Reason is the correct explanation of Assertion.
13) Match the column-I with column-II with respect to oxygen dissociation curve.
Column-I Column-II
15) Additional volume of air a person can inspire by a forcible inspiration is called ?
PHYSICS
SECTION - A
Q. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
A. 3 4 2 1 4 3 1 4 1 1 3 4 3 3 3 2 2 1 4 3
Q. 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35
A. 4 3 1 1 2 4 2 4 4 3 2 4 3 2 2
SECTION - B
Q. 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50
A. 4 4 3 1 2 2 2 2 4 4 2 3 4 3 4
CHEMISTRY
SECTION - A
Q. 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70
A. 3 3 2 1 2 1 4 4 1 3 3 1 1 3 1 3 3 3 3 2
Q. 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85
A. 3 3 2 2 1 1 2 3 1 4 3 3 4 3 4
SECTION - B
Q. 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100
A. 4 2 2 4 2 4 4 4 3 3 3 4 3 4 4
BOTANY
SECTION - A
Q. 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120
A. 1 2 3 4 1 2 2 4 3 1 2 2 1 1 2 2 1 3 2 4
Q. 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135
A. 2 1 3 1 4 1 3 1 2 3 2 3 2 3 4
SECTION - B
Q. 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150
A. 4 4 4 3 4 4 2 4 3 2 2 4 1 3 4
ZOOLOGY
SECTION - A
Q. 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170
A. 4 3 4 2 3 4 2 4 4 4 1 3 3 3 2 1 1 3 1 3
Q. 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185
A. 3 4 4 3 4 2 4 1 2 3 4 3 3 4 3
SECTION - B
Q. 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200
A. 3 2 3 1 1 1 1 3 2 4 1 1 3 3 3
SOLUTIONS
PHYSICS
1)
(A) yes, can assume whole mass of each bodies to be concentrated at C.O.M.
(B) let assume a uniform Rod. of mass 'm' and length .
(C)
let example of Ring. M.O.I about OO' of ring.
I = MR2
If we concentrated at C.O.M, then M.O.I about OO' = 0
Option (C) incorrect.
(D) Momentum of system.
2)
3)
m2b = m1a
4)
5)
6)
7) Ans. (1)
(i) The MOI of a uniform semicircular disc about axis AOB shown in figure is and of
another disc =
So MOI of the composite disc about
AOB is
0
I =
8)
10)
4E =
11)
= constant
Thus ABC, area concept is more ⇒ more time
12)
Gravitation potential
Given,
13)
Gravitational field at center is zero : (A - R)
14)
effective value of acceleration due to gravity at a place of latitude ϕ is nearly equal to g' g–
Rω2 cos2 ϕ
ϕ = 60°
g'= 0
g = Rω2 cos260°
15)
For outside point the shell can be treated as a point mass M kept at the centre of the shell.
⇒
16)
PA = PB
Area of A = Area of B
or PA AreaA = PB AreaB
or FA = FB.
17)
18)
= 2πD2T
19)
20)
21)
ρgH =
= 30 cm
22)
23) Surface area decreases, hence surface energy decreases and temperature increases.
Radius of single bubble is larger than two small bubble
Hence pressure decreases.
24)
Fact Based.
25)
θ < 90° for glass - water interface when capillary is coated with wax which is not wet by water
so θ > 90°
cos θ = –ve
28) When the coin falls, it occupies less volume, therefore, h decreases, decreases as density
of wood decreases.
29)
Let V1 is velocity of efflux at S1 then
Let V2 is velocity at S2
From B to C
Let a is area of S2
A1V1 = A2V2
30)
31)
TS = 3mg
= yS ×
= yb ×
= × × × = ×
32)
ℓ2 – ℓ = ...(ii)
35)
36) F – T = 3a
T = 2a
T = 2.5 × 109 × 4 × 10–8
T = 100 N
T = 2a
100 = 2a
a = 50
F = 5 × 50
F = 250 N
38) In pure rolling, velocity of point of application of friction force i.e. contact point is zero and
hence no work is done by friction force.
39) When a person is high up on the ladder, then a large torque is produced due to his weight
about the point of contact between the ladder and the floor. Whereas when he starts climbing
up, The torque is small. Due to this reason, the ladder is more apt to slip, when one is high up
on it.
40)
a1 = / M1 a2 = / M2
arel. = a1 + a2
= = .
41)
or
42)
0
43) V =
⇒ ⇒
44)
Fluids do not have any exact shape, they acquire the shape of container therefore only bulk
modulus deals with change in volume and can be applied to fluids.
45) ⇒
⇒
46)
K=
⇒ ΔV = σPV
47)
ΔUg = –Mgℓ
ΔUelast = kx2 =
k=
Remaining energy is converted to thermal energy.
48)
49)
∴ v = 1 m/s.
50)
Q ∝ pr4
CHEMISTRY
55)
56)
S = f(Temp)
57)
lnK =
lnK =
59)
Slope = – ΔS = –ve ⇒ ΔS > 0
Intercept = ΔH = +ve
60)
61) KP > KC
62)
ΔG = –RT ln Kp or Kp = e–ΔG/ RT
65)
Isothermal : T = constant
Adiabatic : q = 0
Isochoric : V = constant
Isobaric : P = constant
w = –nRTln
= –1 × 2 × 300ln (R = 2 cal/mol K)
= –600 × ln2
= –600 × 0.7
= –420 cal
For process (2 → 3)
w = –p(V2 – V1)
w = –600 cal
For process (3 → 4)
V1 = 40 L, V2 = 10 L, T = 600 K
w = –nRT ln
w = –1 × 2 × 600 × ln
w = 1200 × 2ln2 = 1680 cal
For process (4 → 1) (isochoric)
w=0
Net work = –420 + 1680 – 600 = 660 cal
73)
(a)
Carbon ⇒ 2° & 3°
But Hydrogen only ⇒ 2°
(b)
Carbon ⇒ 2° & 3° both
But hydrogen only ⇒ 2°
(d)
Carbon and hydrogen both 2°
77)
91)
(iv) O–2 =
BOTANY
107)
NCERT-XII, Pg. # 70
109) NCERT (XIth) Pg. # 71
130)
NCERT Pg # 94
131)
NCERT-XI, Pg # 91
General cortex and endodermis
132)
133) NCERT_11_PG_90_2021-22
134) NCERT Pg # 97
135)
ZOOLOGY
156)
178)
183)
191)