0 ratings 0% found this document useful (0 votes) 30 views 20 pages Practical Lecture 1
The document contains various mathematical problems and solutions related to set theory, statistics, and functions. It includes exercises on finding relations, calculating the number of students in a hostel based on beverage consumption, and determining statistical measures such as mean, variance, and quartiles. Additionally, it discusses graphical representations and the stability of prices in two cities.
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Save Practical lecture 1 For Later A. Activities :
(1) From the following information, find n(MUPUC)', if n(X) = 100.
 
 
 
 
Solution :
(2) From the following representation, write (i) domain (ii) co-domain
(iii) range of R (iv) the formula (Relation between x and y)
where x € A = {1, 2, 3, 4, 5, 6} and
ye A= {l, 2, 3, 4, 5, 6}
 
   
Solution : -oy [s ae ‘| fink
GB) WUe(¥lxreN tL sxs 12},
A= {1 4 7, 10},
B= {2, 4, 6, 7, 11,
CO = {3,'5; 8,9, 12),
complete the following activity
Given : A = zy
24
 
n
U
      
  
  
B. Solve the following :
Q 1. Ina hostel, 25 students take tea, 20 students take coffee, 15 students
take milk, 10 student take both tea and coffee, 8 students take both
milk and coffee. None of them take tea and milk and everyone
takes at least one beverage. Find the number of students in the
xT
hostel.
Solution; -+-+-bat.
uSch..of ot
sakQ 2. Write the domain and range of the following relations
Q) {@b),ae Nias bandh 4)
Gi) {abl abe Nat b= 12)
am) {Q2. 4), Q. 5), 2.6), (2.7)
Solution Cid Demstys Fi a sre a
Fone > 1 ak
GR Donen SLU EES ELE IG
Povye - { Wed t, LES Be, 1%
 
Q 3. IfA= {1, 2, 3}, B = {4, 5, 6}, which of the following are relations
from A to B ?
(i) Ry= (0, 4). C, 5), A, 6}
(i) R, = {d, 5), @ 4), B, 6}
(ii) R,= (1, 4). (1, 5), G, 6), 2, 6), GB, 4)}
(iv) R= (4, 2), 2, 6), 6, D2, 4)}
  
 
 
  
  
AVENE
L(A) GS) 6%
 
  
   
 
 
  
sepa gle felakin, Bais te
2 (C45) Bob)... Q26),.84N -
i pee ma 3y.g.etdien dite Ae B
Gv) {ee Gy, e453 72% ne
: $ 2.) eta] bl Gori fr Ray tn al aeons Bo
Ge) cha Fe a—~< 2. Partition Values 7
Activities :
The height of the students of a college are given below.
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
es - ST Toa
Height of stu- | 160 -| 164 -| 168 - 172 -| 176 -| 180) 184 -|
dents (in ems) | 163 | 167 | 171| 175 | 179 | 183 |_187_
No. ofstudents | 22 | 80 | 98 | 48 | 104| 43 | 5_
Calculate the height of student such that 75 % students have heights
below it.
To find [Q, _|
Height of students CL f_| Less than Cy;
160-163 159.5 — 163.5 22 22
164-167 163.5 — 167.5 80 yor
168-171 167.5 - [3-5 98 200
172-175 fars)-(ass)| 48 jor-[248] +
176-179 ass ]- [tas || 4= 104 352
180-183 aes |-(ass | 43 345
184-187 183.5 — 85 5 400
Here N = 5 f=[4e0
re
Q, = value of [3 =|) observation
= value of | 3 (48°) | observation
= value of 300® observation
The required class is
L= [i955 Cf =[24@ Lh=4
N=[4e0 }f=[lo4
h(3N
Q=Lt (Bc.
= 1755 + t](s00-
Q = 1755 + SE l(a00 [zag]
=|[t4e-5 | + 7 52)
beg}
1755 +[ 22. Caleulate D, and BP), for the following
 
 
 
Clr 295) 28-20] 30- 45) 35
20-25] | |
i i +" 2 | s & | iP
vess than | | |
2 ] | 1s | 29
oh I! ; (ad
N=Xf=[50
i. D, = value of 1 (s) observation
= value of |[/q |) =2.|| observation
fc
 
= value of 45 r observation
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
AO AO AS AS 50) 50-55
w | 7 6
7 [44] 50
The required class is{ So |-| 55
Toot ie | hls
7 nine
D,=L+ 2 10 of
5
= eo] + Ll
6
= 50 + ex 1
= 50 + | 0°33
= 50.83
a
ii. P,, = value of |[13]| || observation
loo
1h
= value of nf = observation
100
= value of [5 }" observation
The required class is (2s | - [39
 
 
 
 
 
 
- i~L2s] eas
 
B. Solve the following : sticul
1. The number of ATM transactions per day te A a la6 _
location in a certain city are as follows, ‘is 0, 13, 65, 30, 75,
60, 49, 5. Calculate D,, Q, ant " .
0, 49, 58, 72, 55. Cale , eat cabin 34
5..5.%.,60.6S, FEAL
  
  
Solution ;
    
 
 
 
2. Graphically find the values
data.
of Median, D, and P,, for the given“10 of
 
 
 
 
  
  
  
oo. | 70 - | 80 - ]90 -| 100 - [110 - [120 - :
Students | _ 69 79 Ro 99 109 Wo 129
No. of |, i §
ZZ 3 a 4
| Students ' i : a a
SCALE!
: On fe drag
300 2 Gm = ley teil
| lotta
ue) tow je leep
| DA ce aa
fs rlhow
Gorin. hy. ahh
ods Mee Samtl ah seta. Got
 
 
 
roms oy
prtnend Meats 30, thy
3. Daily wages for a group of 100 workers are given below. If
D, = 110, calculate the missing frequencies.
Daily wages in] 0- | 50-] 100- | 7 | 200 -
z
 
 
so | 100 | 150 250
No. of workers | 7 | 2 | 2s | 30 | 2we ep te
[ass ae]
   
 
Woe low SF
Jo bet BE. S85 405)
[lo TAs. = > O23a-s4
     
=> St A8-
 
je = .G 28-99
Pbrnd [$4b= 389 a a
E macaseng fatten are 19 4 20 A
4. Given below is the distribution of a sample of students appearing at
a C.A. examination, Help C.A. board to decide cut off marks for
qualifying the examination when 3% student pass the examination.
Mois 0- | 100- | 200- | 300- | 400- | 500-
100 | 200 | 300 | 400 | 500 | 600
[No. of Students | 130 | 150_| 190 220 | 280 | 130
Solution : Jes mnie ened -meyke dae anlidgpng atest toto, :
when... coplandendp-cpadp Oh haus de Big Pad + =
ceases Sha Ska Bom cmbeben, Grape deot
    
 
 
 
 
 
 
 
 
 
 
 
 
    
     
  
 
 
 
 
 
 
   
 
Bag] Sect
\2e0
AZo
ato
| S42 E
Ate=ed ~
- Wow eG
  
 
 
  
co Rp SAE. :
te cubation fe for: spratidgsng. 28. ctrobeinalisn, a
sis:A.
a)
(2)
 
Activities :
Consider the following geometrical representation
 
 
 
 
 
 
7 aT 2
2 “3; .
3 os —r 22
4 p07. > 46
”
10 2
Where : A = {1, 2, 3, 4}
B= (1-3, 5, 7 10)
C = {-2, 6, 22, 46, 97, 100} and
FS:ASB gi: BoC
xeA, yeBzeC
(i) The relation between x and y is
Y= [e1
 
 
(ii) The relation between y and z is
z= [yes
 seaees
(iii)z = [22-7] -3 (Express z in terms of x)
 
 
 
If fx) = = and g(x) = 8x + 5, find f [gx)] and gfftx)]
by completing the following activity
F tgeyj= 5
 
[bx+5-5 gx
= = ae ~
Afx)] = 8 fx) + 5
8] +
 
 
 
 
 
 
 
 
 
 
   
 
 
What can you conclude from f [g(x)] and AMx)] ?
oe see
corte Re de Comet. Sauntge,.Panckan,(3) Check whether the following relations are functions,
(a)
=
Sree bOI
   
Solution :
 
 
Solution : ----- PM. ye eccceseeeeneeeeeseeresesesserssenieneeerteeaticeesgensesessesntesB. Solve the following :
1. Which sets of ordered pairs represent functions from
A= {1, 2, 3, 4} to B= { -1, 0, 1, 2, 3}? Justify.
(a) {(1, 0), @, 3), 2, -D, 4 D, @ 2}
Solution
  
 
 
Cn AD ee ee 7
coven Rte LRA are dpa gts
(>) {(, 2), 2 -1), GD, 4 3}
Solution :
() (0, 3), 4 D, @ 2)}
Solution : map Qaeg Re ye pyagaig eetWt DQ. QD. Dy
Solution © xpd a ceeds fe
feaforns | Samoa nnd wel fh hoa ts
Te dA ed BURLY AIO de AL
 
2. Find x, if lx) = g(x) where
M+ 28, gx) = 1?
 
3 Inter FS, xed, verify whether (fof) (x) = x
  
yy Remy\
eS
Activitic
Find the
Age
No. of workers (f) 5 ; ae!
Lessthanes. | 45 | 65 | 125 | 155 | 170
pst
range and Q.D. for the following data.
1 95 | 30 40 | 45
(years) (x)
15 25
 
 
 
 
 
 
 
i, Largest value (L) = [ 45
Smallest value (S) = 20
 
 
Range = L-S=45 -[2e ]=[25 ]
ii. For QD, we need to find Q and | Q,
Q
 
 
 
 
 
th
= Value of (2 observation
= Value of | \9¢ ay ® observation
 
2S
 
jth
Q, = Value of [ my observation
QD =F a
 
 
 
Value of qa re observation
Q = [3as |
 
 
 
 
 
 
 
 
 
 
Find the mean and variance of the first n natural numbersw
i. Mean
Mean (x) FF Zz
 
@) -
 
 
a 14+2434.40 _
n
a)vy ’
ii, Variance Vw = —-(%)
(set)
froaa](2m+t) (nt)
6 (4)
eye n+l) on)
it peta
2 6
= (tn-1) _w-1
12esee2
The first group has 100 items with mean 45 and variance 49. If
the combined group has 290 items with mean 51 and variance 130,
find the mean and standard derivation of the second group.
= (45 1 V,@) = 49
x =CS5) |V. = [130
a= VQ) =
 
 
 
 
 
 
 
 
 
 
 
we
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
+ V,Q) = 49, 2 90) = (DF
 
 
 
 
 
 
 
 
 
 
nx tnk
m+n,
100/45 |+[156 |r,
e\ |= 250
12450 |=[4500 |+ 150 | 3
 
 
 
 
 
 
 
 
 
36
} d2= 16
 
 
 
 
 
 
 
 
+d?) +n,(o3 +d?)
7 m+n;
ts 44 ]+36)+150(03 + 6 })
ie
Nn ae(32. Sem] = 100 (jag]) + 190.02 + [24% 00 |
,
“32800 = [Asa] ~ [2qun | = 1500
“21600 = 180 | «3? |
 
 
 
 
 
 
. 9) = [rapa fo, © 12
B. Solve the following : ing
; 7 ie following data ;
1. Find an appropriate measure of dispersion for th
3 | 13-15 above]
| Less 9 [MIB] ISI | ys
5-7 | 7-9
Income (®. Lakhs) “than 5 IL SS
No.of persons | 14 3 8
 
 
 
 
 
 
. went fe
TPR Chap gem by ee
* A asfeoy Aaa chet2. The mean and variance of 12 items are 22 and 9 respectively,
Later on it was found that an item 32 was wrongly taken as 23.
Compute the correct mean and variance.
Solution : Geye.. 22... Mer Oef the following continuous series are 31 and
taking step deviation is as
Mean and variance of
254 respectively. The distribution after t
follows.
3 |-2] -1 | ° 1/2/3
f| 10 | 15{ 25 | 25 110 10] 5
rvals.
 
 
 
 
 
 
 
Determine actual class inte
olution : + Yyeyer ees (= eB
   
 
4Price of vo cities is as follows
4. Price of @ particular commodity in S years in two eilies 18 a8 follows.
Determine which city shows more stability in price
  
 
 
 
 
Price in City A} 10 | 22 | 19 | 28 | 26
Price in City B | 10 | 20] 18 | 12 | 15
(Given V30 = 5.4772, Vi76 = 4.1952)
     
   
tig dete
 
Solution: bed. Sa. dencke pees fy Clg Ah
toys
per}: