Society of Young Engineers Towards Achieving Excellence
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BASPHYS Quiz 1
8i + 5 j − 7k
8i − 5 j − 7k
8i − 5 j − k
8i + 5i − k
R
1
B 6
A 6
6
A+ B + R = 0 1
A + B = −R 6
A+ B = R 36
−( A + B ) = R
m
6
s
m
6
s
m
6
s
a = 3i + 2 j + 2k b = 2i − j + 3k
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BASPHYS Quiz 1
1.16m
1.30m
5500N
m a 5
4.0
s2 53.13
b = 5i − 12 j
m
g = 10 a
s2 3a + (2b − a)
1600N
a•b
3300N
4400N
7700N m
3.5
F m s
a m
200m 1.7
5m s
5a
25a
a
5
a
25
750m
8.5s
2.0844 10−7 N
60kg 8.5s
75kg
−11 m3
G = 6.67 10
kg s 2
1.20m
1.23m
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BASPHYS Quiz 1
m
20
s T2
25 T1
7.5kg
19
0.25
0.6kg
T1 T2
60 30
60 30
T1 T2
0.6kg
m
g = −10
s2
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BASPHYS Quiz 1
i j k
ab 3 2 2
2 −1 3
2 2 3 2 3 2
=i −j +k
−1 3 2 3 2 −1
A B = i[(2)(3) − (−1)(3)] − j[(3)(3) − (2)(2)] +
k[(3)(−1) − (2)(2)]
B = i (6 + 2) − j (9 − 4) + k (−3 − 4)
A a b = 8i − 5 j − 7k
v 2 sin 2 1
A B R H= gM = g
2g 6
v 2 sin 2 v 2 sin 2 3v 2 sin 2
R B HM = = =
2gM 1 g
A 2( g )
6
x=
H M = xH
3v 2 sin 2 v 2 sin 2
= ( x)
g 2g
A+ B + R = 0 3 v 2 sin 2 2g
( 2 2 )=x
g v sin
H M = 6H
a = 3i + 2 j + 2k
b = 2i − j + 3k
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BASPHYS Quiz 1
W = mg 5500 = m(10) a=5
m = 550kg
ax ay
F = ma (5cos53.13 )i (5sin 53.13 ) j
T − mg = ma
T = (550)(10) + (550)(4) 53.13 a = 3.00i + 4.00 j
T = 7700 N
3a + (2b − a)
Gm1m2
Fg = 3(3.00i + 4.00 j ) + [2(5i − 12 j ) − (3.00i + 4.00 j )]
r2
9i + 12 j + (10i − 24 j − 3i − 4 j )
−11 m3
(6.67 10 )(60kg )(75kg ) 9i + 12 j + (7i − 28 j )
−7 kg s 2
2.0844 10 N = 9i + 7i + 12 j − 28 j
r2
m3 16i − 16 j
(6.67 10−11 )(60kg )(75kg )
kg s 2
r2 = a b = ax bx + a y b y
m
2.0844 10−7 kg 2
s a b = (3 5) + [4 (−12)]
−11 m32 a b = 15 − 48
(6.67 10 )(60 kg )(75 kg )( s 2 )
kg s 2
r2 = a b = −33
2.0844 10−7 kg m
(6.67 10−11 m 2 )(60)(75)
r=
2.0844 10−7
a b =| a || b | cos
a=5
ab
r = 1.20m 2 2 = cos
b= b +b x | a || b |
y
b = 52 + (−12) 2 −33 = cos
| 5 ||13 |
b = 25 + 144
−33
a b = 169 cos −1 ( ) =
65
b = 13 = 120.51
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BASPHYS Quiz 1
vbr = 3.5m / s vrs = 1.7m / s d = 200m
vrs d 1.7 d
= =
vbr 200 3.5 200
d = 97.1429 97.14m
m
vbs v0 = 0; a = −9.8 ; h = 750m
s2
0
vbs = (vbr ) 2 + (vrs ) 2 750m
vbs = 3.5 + 1.72 2
m
vbs = 3.8910 3.89
s
8.5s
m
x = vbr t v f = v0 + at = 0 + −9.8 2 (8.5 s )
200 = (3.5)t s
t = 57.1429 57.14sec m
v f = −83.3
s
8.5s
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BASPHYS Quiz 1
1 1 m
d yf = d y 0 + v0t + at 2 = 0 + 0 + −9.8 2 (8.52 s 2 )
2 2 s
m
v 2f = v02 + 2a d y = 0 + 2 −9.8 2 (−750m)
s
d yf = −354.025 dis tan cey = 354.025m
m2 m
v = −9.8(−750) 2
2
f v f = −121.24
s s
8.5s
m
vo = 20 = 25
h8.5 s = h − dis tan cey = 750m − 354.025m s
h8.5 s = 395.975m
1
y = − gt 2 + (vo sin )t
2
t
t
1
d fy = d y 0 + v0t + at 2
2
1 m
−750m = 0 + 0 + −9.8 2 t 2 0m / s
2 s
v y = − gt + vo sin
−750 m s 2
0 = −(9.81)(t ) + (20)(sin 25 )
= t2 t = 12.3718s
−4.9 m t = 0.862sec
750m
d fy
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BASPHYS Quiz 1
1 x = (vo cos )t
y = − gt 2 + vo (sin )t
2 x = (20)(cos 25 )(1.7232)
1
y = − (9.81)(0.862)2 + (20)(sin 25 )(0.862) x = 31.23m
2
y = 3.641m 3.64m
vx = vo cos
vx = (20)cos(25 )
vx = 18.1261m / s
y
v y = − gt + v o sin
v y = −(9.81)(1.7232) + (20)sin(25 )
v y = −8.4522m / s
1
y = − gt 2 + vo (sin )t
2 v = (v x ) 2 + (v y ) 2
1
0 = − (9.81)t 2 + (20)(sin 25 )t v = (18.1261) 2 + (−8.4522) 2
2
t = 1.72sec m
v = 20
t = 0sec s
m = 7.5kg = 19 = 0.25
y
F y =0
N p − W sin = 0
N p = mg sin
N p = (7.5)(9.81)(cos19 )
N p = 69.5665 N
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BASPHYS Quiz 1
T2
Fx = ma Fx Fy
W sin − f = ma
−T1 cos60 T1 sin 60
mg sin − N p = ma
T2 cos30 T2 sin 30
(7.5)(9.81)(sin19 ) − (0.25)(69.5665) = (7.5)(a )
m
a = 0.87 2 Fxnet = T2 cos30 − T1 cos60
s
3 1
m = 0.6kg; = 60 ,30 0 = T2 − T1
2 2
3
60 30
1
T1 = T2
2
T1 = T2 3 ( )
2
60 30 Fynet = T1 sin 60 + T2 sin 30 + Fweight
T1 T2 3 1
0 = T1 + T2 − 6.0 N
0.6kg 2 2
3
Fweight = mg 6.0 N = T2 3 ( ) 1
+ T2
2
2
6.0 N = 2T2 T2 = 3.0 N
T1 T2
T1
m
Fweight = mg = (0.6kg ) −10 2 = −6.0 N
s
T1
T1 = T2 ( 3) T1 = 3.0 N ( 3)
T1 = 5.1962 N 5.20 N
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Society of Young Engineers Towards Achieving Excellence
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BASPHYS Quiz 1
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