2024-25
Subject; Gravitation and lawss
 Name:                                                                                    Duration:
 Class/Section: IX/                                     RT-3 Key
 Roll No:                                                                                  Max Marks: 16
   1. Let P and Q be the two bodies,
   the mass of body P = m1
   And the mass of body Q=m2
   As per the universal law of gravitation, the force of attraction between the earth and the body P is given by,
   Fp = G×Me×m1R2 …..(1)
   Where, R is the distance of the body from the centre of the earth.
   Similarly, the force of attraction between the earth and the body Q is givsen by
   FQ = G×Me×m2R2 …….(2)
   Since, the two forces, i.e., Fp and FQ are equal, thus from (1) and (2),
   ⇒ m1 = m 2
   G×Me×m1R2=G×Me×m2R2
   2.
     Acceleration due to gravity (g)                                  Universal gravitational constant (G)
     1. Acceleration due to gravity is the acceleration               1. Gravitational constant is numerically equal to the
     acquired by a body due to the earth’s gravitational              force of attraction between two masses of 1 kg that
     pull on it.                                                      are separated by a distance of 1 m.
     2. g is a vector quantity.                                       2. G is a scalar quantity.
     3. It is different at different places on the surface            3. The ‘G’ is a universal constant, i.e., its value is
     of the earth. Its value also varies from one celestial           the same (i.e. 6.7 × 10-11 Nm2 kg-2) everywhere in
     body to another.                                                 the universe.
   3.Here, g = 1.67 ms-2, R = 1.74 × 106 m and G = 6.67 × 10-2 Nm2 kg-2
4. Here, initial velocity, u = 0Time taken to reach the ground, t = 4 sAcceleration, a = g = 9.8 m/s 2
Height of the building, h = ?
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