NUCLEAR ASTROPHYSICS
Lecture-20
Resonant reactions…
ANIL KUMAR GOURISHETTY
PHYSICS
1
Recap
Resonant reactions
2
2𝐽 + 1 𝑎 𝑏
𝜎(𝐸) = 𝜋ƛ2 1 + 𝛿12
2𝐽1 + 1 2𝐽2 + 1 𝐸 − 𝐸𝑅 2 + /2 2
Valid for isolated resonances → total width (= a + b) is > separation of nuclear levels
Narrow resonance → total width ≪ Eresonance i.e. is constant over total resonance width
∞
8 1 −𝐸/𝑘𝑇
The stellar reaction rate is 𝜎𝑣 = න 𝐸 𝜎𝐵𝑊 𝐸 𝑒 𝑑𝐸
𝜋𝜇 𝑘𝑇 3/2 0
For narrow resonance, the change in E 𝑒 −𝐸/𝑘𝑇 is very small
∞
8 1
𝜎𝑣 = 3/2
𝐸𝑅 𝑒 −𝐸𝑅 /𝑘𝑇 න 𝜎𝐵𝑊 𝐸 𝑑𝐸
𝜋𝜇 𝑘𝑇 0
3
∞
𝑎 𝑏 𝑎 𝑏
න 𝜎𝐵𝑊 𝐸 𝑑𝐸 = 2𝜋 2 ƛ2 𝜔 where 𝜔𝛾 = Resonance Strength
0
∞
𝑎 𝑏 𝜋
At E = ER, 𝜎(𝐸)= 𝜎 𝐸 = 𝐸𝑅 = 4𝜋ƛ2𝑅 𝜔 2
න 𝜎𝐵𝑊 𝐸 𝑑𝐸 = 𝜎
2 𝑅
0
Area under the resonance curve = Total width height 𝜎𝑅
3/2
2𝜋 Stellar reaction rate per particle pair for a narrow
𝜎𝑣 = ℏ2 𝜔𝛾 𝑅 𝑒 −𝐸𝑅 /𝑘𝑇 𝑓
𝜇𝑘𝑇 resonance
Strength, width and resonance energy → Measurable parameters
Gamow peak = Resonance energy ER → nuclear burning at a narrow resonance
3/2
2𝜋
For many narrow resonances, 𝜎𝑣 = 𝜔𝛾 𝑖 𝑒 −𝐸𝑅/𝑘𝑇 𝑓
𝜇𝑘𝑇
𝑖
4
Rection A(x,)B 1 eV;
𝑥𝛾
At ER near Vc , 𝑥 is ~ MeV 𝜔𝛾 = 𝛾
At ER far below Vc , 𝑥 𝑥 ≪ 𝛾 𝜔𝛾 = 𝑥 𝛾 𝑥
Strength decreases very rapidly due to barrier penetration term in 𝑥
2𝜋 3/2
From the reaction rate 𝜎𝑣 = σ𝑖 𝜔𝛾 𝑖 𝑒 −𝐸𝑅/𝑘𝑇 𝑓
𝜇𝑘𝑇
resonances with ER near kT dominates reaction rate
For low T, it is very important to know locations and strengths of low energy
resonances
5
Ex: 14N(p,)15O, T6 = 30, ratio of reaction rates at 10 keV and 2 MeV is 10312
Mean lifetime of nuclei and stars’ properties change dramatically for a small
difference in resonance energies ER.
For neutron induced resonant reactions (radiative capture), holds for
nearly all resonance energies
Nuclei having states with long life-times can participate in the reaction. How to
find such number N12?
6
Production rate: no. of nuclei in resonance state.
At high resonance energies, a >> b a b
3/2
𝑁1 𝑁2 𝑁1 𝑁2 2𝜋
𝑟12 = 𝜎𝑣 = ℏ2 𝜔 𝑏 𝑒 −𝐸𝑅/𝑘𝑇
1 + 𝛿12 1 + 𝛿12 𝜇𝑘𝑇
Decay rate: b determines life-time of b of nuclei N12
𝑁12 𝑏 𝑁12
𝑟12 = =
𝜏𝑏 ℏ
𝑁1 𝑁2 2𝜋 3/2 3
Combining, 𝑁12 = ℏ 𝜔 𝑒 −𝐸𝑅/𝑘𝑇 Saha equation
1+𝛿12 𝜇𝑘𝑇
Valid for all reactions when equilibrium is established
Ex: Triple reaction → N(8Be)/N(4He) = 10−10 sufficient to bridge mass gaps at 5 & 8