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Lec Ena07

The lecture covers Millman's and Tellegen's theorems in electrical network analysis. Millman's theorem allows for the replacement of multiple parallel voltage sources with a single equivalent voltage source and resistance, while Tellegen's theorem states that the sum of power in any network is zero. The document includes explanations, formulas, and numerical examples to illustrate these concepts.

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0% found this document useful (0 votes)
7 views16 pages

Lec Ena07

The lecture covers Millman's and Tellegen's theorems in electrical network analysis. Millman's theorem allows for the replacement of multiple parallel voltage sources with a single equivalent voltage source and resistance, while Tellegen's theorem states that the sum of power in any network is zero. The document includes explanations, formulas, and numerical examples to illustrate these concepts.

Uploaded by

3cy7ag90a0
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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Electrical Network Analysis

(EE-151)

Lecture-07
Network Theorems
(Millman’s and Tellegen’s Theorems)

Dr. M. N. Alam, EED, NITW


Outlines
©2023 Dr. M. N. Alam

This Lecture covers:


• Millman’s theorem
• Tellegen’s theorem

10-04-2023 EE151 - Dr. M. N. Alam, EED, NITW 2


Millman’s Theorem
©2023 Dr. M. N. Alam
• It states that “if there are 𝑛 voltage sources 𝑉1 , 𝑉2 , … , 𝑉𝑛 with internal
resistances 𝑅1 , 𝑅2 , … , 𝑅𝑛 respectively connected in parallel then these
voltage sources can be replaced by a single voltage source 𝑉𝑚 and a single
series resistance 𝑅𝑚 .”

10-04-2023 EE151 - Dr. M. N. Alam, EED, NITW 3


Millman’s Theorem
©2023 Dr. M. N. Alam

• Where

𝑉1 𝐺1 + 𝑉2 𝐺2 + ⋯ + 𝑉𝑛 𝐺𝑛
𝑉𝑚 =
𝐺1 + 𝐺2 + ⋯ + 𝐺𝑛

𝑉1 /𝑅1 + 𝑉2 /𝑅2 + ⋯ + 𝑉𝑛 /𝑅𝑛


=
1/𝑅1 + 1/𝑅2 + ⋯ + 1/𝑅𝑛

1 1
𝑅𝑚 = =
𝐺𝑚 𝐺1 + 𝐺2 + ⋯ + 𝐺𝑛

1
=
1/𝑅1 + 1/𝑅2 + ⋯ + 1/𝑅𝑛

10-04-2023 EE151 - Dr. M. N. Alam, EED, NITW 4


Millman’s Theorem
©2023 Dr. M. N. Alam
Explanation of Millman’s theorem:
• By source transformation, each voltage source in series with a resistance can be
converted to a current source in parallel with a resistance as shown below

• Let 𝐼𝑚 be the resultant current of the parallel current sources and 𝑅𝑚 be the
equivalent resistance
𝑉1 𝑉2 𝑉𝑛
𝐼𝑚 = 𝐼1 + 𝐼2 + ⋯ + 𝐼𝑛 = + + ⋯+ = 𝑉1 𝐺1 + 𝑉2 𝐺2 + ⋯ + 𝑉𝑛 𝐺𝑛
𝑅1 𝑅2 𝑅𝑛
1 1 1 1
= + +⋯+ = 𝐺1 + 𝐺2 + ⋯ + 𝐺𝑛 = 𝐺𝑚
𝑅𝑚 𝑅1 𝑅2 𝑅𝑛

10-04-2023 EE151 - Dr. M. N. Alam, EED, NITW 5


Millman’s Theorem
©2023 Dr. M. N. Alam
• So, we get an equivalent current source as an equivalent parallel resistance

𝐼𝑚 = 𝑉1 𝐺1 + 𝑉2 𝐺2 + ⋯ + 𝑉𝑛 𝐺𝑛

1
𝑅𝑚 =
𝐺1 + 𝐺2 + ⋯ + 𝐺𝑛

• By source transformation, Millman’s equivalent network is obtained as shown below

𝑉1 𝐺1 +𝑉2 𝐺2 +⋯+𝑉𝑛 𝐺𝑛
𝑉𝑚 = 𝐼𝑚 𝑅𝑚 =
𝐺1 +𝐺2 +⋯+𝐺𝑛

10-04-2023 EE151 - Dr. M. N. Alam, EED, NITW 6


Millman’s Theorem
©2023 Dr. M. N. Alam
Dual of Millman’s Theorem:
• It states that “if there are 𝑛 current sources 𝐼1 , 𝐼2 , … , 𝐼𝑛 with internal
resistances 𝑅1 , 𝑅2 , … , 𝑅𝑛 respectively connected in series then these current
sources can be replaced by a single current source 𝐼𝑚 and a single parallel
resistance 𝑅𝑚 .”

• Where

10-04-2023 EE151 - Dr. M. N. Alam, EED, NITW 7


Millman’s Theorem
©2023 Dr. M. N. Alam
Steps to be Followed in Millman’s Theorem
1. Remove the load resistance 𝑅𝐿
2. Find Millman’s voltage across points A and B
𝑉1 𝐺1 + 𝑉2 𝐺2 + ⋯ + 𝑉𝑛 𝐺𝑛
𝑉𝑚 =
𝐺1 + 𝐺2 + ⋯ + 𝐺𝑛
3. Find Millman’s resistance 𝑅𝑚 between points A and B
1
𝑅𝑚 =
𝐺1 + 𝐺2 + ⋯ + 𝐺𝑛
4. Replace the network voltage by a voltage source 𝑉𝑚 in series with
resistance 𝑅𝑚
5. Find the current through 𝑅𝐿 using ohm’s law
𝑉𝑚
𝐼𝐿 =
𝑅𝑚 + 𝑅𝐿

10-04-2023 EE151 - Dr. M. N. Alam, EED, NITW 8


Millman’s Theorem
©2023 Dr. M. N. Alam

Numerical Example-17:
• Find current through 10 Ω resistor using Millman’s theorem.

10-04-2023 EE151 - Dr. M. N. Alam, EED, NITW 9


Millman’s Theorem
©2023 Dr. M. N. Alam

Solution:
Step I: Calculation of 𝑉𝑚

1 1 1
𝑉1 𝐺1 + 𝑉2 𝐺2 + 𝑉3 𝐺3 5 − 10 + 15
2 4 6
𝑉𝑚 = = = 2.73 𝑉
𝐺1 + 𝐺2 + 𝐺3 1 1 1
2+4+6

Step II: Calculation of 𝑅𝑚

1 1 1
𝑅𝑚 = = = = 1.09 Ω
𝐺𝑚 𝐺1 + 𝐺2 + 𝐺3 1 + 1 + 1
2 4 6

10-04-2023 EE151 - Dr. M. N. Alam, EED, NITW 10


Millman’s Theorem
©2023 Dr. M. N. Alam
Step III: Millman’s Equivalent

• Step IV: Calculation of 𝐼𝐿


𝑉𝑚 2.73
𝐼𝐿 = = = 0.25 𝐴
𝑅𝑚 + 𝑅𝐿 1.09 + 10

10-04-2023 EE151 - Dr. M. N. Alam, EED, NITW 11


Millman’s Theorem
©2023 Dr. M. N. Alam

Numerical Example-18:
• Find Millman’s equivalent for the left of the terminals A-B

10-04-2023 EE151 - Dr. M. N. Alam, EED, NITW 12


Millman’s Theorem
©2023 Dr. M. N. Alam

Solution:
• By source transformation,

Step I: Calculation of 𝑉𝑚

1 1
𝑉1 𝐺1 + 𝑉2 𝐺2 6 + 2
4 2
𝑉𝑚 = = = 3.33 𝑉
𝐺1 + 𝐺2 1 1
+
4 2

10-04-2023 EE151 - Dr. M. N. Alam, EED, NITW 13


Millman’s Theorem
©2023 Dr. M. N. Alam
Step II: Calculation of 𝑅𝑚

1 1 1
𝑅𝑚 = = = = 1.33 Ω
𝐺𝑚 𝐺1 + 𝐺2 1 + 1
4 2

Step III: Millman’s Equivalent

10-04-2023 EE151 - Dr. M. N. Alam, EED, NITW 14


Tellegen’s Theorem
©2023 Dr. M. N. Alam
• Tellegen’s theorem can be stated as
• In any linear, non-linear, passive, active, time-variant or time-invariant
network, the summation of power (instantaneous or complex power for ac
sources) is zero.
• In other words, if a network is having n branches
𝑛

෍ 𝑉𝑘 𝐼𝑘 = 0
𝑘=1
• In order to justify this theorem in electrc network, the first step is to find the
branch voltage drops and the corresponding branch currents using
conventional analysis.
• Telegen’s theorem can then be justified by summing all products of branch
voltages and currents.

10-04-2023 EE151 - Dr. M. N. Alam, EED, NITW 15


Tellegen’s Theorem
©2023 Dr. M. N. Alam

HW Problem:
• Justify Tellegen’s theorem in the network shown below.

10-04-2023 EE151 - Dr. M. N. Alam, EED, NITW 16

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