TRUIONG DH SU PHAM KY THUT VINH BE THI KEPT THUC MON HOC
KHOA DIEN, DIEN Hoc 1(y: 1 Nam hoc: 2024-2025
HQC phAn: He th6ng thong tin cong nghi'0
N45. HP: 3DN139DH
Trinh dO: Dai hoc,
Thai gian lam bai: 90 phut
BE SO 01
Cau Y NCii dung Di'e'm
1 2,0
Gingnhau: Day cle'u la 2 chuan truye'n thong sir dung de truyen tin hiti. Tin
hien là di@-lap mot chie'u. 0,5
Khac nhau
RS232
- TruyL an khong ct6i xung
- Six dung din ap: -15V±15V 0,75
- Ket not diem diem
- Truyen dir lieu glib PC voi moden, PLC, PC, tilt& bi do, ...
- Khoang cach truyen ngan, khan nhi6u kern
RS485
- Truyen an d6i xirng
- Sir dung din ap: -5V±5V
- Ket not da diem 0,75
- TruyL ar lieu trong mang cong nghi0
- Khoang cach truyen xa co the len den 1,5km, khan nhiL tot
2 2,0
Phuang phap truy nh:ap bus tin dinh: Phuang phap cluo.c thie't 14 trtroc khi N
thong di vao hoat dOng, phan chia theyi gian co dinh sir dung deang truyen cho
cac thie't bi tham gia vao N thong mang. Phuang phap nay dan gian, de thgc 0,5
hi.0 nhung hitt suat sir dung dungtruyen khong cao.
Wm c6 3 phuang phap: Chu/to', token passing, TDMA
Phuang phap chit to':
Kiem sok hoan toan giao ti6p trong h" thong, hoc chi clang vai tr6 phan Chia
quyL truy nhjp bus. N6u hoat ciOng din ra theo chu kST, tram chil ,se có trach
nhi:e'm chu dOng yeu cau du' lieu tir tram to' can giri va sau chuyen toi tram
to. can nh4n. Trong truang hop mot tram to' can trao doi bat among voi tram 0
khac phai thong bao yeu eau cua minh khi cluo'c tram chil hoi den va sau id() 0,5
the' phvc vu. Trinh tir tham gia giao ti6p, hay trinh tax hoi/dap cita cac tram tar
có the do ngtreyi dung qui dinh truck (tien dinh) bang cong cu cl:dt cau hinh.
Oing dung chil yeu : Pho bien trong cac N thong bus cap thap (bus twang hay
bus thietbi). Trao doi thong tin,hau nhu chi die ra gifra tram chu la thiet bi
dieu khien va cac tram to' là thiet bi trueyng ho4c cac module vao/raphan tan.
Phuang phap Token passing:
Nguyen1)'7: de cap phut quyen truy nhjp clueing truyen cho cac tram dan có nhu
cau truyen at' Ru, not the bai dugc ltru chuyen ten mot yang logic thiet 14p
bad cac tram do.
Khi mot tram nNn dugc the bai thi no dtxgc quyen sir dung clueing truyen trong 0,5
mot thoi gian xac dinh tru&c. Trong thai gian do no co the truyen mot hay nhi.L.
dan vi dir lieu. Khi dd het clit lieu ho4c het tiled gian cho phep, tram phai chuy6n
the bai den tram ti6p theo trong mach yang logic.
Ma hieu: QT.02.KTCL/BM.09b NO)/ ban hanh: 01/10 /2014 LAn ban hanh: 01
Nhu v4y,,cong v* dau tien la. phai thi6t lap Ong logic (hay con goi là yang
do) bao Om cac tram dang co nhu cau trao doi du lieu dugc xac dinh vi tri then
mot chu6i thir tax ma tram cuoi cung se tiep lien sau bai tram dau tien. M8i tram
dtzo.c biet dia chi ct.la tram ke truac \id sau no.
Thiin tax caa tram tren yang logic co the dOc 14p voi thin ti cua tram teen yang vat
lf. Cac tram khong hoac chua co nhu cau trao doi dir lieu thi khong dugc dua
vao yang logic. .
TDMA: Phan chia thei gian co dinh
Khe tp0 an (time slot)
„.........-%
1 N iTheo yeu cau
Chu kii bus (chu kit TDMA)
0,5
ting dung: Cho
yeu a cap trtamg
Thuong là ket hop voi Master/Slave (vi du Profibus-DP V2.0, Interbus) hoac
Token Passing (Foundation Fieldbus H1).
3 3,0
Da thirc G = 11011, b4c n = 4
Thong tin cAn truy&I I = 111111001, sau 5 bit 1 lien tie them 1 bit 0
nen 1,0
Da thdc P = 11111010010000
Lary P chia G 1,0
Ket qua 1011101100, du R = 100
Day bit gin di D=P+R= 11111010010100
Ben nh4n dugc chu8i bit: Ki6m tra sau 5 bit 1 lien ti6p co bit 0 hay khong, 10
chu8i bit nh'4n dugc co chia het cho G? Sau khi kiem tra xong thi loci bit 0 sau
5 bit 1 lien ti6p
3,0
4
Cam bin LM35
ULM35 = 0 ± 10MVX100 = 0 ± 1V 05
Cam bien do mix chat long
Uh = 4 ± 20(mA)xlid2 = 4 ± 20V
BO khu6ch dai cho cam bie'n cap nh* co N so khukh dai là:
5V
G==
1 5
BO khuech dai cho cam bie'n mire co N so khuech dai là:
5V —1
G2 = - = —5.
16V 16 0,5
BO khuech dai cho van tuyen tinh co N so khuech dai là:
24V
G3 = = 2,4
10V
IR) khuech dai cho van Ong co co h' so khuech dai là:
24V
G4 = = 2,4
10V
RF
BO khuk h dai khong dao G = 1 + R—
Viii GI chon RF là bin troy 101a va di6u chinh oa gia tri O. gia tri 4142 con
RG=1k0
MA hi#0: QT.02.KTCL/BM.09b Ngay ban Ural: 01/10 /2014 Can ban hanh: 01
Val G3 chon RF là bin troy 101a va di6u chinh a gia tri a gia tri 1,4kS2 con
RG=
Val G4 chon RF là bin troy 101M, va di6u chinh a gia tri a gia tri 1,41M con
RG=1 k,c2
0,5
Figure 1. DC.Coupled, G = +4, Bipolar Supply,
Specification and Test Circuit
Bo khuech dai dao G = — 12-1
RG
.1V PC0,41,..114,*
112
OPA2614
IOU
0,5
V 0--rvfv.
, Wail
Figure 2. DC-Coupled, G = -4, Bipolar Supply.
Specification and Test Circuit
Vali G2 chon RF là bin traf 5kQ, RG=11c0 mac not ti6p nhau 110 khu6ch dti dao
có RF = 1 kC2 va bin troy RG=22kQ, diL chinh y gia tri 16kS2
Card do
ULM35
G1
LCD
M UX AD0804 11C8051
UH
G2 RS232
PC
1,0
VAN
• G3
AD7524
DC
• G4
Ma hie;u: QT.02.KTCL/BM.09b Ngay ban hanh: 0 1/1 0 /2014 Lan ban hanh: 01
NgN An, ngay 12 thang 11 narn 2024
Du)* Ngueyi lam dap an
Nguy6n Khac TuAn Ngo Thi Le
MA h*I: QT.02.KTCL/BM.09b NO)/ ban hanh: 01/10 /2014 Lan ban hanh: 01
