0% found this document useful (0 votes)
18 views12 pages

7010 Computer Studies: MARK SCHEME For The May/June 2013 Series

This document is the mark scheme for the Cambridge International Examinations GCE Ordinary Level Computer Studies Paper 1 from May/June 2013. It outlines the marking criteria for various questions, including sensor applications, loop structures, network types, and programming concepts. The mark scheme serves as a guide for teachers and candidates, detailing how marks are awarded based on specific answers and criteria.

Uploaded by

Izumi Here
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
0% found this document useful (0 votes)
18 views12 pages

7010 Computer Studies: MARK SCHEME For The May/June 2013 Series

This document is the mark scheme for the Cambridge International Examinations GCE Ordinary Level Computer Studies Paper 1 from May/June 2013. It outlines the marking criteria for various questions, including sensor applications, loop structures, network types, and programming concepts. The mark scheme serves as a guide for teachers and candidates, detailing how marks are awarded based on specific answers and criteria.

Uploaded by

Izumi Here
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
You are on page 1/ 12

CAMBRIDGE INTERNATIONAL EXAMINATIONS

GCE Ordinary Level

MARK SCHEME for the May/June 2013 series

7010 COMPUTER STUDIES


7010/11 Paper 1, maximum raw mark 100

This mark scheme is published as an aid to teachers and candidates, to indicate the requirements of
the examination. It shows the basis on which Examiners were instructed to award marks. It does not
indicate the details of the discussions that took place at an Examiners’ meeting before marking began,
which would have considered the acceptability of alternative answers.

Mark schemes should be read in conjunction with the question paper and the Principal Examiner
Report for Teachers.

Cambridge will not enter into discussions about these mark schemes.

Cambridge is publishing the mark schemes for the May/June 2013 series for most IGCSE, GCE
Advanced Level and Advanced Subsidiary Level components and some Ordinary Level components.
Page 2 Mark Scheme Syllabus Paper
GCE O LEVEL – May/June 2013 7010 11

1 A different sensor is needed for each application

(i) central heating system


– temperature sensor

(ii) automatic doors


– pressure sensor/pad
– light sensor
– infra red sensor

(iii) detection of intruders


– pressure sensor/pad
– light sensor
– infra red sensor
– sound/acoustic sensor

(iv) greenhouse monitoring


– temperature sensor
– moisture/humidity sensor
– light sensor
– pH sensor
– CO2/O2 (levels) sensor [4]

2 1 mark for name of loop structure + 1 mark for correct loop structure including initialisation + 1
mark for correct input inside loop:

for (… to … next) loop

example: for x = 1 to 10
input number
next x

repeat (… until) loop

example: c = 0
repeat
input number
c=c+1
until c > 9 (or equivalent)

while (… endwhile/wend) loop

example: c = 0
while c <> 10 do
input number
c=c+1
endwhile

[6]

© Cambridge International Examinations 2013


Page 3 Mark Scheme Syllabus Paper
GCE O LEVEL – May/June 2013 7010 11

(3) (a) 2 marks minus 1 for each error.

activity Yes No


chat rooms


cookies


pharming


virus


VoIP
[2]

(b) 1 mark per description

chat rooms
– place for online conversations
– use instant messaging
– to allow communications in real time
– users register and choose user name and password
– log onto enter chat room using user name and password
– list of people currently in room will be alerted as soon as new person enters room

cookies
– small files sent to user’s computer when visiting a website
– stores information about user which is accessed every time user visits that website
– lets website know who you are/past visitor

pharming
– malicious code installed on a user’s computer/web server
– misdirecting the user(s) to a bogus/fake fraudulent website
– can use domain name poisoning

virus
– programs that replicate themselves
– designed to disrupt computer system
– delete/alter/corrupt files

VoIP
– Voice over Internet Protocol
– system that allows user to talk to another user using the Internet
– can use USB phone or head set (microphone and headphones)
– requires fast broadband connection to work
– can also combine with webcam and instant messaging [5]

© Cambridge International Examinations 2013


Page 4 Mark Scheme Syllabus Paper
GCE O LEVEL – May/June 2013 7010 11

(4) (a) (i) ring [1]

(ii) star [1]

(b) 1 mark for benefit and 1 mark for drawback

benefit
– share resources such as hardware e.g. printer, software
– easier to monitor what users are doing
– easier communication between users

drawback
– greater risk of viruses
– greater security risk (such as hacking)
– expensive hardware such as servers, cabling, …
– needs management [2]

(c) 1 mark for LAN feature and 1 mark for WAN feature

LAN
– used over a small geographic area (e.g. one building)
– doesn’t require external telecommunication

WAN
– used over remote/vast geographic area (e.g. continents)
– needs modem, external phone lines, microwaves… [2]

5 1 mark for each correct device

application hardware device

automatic stock control system in a


barcode reader/scanner/EFTPOS terminal
supermarket

keeping track of the live stock on a large barcode/RFID/microchip reader


farm

input data into a computer using speech microphone


recognition

[3]

© Cambridge International Examinations 2013


Page 5 Mark Scheme Syllabus Paper
GCE O LEVEL – May/June 2013 7010 11

6
generating intermediate
frames between two images
to give the appearance of morphing
movement

special effect that changes


one image into another
image (e.g. the special effect rendering
of a person slowly turning
into an alien)

generating a final completed


3D image from a given 2D tweening
model by the use of software

very simple drawing made


up of lines, circles and dots key frames
used to depict a character
(e.g. a human being)

variable controlling the stick figure


position of part of an
animated character (e.g.
control changes in a facial
expression)

drawings that define the


starting point and end point
of any smooth transition in avar
animation

[5]

© Cambridge International Examinations 2013


Page 6 Mark Scheme Syllabus Paper
GCE O LEVEL – May/June 2013 7010 11

7 1 mark for each correct term.

(i) verification [1]

(ii) interrupt [1]

(iii) handshaking [1]

(iv) (printer) buffer, RAM [1]

(v) checksum [1]

(8) (a) Any three features from:


– road map and satellite views
– superimpose road map and satellite images
– ability to zoom in and zoom out
– arrow keys to move N, S, E and W
– detailed directions to get from customer’s home to the house
– ability to use street name, post code, zip code (etc.) in searches
– “pins” to show exact location of house on the map/hotspot
– local amenities e.g. post office, school etc.
– scale/conversion of miles to kilometres [3]

(b) (i) virtual reality [1]

(ii) Any three from:


– zoom in and out
– buttons to navigate between rooms/enter the tour
– arrow keys to rotate through 360º
– print out of rooms
– save houses visited as “favourites”
– choice of area within house to view [3]

(9) (a) Any three from:


– knowledge base
– inference engine
– rule(s) base
– (expert system) shell
– explanation system [3]

(b) Any two from:


– yes/no type of questions
– multiple choice questions
– explanations/examples [2]

© Cambridge International Examinations 2013


Page 7 Mark Scheme Syllabus Paper
GCE O LEVEL – May/June 2013 7010 11

10 (a) (i)
A B X
0
0
0
1
1
0
} 1 mark

1
1
0
1
0
0
} 1 mark

[2]

(ii) NOR gate (allow follow through from part (i)) [1]

(b) (i)
A
0
B
0
C
0
X
0 } 1 mark

}
0 0 1 1
0 1 0 0 1 mark
0 1 1
}
1
1 0 0 0 1 mark
1 0 1 1
1
1
1
1
0
1
0
1
} 1 mark

[4]

(ii) input C only [1]

11 (a)

row value
1
2
255
192
} 1 mark

3
4
96
48
} 1 mark

5
6
96
192
} 1 mark

7
8
255
0
} 1 mark

[4]

(b) 128 64 32 16 8 4 2 1

} 1 mark

} 1 mark

} 1 mark

} 1 mark
[4]

© Cambridge International Examinations 2013


Page 8 Mark Scheme Syllabus Paper
GCE O LEVEL – May/June 2013 7010 11

12 (a) 7 [1]

(b) KO, OS, SN

(–1 mark for each error) [2]

(c) (Share price ($) < 50.00) OR (Profits (billion $) > 8.0)

< - - - - - (1 mark) - - - - -> < - - - - - - - (1 mark) - - - - - - - >

(Profits (billion $) > 8.0) OR (Share price ($) < 50.00)

< - - - - - (1 mark) - - - - > < - - - - - - - (1 mark) - - - - - - - > [2]

© Cambridge International Examinations 2013


Page 9 Mark Scheme Syllabus Paper
GCE O LEVEL – May/June 2013 7010 11

13 START

X=0

END INPUT 8-
digit id

1 mark
Yes
10 11
9 1 mark

No

Yes
8/3

No

Yes
3/8 1 mark

No

7 1 mark

Yes
4
No

6 1 mark

INPUT 3
characters from
password
1 mark

Yes No
2 1 END

[6]

© Cambridge International Examinations 2013


Page 10 Mark Scheme Syllabus Paper
GCE O LEVEL – May/June 2013 7010 11

14 (a) Any two from:


– if all computers ‘agree’ system works automatically
– if one computer fails, there are still 2 working
– if one computer is faulty, use “majority output” to make decisions
– increases passenger confidence in the system [2]

(b) Any four points from:


– sensor readings are taken (continuously)
– these are converted to digital (using ADC)
– data/signals sent to the computer
– the computer compares the data received with stored values/computer interprets signals
– if outside acceptable range, computer sends signals
– signals converted to analogue (using DAC)
– fuel to engines is increased/decreased to control aeroplane speed
– if one computer gives a different signal, a warning message is sent [4]

(c) (i) Any three points from:


– satellite sends/broadcasts signals to earth
– GPS system uses satellite signals to calculate position of aeroplane
– …..data from at least three satellites needed to calculate this position
– satellites use atomic clocks to ensure very accurate timing
– each satellite transmits data giving its position and time
– computer compares calculated position supplied by GPS system with flight path …
– … if aeroplane off course, then computer sends signals …
– … and rudder settings are changed (using motors) to control direction
– if aeroplane is on course, no action is taken
– direction checking is carried out continuously [3]

(ii) 1 mark for benefit and 1 mark for drawback

benefit
– estimate time of arrival at destination/remaining flight time
– location of alternative airports in case of emergency
– more accurate flight path maintained
– more efficient fuel costs since fewer course corrections are made

drawback
– if weather is bad, GPS and computer won’t automatically “steer around the problem”
– loss of satellite signal could lead to wrong direction/decision making [2]

© Cambridge International Examinations 2013


Page 11 Mark Scheme Syllabus Paper
GCE O LEVEL – May/June 2013 7010 11

15 (a) B2 – B3 [1]

(b) B5/100 or B5*1% [1]

(c) C4 * C5 * B6 [1]

(d) (C4 + C7) / (B6 * 12)


< 1 mark > < 1 mark > [2]

(e) B2
– check for negative numbers
– check for numbers only (character/type check)
– presence check
– range check

B5
– range check
– character/type check
– presence check

(validation checks must be DIFFERENT for each part of question) [2]

(f) Any two points from:


– input data with known results
– compare output with known results
– use data to check if validation rules work
– use of normal and abnormal and extreme data
– check deposit < price [2]

© Cambridge International Examinations 2013


Page 12 Mark Scheme Syllabus Paper
GCE O LEVEL – May/June 2013 7010 11

16 marking points:
– set total of barcodes entered correctly to zero (initialisation, e.g. match = 0 below) 1 mark
– input 100 numbers (correct loop structure) 1 mark
– input 5 digits of the barcode (a, b, c, d and e) INSIDE a loop 1 mark
– find total value using barcode formula given 1 mark
– method for finding remainder 2 marks
(e.g. subtract 10 from total (1 mark) using a loop (1 mark) until total < 10)
– finding out how many correct barcodes were input 1 mark
– correct output (OUTSIDE loop – must have a loop to get mark) 1 mark

example of suitable coding:

match = 0
1 mark
for number = 1 to 100 1 mark
input a, b, c, d, e 1 mark
total = (a * 3) + (c * 3) + (b * 2) + (d * 2) 1 mark
repeat
total = total – 10 2 marks
until total < 10
if total = e then match = match + 1 1 mark
next number
print match 1 mark
[5]

© Cambridge International Examinations 2013

You might also like