MBA Wallah

Batch: PIONEER (CAT)

Subject : Data Interpretation & Logical Reasoning
DPP - 01
Topic : Data Interpretation - Tables

Direction : Answer the questions on the basis of the Directions: A business strategy competition was
information given below. conducted in which 5 schools A, B, C, D and E
participated in the final round. The event was finally
DIFFERENT HOTEL CHAINS
won by school C. The following table gives the number
Net profit Percentage of profits
of girls from A, B, D and E who participated in the
(Rs. In crore) disbursed as dividend
event as a percentage of the total students from school
2018-19 2019-20 2018-19 2019-20 C who participated in the event.
H1 471 531 35 45 School %
H2 259 501 45 45 A 40
H3 282 322 40 40 B 15
H4 229 251 55 55 D 25
H5 31 41 40 40 E 20
H6 46 42.5 30 30 It is also known that the ratio of the number of girls to
H7 129 138 85 85 boys in the schools A, B, D and E who participated in
H8 20 37.5 45 40 the event was 1:3, 3:2, 4:3 and 5:3 in no particular
H9 96 123 50 50 order.
H10 6 7 38 30
H11 36 40 60 50 6. If it is known that 80 students participated from
H12 25 28 60 75 school C, find the difference between the number
of boys who participated from school B and school
1. Find the approximate difference between the profit D?
of H1 in 2018-19 and the average profit of all the (a) 4 (b) 6
hotels together in 2019  20? (c) 8 (d) Cannot be determined
(a) 346 (b) 169
(c) 865 (d) 300 7. It is known that the number of boys who
participated from schools A, B, D and E were 14,
2. Which hotel disbursed the highest dividend in 24, 27 and 30 in no particular order. Find the
201819? maximum number of students who participated
(a) H10 (b) H1 from the four schools put together?
(c) H2 (d) H4 (a) 235 (b) 225
(c) 210 (d) Cannot be determined
3. What is the percentage increase in net profits of
H4 in 2019-20? 8. It is known that 180 students participated from
(a) 9.6% (b) 9.1% school C. The maximum number of students who
(c) 8.8% (d) 9.9% participated is from which school?
(a) A (b) B
4. Which hotel showed the second highest percentage (c) E (d) Cannot be determined
increase in profits in 2019-20 out of H2, H8, H5
and H1. 9. It is known that 80 students participated from
(a) H2 (b) H8 school C. Which among the following can be the
(c) H5 (d) H1 ratio of the number of boys who participated from
school A to the total number of students who
5. Find the ratio between the profit earned by H5 and participated from school B?
H7 together in 2018-19 to the profit earned by H6 (a) 5 : 6
and H8 together in 2019  20? (b) 6 : 5
(a) 2 : 1 (b) 11 : 29 (c) 1 : 1
(c) 1 : 1 (d) 3 : 4 (d) Cannot be determined
 MBA Wallah

10. It is known that 180 students participated from 15. Find the average number of total 30% Alcohol
school C. Find the number of boys who sanitizers sold by all the five states together?
participated from school D? (a) 1080 (b) 980
(a) 27 (b) 45 (c) 910 (d) 827
(c) 72 (d) 36
Direction : Refer to the data below and answer the
Directions: The table given below shows the total questions that follow.
number of sanitizers which were estimated to be sold in A famous Maths book was published in a country in
five states. Out of total sanitizers sold a percentage of four languages namely, Bengali, Marathi, Spanish and
70% Alcohol sanitizers sold, and the ratio between English. These books were published in two types,
30% Alcohol and 0% Alcohol sanitizers is given. Study “Notebooks” and “Practice books”. Some of these
the data carefully and answer the following questions. books are “Good” and some are “Not Good” according
States Sanitizers 70% 30% to the feedback given by the students.
that can be Alcohol Alcohol : The following table gives the information on the books
sold sanitizers 0% Alcohol published in the country.
sold (in%) sanitizers
U.P. 2300 15% 9:8 Bengali Marathi Spanish English
West Bengal 4500 35% 5:8 Total 400 500 200 300
Telangana 3800 25% 4:5 number of
Gujarat 1000 45% 5:3 books
Delhi 1500 20% 8:5 published
Note: 200 sanitizers remain unsold in each state which
can be sold. Number of 60% 80% 40% 70%
notebooks as
Total sanitizers in each state = 70% Alcohol sanitizers
a percentage
+ 30% Alcohol sanitizers + 0% Alcohol sanitizers +
of total
unsold sanitizers books
published
11. Total 70% Alcohol and 0% Alcohol sanitizers sold
in West Bengal is approximately what percent Percent of 50% 37.5% 25% 40%
more than the total number of 70% Alcohol and notebooks
30% Alcohol sanitizers sold in Gujarat state? that were
(a) 100% (b) 220% “Good”
(c) 375% (d) 408% according to
the students
12. Total 30% Alcohol sanitizers sold in U.P. is how
much less/more than 0% Alcohol sanitizers sold in Percent of 12.5% 40% 60% 30%
Delhi? Practice
(a) 320 (b) 425 books that
(c) 545 (d) 670 were “Not
Good”
13. Find the ratio between total 0% Alcohol sanitizers according
sold in Telangana and Gujarat together to total to the
30% Alcohol sanitizers sold in West Bengal and students
Telangana?
(a) 1 : 3 (b) 333 : 455 Total 400 500 200 300
(c) 299 : 311 (d) 457 : 333 number of
books
14. Find the average number of total 70% Alcohol published
sanitizers sold by all the five states together?
(a) 300 (b) 420
(c) 595 (d) 668
 MBA Wallah

16. What percent of the total books published in the 24. What is the percentage of Married faculties among
country received “Good” feedback by the Associate Teachers?
students? [Approximate to the nearest integer] (a) 46 (b) 50.5
(c) 62 (d) 66
17. Books published in how many languages received 25. If among the Assistant Teachers, 60% of females
“Good” feedback for at least 60% of the total are married, what is the number of married males?
books published in that language? (a) 320 (b) 315
(c) 210 (d) 185
18. What was the percent of Notebooks out of the total
books published in the four languages in the Directions: Answer the questions based on the
information given below.
country? [Approximate to the nearest integer]
The table given below shows the average monthly
income (in Rs.) and annual savings (in Rs.) of four
19. What was the percent of Practice books that different persons, namely ‘A’, ‘B’, ‘C’ and ‘D’. The
received “Good” feedback from the students? table also shows the number of months for which a
[Approximate to the nearest integer] person was employed during the given year.
Note:
20. Find the total number of Books that received “Not (a) The average monthly income and average monthly
expenditure are calculated for the whole year i.e.
Good” feedback by the students?
12 months, irrespective of the number of months
for which the person is employed.
Direction : Directions: Read the following passage and (b) For each person, actual average monthly income =
answer the questions that follow: (Total annual income)/(number of months for
The School has a total of 2000 faculty members, 62.5% which he is employed)
of whom are Assistant Teachers, and the rest are
divided in the ratio 3:2 between Associate Teachers and Name Average Annual Number of
monthly Saving months for
Teachers respectively. Income (In Rs.) which the
Females Married (In Rs.) person was
Assistant --- 40% employed
Teachers A 12,000 48,000 10
Associate 60% --- B 16,000 72,000 8
Teachers C 15,000 72,000 12
Teachers 55% 71% D 20,000 60,000 10
Total 48% 50.5%
The table shows the percentage of female faculty 26. Find the difference (in Rs.) between sum of
members and the percentage of married faculties in a average monthly expenditure and average monthly
School. savings of ‘A’ and actual average monthly income
of ‘B’.
21. What is the percentage of Male Assistant (a) 12000 (b) 6000
Teachers? (c) 5000 (d) 1000
(a) 42% (b) 55%
(c) 61% (d) 58% 27. Out of the given four persons whose actual
average monthly income was highest?
22. Among Married Associate Teachers, if 66.66 %are (a) A (b) B
female, what is the difference between the number (c) D (d) Both (B) and D
of married males and unmarried females?
(a) 144 (b) 27 28. If both ‘D’ and ‘A’ were employed for the first six
(c) 72 (d) 99 months of the given year, then find the difference
between the amount earned by them during the
23. What is the percentage of married faculties among first six months of the year.
Assistant Teachers and Teachers combined? (a) Rs 48,000 (b) Rs 56,400
(a) 50.5 (b) 66 (c) Rs 64,000 (d) Rs 57,600
(c) 46 (d) 58
 MBA Wallah

29. During the given year, ‘B’ worked at two different 30. What is the mean of the average monthly savings
companies namely ‘X’ and ‘Y’. If his monthly of C and D?
salary at ‘X’ and ‘Y’ was Rs. 30,000 and Rs. (a) 2200 (b) 4400
18,000, respectively, then find the number of (c) 6600 (d) 5500
months for which he worked at ‘X’ given that his
salary is his only source of income.
(a) 2 (b) 4
(c) 6 (d) 5
 MBA Wallah

Answer Key
1. (d) 11. (d) 21. (d)
2. (b) 12. (c) 22. (b)
3. (a) 13. (b) 23. (c)
4. (b) 14. (d) 24. (d)
5. (a) 15. (d) 25. (d)
6. (a) 16. (49) 26. (a)
7. (c) 17. (1) 27. (d)
8. (d) 18. (66) 28. (d)
9. (b) 19. (66) 29. (b)
10. (a) 20. (715) 30. (d)
 MBA Wallah

Hints& Solutions
1. (d) Total number of profit get by H6 and H8 together
Profit of H1 in 2018-19 = 471 in 2019–20
Average profit of all the hotels together in 2019-20 = 42.5 + 37.5 = 80
531  501  322  251  41  42.5  138  37.5  123  7  40  28 Required ratio = 160 : 80
12 =2:1
= 171.833
Required difference = 471 – 171.833 = 299.167 6. (a)
= 300 (approx.) It is known that 80 students participated from
school C. The number of girls from schools A, B,
2. (b) D and E will be as follows:
H10 : 0.38 × 6 = 2.28 School % Number of Girls
H1 : 0.35 × 471 = 164.85 A 40 32
H2 : 0.45 × 259 = 116.55 B 15 12
H4 : 0.55 × 229 = 125.95 D 25 20
E 20 16
3. (a) It is also known that the ratio of the number of
Percentage increase girls to boys in the schools A, B, D and E who
251  229 participated was 1:3, 3:2, 4:3 and 5:3 in no
  100
229 particular order.
= 9.606% The ratio 5 : 3 must be of school D as there is no
= 9.6% other number for the total girls which is a multiple
of 5. If we take the ratio as 4 : 3 for D then for E
4. (b) we don't have any ratio because 16 is not a
531  471 multiple of 5 and 3. Similarly, the ratio 3 : 2 must
H1 percentage increase =  100  12.7%
471 be of school B.
=12.7% 5
For school D, of total = 20
501  259 8
H2 percentage increase = 100  93.4%
259 Total students in D = 32
41  31 3 
H5 percentage increase =  100  32.25% Number of boys in D = 12  of 32 
31 8 
37.5  20 3
H8 percentage increase = 100  87.5% For school B, of total = 12
20 5
Hence, percentage increase is the second highest Total students = 20
for H8.
Number of boys in B = 8
Required difference = 12  8 = 4.
5. (a)
Number of profit get by H5 in 2018-19 = 31
7. (c)
Number of profit get by H7 in 2018-19 = 129
It is known that the ratio of the number of girls to
Total number of profit get by H5 and H7 together
boys in the schools A, B, D and E who
in 2018–19
participated was 1:3, 3:2, 4:3 and 5:3 in no
= 31 + 129 = 160
particular order.
Number of profit get by H6 in 2019  20 = 42.5
Number of profit get by H8 in 2019  20 = 37.5
 MBA Wallah

3 2 3 School % Number of Girls

Boys will be of the total, of the total, of
4 5 7 A 40 32
3 B 15 12
the total and of the total.
8 D 25 20
It is given that the number of boys who E 20 16
participated from the mentioned 4 schools is 14, It is also known that the ratio of the number of
24, 27 and 30 in no particular order. girls to boys who participated in the schools A, B,
For maximum value we need to have D and E was 1:3, 3:2, 4:3, and 5:3 in no particular
3 order.
of total 1 = 30
8 The ratio of 5:3 must be of school D as there is no
Total 1 = 80 other number for the total girls which is a multiple
3 of 5. If we take the ratio as 4 : 3 for D then for E
of total 2 = 27
7 we don't have any ratio because 16 is not a
Total 2 = 63 multiple of 5 and 3. Similarly, the ratio of 3 : 2
3 must be of school B.
of total 3 = 24
4 Let the total number of students in school B be q.
Total 3 = 32 3
of q = 12
2 5
of total 4 = 14
5 q = 20
Total 4 = 35 Let the total number of students in School A be p.
Maximum strength = 80 + 63 + 32 + 35 = 210 The ratio of girls to boys for school A can be
students. either 1 : 3 or 4 : 3.
If the ratio is 1:3 then
8. (d) 1
of the total p is 32
It is known that 80 students participated from 4
school C. The number of girls from schools A, B, Therefore, p = 128
D and E will be as follows: Number of boys from A = 128 – 32 = 96
School % Number of Girls The required ratio of the number of boys from A to
A 40 72 the number of students from B
B 15 27 = 96 : 20 = 24 : 5
D 25 45 If the ratio is 4 : 3 then
E 20 36 4
of the total p is 32
It is given that 180 students participated from 7
school C and so the number of girls from schools Therefore, p = 56
A, B, D and E will be as shown above. Number of boys from A = 56 – 32 = 24
It is known that the ratio of the number of girls to The required ratio of the number of boys from A to
boys in the schools A, B, D and E who participated the number of students from B
was 1:3, 3:2, 4:3 and 5:3 in no particular order. = 24 : 20 = 6 : 5.
Since we do not know the particular order, we
cannot definitely identify the school with the 10. (a)
maximum participation. School % Number of Girls
A 40 72
9. (b) B 15 27
It is known that 80 students participated from D 25 45
school C. The number of girls from schools A, B, E 20 36
D and E will be as follows:
 MBA Wallah

It is given that 180 students participated from 13. (b)

school C and so the number of girls from schools 0% Alcohol sanitizers sold in Telangana and
A, B, D and E will be as shown above. Gujarat together
It is known that the ratio of the number of girls to 75 5 55 3
 3600    800  
boys in the schools A, B, D and E who participated 100 9 100 8
was 1:3, 3:2, 4:3 and 5:3 in no particular order. = 1500 + 165
The ratio of girls to boys for school D must be 5:3 = 1665
30% Alcohol sanitizers sold in West Bengal and
because if we choose any other ratio then there is
Telangana together
no number which could be divided by 5.
65 5 75 4
Let the total students in school D be s.  4300    3600  
100 13 100 9
5
So, of s = 45 = 1075 + 1200 = 2275
8 1665 333
s = 72. Required Ratio   .
2275 455
Number of boys who participated from school
D = 72  45 = 27. 14. (d)
Total number of 70% Alcohol sanitizers sold by
11. (d) all the five states together
Total 70% Alcohol and 0% Alcohol sanitizers sold 15 35 25 45
 2100   4300   3600   800 
in West Bengal 100 100 100 100
35 65 8 20
 4300   4300   1300 
100 100 13 100
= 1505 + 1720 = 3225 = 315 + 1505 + 900 + 360 + 260 = 3340
Total number of 70% Alcohol and 30% Alcohol 3340
Required average   668
sanitizers sold in Gujarat 5
45 55 5
 800   800   15. (d)
100 100 8
= 360 + 275 = 635 States Sanitiz 70% 30% 30% Alcohol
Required percentage ers that Alcoho Alcoho sanitizers sold
3225  635 can be l l : 0% (in %)
  100
635 sold sanitize Alcoho
2590 rs sold l
  100 (in%) sanitize
635
= 407.87% rs
U.P. 2300 15% 9:8 9
85%   45%
17
12. (c)
30% Alcohol sanitizers sold in U.P. West 4500 35% 5:8 5
85 9 65%   25%
 2100   Bengal 13
100 17
= 945 Telang 3800 25% 4:5 4 100
75%   %
0% Alcohol sanitizers sold in Delhi ana 9 3
80 5
 1300   Gujara 1000 45% 5:3 5 275
100 13 55%   %
t 8 8
= 400
Required difference = 945 – 400 = 545
Delhi 1500 20% 8:5 8 640
80%   %
13 13
 MBA Wallah

So, we can infer that the number of 30% Alcohol s that =

sanitizers sold in the states are: were 250
U.P. : 45%× (2300 - 200) = 945 “Not
West Bengal: 25% × (4500 – 200) = 1075 Good”
4
Telangana: (3800 – 200) × 75% × = 1200
9 Number 12.5 40% 60% 30% 159
5 of % of of of 120 of 90
Gujarat: (1000 – 200) × 55% × = 275
8 Practice 160 = 100 = 72 = 27
8 books 20 = 40
Delhi: (1500 – 200) × 80% × = 640 that were
13
Hence the average is “Not
945  1075  1200  275  640 Good”
  827.
5
Number 160 – 100 120 – 90 – 311
16. (49) of 20 = – 40 72 = 27 =
We can make a table on the basis of the Practice 140 = 60 48 63
information given, books
Beng Mara Spani Engli Tota that were
ali thi sh sh l “Good”

Total 400 500 200 300 1400 Total number of books that received “Good”
number feedback by the students = 374 + 311 = 685
of books 685
Required percent = × 100 = 48.9%
published 1400
= 49 (approx.)
Number 60% 80% 40% 70% 930
of of of of 200 of 17. (1)
notebook 400 = 500 = 80 300 = We can make a table on the basis of the
s 240 = 210 information given,
400 Beng Mara Spani Engli Tota
ali thi sh sh l
Number 400 - 500 200 – 300 – 470 Total 400 500 200 300 1400
of 240 = – 80 = 210 = number
practice 160 400 120 90 of books
books = published
100
Number 60% 80% 40% 70% 930
Number 50% 37.5 25% 40% 374 of of of of 200 of
of of % of of 80 of notebook 400 = 500 = 80 300 =
notebook 240 = 400 = 20 210 = s 240 = 210
s that 120 = 84 400
were 150
“Good” Number 400 - 500 200 – 300 – 470
of 240 = – 80 = 210 =
Number 240 – 400 80 – 210 – 556 practice 160 400 120 90
of 120 = – 20 = 84 = books =
notebook 120 150 60 126
 MBA Wallah

100
18. (66)
Number 50% 37.5 25% 40% 374 We can make a table on the basis of the
of of % of of 80 of information given,
notebook 240 = 400 = 20 210 = Beng Mara Spani Engli Tota
s that 120 = 84 ali thi sh sh l
were 150
Total 400 500 200 300 1400
“Good”
number
of books
Number 240 – 400 80 – 210 – 556
published
of 120 = – 20 = 84 =
notebook 120 150 60 126
Number 60% 80% 40% 70% 930
s that =
of of of of 200 of
were 250
notebook 400 = 500 = 80 300 =
“Not
s 240 = 210
Good”
400

Number 12.5 40% 60% 30% 159

Number 400 - 500 200 – 300 – 470
of % of of of 120 of 90
of 240 = – 80 = 210 =
Practice 160 = 100 = 72 = 27
practice 160 400 120 90
books 20 = 40
books =
that were
100
“Not
Good”
Number 50% 37.5 25% 40% 374
of of % of of 80 of
Number 160 – 100 120 – 90 – 311
notebook 240 = 400 = 20 210 =
of 20 = – 40 72 = 27 =
s that 120 = 84
Practice 140 = 60 48 63
were 150
books
“Good”
that were
“Good”
Number 240 – 400 80 – 210 – 556
Total number of Bengali language books that of 120 = – 20 = 84 =
received “Good” feedback by the students notebook 120 150 60 126
= 120 + 140 = 260 s that =
Total number of Marathi language books that were 250
received “Good” feedback by the students “Not
= 150 + 60 = 210 Good”
Total number of Spanish language books that
received “Good” feedback by the students Number 12.5 40% 60% 30% 159
= 20 + 48 = 68 of % of of of 120 of 90
Total number of English language books that Practice 160 = 100 = 72 = 27
received “Good” feedback by the students books 20 = 40
= 84 + 63 = 147 that were
We can observe that only for Bengali language “Not
books, books have received “Good” feedback for Good”
at least 60% of the total books published in that
language.
 MBA Wallah

Good”
Number 160 – 100 120 – 90 – 311
of 20 = – 40 72 = 27 =
Number 12.5 40% 60% 30% 159
Practice 140 = 60 48 63
of % of of of 120 of 90
books
Practice 160 = 100 = 72 = 27
that were
books 20 = 40
“Good”
that were
930 “Not
Required percent = ×100 = 66.4%
1400 Good”
= 66 (approx.)
Number 160 – 100 120 – 90 – 311
19. (66) of 20 = – 40 72 = 27 =
We can make a table on the basis of the Practice 140 = 60 48 63
information given, books
Beng Mara Spani Engli Tota that were
ali thi sh sh l “Good”

Total 400 500 200 300 1400 311

Required percent = ×100 = 66.2%
number 470
of books = 66 (approx.)
published
20. (715)
Number 60% 80% 40% 70% 930 We can make a table on the basis of the
of of of of 200 of information given,
notebook 400 = 500 = 80 300 = Beng Mara Spani Engli Tota
s 240 = 210 ali thi sh sh l
400
Total 400 500 200 300 1400
number
Number 400 - 500 200 – 300 – 470
of books
of 240 = – 80 = 210 =
published
practice 160 400 120 90
books =
Number 60% 80% 40% 70% 930
100
of of of of 200 of
notebook 400 = 500 = 80 300 =
Number 50% 37.5 25% 40% 374
s 240 = 210
of of % of of 80 of
400
notebook 240 = 400 = 20 210 =
s that 120 = 84
Number 400 - 500 200 – 300 – 470
were 150
of 240 = – 80 = 210 =
“Good”
practice 160 400 120 90
books =
Number 240 – 400 80 – 210 – 556
100
of 120 = – 20 = 84 =
notebook 120 150 60 126
Number 50% 37.5 25% 40% 374
s that =
of of % of of 80 of
were 250
notebook 240 = 400 = 20 210 =
“Not
s that =
 MBA Wallah

were 120 150 84 5

No. of Assistant Teachers = 2000 × = 1250
“Good” 8
3
No. of Assistant Teachers = 750 × = 450
Number 240 – 400 80 – 210 – 556 5
of 120 = – 20 = 84 = 2
No. of Assistant Teachers = 750 × = 300
notebook 120 150 60 126 5
s that = If the percentage of married Assistant Teachers is
were 250 x%, then
“Not 1250x% + 450 × 0.6 + 300 × 0.55 = 2000 × 50.5
Good” x = 66%
Associate Teachers, who are married
Number 12.5 40% 60% 30% 159 60
= 450   297
of % of of of 120 of 90 100
Practice 160 = 100 = 72 = 27 2
Now out of 297 people, 66 % % are female so
books 20 = 40 3
that were the rest will be male i.e., 3313 %
“Not 1
297   99
Good” 3
60
Total no. females = 450   270
Number 160 – 100 120 – 90 – 311 100
of 20 = – 40 72 = 27 = 2
No. of females who are married = 297   198
Practice 140 = 60 48 63 3
books No. of females who are unmarried
that were = 270  198= 72
“Good” Therefore, the answer would be
= 99 – 72 = 27.
Total number of Books that received “Not Good”
feedback by the students = 556 + 159 = 715. 23. (c)
5
21. (d) 62.5% 
8
5
62.5%  5
8 No. of Assistant Teachers = 2000 × = 1250
8
5
No. of Assistant Teachers = 2000 × = 1250 3
8 No. of Assistant Teachers = 750 × = 450
5
3
No. of Assistant Teachers = 750 × = 450 2
5 No. of Assistant Teachers = 750 × = 300
5
2
No. of Assistant Teachers = 750 × = 300 Number of Married Assistant Teachers
5
= 1250 × 40% = 500
If the percentage of Female Assistant Teachers is
Number of Married Teachers = 300 × 71% = 213
x%, then
Total number of Assistant Teachers and Teachers
1250x% + 450 × 0.6 + 300 × 0.55 = 2000 × 0.48
= 1250 + 300 = 1550
1250x% = 960  165  270
x = 42% % of married faculties among Assistant Teachers
So, the answer would be = (10042) = 58% and Teachers are
500  213
=  100  46%
22. (b) 1550
5
62.5% 
8
 MBA Wallah

24. (d) = 144000 – 48000 = Rs. 96,000

5 Average monthly expenditure of ‘A’
62.5% 
8 = 96000 ÷ 12 = Rs. 8,000
5 Similarly,
No. of Assistant Teachers = 2000 × = 1250
8 Name Average Actual Average Average
3 monthly average monthly monthly
No. of Assistant Teachers = 750 × = 450 income monthly expenditure saving
5
(in Rs.) income (in Rs.) (in Rs.)
2
No. of Assistant Teachers = 750 × = 300 (in Rs.)
5 A 12,000 14,400 8000 4000
Let the percentage of married members in B 16,000 24,000 10000 6000
Associate Teachers is Y. C 15,000 15,000 9000 6000
1250 × 40% + 450 × Y% + 300 × 71% D 20,000 24,000 15000 5000
= 2000 50.5% Required difference = 24000 – (8000 + 4000)
Y = 66%. = 24000 – 12000 = Rs. 12,000
Hence, option A is the correct answer.
25. (d)
5 27. (d)
62.5% 
8 For ‘A’:
5 Average monthly income = Rs. 12,000
No. of Assistant Teachers = 2000 × = 1250
8 Amount earned by ‘A’ during the year
If the percentage of Female Assistant Teachers is = 12000 × 12 = Rs. 1,44,000
x%, then Average amount saved by ‘A’ per month
1250x% + 450 × 0.6 + 300 × 0.55 = 2000 × 0.48 = 48000 ÷ 12 = Rs. 4,000
1250x% = 960  165  270 Actual average monthly income of ‘A’
x = 42% = 1,44,000 ÷ 10 = Rs. 14,400
No of females who are Assistant Teachers Amount spent by ‘A’ during the year
42 = 144000 – 48000 = Rs. 96,000
= 1250   525
100 Average monthly expenditure of ‘A’
Out of 525 females, 60% are married = 96000 ÷ 12 = Rs. 8,000
60 Similarly,
= 525   315
100
40 Name Average Actual Average Average
Total no. of married members = 1250   500 monthly average monthly monthly
100
income monthly expenditure saving
Therefore, No. of males who are married
(in Rs.) income (in Rs.) (in Rs.)
= 500 – 315 = 185. (in Rs.)
A 12,000 14,400 8000 4000
26. (a) B 16,000 24,000 10000 6000
For ‘A’: C 15,000 15,000 9000 6000
Average monthly income = Rs. 12,000 D 20,000 24,000 15000 5000
Amount earned by ‘A’ during the year We can see in the given table that ‘B’ and ‘D’
= 12000 × 12 = Rs. 1,44,000 have the highest monthly income i.e. Rs. 24,000.
Average amount saved by ‘A’ per month
= 48000 ÷ 12 = Rs. 4,000 28. (d)
Actual average monthly income of ‘A’ For ‘A’:
= 1,44,000 ÷ 10 = Rs. 14,400 Average monthly income = Rs. 12,000
Amount spent by ‘A’ during the year Amount earned by ‘A’ during the year
 MBA Wallah

= 12000 × 12 = Rs. 1,44,000 (in Rs.) income (in Rs.) (in Rs.)
Average amount saved by ‘A’ per month (in Rs.)
= 48000 ÷ 12 = Rs. 4,000 A 12,000 14,400 8000 4000
Actual average monthly income of ‘A’ B 16,000 24,000 10000 6000
= 1,44,000 ÷ 10 = Rs. 14,400 C 15,000 15,000 9000 6000
D 20,000 24,000 15000 5000
Amount spent by ‘A’ during the year
= 144000 – 48000 = Rs. 96,000 Let the number of months for which ‘B’ worked at
Average monthly expenditure of ‘A’ ‘X’ be ‘m’
= 96000 ÷ 12 = Rs. 8,000 So, number of months for which ‘B’ worked at
Similarly, ‘Y’ = ‘8 – m’
Name Average Actual Average Average {m × (30000) + (8 – m) × 18000} ÷ 8 = 24000
monthly average monthly monthly Or, 30000m + 144000 – 18000m = 192000
income monthly expenditure saving Or, 12000m = 48000
(in Rs.) income (in Rs.) (in Rs.) So, m = 4
(in Rs.) Therefore, ‘B’ worked at ‘X’ for 4 months.
A 12,000 14,400 8000 4000
B 16,000 24,000 10000 6000 30. (d)
C 15,000 15,000 9000 6000 For ‘A’:
D 20,000 24,000 15000 5000 Average monthly income = Rs. 12,000
Amount earned by ‘A’ in first 6 months Amount earned by ‘A’ during the year
= 6 × 14,400 = Rs. 86,400 = 12000 × 12 = Rs. 1,44,000
Amount earned by ‘D’ in first 6 months Average amount saved by ‘A’ per month
= 6 × 24000 = Rs. 1,44,000 = 48000 ÷ 12 = Rs. 4,000
Required difference = 144000 – 86400 Actual average monthly income of ‘A’
= Rs. 57,600 = 1,44,000 ÷ 10 = Rs. 14,400
Amount spent by ‘A’ during the year
29. (b) = 144000 – 48000 = Rs. 96,000
For ‘A’: Average monthly expenditure of ‘A’
Average monthly income = Rs. 12,000 = 96000 ÷ 12 = Rs. 8,000
Amount earned by ‘A’ during the year Similarly,
= 12000 × 12 = Rs. 1,44,000 Name Average Actual Average Average
Average amount saved by ‘A’ per month monthly average monthly monthly
= 48000 ÷ 12 = Rs. 4,000 income monthly expenditure saving
Actual average monthly income of ‘A’ (in Rs.) income (in Rs.) (in Rs.)
= 1,44,000 ÷ 10 = Rs. 14,400 (in Rs.)
Amount spent by ‘A’ during the year A 12,000 14,400 8000 4000
= 144000 – 48000 = Rs. 96,000 B 16,000 24,000 10000 6000
Average monthly expenditure of ‘A’ C 15,000 15,000 9000 6000
D 20,000 24,000 15000 5000
= 96000 ÷ 12 = Rs. 8,000
Similarly,
6000  5000
Name Average Actual Average Average Required mean =  5500
2
monthly average monthly monthly
income monthly expenditure saving

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