jsueJes Yeleea yees[& Éeje DeeÙeesefpele

RRB JE
MECHANICAL AND
ALLIED ENGINEERING
CBT Stage-II
mee@uJ[ hesheme& SJeb Øewefkeäšme yegkeâ
ØeOeeve mebheeokeâ
Deevebo kegâceej cenepeve
mebheeove SJeb mebkeâueve
hejer#ee efJeMes<e%e meefceefle
keâchÙetšj «eeefHeâkeäme
yeeueke=â<Ce, Ûejve efmebn
mebheeokeâerÙe keâeÙee&ueÙe
12, ÛeÛe& uesve, ØeÙeeiejepe-211002
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ØekeâeMekeâ Éeje hetCe& meeJeOeeveer yejleer ieF& nw
efHeâj Yeer efkeâmeer $egefš kesâ efueS Deehekeâe
menÙeesie SJeb megPeeJe meeoj Dehesef#ele nw~
efkeâmeer Yeer efJeJeeo keâer efmLeefle ceW
vÙeeefÙekeâ #es$e ØeÙeeiejepe nesiee~

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 efJe<eÙe-metÛeer
mee@uJ[ hesheme&
jsueJes Yeleea yees[& (RRB) DeJej DeefYeÙevlee cewkesâefvekeâue hejer#ee, 2019 CBT
II Stage
JÙeeKÙee meefnle nue ØeMve-he$e (hejer#ee efleefLe :
31.08.2019) ............................................................ 5-30
jsueJes Yeleea yees[& (RRB) DeJej DeefYeÙevlee cewkesâefvekeâue hejer#ee, 2019 CBT
II Stage
JÙeeKÙee meefnle nue ØeMve-he$e (hejer#ee efleefLe :
30.08.2019) .......................................................... 31-55
jsueJes Yeleea yees[& (RRB) DeJej DeefYeÙevlee cewkesâefvekeâue hejer#ee, 2019 CBT
II Stage
JÙeeKÙee meefnle nue ØeMve-he$e (hejer#ee efleefLe :
29.08.2019) .......................................................... 56-81
Øewefkeäšme mesš
RRB JE Øewefkeäšme mesš-1
----------------------------------------------------------------- 82-93
RRB JE Øewefkeäšme mesš-1 keâe JÙeeKÙee meefnle nue
------------------------------------------- 94-106

RRB JE Øewefkeäšme mesš-2

-------------------------------------------------------------- 107-118
RRB JE Øewefkeäšme mesš-2 keâe JÙeeKÙee meefnle nue
----------------------------------------- 119-131

RRB JE Øewefkeäšme mesš-3

-------------------------------------------------------------- 132-143
RRB JE Øewefkeäšme mesš-3 keâe JÙeeKÙee meefnle nue
----------------------------------------- 144-157

RRB JE Øewefkeäšme mesš-4

-------------------------------------------------------------- 158-169
RRB JE Øewefkeäšme mesš-4 keâe JÙeeKÙee meefnle nue
----------------------------------------- 170-182

RRB JE Øewefkeäšme mesš-5

-------------------------------------------------------------- 183-193
RRB JE Øewefkeäšme mesš-5 keâe JÙeeKÙee meefnle nue
----------------------------------------- 194-207

RRB JE Øewefkeäšme mesš-6

-------------------------------------------------------------- 208-219
RRB JE Øewefkeäšme mesš-6 keâe JÙeeKÙee meefnle nue
----------------------------------------- 220-232

RRB JE Øewefkeäšme mesš-7

-------------------------------------------------------------- 233-244
RRB JE Øewefkeäšme mesš-7 keâe JÙeeKÙee meefnle nue
----------------------------------------- 245-258

RRB JE Øewefkeäšme mesš-8

-------------------------------------------------------------- 259-270
RRB JE Øewefkeäšme mesš-8 keâe JÙeeKÙee meefnle nue
----------------------------------------- 271-283

RRB JE Øewefkeäšme mesš-9

-------------------------------------------------------------- 284-295
RRB JE Øewefkeäšme mesš-9 keâe JÙeeKÙee meefnle nue
----------------------------------------- 296-310
RRB JE Øewefkeäšme mesš-10
------------------------------------------------------------ 311-323
RRB JE Øewefkeäšme mesš-10 keâe JÙeeKÙee meefnle nue
--------------------------------------- 324-336
2
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 SYLLABUS
Government of India, Ministry of Railways,
Railway Recruitment Boards
CENTRALISED EMPLOYMENT NOTICE (CEN) No.03/2018
Recruitment of Junior Engineer (JE), Junior Engineer (Information Technology)
[JE(IT)],
Depot Material Superintendent (DMS)

2nd Stage CBT : Short listing of Candidates for the 2nd Stage CBT exam shall be
based on the normalized marks
obtained by them in the 1st Stage CBT Exam. Total number of candidates to be
shortlisted for 2nd Stage shall be 15
times the community wise total vacancy of Posts notified against the RRB as per
their merit in 1st Stage CBT.
However, Railways reserve the right to increase/decrease this limit in total or for
any specific category(s) as required
to ensure availability of adequate candidates for all the notified posts.
Duration : 120 minutes (160 Minutes for eligible PwBD candidates
accompanied with Scribe)
No of Questions : 150
Syllabus : The Questions will be of objective type with multiple choices and are
likely to include questions
pertaining to General Awareness, Physics and Chemistry, Basics of Computers and
Applications, Basics of
Environment and Pollution Control and Technical abilities for the post. The
syllabus for General Awareness,
Physics and Chemistry, Basics of Computers and Applications, Basics of Environment
and Pollution Control is
common for all notified posts under this CEN as detailed below:-
a) General Awareness : Knowledge of Current affairs, Indian geography, culture and
history of India including
freedom struggle, Indian Polity and constitution, Indian Economy, Environmental
issues concerning India and
the World, Sports, General scientific and technological developments etc.
b) Physics and Chemistry: Up to 10th standard CBSE syllabus.
c) Basics of Computers and Applications: Architecture of Computers; input and
Output devices; Storage devices,
Networking, Operating System like Windows, Unix, Linux; MS Office; Various data
representation; Internet and
Email; Websites & Web Browsers; Computer Virus.
d) Basics of Environment and Pollution Control: Basics of Environment; Adverse
effect of environmental
pollution and control strategies; Air, water and Noise pollution, their effect
and control; Waste Management,
Global warming; Acid rain; Ozone depletion.
e) Technical Abilities: The educational qualifications mentioned against each post
shown in Annexure-A, have
been grouped into different exam groups as below. Questions on the Technical
abilities will be framed in the
syllabus defined for various Exam Groups given at Annexure-VII-A, B, C, D, E, F
& G.
The section wise Number of questions and marks are as below :
Subjects No. of Questions
Marks for each Section
Stage-II
Stage-II
General Awareness 15
15
Physics & Chemistry 15
15
Basics of Computers and Applications 10
10
Basics of Environment and Pollution Control 10
10
Technical Abilities 100
100
Total 150
150
Time in Minutes 120
The section wise distribution given in the above table is only indicative and there
may be some variations in the
actual question papers.
Minimum percentage of marks for eligibility in various categories: UR -40%, OBC-
30%, SC-30%, ST -25%. This
percentage of marks for eligibility may be relaxed by 2% for PwBD candidates, in
case of shortage of PwBD
candidates against vacancies reserved for them.
Virtual calculator will be made available on the Computer Monitor during 2nd Stage
CBT.
3

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 2nd Stage Syllabus for Mechanical & Allied Engineering Exam Group – JE
1. Engineering Mechanics : Resolution of forces, Equilibrium and Equilibrant,
parallelogram law of forces,
triangle law of forces, polygon law of forces and Lami’s theorem, couple and
moment of a couple, condition for
equilibrium of rigid body subjected to number of coplanar non-concurrent
forces, definition of static friction,
dynamic friction, derivation of limiting angle of friction and angle of repose,
resolution of forces considering
friction when a body moves on horizontal plane and inclined plane, calculation
of moment of inertia and radius
of gyration of : (a) I-Section (b) channel section (c) T-Section (d) L-Section
(Equal & unequal lengths) (e) Z-
Section (f) Built up sections (simple cases only), Newton’s laws of motion
(without derivation), motion of
projectile, D’Alembert’s principle, definition law of conservation of energy,
law of conservation of momentum.
2. Material Science : Mechanical properties of engineering materials – tensile
strength, compressive strength,
ductility, malleability, hardness, toughness, brittleness, impact strength,
fatigue, creep resistance. Classification
of steels, mild steel and alloy steels. Importance of heat treatment. Heat
treatment processes – annealing,
normalizing, hardening, tempering, carburizing, nitriding and cyaniding.
3. Strength of Materials : Stress, strain, stress strain diagram, factor of safety,
thermal stresses, strain energy,
proof resilience and modules of resilience. Shear force and bending moment
diagram – cant leaver beam,
simply supported beam, continuous beam, fixed beam. Torsion in shafts and
springs, thin cylinder shells.
4. Machining : Working principle of lathe. Types of lathes – Engine lathe –
construction details and
specifications. Nomenclature of single point cutting tool, geometry, tool
signature, functions of tool angles.
General and special operations – (Turning, facing, taper turning thread
cutting, knurling, forming, drilling,
boring, reaming, key way cutting), cutting fluids, coolants and lubricants.
Introduction to shaper, slotter, plainer,
broaching, milling and manufacture of gears, heat treatment process applied to
gears.
5. Welding : Welding – Introduction, classification of welding processes,
advantages and limitations of welding,
principles of arc welding, arc welding equipment, choice of electrodes for
different metals, principle of gas
(oxy-acetylene) welding, equipment of gas welding, welding procedures (arc &
gas), soldering and brazing
techniques, types and applications of solders and fluxes, various flame cutting
processes, advantages and
limitations of flame cutting, defects in welding, testing and inspection modern
welding methods, (submerged,
CO2, atomic – hydrogen, ultrasonic welding), brief description of MIG & TIG
welding.
6. Grinding & Finishing Process : Principles of metal removal by grinding,
abrasives, natural and artificial,
bonds and binding processes, vitrified, silicate, shellac rubber, grinding
machines, classification: cylindrical,
surface, tool & cutter grinding machine, construction details, relative merits,
principles of centreless grinding,
advantages & limitations of centreless grinding work, holding devices, wheel
maintenance, balancing of wheels,
coolants used, finishing by grinding, honing, lapping, super finishing,
electroplating, basic principles – plating
metals, applications, hot dipping, galvanizing tin coating, parkerising,
anodizing, metal spraying, wire process,
powder process and applications, organic coatings, oil base paint, lacquer base
enamels, bituminous paints,
rubber base coating.
7. Metrology : Linear measurement – Slip gauges and dial indicators, angle
measurements, bevel protractor, sine
bar, angle slip gauges, comparators (a) mechanical (b) electrical (c) optical
(d) pneumatic. Measurement of
surface roughness; methods of measurements by comparison, tracer instruments
and by interferometry,
collimators, measuring microscope, interferometer, inspection of machine parts
using the concepts of shadow
projection and profile projection.
8. Fluid Mechanics & Hydraulic Machinery : Properties of fluid, density, specific
weight, specific gravity,
viscosity, surface tension, compressibility capillarity, Pascal’s law,
measurement of pressures, concept of
buoyancy. Concept of Reynold’s number, pressure, potential and kinetic energy
of liquids, total energy, laws of
conservation, mass, energy and momentum, velocity of liquids and discharge,
Bernoulli’s equation and
assumptions, venturimeters, pitottube, current meters. Working principle &
constructional details of centrifugal
pump, efficiencies – manometric efficiency, volumetric efficiency, mechanical
efficiency and overall
efficiency, cavitation and its effect, working principle of jet & submersible
pumps with line diagrams.
9. Industrial Management : Job analysis, motivation, different theories,
satisfaction, performance reward
systems, production, planning and control, relation with other departments,
routing, scheduling, dispatching,
PERT and CPM, simple problems. Materials in industry, inventory control model,
ABC Analysis, Safety stock,
re-order, level, economic ordering quantity, break even analysis, stores
layout, stores equipment, stores records,
purchasing procedures, purchase records, Bin card, Cardex, Material handling,
Manual lifting, hoist, cranes,
conveyors, trucks, fork trucks.
10. Thermal Engineering : Laws of thermo dynamics, conversion of heat into work
vice versa , laws of perfect
gases, thermo dynamic processes – isochoric, isobaric, isothermal hyperbolic,
isentropic, polytrophic and
throttling, modes of heat transfer, thermal conductivity, convective heat
transfer coefficient, Stefan Boltzman
law by radiation and overall heat transfer coefficient. Air standards cycles –
Carnot cycle, Otto cycle, Diesel
cycle, construction and working of internal combustion engines, comparison of
diesel engine and petrol engine.
Systems of internal combustion engine, performance of internal combustion
engines. Air compressors their
cycles refrigeration cycles, principle of a refrigeration plant.
4

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 Railway Recruitment Board
JE Mechanical
[IIst Stage Computer Based Test]
Exam Date : 31.08.2019

1. If 'αα' is angle of projection and 'u' is velocity of

Ans : (b)
projection for a projectile, then its horizontal
End Condition Relation between
range is given by:
equivalent length and
Ùeefo 'α
α' Øe#esheCe keâe keâesCe (angle of projection) nw
actual length
Deewj 'u' Øe#eshÙe kesâ efueS Øe#esheCe (projection for a
Both end hinged Le = l
projectile) keâe Jesie nw, lees Fmekeâer #eweflepe meercee
One end fixed and the Le = 2l
(horizontal range) ............ Éeje oer peeleer nw–
other free
(a) R = (u2 sin2α)/g
Both ends fixed Le = l/2
(b) R = (u2 sinα) / g
One end fixed and other l

hinged Le =
(c) R = (u2 cos2α)/g
2
(d) R = (u2cosα)/g
3. The horizontal component of tensile force in a
Ans : (a)
wire that makes 60o with horizontal and is
Ùeefo α = Øe#esheCe keâesCe
carrying a force of 20 kN is-
u = Øe#esheCe keâe Jesie

Gme leej keâe #eweflepe Ieškeâ %eele keâerefpeS, pees #eweflepe mes

60o keâe keâesCe yeveelee nes Deewj Gme hej 20 kN keâe yeue

ueielee nes–

(a) 30 kN (b) 18 kN

(c) 10 kN (d) 25 kN

Ans : (c)

(i) #eweflepe hejeme (Horizontal range)

u 2 sin 2α

yeue keâe #eweflepe Ieškeâ = 20 cos 60o = 10 kN

R=
yeue keâe TOJee&Oej Ieškeâ = 20 sin 60o = 10 3kN
g
(ii) GñÙeve keâeue (Time of flight)
4. Which will form amphoteric oxide?

FveceW mes keâewve mee GYeÙeOeceea Dee@keämeeF[ (amphoteric

2u sin α
T=
oxide) yeveeÙesiee–
g

(a) Zn (b) Ca
(iii) DeefOekeâlece TBÛeeF& (Maximum height)
(c) Na (d) Al
u 2 sin 2 α
Ans : (a/d) Jes Oeeleg Dee@keämeeF[ pees Decue (acid) leLee #eej
H max =
(Base) oesveeW mes DeefYeef›eâÙee keâjkesâ ueJeCe leLee peue yeveeles nQ,
2g

GYeÙeOeceea Dee@keämeeF[ keânueeles nQ~

2. The effective length 'L' of column hinged at
(1) Al2O3 + 6HCl → 2AlC3 + 3H2O
both ends as compared to its actual length 'l' is-
(2) Al2O3 + 2NaOH → 2NaAlO2 + H2O
JeemleefJekeâ uecyeeF& 'L' keâer leguevee ceW oesveeW efmejeW hej
(3) ZnO + 2HCl → ZnCl2 + H2O
keâypesÙegkeäle Skeâ mlebYe keâer ØeYeeJeer uebyeeF& 'l' keäÙee nesleer
(4) ZnO + 2NaOH → NaZnO2 + H2O
nw–
Dele: efoÙes ieÙes efJekeâuhe ceW (a/d) oesveeW mener nesiee~
(a) L = l/2
5. The number '120' in the grinding wheel R D
(b) L=l
120 N 100 M specifies the-
(c) L = 2l2
«eeFbef[bie Jnerue R D 120 N 100 M ceW mebKÙee 120 keäÙee
(d) L = 2l
oMee&leer nw–
RRB JE Mechanical CBT-II 31-Aug-2019 5
YCT

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 (a) Concentration number/meebõCe Debkeâ
(d) Because the particles in water radiate heat
(b) Average grain size/«esve keâe Deewmele Deekeâej
energy during the process of conversionn
(c) Hardness of grinding wheel
from ice to liquid water/keäÙeeWefkeâ peue ceW ceewpeto
«eeFbef[bie Jnerue keâer keâ"esjlee
keâCe, yehe&â mes lejue peue ceW ™heeblejCe keâer Øeef›eâÙee kesâ
(d) Abrasive strength/DeheIe<e&Ce meeceLÙe&
oewjeve T<ceerÙe Tpee& keâe efJeefkeâjCe keâjles nQ~
Ans : (b) «eeFef[bie Jnerue ceW 120 «esve (Grain) keâe Deewmele Deekeâej Ans : (a)
oMee&leer nw~
«eeFef[bie heefnS keâer efJeefMeef°ÙeeB (Designation of grinding
wheel)–

1. DeheIe<eea keâe Øekeâej (Types of abrasive)

2. «esve meeFpe (Grain size)
3. keâ"esjlee (Hardness) DeLeJee «es[ (Grade)
Lf = 80 calorie
4. mebjÛevee (Structure)
efveÙele leehe T = C hej
5. yevOe kesâ Øekeâej (Type of bond)

Q 2 > Q1
6. Which of the following is an example of flow
production?
Ûetbefkeâ 0oC kesâ yehe&â mes 0oC kesâ heeveer yeveves ceW ieghle T<cee (Latent
FveceW mes keâewve mee ØeJeen Glheeove keâe Skeâ GoenjCe nw–
heat) DeJeMeesef<ele nesleer nw~ Dele: 0oC kesâ heeveer kesâ keâCe keâer Tpee&
(a) Bridge and dam construction
0oC kesâ yehe&â kesâ keâCe keâer Tpee& mes DeefOekeâ nesleer nw~
hegue SJeb yeebOe efvecee&Ce
8. Sigma comparator is a type of ................
(b) Gas and oil/iewme Deewj lesue
comparator :
(c) Textiles/šskeämešeFume
efmeicee keâchewjsšj Skeâ Øekeâej keâe ................ keâchewjsšj nw~
(d) Paint shop/heWš Mee@he
(a) Optical/ØekeâeefMekeâ
Ans. (b) : iewme Deewj lesue keâe Glheeove, ØeJeen Glheeove keâe Skeâ
(b) Electrical/Fuesefkeäš^keâue
GoenjCe nw~
(c) Mechanical/Ùeebef$ekeâ
ØeJeen Glheeove (Flow production)–ØeJeen Glheeove cee@me
(d) Electronic/Fueskeäš^e@efvekeâ
Øees[keäMeve keâe Skeâ Øekeâej nw~ Ùen yenves Jeeueer JemlegDeeW kesâ Glheeove mes

Ans : (c) efmeicee keâchewjsšj Skeâ Øekeâej keâe Ùeebef$ekeâ keâchewjsšj nw~
mecyeefvOele nw~ pewmes–efjheâeFvejer, jemeeÙeefvekeâ hueebš, ogiOe [sjer hueebš
Deeefo~
7. Why do particles in liquid water at 0oC have
more energy as compared to particles in ice at
the same temperature?
0oC hej lejue peue ceW ceewpeto keâCeeW keâer Tpee& meceeve leehe
hej yehe&â ceW ceewpeto keâCeeW keâer leguevee ceW DeefOekeâ keäÙeeW
nesleer nw–
(a) Because the particles in ice absorb heat
Fmekesâ Deefleefjòeâ kegâÚ DevÙe Øekeâej kesâ legueefve$e (comparator) Yeer
 energy during the process of conversion from
nesles nQ, efpeveceW Øe#esheCe legueefve$e, mJeÛeeefuele iesefpebie ceMeerveW,
met#ceoMeea
ice to liquid water/keäÙeeWefkeâ yehe&â ceW ceewpeto keâCe, yehe&â

Deeefo ØecegKe nQ~

mes lejue peue ceW ™heeblejCe keâer Øeef›eâÙee kesâ oewjeve T<ceerÙe
Tpee& DeJeMeesef<ele keâjles nQ~
9. A hollow steel column has to carry an axial

load of 2,00,000 kg and the ultimate stress for

(b) Because the particles in water absorb heat

the steel column is 4800 kg/cm2 and allows a

energy during the process of conversion from

load factor of 4. What is the sectional area of

ice to liquid water/keäÙeeWefkeâ peue ceW ceewpeto keâCe, yehe&â

the column?
mes lejue peue ceW ™heeblejCe keâer Øeef›eâÙee kesâ oewjeve T<ceerÙe

Skeâ KeesKeues mšerue mlecYe keâes 2,00,000 efkeâ«ee keâe

Tpee& DeJeMeesef<ele keâjles nQ~
(c) Because the particles in water absorb heat

De#eerÙe Yeej Jenve keâjvee nw Deewj mšerue mlecYe keâe Ûejce

energy during the process of conversion from
Øeefleyeue 4800 efkeâ«ee/mesceer2 Deewj DevegcevÙe uees[ hewâkeäšj
ice to water vapour/keäÙeeWefkeâ peue ceW ceewpeto keâCe,
4 nw~ mlecYe keâer keâeš keâe #es$eheâue %eele keâerefpeS~
yehe&â mes peue Jee<he ceW ™heeblejCe keâer Øeef›eâÙee kesâ oewjeve
(a) 180.66 cm2 (b) 166.66 cm2
T<ceerÙe Tpee& DeJeMeesef<ele keâjles nQ~
(c) 196.66 cm2 (d) 176.66 cm2
RRB JE Mechanical CBT-II 31-Aug-2019
6
YCT

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Ans : (b) efoÙee nw–
Ans : (a)
De#eerÙe Yeej (w) = 200000 kg
VSD = Jeefve&Ùej mkesâue efJeYeepeve
Ûejce Øeefleyeue (σu) = 4800 kg/cm2
MSD = cesve mkesâue efJeYeepeve

1 MSD = 0.1 mm
Ûejce Øeefleyeue σ
megj#ee iegCeebkeâ · = u
efoÙee nw–
keâeÙe&keâejer Øeefleyeue  w 
A
10 VSD = 9 MSD
 
1 VSD = 0.9 MSD
4800
JeveeaÙej kewâueerhej keâe Deuheleceebkeâ (L.C.) = 1MSD – 1 VSD
4=
 200000 
Deuheleceebkeâ (L.C.) = 1 MSD – 0.9 MSD
 A 
 
L.C. = 0.1 MSD
A = 166.66 cm2
ØeMveevegmeej,
10. Which of the following is equal to a pressure of
1 MSD = 0.1 mm
25 m head of water?
L.C. = 0.1 × 0.1
(Take g = 9.8 m/s2)

L.C. = 0.01mm
efvecveefueefKele ceW mes keâewve, heeveer kesâ 25 ceeršj ns[ kesâ
oyeeJe kesâ yejeyej nw?
13. ............. is used to move the carriage
(peneB g = 9.8 m/s ) 2
automatically during threading.

................. keâe GheÙeesie LeÇsef[bie kesâ oewjeve kewâefjpe keâes

(a) 2.5 kN/m2 (b) 245 kN/m2
(c) 2500 kN/m 2
(d) 25 kN/m 2
mJeÛeeef uele ™he mes Ûeueeves kesâ efueS efkeâÙee peelee nw~
Ans : (b) efoÙee nw–
(a) Lead screw/ueer[ m›etâ
h = 25 m (Meer<e&)
(b) Head wheel/nwC[ Jnerue
g = 9.8 m/s2
(c) Bed/yes[
ρ = 1000 kg/m 3
(d) Feed rod/heâer[ je@[
P = ρgh Ans : (a)
ueer[ m›etâ keâe GheÙeesie LeÇsef[bie kesâ oewjeve kewâefjpe keâes
P = 1000 × 9.8 × 25 N/m2
mJeÛeeefuele ™he mes Ûeueeves kesâ efueS efkeâÙee peelee nw~
P = 245kN / m 2
ueer[ m›etâ efveefkeâue mšerue keâer Skeâ uecyeer Meeheäš nesleer nw efpeme hej
Skeäces ÛetefÌ[Ùeeb keâšer nesleer nQ~ Fmes SØeve kesâ yeerÛe mes iegpeeje peelee
11. Which of the following elements has maximum
atomic radius?

nw~
efvecveefueefKele ceW mes efkeâme lelJe ceW DeefOekeâlece hejceeCeg
Fmekeâe GheÙeesie efYeVe–efYeVe efheÛe keâer ÛetefÌ[Ùee keâešves kesâ efueS
ef$epÙee nw?
efkeâÙee peelee nw~
(a) S (b) Cl
keâF& yeej ueer[ m›etâ keâer hetjer uecyeeF& ceW key–way keâšer nesleer nQ
(c) P (d) Na
pees heâer[ je[ keâe keâeÙe& keâjleer nw~
Ans : (d) peye oes hejceeCegDeeW ceW mebÙeespeer Fueskeäš^e@veeW kesâ
efueÙes n keâe 14. Which of the following is the input
ceeve meceeve nesles nQ, lees DeefOekeâ mebKÙee ceW Øeesše@ve Jeeues hejceeCeg ceW
component(s) to Materials Requirement

Planning (MRP) system?

mebÙeespeer Fueskeäš^e@veeW keâes veeefYekeâ kesâ keâjerye KeeRÛeves kesâ efueÙes
DeefOekeâ efvecveefueefKele ceW mes keâewve–mee meece«eer
DeeJeMÙekeâlee
ØeYeeJeer hejceeCeg DeeJesMe nesiee leLee Fme Øekeâej hejceeCeg ef$epÙee keâce nes

Ùeespevee (MRP) ØeCeeueer keâe Fvehegš Ieškeâ nw?

peeÙesieer~

(a) Master Production Schedule

hejceeCeg ef$epÙee keâe Iešlee ›eâce – Na > P > S > Cl

cegKÙe Glheeove keâeÙe&›eâce

12. In a vernier calliper, the main scale reads in

(b) Inventory status file/FvJeWš^er efmLeefle heâeFue

millimeters with a least count of 0.1 mm. Ten
divisions on the vernier correspond to nine
(c) All of the options/efJekeâuheeW ceW mes meYeer
divisions of the mains scale. Determine the least
(d) Bill of materials/meece«eer kesâ efyeue
count of the calliper.
Ans :
(c) DeewÅeesefiekeâ FbpeerefveÙeeEjie ceW MRP Ùee MRP I keâe hetCe&
Skeâ Jeefve&Ùej kewâefuehej ceW, cegKÙe hewceeves hej 0.1
™he
Materials Requirement Planning (meece«eer DeeJeMÙekeâlee
efceueerceeršj kesâ Deuheleceebkeâ kesâ meeLe efceueerceeršj ceW

Ùeespevee) neslee nw~

hee"dÙeebkeâ efueS pee mekeâles nQ~ Jeefve&Ùej hej ceewpeto ome

meece«eer DeeJeMÙekeâlee Ùeespevee ØeCeeueer keâe Fvehegš Ieškeâ efvecve nw–

efJeYeepeve, cegKÙe hewceeves kesâ veew efJeYeepeveeW kesâ mebiele nQ~

1. cegKÙe Glheeove keâeÙe&›eâce

kewâefuehej keâe Deuheleceebkeâ %eele keâerefpeS~

2. FvJeWš^er efmLeefle heâeFue

(a) 0.01 mm/efceceer (b) 0.001 mm/efceceer
3. meece«eer kesâ efyeue
(c) 0.1 mm/efceceer (d) 1 mm/efceceer
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15. Which of the following diagrams look like a
(a) Impact failure/Fchewkeäš hesâuÙeesj
fish bone?
(b) Creep/›eâerhe
efvecveefueefKele ceW mes keâewve mee DeejsKe ceÚueer keâer nñer keâer
(c) Fatigue/heâšerie
lejn efoKelee nw?
(d) Embrittlement/SefcyeÇšueceWš
(a) Run chart/jve Ûeeš&

Ans : (c) Ûe›eâerÙe uees[ kesâ keâejCe meece«eer efJeheâuelee heâšerie keânueeleer
(b) Histogram/efnmšes«eece
nw~ Gleej–ÛeÌ{eJe Jeeues leLee efJehejerle yeej–yeej MeerIeÇ ØeefleyeueeW kesâ
(c) Cause and effect diagram
GlheVe nesves kesâ keâejCe Oeeleg KeC[eW kesâ DeÛeevekeâ štš peeves keâe Yeüce
keâejCe SJeb ØeYeeJe DeejsKe
yevee jnlee nw~ leYeer Fme Øekeâej ØeefleyeueeW mes Oeeleg KeC[ štš peeles nQ~
(d) Pareto chart/hewjsšes Ûeeš&
GÛÛe ieefle hej Ietceles Fmheele kesâ MeeheäšeW leLee mebjÛeveeDeeW kesâ Gve ÂÌ{
Ans : (c) efheâMe yeesve DeejsKe Ùee FMeerkeâeJee DeejsKe Skeâ keâejCe Deewj
meomÙeeW ceW Ùen oes<e neslee nw pees keâcheVe mes ØeYeeefJele nesles nQ~
ØeYeeJe DeejsKe (cause and effect diagram)nw, pees ØeyebOekeâeW keâes heâšerie kesâ
keâejCe cewšerefjÙeue hej efvecve ØeYeeJe nesles nQ–
KeeefceÙeeW, efJeefJeOeleeDeeW, oes<eeW Ùee efJeheâueleeDeeW kesâ keâejCeeW keâes
š^wkeâ (i) levÙelee ceW keâceer
keâjves ceW ceoo keâjlee nw~ Ùen DeejsKe "erkeâ Gmeer lejn efoKelee nw pewmes (ii)
meeceLÙe& ceW keâceer
ceÚueer kesâ kebâkeâeue keâer n[d[er~ Fmekesâ efmej ceW mecemÙee keâes Deewj
jerÌ{ ceW (iii) heoeLe& keâer meeceLÙe& leLee ef›eâÙeeMeerue peerJeve keâer
DeefveefMÛelelee
heâeref[bie keâer mecemÙee kesâ keâejkeâ keâes efoKeeÙee peelee nw~
20. Limiting force of friction is the–
16. In MS-Word, what is the maximum font size
meerceeble Ie<e&Ce yeue keäÙee nw?
you can apply for any character?
(a) Tangent of angle between normal reaction
MS–Je[& ceW, DeefOekeâlece heâe@vš Deekeâej keäÙee nw efpemes
and resultant of normal reaction and limiting
Deehe efkeâmeer Yeer JeCe& kesâ efueS ueeiet keâj mekeâles nQ?
friction/‘DeefYeuebyeJele Øeefleef›eâÙee’ Deewj ‘DeefYeuebyeJele
(a) 163 (b) 16038
Øeefleef›eâÙee’ Deewj ‘meerceeble Ie<e&Ce kesâ heefjCeeceer’ kesâ yeerÛe kesâ
(c) 1670 (d) 1638
keâesCe keâer mheMe&pÙee
Ans : (d) [^e@he[eGve metÛeer ceW ceeF›eâesmee@heäš Jeu[& (MS-Word)
(b) Ratio of limiting friction and normal reaction
2010 ceW GheueyOe DeefOekeâlece heâe@vš- Deekeâej 72 nw, uesefkeâve heâe@vš
meerceeble Ie<e&Ce Deewj DeefYeuebyeJele Øeefleef›eâÙee keâe Devegheele
keâe Deekeâej heâe@vš kesâ efueÙes cewvÙegDeue ™he mes šeFhe keâjkesâ 1638 lekeâ
(c) Friction force acting when the body is just
mesš efkeâÙee pee mekeâlee nw~
about to move/peye efheb[ yeme Ûeueves ner Jeeuee nes,
17. A Meander drive is a ................ shaft
Gme efmLeefle hej ueieves Jeeuee Ie<e&Ce yeue
mechanism.
(d) Friction force acting when the body is in
Skeâ cesv[j [^eFJe Skeâ ........... Meeheäš ØeCeeueer nw~
motion/ieefleceeve DeJemLee ceW efheC[ hej ueieves Jeeuee
(a) Four/Ûeej (b) One/Skeâ
Ie<e&Ce yeue
(c) Two/oes (d) Three/leerve
Ans : (c) peye efheC[ yeme Ûeueves ner Jeeuee nes, Gme efmLeefle ceW Gme
Ans : (d) cesv[j [^eFJe ceW leerve Mee@Heäš ØeCeeueer nesleer nw~
hej ueieves Jeeuee Ie<e&Ce yeue meerceevle Ie<e&Ce yeue neslee nw~
18. Which of the following is the most common

Ûejce Ùee meerceevle Ie<e&Ce (Limiting Friction)– oes efheC[eW kesâ

substrate material for hot-dip metallic coating? mecheke&â leue hej Jen
DeefOekeâlece Ie<e&Ce, peye Gve efheC[eW ceW meehes#e ieefle
ne@š–ef[he Oeeleg uesheve kesâ efueS ØeÙegòeâ meJee&efOekeâ Deece nesves
ner Jeeueer nesleer nw, Ûejce Ùee meerceevle Ie<e&Ce (limiting
meymeš^sš heoeLe& FveceW mes keâewve mee nw?
friction) keânueelee nw~
(a) Aluminium/SuÙetceerefveÙece
21. The ratio of oxygen to acetylene in the neutral

flame is–
(b) Steel/Fmheele

Goemeerve ueew ceW Dee@keämeerpeve Deewj Sefmeefšueerve keâe

(c) Zinc/efpebkeâ

Devegheele ................ neslee nw~

(d) Terene/šsjerve

(a) 2 : 1 (b) 1 : 1
Ans : (c) ne@š–ef[he Oeeleg uesheve kesâ efueS meJee&efOekeâ Deece

(c) 3 : 1 (d) 1 : 3
(common) meymeš^sš heoeLe& efpebkeâ (Zinc) nw~ ne@š–ef[he uesheve
Øeef›eâÙee DeeOeej OeelegDeeW hej meb#eejCe ØeeflejesOeer OeelegDeeW keâe ueshe
ÛeÌ{eves Ans : (b) Goemeerve ueew (Neutral flame) ceW Deekeämeerpeve Deewj
keâer Skeâ õgle Je memleer efJeefOe nw, efpemekeâe efJemle=le GheÙeesie ueesns
leLee Sefmeefšueerve keâe Devegheele 1 : 1 neslee nw~
mšerue hej pemles keâer hejle ÛeÌ{eves kesâ efueS efkeâÙee peelee nw~ pemles kesâ
DeueeJee efšve, meermee leLee SuÙegefceefveÙece keâer hejleW Yeer DeeOeej
OeelegDeeW
hej Fmeer neš–ef[he uesheve efJeefOe Éeje ÛeÌ{eÙeer peeleer nw~
19. The failure of the material due to cyclic loads is
known as–
Ûe›eâerÙe uees[ kesâ keâejCe meece«eer efJeheâuelee ...............
keânueeleer nw~
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22. Which two words appeared on the first postage 25.
Which of the following processes is an example
stamp of independent India?
of a reversible process?
mJeleb$e Yeejle kesâ henues [ekeâ efškeâš hej keâewve mes oes Meyo
efvecveefueefKele ceW mes keâewve meer Øeef›eâÙee Gl›eâceCeerÙe Øeef›eâÙee
cegefõle efkeâS ieS?
keâe Skeâ GoenjCe nw?
(a) Vande Matram/Jebos ceelejce
(a) Combustion/onve
(b) Jai Hind/peÙe efnvo
(b) Heat transfer/T<cee DeblejCe
(c) Jai Bharat/peÙe Yeejle
(c) Electrolysis/efJeÅegle DeheIešve
(d) Jai Kisan/peÙe efkeâmeeve

(d) Plastic deformation/DeØelÙeemLe efJe™heCe

Ans : (b) mJeleb$e Yeejle keâe henuee [ekeâ efškeâš 21 veJecyej, 1947

Ans : (c) Gl›eâceCeerÙe Øeef›eâÙee- ØeejefcYekeâ DeJemLee ceW Debeflece DeJemLee

keâes peejer ngDee~ Fmekeâe GheÙeesie kesâJeue osMe kesâ Deboj [ekeâ Yespeves kesâ

lekeâ Ûeueves Jeeueer Skeâ T<ceeieeflekeâ Øeef›eâÙee keâes Gl›eâceCeerÙe keâne

peelee
efueÙes efkeâÙee ieÙee~ Fme hej YeejleerÙe OJepe keâe efÛe$e Deewj peÙe efnbo
Meyo cegefõle Les~
nw, Ùeefo ØeCeeueer Je Fmekeâe JeeÙegceC[ue yeÇÿeeC[ ceW efkeâmeer heefjJele&ve
kesâ

efyevee Deheves ØeejefcYekeâ DeJemLee ceW Jeeheme Dee peelee nw- GoenjCe –
23. Which carburising method has high
production rate?
efJeÅegle DeheIešve, Ie<e&Cenerve oesueve~
efkeâme keâeyÙet&jeefpebie efJeefOe keâer Glheeove oj GÛÛe nesleer nw?
26. For which surface, is a spirit level used for
(a) Solid powder carburising
testing straightness?
mee@efue[ heeG[j keâeyeg&jeF&efpebie
efkeâve meleneW kesâ $e+peglee hejer#eCe kesâ efueS efmheefjš uesJeue
(b) Liquid carburising/lejue keâeyÙet&jeFefpebie
keâe GheÙeesie efkeâÙee peelee nw?
(c) Pack carburising/hewkeâ keâeyÙet&jeFefpebie
(a) Inclined surfaces/Deevele melen
(d) Gas carburising/iewme keâeyÙet&jeFefpebie
(b) Horizontal surfaces/#eweflepe melen
Ans : (d) iewme keâeyÙet&jeFefpebie keâer Glheeove oj GÛÛe nesleer nw~
(c) Both horizontal and vertical surfaces
iewme keâeyÙet&jeFefpebie (Gas Carburising)– Fme efJeefOe ceW efvecve
#eweflepe Deewj TOJee&Oej melen oesveeW
keâeye&ve kesâ Oeeleg Keb[eW keâes Yeªer ceW jKee peelee nw leLee Yeªer ceW
(d) Vertical surfaces/TOJee&Oej melen
keâeye&veÙegòeâ iewmes (ceerLesve, Øeeshesve, yÙetšsve) keâe heefjmebÛejCe efkeâÙee
peelee Ans : (c) #eweflepe meleneW keâer $e+peglee (Straightness) hejer#eCe
kesâ
nw~ Yeªer ceW iewmeeW keâe ueieeleej heefjmebÛejCe yeveeS jKevee DeeJeMÙekeâ
efueS efmheefjš uesJeue keâe GheÙeesie efkeâÙee peelee nw~ efmheefjš uesJeue ceW
oes
neslee nw leLee ØeÙeesie ceW DeeF& iewmeeW keâe yeenj efvekeâeuevee Yeer
DeeJeMÙekeâ Ùee leerve veeefueÙeeB nesleer nQ, pees lejue heoeLe& mes
Yeejer nesleer nw pewmes efkeâ
neslee nw~ Fme iewme keâeye&gjerkeâjCe ceMeerve keâer keâercele DeefOekeâ nesleer
nw SsLesvee@ue~ ieg™lJeekeâ<e&Ce keâer efJehejerle efoMee ceW nJee kesâ
yeerÛe ceW Skeâ
Dele: Øeesmesme DeeefLe&keâ ™he mes GheÙegòeâ leYeer nesleer nw peye DeefOekeâ
cee$ee yegueyeguee neslee nw~ #eweflepe meceleue melen leye lekeâ Øeehle
veneR neslee nw
ceW heešdme& keâe keâeyegjeakeâjCe efkeâÙee peeS~
peye lekeâ efkeâ nJee keâe yegueyeguee kesâvõ ceW efmLele ve nes~
24. The square root of the ratio of the inertia force
27.
The lower critical point for all steels is–
due to flow to the elastic force of fluid is known
as–
meYeer Øekeâej kesâ Fmheele kesâ efueS efvecve ›eâebeflekeâ efyevog
ØeJeen keâer Jenpe mes GlheVe peÌ[lJe yeue Deewj õJe kesâ
............. neslee nw~
ØelÙeemLe yeue kesâ Devegheele kesâ Jeie&cetue keâes keäÙee keâne
(a) 600oC (b) 723oC
peelee nw?
(c) 800oC (d) 913oC
(a) Strouhal number/mše@nue mebKÙee
Ans : (b) meYeer Øekeâej kesâ Fmheele kesâ efueS efvecve ›eâebeflekeâ
efyevog
(b) Reynolds number/jsvee@u[dme mebKÙee
723oC neslee nw~ efpeme leeheceeve hej mšerue keâer mebjÛevee ceW
heefjJele&ve
(c) Mach number/cewkeâ mebKÙee
neslee nw ›eâebeflekeâ leeheceeve keânueelee nw~ Ùeefo mšerue keâes iece& efkeâÙee
(d) Froude number/øeâeG[ mebKÙee
peelee nw lees leeheve kesâ oewjeve Gmekeâer mebjÛevee ceW heefjJele&ve nesles nQ~
Fme
Ans : (c) peÌ[lJe yeue (Inertia force) Deewj õJe kesâ ØelÙeemLe yeue
heefjJele&ve keâes mšerue keâe ™heevlejCe keânles nQ~ "esme DeJemLee ceW mšerue
(elastic force) kesâ Devegheele kesâ Jeie&cetue keâes cewkeâ (Mach number)
keâe leeheve keâjves hej ™heevlejCe efveefMÛele leeheceeveeW hej neslee nw efpevnW
mebKÙee keâne peelee nw~
›eâeefvlekeâ leeheceeve Ùee ›eâebeflekeâ efyevog keânles nQ~ Megæ ueesns keâes peye
Fi
Gmekesâ mebueive leehe›eâce lekeâ iece& efkeâÙee peelee nw lees Gmekeâer mebjÛevee
ceW
cewkeâ mebKÙee (Mach No.) =
heefjJele&ve neslee nw~ ueesns kesâ Ûeej Dehej™he nesles nQ~
Fe

28. With which of the following are Participatory

cewkeâ mebKÙee ØeJeen keâe Øekeâej
Notes (PNs) associated?
Ma < 1 meye meesefvekeâ ØeJeen
heeefš&efmehesšjer veesšdme (PN) FveceW mes efkeâmemes mebyebefOele nQ?
Ma = 1 meesefvekeâ ØeJeen
(a) Kyoto Protocol/keäÙeesšes Øeesšeskeâeue
Ma > 1 meghej meesefvekeâ ØeJeen
(b) United Nations Development Programme
Ma > 5 neFhej meesefvekeâ ØeJeen
mebÙegòeâ je°^ efJekeâeme keâeÙe&›eâce
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 (c) Consolidated Fund of India
32. Moment of inertia of a rectangular section
Yeejle keâer mecesefkeâle efveefOe
having width (b) and depth (d) about an axis
(d) Foreign Institutional Investors
passing through its centre of gravity and
efJeosMeer mebmLeeiele efveJesMekeâ
parallel to the depth, is–

ÛeewÌ[eF& (b) Deewj ienjeF& (d) Jeeues Skeâ DeeÙeleekeâej Keb[

Ans : (d) menYeeieer veesš Ùee heefš&efmehesšjer veesšdme Gve Øehe$eeW keâes
keânles
nQ, efpevnW hebpeerke=âle efJeosMeer mebmLeeiele efveJesMekeâ (Foregin
keâe Gmekesâ ieg®lJe kesâvõ mes iegpejves Jeeueer Fmekeâer ienjeF&
Institutional Investors), efJeosMeeW ceW efmLele efveJesMekeâeW kesâ osles nQ
kesâ meceevlej De#e hej peÌ[lJe DeeIetCe& %eele keâerefpeS
(a)
db3/36
leeefkeâ Jes mesyeer ceW hebpeerke=âle ngÙes efyevee Yeer YeejleerÙe mše@keâ
ceekexâš ceW (b) db3/12
efveJesMe keâj mekesâ~ FvnW heer-veesšdme (P-Notes) Yeer keânles nQ~ (c)
bd3/12 (d) bd3/36
29. ................. is the death rate per thousand Ans : (b) ÛeewÌ[eF& (b)
Deewj ienjeF& (d) Jeeues Skeâ DeeÙeleekeâej KeC[
individuals. keâe Gmekesâ
ieg®lJe kesâvõ mes iegpejves Jeeueer Fmekeâer ienjeF& kesâ meceevlej
............. Øeefle npeej JÙeefòeâÙeeW hej ce=lÙeg oj nw~ De#e hej
peÌ[lJe DeeIetCe& db3/12 nesiee leLee ÛeewÌ[eF& kesâ meceevlej
(a) Emigration rate/ØeJeemeve oj
bd 3
peÌ[lJe
DeeIetCe& nesiee~
(b) Mortality rate/ce=lÙeg oj
12
(c) Natality rate/vesleeefuešer vesš 33. Which of
the following is NOT an angular
(d) Immigration rate/Dee›epeve oj
measuring instrument?
Ans : (b) pevemebKÙee kesâ Øeefle Skeâ npeej JÙeefòeâÙeeW hej efkeâmeer osMe
Ùee FveceW mes keâewve mee keâesCeerÙe ceehe–Ùeb$e veneR
nw?
#es$e ceW cejves Jeeues JÙeefòeâÙeeW keâer mebKÙee keâes ce=lÙegoj (Mortality
(a) Autocollimator/Dee@šeskeâesueercesšj
Rate) keânles nQ~
(b) Sinebar/meeFveyeej
30. Shear thickening fluid is also known as–
(c) Micrometer/ceeF›eâesceeršj
Dehe™heCe ØeieeÌ{ve õJe keâes ................. Yeer keâne
peelee (d) Bevel Protractor/yesJeue Øeesš^skeäšj
nw~
Ans : (c) Dee@šeskeâesueercesšj, meeFve yeej leLee yesJeue Øeesš^skeäšj leerveeW
(a) Pseudoplastic/mÙet[eshueeefmškeâ
keâesCeerÙe ceehe Ùeb$e (Measuring instrument) nw peyeefkeâ ceeF›eâesceeršj
(b) Dilatant/ef[uesšsvš
kesâ Éeje Deevleefjkeâ leLee yee¢e JÙeeme FlÙeeefo ceeheve efkeâÙee peelee nw~
(c) Thixotropic/efLekeämeesš^e@efhekeâ
Dee@šeskeâesueerceeršj Ùeb$e Éeje ueieYeie oes ceeršj keâer otjer lekeâ
(d) Rheopectic/efjÙeesheesefkeäškeâ
mLeeefhele hejeJele&keâ melen kesâ efyecye keâes mhe° ™he mes osKee pee
Ans : (b) Dehe™heCe ØeieÌ{ve õJe (Shear thickning fluid) keâes
mekeâlee nw~ FmeceW ueieYeie 20o lekeâ kesâ Deevele keâesCe heÌ{ves keâer
ef[uesšsvš (Dilatent) Yeer keâne peelee nw~
#ecelee nesleer nw~
ef[uesšsvš (Dilatent)– ef[uesšsvš lejue keâer MÙeevelee, keâle&ve efJeke=âefle
meeFveyeej keâe ØeÙeesie pee@ye keâe šshej %eele keâjves kesâ efueS efkeâÙee
keâer oj (rate of shear strain) yeÌ{ves mes yeÌ{leer nw~ Ssmes lejue
peelee nw~ meeFveyeej keâer heefjMegælee 0.0001" Øeefle FbÛe nesleer nw~
shear thickening fluids keânueeles nQ~ pewmes– yešj, efkeäJekeâmew[
yesJeue Øeesšwkeäšj keâe ØeÙeesie keâesCe keâes Deewj DeefOekeâ heefjMegælee mes
(Quick sand) efØebšj mÙeener FlÙeeefo~ ef[uesšsvš lejue kesâ n keâe ceeve
veeheves kesâ efueS efkeâÙee peelee nw~ Fmekeâe Deuheleceebkeâ 5 efceveš
1 mes pÙeeoe neslee nw~
neslee nw~
31. The ability of a material to resist deformation
34.
The malleability is the property of a material
or deflection under stress is known as–

by virtue of which a material–

efkeâmeer meece«eer keâer Øeefleyeue kesâ DeOeerve efJe™heCe Ùee

DeeIeeleJeOe&veerÙe efkeâmeer meece«eer keâe Jen iegCe nw, efpemekeâer

efJe#esheCe keâe efJejesOe keâjves keâer #ecelee keâes keäÙee keâne

Jepen mes meece«eer .................... ~

peelee nw?

(a) Retains the deformation produced under load

(a) Ductility/leveveMeeruelee
permanently/uees[ kesâ DeOeerve GlheVe efJe™heCe keâes
(b) Mechanical strength/Ùeebef$ekeâ meeceLÙe&
mLeeÙeer ™he mes yeveeS jKeleer nw
(c) Stiffness/keâÌ[eheve
(b) Regains its shape and size after the removal
(d) Toughness/keâ"esjlee
of external forces/yee¢e yeueeW keâes nševes kesâ yeeo
Ans : (c) efkeâmeer heoeLe& keâer ØelÙeemLelee meercee kesâ Debleie&le yeue
ueieeves Deheveer Deeke=âefle Deewj Deekeâej keâes
hegve: Øeehle keâj uesleer nw
mes GlheVe efJe™heCe Ùee PegkeâeJe keâe efJejesOe keâjves keâer meeceLÙe& keâes
(c) Can be drawn into wires with the application
keâÌ[eheve (Stiffness) keânles nQ~ efkeâmeer {eÛes keâer Deeke=âefle Ùee ceMeerve
of a tensile force/hej leveve yeue keâe ØeÙeesie keâjkesâ
heešd&me keâer Deeke=âefle hej keâÌ[eheve efveYe&j keâjleer nw~ heešdme& keâer
meceeve Gmekesâ leej KeeRÛes pee mekeâles nQ
pÙeeefceefle kesâ efueS Gvekeâer keâÌ[eheve Gvekesâ ØelÙeemLe iegCeebkeâ kesâ
(d) Can be rolled or hammered into thin
meceevegheeleer nesleer nw~ Fve efmLeefleÙeeW ceW ØelÙeemLelee keâes Modulus of
sheets/keâes jesue keâjkesâ Ùee nLeewÌ[s mes heerškeâj heleueer
stiffness keânles nQ~
ÛeeojeW kesâ ™he ceW yeouee pee mekeâlee nw
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Ans : (d) DeeIeeleJeOe&veerÙelee Ùee kegâšdÙelee (Malleability) iegCe kesâ
jsKeeSB yeve peeleer nw~ pewmes-pewmes Fueskeäš^es[ kesâ Deeke&â Jeeues Úesj keâer
keâejCe heoeLe& keâes efyevee štšs nLeewÌ[eW keâer Ûeesš Ùee jesefuebie Éeje
heleueer Deesj Ùes jsKeeSB yeÌ{leer nw Je=le keâe JÙeeme Iešlee peelee nw,
efpemekesâ keâejCe
MeeršeW ceW heefjJeefle&le efkeâÙee pee mekeâlee nw~ leehe›eâce kesâ yeÌ{ves hej
Fueskeäš^es[ hej Ùes ÛegcyekeâerÙe yeue jsKeeSB Skeâ yeue ueieeleer nwb efpemekesâ
kegâšdÙelee ceW Je=efæ nesleer nw~ meesvee keâes meyemes DeefOekeâ DeeIeeleJeæ&keâ
keâejCe Deeke&â Jeeues Úesj hej efheIeueer Oeeleg ieesueer kesâ ™he ceW yeveleer
nw~
(Malleable) ceevee peelee nw~
Fme ØeYeeJe keâes mebkegâÛeve (Pinch) ØeYeeJe keânles nw~
35. The sum of the clearance angle, rake angle and 37.
The height by which a tooth of a gear projects
cutting wedge angle is always equal to–
beyond the standard pitch or pitch line is

technically known as–

efkeäueÙejWMe keâesCe, jskeâ keâesCe Deewj keâefšbie Jespe keâesCe keâe

Jen TBÛeeF& efpemekesâ DeeOej hej ceevekeâ efheÛe meke&âue Ùee

Ùeesie ncesMee .............. kesâ yejeyej neslee nw~
efheÛe ueeFve mes efieÙej Øeespeskeäš keâe Skeâ oeBle lekeâveerkeâer
(a) 90o (b) 180o
keâes ................ ™he mes peevee peelee nw~
(c) 360o (d) 45o

(a) Dedundum/[s[v[ce
Ans : (a)

(b) Addendum/De[sv[ce

(c) Pitch radius/efheÛe jsef[Ùeme

(d) Backlash/yewkeâuesMe

Ans : (b) Jen TBÛeeF& efpemekesâ DeeOeej hej ceevekeâ efheÛe meke&âue Ùee

efheÛe ueeFve mes hejs (beyond) efieÙej Øeespeskeäš keâe Skeâ oeBle keâes

lekeâveerkeâer ™he mes De[sv[ce (Addendum) kesâ ™he ceW peevee peelee

nw~

efheÛe Je=òe mes oeBles kesâ Thejer efkeâveejs lekeâ $ewpÙe otjer (Radial

distance) De[wv[ce keânueeleer nw~ Fmekeâe ceeve Skeâ cee[dÙetue kesâ

yejeyej neslee nw~

Je=òeerÙe efheÛe Pc D 1
α + Ψ + γ = 90º
De[wv[ce (a) = = = = =m

π π T Pd
keâšeF& Deewpeej kesâ efyevog keâes ceewefuekeâ ™he ceW Skeâ heâVeer (Wedge)
ceevee pee mekeâlee nw~ heâVeer keâer keâeÙe& KeC[ hej keâšeF& keâer ef›eâÙee
38. What is the unit of electric potential?
ØeoefMe&le keâer ieF& nw~ heâVeer keâer meeF[ AB hesâme leLee meeF[ BC
efJeÅegle efJeYeJe keâe cee$ekeâ keäÙee nw?

(a) Volt (V)/Jeesuš (V)

heâuekeâ Ùee heäueQkeâ keânueeleer nw~ Fve oesveeW kesâ yeerÛe keâesCe ψ Jespe
keâesCe

(b) Coulomb (C)/ketâuecye (C)

keânueelee nw~ Fmeer Øekeâej ceMeerefvele mecetn BD Deewj heäueQkeâ BC kesâ

(c) Joule (J)/petue (J)

yeerÛe keâesCe γ mes oMee&Ùee peelee nw, Ùen DeJekeâeMe keâesCe (Clearance

(d) Ampere (A)/ScheerÙej (A)

angle) keânueelee nw~ ceMeerefvele melen BD hej uecye leLee hesâme AB
kesâ yeerÛe keâesCe α Éeje oMee&Ùee peelee nw, pees jskeâ keâesCe keânueelee nw~
Ans : (a) Yeeweflekeâ jeefMeÙeeW kesâ efJeefYeVe SI cee$ekeâ
Fme Øekeâej efkeäueÙejWme keâesCe, jskeâ keâesCe Deewj keâefšbie Jespe keâesCe keâe
Yeeweflekeâ jeefMe SI cee$ekeâ
Ùeesie ncesMee 90o neslee nw~
efJeÅegle efJeYeJe Jeesuš (V)
36. Pinch effect in welding is the result of–
efJeÅegle DeeJesMe ketâuee@ce (C)
Jesefu[bie ceW mebkegâÛeve ØeYeeJe ...............
kesâ keâeÙe& leLee Tpee& petue (J)
heefjCeecemJe™he GlheVe neslee nw~
efJeÅegle Oeeje SefcheÙej (A)
(a) Surface tension of the molten metal
39. How do the hard disks record information?
efheIeueer ngF& Oeeleg keâe he=‰erÙe leveeJe
ne[& ef[mkeâ ceW FveheâecexMeve kewâmes efjkeâe@[& nesles nQ?
(b) Shielding gases/heefjj#eCe iewmeeW
(a) Gravitation/«esJeeršsMeve
(c) Expansion of gases in the arc
(b) Magnetisation/cewievesšeFpesMeve
Deeke&â ceW iewmeeW kesâ Øemeej
(c) Propagation/ØeeshesiesMeve
(d) Electromagnetic forces/efJeÅegle ÛegcyekeâerÙe yeueeW
(d) Centrifugation/meWš^erheäÙetiesMeve
Ans. (d) : Jesefu[bie ceW mebkegâÛeve ØeYeeJe efJeÅegle ÛegcyekeâerÙe yeueeW kesâ
Ans : (b) ne[& ef[mkeâ keâchÙetšj kesâ efueÙes ÛegbyekeâerÙe YeC[ejCe keâe
heefjCeecemJe™he GlheVe neslee nw~
ceeOÙece nw~ ne[& ef[mkeâ heäuewš mekeg&âuej huesšdme, pees SuÙegefceefveÙece Ùee
mebkegâÛeve ØeYeeJe (Pinch effect)–peye Oeeje Fueskeäš^es[ mes neskeâj iueeme mes
yeveer nesleer nw Deewj Skeâ ÛegcyekeâerÙe meece«eer kesâ meeLe uesefhele
iegpejleer nw, lees Fueskeäš^es[ hej mebkesâvõerÙe Je=òe kesâ ™he ceW ÛegcyekeâerÙe
yeue nesleer nw~ ne[& ef[mkeâ metÛevee keâes šsjeyeeFšdme ceW mšesj keâj mekeâleer
nw~
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40. Cholera is caused by the bacteria called–
43. The working cycle of two stroke engine is
nwpee ............. veecekeâ peerJeeCeg keâe keâejCe neslee nw~
completed in .................. revolutions of crank
(a) Salmonella typhi/meeuceesvesuee šeFheâer
shaft.

2–mš^eskeâ Fbpeve keâe keâeÙe& Ûe›eâ ›eQâkeâ Meeheäš kesâ

(b) Treponema Palladium/š^sheesefvecee hewuesef[Ùece
(c) Clostridum botulinum/keäueesmš^eref[Ùece yeesšgefuevece
.............. ÛekeäkeâjeW ceW hetje neslee nw~
(d) Vibrio cholerae/efJeefyeÇÙees keâesueje
(a) Two/oes (b) Four/Ûeej
Ans : (d) peerJeeCegDeeW kesâ veece leLee Gvemes nesves Jeeues jesie-
(c) One/Skeâ (d) Three/leerve
jesie peerJeeCeg kesâ veece Ans :
(c) oes mš^eskeâ Fbpeve ceW Skeâ ef›eâÙee Ûe›eâ keâes hetCe& keâjves kesâ
nwpee efJeefyeÇDees keâe@uesjer efueS
efhemšve kesâ oes mš^eskeâ hetCe& keâjves nesles nQ leLee ›eQâkeâ MeeHeäš 1
šeÙeheâeÙe[ meeuceesvesuee šeFheâer
Ûekeäkeâj hetje keâjlee nw~ Fve oes mš^eskeâ ceW ner ÛeejeW DeehejsMeve Ûet<eCe,
efmeefheâefueme š^sheesefvecee heesuesef[Ùece
mebheer[ve, Meefòeâ leLee efvekeâeme Øeef›eâÙeeSB hetCe& nesleer nQ~ oes mš^eskeâ
Fbpeve
efššvesme keäuee@mš^eref[Ùece efššsveer ceW
ØeJesMe leLee efvekeâeme JeeuJe veneR nesles nQ, JeeuJe kesâ mLeeve hej heesš&
ueies
nesles nQ~ efmeefueC[j ceW leerve heesš& (ØeJesMe, efvekeâeme leLee š^ebmeheâj)
41. In an air standard Otto cycle, the compression
ratio is 7. Find the cycle efficiency. Ûeepe&
keâe ØeJesMe, peueer iewmeeW keâes yeenj efvekeâeueves leLee DeebefMekeâ ™he mes
Skeâ JeeÙeg ceevekeâ Dee@šes Ûe›eâ ceW, mebheer[ve Devegheele 7 nw~
mebheeref[le Ûeepe& keâes ›ewâkeâ kesâme mes efmeefueC[j ceW š^ebmeheâj keâjves
kesâ
Ûe›eâ o#elee %eele keâerefpeS~ GösMÙe
mes jKes peeles nQ~
(a) 38% (b) 71%
44. The moment of inertia of a solid cylinder of
(c) 54% (d) 80%
mass 'm', radius 'r' and length 'l' about the
Ans : (c) efoÙee nw–
longitudinal axis or polar axis is–
mebheer[ve Devegheele (rc) = 7
DevegowOÙe& De#e Ùee OeÇgJeerÙe De#e hej õJÙeceeve 'm', ef$epÙee

'r' Deewj uecyeeF& 'l' Jeeues "esme efmeueW[j keâe peÌ[lJe

1
Dee@šes Ûe›eâ keâer o#elee (ηotto) = 1 −
DeeIetCe& efkeâlevee neslee nw?
rcγ−1

(a) mr2/4
1
(b) mr2/8
ηotto = 1 −
71.4−1
(c) mr2/6
ηotto = 54%
(d) mr2/2
42. The Moment of Inertia of a circular area of
Ans : (d)
diameter 'd' about its diameter axis is–
Solid Moment of Inertia (IZZ)
JÙeeme 'd' keâe Skeâ Je=òeerÙe #es$e keâe peÌ[lJe DeeIetCe& Gmekesâ
Solid Cylinder mr 2
JÙeeme kesâ De#e kesâ heefjle: nw—
2
(a) πd2/64 (b) πd2/36
Thin Spherical shell 2 2
(c) πd3/36 (d) πd4/64
mr

3
Ans : (d)
Section Figure IXX IYY

Slab m 2

12

a + b2 ( )
Rectangular bd 3
db 3

Solid Sphere 2 2

mr
12 12
5

45. Determine the elevation for 30o using 5.00" sine

bar.

5.00" meeFve yeej keâe GheÙeesie keâjkesâ 30o kesâ efueS

Triangular bh 3 hb3
GVeleebMe %eeve keâerefpeS~
36 36
(a) 2.5000" (b) 3.8302"

(c) 2.8679" (d) 1.7101"

Ans : (a) 5.00" meeFve yeej keâe GheÙeesie keâjkesâ 300 kesâ efueS
Circular πd 4 πd 4
GVeleebMe 2.5000" nesiee~
64 64

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 h 48.
In which of the following cities did the
∵ sin θ =
Jallianwala Bagh massacre take place?
ℓ
⇒ h = ℓ sin θ
peefueÙeebJeeuee yeeie nlÙeekeâeb[ FveceW mes efkeâme Menj ceW
ℓ = 5.00" θ = 300 efoÙee nw,
ngDee Lee?
1
(a) Bhatinda/Yeefšb[e (b) Jalandhar/peeuebOej
h = 5.00"sin 30 = 5.00"×
(c) Amritsar/Dece=lemej (d) Patiala/heefšÙeeuee
2
h = 2.5000"
Ans : (c) jesuesš Skeäš kesâ efJejesOe ceW Deveskeâ mLeueeW hej peve meYeeÙeW
meeFve yeej keâe ØeÙeesie keâesCe ceeheves kesâ efueS efkeâÙee peelee nw~
DeeÙeesefpele keâer ieF&~ Fmeer oewjeve mejkeâej ves hebpeeye kesâ ueeskeâefØeÙe
veslee
46. The demand rate a particular item is 12000
[e. mewhegâöerve efkeâÛeuet Je [e. melÙeheeue keâes efiejheäleej keâj efueÙee~
Fmeer
units/year/ The ordering cost is Rs. 100 per
efiejheäleejer keâe efJejesOe keâjves kesâ efueÙes 13 DeØewue, 1919 F&. keâes
order and the holding cost is Rs. 0.80 per item
Dece=lemej kesâ peefueÙeeBJeeuee yeeie ceW Skeâ pevemeYee DeeÙeesefpele ngF&,
efpeme
per month. If no shortages are allowed and the
hej pevejue [eÙej ves ieesueer ÛeueJee oer, efpemeceW mewkeâÌ[eW ueesie ceejs
ieÙes~
replacement is instantaneous, then the number
49.
Bimbisara was the ruler of–
of order per year is–

efyeefcyemeej .................. keâe Meemekeâ Lee~

efkeâmeer efJeMes<e Jemleg keâer ceebie oj 12000 Ùetefveš/Je<e& nw~

(a) Magadha/ceieOe (b) Mathura/ceLegje

Dee@[&j keâjves keâer ueeiele ®. 100 Øeefle DeeosMe Deewj OeejCe

(c) Gandhara/ieebOeej (d) Taxila/le#eefMeuee

ueeiele ®. 0.80 Øeefle DeeFšce Øeefle ceen nw~ Ùeefo keâesF& Yeer
keâceer DevegcevÙe veneR nw Deewj ØeeflemLeeheve leel#eefCekeâ nw, Ans
: (a) efyeefcyemeej (544 F&.het.-493 F&.het.)- pewve meeefnlÙe ceW
lees Øeefle Je<e& DeeosMeeW keâer mebKÙee ............. nw~
Fmes ßesefCekeâ keâne ieÙee nw~ Jen ceieOe kesâ henues JebMe nÙe&keâ JebMe keâe
(a) 48 (b) 24
ØeLece MeefòeâMeeueer Meemekeâ Lee~ Gmekeâer jepeOeeveer efieefj›epe (jepeie=n)
(c) 36 (d) 12
Leer~ keâesMeue, JewMeeueer SJeb hebpeeye Deeefo mes JewJeeefnkeâ mebyebOeeW keâer
veerefle
Ans : (b) Jeeef<e&keâ ceebie (D) = 12000 Ùetefveš/Je<e&
Deheveekeâj efyeefcyemeej ves Deheves meeceüepÙe keâe efJemleej efkeâÙee~ Ùen yeewæ
Dee@[&j keâjves keâer ueeiele (Oc) = 100 Øeefle DeeosMe
leLee pewve oesveeW celeeW keâe hees<ekeâ Lee~ Fmekeâer nlÙee Fmekesâ heg$e
OeejCe ueeiele (hc) = 0.80 Øeefle DeeFšce Øeefle ceen
DepeeleMe$eg ves keâer Leer~
= 9.6 Øeefle DeeFšce Øeefle Je<e& 50.
Heat is absorbed by a refrigerant during a

refrigeration cycle in a–
ØeefleJe<e& DeeosMeeW keâer mebKÙee (N) = ?

ØeMeerleve Ûe›eâ kesâ oewjeve, T<cee ................. ceW ØeMeerlekeâ

2 × D × Oc 2 × 12000 ×100
∵ EOQ = =
Éeje DeJeMeesef<ele keâer peeleer nw~
hc 9.6

(a) Compressor/kebâØesmej
EOQ = 500

(b) Throttle valve/LeÇe@šue JeeuJe

ceebie ( Demand ) 12000
(c) Condenser/mebIeefve$e
∵ N= =
EOQ 500

(d) Evaporator/Jeeef<he$e
N = 24 ØeefleJe<e&
Ans : (d) ØeMeerleve Ûe›eâ kesâ oewjeve, T<cee Jeeef<he$e (Evaporator)
47. Soft solder consists of–
Éeje DeJeMeesef<ele keâer peeleer nw~
ce=og meesu[j ............. neslee nw~
(a) Lead and tin/meermee Deewj efšve
(b) Lead and zinc/meermee Deewj efpebkeâ
(c) Lead and aluminum/meermee Deewj SsuegefceefveÙece
(d) Copper and tin/leebyee Deewj efšve
Ans : (a) ce=og meesu[j keâe mebIešve meermee Deewj efšve neslee nw~
meesu[j kesâ Øekeâej (Type of Solders)
Solders Pb : Sn
(i) Soft solder 40% : 60%
Process 1–2 : ™æes<ce mebheer[ve
(ii) Medium 50% : 50%
Process 2–3 : efveÙele oeye hej T<cee efve<keâemeve
(iii) Electricians 60% : 40%
Process 3–4 : DeeFmesvLewequhekeâ Øemeej
(iv) Plumbers 70% : 30%
Process 4–1 : efveÙele oeye hej T<cee Ùeesie
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51. When Mach number is less than unity, the flow DeefOekeâlece Dehe™heCe
Øeefleyeue efmeæeble (Max shear stress
is called– theory)–
Fme efmeæeble kesâ Devegmeej efkeâmeer efyevog hej keâesF&
Debie leye
peye cewkeâ (Mach) mebKÙee Skeâkeâ mes keâce nesleer nw, lees Demeheâue
neslee nw~ peye Gme efyevog hej DeefOekeâlece keâle&ve Øeefleyeue
keâe
ØeJeen keâes keäÙee keâne peelee nw?
ceeve heoeLe& kesâ mejue leveeJe hejer#eCe ceW Gmekeâer ØelÙeemLelee meercee hej
(a) Sub–sonic flow/meye–meesefvekeâ ØeJeen
DeefOekeâlece keâle&ve Øeefleyeue kesâ yejeyej nes peelee nw~
(b) Sonic flow/meesefvekeâ ØeJeen
σy

τmax ≤
(c) Hyper–sonic flow/neFhej–meesefvekeâ ØeJeen
2
(d) Super–sonic flow/meghej–meesefvekeâ ØeJeen
Fme efmeæeble keâe DeefOekeâlece ØeÙeesie levÙe heoeLeeX kesâ efueS efkeâÙee peelee
nw~
Ans : (a)
54. The temperature point at which the change
cewkeâ mebKÙee (Mach No.) ØeJeen (Flow)
starts on heating the steel is called–

Jen leehe efyebog, efpeme hej mšerue keâes iece& keâjves hej FveceW
Ma < 1 meye meesefvekeâ ØeJeen
heefjJele&ve nesvee Meg™ neslee nw, keäÙee keânueelee nw?
Ma = 1 meesefvekeâ ØeJeen
(a) Point of recalescence/hegve™<ceCe efyebog
Ma > 1 meghej meesefvekeâ ØeJeen
(b) Point of decalescence/efJeT<ceCe efyebog
Ma > 5 neFhej meesefvekeâ ØeJeen
(c) Lower critical point/efvecve ›eâebeflekeâ efyebog
52. If 1 kg mixture of steam contains 0.8 kg of dry
(d) Upper critical point/GÛÛe ›eâebeflekeâ efyebog
vapour and 0.2 kg of moisture, then the
Ans : (c) efvecve ›eâeefvlekeâ efyevog (Lower Critical Point) hej
dryness fraction of the steam is–
mšerue keâes iece& keâjves hej FmeceW heefjJele&ve Meg™ nes peelee nw~ Ùeefo
Ùeefo 1 efkeâ«ee Jee<he kesâ efceßeCe ceW 0.8 efkeâ«ee Meg<keâ Jee<he
mšerue keâes iece& efkeâÙee peelee nw lees leeheve kesâ oewjeve Gmekeâer mebjÛevee
ceW
Deewj 0.2 efkeâ«ee veceer nes lees Yeehe keâe Meg<keâlee DebMe %eele
heefjJele&ve nesles nQ~ Fme heefjJele&ve keâes mšerue keâe ™heevlejCe keânles nQ~
keâerefpeS~
"esme DeJemLee ceW mšerue keâe leeheve keâjves hej ™heevlejCe efveefMÛele
(a) 0.5 (b) 0.6
leeheceeveeW hej neslee nw efpevnW ›eâeefvlekeâ leeheceeve Ùee ›eâeefvlekeâ efyevog
keânles
(c) 0.2 (d) 0.8
nQ~ Dehe™heer heefjJele&ve mšerue keâer mebjÛevee ceW leeheve SJeb Meerleueve
Ans : (d)

Øeef›eâÙee kesâ oewjeve ØelÙeeJeleea heefjJele&ve neslee nw~

mv
55. Which of the following states that, "If a body is
Meg<keâlee DebMe (Dryness fraction) =
in equilibrium, under the action of three
m v + mi
concurrent forces, each force is proportional to
mv = 0.8 kg
the sine of the angle between the other two
mi = 0.2 kg
forces"?
0.8
FveceW mes efkeâme efveÙece kesâ Devegmeej, ‘‘Ùeefo leerve yeueeW kesâ
x= = 0.8
ef›eâÙeeDeeW kesâ DeOeerve keâesF& efheb[ meblegueve (equilibrium)
0.8 + 0.2
Dele: Yeehe keâe Meg<keâlee DebMe 0.8 nesiee~
ceW nw, lees ØelÙeskeâ yeue DevÙe oes yeueeW kesâ yeerÛe kesâ keâesCe

keâer pÙee (sine) kesâ meceevegheeleer neslee nw’’?

53. Which theory of failure will you use for
aluminum components under steady loading?
(a) Varignon's theorem/Jesefjiveve keâer ØecesÙe
efmLej ueesef[bie kesâ DeOeerve SuÙetceerefveÙece kesâ IeškeâeW kesâ
(b) Lami's theorem/ueeceer keâer ØecesÙe
efueS Deehe efJeheâuelee kesâ efkeâme efmeæeble keâe GheÙeesie
(c) Parallelogram law of forces

yeueeW keâe meceeblej ÛelegYeg&pe efveÙece

keâjWies?

(d) Transmissiblity of forces/yeueeW keâe mebÛejCeerÙelee

(a) Maximum strain energy theory

Ans : (b) uee@ceer kesâ Devegmeej, Ùeefo efkeâmeer efheC[ hej keâeÙe& keâj jns
DeefOekeâlece efJeke=âefle Tpee& efmeæeble

leerve yeue meblegueve ceW nes, lees ØelÙeskeâ yeue Mes<e oes yeueeW kesâ yeerÛe
kesâ
(b) Maximum shear stress theory

keâesCe keâer pÙee kesâ meceevegheeleer neslee nw~

DeefOekeâlece Dehe™heCe Øeefleyeue efmeæeble
(c) Maximum principal stress theory
DeefOekeâlece cegKÙe Øeefleyeue efmeæeble
(d) Maximum principal strain theory
DeefOekeâlece cegKÙe efJeke=âefle efmeæeble
Ans : (b) efmLej ueesef[bie (Steady loading) kesâ DeOeerve By Lami theorem–
SuÙegefceefveÙece kesâ IeškeâeW kesâ efueS DeefOekeâlece Dehe™heCe Øeefleyeue F1
F F

= 2 = 3 (When Body is equilibrium)

efmeæeble (Max Shear Stress theory) keâe GheÙeesie efkeâÙee peelee nw~ sin α
sin β sin γ

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56. Which of the following operations does NOT Ans : (a) efmuehe
iespe (Slip gauge) keâes pee@vemeve iespe Ùee iespe
use a Multiple–point cutting tool? yueekeâ Yeer keânles nQ~
Ùes DeeÙeleekeâej heermeerpe (pieces) nesleer nw~ Fvekeâes
efvecveefueefKele ceW mes keâewve–mee heefjÛeeueve ceušerheue– GÛÛe
keäJeeefuešer keâer štue mšerue Ùee mšsvueeFp[ ›eâesefceÙece mšerue mes
hee@Fbš keâefšbie štue keâe GheÙeesie keâjkesâ veneR efkeâÙee peelee
yeveeÙee peelee nw~ YeejleerÙe mšwC[[& (ISI) kesâ Devegmeej Ùen 10 mm
nw? Ùee
Fmemes yeÌ[s meeFpe ceW efceueles nQ~ Fmekeâe ØeÙeesie mece™he iespeeW keâer
(a) Milling/efceefuebie
met#celee Ûeskeâ keâjves kesâ efueS Deewj meeFve yeej keâes efkeâmeer šshej ceW
mewš
(b) Drilling/ef[^efuebie
keâjves kesâ efueS neslee nw~ Ùes mesšeW ceW heeÙes peeles nQ~ efmuehe iespeeW kesâ
(c) Turning/šefveËie
GheÙeesie keâjves kesâ Ghejevle keâeye&ve šsš^e keäueesjeF[ keâe ØeÙeesie meeheâ
(d) Broaching/yeÇesefÛebie
keâjves kesâ efueS efkeâÙee peelee nw~
Ans : (c) šefveËie DeehejsMeve ceW Skeâue efyevog Deewpeej (Single Point 60. A
single unit which is composed of small group

of bits is known as–

tool) keâe GheÙeesie efkeâÙee peelee nw~ Skeâue efyevog Deewpeej Éeje
hesâefmebie, ................ Skeâ efmebieue Ùetefveš nw, pees efyeš kesâ
Úesšs
keâefšbie, KeeBÛee, heâeefceËie, ÛetÌ[er keâle&ve, yeesefjbie Deeefo mebef›eâÙeeSB
mecetn mes yeveer nesleer nw~
(operation) efkeâÙee peelee nw~ cejes[ Ì er yejcee (Twist drill), jercej

(a) Byte/yeeFš (b) Bug/yeie

(Reamer), šwhe leLee efceefuebie keâšj Deeefo yeng efyevog Deewpeej nQ~

(c) Flag/heäuewie (d) Bit/efyeš

Deewpeej keâe ef›eâÙeekeâejer Yeeie Skeâ Ùee DeefOekeâ DeJeÙeJeeW keâe yevee neslee
nw~ keâšeF& Deewpeej Skeâ Ùee DeefOekeâ efyevogDeeW Jeeues nesles nQ Deewj
ØelÙeskeâ Ans : (a) yeeFš (Byte) mebie"ve Je otj mebÛeej ceW metÛevee keâer FkeâeF&
efyevog mJeleb$e ™he mes keâšeF& keâjves ceW me#ece neslee nw~
nesleer nw~ Ùen 8 efyeš (Bit) mes efceuekeâj yeveer nesleer nw~ Ùen keâchÙetšj

mce=efle keâer otmejer meyemes Úesšer FkeâeF& nesleer nw~ Fmes 'B' mes oMee&Ùee
57. Where is India's the first oceanarium being set
up?

peelee nw~
Yeejle keâer henuee mecegõMeeuee keâneB yeveeF& pee jner nw?
61. If 'α' is the helix angle and 'φ' is the angle of

friction then, when will the efficiency of a

(a) Mumbai/cegcyeF&
screw jack be maximum?
(b) Goa/ieesJee
Ùeefo efkeâmeer m›etâ pewkeâ keâe nsefuekeäme keâesCe 'α' nw Deewj
(c) Kochi/keâesefÛÛe
Ie<e&Ce keâesCe 'φ' nw, lees m›etâ pewkeâ keâer o#elee keâye
(d) Vishakhapatnam/efJeMeeKeeheóvece
DeefOekeâlece nesieer?
Ans : (c) Yeejle keâer henueer mecegõMeeuee kesâjue kesâ keâesefÛÛe ceW yeveeF&
(a) α = 90o + φ (b) α = 45o + (φ/2)
pee jner nw~ Ùen heefjÙeespevee celmÙe heeueve heÙe&šve keâes yeÌ{eJee osves,
(c) α = 45 – (φ/2) (d) α = 90o – φ
MeesOekeâòee&DeeW Deewj ueesieeW keâes Jnsue Deewj Meeke&â pewmeer yeÌ[er
ØepeeefleÙeeW Ans : (c)
meefnle mecegõer ØepeeefleÙeeW keâe DeOÙeÙeve keâjves kesâ efueÙes yeveeF& pee jner
nw~ m›etâ pewkeâ keâer o#elee η = tan α

( )
58. The rate at which the entire organization
tan ( φ + α )
generates money through sales for a product or
DeefOekeâlece o#elee kesâ efueS oMeeSB (Condition)—
service is–

φ
Jen oj, efpeme hej hetje mebie"ve efkeâmeer Glheeo Ùee mesJee keâer
α = 45o −

2
efye›eâer kesâ ceeOÙece mes Oeve Deefpe&le keâjlee nw, ..............

1 − sin φ
keânueeleer nw~
DeefOekeâlece o#elee ( ηmax ) =

1 + sin φ
(a) Takt time/šwkeäš šeFce

peneB φ = Ie<e&Ce keâesCe

(b) Operating expense/heefjÛeeueve JÙeÙe

α = nsefuekeäme keâesCe
(c) Throughput/ØeJeen #ecelee

62. Which of the following Japanese terms in 5S

(d) Inventory/metÛeer
methodology represents the meaning of shine?
Ans : (c) Jen oj, efpeme hej hetje mebie"ve efkeâmeer Glheeo Ùee mesJee keâer
5S ØeCeeueer ceW FveceW mes keâewve mee peeheeveer Meyo Ûecekeâ
efye›eâer kesâ ceeOÙece mes Oeve Deefpe&le keâjlee nw ØeJeen #ecelee keânueeleer
nw~ keâes efve™efhele keâjlee nw?
59. Johannsen Gauges are otherwise known as–
(a) Shitsuke/Meerlemegkesâ (b) Seiso/meermees
peesnevemeve iespe keâes DevÙeLee ................ Yeer keâne peelee
(c) Seiton/meeršve (d) Seiri/meerjer
nw~
Ans : (b) 5'S' DeefYeOeejCee (concept) Skeâ peeheeveer MeyoeW keâe
(a) Slip gauges/efmuehe iespe
meceekeâueve nw~
(b) Radius gauges/jsef[Ùeme iespe
• Fmekesâ Debleie&le cewvespeceWš leLee keâce&Ûeejer kesâ menÙeesie Éeje
(c) Snap gauges/mvewhe iespe
keâeÙe&mLeue, ceMeerve, GhekeâjCe Deeefo keâe GefÛele jKe-jKeeJe leLee
(d) Feeler gauges/heâeruej iespe
megjef#ele jnkeâj keâeÙe& efkeâÙee peelee nw~
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 • 5 'S' kesâ DeefYeOeejCeeSB—
(a) Rulings follow a logarithmic scale
S.N. Japanese Hindi English
jsKeeSb ueIegieCekeâerÙe hewceeves kesâ Deveg™he nesleer nw
1. Seiri ÚšeF& Sorting
(b) Rulings need not have any pattern

jsKeeDeeW keâe efkeâmeer Yeer hewšve& ceW nesvee DeeJeMÙekeâ veneR nw

2. Seiton megJÙeJemLee Set in order

(c) Rulings are more closely spaced, producing a

3. Seiso mJeÛÚlee Sine

periodic pattern without blank gaps

4. Sieketsu ceevekeâerkeâjCe Standardise
jsKeeSb efjòeâ mLeeve kesâ efyevee DeeJeefOekeâ hewšve& yeveeles ngS,
5. Shitsuke DevegMeemeve Sustain
DeefOekeâ efvekeâš efmLeefle nesleer nw
63. If 'W' is weight of a body, 'α' is angle of an
(d) Rulings are spaced relatively far apart,
inclined plane and 'φ' is angle of friction, then
requiring some type of interpolating device to
the force required to drag the body when it is
make accurate settings/jsKeeSb Dehes#eeke=âle heÙee&hle
just impending to move up the plane, is–
otjer hej nesleer nw, mešerkeâ mesefšbie kesâ efueS efkeâmeer Øekeâej kesâ
Ùeefo efkeâmeer efheC[ keâe Yeej 'W' nw, PegkeâeJe Jeeues meceleue
Fbšjheesefuebie ef[JeeFme keâer DeeJeMÙekeâlee nesleer nw
keâe keâesCe 'α' nw Deewj Ie<e&Ce keâe keâesCe 'φ' nw, lees efheC[ Ans : (c)
cesš^esuee@peer ceW ‘«esefšbie’ Meyo keâe DeLe&, jsKeeSB efjòeâ mLeeve
keâes efJejesOe keâjves keâe DeeJeMÙekeâ yeue, peye Ùen meceleue kesâ efyevee
DeeJeefOekeâ hewšve& yeveeles ngS DeefOekeâ efvekeâš eqmLele nesvee nw~
keâes Thej ues peeves kesâ efueS ØeJe=òe neslee nw, lees Jen ......... 65.
Which of the following countries hosted the
nw~
first Commenwealth Games in 1930?
(a) W sin (α + φ) (b) W tan (α + φ)
efvecveefueefKele ceW mes efkeâme osMe ves 1930 ceW DeeÙeesefpele
(c) W sec (α + φ) (d) W cos (α + φ)
ØeLece je°^ceC[ue KesueeW keâer cespeyeeveer keâer?
Ans. (b) :
(a) Australia/Dee@mš^sefueÙee

(b) New Zealand/vÙetpeeruewC[

(c) Canada/keâvee[e

(d) England/FbiuewC[
Ans :
(c) henuee je°^ceC[ue Kesue 1930 ceW keâvee[e kesâ nwefceušve
Menj
ceW ngDee Lee~ FmeceW 11 osMeeW kesâ ueieYeie 400 efKeueeefÌ[ÙeeW ves,
Ú:
KesueeW keâer 59 ØeefleÙeesefieleeDeeW ceW Yeeie efueÙee~ Ùen leye mes ØelÙeskeâ
ΣV = 0 mes, Ûeej
Je<e& ceW DeeÙeesefpele efkeâÙes peeles nQ~
R = P sin α + W cos α ............(i)
66. Which of the following distribution represents
ΣH = 0 mes,
the time estimates in PERT?
P cos α = µR + W sin α ...........(ii)
FveceW mes keâewve efJelejCe PERT ceW meceÙe DevegceeveeW keâes
meceer. (ii) ceW 'R' keâe ceeve jKeves hej,
efve™efhele keâjlee nw?
P cos α = µ [ P sin α + W cos α ] + W sin α
(a) Weibul distribution/Jeeryegue efJelejCe
P [ cos α − µ sin α ] = W [µ cos α + sin α ] ......(iii)
(b) Normal distribution/meeceevÙe efJelejCe

Ùeefo Ie<e&Ce keâesCe φ nes lees,

(c) Poisson distribution/hJeebmees efJelejCe
µ = tan φ meceer. (iii) ceW jKeves hej,
(d) Beta distribution/yeerše efJelejCe
P [ cos α − tan φ sin α ] = W [ tan φ cos α + sin α ]
Ans : (d)
[cos α .cos φ − sin α.sin φ] = W [cos α.sin φ + sin φ.cos α]
yeerše efJelejCe (Beta distribution) PERT ceW meceÙe DevegceeveeW
P
cos φ cos φ
keâes efveOee&efjle keâjlee nw~
P  cos ( α + φ )  = W sin ( α + φ ) 
PERT keâe keâce&Ûeejer meceÙe (Activity duration) efveOee&efjle

veneR neslee nw~

sin ( α + φ )
PERT keâe ØeÙeesie veS Øeespeskeäš (New Project) kesâ efueS ØeÙeesie
P=W
cos ( α + φ )
efkeâÙee peelee nw~
P = W tan ( α + φ )
PERT has three time estimates

(i) Optimistic time (to)

64. The term 'grating' in metrology means that–
(ii) Most likely time (tm)
cesš^esuee@peer ceW ‘«esefšbie’ Meyo keâe keäÙee DeLe& nw?
(iii) Pessimistic time (tp)

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 t o + 4t m + t p
70. The complete resistance spot weld cycle has
Expected time (te) =
been divided into ............ parts.
6

hetCe& heeflejesOe mhee@š Jesu[ Ûe›eâ keâes ................. YeeieeW ceW

efJeYeeefpele efkeâÙee ieÙee nw~

(a) Three/leerve (b) Four/Ûeej

(c) Two/oes (d) Five/heeBÛe

Ans : (b) hetCe& ØeeflejesOe mhee@š Jesu[ Ûe›eâ keâes Ûeej YeeieeW ceW

efJeYeeefpele efkeâÙee peelee nw~ FmeceW leeByes DeLeJee keâeBmes keâer yeveer ngF&
Ûeue

leLee efmLej oes YegpeeDeeW ceW pekeâÌ[s ngS leeByes kesâ oes Fueskeäš^es[dme
nesles nw;
67. Up milling is also called as–
pees Skeâ mšwhe [eGve Jesefu[bie š^ebmeheâece&j mes efvecve Jeesušlee hej GÛÛe
Dehe efceefuebie ................... Yeer keâne peelee nw~
Oeeje Øeehle keâjles nQ~ Jesu[ keâer peeves Jeeueer OeelegDeeW keâes oesveeW
(a) Face milling/hesâme efceefuebie
Fueskeäš^es[es kesâ ceOÙe JÙeJeefmLele keâjkesâ Ûeue Fueskeäš^es[ mes Ùeebef$ekeâ
oeye
(b) Conventional milling/keâvJeWMeveue efceefuebie
ueieeÙee peelee nw~ Oeeje leLee mheMe& ØeeflejesOe kesâ keâejCe oesveeW huesšeW
kesâ

ceOÙe mheMe& efyevogDeeW hej DeefOekeâ T<cee GlheVe nesleer nw~ Fme Øekeâej
(c) Climb milling/keäueeFbye efceefuebie

oeye leLee T<cee kesâ keâejCe oesveeW huesšs mheMe& efyevogDeeW hej efheIeuekeâj
(d) End milling/Sb[ efceefuebie

Jesu[ nes peeleer nQ~

Ans : (b) Dehe efceefuebie keâes keâvJeWMeveue efceefuebie (Conventional 71.
Steel containing less than 0.15% carbon
milling) Yeer keâne peelee nw~ Fme efJeefOe ceW keâeÙe&KeC[ keâe YejCe
content is known as–
(feed) keâšj keâer IegceeJe efoMee kesâ efJe™æ neslee nw~ meeceevÙele:
0.15% mes keâce keâeye&ve meece«eer Jeeues mšerue keâes keäÙee
yesueveekeâej efceefuebie ceW Fmeer efJeefOe keâe ØeÙeesie efkeâÙee peelee nw~
keâšeF& kesâ keâne peelee nw?
Debleie&le keâšj keâe ØelÙeskeâ oelee Oeeleg ceW ØeefJe‰ nesves mes henues Gmekeâer
(a) High carbon steel/GÛÛe keâeye&ve Fmheele
ceMeerefvele melen hej efheâmeuelee nw~ Fme efJeefOe kesâ Debleie&le keâšj keâeÙe&–
(b) Medium carbon steel/ceOÙece keâeye&ve Fmheele
KeC[ keâes G"eves keâer ØeJe=efòe jKelee nw~
(c) Dead mild steel/[s[ ceeFu[ mšerue
68. The science that deals with the relationship of
(d) Stainless steel/mšsveuesme mšerue
various organisms with their environment is

Ans : (c) 0.15% mes keâce keâeye&ve meece«eer Jeeues mšerue keâes [s[
known as–
 efJeefYeVe peerJeeW kesâ heÙee&JejCe kesâ meeLe mebyebOeeW mes
mebyebefOele ceeFu[ mšerue (Dead mild steel) keâne peelee nw~

(i) Dead mild steel : up to 0.15% carbon

efJe%eeve keâes ................. keâne peelee nw~
(ii) Low carbon or mild steel : 0.15% – 0.30% carbon
(a) Geology/YetieYe&MeeŒe
(iii) Medium carbon steel : 0.30% – 0.8% carbon
(b) Ecology/heeefjefmLeeflekeâer efJe%eeve
(iv) High carbon steel : 0.8% – 1.5% carbon
(c) Anthropology/ceeveJe–MeeŒe
72. Otto cycle is constant ................ cycle.
(d) Cytology/keâesefMekeâe efJe%eeve
Deesšes Ûe›eâ Skeâ efmLej .................. Ûe›eâ nw~
Ans : (b) heeefjefmLeeflekeâer (Ecology) peerJeOeeefjÙeeW Deewj
Gvekesâ (a) Temperature/leehe (b) Entropy/Sbš^e@heer
JeeleeJejCe kesâ meeLe mebyebOeeW keâe DeOÙeÙeve keâjlee nw~ Fme Øekeâej
(c) Pressure/ oeye (d) Volume/DeeÙeleve
heeefjefmLeeflekeâer peerJe efJe%eeve keâer Jen MeeKee nw, efpemekesâ Devleie&le
peerJeeW Ans : (d) Deešes Ûe›eâ Skeâ efmLej DeeÙeleve Ûe›eâ nw~
kesâ JeeleeJejCe kesâ meeLe Devle:mecyevOeeW keâe DeOÙeÙeve efkeâÙee peelee nw~
69. Which of the following is NOT a type of virus?
efvecveefueefKele ceW mes keâewve mee Skeâ Øekeâej keâe JeeÙejme
veneR nw?
(a) McAfee
(b) Boot sector/yetš meskeäšj
(c) Polymorphic/heeueerceeefhe&âkeâ
1–2 : Reversible adiabatic compression

2–3 : Heat addition at constant volume

(d) Multipartite/ceušerhesjeFš

3–4 : Reversible adiabatic expansion

Ans : (a) McAfee Skeâ Sbšer JeeÙejme Øees«eece nw, efpemes McAfee
4–1 : Heat rejection at constant volume
Éeje yeveeÙee Deewj Devegjef#ele efkeâÙee peelee nw~ Fmes henues Fbšsue
Deešes Ûe›eâ ceW T<cee keâe Ùeesie leLee efvekeâeme oesveeW efveÙele DeeÙeleve
efmekeäÙeesefjšer (Intel Security) kesâ ™he ceW peevee peelee Lee~
hej neslee nw FmeefueS Fmes efmLej DeeÙeleve Ûe›eâ keânles nQ~
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73. Which of the following is an extensive 76.
When the pressure intensity at a point is more
property?
than the local atmospheric pressure, then the
efvecveefueefKele ceW mes keâewve mee Skeâ efJemleejer iegCe nw?
difference of these two pressures is called–
(a) Density/IevelJe
peye efkeâmeer efyebog hej oeye keâer leer›elee, mLeeveerÙe
(b) Volume/DeeÙeleve
JeeÙegceb[ueerÙe oeye mes DeefOekeâ nesleer nw, lees Fve oes oeyeeW
(c) Boiling point/keäJeLeveebkeâ
kesâ Deblej keâes keäÙee keâne peelee nw?
(d) Melting point/ieueveebkeâ
(a) Barometric pressure/yewjesceeršj keâe oeye
Ans : (b) DeeÙeleve Skeâ efJemleejer iegCe (Extensive property) nw
(b) Negative gauge pressure/vekeâejelcekeâ Øeceeheer oeye
keäÙeeWefkeâ Ùen efvekeâeÙe kesâ õJÙeceeve hej efveYe&j neslee nw~
(c) Positive gauge pressure/Oeveelcekeâ Øeceeheer oeye

(d) Absolute pressure/efvejhes#e oeye

Ans : (c) peye efkeâmeer efyevog hej oeye keâer leer›elee, mLeeveerÙe

JeeÙegceC[ue oeye mes DeefOekeâ nesleer nw, lees Fve oes oeyeeW kesâ Deblej keâes

Oeveelcekeâ Øeceeheer oeye (Positive gauge pressure) keâne peelee nw~

• keäJeLeveebkeâ
• ieueveebkeâ
74. Pallet is an example for which operating
principle of material handling plan?
hewuesš, meece«eer nQ[efuebie Ùeespevee kesâ efkeâme heefjÛeeueve 77.
Silicon steel is widely used for–
efmeæeble keâe Skeâ GoenjCe nw?
............ kesâ efueS efmeefuekeâe@ve mšerue keâe GheÙeesie JÙeehekeâ
(a) Flow principle/ØeJeen efmeæeble
™he mes efkeâÙee peelee nw~
(b) Gravity principle/ieg®lJeekeâ<e&Ce efmeæeble
(a) Cutting tools/keâle&ve GhekeâjCe
(c) Space utilization principle/mLeeve GheÙeesie efmeæeble
(b) Connecting rods/mebÙeespevekeâ ÚÌ[eW
(d) Unit load principle/Ùetefveš uees[ efmeæeble
(c) Motor crank shafts/ceesšj ›eQâkeâ Meeheäš
Ans : (d) hewuesš, meece«eer nQ[efuebie Ùeespevee Ùetefveš uees[ heefjÛeeueve
(d) Transformers/š^evmeheâe@ce&j
efmeæeble keâe Skeâ GoenjCe nw~
Ans : (d)
hewuesš (Pallet)–hewuesš Skeâ #eweflepe heesšxyeue huesšheâece& ef[JeeFme nw,
š^ebmeheâe@ce&j kesâ efueS efmeefuekeâe@ve mšerue keâe GheÙeesie JÙeehekeâ ™he mes
efpemekeâe ØeÙeesie FkeâeF& Yeej ceW meece«eer keâes mebYeeueves (Handlling) kesâ
efkeâÙee peelee nw~
efueS DeeOeej kesâ ™he ceW efkeâÙee peelee nw~ Ùen FkeâeF& Yeej kesâ efmeæeble
efmeefuekeâe@ve mšerue ceW efmeefuekeâe@ve keâer cee$ee 3.5³ mes 4³ Deewj
hej keâeÙe& keâjlee nw~
keâeye&ve 0.2³ lekeâ nesleer nw~
75. The Ramsar convention is related to the
efmeefuekeâe@ve mšerue keâe ØeÙeesie efyepeueer kesâ pevejsšj, ceesšj Deewj
conservation of–
š^ebmeheâece&j yeveeves ceW efkeâÙee peelee nw~ peyeefkeâ ceQieveerpe mšerue keâe
jecemej meccesueve ............... kesâ mebj#eCe mes mebyebefOele nw~
ØeÙeesie keâvewefkeäšbie je@[, jsueJes kesâ ›eâeefmebie kesâ hJeeFbšme, jsueJes
keâer
(a) Grasslands/Ieeme kesâ cewoeveeW
hešjer Deewj ›esâMej Deeefo yeveeves ceW efkeâÙee peelee nw~
(b) Wetlands/Deeõ&YetefceÙeeW
78. Which of the following is an example of
(c) Oceans/cenemeeiejeW
paramagnetic material?
(d) Forests/JeveeW
efvecveefueefKele ceW mes keâewve mee DevegÛegbyekeâerÙe heoeLe& keâe
Ans : (b) F&jeve kesâ Menj jecemej ceW 2 heâjJejer, 1971 keâes ngÙes
GoenjCe nw?
meccesueve ceW ØeefleYeeieer je°^eW Éeje Deeõ&YetefceÙeeW (Wetlands) kesâ
(a) Gold/meesvee (b) Tantalum/šQšuece
mebj#eCe mes mecyebefOele Debleje&°^erÙe mebefOe/mecePeewles hej nmlee#ej efkeâÙes
ieÙes~ (c) Copper/leebyee (d) Silver/Ûeeboer
Ùen meccesueve jecemej meccesueve kesâ veece mes peevee peelee nw~
Ans : (b) kegâÚ heoeLe& Ssmes nQ, efpevnW oes MeefòeâMeeueer ÛegcyekeâeW kesâ
• Je<e& 2022 kesâ efueS efJeÕe Deeõ& Yetefce efoJeme keâer Leerce
‘‘JesšuewC[ OeÇgJeeW kesâ ceOÙe ueškeâe osves hej Ùes ÛegcyekeâerÙe #es$e keâer
efoMee kesâ meceevlej
SkeäMeve heâe@j heerhegume Sb[ vesÛej’’ nw~
nes peeles nw~ Fve heoeLeeX kesâ Devoj Øesefjle ÛegcyekeâerÙe #es$e keâer efoMee
yee¢e
• 2 heâjJejer keâes ØeefleJe<e& efJeÕe Deeõ&Yetefce efoJeme kesâ ™he ceW ceveeles
nQ~ Deejesefhele ÛegcyekeâerÙe #es$e keâer efoMee ceW nesleer nw~ Fme ßesCeer kesâ
heoeLeeX
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keâer ÛegcyekeâMeeruelee (µ) Deewj ÛegcyekeâerÙe ØeJe=efòe K keâe ceeve yengle
keâce je@keâJesue ne[&vesme šsefmšbie ceMeerve kesâ Fb[wšj keâe keâesCe
120o neslee
neslee nw~ Ssmes heoeLeeX keâes peye mece™he ÛegcyekeâerÙe #es$e ceW jKee peelee
nw~ jekeâJesue efJeefOe ceW Oeeleg keâe ne[&vesme Ûeskeâ keâjves kesâ efueS štue
nw, lees Jes MeefòeâMeeueer Ûegcyekeâ kesâ Éeje nukeâe mee Deekeâef<e&le nesles nQ~
kesâ hJeeFbš hej [eÙeceC[ keâe keâesve ueiee neslee nw~ Fmekesâ Éeje
Fve heoeLeeX keâes DevegÛegcyekeâerÙe heoeLe& keânles nw~ GoenjCe– huewefšvece,
mšerue keâer ne[&vesme Ûeskeâ keâer peeleer nw~
›eâesefceÙece, meesef[Ùece, heesšwefMeÙece, Dee@keämeerpeve, šQšsuece (Tantalum)
je@keâJesue ne[&vesme šsefmšbie ceMeerve keâe Fb[wšj [eÙeceC[ heoeLe& keâe
Deeefo~
yevee neslee nw, FmeceW oes Øekeâej kesâ mkesâue ØeÙeesie efkeâS peeles nQ~
79. What is meant by HVOF in metal coating?
(i) B–Scale; Fmes HRB keânles nQ~
Oeeleg uesheve ceW HVOF keâe keäÙee DeefYeØeeÙe nw?
(ii) C–Scale; Fmes HRC keânles nQ~
(a) High Velocity Oxidised Filler
82. Which of the following contains Citric acid?
neF& Jesuee@efmešer Dee@keämeer[eFp[ efheâuej
FvecesW mes efkeâmeceW efmeefš^keâ Decue ceewpeto neslee nw?
(b) High Viscous Oxidised Fluid
(a) Tamarind/Fceueer
neF& efJemkeâme Dee@keämeer[eFp[ heäuetF[
(b) Sour milk/Keóe otOe
(c) High Viscous Oxygen Fuel
(c) Orange/veejbieer
neF& efJemkeâme Dee@keämeerpeve heäÙetue
(d) Tomato/šceešj
(d) High Velocity Oxygen Fuel

Ans : (c) kegâÚ keâeye&efvekeâ Decue leLee Gvekesâ ßeesle–

neF& Jesuee@efmešer Dee@keämeerpeve heäÙetue

œeesle Decue
Ans : (d) HVOF : High Velocity Oxygen Fuel
GÛÛe Jesie Dee@keämeerpeve FËOeve (HVOF) keâesefšbie Skeâ Lece&ue mØes
keâesefšbieFceueer šeš&efjkeâ Decue
Øeef›eâÙee nw, efpemekeâe GheÙeesie efkeâmeer Ieškeâ keâer melen kesâ iegCeeW Ùee
Keóe otOe uewefkeäškeâ Decue
DeeÙeeceeW keâes megOeejves Ùee hegve&mLeeefhele keâjves kesâ efueS efkeâÙee peelee
nw~ šceešj Deekeämewefuekeâ Decue
Fme Øekeâej Ùen GhekeâjCe kesâ peerJeve keâes yeÌ{ekeâj Oeeleg, efceße Oeeleg Deewj
mebleje (veejbieer) efmeefš^keâ Decue
Ûeerveer efceóer keâer ÛeerpeW pewmes—keâesefšbie meece«eer kesâ GheÙeesie mes
meece«eer 83. What is the magnitude of the maximum
keâes DemeeOeejCe keâ"esjlee, Glke=â° Deemebpeve Deewj heÙee&hle efIemeeF&
disturbance in the medium on either side of the

mean value called?

ØeeflejesOe Deewj meb#eejCe ØeeflejesOe Øeoeve keâjves keâer Devegceefle oslee nw~
ceeOÙece kesâ ceeOÙe ceeve kesâ efkeâmeer Skeâ Deesj DeefOekeâlece
80. In BCD code, maximum possible characters set
efJe#eesYe kesâ heefjCeece keâes keäÙee keâne peelee nw?
size is–

(a) Frequency/DeeJe=efòe
BCD keâes[ ceW, DeefOekeâlece mebYeJe kewâjskeäšj mesš Deekeâej
(b) Oscillation/oesueve
............... neslee nw~

(c) Amplitude/DeeÙeece
(a) Character set of 94/94 kewâjskeäšj mesš

(d) Wavelength/lejbieowOÙe&
(b) Character set of 104/104 kewâjskeäšj mesš

Ans : (c) DeeÙeece– Ùen oesueve keâjles Skeâ efheC[ keâer ceeOÙe efmLeefle
(c) Character set of 84/84 kewâjskeäšj mesš

mes Skeâ Deesj DeefOekeâlece efJemLeeheve neslee nw~ OJeefve lejbieeW kesâ meeLe
Ùen
(d) Character set of 64/64 kewâjskeäšj mesš

nJee kesâ keâCeeW keâes lejbie mebÛejCe keâer efoMee ceW ceeOÙe efmLeefle mes Skeâ
Ans : (d) yeermeer[er (yeeFvejer keâes[s[ [smeerceue) ceW, DeefOekeâlece mebYeJe
Deesj DeefOekeâlece efJemLeeefhele keâjves keâer meercee nw~ Dele: ceeOÙece kesâ
ceOÙe
kewâjskeäšj mesš keâe Deekeâej 64 neslee nw~ Ùen oMeceueJe Debkeâ keâe kesâJeue
ceeve kesâ efkeâmeer Skeâ Deesj DeefOekeâlece efJe#eesYe kesâ heefjCeece keâes
DeeÙeece
4-efyeš yeeFvejer keâes[ keâes oMee&lee nw~ yeermeer[er keâes[ keâes Dekeämej keâne
peelee nw~
8421 keâne peelee nw keäÙeeWefkeâ yeermeer[er Skeâ Yeeefjle keâes[ neslee nw~

84. Communication between a computer and a

81. In Rockwell hardness testing method, the
keyboard involves .............. transmission.
hardness of a material is measured by–
keâchÙetšj Deewj keâeryees[& kesâ yeerÛe mebÛeejCe ceW ..............
je@keâJesue keâ"esjlee hejer#eCe efJeefOe ceW meece«eer keâer keâ"esjlee
š^ebmeefceMeve Meeefceue neslee nw~
............... Éeje ceeheer peeleer nw~
(a) Simplex/efmebhueskeäme
(a) Material failure/meece«eer keâer efJeheâuelee
(b) Full–duplex/hegâue [ghueskeäme
(b) Depth of indentation/efveMeeve keâer ienjeF&
(c) Automatic/mJeÛeeefuele
(c) Elongation of material/meece«eer keâe oerIeeakeâjCe
(d) Half–duplex/neheâ [ghueskeäme
(d) Surface roughness/melen keâe Kegjojeheve
Ans : (a) efmechueskeäme (Simplex) š^ebmeefceMeve Skeâ Øekeâej keâe
Ans : (b)
š^ebmeefceMeve cees[ nw~ Fme Øekeâej kesâ š^ebmeefceMeve cees[ ceW [sše keâes
je@keâJesue keâ"esjlee hejer#eCe efJeefOe ceW meece«eer keâer keâ"esjlee
efveMeeve kesâJeue Skeâ efoMee kesâ ceeOÙece mes Yespee pee mekeâlee nw~ pewmes-
keâer ienjeF& Éeje ceeheer peeleer nw~
ueeG[mheerkeâj, šsueerefJepeve ØemeejCe, keâeryees[& Deewj cee@veeršj Deeefo nw~
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85. The angle between the resultant reaction and
(a) Pascal's law/heemkeâue kesâ efveÙece
normal to the plane on which the motion of
(b) Charle's law/Ûeeume& kesâ efveÙece
body is impending is known as–

(c) Newton's law/vÙetšve kesâ efveÙece

heefjCeeceer Øeefleef›eâÙee Deewj Gme leue kesâ DeefYeuebye kesâ yeerÛe
keâe keâesCe, efpeme hej efheb[ ieefle keâjlee nw, keäÙee keânueelee
(d) Boyle's law/yee@Ùeue kesâ efveÙece
nw? Ans :
(a) neF[^esefuekeâ Øesme heemkeâue kesâ efmeæeble hej keâeÙe& keâjlee nw~
(a) Angle of limiting friction/meerceeble Ie<e&Ce keâesCe
heemkeâue keâe efveÙece (Pascals law)– Fme efveÙece kesâ Devegmeej keâesF&
(b) Angle of repose/efJeßeebefle keâesCe Yeer
lejue efJejeceeJemLee ceW meYeer efoMeeDeeW ceW meceeve oeye ueieelee nw~
(c) Angle of friction/Ie<e&Ce keâesCe
P1 = P2 = P3
(d) Angle of zenith/pesefveLe keâe keâesCe
FmeefueS õJe kesâ Devoj efkeâmeer Jemleg hej oeye leer›elee meYeer efoMeeDeeW ceW
Ans : (a)
meceeve neslee nw~ heemkeâue efveÙece keâe GheÙeesie efJeefYeVe õJe Ûeeefuele

ceMeerveeW pewmes õefJekeâ Øesme, efjJesškeâ pewkeâ, efueheäš leLee ›esâve Deeefo
ceW

neslee nw~

88. Grain size range between 90 and 220 is

considered as–

90 mes 220 kesâ yeerÛe kesâ «esve kesâ Deekeâej keâes ............

ceevee peelee nw~

(a) Fine grain/cenerve «esve

(b) Normal grain/meeceevÙe «esve

(c) Very fine grain/yengle cenerve «esve

(d) Coarse grain/ceesšs «esve

peneB, R' · heefjCeeceer Øeefleef›eâÙee, RN · DeefYeuebye Øeefleef›eâÙee, φ = Ans :
(a) 90 mes 220 kesâ yeerÛe kesâ «esve (grains) kesâ Deekeâej keâes
meerceevle Ie<e&Ce keâesCe (Angle of limiting friction)
cenerve «esve (fine grain) ceevee peelee nw~
meecÙeeJemLee ceW efheC[ hej leerve yeue keâeÙe&jle nesles nQ—
«esve meeFpe ue#eCe
(i) efheC[ keâe Yeej (W)
10–24 – Coarse grain for
(ii) #eweflepe ueieeÙee ieÙee yeue (P)
roughening

30–60 – Medium grain

(iii) efheC[ A leLee huesve B keâe øeefleef›eâÙee (Reaction)

70–180 – Fine grain for

heefjCeeceer Øeefleef›eâÙee Deewj Gme leue kesâ DeefYeuecye kesâ yeerÛe keâe
keâesCe, finishing
efpeme hej efheC[ ieefle keâjlee nw meerceevle Ie<e&Ce keâesCe keânueelee nw~
220–600 – Very fine grain for
86. Water decomposes in presence of electricity
superfinishing
into H2 and O2, this process is called– 89.
Which of the following processes uses non–
efJeÅegle keâer GheefmLeefle ceW peue kesâ H2 Deewj O2 ceW
consumable electrode?
DeheIešve keâer DeefYeef›eâÙee keâes keäÙee keâne peelee nw?
efvecveefueefKele ceW mes efkeâme Øeef›eâÙee ceW iewj–GheYeespÙe
(a) Displacement Reaction/efJemLeeheve DeefYeef›eâÙee
Fueskeäš^es[ keâe GheÙeesie efkeâÙee peelee nw?
(b) Electrolysis/efJeÅegle DeheIešve
(a) TIG welding/TIG Jesefu[bie
(c) Photochemical decomposition
(b) MIG welding/MIG Jesefu[bie
ØekeâeMe–jemeeÙeefvekeâ DeheIešve
(c) Laser welding/uespej Jesefu[bie
(d) Thermal decomposition/leeheerÙe DeheIešve
(d) Electroslag welding/Fueskeäš^es–muewie Jesefu[bie
Ans : (b) peye peue mes neskeâj efJeÅegle Oeeje ØeJeeefnle keâer peeleer nw lees
Ans : (a) TIG Jesefu[bie ceW iewj–GheYeespÙe Fueskeäš^es[ (Non-
peue kesâ DeCegDeeW keâe efJeIešve nes peelee nw Deewj Dee@keämeerpeve SJeb
consumable electrode) keâe GheÙeesie efkeâÙee peelee nw~
neF[^espeve Øeehle nesleer nw, Fmes ner peue keâe efJeÅegle DeheIešve
TIG Jesefu[bie ceW ØeÙeesie efkeâS peeves Jeeues Fueskeäš^es[ keâe keâesj Oeeleg
(Electrolysis) keânles nQ~
šbiemšve neslee nw~ FmeceW 1–2³ LeesefjÙece Dee@keämeeF[ efcekeäme
2H 2 O ( ℓ ) 
Electrolysis
→ 2H 2 ( g ) + O 2 ( g )
(Mixed) efkeâÙee peelee nw~

87. A hydraulic press is based on the principle of–

Megæ šbiemšve Fueskeäš^es[ Less current carry keâjlee nw~

neF[^esefuekeâ Øesme ................. kesâ efmeæeble hej DeeOeeefjle
TIG Jesefu[bie ceW efveÙele Oeeje Øekeâej (constant current type)
nw~
keâe heeJej meesme& ØeÙeesie efkeâÙee peelee nw~
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90. India's first National Centre for Marine Bio– Ans : (b) yeueÙegice
(Couple) ceW keâeÙe&jle yeueeW kesâ yeerÛe
Skeâ
diversity (NCMB) is located in– heefjefcele Ûej otjer (A
finite variable distance) nesleer nw~
Yeejle keâe henuee je°^erÙe mecegõer pewJe–efJeefJeOelee kesâvõ

oes yejeyej Deewj efJehejerle efoMee ceW yeue, efpevekeâer ef›eâÙee jsKeeSB
(NCMB) keâneB efmLele nw?

meceveeblej nes, Skeâ yeueÙegice yeveeles nQ~

(a) Mumbai/cegcyeF& (b) Puducherry/heg[gÛesjer

yeueÙegice kesâ yeueeW keâer ef›eâÙee jsKeeDeeW kesâ yeerÛe keâer vÙetvelece otjer
(c) Bhavnagar/YeeJeveiej (d) Jamnagar/peeceveiej
keâes yeueÙegice keâer Yegpee keânles nQ~
Ans : (d) Yeejle keâe henuee je°^erÙe mecegõer pewJe-efJeefJeOelee kesâvõ
Ùeefo yeueÙegice kesâ Skeâ yeue keâes yeueÙegice keâer Yegpee keâer uecyeeF& mes
iegpejele kesâ peeceveiej efpeues ceW keâÛÚ keâer KeeÌ[er ceW efmLele nw~
iegCee efkeâÙee peeS lees Øeehle iegCeveheâue keâes yeueÙegice keâe DeeIetCe&
91. The electron distribution in a magnesium atom
keânles nQ~
is–

95. Which of the following phase is obtained as the

cewiveerefMeÙece hejceeCeg ceW Fueskeäš^e@veeW keâe
efJelejCe ............. end product, after complete heat treatment
neslee nw~
cycle in austempering process?
(a) 8, 2, 2 (b) 2, 8, 3
Dee@mšscheefjbie Øeef›eâÙee ceW T<ceerÙe GheÛeej Ûe›eâ kesâ hetCe&
(c) 2, 8, 2 (d) 8, 2, 3
nesves kesâ yeeo Debeflece Glheeo kesâ ™he ceW FveceW mes keâewve meer
Ans : (c) cewiveerefMeÙece hejceeCeg ceW Fueskeäš^e@veeW keâe efJelejCe 2,8,2
DeJemLee Øeehle nesleer nw?
neslee nw~ Fmes Mg mes ØeoefMe&le efkeâÙee peelee nw~ Fmekeâer hejceeCeg mebKÙee
(a) Pearlite/efheÙejueeFš (b) Bainite/yewveeFš
12 SJeb meeceevÙe Dee@keämeer[sMeve mebKÙee +2 nw~
(c) Martensite/ceešxmeeFš (d) Austenite/Dee@mšsveeFš
92. Which of the following is a disadvantage of Ans : (b) Dee@mšscheefjbie
Øeesmesme ceW mšerue keâes ueieYeie 700oC hej
most of the renewable energy sources?
FveceW mes keâewve mee vegkeâmeeve DeefOekeâebMe De#eÙe Tpee& iece&
efkeâÙee peelee nw~ Fmeer leehe›eâce hej mšerue keâes kegâÚ meceÙe kesâ efueS

Yeªer ceW Úes[Ì efoÙee peelee nw~ Fmekesâ heMÛeele Oeeleg KeC[ keâes meeuš
œeesleeW ceW ceewpeto neslee nw?

yeeLe Yeªer ceW ueieYeie 500oC lekeâ "b[e efkeâÙee peelee nw Deewj efheâj
(a) Unreliable supply/DeefJeMJemeveerÙe Deehetefle&

keâeheâer meceÙe kesâ efueS ÚesÌ[ efoÙee peelee nw~ Fmemes yewveeFš keâer Glheefòe
(b) High running cost/GÛÛe heefjÛeeueve ueeiele
nesleer nw~ Devle ceW mšerue kesâ KeC[ keâes heeveer ceW keâcejs kesâ leeheceeve
lekeâ
(c) Highly polluting/DelÙeefOekeâ Øeot<eCe
Meerleueve keâjles nQ~ Deemešscheefjbie ef›eâÙee mes keâ"esj mšerue keâer
keâ"esjlee
(d) High waste disposal cost
ceW keâesF& keâceer veneR Deeleer nw, hejbleg ojejW meceehle nes peeleer nw~ mšerue
GÛÛe DeheefMe° efveheševe ueeiele
DeefOekeâ levÙe SJeb ÛeerceÌ[heve Ùegòeâ nes peeleer nw~
Ans : (a) DeefJeÕemeveerÙe Deehetefle& (Unreliable supply) keâe 96. What is the
value of the acceleration due to
vegkeâmeeve DeefOekeâebMe De#eÙe Tpee& œeesleeW ceWs ceewpeto neslee nw~
gravity (g) of Earth?
De#eÙe Tpee& Ùee veJeerkeâjCeerÙe Tpee& ceW Jes Tpee& Meeefceue nw pees
he=LJeer kesâ ieg™lJeerÙe lJejCe (g) keâe ceeve efkeâlevee nesiee?
Øeot<eCekeâejkeâ veneR nw leLee efpevekesâ œeesle keâe #eÙe veneR neslee, Ùee
(a) 5.4 m s–2 (b) 9.8 m s–2
efpevekesâ œeesle keâe hegve:-YejCe neslee jnlee nw, pewmes- meewj Tpee&, heJeve
(c) 3.8 m s –2

(d) 6.8 m s–2

Tpee&, peue efJeÅegle Tpee& Deeefo~
Ans : (b) he=LJeer kesâ ieg®lJeerÙe lJejCe (g) keâe ceeve 9.81 ms–2 neslee
93. Free of cost repair of software bug available at nw~ Fmekeâe efJeceerÙe met$e
[M L T ] neslee nw~

0 1 –2

Internet is called–
97. Which of the following is India's first Arctic
Fbšjvesš hej GheueyOe mee@heäšJesÙej yeie keâer efve:Megukeâ
research station?
cejccele keâes ................ keâne peelee nw~
efvecveefueefKele ceW mes keâewve mee Yeejle keâe henuee Deeke&âefškeâ
(a) Version/Jepe&ve (b) Patch/hewÛe
efjmeÛe& mšsMeve nw?
(c) Tutorial/šdÙetšesefjÙeue (d) Ad–on/S[-Dee@ve
(a) Bharati/Yeejleer
Ans : (b) Fbšjvesš hej GheueyOe mee@heäšJesÙej yeie keâer efve:Megukeâ
(b) Maitri/cew$eer
cejccele keâes hewÛe (Patch) keâne peelee nw~
(c) Himadri/efnceeõer
94. The distance between the forces acting in the
(d) Dakshin Gangotri/oef#eCe iebiees$eer
couple is– Ans :
(c) ‘efnceeõer’ Yeejle keâe henuee Deeke&âefškeâ efjmeÛe& mšsMeve nw pees
yeueÙegice ceW keâeÙe&jle yeueeW kesâ yeerÛe keâer otjer efkeâleveer
efmhešdmeyeiexve, mJeeueyee[& (veeJex) ceW efmLele nw~ Ùen mšsMeve vesMeveue
nesleer nw? meWšj
heâe@j Debšeke&âefškeâ Sb[ DeesMeve efjmeÛe& Éeje mebÛeeefuele nw~ Fme
(a) Always a fixed distance/ncesMee Skeâ efveefMÛele otjer
mšsMeve keâe GodIeešve 1 ceF& Je<e& 2008 ceW efJe%eeve Deewj ØeewÅeeseif ekeâer
(b) A finite variable distance/Skeâ heefjefcele Ûej otjer
ceb$eer keâefheue efmeyyeue ves efkeâÙee Lee~ peyeefkeâ cew$eer, Yeejleer SJeb
oef#eCe
(c) Zero/MetvÙe
iebiees$eer Debšeke&âefškeâe OeÇgJe hej efmLele Yeejle kesâ mLeeÙeer DevegmebOeeve
yesme
(d) Infinity/Devevle
mšsMeve nw~
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98. A cutting tool can never have its–
GoenjCe–
keâle&ve Deewpeej keâe ................ keâYeer veneR nes
mekeâlee nw~ (i) je@kesâš keâe Deeies yeÌ{vee~
(a) Clearance angle – negative
(ii) TBÛeeF& mes ketâoves hej Ûeesš ueievee~
efkeäueÙejWme keâesCe – $e+Ceelcekeâ
(iii) yebotkeâ mes ieesueer ÚesÌ[les meceÙe heerÚs keâer Deesj Peškeâe ueievee~

(iv) veeJe Kesves kesâ efueS yeeBme mes peceerve keâes oyeevee~
(b) Rake angle – positive/jskeâ keâesCe – Oeveelcekeâ
(c) Clearance angle – positive
101. The ratio of actual discharge of a jet of water

to its theoretical discharge is known as–

efkeäueÙejWme keâesCe – Oeveelcekeâ
Skeâ peue Oeeje kesâ JeemleefJekeâ efvemmeej keâe Fmekesâ
(d) Rake angle – negative/jskeâ keâesCe – $e+Ceelcekeâ
mewæebeflekeâ efvemmeej mes Devegheele, .............. keânueelee nw~
Ans : (a) keâle&ve Deewpeej (Cutting tool) keâe efkeäueÙejWme keâesCe
(a) Coefficient of velocity/Jesie iegCeebkeâ
$e+Ceelcekeâ keâYeer veneR nes mekeâlee nw~ keâešles meceÙe Deewpeej keâer
heäueQkeâ (b) Coefficient of contraction/mebkegâÛeve iegCeebkeâ
melen keâeÙe& KeC[ hej jieÌ[ ve KeeÙes, FmeefueS Ùen keâesCe Øeoeve keâer
(c) Coefficient of discharge/efvemmejCe iegCeebkeâ
peeleer nw~
(d) Coefficient of viscosity/MÙeevelee iegCeebkeâ
• meeOeejCele: DeJekeâeMe keâesCe 5 mes 12 lekeâ jKee peelee nw~
o o
Ans : (c) JeemleefJekeâ efJemepe&ve leLee mewæeefvlekeâ efJemepe&ve kesâ Devegheele
• meeceevÙele: keâ"esj heoeLeeX keâes keâešves kesâ efueS DeJekeâeMe keâesCe keâe
keâes efJemepe&ve iegCeebkeâ keânles nQ~ Fmes Cd Éeje ØeoefMe&le keâjles nQ~
ceeve keâce leLee ce=og heoeLeeX kesâ efueS DeefOekeâ jKee peelee nw~
JeemleefJekeâ efJemepe&ve

efJemepe&ve iegCeebkeâ (Cd) =

• $e+Ceelcekeâ jskeâ keâesCe meeceevÙele: 2o mes 10o lekeâ ØeÙeesie efkeâS peeles
mewæebeflekeâ efJemepe&ve

Q
nQ~
Cd =

a 2gh
99. The Stockholm Convention on Persistent
Organic Pollutants (POPs) was signed in the
Cd keâe ceeve meeOeejCele: 0.61 mes 0.64 kesâ yeerÛe neslee nw~
year– 102.
Cyaniding is carried out at a temperature of
mLeeÙeer keâeye&efvekeâ Øeot<ekeâeW (POP) hej mše@keânesce
..........

meeFveeFef[bie .................. leeheceeve hej keâer peeleer nw~

keâvJeWMeve hej Je<e& .............. ceW nmlee#ej efkeâS ieS Les~

(a) 300oC (b) 500oC

(a) 1998 (b) 2001
(c) 950 C o
(d) 175oC
(c) 1999 (d) 2000
Ans :
(c) meeFveeFef[bie melen keâ"esjlee keâer Skeâ efJeefOe nw~ FmeceW Oeeleg
Ans : (b) mLeeÙeer keâeye&efvekeâ Øeot<ekeâeW (POP) hej mše@keânesce KeC[ keâer yee
¢e melen keâes keâeye&ve leLee veeFš^espeve oesveeW ner Éeje meble=hle
keâevJeWMeve (mJeer[ve) hej Je<e& 2001 ceW nmlee#ej efkeâÙes ieÙes leLee Ùen
efkeâÙee peelee nw~ FmeceW Oeeleg KeC[ keâer Yeerlejer melen ce=og leLee levÙe
2004 ceW ØeYeeJeer nes ieÙee~ Deewj
meeLe–meeLe šheâ Yeer yeveer jnleer nw~ Fme efJeefOe mes hetCe& melen Ùee
100. Action and reaction act on–
Gmekeâe kegâÚ Yeeie keâ"esj efkeâÙee pee mekeâlee nw~ Fme mebef›eâÙee ceW mšerue
ef›eâÙee Deewj Øeefleef›eâÙee ................. ceW ueeiet nesleer
nw~ kesâ Oeeleg Keb[ keâes efveef<›eâÙe efheIeues ueJeCeeW Na2
CO2, Nacl Deeefo kesâ

meeLe meeÙeveeF[ Ùeewefiekeâ Ca(CN)2, NaCN Deeefo keâes Ieesuekeâj

(a) Different bodies but in same direction

850oC–950oC leehe›eâce lekeâ iece& efkeâÙee peelee nw~ iece& keâjves keâer
Deueie–Deueie efheC[eW hej, efkeâvleg meceeve efoMee

DeJeefOe 5 min mes 90 min lekeâ jnleer nw~

(b) Same body but in opposite direction

• Ùes Øeef›eâÙeeSB pÙeeoelej Dee@šesceesyeeFume heešex hej keâer peeleer nw~

Skeâ ner efheC[ hej, efkeâvleg efJehejerle efoMee
veesš:-keâeyeg&jeFefpebie, veeFš^eFef[bie SJeb meeÙeveeFef[bie efvecve Je ceOÙece
(c) Same body and in same direction
keâeye&ve mšerue kesâ efueS leLee FC[keäMeve ne[xefvebie Heäuesce ne[xefvebie GÛÛe
Skeâ ner efheC[ hej Deewj meceeve efoMee
keâeye&ve mšerue kesâ efueS ØeÙegòeâ nesles nQ~
(d) Different bodies but in opposite direction
103. A stream line and an equipotential line in a two
Deueie–Deueie efheC[eW hej, efkeâvleg efJehejerle efoMee
dimensional inviscid flow field–
Ans : (d) ef›eâÙee Deewj Øeefleef›eâÙee Deueie-Deueie efheC[eW hej efkeâvleg
oes efJeceerÙe DeMÙeeve ØeJeen #es$e ceW Skeâ mš^erce ueeFve Deewj
efJehejerle efoMee ceW ueeiet nesleer nw~
Skeâ FkeäJeerheesšWefMeÙeue ueeFve–
vÙetšve kesâ ieefle kesâ le=leerÙe efveÙece keâes ef›eâÙee-Øeefleef›eâÙee keâe
efveÙece keânles (a) Are identical/mece™he nesleer nQ

(b) Are parallel to each other

nw~ Fme efveÙece kesâ Devegmeej ØelÙeskeâ ef›eâÙee kesâ yejeyej hejvleg efJehejerle

Skeâ otmejs kesâ meceeveeblej nesleer nQ

efoMee ceW Øeefleef›eâÙee nesleer nw~ DeLee&led oes JemlegDeeW keâer heejmheefjkeâ
ef›eâÙee

(c) Are perpendicular to each other

ceW Skeâ Jemleg otmejer Jemleg hej efpelevee yeue ueieeleer nw, otmejer Jemleg Yeer
Skeâ–otmejs kesâ uebyeJele nesleer nw
efJehejerle efoMee ceW Glevee ner yeue henueer Jemleg hej ueieeleer nw~ FmeceW
(d) Intersect at an acute angle
Skeâ yeue keâes ef›eâÙee Je otmejs keâes Øeefleef›eâÙee yeue keânles nw~
Skeâ vÙetve keâesCe hej ØeefleÛÚsefole keâjleer nQ
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Ans : (c) oes efJeceerÙe DeMÙeeve (inviscid) ØeJeen #es$e ceW Skeâ mš^erce
(a) Form turning/heâe@ce&

šefveËie
ueeFve Deewj Skeâ FkeäJeerheesšWefMeÙeue ueeFve Skeâ otmejs kesâ uecyeJele nesleer
(b) Contour
turning/kebâštj šefveËie
nw~ (c)
Facing/hesâefmebie
Equipotential Line– A line along which the velocity
(d) Taper
turning/šshej šefveËie
potential φ is constant is called equipotential line.
FkeäJeerheesšWefMeÙeue ueeFve kesâ efueS Ans : (b) kebâštj šefveËie
heefjÛeeueve ceW štue keâes meerOes ceeie& ceW heâer[ veneR
φ = efveÙeleebkeâ efkeâÙee peelee nw~ kebâštj
šefveËie kesâ efueS Deewpeej keâer keâšeF& keâesj keâes
φ = f(x,y) GheÙegòeâ Deeke=âefle leLee
™he keâe yeveeÙee peelee nw~ Fme Øekeâej efJeefYeVe
∂φ ∂φ ef›eâÙeeDeeW kesâ efueS
Deewpeej keâer efJeefYeVe Deeke=âefleÙeeB ØeÙeesie keâer peeleer nQ~
dφ = dx + dy
∂x ∂y Úesšer uecyeeF& kesâ šshej
osves kesâ efueS kebâštj šefveËie meJeexòece neslee nw~ kebâštj
FkeäJeerheesšWefMeÙeue ueeFve kesâ efueS štue mes šsheefjbie keâjles
meceÙe kewâefjpe keâes uee@keâ keâj efoÙee peelee nw~
dy −u
106. Which of the following varnishes are prepared
=
dx v
by dissolving hardest gums like copal in drying
dy
oil and volatile solvents?
= FkeäJeerheesšWefMeÙeue ueeFve keâer ØeJeCelee
dx
FveceW mes keâewve meer JeeefveËMe, jeue pewmes keâ"esj ieeo keâes
−u
lesue Deewj Jee<heMeerue efJeueeÙekeâeW ceW Ieesuekeâj lewÙeej keâer
m1 =
v
peeleer nw?
mš^erce ueeFve kesâ efueS,
(a) Oil varnish/lesue Jeeefve&Me
dy v
=
(b) Turpentine varnish/leejheerve Jeeefve&Me
dx u

(c) Water varnish/peue Jeeefve&Me

v
m2 =
(d) Spirit varnish/efmheefjš Jeeefve&Me
u
oesveeW ØeJeCeleeDeeW keâe iegCeveHeâue · m1 × m2
Ans : (a) lesue Jeeefve&Me, je@ue (Copal) pewmes keâ"esj ieeo keâes lesue
−u v
Deewj Jee<heMeerue efJeueeÙekeâeW ceW Ieesuekeâj lewÙeej keâer peeleer nw~
= ×
v u
Jeeef ve&Me (Varnish)–Jeeefve&Me, jsefpeve Ùee jsepf eve leLee Mees<ekeâ lesue
= –1
(Drying oil) keâe Jee<heMeerue efJeueeÙekeâ ceW Ieesue nw~ kesâJeue jsefpeve
oesveeW ØeJeCeleeDeeW keâe iegCeveHeâue –1 nw Dele: oesveeW ueeFveW Skeâ-otmejs
kesâ Éeje yeveer Jeeefve&Me keâes efmØeš Jeeefve&Me keânles nw~ jsefpeve leLee
lesue mes
uecyeJele nQ~
yeveer Jeeefve&Me keâes DeesefueÙeesjsefpeveme Jeeefve&Me keânles nw~ Fmekeâe
ØeÙeesie
104. Who among the following released the book melen keâes DeefOekeâ megvoj,
Ûecekeâerueer leLee megjef#ele yeveeves kesâ efueS
'Mann Ki Baat – A Social Revolution on Radio'
in 2019?

efkeâÙee peelee nw~

efvecveefueefKele ceW mes efkeâmeves 2019 ceW ‘ceve keâer yeele – S
107. ................ is a process for placing a thin
meesMeue efjJee@uÙetMeve Dee@ve jsef[Ùees’ hegmlekeâ keâe efJeceesÛeve
phosphate coating on steel.
efkeâÙee?
................ mšerue hej heleueer heâe@mhesâš keâesefšbie ÛeÌ{eves
(a) Arun Jaitley/De®Ce pesšueer
keâer Øeef›eâÙee nw~
(b) Rajnath Singh/jepeveeLe efmebn
(a) Anodizing/Svees[eFefpebie
(c) Narendra Modi/vejsvõ ceesoer
(b) Galvanization/iewuJesveeFpesMeve
(d) Manmohan Singh/ceveceesnve efmebn
(c) Parkerizing/heeke&âjeFefpebie
Ans : (a) veF& efouueer ceW efJeòe ceb$eer De®Ce pesšueer Éeje ‘ceve keâer
(d) Sheradizing/Mesj[e&Fefpebie
yeele-S meesMeue efjJee@uÙetMeve Dee@ve jsef[Ùees’ veecekeâ hegmlekeâ keâe Ans :
(c) mšerue hej heleueer heâe@mhesâš keâer hejle ÛeÌ{eves keâes heâemhesâš
efJeceesÛeve efkeâÙee ieÙee~ Ùen hegmlekeâ ØeOeeveceb$eer vejsvõ ceesoer Éeje ‘ceve
uesheve Ùee heeke&âjerkeâjCe (Phosphate coating or Parkerizing)
keâer yeele’ keâeÙe&›eâce ceW 50JeW mebmkeâjCeeW keâes Meeefceue keâjles ngS Skeâ

keânles nQ~ Fmeer Øekeâej mšerue keâer huesš hej efšve uesheve keâes
mebkeâueve nw~

iewuJesveerkeâjCe (Galvanizing) keânles nQ~ lehle efveceppeve DeeOeej

105. In which of the following operation of lathe
machine is the tool NOT fed in a straight path?

OeelegDeeW hej meb#eejCe ØeeflejesOeer OeelegDeeW keâe ueshe ÛeÌ{eves keâer Skeâ
õgle Je
uesLe ceMeerve kesâ FveceW mes efkeâme heefjÛeeueve ceW štue keâes
memleer efJeefOe nw~ efpemekeâe efJemle=le GheÙeesie ueesns leLee Fmheele hej
pemles
meerOes ceeie& ceW heâer[ veneR efkeâÙee peelee nw?
keâer hejle ÛeÌ{eves kesâ efueS efkeâÙee peelee nw~
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 heâemhesâš uesheve keâe JÙeehekeâ GheÙeesie DeešesceesefšJe leLee efJeÅegle
(a) Tempering/šscheefjbie
GhekeâjCe GÅeesieeW ceW efveefce&le DeešesceesyeeFume, keâheÌ[e Oeesves Jeeueer
(b) Annealing/Deveerefuebie
ceMeerveeW ceW ØeÙeesie neslee nw~
(c) Austempering/DeemheWheefjbie
heâemhesâš uesheve keâer heeke&âjerkeâjCe veecekeâ efJeefOe Éeje 0.0038 mm
(d) Marquenching/ceekeäJeXefÛebie
mes 0.0075 mm ceesšeF& keâe ßes‰ meb#eejCe jesOeer he=‰ 45 min Ans : (d)
ceekeäJeXefÛebie Øeef›eâÙee hegpex ceW efkeâmeer Yeer ojej Ùee efJeke=âefle kesâ
ceW Øeehle nes peelee nw~
efyevee, Gmekeâer DevegØemLe keâeš kesâ ÛeejeW Deesj ceewpeto DeemšsveeFš keâes
108. Nixan Gold Cup is associated with which ceešxvemeeFš ceW yeoueves keâer
Devegceefle oslee nw~
sport?
• mšerue ceW ›eâebeflekeâ leeheceeve kesâ Thej iece& keâjves hej Skeâ efveefMÛele
efvekeämeeve ieesu[ keâhe efkeâme Kesue mes mebyebefOele nw?
meceÙe kesâ efueS ÚesÌ[e peelee nw efpememes mesefkebâie hetCe& ™he mes nes mekesâ~
(a) Basketball/yeemkesâšyee@ue
Fmekesâ heMÛeele Oeeleg KeC[ keâes heeveer, lesue Ùee yeÇeFve Ieesue ceW yegPeeÙee
(b) Badminton/yew[efcebšve
peelee nw~ efpememes Oeeleg keâ"esj nes peeleer nw~ Fme Øekeâej peye Oeeleg KeC[
(c) Football/hegâšyee@ue
keâes ›eâeefvlekeâ leeheceeve mes Thej iece& keâjles nQ, lees mšerue keâer cetue
(d) Volleyball/Jee@ueeryee@ue
mebjÛevee DeemšsveeFš ceW ™heevleefjle nes peeleer nw pees heeveer ceW yegPeeves
hej
Ans : (c) efJeefYeVe Kesue leLee Gvemes mecyebefOele ØecegKe keâhe SJeb

hegve: ceešxvemeeFš ceW heefjJeefle&le nes peeleer nw~

š^e@efheâÙeeB-
111. ..................... is a group of fine holes on the

surface of the weld caused by gas entrapment.

Kesue mebyebefOele keâhe SJeb š^e@efheâÙeeB
............. iewme ve efvekeâue heeves kesâ keâejCe Jesu[ keâer melen
hegâšyee@ue efvekeämeeve ieesu[ keâhe, [tjC[ keâhe,
hej yeveves Jeeues yeejerkeâ efÚõ keâe Skeâ mecetn nw~
ce[xkeâe keâhe Deeefo

(a) Gas pocket/iewme hee@kesâš

yew[efcebšve veejbie keâhe, Ûeºe keâhe
(b) Porosity/mejbOeÇlee
yeemkesâšyeeue vesn™ keâhe, hesâ[jsMeve keâhe
(c) Blow holes/yuees nesue
ieesuheâ Jeekeâj keâhe, meefke&âš keâhe
(d) Crack/›ewâkeâ
109. Which part of the box type solar cooker is

Ans : (b) Jewefu[bie Øeef›eâÙee ceW peye efheâuej cewšue efheIeueleer nw lees Jen
responsible for producing the greenhouse effect
of trapping maximum heat from light rays?
Deheves Devoj iewmeeW keâes meesKe uesleer nw Deewj peye Ùen Oeeleg "C[er nesleer
yee@keäme Øekeâej kesâ meesuej kegâkeâj keâe keâewve mee Yeeie ØekeâeMe
nw lees Ùes iewmes yeenj efvekeâueves keâer keâesefMeMe keâjleer nw~ Fve iewmeeW
kesâ
efkeâjCeeW keâer DeefOekeâlece T<cee kesâ Øe«enCe Éeje «eerveneGme
yeenj efvekeâueves mes Oeeleg keâer Deevleefjkeâ mebjÛevee ceW mejbOeÇlee Dee
peeles nQ~
 ØeYeeJe GlheVe keâjlee nw?
mejbOeÇlee (Porosity) kesâ keâejCe–
(a) Utensils placed inside the box
(i) efJeÅegle Oeeje keâe DeefOekeâ nesvee
yee@keäme kesâ Deboj jKes yeS yele&ve
(ii) DevegefÛele Jewefu[bie lekeâveerkeâer keâe ØeÙeesie
(b) Plane mirror reflector/meceleue ohe&Ce hejeJele&keâ
(iii) mener efheâuej je@[ keâe ØeÙeesie ve nesvee~
(c) Glass sheet cover/MeerMes keâe DeeJejCe
(iv) Deeke&â DeeJeMÙekeâlee mes DeefOekeâ yeÌ[e nesvee~
(d) Black coating inside the box
112. Who won the Orange Cap for scoring highest

runs in the IPL 2019?

yee@keäme kesâ Deboj keâer keâeueer keâesefšbie

IPL 2019 ceW meJee&efOekeâ jve yeveeves kesâ efueS efkeâmeves

Ans : (c) yee@keäme Øekeâej kesâ meesuej kegâkeâj ceW keâebÛe keâer Meerš keâe

Dee@jWpe kewâhe peerlee?

DeeJejCe kegâkeâj kesâ Devoj kesâ leeheceeve keâes yeveeS jKeves ceW ceoo keâjlee

(a) Rohit Sharma/jesefnle Mecee&

nw~ keâebÛe keâer Meerš metÙe& kesâ ØekeâeMe kesâ Lece&ue efJeefkeâjCe keâes
yee@keäme mes

(b) David Warner/[sefJe[ Jeeve&j

yeenj peeves mes jeskeâleer nw, efpememes yee@keäme kesâ Deboj «eerve neGme ØeYeeJe

(c) Quinton de Kock/efkeäJebšve [er keâe@keâ

GlheVe neslee nw~

(d) Chris Gayle/ef›eâme iesue

110. Which of the following processes permits the
transformation of austenite to martensite, Ans : (b) IPL 2019 ceW
meJee&efOekeâ jve (692) yeveeves Jeeues [sefJe[
throughout the cross–section of a component Jeeve&j ves Dee@jWpe keâwhe
peerlee Lee~ peyeefkeâ 2021 ceW meJee&efOekeâ jve yeveeves
without cracking or distortion? Jeeues $e+legjepe
ieeÙekeâJeeÌ[ (627) ves Dee@jWpe keâwhe peerlee~
efvecveefueefKele ceW mes keâewve meer Øeef›eâÙee hegpex ceW efkeâmeer
Yeer 113. Gun metal contains 2 percent of–
ojej Ùee efJeke=âefle kesâ efyevee, Gmekeâer DevegØemLe keâeš kesâ
ieve cesšue ceW 2 ØeefleMele ............... efceuee neslee nw~
ÛeejeW Deesj ceewpeto Dee@mšsveeFš keâes ceešxvemeeFš ceW yeoueves
(a) Tin/efšve (b) Zinc/pemlee
keâer Devegceefle osleer nw?
(c) Copper/leebyee (d) Nickel/efvekeâue
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Ans : (b) ieve cesšue (Gun Metal) leeByee, efšve leLee pemles keâe Ans : (b)
ØecegKe Yeeweflekeâ jeefMeÙeeW kesâ cee$ekeâ Je
Gvekesâ efJeceerÙe met$e–
SueeÙe nw~ FmeceW 88³ leeByee (Copper), 10% efšve leLee 2³ pemlee Yeeweflekeâ
jeefMe cee$ekeâ
efJeceerÙe met$e
nesles nQ~ Ùen keâ"esj, cepeyetle leLee meb#eejCe jesOeer neslee nw~ Fmekeâe

peÌ[lJe DeeIetCe& ef›eâ«ee./ceer2 ML2

GheÙeesie cegKÙele: yegMe yesÙeefjbie, JeeuJe, {ueeF&ÙeeB Deeefo yeveeves ceW
neslee
nw~
ieghle T<cee petue/efkeâ«ee. L2T–2

114. Paramparagat Krishi Vikas Yojana was ÛegcyekeâerÙe heäuekeäme

Jesyej ML2T–2 A–1
launched in April, 2015 to support and keâeÙe&
petue Ùee vÙetšve-ceeršj ML2T–2
promote–
efkeâmekeâes meceLe&ve Deewj yeÌ{eJee osves kesâ efueS DeØewue 2015 he=‰
leveeJe vÙetšve/ceer–2 MT–2

ceW hejchejeiele ke=âef<e efJekeâeme Ùeespevee keâes Meg™ efkeâÙee

117. Which of the following indicates the amount of

superabrasive grit in grinding wheel?

ieÙee Lee?

FveceW mes keâewve mee DeheIe<e&keâ heefnS ceW meghejSyeÇsefmeJe ef«eš

(a) Vegetable farming/meypeer keâer Kesleer

keâer cee$ee keâes oMee&lee nw?

(b) Organic farming/pewefJekeâ Kesleer

(a) Grade/«es[
(c) Oil production/lesue Glheeove

(b) Structure/mebjÛevee
(d) Wheat agriculture/iesntB keâer Kesleer

(c) Concentration/meebõlee
Ans : (b) 2015 ceW ueebÛe hejchejeiele ke=âef<e efJekeâeme Ùeespevee

(d) Grit/ef«eš
(heerkesâJeerJeeF&), kesâvõ ØeeÙeesefpele melele ke=âef<e efJekeâeme hej je°^erÙe
efceMeve
kesâ lenle ce=oe mJeemLÙe ØeyebOeve keâe Skeâ efJemleeefjle Ieškeâ nw~ Ans :
(c) «eeFef[bie– «eeFef[bie Skeâ Øe›eâce nw, efpemeceW «eeFef[bie
heerkesâJeerJeeF& keâe ue#Ùe pewefJekeâ Kesleer (Organic Farming) keâe
heefnÙes kesâ GheÙeesie mes, Oeeleg nševes keâer Øeef›eâÙee keâer peeleer nw,
«eeFef[bie

heefnÙee meghej SyeÇsefmeJe ef«eš Je SyeÇsefmeJe «esve keâe yevee neslee nw pees
meceLe&ve Deewj ØeÛeej keâjvee nw, efpemekesâ heefjCeece mJe™he efceóer keâer
iegCeJeòee ceW megOeej ngDee nw~
heefnÙees ceW keâšeF& efkeâveejes keâe ™he ueslee nw~ «eeFef[bie heefnÙes ceW
115. The maximum heat in resistance welding is at DeeJeMÙekeâ SyeÇsefmeJe «esve
keâe Deekeâej, «eeFef[bie efkeâÙes peeves Jeeues heoeLe&
the– keâer
keâ"esjlee hej efveYe&j keâjlee nw~ Dele: DeheIe<e&keâ heefnS ceW
ØeeflejesOe Jesefu[bie ceW DeefOekeâlece T<cee keâneB ceewpeto nesleer
meghejSyeÇsefmeJe ef«eš keâer cee$ee, meevõlee (concentration) keâes Yeer
nw?
oMee&lee nw~
(a) Top surface of the plate at the time of electric 118. In machine lapping,
for hard materials, a
contact with the electrode/Fueskeäš^es[ kesâ meeLe
pressure up to ..................... is applied.
efJeÅegle mecheke&â kesâ meceÙe huesš keâer Thejer melen hej
ceMeerve uewefhebie ceW, keâ"esj meece«eer kesâ efueS ................
(b) Interface between the two plates being
lekeâ keâe oeye Deejesefhele efkeâÙee peelee nw~
joined/peesÌ[er peeves Jeeueer oes huesšeW kesâ yeerÛe kesâ

(a) 1 N/mm2 (b) 0.02 N/mm2

Fbšjhesâme hej melen hej
(c) 0.05 N/mm 2

(d) 0.5 N/mm2

(c) Tip of the positive electrode

Ans : (c) ceMeerve uewefhebie ceW keâ"esj meece«eer kesâ efueS 0.07 N/mm2
Oeveelcekeâ Fueskeäš^es[ keâer veeskeâ hej

keâe oyeeJe ueieeÙee peelee nw leLee ce=og meece«eer kesâ efueS 0.01 mes 0.03
(d) Tip of the negative electrode

N/mm2 lekeâ oyeeJe ueieeÙee peelee nw~

$e+Ceelcekeâ Fueskeäš^es[ keâer veeskeâ hej

ceMeerve uewefhebie (Machine lapping)– ceMeerve uewefhebie keâe ØeÙeesie

Ans : (b) ØeeflejesOe Jesefu[bie ceW DeefOekeâlece T<cee peesÌ[er peeves Jeeueer

cegKÙele: meleneW hej GÛÛelece he=‰ heefj<ke=âefle Øeoeve keâjves kesâ efueS
efkeâÙee
oesveeW huesšeW kesâ yeerÛe kesâ Fbšjhesâme hej ceewpeto nesleer nw keäÙeeWefkeâ
ÙeneB
ØeeflejesOe pÙeeoe nesves kesâ keâejCe pÙeeoe T<cee GlheVe nesleer nw~ Ùeebef$ekeâ
peelee nw~ GoenjCe– yeeue leLee jesuej efyeÙeefjbieeW keâer jsmeeW, efieÙej,
›eQâkeâ
oeye kesâ Debleie&le Oeeleg KeC[ kesâ GÛÛe Oeeje ØeJeen leLee GÛÛe mecheke&â
Meeheäš, iespe yuee@keâ, efyeÙeefjbie FlÙeeefo~ ceMeerve uewefhebie keâe GheÙeesie
ØeeflejesOe kesâ keâejCe GlheVe leehe mes efheIeuekeâj pegÌ[ves keâer ef›eâÙee
keâes Je=òeekeâej, Ûehešs he=‰ Jeeues keâeÙe&KeC[eW kesâ uewefhebie ceW
neslee nw~
jsefpemšsme Jesefu[bie keânles nW~ JeemleJe ceW Ùen Skeâ Øekeâej keâer oeye
Note :– DeeÙeesie Éeje efJekeâuhe (d) keâes mener ceevee ieÙee nw~
Jesu[ve nw, efpemeceW Oeeleg KeC[eW kesâ efheIeueves kesâ efueS DeeJeMÙekeâ
119. Which computer application scans texts and
T<cee, pegÌ[ves Jeeues oes he=‰eW kesâ yeerÛe mecheke&â ØeeflejesOe mes neskeâj
yenves converts into readable form in computer?
Jeeueer efJeÅegle Oeeje mes GlheVe nesleer nw~ Fmes hueeefmškeâ Jesefu[bie Yeer
keâewve mee keâchÙetšj SefhuekesâMeve šskeämš keâes mkewâve keâjlee nw
keânles nQ~
Deewj keâchÙetšj ceW he"veerÙe ™he ceW heefjJeefle&le keâjlee nw?
116. The unit of moment of inertia of mass of–
(a) Optical Character Evaluator
õJÙeceeve peÌ[lJe DeeIetCe& keâer FkeâeF& keäÙee nw?
Dee@efhškeâue kewâjskeäšj SJeeuegšj
(a) m2/kg (b) kg–m2
(b) Optical Marker Recognition
(c) kg/m (d) kg/m2
Dee@efhškeâue ceeke&âj efjkeâe@eif veMeve
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 (c) Optical Scanner Reader/Dee@efhškeâue mkewâvej
jer[j (c) Coordinate Monitoring Machine
(d) Optical Character Recognition
keâesDee@ef[&vesš cee@efvešefjbie ceMeerve
Dee@efhškeâue kewâjskeäšj efjkeâe@efiveMeve
(d) Coordinate Measuring Machine

keâesDee@ef[&vesš cespeefjbie ceMeerve

Ans : (d) Dee@efhškeâue kewâjskeäšj efjkeâefiveMeve (OCR) keâchÙetšj

Ans : (d) CMM keâe hetCe& ™he– Co-ordinate Measuring

SefhuekesâMeve šskeämš keâes mkewâve keâjlee nw leLee GvnW keâchÙetšj ceW he"veerÙe

Machine (CMM) neslee nw~ keâesDee@ef[&vesš cespeefjbie ceMeerve (CMM)

™he ceW heefjJeefle&le keâjlee nw, Deewj efheâj mkewâve efkeâÙes ieÙes šskeämš
keâes

efkeâmeer Jemleg keâer Yeeweflekeâ SJeb pÙeeefceleerÙe efJeMes<eleeDeeW keâes

ceeheves keâe
efmemšce cesceesjer hej mšesj keâjlee nw, efpemes yeeo ceW Sef[š Yeer efkeâÙee pee
GhekeâjCe nw~
mekeâlee nw~
123. Which of the following shutdown methods is
120. Major purpose of most of the dams around the
often called Warm Boot?
world is–
efvecveefueefKele Meš[eGve efJeefOeÙeesW ceW mes efkeâmes Dekeämej
ogefveÙee Yej ceW ceewpeto DeefOekeâebMe yeebOeeW keâe ØecegKe GösMÙe
Jeece& yetš keâne peelee nw?
keäÙee nw?
(a) Restart/jermšeš&
(a) Drinking water supply /hesÙepeue Deehetefle&
(b) Hibernate/neFyejvesš
(b) All of the options/efJekeâuheeW ceW mes meYeer
(c) Shut Down/Meš [eGve
(c) Irrigation/efmebÛeeF&
(d) Sleep/mueerhe
(d) Power generation/efJeÅegle Glheeove
Ans : (a) Meš[eGve Skeâ Øeef›eâÙee nesleer nw keâchÙetšj keâes jermšeš&

keâjves keâer jermšeš& keâes Dekeämej Jee@ce& yetš Yeer keâne peelee nw~ Fmes Skeâ
Ans : (b) yeebOe efvecveefueefKele ceeveJeerÙe cetueYetle DeeJeMÙekeâleeDeeW keâer

Cold Boot kesâ meeLe leguevee Yeer keâer pee mekeâleer nw, efpemekeâe DeLe&
hetefle& keâjves ceW GuuesKeveerÙe Ùeesieoeve osles nQ-

neslee nw Skeâ turned off Computer keâes start keâjvee~

• hesÙepeue Deewj DeewÅeesefiekeâ GheÙeesie nsleg peue
124. If
'α' is coefficient of thermal expansion, '∆T' is
• efmebÛeeF&
magnitude of change in temperature and 'E' is
• yeeÌ{ efveÙeb$eCe
modulus of elasticity, then the expression for

thermal stress induced in a rod of length 'l'

• peue-efJeÅegle Glheeove
that is fixed between two rigid ends is given as–
• DevleoxMeerÙe veew heefjJenve Deeefo~
Ùeefo Lece&ue efJemleej keâe iegCeebkeâ 'α' nw, leeheceeve ceW
121. To what degree are the edges of optical flats
heefjJele&ve keâe heefjceeCe '∆T' nw Deewj ueesÛe keâe ceeheebkeâ
bevelled? 'E'
nw, lees Lece&ue leveeJe kesâ efueS DeefYeJÙeefòeâ keâer uecyeeF&
efkeâme keâesCe lekeâ Dee@efhškeâue heäuewšdme kesâ efkeâveejeW keâes 'l'
keâer ÚÌ[ ceW Øesefjle nesleer nw pees oes keâ"esj ÚesjeW kesâ yeerÛe
ØeJeefCele efkeâÙee peelee nw?
leÙe keâer peeleer nw~ Jen efkeâme Øekeâej efve™efhele keâer peeleer
(a) 90o (b) 30o
nw?
(c) 45o (d) 60o
(a) αE∆T (b) α∆T/El
Ans : (c) 45º keâesCe lekeâ Dee@efhškeâue heäuewšdme kesâ
efkeâveejeW keâes (c) αEl∆T (d) αl∆T
ØeJeefCele (Bevel) efkeâÙee peelee nw~
Ans : (a) Thermal stress and strain
Dee@efhškeâue heäuewšdme kesâ efkeâveejs GefÛele «eeFbef[bie Éeje meceevÙele: 45º
(i) σth = E α ∆T

(ii) uecyeeF& ceW heefjleJe&ve (∆) = L α ∆T

keâesCe hej yesJesu[ efkeâS peeles nQ leLee efkeâmeer Yeer Øekeâej kesâ efÛehme
Deeefo

L α ∆T
mes efkeâveejeW keâes cegòeâ keâjves kesâ efueS Gmekeâer hee@efueefMebie keâer
peeleer nw~ (iii) efJeke=âefle ( e ) = = α ∆T
Dee@efhškeâue heäuewšdme keâer keâeÙe&keâejer meleneW keâes hee@efueefMebie Deewj
uewefhebie L

peneB σ = G<ceerÙe Øeefleyeue

Øeef›eâÙee Éeje heefj<ke=âle efkeâÙee peelee nw leLee yesueveekeâej meleneW keâes

α = jsKeerÙe Øemeej iegCeebkeâ

«eeFbef[bie Øeef›eâÙee Éeje heefj<ke=âle efkeâÙee peelee nw~

∆T = leeheceeve heefjJele&ve
GheÙeesie– Dee@efhškeâue heäuewšdme keâe GheÙeesie efJeefYeVe Dee@efhškeâue meleneW

125. If the Reynolds number is less than 2000, the

kesâ meceleuelee keâer peeBÛe keâjves kesâ efueS efkeâÙee peelee nw~ Dee@efhškeâue
flow in pipe is–
heäuewšdme meleneW kesâ meceleuelee keâe efveOee&jCe FbšjhewâjWme (Interfrence)
Ùeefo jsvee@u[dme mebKÙee 2000 mes keâce nw, lees heeFhe ceW
Éeje keâjles nw~
ØeJeen ............. neslee nw~
122. What is the full form of CMM?
(a) Laminar/hešueerÙe
CMM keâe hetCe& ™he keäÙee nw?
(b) Transitional from laminar to turbulent
(a) Cantilever Measuring Machine
hešueerÙe mes Øe#egyOe lekeâ heefjJeleea
keQâšerueerJej cespeefjbie ceMeerve
(c) Inviscid/DeMÙeeve
(b) Current Measuring Machine/keâjWš
cespeefjbie ceMeerve (d) Turbulent/Øe#egyOe

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Ans : (a) Ùeefo jsveeu[ mebKÙee 2000 mes keâce nw, lees heeFhe ceW
128. Funds belonging to the Government of India
ØeJeen uesefceveej (laminar) neslee nw~
are kept in–
ØeJeen oMeeS heeFhe ØeJeen Keguee Ûewveue ØeJeen
Yeejle mejkeâej mes mebyebefOele efveefOeÙeeW keâes ................ ceW
(flow
jKee peelee nw~
condition)
(a) Public Account of India/Yeejle kesâ ueeskeâ uesKee
Laminar flow Re ≤ 2000 Re ≤ 500
(b) Consolidated funds of India
Transitional 2000 < Re < 500 < Re < 1000
Yeejle kesâ mecesefkeâle keâes<e
flow 4000
(c) Contingency Fund of India
Turbulent flow Re > 4000 Re > 1000
Yeejle keâer Deekeâefmcekeâlee efveefOe
126. ...........layout is also called line layout.
(d) All of the options/efJekeâuheeW ceW mes meYeer
.............uesDeeGš keâes ueeFve uesDeeGš Yeer keâne peelee nw~

Ans : (d) Yeejle mejkeâej mes mebyebefOele efveefOeÙeeW keâes efvecveefueefKele

kesâ
(a) Fixed position layout/efveefMÛele efmLeefle uesDeeGš
lenle jKee peelee nw-
(b) Process layout/Øeef›eâÙee uesDeeGš

Yeejle keâer mecesefkeâle efveefOe DevegÛÚso- 266(1)

(c) Functional layout/keâeÙee&lcekeâ uesDeeGš

Yeejle keâer Deekeâefmcekeâ efveefOe DevegÛÚso-267(1)

(d) Product layout/Glheeo uesDeeGš

Yeejle keâer ueeskeâ uesKee efveefOe DevegÛÚso- 266(2)

Ans : (d)
Glheeo uesDeeGš keâes ueeFve uesDeeGš Yeer keâne peelee nw~
129. Which of the following is an example of diffuse

reflection?
FmeceW mecemle ceMeerveeW keâes Skeâ ner jsKee ceW ueieeÙee peelee nw~

efvecveefueefKele ceW mes keâewve mee efJemeefjle hejeJele&ve keâe

FmeceW Skeâ ner Øekeâej keâe Glheeo yeveeÙee peelee nw~

GoenjCe nw?
FmeceW DeefYevÙeeme ceW ßece ueeiele Dehes#eeke=âle keâce ueieleer nw~

(a) Reflection on mirrors/ohe&CeeW hej yevee Øeefleefyebye

Glheeo uesDeeGš ceW ØeejefcYekeâ hetBpeer Dehes#eeke=âle DeefOekeâ ueieleer
nw~

(b) Both reflection on mirror and still water

 Glheeo uesDeeGš ceW efvejer#eCe mejue SJeb megiece neslee nw~

ohe&Ce Deewj Meeble peue oesveeW ceW yevee Øeefleefyebye

127. In electrochemical grinding process, the
material removal rate is inversely proportional
(c) Reflection on roadways
to–
meÌ[keâ ceeie& hej yevee Øeefleefyebye
JewÅegle–jemeeÙeefvekeâ DeheIe<e&Ce Øeef›eâÙee ceW, meece«eer
(d) Reflection on still water
efve<keâemeve oj..............kesâ JÙegl›eâceevegheeleer nesleer nw~
Meeble peue ceW yevee Øeefleefyebye
(a) Both density of the workpiece material Ans : (c) efJemeefjle
hejeJele&ve- peye meYeer meceevlej efkeâjCeW efkeâmeer
supply current/Jeke&âheerme meece«eer kesâ IevelJe Deewj Kegjogjs
Ùee DeefveÙeefcele he=‰ mes hejeJeefle&le nesves kesâ he§eele meceevlej veneR
Deehetefle& Oeeje oesveeW kesâ nesleer,
lees Ssmes hejeJele&ve keâes ØekeâeMe keâe efJemeefjle hejeJele&ve keânles nQ
(b) Density of the workpiece material
pewmes-
meÌ[keâ ceeie& hej yevee Øeefleefyecye leLee efkeâmeer keâcejs ceW ØekeâeMe keâe
Jeke&âheerme meece«eer kesâ IevelJe
ØeJesMe
keâjvee Deeefo~
(c) Total supply current/kegâue Deehetefle& Oeeje
130. Who
has won the Sir Garfield Sober Trophy
(d) Feed rate of electrode/Fueskeäš^es[ keâer heâer[ oj

for Cricketer of the Year 2017?

Ans : (b)
efkeâmeves mej iee@jheâeru[ meesyej š^e@heâer keâes Je<e& 2017 kesâ
JewÅegle jemeeÙeefvekeâ DeheIe<e&Ce Øeef›eâÙee ceW heoeLe& efve<keâemeve oj
efueS peerlee nw?
(Material removal rate) keâeÙe&KeC[ heoeLe& kesâ IevelJe kesâ

(a) Virat Kohli/efJeješ keâesnueer

JÙegl›eâceevegheeleer neslee nw~

(b) Ravichandran Ashwin/jefJeÛevõve DeefMJeve

efJeÅegle jemeeÙeefvekeâ DeheIe<e&Ce kesâ oewjeve Oeeleg keâe he=LekeäkeâjCe
DeheIe<eea keâCeeW keâer keâle&ve ef›eâÙee leLee efJeÅegle jemeeÙeefvekeâ
DeheIešve (c) Steve Smith/mšerJe efmceLe
(electro–chemical decomposition) oesveeW kesâ ner mebÙegòeâ
(d) Ravindra Jadeja/jefJevõ pe[spee
ØeYeeJe mes mecheVe neslee nw~ FmeceW ueieYeie 90³ Oeeleg jemeeÙeefvekeâ
Ans : (a) Je<e& 2017 kesâ efueÙes mej iee@jheâeru[ meesyej š^eheâer keâes
leewj hej he=Lekeäke=âle nesleer nw Deewj Mes<e DeheIe<eea keâCeeW keâer
keâle&ve efJeješ keâesnueer ves peerlee Lee~ peyeefkeâ Je<e& 2021 kesâ
efueÙes heeefkeâmleeveer
ef›eâÙee mes neslee nw~
lespe ieWoyeepe Meenerve Deheâjeroer keâes efoÙee ieÙee~
efJeÅegle jemeeÙeefvekeâ DeheIe<e&Ce ceW pees DeheIe<e&Ce heefnS ØeÙeesie ceW
131. The first instrument for routine monitoring of
ueeÙes peeles nw~ Jes heejcheefjkeâ Deekeâej Je mebjÛevee Jeeues nesles nw~
total ozone was developed by–
efJeÅegle jemeeÙeefvekeâ DeheIe<e&Ce efJeefOe mes ueieYeie ± 0.02 mm
šesšue Deespeesve keâer efveÙeefcele efveiejeveer kesâ efueS henuee
tolerance Jeeueer Accuracy Øeehle nes peeleer nw~
Ùeb$e efkeâmekesâ Éeje efJekeâefmele efkeâÙee ieÙee Lee?
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 (a) Gordon M.B. Dobson/iee@[&ve M.B. [esyemeve
134. The horizontal feed in a lathe is controlled by–
(b) Samuel Langley/mewcegDeue ueQieueer
uesLe ceW #eweflepe heâer[ keâes .............. Éeje efveÙebef$ele efkeâÙee
(c) William Strugeon/efJeefueÙece mšpe&ve
peelee nw~
(d) Robert Moog/je@yeš& cetie
(a) Cross–slide/›eâe@me–mueeF[
Ans : (a) iee[&ve Sce.yeer.[e@yemeve ves šesšue (kegâue) Deespeesve keâer
(b) Apron/SØeve
efveÙeefcele efveiejeveer kesâ efueÙes henuee GhekeâjCe 1920 kesâ oMekeâ ceW
(c) Tailstock/šsuemše@keâ
efJekeâefmele efkeâÙee Lee~ Fme GhekeâjCe keâes Deye [e@yemeve
mheskeäš^esheâesšesceeršj (d) Headstock/ns[mše@keâ
keâne peelee nw~ Ùen oes hejeyeQieveer lejbieowOÙe& hej metÙe& kesâ ØekeâeMe keâer
Ans : (b) uesLe ceW #eweflepe heâer[ keâes SØeve Éeje efveÙebef$ele efkeâÙee peelee
leer›elee keâes ceehelee nw- Skeâ pees Deespeesve Éeje ÂÌ{lee mes DeJeMeesef<ele
nw~ SØeve keâe"er (Saddle) kesâ meeceves yeesušeW Éeje ueiee neslee nw leLee
neslee nw leLee otmeje pees keâcepeesj ™he mes DeJeMeesef<ele neslee nw~
Kejeo kesâ DeeOeej kesâ meeceves keâer lejheâ neslee nw~ Fmemes Jeenve leLee
132. Control volume in a thermodynamic system Deewpeej keâes neLe leLee Meefòeâ
Éeje Ûeueeves kesâ efueS hetCe& Ùeb$e efJevÙeeme
refers to–
neslee nw efpemeceW ueerJej, efieÙej leLee keäueÛe nesles nQ~ Ùen KeesKeues
yee@keäme
T<ceeieeflekeâerÙe ØeCeeueer ceW kebâš^esue Jee@uÙetce .............
keâes kesâ meceeve {ueJeeB ueesns keâe yevee neslee nw~ efmhueš neheâ veš keâes
ueer[
meboefYe&le keâjlee nw~
m›etâ kesâ meeLe Sbiespe keâjkesâ ÛetefÌ[ÙeeB keâešer peeleer nQ~
(a) A specified mass in fluid flow
135. After New moon, the next fourteen days where
õJe ØeJeen ceW Skeâ efveefo&° õJÙeceeve
the moon grows thicker and thicker and
(b) Mass that moves across the boundary
becomes visible as a full, near perfect round
meercee kesâ heej peeves Jeeuee õJÙeceeve
moon is called as which phase of the moon?
(c) Fixed region in space for thermodynamic
DeceeJemÙee kesâ yeeo, Deieues Ûeewon efoveeW ceW, peneB Ûevõcee
study/T<ceeieeflekeâerÙe DeOÙeÙeve kesâ cegòeâ Debleefj#e ceW
ceesše neslee peelee nw Deewj ueieYeie hetCe& ieesueekeâej efoKeeF&
efveefMÛele #es$e
osves ueielee nw, Ûebõcee keâer Fme keâuee keâes keäÙee keâne peelee
(d) Transfer of energy across the boundary
nw?
Tpee& keâe meercee kesâ heej mLeeveeblejCe
(a) Waning phase of the moon
Ans : (c) T<ceeieeflekeâer ØeCeeueer ceW kebâš^esue JeeuÙetce T<ceeieeflekeâerÙe
Ûebõcee keâer #eÙeCe keâuee
DeOÙeÙeve kesâ efueS cegòeâ Debleefj#e ceW efveefMÛele #es$e keâes meboefYe&le
keâjlee (b) Vanishing phase of the moon
nw~ T<ceeieeflekeâer ceW Skeâ #es$e keâes efveOee&efjle efkeâÙee peelee nw leLee
Ûebõcee keâe ueesheMeerue keâuee
efJeÛeejnerve #es$e kesâ efvekeâš Skeâ meercee KeerÛe ueer peeleer nw~ Dele: Ùen
(c) Waxing phase of the moon/ÛeeBo keâer JeOe&ve keâuee
meercee JeemleefJekeâ Ùee keâeuheefvekeâ nes mekeâleer nw Deewj heefjJele&veMeerue
Yeer (d) Decreasing phase of the moon
nes mekeâleer nw~ Dele: meercee kesâ Devoj pees kegâÚ Yeer ef›eâÙee nesleer nw Gmes
Ûebõcee keâe Üemeer keâuee
efvekeâeÙe keânles nQ~ meercee kesâ yeenj kesâ #es$e keâes heefjmLeeve keânles nQ~
Ans : (c) DeceeJemÙee kesâ yeeo, Deieues Ûeewon efoveeW ceW, peneB Ûevõcee
133. Gantt chart is a type of chart which illustrates
cees še neslee peelee nw Deewj ueieYeie hetCe& ieesueekeâej efoKeeF& osves ueielee
the–
nw, Ûevõcee keâer Fme keâuee keâes ÛeeBo keâer JeOe&ve keâuee (Waxing
ieQš Ûeeš& Skeâ Øekeâej keâe Ûeeš& nw, pees ................ keâes phase
of the moon) keâne peelee nw~
oMee&lee nw~
136. Which film has won the Best Film (Popular)
(a) Assignable causes of variation in a process
award at the 63rd Jio Filmfare Award 2018?
efkeâmeer Øeef›eâÙee ceW efYeVelee kesâ efveoxMÙe keâejCe
efkeâme efheâuce ves 63JeW efpeÙees efheâucehesâÙej DeJee@[&dme 2018
(b) Project schedule/heefjÙeespevee DevegmetÛeer
ceW meJe&ßes‰ efheâuce (ueeskeâefØeÙe) keâe hegjmkeâej peerlee?
(c) Inventory status materials requirement
(a) Bareilly ki Barfi/yejsueer keâer yeheâea
metÛeer keâe efmLeefle Deewj meece«eer keâer DeeJeMÙekeâlee
(b) Hindi Medium/efnvoer ceeref[Ùece
(d) Common causes of variation in a process
(c) Newton/vÙetšve
Skeâ Øeef›eâÙee ceW efYeVelee kesâ meeceevÙe keâejCe
(d) Secret Superstar/meer›esâš meghejmšej
Ans : (b) ieQš Ûeeš& Skeâ Øekeâej keâe yeej Ûeeš& neslee nw pees efkeâ Ans : (b)
63JeW efpeDees efheâucehesâÙej DeJee@[&dme 2018 ceW meJe&ßes‰
Øeespeskeäš Mes[dÙetue keâer JÙeeKÙee keâjlee nw, efpemekeâe veece nsvejer ieQš
kesâ efheâuce keâe DeJee[& efnvoer ceeref[Ùece keâes efoÙee ieÙee~ peyeefkeâ 66JeW
veece hej jKee ieÙee Lee~ DeeOegefvekeâ ieQš Ûeeš& ieefleefJeefOeÙeeW Deewj
Jele&ceeve efheâuce hesâÙej DeJee@[&, 2021 ceW meJe&ßes‰ efheâuce keâe DeJee@[&
efheâuce
DevegmetÛeer efmLeefle kesâ yeerÛe efveYe&jlee, mebyebOeeW keâes Yeer oMee&lee nw~
‘LehheÌ[’ keâes efoÙee ieÙee~
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137. Through which of the following states does the
efJeke=âefle Tpee& Ùee levÙekeâlee (Strain energy or Resilience)
Chambal river flow?

σ2
Ûebyeue veoer keâer efvecve jepÙeeW ceW mes efkeâme jepÙe ceW ØeJeen
U= × Debie keâe DeeÙeleve
keâjleer nw?
2E

(a) Rajasthan/jepemLeeve
141. Which of the following is an organic flux?

efvecveefueefKele ceW mes keâesve mee Skeâ Deeiexefvekeâ heäuekeäme nw?

(b) All of the options/efJekeâuheeW ceW mes meYeer

(a) Zinc chloride/efpebkeâ keäueesjeF[

(c) Uttar Pradesh/Gòej ØeosMe

(b) Phosphoric acid/heâe@mheâesefjkeâ Sefme[

(d) Madhya Pradesh/ceOÙe ØeosMe

(c) Tallow/šwuees
Ans : (b) Ûecyeue veoer Ùecegvee veoer keâer meneÙekeâ veoer nw~ Fmekeâe
(d) Hydrochloric acid/neF[^eskeäueesefjkeâ Sefme[
Godiece mLeue ceOÙe ØeosMe ceW cent efpeues kesâ peeveeheeJe heJe&le mes neslee nw~

Ans : (c) šwuees heäuekeäme Skeâ keâeye&efvekeâ heäuekeäme nw, Ùen Skeâ
Fmekeâe ØeeÛeerve veece Ûece&CJeleer Lee~ Ùen veoer Yeejle kesâ Gòej leLee Gòej-
Demeb#eejkeâ ieeuekeâ neslee nw~ Fmekeâe ØeÙeesie meermes kesâ meesu[efjbie ceW
efkeâÙee
ceOÙe Yeeie ceW jepemLeeve kesâ keâesše leLee Oeewuehegj, ceOÙe ØeosMe kesâ Oeej,
peelee nw~
Gppewve, efYeb[, cegjwvee Deeefo efpeueeW mes nesleer ngF&, Gòej ØeosMe kesâ FšeJee

Demeb#eejkeâ ieeuekeâ (Non corrosive flux)–peye Oeeleg Ùee efceße

efpeues ceW Ùecegvee mes efceue peeleer nw~ Fme veoer hej Ûeej peue efJeÅegle
Oeeleg melen keâe meb#eejCe jeskeâvee DeeJeMÙekeâ neslee nw, lees Fve ieeuekeâeW
heefjÙeespevee- (ieebOeer meeiej, jeCee Øeleehe meeiej, peJeenj meeiej leLee
keâe ØeÙeesie efkeâÙee peelee nw~ Oeeleg leLee efceße Oeeleg kesâ ØelÙeskeâ «eghe
kesâ
keâesše yewjepe) yeveeÙes ieÙes nw~
efueS efYeVe Demeb#eejkeâ ieeuekeâ keâe ØeÙeesie efkeâÙee peelee nw~
138. Where was the 27th Fusion Energy Conference Fmekesâ Debleie&le efvecve
ieeuekeâ Deeles nw–
held?
(a) Deesefuekeâ Decue–efšve huesš kesâ meesu[efjbie kesâ efueS
27JeeR heäÙetpeve Svepeea keâe@vøeWâme keâe DeeÙeespeve keâneB efkeâÙee
(b) šwuees–meermes kesâ meesu[efjbie kesâ efueS
ieÙee Lee?
efpebkeâ keäueesjeF[ (Zinc chloride)–leeByee, heerleue, Fmheele leLee
(a) New Delhi/veF& efouueer
ueesns kesâ efueS Ùen Skeâ ØeYeeJekeâejer ieeuekeâ nw~ Ùen heeG[j Ùee hesmš
(b) Maharashtra/ceneje°^
kesâ ™he ceW ØeÙeesie efkeâÙee peelee nw~
(c) Gujarat/iegpejele
142. A radius gauge is also known as–
(d) Kerala/kesâjue
ef$epÙe–Øeceeheer iespe keâes ............. Yeer keâne peelee nw~
Ans : (c) 27Jeeb mebueÙeve Tpee& meccesueve iegpejele kesâ ieebOeer veiej ceW
(a) Fillet gauge/efheâuesš iespe
Dekeäštyej 2018 ceW Meg™ efkeâÙee ieÙee~ Fmes Devleje&°^erÙe hejceeCeg Tpee&
(b) Snap gauge/mvewhe iespe
mebmLee (DeeF&.S.F&.S) Éeje DeeÙeesefpele efkeâÙee ieÙee Lee~
(c) Feeler gauge/heâeruej iespe

(d) Slip gauge/efmuehe iespe

139. What is the chemical symbol of acetylene gas?
Sefmeefšueerve iewme keâe jemeeÙeefvekeâ Øeleerkeâ keäÙee nw?
Ans : (a)
(a) CH2 (b) CH3

jsef[Ùeme iespe (Radius gauge) keâes efheâuesš iespe Yeer keâne peelee
(c) C3H2 (d) C2H2
nw~
Ans : (d) iewme jemeeÙeefvekeâ Øeleerkeâ
efkeâmeer pee@ye hej yeves Gòeue Ùee DeJeleue jsef[Ùeme keâes Ûeskeâ keâjves kesâ

efueS jsef[Ùeme iespe keâe ØeÙeesie efkeâÙee peelee nw~

Sefmeefšueerve C2H2

jsef[Ùeme iespe keâe ØeÙeesie efkeâmeer pee@ye ceW Jesefu[bie Éeje Ùee DevÙe
cesLesve CH4
Øekeâej mes yeveer efheâuesš keâe jsef[Ùeme Ûeskeâ keâjves kesâ efueS Yeer ØeÙeesie
SLesve C2H6
efkeâÙee peelee nw~
140. The ability of a material to absorb energy in 143. The process of draining
steam for heating the
the elastic region is called– feedwater is known as–
heoeLe& keâer ØelÙeemLe #es$e ceW Tpee& DeJeMeesef<ele keâjves keâer
heâer[Jee@šj keâes iece& keâjves kesâ efueS Yeehe efvekeâeueves keâer
#ecelee keâes keäÙee keâne peelee nw?
Øeef›eâÙee keâes .............. kesâ ™he ceW peevee peelee nw~
(a) Resilience/levÙekeâlee (b) Toughness/ÂÌ{lee
(a) Cooling/Meerleueve
(c) Ductility/leveveMeeruelee (d) Hardness/keâ"esjlee
(b) Bleeding/œeJeCe
Ans : (a) ØelÙeemLe meercee kesâ Deboj heoeLe& ceW efJeke=âefle (Strain) kesâ
(c) Reheating of steam/Yeehe keâe hegve:mleeheve
™he ceW Fkeâªs ngS keâeÙe& Ùee Tpee& keâes efJeke=âefle Tpee& (Strain energy
(d) Governing/efveÙeb$eCe
or Resilience) keânles nQ~ efyevee mLeeÙeer efJeke=âefle (without
Ans : (b) šjyeeFve keâer peerefJele Yeehe (live steam) keâes Ûetef<ele
permanent strain) GhepeeÙes Ùee ØelÙeemLe meercee kesâ Deboj, efkeâmeer
(extract) keâjkesâ Heâer[ Jeešj keâes iece& keâjves keâer Øeef›eâÙee yueeref[bie
heoeLe& kesâ šgkeâÌ[s ceW Fkeâªer keâer pee mekeâves Jeeueer DeefOekeâlece
efJeke=âefle keânueeleer nw~ yueeref[bie Yeehe keâes efpeme yee@keäme ceW jKee
peelee nw, Gmes
Tpee& keâes Gmekeâer ØeceeCe efJeke=âefle Tpee& keânles nQ~
Heâer[ Jee@šj neršj (FWH) keânles nQ~
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• yueeref[bie Øeef›eâÙee mes šjyeeFve keâer o#elee yeÌ{ peeleer nw~
Jen ef›eâÙee, pees DeheIe<e&keâ heefnS keâer KeesF& ngF& Deeke=âefle
veesš:-efceleesheÙeespekeâ (Economiser) kesâ Éeje Heâer[ Jee@šj keâes efÛeceveer
keâes hegve: Øeehle keâjves kesâ efueS Fmekeâer heefjefOe keâes Gmekeâer
ceW pee jner oiOe iewmeeW (flue gases) mes iece& keâer peeleer nw~
Oegjer kesâ meeLe mebkesâefvõle yeveeves kesâ efueS keâer peeleer nw,

keäÙee keânueeleer nw?

144. The performance of cache memory if
frequency measured in terms of a quantity
(a) Loading/ueesef[bie (b) Glazing/iuesefpebie
called ................. .
(c) Truing/šÎFbie (d) Dressing/[^sefmebie
kewâMe cesceesjer keâe ØeoMe&ve Dekeämej ............... veecekeâ Skeâ
Ans : (c) Jnerue efmheb[ue De#e kesâ «eeFef[bie Jnerue keâer melen keâes
cee$ee kesâ meboYe& ceW ceehee peelee nw~
mebkesâvõerÙe leLee mener yeveeves keâer Øeef›eâÙee šÍFbie (Truing) keânueeleer nw~
(a) Set–associative Mapping/mesš–SmeesefmeSefšJe
cewefhebie [^sefmebie keâe leelheÙe& heefnS keâes meeheâ keâjvee leLee
Oeeleg efÚuekeâeW Deewj
(b) Register/jefpemšj
kegâvo DeheIe<e&keâ keâCeeW keâes efvekeâeue osvee nw efpememes veS keâCe keâšeF&
kesâ
(c) Associative Mapping/menÙeesieer ceeveefÛe$eCe
efueS efmLeefle ceW Dee peeS~ [^sefmebie leLee šÍFbie ef›eâÙeeDeeW kesâ efueS
keâ"esj
(d) Hit ratio/efnš Devegheele
Fmheele kesâ heefnS Ùee meerOee keâjves Jeeues nerjkeâ (Turning

diamonds) ØeÙeesie efkeâS peeles nw~ Ùes ef›eâÙeeS Fve DeewpeejeW Éeje heefnS
Ans : (d) kewâMe cesceesjer keâe ØeoMe&ve Dekeämej efnš Devegheele (Hit

keâer Ietceleer DeJemLee ceW keâer peeleer nw~

ratio) veecekeâ Skeâ cee$ee kesâ meboYe& ceW ceehee peelee nw~

148. Which of the following is a junction of side and

145. Internal energy of a perfect gas depends upon–
end of cutting edge in single point cutting tool?
Skeâ hejhesâkeäš iewme keâer Deebleefjkeâ Tpee& ................ hej
FveceW mes keâewve mee, Skeâue efyebog keâle&ve Deewpeej ceW meeF[
efveYe&j keâjlee nw~
Deewj efmejs keâe peesÌ[ nw?
(a) Temperature and volume/leeheceeve Deewj DeeÙeleve
(a) Base/yesme (b) Flank/heäueQkeâ
(b) Temperature, specific heat and entropy
(c) Nose/veespe (d) Heel/nerue
leeheceeve, efJeefMe° T<cee Deewj Svš^eheer
Ans :
(c) Skeâue efyevog keâle&ve Deewpeej ceW meeF[ keâle&ve efkeâveej (Side
(c) Volume and pressure/DeeÙeleve Deewj oyeeJe

cutting edge) leLee SC[ keâle&ve efkeâveej (End cutting edge) kesâ
(d) Temperature only/kesâJeue leeheceeve peesÌ[
keâes veespe (Nose) keânles nw~
Ans : (d) hejhesâkeäš iewme keâer Deevleefjkeâ Tpee& kesâJeue leeheceeve hej
heäueQkeâ (Flank)– Deewpeej efyevog hej Jes melenW pees keâeÙe&KeC[ kesâ
efveYe&j keâjleer nw~
meccegKe nesleer nw~
Deevleefjkeâ Tpee& (u) = mcvdT 149.
The velocity with which the water approaches
du ∝ dT
a notch is called–
u = f (T)
Jesie, efpemekesâ meeLe peue Skeâ mlej keâer Deesj Deelee nw,
T<ceeieeflekeâer keâe ØeLece efveÙece Deevleefjkeâ Tpee& keâes heefjYeeef<ele
keâjlee .............. keânueelee nw~
nw~
(a) Velocity of approach/hengBÛe Jesie
146. Chilled cast iron is produced–
(b) Velocity of whirl/YebJej Jesie
efÛeu[ keâemš DeeÙejve ............... lewÙeej efkeâÙee peelee nw~
(c) Velocity of flow/ØeJeen keâe Jesie
(a) By adding magnesium to molten cast iron/
(d) Shear velocity/Dehe™heCe Jesie
efheIeues ngS {ueJeeb ueesns ceW cewiveerefMeÙece efceueekeâj
Ans : (a) Jen Jesie efpemekesâ meeLe peue vee@Ûe hej hengBÛe peeleer nw, hengBÛe
(b) By quick cooling of molten cast iron
Ùee Deeieceve Jesie keânueelee nw~
efheIeues ngS {ueJeeb ueesns keâes MeerIeÇ "b[e keâjkesâ

150. When the dispersed phase is gas and dispersing

(c) From white cast iron by annealing process
medium is solid and the type of colloid is–
mehesâo {ueJeeb ueesns kesâ leeheevegMeerleve Øeef›eâÙee Éeje
peye efJeleefjle DeJemLee iewme Deewj efJelejCe ceeOÙece "esme
(d) All of the options/efJekeâuheeW ceW mes meYeer
neslee nw, lees keâesueeF[ keâe Øekeâej FveceW mes keâewve mee nw?
Ans : (b) {ueJeeB jesume, jsueJes kewâjerpe Jnerume, SveefJeume Deeefo kesâ
(a) Aerosol/Sjesmeesue (b) Emulsion/FceuMeve
efvecee&Ce nsleg Fve keâeefmšbie keâer Skeâ melen keâes leer›e ieefle mes "C[e
efkeâÙee (c) Gel/pesue (d) Foam/heâesce
peelee nw leLee Mes<e Yeeie keâes cevo ieefle mes "C[e keâjles nQ~ Fme Øekeâej
Ans : (d) keâesueeF[ kesâ meeceevÙe GoenjCe :
leer›e ieefle mes Meereflele Yeeie kesâ iegCe efYeVe Øeehle nesles nQ~ leer›e
ieefle mes efJeleefjle DeJemLee efJelejCe ceeOÙece Øekeâej GoenjCe
"C[e efkeâÙee ngDee DeeÙejve efÛeu[ keâemš DeeÙejve yeve peelee nw Deewj

õJe iewme Sjesmeesue keâesnje, yeeoue

Mes<e Yeeie Oetmej keâemš DeeÙejve yeve peelee nw~

"esme iewme Sjesmeesue yeeoue, OegBDee

147. The operation which is done to make periphery
of grinding wheel concentric with its axis to

õJe õJe FceuMeve otOe hesâme ›eâerce

recover its lost shape is known as–
iewme "es m e heâes

c e (Peeie) jyej
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