Trigonometric Equation
Formulae
Condition          Solution               Condition            Solution
                                                                     π
sin θ = 0       θ = nπ, [n ∈ ℤ]          sin θ = −1      θ = 4n − 1 , [n ∈ ℤ]
                                                                     2
                      π
cos θ = 0   θ = 2n + 1 , [n ∈ ℤ]         cos θ = −1       θ = (2n + 1)π, [n ∈ ℤ]
                      2
                                                                    π
                                                            θ = nπ − , [n ∈ ℤ]
tan θ = 0       θ = nπ, [n ∈ ℤ]          tan θ = −1                 4
                                                                        π
                                                         Or θ = 4n − 1 , [n ∈ ℤ]
                                                                           4
                          π                                            n
sin θ = 1    θ = 4n + 1 , [n ∈ ℤ]        sin θ = sin α   θ = nπ + −1 α, [n ∈ ℤ]
                          2
cos θ = 1       θ = 2nπ, [n ∈ ℤ]      cos θ = cos α        θ = 2nπ ± α, [n ∈ ℤ]
                        π
               θ = nπ + , [n ∈ ℤ]
tan θ = 1               4             tan θ = tan α        θ = nπ + α, [n ∈ ℤ]
                            π
            Or θ = 4n + 1 , [n ∈ ℤ]
                           4
        Related to Trigonometric Equation Solution
❖ Solve: sin + cos =   2sin2θ
       Related to Trigonometric Equation Solution
❖ Solve:   cos 2x + 2 = sin x + cos x [0 ≤ x ≤ π]
       Related to Trigonometric Equation Solution
❖ Solve: cos x + 3 sin x = 2.                       [BUET’10-11]
       Related to Trigonometric Equation Solution
              3           1
❖ Solve:            −            =4                 [BUET’06-07]
           sin 2x       cos 2x
                                Quiz – 01
❖ How many integer value of k are there so that 7 cos x + 5 sin x = 2k + 1 equation
    may have at least one solution?                                        [2002, 1M]
    (a) 4
    (b) 8
    (c) 10
    (d) 12
        Related to Trigonometric Equation Solution
❖ Solve: cot θ cot 3θ = 1                            [DU’18-19]
        Related to Trigonometric Equation Solution
❖ Solve: cotx + cot2x + cot3x = cotx cot2x cot3x.    [BUET’14-15]
        Related to Trigonometric Equation Solution
❖ Solve: sec 4θ − sec 2θ = 2
         Related to Trigonometric Equation Solution
❖ Solve: sin θ + sin 3θ + sin 2θ = 1 + cos 2θ + cos θ [0 < θ < π]
                                                               [BUET’08-09, RUET’15-16]
        Related to Trigonometric Equation Solution
❖ Solve: 1 + sin 2ϕ + sin 2θ = cos 2ϕ + 2θ [θ ≤ ϕ, θ ≤ 90°]   [BUET’05-06]
         Related to Trigonometric Equation Solution
❖ Solve: 4 cos x cos 2x cos 3x = 1 ; 0 < x < π.   [CUET’08-09, BUTEX’03-04, KUET’06-07]
         Related to Trigonometric Equation Solution
                                                            2
❖ Determine the values of x that satisfies 2
                                           1+ cos x +   cos     x + ………
                                                                          = 4 where, x ∈
     −π, π .                                                                         [1984, 2M]
       Related to Use of Maximum / Minimum Value
❖ Solve: sin x cos y = 1 ; x, y ∈ [0,2π]
      Related to Use of Maximum / Minimum Value
❖ Solve: sin x + cos y = 2 sec z
            2       2        2
      Related to Use of Maximum / Minimum Value
❖ Solve: cos   50
                    x − sin   50
                                   x=1
                              Quiz – 02
❖ No of solutions of the equation sin(e ) = 5 + 5
                                      x     x    −x
                                                      are-   [1991, 2M]
   (a) 0
   (b) 1
   (c) 2
   (d) Infinity
          Related to Use of Maximum / Minimum Value
                                                                                         π
❖ Determine the range of the value of k if sin−1    2             −1
                                                   x + 2x + 2 + tan     2
                                                                       x − 3x − k   2
                                                                                        > .
                                                                                         2
       Solution to Pair of Trigonometric Equation with Two Variables
❖ Solve: 5 sin x cos y = 1 and 4 tan x = tan y.
                            Related to Proof
❖ If the roots of the equation a tan θ + b sec θ = c are α, β , then prove that
                   2ac
    tan α + β =                                                              [BUET’19-20]
                  a2 −c2
 Matrix &
Determinant
     Discussions Related to Matrix, Order of Matrix & Classification of
                                  Matrix
❖ Symmetric Matrix:
❖ Skew-Symmetric Matrix:
      Discussions Related to Matrix, Order of Matrix & Classification of
                                   Matrix
                                                                   2 3
❖ If A is a symmetric and B is a skew-symmetric matrix and A + B =      , then
                                                                   5 −1
   the value of AB is-                                          [2019 Main, 12 April I]
       −4 −2
   (a)
       −1 4
        4   −2
   (b)
       −1   −4
       4 −2
   (c)
       1 −4
       −4    2
   (d)
        1    4
     Discussions Related to Matrix, Order of Matrix & Classification of
                                  Matrix
         a     b    c
❖ If A = b     c    a where a, b, c are positive real numbers, abc = 1 and A A = I, then
                                                                            T
         c     a    b
  determine   the   value of a + b + c .
                              3    3    3
                                                                              [2003, 2M]
           Some Properties of Diagonal Matrix
         i 0 0
❖ If A = 0 i 0 , then σk=1 A =?
                       100 k
         0 0 i
                Related to Trace of Matrix
        2
         k  7    5
❖ If A = 4 9k   −6 and Trace(A) = 0 , then k =?
         −3 2   14
                   Related to Matrix Equity
            x+y        −6         −3   a+b
❖ Given A =               and B =          , where A + B = I. What are the
                                                    T   T
             ab         7         −9   x+y
  values of a and b?                                                 [IUT’21-22]
  (a) 3, −3
  (b) −3, −3
  (c) 3, 3
  (d) −3, 3
                Related to value Determination
❖ Two matrix will be multipliable if the no. of columns of the first matrix is equal to
  the no. of rows of the second matrix. If the order of matrix A is m × n and order of
  matrix B is n × p , then AB is multipliable but BA is not multipliable. The order of
  matrix AB will be = m × p
❖ If the orders of matrices A, B and C are 4 × 5, 5 × 4 and 4 × 2 then the order of
  matrix (A + B)C will be-
            T
                                                  [BUET’10-11, BUTEX’ 15-16, IUT'18-19]
    (a) 5 × 4
    (b) 4 × 2
    (c) 5 × 2
    (d) 2 × 5
                     Matrix Multiplication
❖ If A and B are two matrices, AB = B and BA = A, then A + B =?
                                                      2    2
   (a) I
   (b) AB
   (c) A − B
   (d) A + B
                   Related to value Determination
                        1   n
❖ Given the matrix, A =       , what is the resultant matrix A ?
                                                              n
                                                                   [IUT’21-22]
                        0   1
               n
       1   n
   (a)
       0   1
               2
   (b) 1 n
       0 1
       n   n
   (c)
       0   n
       n   n
   (d)
       0   1
                    Related to value Determination
           cos α      − sin α                               0   −1
❖ Say, A =                    , (α ∈ R) which satisfies A =
                                                         32
                                                                   . Then one of the
           sin α       cos α                                1    0
   value of α is-                                                 [2019 Main, 8 April I]
         π
   (a)
         32
   (b) 0
         π
   (c)
         64
         π
   (d)
         16
           Related to the Entries of Matrices
         4 3          10   17
❖ If A =     and AB =         , then determine the entries of matrix B.
         2 1          4    7
                                                       [BUET’16-17, RUET'09-10]
             Related to the Entries of Matrices
     4       −4 8 4
❖ If 1 × A = −1 2 1 , then determine the matrix A.   [BUET’17-18]
     3       −3 6 3
           Related to the Entries of Matrices
         2 1      −2   1            −2    4
❖ If A =     ,C =         and ABC =         , then B =?   [BUET'20-21]
         3 2       5   −2            3   −1
                Singular/Non-Singular Matrix
❖ Singular Matrix:
                 6       −3
   Example: A =
                −16       8
❖ Non-Singular Matrix:
                1 2
   Example: A =
                5 8
                 Singular/Non-Singular Matrix
     k k      2
❖ If             is a real matrix. For which value of k the matrix won’t be invertible?
      2        k
                                                               [KUET'12-13, SUST’17-18]
  (a) −2
  (b) 2
  (c) ±2
  (d)     2
  (e) − 2
            Minor and Cofactor of Determinant
                                                       2 3 −1
❖ Determine the minor and cofactor of the (3,2) entry 5 6 0 .
                                                      −2 1 4
                   Minor and Cofactor of Determinant
❖ What is the cofactor of (−2a) of the determinant below?   [KUET'11-12, RUET’14-15]
         2         2
    1+a −b                2ab                 −2b
                           2   2
      2ab               1−a +b                 2a
                                                2  2
      2b                  −2a               1−a −b
   (a) 1 − a   4            2
                       −b 4−b           2
   (b) 2a(1 + a + b )
                   2            2
                             3
   (c) 1 + a + b
             2             2
   (d) (1 + a + b )
               2           2
   (e) −2a(1 + a + b ) 2            2
                            Inverse Matrix
                                                       1
❖ If A is a Non-Singular square matrix , then A
                                              −1
                                                   =       adj A
                                                       A
         0    1 2
❖ If A = 1    2 3 and B = A , then b23 =?
                           −1
                                                                   [IUT'17-18]
         3    1 1
   (a) 1
   (b) 2
   (c) −1
   (d) −2
                             Inverse Matrix
❖ Two matrices A and B are given. Determine the relation between AB and BA (if they
   have any). Represent B   −1
                                 in terms of x and A.                  [BUET'19-20]
        3x −4x       2x        x           2x −2x
   A = −2x  x        0 and B = 2x          5x −4x
       −x  −x         x        3x          7x −5x
                              Inverse Matrix
              5   1
              7   7
❖ If A
     −1
          =   3   2   , then determine the value of A + 2A.
                                                    2
                                                              [BUET'18-19]
              7   7
                          Inverse Matrix
                          4   5   0   0
                          3   4   0   0
❖ Find the inverse of A =                                           [IUT’21-22]
                          0   0   3   2
                          0   0   4   3
         1   1                                  1
                 0 0                                 −5   0    0
         4   5                                  4
         1   1                                       1
                 0 0                            −3        0    0
         3   4                                       4
   (a)           1   1                    (b)             1
         0 0                                    0    0         −2
                 3   2                                    3
                 1   1                                         1
         0 0                                    0    0    −4
                 4   3                                         3
        4 −3 0   0                            4 −5 0  0
       −5 4   0  0                            −3 4  0 0
   (c)                                    (d)
        0  0  3 −4                            0  0  3 −2
        0  0 −2 3                             0  0 −4 3
                       Inverse Matrix
     1    1 1    2 1 3     1   n−1   1   78
❖ If       ⋅      ⋅    ………         =        then what is the inverse
     0    1 0    1 0 1     0    1    0   1
            1    n
  matrix of        ?                                [2019 Main, 0 April I]
            0    1
      1 0
  (a)
      12 1
      1    −13
  (b)
      0     1
       1   0
  (c)
      13   1
      1 −12
  (d)
      0  1
         Condition for Value of Determinant to be Zero
     1 0 10                      2 −5 18
❖   −1 0 8 =?                ❖   2 −5 −9 =?
     2 0 11                      2 −5 27
     1   5 10                     2    6   18
❖   −1   3 8 =?              ❖   −1   −3   −9 =?
     2   6 11                     3    9   27
        Determination of the Value of the Determinants
                             3  0   0 −2    4
                             0  2   0 0     0
❖ Determine the value of:    0 −1   0 5    −3            [RUET’15-16]
                            −4 0    1 0     6
                             0 −1   0 3     2
         Determination of the Value of the Determinants
                                        0   0   1
                     0   1
❖ If J1 = 1 ; J2   =       = −1; J3   = 0   1   0 = −1, then what is the value of
                     1   0
                                        1   0   0
    J100 =?                                                               [IUT’21-22]
        Determination of the Value of the Determinant
     x−4  2x  2x
❖ If 2x  x−4  2x = A + Bx x − A     2
                                        then value of (A, B) is-
      2x  2x x−4
                                        [BUET’22-23 (Collected), JEE Main 2018]
  (a) (−4, −5)
  (b) (−4, 3)
  (c) (−4, 5)
  (d) (4,5)
        Determination of the Value of the Determinant
                 2   2 2ab      2b
              1+a −b
❖ Prove that:   2ab     2
                     1−a +b 2
                                −2a            2   2 3
                                       = (1 + a + b )
                                 2   2
                −2b    2a     1−a −b
                                                 [KUET’03-04, 04-05, 11-12]
         Related to the Determinant of a Square Matrix
❖ If A is a 3 × 3 matrix and A = −7 then what is the value of   2A   −1
                                                                          ?
   (a)   pA    =p A   n
                            1
   (b)   pA   −1
                   =
                          pn A
                          p n
   (c)    −1
         pA        =
                          A
                 −1             A
   (d)   pA   −1
                          =
                                pn
                          1
   [Note: A   −1
                   =            ]
                          A
         Related to the Determinant of a Square Matrix
         3 −4
❖ If A =      then what is the value of det 2A ?
                                              −1
                                                         [DU’19-20]
         2 −3
   (a)   pA    =p A   n
                            1
   (b)   pA   −1
                   =
                          pn A
                          p n
   (c)    −1
         pA        =
                          A
                 −1             A
   (d)   pA   −1
                          =
                                pn
                          1
   [Note: A   −1
                   =            ]
                          A
        Related to the Determinant of a Square Matrix
❖ If A is matrix of order 4 × 4 and   T
                                      A A A = A   P
                                                      then what is the value of p?
                            Quiz – 03
         α   2
❖ If A =       and A = 125 then the value of α is-
                    3
                                                     [2004, 1M]
         2   α
   (a) ±1
   (b) ±2
   (c) ±3
   (d) ±5
           Related to the Determinant of a Square Matrix
❖ Say P = aij is a 3 × 3 matrix and Q = bij where bij = 2i+j
                                                               aij (1 ≤ i, j ≤ 3) if
   det(P) = 2 , then det Q =?                                           [JEE Main 2012]
   (a) 2
       10
   (b) 2   11
   (c) 2
       12
   (d) 2   13
      Related to the Determinant of a Square Matrix
          7 3 1
❖ If A = 5 2 −4 , then i adj A   =? and ii adj adj A   =?
         12 5 −2
     Related to the Solution of Equations Containing Determinants
           x+4  3   3
❖   Solve:  3  x+4  5 = 0 [RUET’04-05, KUET’04-05, CUET’13-14, BUET’01-02,13-14]
            5   5  x+1
     Solution to Equations Using the Concept of Inverse Matrix
❖ Concept of Solution Using Inverse Matrix:
  a1 x + b1 y + c1 z = d1          a1   b1        c1       x       d1
❖ a2 x + b2 y + c2 z = d2 Say, A = a2   b2        c2 ; x = y ; B = d2
  a3 x + b3 y + c3 z = d3          a3   b3        c3       z       d3
   Here, AX = B ⇒ A  −1         −1           −1          −1
                          AX = A B ⇒ A A X = A B ⇒ IX = A B ⇒ X = A B   −1   −1
   2x + y + 3z = 13
❖ x − y + 6z = 17 Solve the equations. (Home Work)
  5x + 10y − 6z = 7
      Solution to Equations Using Determinants (Cramer’s Rule)
                       a1 x + b1 y + c1 z = d1
❖ Solve the equations: a2 x + b2 y + c2 z = d2
                       a3 x + b3 y + c3 z = d3
        a1    b1      c1        d1        b1   c1        a1   d1   c1        a1   b1   d1
    D = a2    b2      c2 , Dx = d2        b2   c2 , Dy = a2   d2   c2 , Dz = a2   b2   d2
        a3    b3      c3        d3        b3   c3        a3   d3   c3        a3   b3   d3
          Dx          Dy             Dz
    ∴x=      ,y   =        and z =
          D           D              D
❖ Solve using Determinants: x + 2y−z = 5, 3x−y + 3z = 7, 2x + 3y + z = 11
                                                                                  [BUTEX’10-11]
      Solution to Equations Using Determinants (Cramer’s Rule)
❖ Say, λ ∈ ℝ and x + y + 7 = 6, 4x + λy − λz = λ − 2 and 3x + 2y − 4z = −5 equation
   system has infinite amounts of solutions, λ is the root of which of the following
   equation?                                                     [2019 Main, 10 April II]
   (a) λ − 3λ − 4 = 0
        2
   (b) λ + 3λ − 4 = 0
        2
   (c) λ − λ − 6 = 0
        2
   (d) λ + λ − 6 = 0
        2
       Solution to Equations Using Determinants (Cramer’s Rule)
❖ If the roots (x, y, z) of the system of equations x + ky + 3z = 0, 3x + ky − 2z = 0,
                                                               xz
    2x + 4y − 3z = 0 are non zero, then what is the value of      ?          [2018 Main]
                                                               y2
    (a) −10
    (b) 10
    (c) −30
    (d) 30
Characteristic Equation of Matrix
             Characteristic Equation of Matrix
                           0   1   0
❖ Show that the matrix A = 0   0   1 , satisfies the equation λI − A = 0. Hence
                           1   0   0
  find A .
        12
                                                                         [BUET’21-22]
              Characteristic Equation of Matrix
         1 2
❖ If A =      is a matrix, then determine the value of A − 4A + 8A − 12A +
                                                        6    5    4     3
         −1 3
      2
   14A .