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#Include #Include Using Namespace STD

The provided C++ code checks if a given integer 'n' can be expressed in a specific mathematical form involving two variables 'i' and 'j'. It iterates through possible values of 'i' and 'j' up to the square root of 'n', and prints 'YES' if a valid combination is found, otherwise it prints 'NO'. However, the code has a logical flaw as it does not break out of the outer loop upon finding a solution.

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Da Hood
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23 views1 page

#Include #Include Using Namespace STD

The provided C++ code checks if a given integer 'n' can be expressed in a specific mathematical form involving two variables 'i' and 'j'. It iterates through possible values of 'i' and 'j' up to the square root of 'n', and prints 'YES' if a valid combination is found, otherwise it prints 'NO'. However, the code has a logical flaw as it does not break out of the outer loop upon finding a solution.

Uploaded by

Da Hood
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as TXT, PDF, TXT or read online on Scribd
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#include <iostream>

#include <bits/stdc++.h>
using namespace std;

int main(){
int n, i, j;
cin >> n;

for(i = 1; i < sqrt(n); i++){


for(j = 1; j < sqrt(n); j++){
if(n == (i+j)*(i*i-i*j+j*j)){
cout << "YES";
break;
}
}
}
cout << "NO";
}

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