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PK Calculations

The document contains pharmacokinetic calculations for various scenarios including dosage calculations for adrenaline, infusion rates for saline, iron requirements for patients, and drug clearance and volume of distribution. Key calculations include determining the volume required for specific doses, infusion rates in drops per minute, and pharmacokinetic parameters such as half-life and bioavailability. The document provides specific answers for each calculation based on given data.

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barmananubhab00
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13 views25 pages

PK Calculations

The document contains pharmacokinetic calculations for various scenarios including dosage calculations for adrenaline, infusion rates for saline, iron requirements for patients, and drug clearance and volume of distribution. Key calculations include determining the volume required for specific doses, infusion rates in drops per minute, and pharmacokinetic parameters such as half-life and bioavailability. The document provides specific answers for each calculation based on given data.

Uploaded by

barmananubhab00
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as PDF, TXT or read online on Scribd
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Pharmacokinetic Calculations

• 1. ADRENALINE IS AVAILABLE AS 1 ml AMPOULE IN THE STRENGTH


OF 1:1000 SOLUTION. CALCULATE THE VOLUME REQUIRED TO
ADMINISTER 0.5 mg.
• Ans.Concentration of adrenaline: 1:1000 solution, meaning 1 gram of
adrenaline is present in 1000 ml of solution.

• Ans- 0.5ml
2. IT HAS BEEN PRESCRIBED TO INFUSE 1 LITRE OF NORMAL SALINE
OVER 8 HOURS USING A MACRO DRIP SET. CALCULATE THE RATE OF
INFUSION i.e., NUMBER OF DROPS PER MINUTES.
• Ans.Drip factor of macro drip set = 20 drops/ml

• Ans. 42drops/min
3. A male patient weighing 50 kg with Hb 9.3 g/dl, calculate the parenteral
iron requirement of the patient.

4. A female patient weighing 56 kg with Hb 8 g/dl, calculate the parenteral


iron requirement of the patient.
• 3. Iron requirement (mg)=4.4×(body weight (kg)×(15−Hb (g/dL))

• 4.Iron requirement (mg)=4.4×(Ideal body weight (kg)×(14−Hb (g/dL))


• 5. ADRENALINE IS AVAILABLE AS 1 ml AMPOULE IN THE STRENGTH
OF 1:10000 SOLUTION . CALCULATE THE VOLUME REQUIRED TO
ADMINISTER 0.5 mg.
• Concentration of adrenaline: 1:10,000 solution. This means 1 gram of
adrenaline is present in 10,000 ml of solution, or equivalently, 0.1 mg per
ml.

• Ans. 5ml
• 6. IT HAS BEEN PRESCRIBED TO INFUSE 500 ml OF NORMAL SALINE
OVER 8 HOURS USING A Micro DRIP SET. CALCULATE THE RATE OF
INFUSION i.e., NUMBER OF DROPS PER MINUTES.
• Drip factor for micro drip set- 60drops/ml

• Ans. 63drops/min
• 7. A drug has a half-life of 4 hours. If the initial concentration of the drug in
the plasma is 100 mg/L, what will be the plasma concentration after 12
hours?
• 12.5mg/L
• 8. A patient receives a dose of 500 mg of a drug. The plasma
concentration immediately after the dose is 5 mg/L. What is the volume of
distribution (Vd) of the drug?
• Ans. 100L
• 9.A drug has a half-life of 6 hours. If the volume of distribution is 120 L,
calculate the clearance of the drug.
• Cl= 0.693* Vd/t1/2= 0.693*120/6= 13.86L/h
• 10.A drug is administered intravenously at a rate of 20 mg/h. The volume
of distribution is 50 L, and the clearance is 5 L/h. What is the steady-state
concentration (Css) of the drug?
• Steady state conc= drug infusion rate/ clearence= 4mg/L
• 11.A drug has a volume of distribution (Vd) of 25 L, and the desired
plasma concentration is 10 mg/L. Calculate the loading dose (LD) required
to achieve this concentration.
• Ans LD= C* Vd= 10*25= 250mg
• 12.A drug is administered orally, and its peak plasma concentration is
found to be 50 mg/L. When the same drug is given intravenously, the peak
plasma concentration is 100 mg/L. What is the bioavailability of the drug?
• Ans F= C oral/ C IV= 50/100 =0.5 Thus, the bioavailability is 0.5 or 50%.
• 12.A drug has a volume of distribution of 60 L and a half-life of 8 hours.
Calculate the elimination rate constant and clearance of the drug.
• Ans.

• k= 0.693/t1/2= 0.0866/hr

• Cl= k* Vd= 5.196L/h

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