Vidyamandir Classes: Innovating For Your Success

Selection Test | Paper 1 | JEE 2022

General Instructions
1. Date : 14/11/2021
The test is of 3 hours duration and the maximum marks is 198. Maximum Marks : 216

2. The question paper consists of 3 Parts (Part I: Physics, Part II: Chemistry, Part III: Mathematics). Each Part
Duration: 3.0 Hrs
has Three sections (Section 1, Section 2 & Section 3).
General Instructions
3. Section 1 contains SIX (06) 1. questions. The is
The test answer to each
of 3 hours question
duration a SINGLE
andisthe maximum DIGIT
marksINTEGER
is 198.ranging from
0 TO 9. BOTH INCLUSIVE.
2. The question paper consists of 3 Parts (Part I: Physics, Part II: Chemistry, Part III: Ma
4. Section 2 contains 6 Multiple Correct Answers
General
has Three Type (Section
Questions.
Instructions
sections Each question
1, Section has 43).choices (A), (B), (C) and
2 & Section
(D), out of which ONE OR MORE THAN ONE CHOICE is correct.
1. The test is of 3 hours duration3. and the Section
maximum 1 contains
marks SIX (06) questions. The answer to each question is a SINGLE DIGIT
is 216.
5. Section 3 contains 6 Numerical Value 0 TO Type
9. BOTHQuestions.
INCLUSIVE.The answer to each of the question is a numerical
2.  Thvalue.
e question paperquestion,
For each 3 Parts
consists ofenter the(Part I: Physics,
correct II: Chemistry,
Part value
numerical Part III:IfMathematics).
of the answer. the answer isEach Part
a decimal
has TWO sections (Section 4. 1, SectionSection
2). 2 contains 6 Multiple Correct Answers Type Questions. Each question has 4 c
numerical value, then round-off the value to TWO decimal places. If the answer is an Integer value,
(D), out of which ONE OR MORE THAN ONE CHOICE is correct.
then do
3. Section not add10
1 contains zero in theCorrect
Multiple decimalAnswers
places. In theQuestions.
Type OMR, do not Eachbubble
question  sign
thehas for positive
4 choices (A), (B),values.
(C)
and (D), outfor
However, of which ONE
negative OR MORE
values,
5. Θ sign THAN
should
Section ONE CHOICE
be bubbled.
3 contains is correct.
(Example:
6 Numerical 6, 81,
Value 1.50,
Type 3.25, 0.08)The answer to each of the que
Questions.
4. Section 2 contains 8 Numerical Valuevalue.
Type For each question,
Questions. The answerenterto the correct
eachseparately. numerical
of the question avalue
is fill of the answer. If the a
numerical
6. For answering a question, an ANSWER SHEET (OMR SHEET) is provided Please your Test Code,
numerical value,value
thenofround-off the value to TWO decimal places. If the answer i
value. For each
Roll No. question,
and Group enter the
properly correct
in the space numerical
given in the ANSWER SHEET.If the answer is a decimal numerical
the answer.
value, then “Truncate/Round off ” the value
then do tonotTWOadd decimal
zero in the places. If theplaces.
decimal answerInis the
an Integer
OMR, do value,
not then
bubble the  sign
do not add zero in the decimal places. However, for negative values, Θ sign should be bubbled. (Example: 6,for
In the OMR, do not bubble the Å sign for positive values. However, 81, 1.50, 3.25, 0
negative values, Θ sign should be bubbled. (Example: 6, 81, 1.50, 3.25, 0.08)
6. For answering a question, an ANSWER SHEET (OMR SHEET) is provided separately. Plea
5.  For answering a question, an ANSWER SHEET (OMR SHEET) is provided separately. Please fill your Test
Roll No. and Group properly in the space given in the ANSWER SHEET.
Code, Roll No. and Group properly in the space given in the ANSWER SHEET.

VMC | JEE-2021 | Paper-2 1 JEE Advanced Final Practice Test-6

 SECTION - 1 (Maximum Marks: 40)
   This section consists of TEN (10) Questions. Each question has FOUR options. ONE OR
MORE THAN ONE of these four option(s) is(are) correct answer(s).
  Answer to each question will be evaluated according to the following marking scheme:
Full Marks: +4 If only (all) the correct option(s) is(are) chosen
Partial Marks: +3 If all the four options are correct but ONLY three options are
chosen
Partial Marks: +2 If three or more options are correct but ONLY two options are
chosen and both of which are correct
Partial Marks: +1 If two or more options are correct but ONLY one option is
chosen, and it is a correct option
Zero Mark: 0 if none of the options is chosen (i.e. the question is unanswered)
Negative Marks: –1 In all other cases.

SECTION - 2 (Maximum Marks: 32)

   This section has EIGHT (08) Questions. The answer to each question is a NUMERICAL
VALUE.
  For each question, enter the correct numerical value of the answer using the mouse and the
on-screen virtual numeric keypad in the place designated to enter the answer. If the numer-
ical value has more than two decimal places, truncate/round-off the value of TWO decimal
places.
   Answer to each question will be evaluated according to the following marking scheme:
Full Marks: +4 If ONLY the correct numerical value is entered.
Partial Marks: 0 In all other cases.
Target : JEE (Main + Advanced) 2020/08-09-2020/Paper-2
ALLEN Target : JEE (Main + Advanced) 2020/08-09-2020/Paper-2
ALLEN
SOME USEFUL CONSTANTS
SOME USEFUL CONSTANTS
Atomic No. : H = 1, B = 5, C = 6, N = 7, O = 8, F = 9, Al = 13, P = 15, S = 16,
Atomic No. : H = 1, B = 5, C = 6, N = 7, O = 8, F = 9, Al = 13, P = 15, S = 16,
Cl = 17, Br = 35, Xe = 54, Ce = 58
Cl = 17, Br = 35, Xe = 54, Ce = 58
Atomic masses : H = 1, Li = 7, B = 11, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24,
Atomic masses : H = 1, Li = 7, B = 11, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24,
Al = 27, P = 31, S = 32, Cl = 35.5, Ca=40, Fe = 56, Br = 80, I = 127,
Al = 27, P = 31, S = 32, Cl = 35.5, Ca=40, Fe = 56, Br = 80, I = 127,
Xe = 131, Ba=137, Ce = 140,
Xe = 131, Ba=137, Ce = 140,
· Boltzmann constant k = 1.38 × 10–23 JK–1
· Boltzmann constant k = 1.38 × 10–23 JK–1
g = 10 m/s^2 unless stated otherwise 1
1 = 9 ×10 9
9
· Coulomb's law constant
· Coulomb's law constant 4 pe0 = 9 ×10
4 pe0
· Universal gravitational constant G = 6.67259 × 10–11 N–m 22 kg–2
· Universal gravitational constant G = 6.67259 × 10 –11
N–m kg–2
· Speed of light in vacuum c = 3 × 1088 ms–1
· Speed of light in vacuum c = 3 × 10 ms–1
· Stefan–Boltzmann constant s = 5.67 × 10–8 Wm–2 –K–4
· Stefan–Boltzmann constant s = 5.67 × 10–3
–8
Wm–2 –K–4
· Wien's displacement law constant b = 2.89 × 10–3 m–K
· Wien's displacement law constant b = 2.89 × 10 m–K
· Permeability of vacuum µ0 = 4p × 10–7 NA–2
· Permeability of vacuum µ0 = 4p × 10–7 NA–2
1
· Permittivity of vacuum Î0 = 1 2
· Permittivity of vacuum Î0 = m 0 c 2
m0c
· Planck constant h = 6.63 × 10–34 J–s
· Planck constant h = 6.63 × 10–34 J–s
Space for Rough Work
 (b) Assuming no temperature change and
atmospheric pressure to be Po, find the Where DP is pressure difference at the two ends of
surface tension of the soap solution. the tube and h is coefficient of viscosity. Assume
Q.23. In the last problem, one aof the bubbles supplies Vidyamandir
Vidyamandir Classes Classes that the bubble remains spherical.
its entire air to the other bubble and a film of soap Q.27. Two blocks are floating in water. When they are
solution is formed at the end of the straw whichÞ brought sufficiently close they are attracted to
keeps it closed. What is the radius of curvature each other due to surface tension effects. When
of this film if the bigger bubble has grown in size the experiment is repeated after replacing water
a Target a: JEE (Main + Advanced) 2020/18-09-2020/Paper-1
ALLENand its radius has become R3. with mercury, once again the two blocks are
SECTION-I(ii) : (Maximum Marks: attracted.32) Explain the phenomena. It is given that
1
een the ˜
LeveL 3This section
(A) 2U 0
Mathematics
(B) Properties
contains EIGHT0 questions.
2 2U Part of Matter
Test
Physics Selection Test 1
-
(C) 4 Question
|2U JEE
0 water SET
Advanced-2020
wets 2 material
(D)
the U0 of the block where as
at point 2
˜ Each question Matrices has FOUR options
& Determinants, Film of soap for correctProbability, answer(s). mercury
Vectors ONE doesOR
& MORE THAN ONE of
not.
3D-Geomatry
4.3. these
Q.1:
Q.24. Consider
With anfouraim option(s)
a rain
ofdropdeterminingis (are)
falling the correct
at terminal solution
magnetic speed. option(s).
For
moment of
Q.5:a permanent
Q.28. A long thin magnet stringa hassimplea coatexperimental
of water on set it. The
r2 = r. ˜ For
whateach radiusquestion,
(R) of the TIME choose
drop : 3SECTION
can the correct- 1the
we disregard
hrs (Maximum
option(s) Marks:
to answer 40)
the question.
radius of the water cylinder is r. After some time
M.M. : 236
up has been used in on which a small cylindrical
tension magnet of radius r0 having magnetic moment M is
terface Answer
˜    influence
This to each
of gravity question
its shape? will be
Surface
section consists of TEN (10) Questions. Each questionevaluated according to the
it was found
hasfollowing
that
FOUR marking
the string
options. had ONE scheme:
a series ORof equally
and density
Full
placed Rat
Marks 3 theof water
center : +4
areofT If
and
a r
only
circular (all)
respectively.
coil theof correct
radius r option(s)
and having
spacedis n(are)
turn
identicalchosen.
of wires.
water The
drops length
on it.of the the
Find
MORERead THAN theONE followingof theseInstructions
four option(s) very carefully
is(are) correctbefore answer(s). you proceed.
Partial Marks each:radius
+3 IfR to
all the four options are correct to&but ONLY three optionsscheme:area chosen.
sts and Q.25. A soap bubble minimum distance between two successive drops.
Q.2: magnet
   Answer to has
is question
perpendicular question andthe thickness
will be
plane of
evaluated its
the according
of(Section coil. Further the
the following
coil marking
is connected to ballistic
le find 1.
Partial
This
wall is a.Marks Calculate: the +2 apparent
paper
If threeweight
consists of
or more
3 (= options
sections true are
I,
correct
Section
Q.29.
Q.6:
II
but having
Section
A liquid ONLY surface
III).
two options
tensionare T andchosen,
density r
en that galvanometer.
Full Marks:
weight - Buoyancy) of both
2. Section I The
contains total
3 resistance
the bubble
types of +4
of which
questions Ifofonlythe coil,
(all) connecting
the
are correct options.
if surface
[Type 1, Type correct
2 & Typeis in contact with a vertical solid wall. TheOn
3]wires
option(s) and the
is(are) galvanometer
chosen is R. liquid
R and of: the
+1 If two or
tension
Partial
sudden of
Partial soap
Marks
removal
Type
solution
1Marks: 
contains
and
magnet
10 Single
its
+3 more
density
from
Correct Ifare
its T options
and
all position
Answer theTypefour are
aoptions correct
charge
Questions.
surface
are
Each q flowsbut through
gets
correct
question ONLY
curved
but4ONLY
has one
as option
shown in
the galvanometer.
choices three is and
the
(A), (B),options
(C) chosen
figure.
are the
At
Find
(D), V
d respectively. The atmospheric andCHOICE pressure
it is is
isacorrect.
correct0 option.
P bottom the liquid surface is flat.
the
and magnetic
density of moment
out of which ONLYofONE
atmospheric the
air magnet.
is r
chosen
. By (r >> r0)
assuming
Zero Marks –6 Marking : 0 If
scheme none
[3
0
Marksof the
for options
Correct answer is chosen The(i.e.
& –1 NEGATIVE the
atmospheric
MARKING question
pressure
for wrongisis unanswered).
o.
Panswer]
a = 10 Partial = 10 cm, P0 = 105 Nm
m, RMarks:  –2
+2 If, rthree 0 = 1.2 or more options are correct but ONLY two options are
Negative Marks : –1 In all other cases.
kg m–3, Type d = 10 3
kg m–3,20T Multiple
= 0.04 Nm –1
chosen ; show and that Type of
areboth which are
2 contains Correct Answer Questions. Eachcorrect
question has 4 choices (A), (B), (C) and
˜ For Example : If first, third and fourth thedxONLY three correct
A options for a question with
the weight of the bubble is mainly because of
x be correct.
second option being an incorrect option; selecting only all arethe threebut correct options will result
(D), out of which ONE OR MORE CHOICES may
water Partial Marks: 
inthe skin. What scheme
is weight of+1 theIffor two
bubble? or more options correct ONLY one h option is
in +4 marks. Selecting only twochosen, of the and three correct options (e.g. the first and fourth options),
Marking [4 Marks All Correct answers & –1 NEGATIVE MARKING for wrong answer]
Q.26. without
A soap Type bubble is blown atincorrect
the end ofoption aBased
capillary
it is a correct option
Q.3: selecting
3 contains any
FIVE paragraphs. (second
on option in there
these paragraphs, this arecase),TEN will result
questions. Eachinquestion
+2 marks. has
R1) are
tube Zero
Selectingof
FOUR Mark:
radius
only a and length
one(A),
options of (B), L.
the(C) When
threeand 0 if ONLY
the
correct
(D). noneONE
other of the
end
options options
(either
of these isfirst
four optionschosen
or (i.e. the
third
is correct. question
or fourth is unanswered)
option), without
is leftqrR open, the bubble begins to deflate. Write
bble to selecting  any Marks:
Negative incorrect option (second
–1 In option in 2qrRthis
& –1case), willMARKING
result in for+1 marks. Selecting
as a qr 0R of all other cases. 2qr 0R
Marking scheme [3 Marks for Correct answer NEGATIVE wrong answer]
the radius of the
(A) bubble (B) function time if (C) (D)
mains. any incorrect
m0Section
n radius option(s) (second option in this case), with or without selection of any correct
the initial
3. of the bubble
II contains 2mwas
16 Single 0 n Integer
R0. Surface Value Type Questions. m0 n (i) The Findanswer
the pressure m 0innof
to each thetheliquid at the top
questions is aof the
option(s) will result in –1 marks.
tensionsingle-digit
of soap solution is T. Itfrom
integer, ranging is known0 to 9 (both that inclusive). meniscus (i.e. at A)
1. The
5.4. volume rightflow endrate ofthrough
a string is [4tied
a tube to for
of radius a ring a and that can&slide NO (ii) withoutMARKING friction for upwrong
and down the rod,
Marking scheme Marks
Space
Correct
for
answer
Rough Work
NEGATIVECalculate the difference inanswer]
height (h) between
left end of the string is
length L is given by Poiseuille’s equation- tied, rigidly to another rod. Two pulses are sent along the string
thequestion
bottom and top ofstatements
the meniscus.
toward
4. 4the right
Section
p a DP rod,
III contains the pulses
4 Match reflects
the columns fromtyperight rod
questions. and
Each then from left
contains rod and so on.
givenAtina
given
Q = point 2 columns.of time the string’s
Statements in the first appearance
column haveisto illustrated
Q.7:
Q.30. Is it in
be matched the
possible
with figure
statements below.
that water The column.
evaporates
in the second string’sfrom a
appearance h L answers
8The at a later
to these point
questions after have complete or partialbubbled
to be appropriately reflection
spherical in the may
drop
answer of be:
water
sheet.just by means of surface
energy supplying the necessary latent heat of
 Marking scheme [8 Marks if you darken ALL the bubbles corresponding ONLY to the correct
L vaporisation? The drop does not use its internal
answer or given 2 MarksReach for correct bubbling of answer in any row. No Negative mark will be
2a
0
thermal energy and does not receive any heat
given for an incorrectly bubbled answer]
from outside. It is known that water drops of
ut ? 5. For answering a question, an ANSWER SHEET (OMR SHEET) size less than 10–6separately.
is provided m do not exist.PleaseLatent
fill your heat of Q.32. A
Test Code, Roll No. and Group Properly in the space given invaporisation the ANSWER of SHEET.water is L = 2.3 × 106 Jkg–1 and a
e and i
surface tension is T = 0.07 Nm–1.
nd the Where DP is pressure difference at the two ends of t
the tube and h is coefficient of viscosity. Assume Q.31. In the arrangement shown in the figure, A is a jar
Q.8:
t
upplies (A)
that the bubble remains spherical. (B) half filled with water and half filled with air. It
is fitted with a leak proof cork. A tube connects
of soap Q.4:
Q.27. Two blocks are floating in water. When they are
it to a water vessel B. Another narrow tube
which brought sufficiently close they are attracted to
rvature E-4/28 fitted to A connects it to1001CJA102120126 a narrow tube C via
VMC | each
Finalother due to surface
Advanced Test 7 tension effects. When 4 a water monometerJEE ADVANCED
M. The tip of the tube 2021 C is
in size the experiment is repeated after replacing water
(C) (D) just touching the surface of a liquid L. Valve V
with mercury, once again the two blocks are
is opened at time t = 0 and water from vessel B
attracted. Explain the phenomena. It is given that
pours down slowly and uniformly into the jar A.
water wets the material of the block where as
Space for Rough Work An air bubble develops PartatTest-4
the tip| JEE-2020
of tube C. The
mercury does not.
VMC | Mathematics 1
Q.33. A
cross sectional radius of tube C is r and density of
Q.28. A long thin string has a coat of water on it. The water is r. The difference in height ofJEE water2022(h) in c
VMC || Physics
VMC Selection Test
Assignment 1
1 PhysiCs
radius of the water cylinder is r. After some time the two arms of the manometer varies with time i
it was found that the string had a series of equally 't' as shown in the graph. Find the surface tension d
spaced identical water drops on it. Find the of the liquid L. t
minimum distance between two successive drops. t
 PART-1 : PHYSICS
SECTION-I(i) : (Maximum Marks: 32)
˜ This section contains EIGHT questions.
˜ Each question has FOUR options for Leader answer(s).
Vidyamandir
correct & Enthusiast
ClassesCourse/Score(Advanced)/18-09-2020/Paper-1
ONE OR MORE THAN ONE of
ALLEN
6.5. The these fourprocess
cyclic option(s)C1 : is (are) correct
1–2–3–4 & C2 : option(s). Leader & Enthusiastare
2–3–4–A–B–C–2 Course/Score(Advanced)/18-09-2020/Paper-1
performed over one mole of an
ALLEN
˜ For each
idealcyclic question,
monoatomic choose the correct option(s) to answer ofthe
the question.
6.5.2. The process gas C1 :(figure)
1–2–3–4 and &the C2 gas receives the amount
: 2–3–4–A–B–C–2 are performed heat Q1 from
over the heater
one mole of an
˜ Answer
in process toC each
& Q question
is the amount will be
of evaluated
heat received according
in process to
C .the
Q ' following
& Q ' are marking
the heat scheme:
rejected
ideal monoatomic 1 2gas (figure) and the gas receives the amount 2 of 1the heat 2 Q1 from the heater
Full
byprocess Marks
gas in C process : +4
C1the& C If only (all)
respectively the correct
& therefore option(s)
net heat is (are) chosen.
in & Q2 is amount
2 of heat received in process C2. absorbed
Q1' & Q2' are by the
the heat
gasesrejected
are in
CPartial
: DQ = Marks
Q
1
– Q ' &: that
+3 Ifinall C the
: DQ four
= Qoptions
– Q '. are correct
Efficiency of but
the ONLY
gas in C three
is h options
and in C are
it ischosen.
h2.
by1 gas 1in process1 1 C1 & C2 respectively 2 2 2 & therefore
2 net heat absorbed 1 by 1the gases 2 are in
Partial
Choose Marks : +2 If three or more options are correct but ONLY two options are chosen,
C : DQ1 the – Q1' & thatstatement(s).
= Q1CORRECT in C : DQ2 = Q Dotted
– Q2'.curve 2–B–4
Efficiency of shown
the gasisinan C1isotherm
is h1 and & C32 =
in T it 16T
is h21..
1
both2 of which 2
are correct options.
Choose the CORRECT statement(s). Dotted curve 2–B–4 shown is an isotherm & T3 = 16T1.
Partial Marks : +1 If two or more options are correct but ONLY one option is chosen
P
and it is a correct option.
Zero Marks : 0 If none Pof the 2 options3 is chosen (i.e. the question is unanswered).
T3
Negative Marks : –1 In all other cases. 2 3 Target : JEE (Main + Advanced) 2020/18-09-2020/Paper-1
ALLEN TONLY
˜ For Example : If first, third and fourth C are B the 3 three
Target : JEE (Main correct options
+ Advanced) for a question with
2020/18-09-2020/Paper-1
ALLEN second option being an incorrect option; selecting only all the three 330
correct m options will result
TC1 x2 + yB p
9. A source is moving in a circle given by 2
= R2 with a constant speed / s in clockwise
in +4 marks. Selecting only two of the 1 three
A 6
correct options (e.g. the first and fourth options),
9. A source is moving in a circle given by T1 x2 + y2 = R42 with a constant speed 330 p m / s in clockwise
without
sense. A selecting
detector isany incorrect
at rest at (2R, 0option
0).1Find (second
A the option
V in of
4coordinates thisthecase),
sourcewill result
6at the in +2
instant marks.
when
Selecting
the detector only one
records ofthe
sense. A detector is at rest at (2R,thesame three correct
frequency options
as that
0 0). Find the coordinates (either
of the first
source or third
(speed or
of fourth
sound =
of the source at the instant when option),
330 m/s) without
V
selecting
the detector any incorrect
records the option
same frequency(second option as thatinofthis the case),
sourcewill (speed result
of soundin +1=marks.330 m/s) Selecting
any 3R24 R öoption(s) (second
æincorrect æ 3R56Roption ö in this case), 8 with or without selection 23 of any correct
Q = Q
(A) çç 2 2 23, - 21 ÷÷
(A) (B) Q '
(B) çç 2 2 69 = Q
, ÷÷1 ' (C) D Q
(C) (0, 2R) 9= D Q (D) h
(D) (R, =
1 0) h
æè 3R24will
option(s) R öøresult in –1 æè 3R 56R
marks.2 öø 8
1
27 2
23
(A) Q
(A) çç 2 = , -Q1 ÷÷
2 23mass 2 (B) Q
(B) çç 2 ' = , Q÷÷1 '
2 69is
2
(C)
(C) D Q2R)
(0, = DQ1
9 v along a
(D)
(D) h 1= 0) h2
(R, 27
1. 7.
10. 3. A cube of m and
6. A point charge q is placed at a Space
è ø side
è 2a sliding
distance
ø with
forl Rough velocity
from centre Work frictionless,
of an uncharged conducting horizontal
sphere of floor.
The cube hits a very low step head-on and the leading edge comes abruptly to rest such that
6. A radius
point r charge
(l >> r)q is placed at a Space distance
10. the cube then rotates about the step.for l Rough
See from Work
the centre
figure of an uncharged conducting sphere of
below.
radius r (l >> r)
v
2a
q
q
q
q

qr 3
(A) Induced dipole moment of sphere is given by 23 .
(A) Induced
Momentum, qrl
(A) dipoleangular
momentmomentum,
of sphere is energy
given byare 2conserved
. during the process
l
2v2qr3
(B) Angular dipole
(B) Induced velocity of cube
moment of after
spherecollision
is givenisby7a .2 3
2qrl
(B) Induced dipole moment of sphere is given by3v 2
(C) Angular velocity of cube after collision is l.
3q cos q
(C) Induced surface charge density s as a function of q is given by
8a
(D) Minimum velocity required for cube to roll over in same direction pl2 q of initial velocity is
3q4cos
(C) Induced surface charge density s as a function of q is given by
4 pl2
q cos q
16ag
3
( )
2 - 1 charge density s as a function of q is given by
(D) Induced surface
pl2q
4cos
Target : JEE (Main +qAdvanced) 2020/18-09-2020/Paper-2
ALLEN(D) Induced surface charge density s as a function of q is given by 2
4 pl
4. Suppose we make a frame of a Space
2.8. Space
regular
for Rough
for Rough
tetrahedron
Work
Worksix resistors with the same resistance,
using
r and apply a voltage V between Space
pointforO Rough
and pointWorkM as shown in the figure. A current I flows
into point O and flows out of point M. M is the midpoint of resistor BC.

1001CJA102119120 E-3/36
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VMC | Final Advanced Test 2 3 JEE ADVANCED 2021

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1001CJA102119119 E-7/28
VMC | Final Advanced Test 1
1001CJA102119119 7 M JEE ADVANCED 2021
I E-7/28
VMC | Final Advanced Test 1 7 JEE ADVANCED 2021
A B

VMC | Selection Test 3 2 JEE 2022

(A) The current between O and B is I.
8

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(B) The current between A and B is .
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(A) The current between O and B is I.
8

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(B) The current between A and B is .
8

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(C) The potential at point B is .
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(D) The equivalent resistance between point O and M: JEE
Target is (Main + Advanced) 2021/21-08-2021/Paper-1
ALLEN 8
Space
8. A glass capillary tube closed at upper
8.
5. endfor
has Rough
internal Work
and external radius as r and R respectively.
The tube is held vertical with its lower end touching the surface of water. Assume that water
perfectly wets the glass. Then, (Atmospheric pressure is Po, surface tension of water is T, density of
water is r, mass of empty tube is M)
æ 2Po rh ö
(A) For water in it to rise upto height h (< L), length (L) of such tube is ç h + ÷
è 2T - rgrh ø
æ Po rh ö
(B) For water in it to rise upto height h (< L), length (L) of such tube is ç h + ÷
è 2T - rgrh ø
(C) The vertical force needed to hold tube in this position will be
é 2 Lr 2 ù Target : JEE (Main + Advanced) 2020/13-09-2020/Paper-2
ALLEN
F = Mg + pPo ê R - SECTION-II ú + 2p(R: +(Maximum
r)T Marks: 24)
ê
ë L - h ú
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˜ This section contains SIX questions.
The
˜ (D) answer
The verticaltoforce
eachneeded
question is atube
to hold NUMERICAL
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second decimal
= Mg + pP ê R - ú +e.g.
place; 2p(R6.25, 7.00, –0.33, –.30, 30.27, –127.30, if answer is 11.36777.....
+ r)T
then both 11.36 oand
êë 11.37 will
L + h úû be correct) by darken the corresponding bubbles in the ORS.
ALLEN Enthusiast Course/Score-III (All Star Batch)/21-08-2021/Paper-2
For Example : If answer is –77.25, 5.2 thenEnthusiast
ALLEN fill theCourse/Score-III
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Star Batch)/21-08-2021/Paper-1
9.9. Largest
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6.
10. A an
In ac and
spherical smallest
ball
circuit shown distance
of mass of a satellite
m andvoltages
below, radius
+ – rV andfrom
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100 are
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given
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in
min.a

respectively.
then, [Allfluid
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given these two positions
valuescoefficient
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0 0 values]0 • 0 0
of0 viscosity are given v
h as0 shown. and v
0 min0 0 • 0 max0
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1 1 1 1 • 1 1 1 1 1 1 • 1 1

alwaysRacted+ Rby a force F= 23 A23 ´ v 2 2 2 2

where A is a23 constant
3 3 • 3 3
2 2 2 2 2
3 3 3 • 3 3
vector along positive z-axis and v is
max min
(A) a = (B) bY = R . R
4 4 4max4 • min
Z
instantaneous 2 velocity vector4 of4 theX4 ball.
4 • 4 4 4 4
1001CJA102119120
E-4/36 5 5 5 5 • 5 5 5 5 5 5 • 5 5
L6 6 • 6 6
VMC (C)
| Final T
Advanced Test 2 6 6 6 6 • 6 6 6 4 6T 2mv JEE ADVANCED 2021
(A)aThe v max v min
= displacement of ball7until the7 ball stops
C (D)isb7 = 7 7 v7max 0 v
min
2p 7 7 • 7 7 2p • 7 7
8 8+ (6 8 ph
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8 5A
8 8 8 • 8 8 8 A • 8 r)8
9 9 9 9 • 9 9 9 9 9 9 • 9 9
Space for Rough mv
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(B) to each question
The displacement of ballwill be
until evaluated
the ball stops is Workto0 the following marking scheme:
according
Full Marks : +4 If ONLY the correct numerical ~
A 2 + (6value
phr) 2 is entered as answer.
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Marksof ball :is always in x-yofplane 100V, 50Hz
the bubbles is darkened.
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consumed : –1 æIn
v all
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(D) Speed of particle is ç 0 ÷ after seconds.
1. TheThe
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of circuit a mr
hollow
will
6 ph sphere are measured to be (4.20 ± 0.01) cm and
be 40W.
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5 3 1æ pö
2.
11.
4.
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from
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theCurrent
normalin capacitor
force exerted by the ground is lmg, YZ find l. Take QvB = mg.
2GM
(A) Gravitational potential at the centre of
11. A solid cube of side length l and mass M is pivoted sphere is - on a horizontal axis such that it can rotate
R
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5. A point object is placed at 30 cm from a convex glass lens ç m g = ÷ of focal length 20 cm. The
è 2ø
Vidyamandir Classes
Leader
ALLEN final image of object will be formed at infinity if -& Enthusiast Course/Score(Advanced)/08-09-2020/Paper-1
(A)
5.7. A
4. nonAnother concave
conducting lens thin
uniform of focal
shelllength 60 m
of mass cmandis placed
radius inR iscontact
havingwith the previous
uniform lens
charge density
(B)
+ s Another convex
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another 60 cm is placed
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figure. of 30 cm
It is placed on from the first
a rough non
lens r
conducting horizontal plane. At t = 0 a uniform electric field E = - E0 ˆjN / C is switched on and
(C) The whole system is immersed in a liquid of refractive index 4/3
the
(D) solid
The sphere starts rolling
whole system withoutinslipping.
is immersed a liquidThen which ofindex
of refractive the following
9/8 is/are CORRECT.
6. In the cylindrical region of radius R = 2m, there
6.
ALLEN exists
Enthusiast a time varying
Course/Score-III (All Starmagnetic field B such
Batch)/21-08-2021/Paper-1
SECTION- I(ii) : (Maximum Marks: 32)
y
dB
˜ that = 2contains
This section EIGHT
Tesla/sec. (08) questions.
A charged particle having charge q = 2C is placed at the point P at a
˜ dt
Each question has FOUR options. ONE OR MORE THAN ONE of these four option(s) is (are)
distance d from its center O. Now, the particle is moved in the direction perpendicular to the
correct answer(s).
For each question, choose the option(s) 53°
corresponding to (allis)no
thegain
correct answer(s)
˜ line OP by an external agent up to infinity so that there in kinetic energy of charged
˜ Answer to each question will be evaluated according to the following marking scheme:
particle. If (d > R), then which of the folllowing options is/are CORRECT?
Full Marks : +4 If only (all) the correct option(s) is (are) chosen.
Partial Marks : +3 If all the four options are correct but ONLY three options are chosen.
Partial Marks : +2 If three or more options are correct but ONLY two options are chosen and
both of which are correct.
O
Partial Marks : +1 If two or more options are correct x but ONLY one option is chosen
and it is a correct option.
Zero Marks : 0 If none of the options is chosen (i.e. the question is unanswered).
Negative Marks : –1 In all other cases.
˜ For example, in a question, if (A), (B) and (D) are the ONLY three options36corresponding
psE0 R2 to
(A) Theanswers,
correct acceleration
then of the topmost point of the d hollow sphere at t = 0, is .
25 m
choosing ONLY (A), (B) and (D) will get +4 marks;
choosing ONLY (A) and (B) will get +2 marks; 18
(B) The magnitude
choosing ONLY (A)of frictional
and (D) will force
get +2atmarks;
t = 0 Pis p sE0 R 2 .
q
25
choosing ONLY (B) and (D) will get +2 marks;
choosing ONLY (A) will get +1 marks; 2
(A) work ONLY
choosing done by(B)external
will getagent
+1 is 4p Joule when d = 4m
marks; 12 psE0 R
(C) The acceleration of centre of mass of the hollow sphere at t = 0, is .
(B) work ONLY
choosing done by(D)external
will getagent is 4p Joule when d = 8m.
+1 marks; 25 m
(C) work no
choosing done by external
option agent isisindependent
(i.e. the question unanswered) of willd.get 0 marks, and
9
choosing
(D)
(D) The any other
workmagnitude
done combination
of frictional
by external offorce
agent options
at twill
= 0 get
is positive. is –1 p
0 sE R 2 .
mark.
25
Space for
for Rough
Rough Work
Work
8. Figure shows part of a large network in which potentials of some of the points are shown. Each
Space
5.7.
capacitor has capacitance 5mF. Which of the following statements is/are true at steady state?
B

C2

C1 C3
A C
–10V O R 10V

C4

(A) From the given information potential of point O can be determined but that of B cannot be
determined
(B) From the given information, potential of both points O and B cannot be determined
(C) If charge on capacitor C were also specified, potential of point O can be determine but that of
1001CJA102119115
E-6/28 B cannot be determined 2
VMC | Final Advanced Test 5 6 JEE ADVANCED 2021
(D) If charge on capacitor C2 were also specified, potential of both points O and B can be
VMC | Selection
determinedTest 4 JEE 2022

1001CJA102119115 Space for Rough Work E-5/28

VMC | Final Advanced Test 5 5 JEE ADVANCED 2021
 Selecting only one of the three correct options (either first or third or fourth option), without
selecting any incorrect option–10V (second optionO in this case),
R 10Vwill result in +1 marks. Selecting
any incorrect option(s) (second zoption = 0 in this case), with or without selection of any correct
CUpper end
option(s) will result in –2 marks. Vidyamandir 4
Classes
3r
1.4. A solid cone of base radius 'r' and halfz angle 45° made of material have density . Cone is
2
(A) From
placed the given
inside information
a container potential
which of point
is filled withOtwo can be determinedliquid
immiscible but that
of of B cannot
density r be
and 2r
determined Lower end
respectively. The cone is at rest with respect to container as shown in diagram. Which of the
(B) Fromis/are
following the given information,
CORRECT potential of
statements both points
? (Neglect O andofBatmospheric
effect cannot be determined
pressure)
(A)
(C)The upper on
If charge endcapacitor
and lowerC2 end
wereofalso
tubespecified,
are openpotential
and closedof respectively.
point O can be determine but that of
1001CJA102119115
E-6/28 B cannot be determined
(B) The upper end
VMC | Final Advanced Test 5 and lower end of tube are closed and
6 open respectively.
JEE ADVANCED 2021
(D)The
(C) If air
charge on capacitor
column C2 inwere
is vibrating third
r also specified, potential of both points O and B can be
harmonic.
determined 1 45°
(D) The air column is vibrating in second overtone. a=g
9. 2 2r
4.3. In an AC circuit, we have an inductance L joined in series to two resistors of resistance R
Space for Rough Work
each. In the first case, the resistors are inr series with each other and in the second case,
the resistors are parallel to each other. The power consumed by the circuit in the first case is
810W and in the second case, it is 506.25 W. If the source voltage is 225 V,
(A) The ratio ofRvolume
(A) Resistance = 20 W of cone in liquid 1 and liquid 2 is 1.
(B) In the first case, the phase difference between current through the source pand r 2 voltage across it
(B) is 37°.force exerted by the liquid 1 on the cone in vertical direction is 3 rg
The
In the second
(C) Option (A) andcase, the phase
(B) both difference between current through the source and voltage
are correct
across it is tan -1
(3)
(D) Option (A) and (B) both are wrong.
1001CJA102120126 Target : JEE (Main + Advanced) E-5/28
VMC
ALLEN|(D) Inductive
Final Advanced reactance
Test is
7 30 W 5 JEE2020/08-09-2020/Paper-2
ADVANCED 2021
Space for Rough Work
5. Consider a square frame madeSpace
2.
10. of uniformly charged
for Rough Work non conducting wires of length d and
C
linear charge density l . Choose the CORRECT statement(s).
m

d
d
1001CJA102119116 E-3/36
A B
VMC | Final Advanced Test 6 d 3d JEE ADVANCED 2021

(A) The electric field at A is zero.

(B) The potential at centre A is higher than potential at B.

E-4/36 é 32 Kl ù N 1001CJA102119117
VMC | (C) The
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Advanced field
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é sec q + tan q ù J é 1 ù
(D) The potential at B is =
V 4Kl log e ê ú : where q is sin -1 ê ú
ë sec q - tan q û C ë 6û
3. In rural areas where electric power lines carry current to big cities, it is possible to generate
small amount of electricity from the lines by means of induction in a single coil. The overhead
power lines carry relatively large currents that periodically reverse in direction 50 time per
second. How would you orient the plane of the coil to produce maximum induced current if
the power lines ran in a north-to-south direction ?
(A) Parallel to the ground.
(B) Perpendicular to the ground in the North-South directions.
(C) Perpendicular to the ground in the East-West direction.
(D) The orientation of the coil would not affect the size of the induced current.
VMC | Selection Test 5 JEE 2022
Space for Rough Work
 Vidyamandir Classes

SECTION - 2 (Maximum Marks: 32)

   This section has EIGHT (08) Questions. The answer to each question is a NUMERICAL
VALUE.
  For each question, enter the correct numerical value of the
Target : JEE answer using the2020/18-09-2020/Paper-2
(Main + Advanced) mouse and the
ALLEN on-screen virtual numeric keypad in the place designated to enter the answer. If the numer-
SECTION-II
ical value has more than two decimal:places,
(Maximum Marks: 18)the value of TWO decimal
truncate/round-off
˜ Thisplaces.
section contains SIX questions.
TheAnswer
˜    answer to to each
each question
question is evaluated
will be a NUMERICAL
according VALUE.
to the following marking scheme:
˜ For each question, enter the correct numerical value (in decimal notation, truncated/rounded-
Full
off to Marks:
the +4 If ONLY
second decimal place; the correct
e.g. 6.25, 7.00, numerical
–0.33, –.30, value is entered.
30.27, –127.30, if answer is
11.36777..... then
Partial Marks: both 11.36 and 11.37 will be
0 In all other cases. correct) by darken the corresponding bubbles
in the ORS.
For Example : If answer is –77.25, 5.2 then fill
Leader the bubbles
& Enthusiast as follows.
Course/Score(Advanced)/18-09-2020/Paper-1
ALLEN
+ – + –
12. A small conducting loop of0 radius
2.
11. a and resistance r is pulled with velocity v perpendicular
0 0 0 • 0 0 0 0 0 0 • 0 0
to a long straight conductor 1 carrying
1 1 1 • 1 a 1current1 i0.1 If1 a 1constant
• 1 1 power P is dissipated in the
loop, find the velocity (in m/s) of the loop when x = 1m. Given that x >> a.
2 2 2 2 • 2 2 2 2 2 2 • 2 2
3 3 3 3 • 3 3 3 3
3 3 • 3 3
(Given : P = 1 × 10–15W, r = 41mW,
4 4 a 4=• 1cm,
4 4 i0 = 1A)
4 4 4 4 • 4 4
5 5 5 5 • 5 5 5 5 5 5 • 5 5
6 6 6 6 • 6 6 6 6 6 6 • 6 6
7 7 7 7 • 7 7 Target : JEE (Main + Advanced) 2020/18-09-2020/Paper-1
7 7 7 7 • 7 7
ALLEN 8 8i • 8 v
8 8 8
a 8 8 8 8 •8 8
5. A long non conducting plane 9of width b 9having9surface
9 9 9 charge density s = s0x is moving with
0
9 9 9 • 9 • 9 9

˜ Answer
velocity to
v =each
v 0 ˆj . question will field
The magnetic be evaluated
(in Tesla) according
at point (a,toa,the following
0) will be : marking scheme:
Full Marks : +3 If ONLY the correct numerical value is entered as answer.
x
Zero Marks 4 p : 0 In all other cases.
[ given s0 = C / m3 , a = 2m and b = 1m, v0 = 2m/s]
1.
15. m0
12. Consider a cylindrical capacitor with a uniform magnetic field B directed along the axis and
13.
3. In the figure ammeter (I) reads a current of 10mA, while the voltmeter reads a potential
perpendicular to the paper pointing into the paper. A particle of mass M and charge (–e) flies
difference of 3V. What does ammeter y (II) (in mA) read ? The ammeter are identical, the
into the entrance slit with kinetic energy K. What must the potential difference(in Volt)
internal resistance of the battery is negligible. (Consider all ammeters and voltmeters as
between the inner and outer cylinder be if we want the particle to fly along the capacitor's
non ideal)
mid-line ? (Take r1 = 1m, r2 = 4m, K = 10 eV, B = 1T, P m = 1.6 × 10–18 kg, 2 = 1.41 , ln2 = 0.69)
(a, a, 0)

100W A I
O x
4V II
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100WLeader &VEnthusiast Course/Score(Advanced)/18-09-2020/Paper-2

ALLEN
2. Space
16. The rotational axis of the turntable for Rough
is inclined at anWork
angle a with the vertical. The turntable
shaft pivots freely in bearing which areb not shown. If a small block of mass m is placed at a
4.
6. distance
14. The peak
In the r emission
from
region point
magneticO,field
from determine
a black athe
of 1T,body natural
at frequency
a certain
semicircular for small
temperature
w0ring
conducting tºC rotational
ACBoccurs
of at a1m
radius oscillations
wavelength
is rotated
through
9000 Å. angle
If the The
peak
q.
with angular velocity massabout an axis passing through C and perpendicular to planeisof
emission moment
from of
the inertia
black of
body turntable
at 927ºC about
is ablethe
to axis
just of its
emit shaft I. ring.
The
photo-electrons
w
from mgr value of t (in ºC is) is: [ h = ´ 10 -34 J - sec ]
valueaofmetal of work
angular function
frequency w is2.5
k eV. The , the value of k is (Take : a =6.6
30°)
I + mr 2 é 3 ù
Find potential difference (in Volt) between
Space B. ê cos q
A and Work
for Rough
= , w= 5 rad / s ú
ë 5 û
a

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6 × JEE 2022
w
× × × × × ×
C
× × × × × ×
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 Vidyamandir Classes
Leader & Enthusiast Course/Score(Advanced)/18-09-2020/Paper-2
ALLEN
16. Space
13. The rotational axis of the turntable
2. for Rough
is inclined at anWork
angle a with the vertical. The turntable
shaft pivots freely in bearing which are not shown. If a small block of mass m is placed at a
distance r from point O, determine the natural frequency w0 for small rotational oscillations
through angle q. The mass moment of inertia of turntable about the axis of its shaft is I. The
mgr
value of angular frequency w is k , the value of k is (Take : a = 30°)
I + mr 2

r O
q

Leader
Leader &&Enthusiast
EnthusiastCourse/Score(Advanced)/18-09-2020/Paper-2
Course/Score(Advanced)/18-09-2020/Paper-2
ALLEN
ALLEN
14. Figure
5.
5.
17.
17. Figure shows
E-14/36 shows the
the arrangement
arrangement of
of aa set
Space of
of saddle
setfor Roughcoils.
saddle coils.
Work If
If the
the magnitude
magnitude of of magnetic
magnetic field
field at
1001CJA102119120at
VMC | Final Advanced Test 2 14 JEE ADVANCED 2021
am00ii
am
point
point P
P is
is ,, then
then value
value of
of aa is
is
ppaa

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2a

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P

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2a II

6.
6.
15.
18.
18. The
The massless
massless pulley
pulley P
P is
is moving
moving vertically
vertically downwards
downwards with
with constant
constant speed
speed of
of 15
15 m/s.
m/s. Find
Find
the
the velocity
velocity (in
(in m/s)
m/s) with
with which
which the
the block
block QQ moves
moves up
up at
at the
the instant
instant shown.
shown. (All
(All pulleys
pulleys are
are
fictionless)
fictionless)

37°
37° 37°
37°
P
P

Q
Q 15m/s
15m/s

Space
Space for
for Rough
Rough Work
Work

VMC | Selection Test 7 JEE 2022

1001CJA102119120 E-15/36
 5kW53°
in the ORS.
For Example : If answer is –77.25, 5.2 then fill the bubbles as follows.

4.
13. In theList–I
figure shown below, the maximum+ – possibleClasses
Vidyamandir unknown
+ – resistance (X),List–II
that can be measured
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0 0 0 0 • 0 0
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0 0 0 0 • 0 0
then R is :Course/Score(Advanced)/13-09-2020/Paper-2
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ALLEN max
1 1 1 1 • 1 1 1 1 1 1 • 1 1
only one
16. Refer plug in arm AB below.
and
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theinswitch
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3. (II) to the
The circuit
time given
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the points position–1
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2

plugs):
switch is changed to position–2.
3 3
4 4 After
3
4 4 •a
3 • 3
4 time
4
3
t (measured
3
4 4 4 4 •from
3 3 3 • 3 3
4 4 the change over of the switch) the
3 5 5 5 5 • 5 5 5 5 5 5 • 5 5
which are at th of the 6 6 maximum
6 6 • 6 6 height 5 6 6 6 6•6 6
4
voltage across 5 kW resistance 7 7is found
7 7 • 7 to 7 be volt.
7 7 Then, 7 7 • 7 find
7 the value of t (in milli sec)
attained by the E +paritcle8 G8 (in8 8sec).
• 8 8 3 8 8 8 8•8 8
9 9 9 9 • 9 9 9 9 9 9 • 9 9
–
˜ (III) when velocity
1 P
Answer to each question will be evaluated according to the (R)
The time instant is Q
perpendicular following60 marking scheme:
Full toMarksinitial velocity
: +3 If(in ONLYsec).
A the correct 10kW
1000 100 10 B 10 numerical
100 1000 C value is entered as answer.
S 1000 makes unknown
Zero The
(IV) Marks tangential: 0 acceleration
In all other 5000 cases.
when 2000velocity (S) 100
resistance
1. an angle 37°
In a radioacitve with
decay A the
is
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horizontal
converting
R(in
into
t = 0 nuclei of B and C are not present, decay constant for A 20
100 200
m/s
B and
200
).
2500 B is converting into C. It is given that at

to B X
mFis l and decay constant for
(T) 1 6
5kW
B to C is l2, take l1 = 5l and l2 = 2l. The time after which B will(U) have maximum No.above
None of the of nuclei
Target : JEE (Main + Advanced) 2020/13-09-2020/Paper-2
ALLEN(A) I ® R ; II ® S ;/ III
ln(5 2) ® P ; IV ® P
4.17.
14. is
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levels will be
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the tworesistance (X), that cancapillaries
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(D) Ione
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plug ®armQ ; IIIAB®and UA;only
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3
ALLEN
6.
2.
15. A system of two planks and a sphere of radius R is in motionsupply
Proton
plugs): separation energy is the amount of energy we must as shown to remove a proton
in figure. Radiusfrom a
of the
6.
11.
18. A uniform solid cylinder of massSpace ‘m’ rests foron two horizontal
Rough Work planks. A thread is wound on the
sphere is R and there is no slipping anywhere.4 It is given that Ra = 2a0 where a is angular
nucleus. Find
cylinder. The the protonend
hanging separation
of the threadenergy is of pulled
2 He (invertically
MeV) . The downmass of a constant force F,
with
acceleration of sphere and acceleration of upper block is a1 = ka0 where k is a +ve constant
which
thenmthe( )
still doesofnot
1 value bring
k will
1 H = 1.007825
be any
E +amu G
: sliding of the cylinder. If the coefficient of friction between the
cylinder and planks in equal to µ. What is the maximum acceleration amax of the axis of cylinder
( )
m 13over
rolling H =the
–
planks.
3.016049 amu
a
P
(Assume 1m =1/3 and take g = 10 m/ sec.2) Q
A 1000 100 10 B 10 100 1000C
m( He ) = 4.002603 amu
4
2 5000
a
2000 a
1000 unknown
resistance
ALLEN
(Take : 1amu = 931 MeV).
D R
a0
100
Target : JEE (Main + Advanced) 2020/08-09-2020/Paper-1
200
Space for Rough Work X200
500

16.
3. An infinite uniform current carrying wireRough
Space for is keptWork
along z-axis, carrying current I0 in the
direction of the positive z-axis. OABCDEFG represents a circle (where all the points are
equally spaced) whose centre at point (4m, F 0m) and radius 4m as shown in the figure.
Space for Rough Work
® ® m I k
7. ò
B × dl =0 0 in S.I. unit, then the value of k is :
A capacitor of 2capacity 6 µF and initial charge 160 µC is connected with a key S and resistance
DEF
as shown in figure. Point M is earthed. If key is closed at t = 0 then the current through
1001CJA102119118 E-11/28
VMC |resistance
Final Advanced at t4= 16 µ sec will be ___ Amp.
R = 1 WTest 11 (Assume e = 2.7)
JEE ADVANCED 2021
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1001CJA102119120 G E-13/36
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1001CJA102119115 E-9/28
VMC | Final Advanced Test 5 x
S 9 JEE ADVANCED 2021
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8.4.A closed
The organ
distance pipe of the
between length L andplates
parallel an open
of aorgan pipecharged
isolated contain gases of densities
condenser andand
is d = 5r1cm r2 the
respectively. The compressibility of gases are equal in both the pipes. Both the pipes are
intensity of the field E = 300 V cm–1. A slab of dielectric constant K = 5 and 1 cm wide is
VMC | Selection Test 8 JEE 2022
inserted parallel to the plates. Determine the potential difference (in volt) between æthe r ö plates,
1/ 2

vibrating in their first overtone with same frequency. The length of open organ pipe is kL ç 1 ÷ .
after the slab is inserted. è r2 ø

Find value of k
1001CJA102119118 Space for Rough Work E-11/28
 ˜ (b) Assuming
This section contains no temperature FOURchange questions. and
atmospheric pressure to be Po, find the Where DP is pressure difference at the two ends of
˜ Eachsurface questiontensionhas of theFOUR options (A), (B), (C) andthe(D).
soap solution. ONLY ONE of these four options
tube and h is coefficient of viscosity. Assume
Q.23. is In correct.
the last problem, one of the bubbles Vidyamandir Classesthat the bubble remains spherical.
Vidyamandir Classes
supplies
˜ For each
its entire airquestion,
to the other bubble darken andthe a film bubble
of soapcorrespondingQ.27. Two blocks to thearecorrect floating option
in water.in When the theyORS. are
˜ solution is formed at the end
For each question, marks will be awarded in one of the straw which Target of: JEE
brought the(Main + Advanced)
sufficiently
following close 2020/18-09-2020/Paper-1
they
categories are : attracted to
ALLEN keeps it closed. What is the radius of curvature
: +3 If only the Chemistry
bubble Tests each
corresponding 1 other to the
due to surface tension effects. When
correct
Full
of thisMarks
film if the bigger bubbleSECTION-I(ii)
has grown in size: (Maximum theMarks:
experiment 32)is repeatedoption is darkened.
after replacing water
˜ Zero Marks
This section contains EIGHT
and its radius has become: 0 R If
3. none of the
questions. bubbles is darkened.
with mercury, once again the two blocks are
: –1 In all other for
Each question Markshas options
Partofcases correct answer(s).
˜ Negative FOUR attracted.ONE Explain OR the MORE
phenomena. THAN It is given
ONE thatof
een the Mathematics Properties Matter
Test - 4Leader JEE& water
|Question Enthusiast SETCourse/Score(Advanced)/18-09-2020/Paper-1
Advanced-2020 2
ALLEN
L1.
eveLAn these
3 aqueous four option(s)
solution is is 2M(are) Chemistry
in correct
Ca(NO 3option(s).
Selection Test
) 2 and 3m in mercury
1 ) . What should be the densityasof
wets
Al(NO 3does
the material of the block where
at point Select option(s) with correct
6. ofmajor product? not.
3
˜ For each Matrices
question, & choose
Determinants, Filmthe correct
soap Probability,
option(s) to Vectors
answer&the 3D-Geomatry
question.
Q.1:
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Q.24. Consider
Answera rain such
to each that
drop the at
falling
question molality
terminal
will and
SECTION speed.molarity
solution
- For
be evaluated
1 (Maximum of
Q.5:NOMarks:
Q.28.
–
ion becomes
3 A longto
according thin
40) the string numerically
has a coatmarking
following of same?
water on it. The
scheme:
r2 = r. what radius (R) of the TIME drop can : 3 hrswe disregard the radius of the water cylinder is r. After some time
M.M. : 236
Full
[Ca = Marks
40, Al = 27] : +4 ofIfTEN only(10) Clthe correct
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terface     This
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N
section
of gravity consists
on its shape? Surface tension question
it was found that options.
the string had ONE
a seriesOR of equally
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waterCCl :
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are +3
¾¾¾® KOH
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r thefour
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correct but ONLY
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(A) 1.0 gm/ml
3
Read the following4 T (B) 1.967 Ngm/ml
Instructions very (C)carefully
1.310 gm/ml
spaced identical
before you (D)
water 1.918 gm/ml Find the
proceed.drops on it.
sts and    Partial
AnswerH Marks
to each : +2 If three
question will be orevaluated
more options according are correct
to the
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Q.25. A soap bubble has radius R and thickness of its
Q.2:
le find In an
2. 1.wall empty
This vessel
question paperof 4.0 L
both
consists capacity,
of of
3 which0.2
sections mgare of
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correct
I, Section less volatile
options.
II & Section liquid
III). (Molar mass = 100 gm mol )
is a.Marks:
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only (all) the Q.29.
Q.6:
correct A option(s)
liquid having is(are)surfacechosentension T and density r
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en that 2.is taken
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R and Partial
tension O
of soapMarks: 
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allTthe option.
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question
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out of which ONLY ONE Δ CHOICE is correct. 0
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and
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all Athe three
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choices (A), (B), (C)willand result
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20.25
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and option is
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the for
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it is a correct option
without selecting any incorrect option
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& –1 in this case), will result
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answer]
3. Which
Q.26. ASelecting
soap Type compound
bubble is blown will
at the yield
end 2-methyl-6-oxoheptanal
of a capillary upon ozonolysis
Q.3:
Zero 3only
Mark: containsoneFIVE of the three
paragraphs. correct
0 if Based
none options
of these
on the options (either
paragraphs, is chosenfirstare
there orTEN
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the or fourth
question
questions. Each option),has
is question
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tube of radiusany
selecting aF and length L. option
incorrect When the other end
(A), (B), (C) and (D).(second ONLY ONEoption
NH 2 in this case), will result in +1 marks. Selecting
R1) are FOUR options of these four options is correct.
bble to any Negative
is left
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incorrect Marks:
bubble
option(s)
begins to –1
Clscheme (B) [33MarksIn
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inanswer
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 Marking NH for Correct & –1 MARKING for wrong answer]
mains. (D)
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®
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of time if
the initial Nradius of the bubble R0O . Surface (i) The
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the pressure
to eachin of thethe
liquid at the top is aof the
OSection 2N which has +1 spin quantum number in manganese atom.
3. II contains Integer Value Type Questions. questions
4.
5. Find
Liquids
4.1. tension the2 maximum
of 'A'
soap
single-digitand 'B' form
solution
integer, number
is T.
ranging anItfromofiselectron
ideal known
0 tosolution. The vapour
that inclusive).
9 (both 2 pressure
meniscus of solution
(i.e. at A) at 313K is
Select
(A)
7. volume 10flow incorrect
rate through
Marking statement(s)
a(B)
scheme tube[415 of radius
Marks a and answer
for Correct (C)& 12 NO (ii) Calculate
NEGATIVE MARKING (D) for 13
the difference wronginanswer]
height (h) between
P [/cm Hg] = 60 + 40
length L is given by Poiseuille’s equation- x
4. SectionOIII contains 4 Match the Space columns for type Rough
questions.Work Eachthequestion
bottom and top ofstatements
contains the meniscus. given in
wherep a 4 D'x'P is the mole-fraction of liquid 'A' in the liquid solution at equilibrium. If 'y' represents
Q = 2 columns. Statements in the first column have to Q.7:
Q.30. Is it with
be matched possible that water
statements evaporates
in the second column. from a
(A) 8h L give aldol with NaOH
the mole-fraction
The
O
answers to of 'A' in the vapours in equilibrium with the liquid solution at 313K,
these questions have to be appropriately spherical
bubbled in thedrop
answer of water
sheet. just by means of surfacethe
energy supplying the necessary latent heat of
CORRECT 
OH information(s)
Marking
L
scheme [8related Marks ifwith the solution
you darken ALL the is/are
bubbles corresponding ONLY to the correct
vaporisation? The drop does not use its internal
answer or given 2 MarksReach for correct bubbling of answer in any row. No Negative mark will be
2a(B) Me
0
thermal energy and does not receive any heat
(A) PA0 =–100cm CHCOOH
givenHg for angive incorrectlypositive bubbled Iodoform
answer] (B) testPB0 = 100 cm Hg
from outside. It is known that water drops of
ut ? (C) Cl
5.(C) If For C – CH=O give Cannizaro reaction with NaOH
size less than 10–6separately.
m do not exist. Latent heat of Q.32. A
x3 = answering
0.5, then ay question, = 0.625 an ANSWER SHEET (OMR (D) IfSHEET)
y = 0.5, is then
providedP = 75 cm HgPlease fill6 your–1
(D) PhCHO Test Code,and Roll No. MeCHO
and Group can be differentiated
Properly in the space given in by theTollen's
vaporisation
ANSWER of test
water is L = 2.3 × 10 Jkg and
SHEET. a
e and Space for Rough Work
8. Select reaction(s) with correct major product
5.2. Where surface tension is T = 0.07 Nm . –1 i
nd the DP is pressure difference at the two ends of t
the tube and h is coefficient of viscosity. Assume Q.31. InMe
Q.8: the arrangement shown inMe the figure, A is a jar
t
that moist half filled withSOCl water and half filled with air. It
upplies (A)the bubble remains ¾¾¾® Ag2O
spherical. (B) H OH ¾¾¾¾ 2
® H cork. ACltube connects
Q.27. Two blocks areI floating in water. When OHthey are is fitted with a leak proof
of soap Q.4:
itDto a water vessel B. Another D narrow tube
which brought sufficiently close they are attracted to
fitted to A connects it to a narrow tube C via
rvature each other due to surface tension effects. When
NMe3OH a water Br monometer M. The tip of the tube C is
in size alc. KOH
(C)experiment is repeated
the ¾¾ ® after replacing water (D) just touching¾¾¾¾® the surface of a liquid L. Valve V
1001CJA102119119
with mercury, once again the two blocks areΔ
E-15/28
VMC attracted.
| Final Advanced Test 1 It is given that 15 is opened at time t = 0 JEE water
and ADVANCED from vessel2021 B
Explain the phenomena.
water wets the material of the block Space where asfor Rough Work
pours down slowly and uniformly into the jar A.
An air bubble develops PartatTest-4
the tip| JEE-2020
of tube C. The
mercury does not.
VMC | Mathematics 1
Q.33. A
cross sectional radius of tube C is r and density of
Q.28. A long thin string has a coat of water on it. The water is r. The difference in height ofJEE water2022(h) in c
VMC || Physics
VMC Selection Test
Assignment 1
1 PhysiCs
radius of the water cylinder is r. After some time the two arms of the manometer varies with time i
it was found that the string had a series of equally 't' as shown in the graph. Find the surface tension d
spaced identical water drops on it. Find the of the liquid L. t
minimum distance between two successive drops. t
 (C)
(C) The
these The four number
numberoption(s) of
of occupied
is (are) p
occupied pcorrect * M.O. of O is 2
M.O. of option(s). O22 is 2
Zero
Zero Marks
Marks :: 0 0 If
If none
none of
of the
the options options is
is chosen chosen (i.e.
(i.e. the the question
question is
the question. is unanswered).
unanswered).
˜ (D)
(D) both
For each have
both question,
have same
same choose p-bond the
p-bond order
order correct option(s) to answer
Negative
NegativetoMarks Marks : –1
: –1option In all
In allfor other
other cases.
cases.
10.
10.
˜ 7. Choose
Choose CORRECT
7. Answer each question
CORRECT optionwill for be boiling
boiling evaluated point.
point. according to the following marking scheme:
For Example :: If
If first,
first, third
third and
and fourth
fourth are
are the
the(C) ONLY three
three correct options for
for>a question
question with
For Example ONLY is correct options aBF with
˜
˜ (A)
Full
(A) H
H SO
Marks
SO >
> Me
Me SO
:
SO +4 If (B)
(B)only H
H >
(all)
> He
He the
Vidyamandir correct Classes
(C) CCl
option(s)
CCl >
> SiCl
SiCl (are) (D)
chosen.
(D) BMe
BMe > BF
second 2 option
2
second option
4
4 being
being
2
2 4an incorrect
4
anIfincorrect
2
2 option;
option; selecting
selecting only
Target
only all 4 :all
4
JEE the
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2020/18-09-2020/Paper-1
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will result
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11.
11. Choose
8. Partial
8. Choose the
Marks
the CORRECT
CORRECT : +3 all the four
options
options about
about options CFT.
CFT.correct are correct but options are chosen.
in
in +4
+4 marks.
marks. Selecting
Selecting only
only two
two of
of the
the three
three correct options
options (e.g.
(e.g. the
the first
first and
and fourth
fourth options),
options),
9.6. (A) Tetrahedral
Partial
3. Which(A) TetrahedralMarksis CORRECT
option : +2 If three
splitting
splitting is just
is just
for orN more
opposite
opposite andoptions O2of are correct
ofaccording
octahedral
octahedral to but ONLY two options are chosen,
splitting
splitting
MOT.
without
without selecting selecting any any both incorrect
incorrect option
option 2 (second
(second option
option in
in this
this case),
case), will will result
result in in +2 +2 marks.
marks.
(B)
(B)
(A) In
In
The octahedral
octahedral
ratio of s splitting
splitting
bonding axial
axial of which
filled 'd'
'd'
orbitals orbital
orbital arein correct
goes
goes N to
to and options.
higher
higher O is energy
energy1 : 1 level
level than
than non
non axial
axial orbitals.
orbitals.
Selecting
Selecting only
only one
one of
of the
the three
three correct
correct options
options 2(either
(either 2first
first or
or third
third or
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fourth option),
option), without
without
Partial
(C)
(C)
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The Marks
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tetrahedral
number : +1
of If twopaxial
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*
M.O. more 'd'ofoption
'd' options
orbitals
orbitals N2 is in 2 are are
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present
present but ONLY
in result
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lower one option
energy
energy levelisSelecting
level chosen
whereas
whereas
selecting
selecting any
any incorrect
incorrect option
option (second
(second option in this
this case),
case), will
will result in +1
+1 marks.
marks. Selecting
(C) non axial option(s)
'd' of orbital and goes itpto is
to a correct
higher energy option. level.with or without selection of any correct
anyThenon number
axial 'd' occupied
orbital goes M.O. higher ofininO energy is 2case), level.
*
any incorrect
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(second option
option this
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2 case), with(i.e. or +2without selection of any correct
Zero
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) ] the
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Splitting
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will same
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will result of
in
p-bond [M(NH
–1 order
marks. ) ] < tetrahedral [M(NH (if M is same in both)
: –1 inIn–1allmarks.
3 6 3
Negative other 3 6
cases. 3 4
12.
12.
˜ 4. Choose
7.
10.
1.9.
1. 9. Which
Which
Excess
Excess
For ofCORRECT
of
Example
the
ofthe
of solid
solid
following
following
: IfAgCl
AgCl
option
first,is
is/are
is/are
added
isthird
added
for
and
CORRECT
CORRECT boiling
in
infourth 2.0
2.0 L Lare
point. of statement(s)?
ofstatement(s)?
NH
NHthe33ONLY solution
solution three such
such correct that in
in the
that options the final
final solution,
solution,with
for a question the
the
(A) H2SO4 > Me 2SO4 (B) H2 > He (C) CCl
Leader
Leader &
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Course/Score(Advanced)/18-09-2020/Paper-1
Course/Score(Advanced)/18-09-2020/Paper-1
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(A)
(A) The
The
concentration option
movement
movement being
of – an
of incorrect
of colloidal
colloidal option;
particles
particles selecting under
under only anall
an 4
applied
applied the three 4
correct
electric
electric options will
potential
potential is result
is called
called
ALLEN
8. Choose
11. concentration the of Cl
CORRECT Cl– ion ion is
is 0.01M.
0.01M.about
options Which
Which CFT. of
of the
the following
following is/are
is/are CORRECT CORRECT information(s)?
information(s)?
in +4 marks. Selecting only SECTION-II
SECTION-II two of the ::three (Maximum
(Maximum correct options Marks:
Marks: (e.g. 18)the first and fourth options),
18)
(A) electrophoresis.
Tetrahedral
electrophoresis.
(Given K (AgCl)
::selecting splitting
= 2 × 10 is–10 –10just;; K opposite)) of
[Ag(NH +] =
+ octahedral
8 × 10 6; Agsplitting
6
= 108)
˜
˜ (Given
This
without
This sectionsectionK (AgCl)
contains any= 2
sp contains SIX questions.
sp × 10
incorrect
SIX questions. K [Ag(NH
option
f
f (second 3
3 22 ] = 8 ×
option 10 ; Ag
in this = 108) case), will result in +2 marks.
(B)
(B) In
The octahedral
movement splitting
of dispersionaxial 'd' orbital goes to higher energy level than non axial orbitals.
˜
˜ Selecting
The
(B) The
TheInitial
(A)
(A) answer
answer
Initial only
movement
moles
moles toone
to each
each
of
of of
of the
NH
NH question
question
in
in three
dispersionthe
the ismedium
correct
is
solution
solution a
a NUMERICAL
medium NUMERICALoptions
=
= 0.54
0.54
under
under (either
Leader
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an&applied VALUE.
applied
VALUE.
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potential,third or when fourthelectrophoresis
when option), without
electrophoresis
Course/Score(Advanced)/18-09-2020/Paper-2
is
is
ALLEN (C) In tetrahedral
selecting any incorrect splitting
3
3
option axial
(second 'd' option orbitals in are
this presentcase), will in result
lower in energy
+1 level Selecting
marks. whereas
˜ For each
Forprevented question,
each question, enter
enter the
the correct correct numerical
numerical value (in decimal
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ADVANCED
ADVANCED 2021
2021
of reaction under identical conditions. By how many times, o half life of (ii) is greater than the
solution volume is 1 litre, its temperature rises to ‘T’ = 50 C and it also contains a precipitate
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E-18/28 1001CJA102119115
1001CJA102119115
VMC
VMC| |Final
FinalAdvanced
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JEE ADVANCED
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2021
(B) Final solution contains equal moles of Na + and Cl– ions.
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(E) pH of resultant solution is 7
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(F) Resultant solution after filteration can act as buffer solution
VALUE.
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| Selection Test 4 JEE 2022
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VMC | Final Advanced Test 4 25 JEE ADVANCED 2021
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VMC | Final Advanced Test 5 24 JEE ADVANCED 2021
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VMC | Final Advanced Test 4 26 JEE ADVANCED 2021
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VMC | Selection Test 4 JEE 2022

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VMC | Final Advanced Test 5 26 JEE ADVANCED 2021