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Practice Problems

The document contains solutions to problems from the book 'Mechanics of Materials 6th edition' by Riley, Sturges, and Morris, focusing on the analysis of stress and strain as well as beam analysis. It includes various problem numbers along with their corresponding answers, covering topics such as stress, strain, and shear forces. The document is structured into modules, detailing calculations and results for different scenarios in strength of materials.

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5 views4 pages

Practice Problems

The document contains solutions to problems from the book 'Mechanics of Materials 6th edition' by Riley, Sturges, and Morris, focusing on the analysis of stress and strain as well as beam analysis. It includes various problem numbers along with their corresponding answers, covering topics such as stress, strain, and shear forces. The document is structured into modules, detailing calculations and results for different scenarios in strength of materials.

Uploaded by

knightprocoder001
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as PDF, TXT or read online on Scribd
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ME205: Strength of Materials

Problems from the book “Mechanics of Materials 6th edition” by Riley, Sturges, and Morris.
Module 1. Analysis of Stress and Strain
Pb. no. Ans
2-2 σA =106.6 MPa, σB =133.3 MPa, σC =53.3 MPa,
2-4 σAB =7.68 MPa,
2-6 10 mm
2-8 589 kN
2-32 σn =75.6 MPa, τA =106.6 MPa,
2-36 tmin = 40.6 mm
2-46 σab =12.5 MPa, τAB = −9.64 MPa
2-48 σab =155.2 MPa, τAB =53.8 MPa
2-52 σn =70.3 MPa, τn =45.7 MPa
2-58 σx =221 MPa, τn =61 MPa
(a) σp1 =77.7 MPa, at θ = 73.7◦
(b) σp2 =7.72 MPa, at θ = −16.31◦
2-70
(c) σp3 =0
(d) τp = τmax =42.7 MPa
(a) σp1 =203 MPa, at θ = 7◦
(b) σp2 = −3 MPa, at θ = −83◦
2-72
(c) σp3 =0
(d) τp = τmax =103 MPa
2-88 τa = 0, τb = 187.5 kPa, τc = 250 kPa
(a) σp1 =77.7 MPa, at θ = 34.7◦
(b) σp2 =7.72 MPa, at θ = −55.3◦
2-90
(c) σp3 =0
(d) τp = τmax =42.7 MPa
3-6 γxy = 1560 µrad
3-18 ϵn = 175µ, ϵt = −625µ, γnt = 3950µ
ϵp1 = 1576µ, at θ = −65.1◦
ϵp2 = 299µ, at θ = 24.9◦
3-64
ϵp3 = −804µ
γp = ϵp1 − ϵp2 = 1277µ
γmax = ϵp1 − ϵp3 = 2380µ
4-20 σx = −36.6 MPa, σy =248 MPa, τxy = −16.3 MPa
Module 2. Beams
Pb. no. Ans
7-2 11.76 MPa
7-4 5.00 MPa, -2.50 MPa, 6.25 MPa
7-6 97.2 kN.m
7-12 4.19 MPa, -2.91 MPa
7-28 −2x, −x2
7-30 45 − 15x, 45x − 7.5x2
7-32 w(L + x), w2 (x2 + 2Lx − 5L2 )
7-34 93.4 MPa, -93.4 MPa
(a) −12(x + 2), −6(x + 2)2 ,
(b) −12x + 50.4, −6x2 + 50.4x − 24,
7.36
(c) 2.4, 2.4x + 72,
(d) -21.6, −21.6x + 216
(a) −15x + 25.5, −7.5x + 25.5x − 10.88,
7.38 (b) 44.1 MPa,
(c) 53 MPa
7-40 6.89 MPa, -4.14 MPa
7-50
7-52
7-54
7-56
see next page
7-58
7-60
7-62
7-64
7-72 τa = 0, τb = 187.5 kPa, τc = 250 kPa
7-76 (a) 1.51 MPa, (b) 1.72 MPa
7-50 7-54

7-52
7-56
7-58 7-62

𝜎𝑚𝑎𝑥𝑇 = +46.3 𝑀𝑃𝑎, 𝜎𝑚𝑎𝑥𝐶 = −139 𝑀𝑃𝑎


𝜎 = 182.8 MPa 7.64

7-60

𝜎𝑡𝑜𝑝 = −76.9 MPa, 𝜎𝑏𝑜𝑡𝑡𝑜𝑚 = +76.9 Mpa

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