PartC (Ch10 35)
PartC (Ch10 35)
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Part C : Vibration & Oscillation
but the result is that “cycle” can be inserted or removed from a derived unit whenever it makes sense. It
functions outside the rules about units combining algebraically. As a result, both s and s⁄cycle are valid
units for period.
If you want to observe some number of cycles 𝑁, the elapsed time 𝑡 required is proportional to 𝑁. Therfore,
for any particular vibrating motion, the ratio of time interval to number of cycles is always the same. A
particularly useful corresponding pair is that 1 cycle lasts for one period, giving
𝑡 𝑇
= =𝑇 . (10.1)
𝑁 1
There is another often-used parameter that is sort of the alter ego of the period, in that it conveys the same
information about the motion. Especially when dealing with very rapid motion, rather than how much time
each cycle takes, it can be easier to consider how many cycles are completed in each second. This is called
the frequency of the oscillation, denoted by f. The root unit of frequency is cycles/second, which hints at
the mathematical relationship between frequency and period,
1
𝑓= . (10.2)
𝑇
Because it is used so much, cycles/second is given the name hertz, abbreviated Hz, named after a student
of the sound scientist Helmholtz. More about Helmholtz is in Chapter 28.
Often when considering a vibration, we imagine that it goes on forever, with no beginning or end. But any
real vibration does have a beginning and end, and the time interval during which the motion occurs is called
the duration. Duration doesn’t have any special algebraic symbol. Take particular notice of the difference
between the duration and the period of an oscillation.
10b. Displacement
Before getting into how systems oscillate, we need more tools for
describing motion. Our definition of speed in Eq. 4.21 relied on the fact
that sound always travels at a steady speed, but oscillating objects keep
changing speed. We need to distinguish between a few kinds of speed,
which first requires distinguishing between a few kinds of distance.
Consider the motion of the tip of the tine of a tuning fork (see Figure
10.1). Suppose that the extremes of motion are 2 mm apart and that the
motion repeats itself every 𝑇 = 3.8 ms (which makes this a tuning fork
for the pitch “middle C”). In particular, consider the cycle during which
the tine moves from the far left to the far right, and then back to the far
left.
Distance
There is a sense in which the tine has moved 4 mm during that time.
This is what physicists call distance traveled, or just distance. Distance
is always a positive number. Often d is chosen as the algebraic symbol.
Displacement
If you compare the beginning and ending positions, without regard for
where the tine was in between, there is another sense in which the tine Figure 10.1
has not moved at all. Physicists call this idea displacement, and in this Tuning fork vibrating. Arrows
case the displacement is zero. When an object does not end in the same relate to the motion of the dot on the
place as it started, completely describing the result (but not the full upper right corner.
motion) requires giving both the straight-line distance between the
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Part C : Vibration & Oscillation
beginning and ending positions, and the direction of that line. It turns out to be handy to lump both distance
and direction together, and to call the combination the displacement. The fact that direction is included
makes displacement a vector.
In general, to describe a direction with a number, you need to first specify a special reference direction, for
instance “towards North” or “to the right on the page.” Then any other direction can be specified by angles
away from the reference direction.
But luckily, for oscillations there are only two directions involved, because the motion is along a single
axis. That is, the motion is one-dimensional. If we choose to call one direction positive and the other
negative, then the vector idea reduces to simply a signed number. In principle, either direction can be
chosen as positive. But nearly always, positive is chosen to be rightward or upward.
The magnitude of a vector is its size. That is, it is all the information in the vector except its direction. So,
we could correctly say, “For any motion, the magnitude of the displacement due to that motion is the
straight-line distance from the beginning point to the ending point.” For our one-dimensional case,
magnitude is obtained just by taking the absolute value.
It is not necessary to have an actual object moving in order to refer to a displacement. The displacement
from point A to point B is still just a distance and direction, imagining the points to be the start and end
points of a hypothetical motion.
Position
If we want to quantify where an object is, we can do so by first choosing a special point of reference, called
an origin, and choosing a reference direction. We can then specify a position as a displacement from that
origin. Since a position is a special kind of displacement, it is a vector. A common choice for the algebraic
symbol of position is 𝑟. But again, for oscillations, choosing a reference direction reduces to choosing
which direction along the axis of motion to call positive. Positions are then just signed numbers. In that
situation, the usual variable name choice is 𝑥, or sometimes 𝑦 or 𝑧.
Once an origin has been chosen, the displacement between two other places is given by the difference of
their positions. For this reason, a common algebraic symbol for displacement is 𝛥𝑥. The relation to position
is then given by
Δ𝑥 = 𝑥end − 𝑥begin . (10.3)
Notice that this has the pattern “later value minus earlier value,” or “final minus initial” or “ending minus
beginning.” This pattern usually requires a little attention because the parts are reversed from the order in
which they occurred.
Very likely, you once learned in a math class to use the variable 𝑥 to represent “the unknown” in a question.
In physics, that is never done. Algebra is already abstract enough; it’s a bad plan to make the equations
even more obscure by using a generic 𝑥. In principle, algebra allows you to use any symbol that you desire
to represent any quantity. But in practice, it is strongly recommended to use variables that remind you, as
well as anyone reviewing your work, of what type of physical quantity it represents. Reserve 𝑥 for position.
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Part C : Vibration & Oscillation
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Part C : Vibration & Oscillation
is ready to start into the next cycle. Thus 𝛥𝑥 = 0 m and 𝑣2 = 0 m⁄s exactly. Compare that to the tine’s
average speed over one cycle
4 mm m
𝑠2 = = 1.053 . (12.3)
3.8 ms s
This occurs as a result of the change in direction, which results in a distance traveled that is different from
the magnitude of the displacement. So in general, the average speed will equal the magnitude of the average
velocity only when there is no change in direction between the start and finish.
We might calculate the average velocity over a very large number of cycles. Although the tine travels over
a greater and greater distance as time goes on, the displacement can never be larger than 2 mm. So as the
𝛥𝑡 in the denominator gets larger, the average velocity must get very small. The longer the time interval,
the closer the average velocity is to zero. This result is not unreasonable. Certainly, there is a sense in
which the vibrating tuning fork never actually travels anywhere. And depending on the choice of initial
and final positions, the velocity can be positive or negative, so that an average of zero is not a surprise
mathematically. But these observations don’t help us understand the details of that motion. For that, we
need the next few chapters.
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Part C : Vibration & Oscillation
The magnitude of the instantaneous velocity is the instantaneous speed. This brings us back to the
situation where speed equals the magnitude of the velocity. For ease of use, the word “instantaneous” is
often dropped from these names. However, the word “average” is never dropped from the terms average
velocity or average speed.
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Part C : Vibration & Oscillation
One such situation is in determining the direction of acceleration. One approach is to carefully use Eq. 14.1
to determine the sign of 𝑎. This can be done as long as you know the signs and relative sizes of the
velocities; actual numbers are not necessary. For example, suppose that you throw a ball up into the air and
consider a time interval from just after the ball leaves your hand to just before the ball reaches its highest
point. Taking upwards to be positive, 𝑣begin > 𝑣end > 0 (ball is moving in positive direction but slowing
down). This implies that 𝑣end − 𝑣begin < 0, so the acceleration is in the negative direction.
Another approach which may be useful is to anthropomorphize the moving object, and ask, “In which
direction is it trying to move?” For instance, even though the thrown ball is moving upwards, we can
imagine that it is “trying” to go down, again giving a negative acceleration.
One of the original motivations for defining acceleration was the following very useful model, first studied
thoroughly by Galileo Galilei.5
Any object that has a reasonably large weight, and is reasonably compact
in shape, when near the surface of the earth and not in contact with
anything else, moves with an acceleration of 9.8 m⁄s 2 in the downwards
direction.
Such an object is said to be in free-fall. This special value is named the acceleration due to gravity,
denoted by 𝑔. The next digit, the 0.01 m⁄s 2 place, depends on where you are on the earth, but it is quite
close to 0, so that using just two significant figures gives you better than 1% accuracy. The usual custom
is to not treat 𝑔 as a vector quantity, but as a positive numerical quantity. Thus, if we choose the usual axis
for vertical motion, with the upward direction being positive, the above principle is expressed by the
equation
𝑎free-fall = −𝑔 . (14.2)
Be careful to use this value only in appropriate cases. If there is anything other than gravity influencing an
object’s motion, then its acceleration is highly unlikely to be 𝑔 . Inappropriately assuming that an
acceleration is 9.8 m⁄s 2 is a common error in introductory physics courses.
In a typical introductory physics course, because of the constant acceleration due to gravity, the kinematics
of constantly accelerated motion (also called projectile motion) is studied extensively. However, our goal
is to describe oscillations, for which even the acceleration is not constant. Gravity will be useful in a few
parts of this book. But to make progress, we need to move directly to the cause of acceleration: force and
the subject of dynamics.
5
Galileo Galilei, Dialogs Concerning Two New Sciences, trans. Henry Crew and Alfonso de Salvio (New York:
Dover Publications Inc., (1638) 1954).
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Part C : Vibration & Oscillation
where 𝐹 is the standard symbol for force, and the subscript “on” reminds us that the force is applied on the
object.
While one can always choose to make this definition for accelerating a single object, it is conceivable that
it might fail to be consistent if you apply the same forces to different objects. If force A accelerates a car
twice as much as force B, does that guarantee that force A also accelerates a ball twice as much as force B?
Is force A twice B for any object at all? Centuries of experience give us the answer, “Yes.” This model
has been spectacularly successful.
Of course, any given force will give the ball a much larger acceleration that it will give the car; cars are
much harder to move. As usual with proportional quantities, it is useful to take their ratio. In this case, the
ratio of force applied on an object to the resulting acceleration describes how hard it is to accelerate that
object, and is defined as the object’s inertial mass, usually shortened to just mass and denoted by 𝑚.
Rewriting that ratio gives one of the most famous equations of physics, Newton’s Second Law
𝐹
= 𝑚 ⇒ 𝐹 = 𝑚𝑎 . (15.2)
𝑎
Although it arises as a sort of side-effect in Eq. 15.2, mass is a fundamental type of quantity in the SI
system, like distance and time. More intuitively, it describes how much material, or how much “stuff,” an
object has. Linking directly to Eq. 15.2, mass describes how hard it is to shake the object back and forth.
There is also an extremely close connection to how hard it is to lift the object, which is explored in
Section 18b.
These equations require some new units to be defined. The SI root unit of mass is the gram, with the symbol
g. Other units of mass can be obtained by adding prefixes to gram in the usual way. However, the SI base
unit of mass is the kilogram (kg), which means that the kilogram is used to build named derived units. This
is the only place in SI where the base and root units are different, which can be a source of difficulty.
Usually, the safest method is to always use kilograms in calculations. Something with a mass of 1 kg
weighs a little more than two pounds.
Equation 15.2 tells us that the SI basic unit for force must be (kg ⋅ m⁄s 2 ). Because this is such a mouthful,
this derived unit is given a name of its own, the root unit newton (N). A newton of force is roughly equal
to a quarter pound. Keep in mind that the newton has the kilogram (not gram) inside. When working with
small objects, with masses given in grams, you must remember to convert to kilograms before combining
with newtons.
Notice that when a force pushes in one direction, the pushed object always accelerates in that direction
(even when its velocity is in the opposite direction, such as when the object is being slowed to a stop).
Therefore, 𝐹 and 𝑎 will either both be positive or both be negative, making 𝑚 always positive in Eq. 15.2.
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Part C : Vibration & Oscillation
as much as force B, does that guarantee that force A also stretches a rubber band twice as much as force B?
Is force A twice B for anything springy? Centuries of experience give us the answer, “Yes, within limits.”
Hooke’s model has been very successful, but two drawbacks prevent it from being considered universal.
The first is that if real springy things are stretched or compressed too far, the consistency of Hooke’s model
between different springs starts to fail. Indeed, real springs will eventually break. The second drawback is
that there exist a few oddball springy things that never fit the model. But avoiding those oddball “springs”
and keeping 𝛥𝐿 small-to-moderate is not a severe restriction.
The same force will deform different things by different amounts. For a given spring, the ratio of force to
resulting displacement describes how difficult it is to deform the spring. Rewriting the ratio gives Hooke’s
Law, traditionally written as
𝐹by
= −𝑘 ⇒ 𝐹by = −𝑘 𝛥𝑥 . (16.2)
𝛥𝑥
Here 𝑘 is called the spring stiffness constant, often shortened
to spring constant. The new quantities need new units to be
defined. The SI unit for force is the newton (N), which is roughly
equal to a quarter pound. SI defines the newton in terms of more
fundamental quantities, but that isn’t needed here. (For checking
calcualtions, N = kg ⋅ m/s 2 . For the reasons behind this, see
Chapter 15.) Spring stiffness is not a root quantity in SI either.
From the equation we can see that the derived basic unit for the
spring constant is N⁄m.
In Eq. 16.2 the deformation 𝛥𝐿 has been replaced by the
displacement 𝛥𝑥 of one end of the spring. With the assumption
that the other end is held unmoving, the two are exactly equal,
so this is a change in perspective, not in the math. It is handy, Figure 16.1
because most often we are interested in the displacement of some Spring before and while it is stretched.
object that is attached to the spring. But keep in mind that at its
foundation, Hooke’s Law is about deformation, not displacement. Notice that 𝛥𝑥 refers to displacement of
the spring’s end from a very specific place, namely from the position where no external force is acting to
deform the spring. This is called the equilibrium position for the end of the spring.
For a stretched spring, there are two forces available to focus on. One is the force applied to the spring, for
instance by the hand in Figure 16.1, which was the 𝐹on in Eq. 16.1. The other is the force with which the
spring is pulling back, for instance on the hand, which is the 𝐹by in Eq. 16.2. Hooke’s Law is usually written
with the second option in mind, in order to keep the definition all about the spring, regardless of what is
stretching it. It turns out that 𝐹on and 𝐹by are always equal in magnitude and exactly opposite in direction
(that is Newton’s Third Law, which won’t get much attention in this book), so that the proportion in Eq. 16.1
holds for either force.
Because a spring always wants to return to its undeformed state, the position-dependent force that it
provides is called a restoring force. 𝐹by and 𝛥𝑥 will always be in opposite directions. In our treatment of
physics along one axis this means they have opposite signs, making the ratio in Eq. 16.2 negative. The
minus sign on the right side makes that negative explicit, so that the spring constant 𝑘 will always be
positive.
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Part C : Vibration & Oscillation
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Part C : Vibration & Oscillation
string is balanced by the downward pull of gravity. With the usual choice of upwards as positive, the math
might be
𝐹net = 𝐹string + 𝐹grav = (3 N) + (−3 N) = 0 . (18.2)
Notice that the negative is inside the parentheses.
Whenever it works to add things together to get the total effect, physicists call it superposition. Perhaps
this gets such a grandiose name because the addition is often of things fancier than simple numbers. For
instance, here we are dealing with superposition of vectors. In any case, superposition is a useful model
that will show up multiple times, for instance in Chapter 37.
18b. Gravitational Forces
A hanging rock is actually very useful.
In Chapter 14, it is noted that near the earth’s surface all large, dense objects in free-fall are observed to
accelerate downwards at a certain rate 𝑔. Newton’s Second Law then implies that any such object is feeling
a force which causes that acceleration, a force due to the phenomenon of gravity. Since the acceleration is
always the same, Newton’s Second Law becomes a relationship between mass and this force,
𝐹grav = −𝑚𝑔 . (18.3)
The magnitude of this force of gravity |𝐹grav | is called the object’s weight (although there are a few minor
disagreements between physicists over precisely what the word “weight” means). Weight and mass are so
closely related by Eq. 18.3 that in everyday life it is rarely necessary to distinguish between them. However,
they are not exactly the same concept. If an object were to move far from the earth’s surface, it would still
have an unchanged mass. But if it were dropped back towards earth, it would no longer accelerate at the
rate 𝑔, and Eq. 18.3 would not be correct.
The last paragraph only really considered objects in free-fall. However, there has never been any indication
that the force on an object due to gravity depends on how the object is moving. Even stationary objects
experience the same gravitational force given by Eq. 18.3, and this provides an extremely practical way to
produce well-known forces. Just assemble some rocks of well-known mass and hang one from some
support, like a string.
1. If the rock is stationary, then it is not accelerating: 𝑎 = 0 .
2. Eq. 15.2 therefore tells us that the net force on the rock is zero: 𝐹net = 𝑚𝑎 = 0 .
3. Eq. 18.1 therefore tells us that the forces from the string and from gravity have equal magnitude:
0 = 𝐹net = 𝐹string + 𝐹grav .
4. Eq. 18.3 tells us the magnitude of the force from the string: 𝐹string = −𝐹grav = 𝑚𝑔 .
5. Finally, Newton’s Third Law tells us that if the string is applying 𝐹 = 𝑚𝑔 upwards on the rock, then
the rock is pulling downward on the string (or other support) with a force of the same magnitude.
Thus, you can create well-known forces by hanging well-known masses. Of course, this force is always
downwards, but by running the string over a pulley, we can create a string-pulling force in any direction
we like.
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Part C : Vibration & Oscillation
the right side in Figure 19.1. With nothing on the spring, its lower end is at position 𝑦0 . When stretched,
the displacement of the end is
𝛥𝑦 = 𝑦 − 𝑦0 , (19.1)
which is negative.
When an object is hung from the spring, gravity pulls down on the
object with a constant force, while the spring pulls up on the object
with a force that depends on the object’s position. So, if the object
is lowered gently, it will hang motionless with the spring stretched
just enough to balance the gravitational force. The new equilibrium
position 𝑦1 is determined by the fact that the forces on the object
cancel each other
−𝑚𝑔 = 𝐹grav = −𝐹spring = −(−𝑘 𝛥𝑦)
(19.2)
= 𝑘(𝑦1 − 𝑦0 ) .
If the object is then pulled below this new equilibrium position, then
the spring force increases to be larger than the gravitational force,
pulling the object up. If the object is moved above its equilibrium
position then the spring force decreases, and the larger gravitational
force pulls the object down. In fact, the total force on the object is
now Figure 19.1
𝐹grav + 𝐹spring = −𝑚𝑔 − 𝑘(𝑦 − 𝑦0 ) Spring being stretched down from
(19.3) equilibrium position 𝑦0 .
𝐹net = 𝑘(𝑦1 − 𝑦0 ) − 𝑘(𝑦 − 𝑦0 )
𝐹net = 𝑘(𝑦 − 𝑦1 ) .
where a substitution has been made in the second line using Eq. 19.2. Thus, we have a new result: this
mass-and-spring system behaves as if gravity is not involved at all! Now that 𝑦1 is the new equilibrium
position for this spring, the spring can be either compressed or stretched away from that equilibrium.
While being able to solve questions with numerical answers (like the one in Figure 9.1) is nice, this
conclusion about hanging springs is the kind of thing that a physicist really likes. By carefully combining
a few equations, we find a result that applies in more than just one specific situation, and the result simplifies
how we can think about those situations. Best of all, it is a little surprising, in that the spring stiffness
constant is completely unaffected by the change in equilibrium.
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Part C : Vibration & Oscillation
Notice that a velocity graph is missing one piece of information that is not missing for position graphs: it
does not tell anything about the starting position. However, given a velocity graph and the physical position
at the time origin (or, really, any particular time), it is possible to reconstruct the complete position versus
time, at least in principle. On the other hand, while the origin of a position axis needs to be associated with
a physical location, the origin of a velocity axis needs no clarification; it just means “not moving.”
Going the other way is a bit easier. Given a position-time
graph, we can obtain the velocity at any point by finding the
slope. Thus, it is possible to find the entire velocity-time graph
for a motion from its position-time graph.
For instance, Figure 20.2 shows two graphs describing the
motion of a ball bouncing on the ground. First, consider the
position-time graph. Notice that although the graph looks
similar to what you would see if a ball bounced across a room,
that is not necessarily the motion it describes. The graph only
tells us the vertical position of the ball (described by the
variable y), with the floor chosen as the y origin. There is no
horizontal position information. The ball might be bouncing
straight up and down. In fact, that would be nice, since it’s
Figure 20.2
most similar to oscillating motions that we are interested in.
Position (height) and velocity graphs of ball
The velocity-time graph has been positioned so that its time bouncing on the ground.
axis lines up with the time axis from the position-time graph.
The velocity is positive while the ball is moving up, and negative while the ball is moving down. At the
bounces, a corner in the position-time graph indicates that the velocity changes suddenly. As a result, the
velocity-time graph has an almost-vertical line at that point.
The general rule for creating a velocity-time graph from a position-time
graph is slope to value.
The following are some useful steps to follow when implementing that general rule.
1. Mark times where the position-time graph has zero slope (that is, it is horizontal).
2. Between the zero marks, label the time intervals according to whether the position-time slope is positive
or negative. This tells you where the velocity-time graph should be above or below the horizontal axis.
3. Look for where the position-time graph is steepest. At those points in time, the velocity-time graph
should be farthest from the horizontal axis.
4. Look for places where the position-time graph is a straight line. Over those time intervals, the velocity
is constant, so the velocity-time graph should be horizontal.
5. If the overall motion keeps returning to the same position,
then the object must experience an equal “amount” of
positive and negative velocity. Although the details are
beyond the scope of this book, the consequence is that if
the space between the velocity curve and the horizontal
axis were colored in, then the colored areas above and
below the axis must be equal.
Often the places of zero velocity found in step 1 are points in
time. Sometimes, however, there are whole time intervals with
Figure 20.3
no motion. Figure 20.3 shows an example, which might
Graphs of frog jumping, with pauses between
represent the height of a frog as it jumps. Notice that in this jumps.
graph, the 𝑦 position (or height) origin was not placed at the
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Part C : Vibration & Oscillation
ground. The ground is a natural choice, but it is not required. Also notice that during the times with no
motion, the rule is still “horizontal position graph gives zero on velocity graph.”
20b. Acceleration Graphs
As with position and velocity, you can graph acceleration of an
object versus time as well. And since the defining relationship
between acceleration and velocity (Eq. 14.1) has exactly the
same pattern as the defining relationship between velocity and
position (Eq. 12.1), everything in Chapter 13 and Section 20a
has an analogous rule for acceleration. Once again, slope of a
line on a velocity-time graph gives acceleration. If the line
connects two points on the velocity-time graph, then its slope
is the average acceleration between those points. But it is more
useful to define instantaneous acceleration as the slope of a
tangent line at a single point on a velocity-time graph. Once
again, an acceleration-time graph can be obtained by applying
the slope-to-value rule to a velocity-time graph. Figure 20.4
extends the example of a bouncing ball to an acceleration-time
graph.
In the abstract, given a position-time graph, you could now find
the corresponding acceleration-time graph. First make the
velocity graph, and then all the steps from Section 20a apply
for getting the acceleration graph from the velocity graph. But
in practice, trying to do slope-to-value twice in a row can get Figure 20.4
sloppy. To get cleaner and more accurate graphs, it helps to Position, velocity, and acceleration graphs of a
consider the following additional clues. bouncing ball.
1. If the moving object is ever in free-fall, then the
acceleration is known to be downwards and constant, in particular 𝑎 = −𝑔 = −9.8 m⁄s 2. Figure 20.4
has examples of this. Working backwards, this means that the velocity-time graph is a straight line
with negative slope.
If the moving object is not in free-fall, then cases of constant acceleration are rather rare.
2. Sharp corners in the position-time graph indicate brief intervals of time with large “pulses” of
acceleration.
3. Considering the forces that the object feels may be helpful.
Because of Newton’s Second Law, the direction and relative
magnitudes of forces will be the same as those of
accelerations. That is, a graph of the net force on the object
versus time would look exactly the same as the acceleration
graph, although the scale on the vertical axis would be
different.
20c. The “Circle of Physics”
Attaching an object to the end of a spring that can be both
compressed and stretched, as in Figure 16.2, applies a restoring
force on the object, with the result that the object can oscillate.
Figure 20.5
This is why Hooke’s Law is particularly important to the subject
of sound. It is true that a restoring force does not have to be Circle of physics equations.
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Part C : Vibration & Oscillation
linear in order to cause oscillation. But it is a very common situation. In this situation, exactly what sort
of motion will occur?
Combining our equations from kinematics and dynamics, we
find that the four main variables are linked by four equations,
as illustrated in Figure 20.5. The figure uses the assumption
that the displacement of the object and the stretch or
compression of the spring are exactly the same, Δ𝐿 = 𝛥𝑥. The
variables 𝛥𝑥, 𝑣, and 𝑎 all refer to the object, while 𝐹 refers to
the force applied on the object by the spring.
When equations link variables in a “circle of physics” like this,
physicists get very excited. It means that only certain types of
motion can satisfy the equations. When solving a numerical
question, as in Chapter 9, finding four equations relating four
unknowns would mean that you have found enough information
to answer the question. The current situation is similar, except
that some of these equations involve changes over time. As a
result, the “solution” is not just a number; the solution is an
entire type of motion, that is, a particular way that position
varies in time.
Calculus is necessary to derive exactly the kind of motion that
works, but graphing techniques can well illustrate how the
equations constrain the possible motions. Our goal is to find a
Figure 20.6
displacement-time graph such that, after obtaining velocity-,
An oscillation that fails to satisfy circle of
acceleration-, and force-time graphs, we will come back to the
physics, because bottom 𝛥𝑥 graph doesn’t
same position-time graph after working all the way around the match top graph.
circle of physics.
For instance, the top of Figure 20.6 shows a plausible
motion for this oscillation. It is constant velocity motion
(the dotted lines) alternating with reversals of direction (the
solid curves). In the next two graphs, slope-to-value is used
to obtain the corresponding velocity and acceleration
graphs. A graph of the force F would look the same as the
graph of a, because Newton’s Second Law tells us that they
are proportional with the same sign. Finally, Hooke’s Law
tells us that displacement should be proportional to the
force, but with the opposite sign.
Since the bottom graph of Figure 20.6 does not match the
top graph, this motion does not satisfy the circle of physics.
The most significant failing is that the straight segments in
the top graph result in intervals of zero in the bottom graph.
The displacement-time graph that does successfully satisfy
the circle of physics is illustrated in Figure 20.7. Graphs of
this shape are called sinusoidal graphs because the
mathematical functions that generate them are the sine or
cosine functions.
Figure 20.7
This particular, extremely common natural motion, arising
Oscillation that does satisfy the circle of physics.
from a linear restoring force, is named Simple Harmonic
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Part C : Vibration & Oscillation
Motion, or SHM for short. SHM and sinusoidal motion more generally are extremely important to the
study of sound.
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Part C : Vibration & Oscillation
48
Part C : Vibration & Oscillation
49
Part C : Vibration & Oscillation
𝛥𝑥 2𝑥𝑚 𝑥𝑚
𝑠𝑎𝑣𝑔,𝑝𝑝 = |𝑣𝑎𝑣𝑔,𝑝𝑝 | = = 1 =4 . (24.1)
𝛥𝑡 2
𝑇 𝑇
However, that is not the maximum speed achieved during the motion. The steepest point on the sinusoidal
graph is where the displacement is zero. It turns out that a tangent line at that point has the slope
𝜋 𝑥𝑚
𝑠𝑚 = 𝑠𝑎𝑣𝑔,𝑝𝑝 = 2𝜋 . (24.2)
2 𝑇
Deriving that result is most easily done with calculus, and thus is beyond the scope of this book. But it
should be apparent on a graph that the maximum slope is roughly 50% higher than the average found in
Eq. 24.1.
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Part C : Vibration & Oscillation
things being equal) the object moves more slowly, resulting in a longer period and a lower frequency. The
exact relationship is
𝑚
𝑇0 = 2𝜋√ , (27.1)
𝑘
1 𝑘
𝑓0 = √ . (27.2)
2𝜋 𝑚
Although these equations are offered without derivation, you should still be able to verify that they do,
indeed, exhibit the relationships described above. The results are called the natural period and natural
frequency of that particular system. The subscript zero is commonly used to indicate this natural status,
i.e., that the variable represented arises is a property of the vibrating system with no external influence.
𝑠 𝐴
𝑓0 = √ , (28.1)
2𝜋 𝑉ℎ
where 𝑠 is the speed of sound for the air in the bottle, and ℎ, 𝐴, and 𝑉 are dimensions of the bottle,
respectively the length of the bottle neck (along the axis of vibration), the cross-sectional area of the bottle
neck (perpendicular to the axis of vibration), and the volume of the bottle body. You can see in the form
of this equation hints that it came from Eq. 27.2, although exactly how the two relate has become obscured.
6
Hermann von Helmholtz, On the sensations of tone as a physiological basis for the theory of music, trans.
Alexander J. Ellis (London: Longmans, Green, and Co., 1885), 43.
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Part C : Vibration & Oscillation
Beyond where Eq. 28.1 comes from, there are other complications that can arise. When whistling, your
oral cavity is open at both your lips and the back of your throat—how does that change things? And why
should a steady blowing over the mouth of a bottle cause it to vibrate? (See Chapter 196 for a partial
answer.) In any case, the fact that it does vibrate in response to an external cause is the reason that the setup
is called a “resonator” instead of a “vibrator.”
You have probably experienced the Helmholtz resonator in another
way, when someone opens a single window in a travelling car and a
throbbing sound results. Here the cabin of the car forms the volume,
and the open window forms the neck. However, Eq. 28.1 can’t be
applied properly because there is no apparent length to the neck. The
opening in the window provides a clear area A, but what should you
use for the variable h?
When faced with such a situation in a physics question, one usually
needs to look back at where the equation came from. Certainly, it is
not a recipe for success to cast about for another value to use. To Figure 28.2
think, “I’m missing a length… maybe it will work if I just use the Dimensions of Helmholtz resonator with
neck diameter,” is guessing, not science. no neck.
The length of the neck was used in Figure 28.1 because that is also
the length of the oscillating chunk of air. With an opening instead of a neck, there can still be an oscillating
chunk of air, as in Figure 28.2, but how thick is it? Answering that question requires physics well beyond
the scope of this book. So instead, use this rule of thumb: the effective thickness / neck length is 85% of
the smallest width of the opening,
ℎeff = 0.85 ⋅ 𝑤min . (28.2)
For a circular opening, 𝑤min is the diameter. For an oblong opening, 𝑤min is the width, not the length.
Many similar shapes act as Helmholtz resonators, even though the shape makes it difficult to say precisely
how large the “neck,” or even the “body,” is. In fact, a detailed investigation of even a perfectly cylindrical
neck will reveal that it has an effective length that is slightly longer than its physical length. Nevertheless,
judicious use of the two models above can give quite acceptable results.
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Part C : Vibration & Oscillation
This qualitative idea is fine as far as it goes, but it took many talented scientists several centuries during the
Renaissance to figure out and implement a very special property of energy. If energy is quantified in the
right way, then the total amount of energy around us is constant. Energy is not “stuff” in the same sense as
objects in the material world. But it nevertheless shares some of the properties of “stuff”: it can be moved
around, but it cannot be created or destroyed, although it can be converted from one form to another. In
technical language, energy is conserved.
In order to make this energy conservation idea work, from time to time physicists have had to invent (or
discover, depending on your perspective) new forms of energy. For instance, a book held high in the air
can be dropped, with the result that its kinetic energy increases. If energy is to be conserved, then the book
must have had that energy all along, simply by virtue of being high in the air; this is another form of
potential energy. (An even more enlightened understanding of this energy is that is belongs to the
combination of the book and the earth, which are pulling each other together with gravity.) A hot pan from
an oven can burn you, which is certainly affecting you, so it must have energy by virtue of being hot; this
is named thermal energy. (It was not until the 1840s that James Joule convincingly showed that thermal
energy was the same sort of thing as mechanical energy.) Several other forms of energy are known, but
they are beyond the scope of this book.
This model of conserved energy has been so successful over history, that it is now considered one of the
most fundamental tenants of physics, even more basic than Newton’s Second Law (see Chapter 15). Every
time a new form of energy has been found, the guiding principle of energy conservation has helped us to
understand that new form. Sometimes it is useful to approach a physics question in a way that doesn’t make
energy conservation evident. For example, when a soccer ball rolls to a stop on level grass, its mechanical
energy clearly is not conserved, but useful information can be obtained without identifying where that
energy went. Nevertheless, you can also be assured that the energy did go somewhere, either to a different
object, or into a non-mechanical form, or both.
When energy is transferred from one object or system to another in a macroscopic way, the amount of
energy transferred is called the work done in the process. Be warned that this terminology only sometimes
aligns with the English use of the word. Simply holding a heavy object stationary in the air could well be
called work in the everyday sense, but in the physics sense no work is being done, because the object is not
receiving any additional energy.
The SI root unit for energy is the joule, abbreviated J. A joule is not a huge amount of energy. If you drop
a 5 pound bag of sugar or flour a distance of 5 cm, it gains roughly 1 J of kinetic energy. In a thermal form,
it would take about 130 J to warm a thimbleful of water from room temperature to hot tap water temperature.
How the joule derives from other units will be seen in Chapter 30.
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Part C : Vibration & Oscillation
effort. Stretching farther requires more effort, just as with gravity. But also, the force against which you
are pulling gets larger, due to Hooke’s law from Chapter 16. As a result, the spring potential energy is
proportional to the square of the distance stretched 𝛥𝑥,
𝑃𝐸spring ∝ 𝛥𝑥 ⋅ 𝛥𝑥 = 𝛥𝑥 2 . (30.2)
Stiffer springs are also harder to stretch, so the spring stiffness constant 𝑘 should show up. The final
formula turns out to be
1
𝑃𝐸spring = 2𝑘 𝛥𝑥 2 . (30.3)
Notice that the square means that spring potential energy is always positive, whether the spring is stretched
or compressed. This correctly corresponds to the observation that one must do work on a spring to deform
it either way. Notice also the 12 , which tends to show up in equations that have quantities squared.
The equation for kinetic energy has a similar form to that of Eq. 30.3, but it is harder to rationalize because
it involves velocity 𝑣 instead of position. The equation for an object with mass 𝑚 is
1 1
𝐾𝐸 = 2𝑚𝑣 2 = 2𝑚𝑠 2 . (30.4)
Because the velocity is squared, the kinetic energy is again positive regardless of the sign (that is, the
direction) of the velocity. This allows for the second form, using speed 𝑠 instead of velocity. Even when
it is necessary to specify the direction of velocity with a fully-fledged vector, the square of a vector is
defined so that it is a positive number.
As usual, these equations tell us not only how to quantify energy, but also how the SI units relate. Working
from Eq. 30.4, we have
m 2 m2
1 J = 1 kg ( ) = 1 kg 2 . (30.5)
s s
Notice that a 1 kg object moving at 1 m⁄s does not have 1 J of kinetic energy, but rather 0.5 J. When doing
the calculation, the numbers combine separately from the units.
This book always uses a variable for energy that contains a capital 𝐸. Other references, in an effort to avoid
two-letter variables, use 𝑈 for potential energy and 𝑇 for kinetic energy.
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Part C : Vibration & Oscillation
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Part C : Vibration & Oscillation
1 2 1 2
𝐸tot = 2 𝑘 𝑥𝑚 = 2 𝑚 𝑣𝑚
𝑥𝑚 2 2
𝑥𝑚 (31.7)
2
𝑘 𝑥𝑚 = 𝑚 (2𝜋 ) = (2𝜋)2 𝑚 2
𝑇 𝑇
𝑚 (31.8)
𝑇 = 2𝜋√ ,
𝑘
where in the second line the maximum velocity from Eq. 24.2 was substituted.
So, by combining basic energy ideas, we have derived the special property of SHM that is given with no
justification in Chapter 27. This is an example of the power of the energy viewpoint. To obtain the same
result considering only forces and accelerations would be far more difficult.
This derivation is also an example of the power of physics in general. When reading about this formula in
Chapter 27, it probably seems to come out of nowhere. At that point, there is no reason to expect squares,
let alone square roots, in the equations relating to SHM. But now we have derived that formula using
relatively simple ideas about energy. In physics we often find that relatively straightforward relationships
can lead to surprisingly complex behavior or can imply surprisingly complex relationships.
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Part C : Vibration & Oscillation
The amplitude need not be the usual “maximum displacement” amplitude. In Chapter 24 and in Eq. 31.6,
𝑠𝑚 and 𝑣𝑚 are velocity amplitudes. Even if you do not know the equation relatting your amplitude to an
energy-related quantity, you can still use this proportionality to compare two natural oscillations or waves.
What about oscillating motion that is not natural motion? You can often identify this situation if the
frequency of the motion is determined by something outside the system. Then this proportion can still be
useful, but it’s necessary to be more careful that the energy and amplitude are directly related. For example,
the maximum kinetic energy would always be proportional to the square of the velocity amplitude, because
of Eq. 31.6. However, the kinetic energy might not be proportional to the maximum displacement.
Figure 33.1
Damped harmonic motion.
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Part C : Vibration & Oscillation
Figure 33.2
Shrinking amplitude of damped harmonic motion. DHM itself is not shown.
The independence of frequency and amplitude is extraordinarily important for the production of music.
Consider what would happen if, as the vibration of a guitar string fades away, the frequency (and hence
pitch) from the string changed!
The amplitude of DHM also decays in a very specific way. Although the amplitude is only evident where
the DHM reaches an extreme displacement, we can imagine the amplitude as a continuous function that
forms an envelope around the oscillation, as shown by the dotted lines in Figure 33.1.
For DHM, over equal intervals of time (or an equal number of cycles) the
oscillation amplitude is reduced by a specific constant fraction.
For example, suppose that for some system the amplitude is reduced by 10% for every five cycles. If it
were to start with an amplitude of 5 cm, as time goes on the amplitude would change as illustrated in Figure
33.2. For equal-sized steps along the time axis, the amplitude is reduced to a specific fraction of its previous
value. This would work for any time interval that you might choose; for a different one (say, three cycles),
the reducing fraction would simply be different.
Notice that this means that the oscillation will never die away completely, because the amplitude will
always be larger than zero. Of course, it will eventually become imperceptibly small.
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Part C : Vibration & Oscillation
For DHM, over equal intervals of time (or an equal number of cycles) the
total energy is reduced by a specific constant fraction.
Second, for a specific time interval, the reducing fraction for energy is the square of the reducing fraction
for amplitude.
59