Cartan Dirac Good
Cartan Dirac Good
Contents
1 Introduction 428
16 Conclusions 475
428 W. A. Rodrigues Jr.
1 Introduction
In this paper we first recall some essential tools concerning the theory
of differential forms in the Cartan, Hodge and Clifford bundles over a n-
dimensional manifold M equipped with a metric tensor g ∈ sec T20 M of
arbitrary signature (p, q), p + q = n and also equipped with metric com-
patible connections, the Levi-Civita (D̊) and a general Riemann-Cartan
(D) one1 . After that we solved with details some exercises involving
different grades of difficult, ranging depending on the readers knowledge
from kindergarten, intermediate to advanced levels. In particular we
show how to express the derivative ( d) and coderivative (δ) operators as
functions of operators related to the Levi-Civita or a Riemann-Cartan
connection defined on a manifold, namely the standard Dirac operator
(∂|) and general Dirac operator (∂). Those operators are then used to
express Maxwell equations in both a Lorentzian and a Riemann-Cartan
spacetime. We recall also important formulas (not well known as they
deserve to be) for the square of the general Dirac and standard Dirac
operators showing their relation with the Hodge D’Alembertian (♦), the
covariant D’ Alembertian () ˚ and the Ricci operators (R̊a , Ra ) and
˚
Einstein operator () and the use of these operators in the Einstein-
Hilbert gravitational theory. Finally, we study the Bianchi identities.
Recalling that the first Bianchi identity is DT a = Rab ∧ θb , where T a
and Rab are respectively the torsion and the curvature 2-forms and {θb }
is a cotetrad we ask the question: Who is D ? T a ? We find the correct
answer (Eq.(218)) using the tools introduced in previous sections of the
paper. Our result shows explicitly that the formula “D ?T a = ?Rab ∧θb ”
recently found in [10] and claimed to imply a contradiction in Einstein-
Hilbert gravitational theory is wrong. Two very simple counterexamples
contradicting the wrong formula for D ? T a are presented. A detailed
account of the issues discussed in the paper appears in the table of con-
tents2 . We call also the reader attention that in the physical applications
we use natural units for which the numerical values of c,h and the grav-
itational constant k (appearing in Einstein equations) are equal to 1.
Dg = 0 and T 6= 0. (1)
Dg 6= 0 and T = 0. (2)
Dg = 0 and T = 0, (3)
3 We left the toplogy of M unspecified for a while.
4 We denote by sec(X(M )) the space of the sections of a bundle X(M ). Note that
all functions and differential forms are supposed smooth, unless we explicitly say the
contrary.
5 The precise definitions of those objects will be recalled below.
430 W. A. Rodrigues Jr.
Dg 6= 0 and T 6= 0. (4)
Dg = 0 and R = 0,
for some purposes. See the example of the Nunes connections in Section 15.
Differential Forms on Riemannian (Lorentzian). . . 431
^4
the volume element τg ∈ sec T ∗ M and a time orientation denoted
by ↑. We omit here the details and ask to the interested reader to con-
sult, e.g., [22]. A general spacetime will be represented by a pentuple
(M, g, D, τg , ↑).
Df X+gY P = f DX P+gDY P,
DX (P + Q) = DX P + DX Q,
DX (f P) = f DX (P)+X(f )P,
DX (P ⊗ Q) = DX P ⊗ Q + P⊗DX Q. (7)
Given Q ∈ sec Tsr M the relation between DQ, the absolute differen-
tial of Q and DX Q the covariant derivative of Q in the direction of the
vector filed X is given by
with
ηab = diag(1, ..., 1 −1, ... − 1)
| {z } | {z } . (11)
p times q times
Moreover, defining
eb = qbν ∂ ν
the set {ea } with ea ∈ sec T M is an orthonormal basis for T U . The
dual basis of T U is {θa }, with θa = qµa dxµ . Also, {θb } is the reciprocal
basis of {θa }, i.e. θa · θb = δba .
D∂ µ V = D∂ µ (V α ∂ α ), D∂ µ C = D∂ µ (Cα θα ) (18)
and using the properties of a covariant derivative operator introduced
above, D∂ µ V can be written as:
D∂ µ V = D∂ µ (V α ∂ α ) = (D∂ µ V )α ∂ α
= (∂ µ V α )∂ α + V α D∂ µ ∂ α
∂V α
ρ α + α
= + V Γµρ ∂ α := (Dµ V )∂ α , (19)
∂xµ
Also, we have
∂µ qνa + ωµb
a b
qν − Γaµb qνb = 0. (23)
Moreover, if we define the object
q = ea ⊗ θa = qµa ea ⊗ dxµ ∈ sec T11 U ⊂ sec T11 M, (24)
which is clearly the identity endormorphism acting on sections of T U ,
we find
a
Dµ qνa := (D∂ µ q)ν = ∂µ qνa + ωµb
a b
qν − Γaµb qνb = 0. (25)
where ai · bj := g(ai , bj ).
We agree that if r = s = 0, the scalar product is simple the ordinary
product in the real field.
Also, if r 6= s, then Ar ·Bs =^0. Finally, the scalar product is extended
by linearity for all sections of T ∗ M .
For r ≤ s, Ar = a1 ∧ ... ∧ ar , Bs = b1 ∧ ... ∧ bs we define the left
contraction by
X
y : (Ar , Bs ) 7→ Ar yBs = i1 ....is (a1 ∧...∧ar )·(bi1 ∧...∧bir )∼ bir +1 ∧...∧bis
i1 <... <ir
(28)
where ∼ is the reverse mapping (reversion) defined by
^p
∼: sec T ∗ M 3 a1 ∧ ... ∧ ap 7→ ap ∧ ... ∧ a1 (29)
^
and extended by linearity to all sections of T ∗ M . We agree that for
V0 ∗
α, β ∈ sec T M the contraction is the ordinary (pointwise) product
V0 ∗ Vr ∗
in the real
Vs ∗ field and that if α ∈ sec T M , Ar ∈ sec T M , Bs ∈
sec T M then (αAr )yBs = Ar y(αBs ). Left contraction
^ is extended
by linearity to all pairs of elements of sections of T ∗ M , i.e., for A, B ∈
^
sec T ∗ M
X
AyB = hAir yhBis , r ≤ s, (30)
r,s
^r
where hAir means the projection of A in T ∗M .
It is also necessary to introduce the operator of right contraction
denoted by x. The definition is obtained from the one presenting the
436 W. A. Rodrigues Jr.
1 p
? θµ1 ...µp = |det g|g µ1 ν1 ...g µp νp ν1 ...νn ϑνp+1 ...νn . (34)
(n − p)!
Some identities (used below) involving the Hodge star operator, the ex-
terior product and contractions are10 :
Ar ∧ ?Bs = Bs ∧ ?Ar ; r = s
Ar · ?Bs = Bs · ?Ar ; r + s = n
Ar ∧ ?Bs = (−1)r(s−1) ? (Ãr yBs ); r ≤ s (35)
Ar y ? Bs = (−1)rs ? (Ãr ∧ Bs ); r + s ≤ n
?τg = sign g; ?1 = τg .
10 See also the last formula in Eq.(45) which uses the Clifford product.
Differential Forms on Riemannian (Lorentzian). . . 437
satisfying:
(i) d(A + B) = dA + dB;
(ii) d(A ∧ B) = dA ∧ B + Ā ∧ dB;
(36)
(iii) df (v) = v(f );
(iv) d2 = 0,
V0 ∗
for every A, B ∈ sec T ∗ M , f ∈ sec
V
T M and v ∈ sec T M .
TheVHodge codifferential operator in the Hodge bundle is the mapping
r ∗ Vr−1 ∗
δ : sec T M → sec T M , given for homogeneous multiforms, by:
where V
? is the Hodge star operator. The operator δ extends by linearity
to all T ∗ M
The Hodge Laplacian (or Hodge D’Alembertian) operator is the map-
ping ^ ^
♦ : sec T ∗ M → sec T ∗ M
given by:
♦ = −(dδ + δd). (38)
dd = δδ = 0; ♦ = (d − δ)2
d♦ = ♦d; δ♦ = ♦δ
(39)
δ? = (−1)r+1 ? d; ?δ = (−1)r d?
dδ? = ?δd; ?dδ = δd?; ?♦ = ♦ ? .
5 Clifford Bundles
Let (M, g, ∇) be a Riemannian, Lorentzian or Riemann-Cartan struc-
ture11 . As before let g ∈ sec T02 M be the metric on the cotangent
bundle associated with g ∈ sec T20 M . Then Tx∗ M ' Rp,q , where Rp,q
11 ∇ may be the Levi-Civita connection D̊ of g or an arbitrary Riemann-Cartan
connection D.
438 W. A. Rodrigues Jr.
1 1
C = s + va θa + bab θa θb + aabc θa θb θc + pθn+1 , (41)
2! 3!
where τg := θn+1 = θ0 θ1 θ2 θ3 ...θn is the volume element and s, va , bab ,
V0 ∗
aabc , p ∈ sec T M ,→ sec C`(M, g).
Vr ∗ Vs ∗
Let Ar , ∈ sec T M ,→ sec C`(M, g), Bs ∈ sec T M ,→ sec C`(M, g).
For r = s = 1, we define the scalar product as follows:
V1 ∗
For a, b ∈ sec T M ,→ sec C`(M, g),
1
a·b= (ab + ba) = g(a, b). (42)
2
We identify the exterior product ((∀r, s = 0, 1, 2, 3, ..., n) of homogeneous
forms (already introduced above) by
Ar ∧ Bs = hAr Bs ir+s , (43)
Vk ∗
where hik is the component in T M (projection) of the Clifford field.
The exterior product is extended by linearity to all sections of C`(M, g).
Differential Forms on Riemannian (Lorentzian). . . 439
The scalar product, the left and the right are defined for homogeneous
form fields that are sections of the Clifford bundle in exactly the same
way as in the Hodge bundle and they are extended by linearity for all
sections of C`(M, g).
In particular, for A, B ∈ sec C`(M, g) we have
X
AyB = hAir yhBis , r ≤ s. (44)
r,s
The main formulas used in the present paper can be obtained (details
V1 ∗
may be found in [22]) from the following ones (where a ∈ sec T M ,→
sec C`(M, g)):
aBs = ayBs + a ∧ Bs , Bs a = Bs xa + Bs ∧ a,
1
ayBs = (aBs − (−1)s Bs a),
2
Ar yBs = (−1)r(s−r) Bs xAr ,
1
a ∧ Bs = (aBs + (−1)s Bs a),
2
Ar Bs = hAr Bs i|r−s| + hAr Bs i|r−s|+2 + ... + hAr Bs i|r+s|
Xm
= hAr Bs i|r−s|+2k
k=0
T ∗ M ,→ C`(M, g)
V
for any A, B, C ∈ sec
440 W. A. Rodrigues Jr.
∂A = ∂ ∧ A + ∂yA
∂ ∧ A = θa ∧ (Dea A), ∂yA = θa y(Dea A). (49)
Recall that the reciprocal basis of {θb } is denoted {θa } with θa ·θb = ηab
(ηab = diag(1, ..., 1, −1, ..., −1)) and that
Dea θb = −ωac
b c
θ = −ωabc θc , (50)
1 bc ^2
ωa = ωa θb ∧ θc ∈ sec T ∗ M ,→ sec C`(M, g), (51)
2
we have (by linearity) that [16] for any A ∈ sec T ∗ M ,→ sec C`(M, g)
V
1
Dea A = ∂ea A + [ωa , A], (52)
2
1
where ∂ea is the Pfaff derivative, i.e., for any A = p! Ai1 ...ip θ ...θ
i1 .ip
∈
Vp ∗
sec T M ,→ sec C`(M, g) it is:
1
∂ea A = [ea (Ai1 ...ip )]θi1 ...θ.ip . (53)
p!
Differential Forms on Riemannian (Lorentzian). . . 441
∂| = θa D̊ea = ϑα D̊eα ,
∂| A = ∂| ∧A + ∂|yA (54)
where
α = g(a, ) , a = g(α, ) (65)
We now show that for any structure (M, g, D) such that Dg = 0 we have
for c, u, v ∈ sec T M ,
But since
[u, v](c · c) =D[u,v] (c · c) = 2(D[u,v] c) · c, (70)
we have from Eq.(69) that
It is crucial here to take into account the place where the contraction in
the Riemann tensor takes place according to our conventions.
We also have:
dϑρ = − 21 cραβ ϑα ∧ ϑβ
(76)
Deα ϑρ = −Lραβ ϑβ
V1 ∗
where ωβρ ∈ sec T M are the connection 1-forms, Lραβ are said to be
V2 ∗
the connection coefficients in the given basis, and the T ρ ∈ sec T M
ρ V 2 ∗
are the torsion 2-forms and the Rβ ∈ sec T M are the curvature
2-forms, given by:
ωβρ = Lραβ ϑα ,
1 ρ α
T ρ = Tαβ ϑ ∧ θβ (77)
2
1
Rρµ = Rµ ραβ ϑα ∧ ϑβ .
2
1 α
Multiplying Eqs.(74) by 2ϑ ∧ ϑβ and using Eqs.(76) and (77), we
get:
dϑρ + ωβρ ∧ ϑβ = T ρ ,
(78)
dωµρ + ωβρ ∧ ωµβ = Rρµ .
We can show that the torsion and (Riemann) curvature tensors can
be written as
T = eα ⊗ T α , (79)
R = eρ ⊗ eµ ⊗ Rρµ . (80)
Differential Forms on Riemannian (Lorentzian). . . 445
Dϑρ = T ρ , (81)
“ Dωµρ = Rρµ . ” (82)
Xνµ11....ν
....µp
q
(v1 , ..., vr ) = X(v1 , ..., vr , eν1 , ..., eνq , ϑµ1 , ..., ϑµp ). (84)
µ ....µ
The exterior covariant differential D of Xν11....νqp on a manifold with
a general connection D is the mapping:
^r ^r+1
D : sec T ∗ M → sec T ∗ M , 0 ≤ r ≤ 4, (85)
such that14
µ ....µ
(r + 1)DXν11....νqp (v0 , v1 , ..., vr )
r
X
= (−1)ν Deν X(v0 , v1 , ..., v̌ν , ...vr , eν1 , ..., eνq , ϑµ1 , ..., ϑµp )
ν=0
X
− (−1)ν+ς X(T(vλ , vς ), v0 , v1 , ..., v̌λ , ..., v̌ς , ..., vr , eν1 , ..., eνq , ϑµ1 , ..., ϑµp ).
0≤λ,ς ≤r
(86)
DXνµ11....ν
....µp
q
= dXνµ11....ν
....µp
q
+ ωµµs1 ∧ Xνµ1s....ν
....µp
q
+ ... + ωµµs1 ∧ Xνµ11....ν
....µp
q
(87)
− ωνν1s ∧ Xνµs1....ν
....µp
q
− ... − ωµµs1 ∧ Xνµ11....ν
....µp
s
.
7.1 Properties of D
The exterior covariant derivative D satisfy the following properties:
Vr ∗ Vs ∗
(a) For any X J ∈ sec T M and Y K ∈ sec T M are sets of
indexed forms16 , then
Dgµν = 0. (90)
1
ω cd = (−ccjk η dj + cd cj ca dj b k
jk η − η ηbk η cja )θ . (92)
2
15 The authors of reference [27] ρ
knows exactly what they are doing and use “Dωµ =
Rρµ ” only as a short notation. Unfortunately this is not the case for some other
authors.
16 Multi indices are here represented by J and K.
Differential Forms on Riemannian (Lorentzian). . . 447
Let moreover,
bραβ = −(£eρ g)αβ , (95)
where £eρ is the Lie derivative in the direction of the vector field eρ .
Then, we have the noticeable formula (for a proof, see, e.g., [22]):
1 ρ 1 ρ
Lραβ = L̊ραβ + Tαβ + Sαβ , (96)
2 2
ρ
where the tensor Sαβ is called the strain tensor of the connection and
can be decomposed as:
ρ ρ 2 ρ
Sαβ = S̆αβ + s gαβ (97)
n
ρ
where S̆αβ is its traceless part, is called the shear of the connection, and
1 µν ρ
sρ = g Sµν (98)
2
is its trace part, is called the dilation of the connection. We also have
that connection coefficients of the Levi-Civita connection can be written
as:
1
L̊ραβ = (bραβ + cραβ ). (99)
2
Moreover, we introduce the contorsion tensor whose components in
an arbitrary basis are defined by
448 W. A. Rodrigues Jr.
1 ρ
Kραβ = Lραβ − L̊ραβ = ρ
(T + Sαβ ), (100)
2 αβ
and which can be written as
1
Kραβ = − g ρσ (gµα Tσβ
µ µ
+ gµβ Tσα µ
− gµσ Tαβ ). (101)
2
We now present the relation between the Riemann curvature ten-
sor Rµ ραβ associated with the Riemann-Cartan connection D and the
Riemann curvature tensor R̊µ ραβ of the Levi-Civita connection D̊.
Rµ ραβ = R̊µ ραβ + Jµ ρ[αβ] , (102)
where:
Jµ ραβ = D̊α Kρβµ − Kρβσ Kσαµ = Dα Kρβµ − Kρασ Kσβµ + Kσαβ Kρσµ . (103)
dQ = ϑα ∧ (D̊eα Q) = ∂| ∧Q,
δQ = −ϑα y(D̊eα Q) = ∂|yQ. (110)
we can write:
♦ = ∂| 2 = ∂| · ∂| + ∂| ∧ ∂| (115)
or,
∂| 2 = (∂|y + ∂| ∧)(∂|y + ∂| ∧)
= ∂|y ∂| ∧ + ∂| ∧ ∂|y (116)
1 αβ h i
∂| · ∂| = g D̊eα D̊eβ + D̊eβ D̊eα − bραβ D̊eρ . (117)
2
Applying this operator to the 1-forms of the frame {θα }, we get:
1
(∂| · ∂|)ϑµ = − g αβ M̊ρ µ αβ θρ , (118)
2
where:
M̊ρ µ αβ = eα (L̊µβρ ) + eβ (L̊µαρ ) − L̊µασ L̊σβρ − L̊µβσ L̊σαρ − bσαβ L̊µσρ . (119)
1 αβ
(∂| · ∂|)ω = g D̊α D̊β ωα1 ...αr θα1 ∧ . . . ∧ θαr , (120)
r!
Differential Forms on Riemannian (Lorentzian). . . 451
where D̊α D̊β ωα1 ...αr are the components of the covariant derivative of
1
ω, i.e., writing D̊eβ ω = r! D̊β ωα1 ...αr θα1 ∧ . . . ∧ θαr , it is:
D̊β ωα1 ...αr = eβ (ωα1 ...αr ) − L̊σβα1 ωσα2 ...αr − · · · − L̊σβαr ωα1 ...αr−1 σ . (121)
where R̊βµ are the components of the Ricci tensor of the Levi-Civita
connection D̊ of g. Thus we have a really beautiful result:
where R̊µ = R̊βµ θβ are the Ricci 1-forms of the manifold. Because of
this relation, we call the operator ∂| ∧ ∂| the Ricci operator of the manifold
associated to the Levi-Civita connection D̊ of g.
We can show [22] that the Ricci operator ∂| ∧ ∂| satisfies the relation:
iσ ω := ϑσ yω. (129)
Observe that applying the operator given by the second term in the
r.h.s. of Eq.(128) to the dual of the 1-forms ϑµ , we get:
where we have used the Eqs.(35). Then, recalling the definition of the
curvature forms and using the Eq.(28), we conclude that:
1
R̊ρσ ∧ (ϑρ yϑσ y ? ϑµ ) = 2 ? (R̊µ − R̊ϑµ ) = 2 ? G̊ µ , (131)
2
˚ = 1 ?−1 (R̊ρσ ∧ iρ iσ ) ? .
(132)
2
Differential Forms on Riemannian (Lorentzian). . . 453
Obviously, we have:
˚ µ = G̊ µ = R̊µ − 1 R̊ϑµ .
θ (133)
2
In addition, it is easy to verify that ?−1 (∂| ∧ ∂|)? = − ∂| ∧ ∂| and ?−1 (R̊σ ∧
iσ )? = R̊σ yjσ . Thus we can also write the Einstein operator as:
and
2 µ
∂| ϑ = −(∂| ω̊ρµ − ω̊ρσ ω̊σµ )ϑρ . (137)
so that:
∂ 2 = ∂ 2y + L+ + ∂ 2 ∧ . (139)
454 W. A. Rodrigues Jr.
1 1 1
F= Fµν dxµ ∧ dxν = Fµν θµ ∧ θν = Fµν θµν , (146)
2 2 2
1 1 1 1p
?F = Fµν (?θµν ) = ?
Fρσ ϑρσ = (Fµν |det g|g µα g νβ αβρσ )ϑρσ
2 2 2 2
(147)
Thus
? 1 p
Fρσ = (?F)ρσ = Fµν |det g|g µα g νβ αβρσ . (148)
2
δ ? F = 0.
dF = θα ∧ (D̊∂ α F )
1 h i
= θα ∧ D̊∂ α (Fµν θµ ∧ θν )
2
1 α h i
= θ ∧ (∂α Fµν )θµ ∧ θν − Fµν Γ̊µ ρ ν ν µ
αρ θ ∧ θ − Fµν Γ̊αρ θ ∧ θ
ρ
2
1 h i
= θα ∧ (D̊α Fµν )θµ ∧ θν
2
1
= Dα Fµν θα ∧ θµ ∧ θν
2» –
1 1 1 1
= D̊α Fµν θα ∧ θµ ∧ θν + D̊µ Fνα θµ ∧ θν ∧ θα + D̊ν Fαµ θν ∧ θα ∧ θµ
2 3 3 3
» –
1 1 α µ ν 1 α µ ν 1 α µ ν
= D̊α Fµν θ ∧ θ ∧ θ + D̊µ Fνα θ ∧ θ ∧ θ + D̊ν Fαµ θ ∧ θ ∧ θ
2 3 3 3
1 “ ”
= D̊α Fµν + D̊µ Fνα + D̊ν Fαµ θα ∧ θµ ∧ θν .
6
So,
1
dF = (∂α Fµν )θα ∧ θµ ∧ θν (150)
2
1
= (∂α Fµν + ∂µ Fνα + ∂ν Fαµ ) θα ∧ θµ ∧ θν ,
6
dF = 0 ⇐⇒ ∂α Fµν +∂µ Fνα +∂ν Fαµ = 0 ⇐⇒ D̊α Fµν +D̊µ Fνα +D̊ν Fαµ = 0.
(151)
Differential Forms on Riemannian (Lorentzian). . . 457
δ ? F = −θα y(D̊∂ α ? F)
1 n o
= − θα y D̊∂ α [? Fµν θµ ∧ θν ]
2
1 n o
= − θα y (∂α ? Fµν )θµ ∧ θν − ? Fµν Γ̊µαρ θρ ∧ θν − ? Fµν Γ̊ναρ θµ ∧ θρ
2
1 α n ? o
= − θ y (∂α Fµν )θµ ∧ θν − ? Fρν Γ̊ραµ θµ ∧ θν − ? Fµρ Γ̊ραν θµ ∧ θν
2
1 α n o
= − θ y (D̊α ? Fµν )θµ ∧ θν
2
1n o
=− (D̊α ? Fµν )g αµ θν − (D̊α ? Fµν )g αν θµ
2
= −(D̊α ? Fµν )g αµ θν
= −[D̊α (? Fµν g αµ )]θν
= −(D̊α ? F να )]θν . (152)
δF = −J,
2 −1
(−1) ? d ? F = −J,
−1
?? d ? F = − ? J,
d ? F = − ? J. (154)
1 n o
δF + J = − θα y D̊∂ α [Fµν θµ ∧ θν ] + Jν θν (155)
2
= (−D̊α F να + Jν )θν .
17 We observe that in terms of the “classical” charge and “vector” current densities
we have J =ρθ0 − ji θi .
458 W. A. Rodrigues Jr.
Then
δF + J = 0 ⇔ D̊α F αν = J ν . (156)
We also observe that using the symmetry of the connection coeffi-
cients and the antisymmetry of the F αν that Γ̊ναρ F αρ = −Γ̊ναρ F αρ = 0.
Also,
p 1
Γ̊α
αρ = ∂ρ ln |det g| = p ∂ρ |det g| ,
|det g|
and
D̊α F αν = ∂α F αν + Γ̊α
αρ F
ρν
+ Γ̊ναρ F αρ
= ∂α F αν + Γ̊α
αρ F
ρν
1 p
= ∂ρ F ρν + p ∂ρ ( |det g|)F ρν .
|det g|
Then
D̊α F αν = J ν ,
p p p
|det g|∂ρ F ρν + ∂ρ ( |det g|)F ρν = |det g|J ν ,
p p
∂ρ ( |det g|F ρν ) = |det g|J ν ,
1 p
p ∂ρ ( |det g|F ρν ) = J ν , (157)
|det g|
and
1 p
δF = 0 ⇔ D̊α F αν = J ν ⇔ p ∂ρ ( |det g|F ρν ) = J ν . (158)
|det g|
or
1
(Dα Fµν + Dµ Fνα + Dν Fαµ )θα ∧ θµ ∧ θν
6
11 α ρ
− T θ ∧ θσ ∧ [θα yFµν (θµ ∧ θν )]
2 2 ρσ
1
= (Dα Fµν + Dµ Fνα + Dν Fαµ )θα ∧ θµ ∧ θν
6
1 α
− Tρσ Fµν θρ ∧ θσ ∧ δαµ θν
2
1
= (Dα Fµν + Dµ Fνα + Dν Fαµ )θα ∧ θµ ∧ θν
6
1 σ
− Tαµ Fσν θα ∧ θµ ∧ θν
2
1
= (Dα Fµν + Dµ Fνα + Dν Fαµ )θα ∧ θµ ∧ θν
6
1 σ σ σ
− (Tαµ Fσν + Tµν Fσα + Tνα Fσµ )θα ∧ θµ ∧ θν
6
1
= (Dα Fµν + Dµ Fνα + Dν Fαµ )θα ∧ θµ ∧ θν
6
1 σ σ σ
+ (Fασ Tµν + Fµσ Tνα + Fνσ Tαµ )θα ∧ θµ ∧ θν .
6
i.e.,
σ σ σ
dF = 0 ⇐⇒ Dα Fµν +Dµ Fνα +Dν Fαµ +Fσα Tµν +Fµσ Tνα +Fνσ Tαµ = 0.
(161)
Also, taking into account that dF = 0 ⇐⇒ δ ? F = 0 we have using the
second noticeable formula in Eq.(111) that
Now,
and
T α y(θα ∧ ?F)
1 α β
= Tβρ (θ ∧ θρ )y(θα ∧ (? Fµν θµ ∧ θν )
4
1 α?
= Tβρ Fµν (θβ ∧ θρ )y(θα ∧ θµ ∧ θν )
4
1 α ? µν β ρ
= Tβρ F θ y[θ y(θα ∧ θµ ∧ θν )]
4
1 α ? µν β ρ
= Tβρ F θ y(δα θµ ∧ θν − δµρ θα ∧ θν + δνρ θα ∧ θµ )
4
1 α ? µν β 1 α ? µν β 1 α ? µν β
= Tβα F θ y(θµ ∧ θν ) − Tβµ F θ y(θα ∧ θν ) + Tβν F θ y(θα ∧ θµ )
4 4 4
1 α ? µν β 1 µ ? ρν β 1 µ ? νρ β
= Tβα F θ y(θµ ∧ θν ) − Tβρ F θ y(θµ ∧ θν ) + Tβρ F θ y(θµ ∧ θν )
4 4 4
1 α ? µν µ ? ρν µ ? νρ β
= (Tβα F − Tβρ F + Tβρ F )θ y(θµ ∧ θν )
4
1 α ? µν µ ? ρν µ ? νρ
= (Tβα F − Tβρ F + Tβρ F )(δµβ θν − δνβ θµ )
4
1 α ? µν µ ? ρν µ ? νρ 1 α ? νµ ν ? ρµ ν ? µρ
= (Tµα F − Tµρ F + Tµρ F )θν − (Tµα F − Tµρ F + Tµρ F )θν
4 4
1 α ? µν µ ? ρν ν ? µρ
= (Tµα F − Tµρ F + Tµρ F )θν (164)
2
1 α ? µν
Dα ? F αν + (Tµα µ ? ρν
F − Tµρ ν ? µρ
F + Tµρ F )=0 (165)
2
and we have
1 α ? µν
dF = 0 ⇔ δ ? F =0 ⇔ Dα ? F αν + (Tµα F − Tµρµ ? ρν
F + Tµρν ? µρ
F ) = 0.
2
(166)
Finally we express the non homogenous Maxwell equation δF = −J in
arbitrary coordinates using the Riemann-Cartan connection. We have
i.e.,
1 α ? µν
Dα F αν + (Tµα µ ? ρν
F − Tµρ ν ? µρ
F + Tµρ F ) = Jν. (168)
2
12 Bianchi Identities
where
ωba = ωcb
a c
θ ,
1 a b
T a = Tbc θ ∧ θc (171)
2
1
Rab = Rb acd θc ∧ θd . (172)
2
Since the T a and the Rab are index form fields we can apply to those
objects the exterior covariant differential (Eq.(87)). We get
Also,
DRab = dRab + ωca ∧ Rcb − ωbc ∧ Rac
= d2 ωba + dωca ∧ ωbc − dωbc ∧ ωca − Rac ∧ ωbc + Rcb ∧ ωca
= dωca ∧ ωbc − (dωca + ωda ∧ ωcd ) ∧ ωbc − dωca ∧ ωbc + (dωbc + ωdc ∧ ωbd ) ∧ ωca
= −ωda ∧ ωcd ∧ ωbc + ωdc ∧ ωbd ∧ ωca
= −ωda ∧ ωcd ∧ ωbc + ωcd ∧ ωbc ∧ ωda
= −ωda ∧ ωcd ∧ ωbc + ωda ∧ ωcd ∧ ωbc = 0. (174)
So, we have the general Bianchi identities which are valid for any one
of the metrical compatible structures18 classified in Section 2,
DT a = Rab ∧ θb ,
DRab = 0. (175)
Now,
a ρ ρ
∂µ Tαβ = (∂µ qρa )Tαβ + qρa ∂µ Tαβ , (177)
and using the freshman identity (Eq.(23)) we can write
a b a b ρ ρ ρ
ωµb Tαβ = ωµb qρ Tαβ = Laµb qρb Tαβ − (∂µ qρa )Tαβ . (178)
So,
a a b
∂µ Tαβ + ωµb Tαβ
ρ ρ
= qρa ∂µ Tαβ + Γaµb qρb Tαβ
ρ ρ
= qρa (Dµ Tαβ + Γκµα Tκβ + Γκµβ Tακ
ρ
). (179)
18 For non metrical compatible structures we have more general equations than the
Cartan structure equations and thus more general identities, see [22].
Differential Forms on Riemannian (Lorentzian). . . 463
κ
Now, recalling that Tµα = Γκµα − Γκαµ we can write
ρ
qρa (Γκµα Tκβ + Γκµβ Tακ
ρ
)θµ ∧ θα ∧ θβ (180)
ρ µ
= qρa Tµα
κ
Tκβ θ α
∧θ ∧θ .β
If we now recall the steps that lead us to Eq.(166) we can write for
the torsion 2-form fields T a ,
dT a = ? ?−1 d ? ?−1 T a
= (−1)n−2 ? δ ?−1 T a = (−1)n−2 (−1)n−2 sgng ? δ ? T a
= (−1)n−2 ?−1 δ ? T a . (186)
464 W. A. Rodrigues Jr.
with sgng = det g/ |det g|. Then we can write the first Bianchi identity
as
δ ? T a = (−1)n−2 ? [Rab ∧ θb − ωba ∧ T b ], (187)
we end with
δ?Ta
1 α ? aµν
= −(Dα ? T aαν + (Tµα T µ ? aρν
− Tµρ T ν ? aµρ
+ Tµρ T ))θν . (190)
2
Also, writing
1∗ a
?Rab = R θc ∧ θd , (191)
2 b cd
we have:
?(Rab ∧ θb ) = θb y ? Rab
1
= θb y(? Rba cd θc ∧ θd )
2
= ? Rba cd η bc θd
= ? Rcacd θd = ? Rcac d θd = ? Rcac d qdν θν . (192)
Differential Forms on Riemannian (Lorentzian). . . 465
1 α ? aµν
(Dα ? T aαν )θν = −δ?T a + (Tµα T µ ? aρν
−Tµρ T ν ? aµρ
+Tµρ T )θν , (198)
2
and taking into account the second formula in Eq.(111) we can write
1 α ? aµν
θα y(D∂α ?T a ) = −δ?T a + (Tµα T µ ? aρν
−Tµρ T ν ? aµρ
+Tµρ T )θν . (199)
2
θα y(D∂α ? T a )
1
= θα y[D∂α (qρa ? T ρµν θµ ∧ θν )]
2
1
= ϑα y[∂α (qρa ? T ρµν )θµ ∧ θν + qρa ? T ρµν D∂α (θµ ∧ θν )]
2
1
= ϑα y[(∂α qρa )? T ρµν θµ ∧ θν + qρa ∂α (? T ρµν )θµ ∧ θν + qρa ? T ρµν D∂α (θµ ∧ θν )]
2
1
= ϑα y[(∂α qρa )? T ρµν θµ ∧ θν + qρa Dα (? T ρµν )θµ ∧ θν ]
2
= (∂α qρa )? T ρµν δµα θν + qρa Dα (? T ρµν )δµα θν . (200)
Solution: First we recall the ?Rab ∧ θb = θb ∧ ?Rab and then use the
formula in the third line of Eq.(35) to write:
R̊ab ∧ θb = 0. (207)
468 W. A. Rodrigues Jr.
Now, the second term in this last equation is null because according to
the Eq.(106), −Rba ad = Rba da = Rbd are the components of the Ricci
tensor, which is a symmetric tensor for the Levi-Civita connection. For
the first term we get
R̊aacd θc ∧ θd = 0, (208)
which implies that as we stated above that
R̊aacd = 0. (209)
But according to Eq.(106) the R̊aacd are not the components of the Ricci
tensor, and so there is not any contradiction. As an additional ver-
ification recall that the standard form of the first Bianchi identity in
Riemannian geometry is
Making b = a we get
14 Direct Calculation of D ? T a
We now present using results of Clifford bundle formalism, recalled
above (for details, see, e.g., [22]) a calculation of D ? T a .
We start from Cartan first structure equation
By definition
D ? T a = d ? T a + ωba ∧ ?T b . (213)
^2
Now, if we recall Eq.(39), since the T a ∈ sec T ∗ M ,→ sec C`(M, g)
we can write
d ? T a = ?δT a . (214)
δT a = δ dθa + ωba ∧ θb
δT a = − ∂| 2 a
θ − dδθa + δ(ωba ∧ θb )
Eq.(115) ˚ a
= −θ − (∂| ∧ ∂|)θa − dδθa + δ(ωba ∧ θb )
Eq.(127) ˚ a
= −θ − R̊a − dδθa + δ(ωba ∧ θb )
˚ a − Ra + J a − dδθa + δ(ωba ∧ θb )
= −θ (216)
So, we have
˚ a − ?Ra + ?J a − ?dδθa + ?δ(ωba ∧ θb )
d ? T a = − ? θ
and finally
˚ a − ?Ra + ?J a − ?dδθa + ?δ(ωba ∧ θb ) + ωba ∧ ?T b (218)
D ? T a = − ? θ
1
g = ∂1 ⊗ ∂1 + ∂2 ⊗ ∂2. (227)
sin2 ϑ
An orthonormal basis for T U is then {ea } with
1
e1 = ∂ 1 , e2 = ∂2, (228)
sin ϑ
with dual basis {θa } given by
1
ω cd = (−ccjk η dj + cd cj ca dj b k
jk η − η ηbk η cja )θ .
2
Then,
472 W. A. Rodrigues Jr.
1
ω 21 = (−c212 η 11 − η 22 η22 η 11 c212 )θ2 = cot ϑθ2 . (232)
2
Then
ω 21 = −ω 12 = cot ϑθ2 ,
ω12 = −ω21 = cot ϑθ2 , (233)
2 2
ω̊21 = cot ϑ , ω̊11 = 0. (234)
Now, from Cartan’ s second structure equation we have
and20
1
R̊2112 = −R̊2121 = −R̊1212 = R̊1221 = . (236)
2
^0
Now, let us calculate ?R12 ∈ sec T ∗ M . We have
?R12 = R
f1 yτ = −(θ1 ∧ θ2 )y(θ1 ∧ θ2 ) = −θ1 θ2 θ1 θ2
2 g
2 2 2
= θ1 θ =1 (237)
and
?R1a ∧ θa = R12 ∧ θ2 = θ2 6= 0. (238)
Now, Evans equation implies that ?R1a ∧ θ1 = 0 for a Levi-Civita con-
nection and thus as promised we exhibit a counterexample to his wrong
equation.
Remark 21 We recall that the first Bianchi identity for (S 2 , g, D̊), i.e.,
DT a = Rab ∧ θb = 0 which translate in the orthonormal basis used above
in R̊b acd + R̊c adb + R̊d abc . = 0 is rigorously valid. Indeed, we have
R̊2 112 + R̊1 121 + R̊2 121 = R̊2 112 − R̊2 112 = 0,
R̊1 212 + R̊1 221 + R̊2 221 = R̊1 212 − R̊1 212 = 0. (239)
20 Observe 1 + R̊2 =
that with our definition of the Ricci tensor it results that R̊ = R̊1 2
−1.
Differential Forms on Riemannian (Lorentzian). . . 473
Now, it is"3,*
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*G&%.,"*3 8& 1.;& that our connection
is characterized by #
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@?
474 W. A. Rodrigues Jr.
h i
R(ek , θa , ei , ej ) = θa c
Dei Dej − Dej Dei − D[e ,e
i j ] ek = 0. (241)
2 2 1 1
T21 = −T12 = cot ϑ , T21 = −T12 = 0. (243)
T 2 = − cot ϑθ1 ∧ θ2 .
If you still need more details, concerning this last result, consider Fig-
ure 1(b) which shows the standard parametrization of the points p, q, r, s
in terms of the spherical coordinates introduced above [17]. According
to the geometrical meaning of torsion, we determine its value at a given
point by calculating the difference between the (infinitesimal)22 vectors
pr1 and pr2 determined as follows. If we transport the vector pq along ps
1
we get the vector ~v = sr1 such that |g(~v , ~v )| 2 = sin ϑ4ϕ. On the other
hand, if we transport the vector ps along pr we get the vector qr2 = qr.
Let w~ = sr. Then,
1
|g(w, ~ 2 = sin(ϑ − 4ϑ)4ϕ ' sin ϑ4ϕ − cos ϑ4ϑ4ϕ,
~ w)| (244)
Also,
1
~u = r1 r2 = −u( ∂2) , u = |g(~u, ~u)| = cos ϑ4ϑ4ϕ. (245)
sin ϑ
22 This wording, of course, means that this vectors are identified as elements of the
Then, the connection D of the structure (S̊ 2 , g, D) has a non null torsion
tensor Θ. Indeed, the component of ~u = r1 r2 in the direction ∂ 2 is
ϕ
precisely Tϑϕ 4ϑ4ϕ. So, we get (recalling that D∂ j ∂ i = Γkji ∂ k )
ϕ
Tϑϕ = Γϕ
ϑϕ − Γ ϕ
ϕϑ = − cot ϑ. (246)
Solution:
16 Conclusions
In this paper after recalling the main definitions and a collection of
tricks of the trade concerning the calculus of differential forms on the
Cartan, Hodge and Clifford bundles over a Riemannian or Riemann-
Cartan space or a Lorentzian or Riemann-Cartan spacetime we solved
with details several exercises involving different grades of difficult and
which we believe, may be of some utility for pedestrians and even for
experts on the subject. In particular we found using technology of the
Clifford bundle formalism the correct equation for D? T a . We show that
the result found by Dr. Evans [10], “D ? T a = ?Rab ∧ T b ” because it
contradicts the right formula we found. Besides that, the wrong formula
is also contradicted by two simple counterexamples that we exhibited
in Section 15 . The last sentence before the conclusions is a crucial
remark, which each one seeking truth must always keep in mind: do
not confuse the Riemann curvature tensor23 of a connection defined in a
given manifold with the fact that the manifold may be bend as a surface
in an Euclidean manifold where it is embedded.
23 The remark applies also to the torsion of a connection.
476 W. A. Rodrigues Jr.
References
[1] Bruhn,G.W., No Energy to be Extracted From the Vacuum, Phys.Scripta
74, 535–536( 2006).
[2] Bruhn G.W, Hehl F.W., Jadczyk A. , Comments on “Spin Connection
Resonance in Gravitational General Relativity”, Acta Physica Polonia B
39 1001-1008 (2008). [arXiv:0707.4433v2]
[3] Bruhn, G. W., Evans’ Central Claim in his Paper #100,
http://www.mathematik.tu-darmstadt.de/˜bruhn/onEvans100-101.html
[4] Carroll, S. M., Lecture Notes in Relativity, http://arxiv.org/PS cache/gr-
qc/pdf/9712/9712019.pdf
[5] Carvalho A. L. T. , and Rodrigues, W. A. Jr, The Non Sequitur
Mathematics and Physics of the ’New Electrodynamics’ of the AIAS
Group, Random Operators and Stochastic Equations 9, 161-206 (2001)
[arXiv:physics/0302016v5]
24 And we hope also on many scientists, see a partial list in [6, 7]!
Differential Forms on Riemannian (Lorentzian). . . 477