Atomic Structure
Atomic Structure
STRUCTURE OF ATOM
John Dalton coined the term atom. The atom is the fundamental particle of matter and
considered to be indivisible and indestructible.
In fact, the atom as the whole is electrically neutral as
number of protons in it is equal to number of electrons.
Gas at low
Pressure Discharge tube
Cathode rays
To vacuum pump
To vacuum pump
H2 gas at low pressure Perforated Cathode
Anode (+)
- +
High voltage
Anode rays Fluorescent ZnS Screen
Fundamental particles:
1) Electron: Electron is a universal constituent discovered by the J.J. Thomson.
Charge: It was determined by Mullikan by oil drop experiment as -1.602x10-19coulombs
or 4.803x10-10 e.s.u.
Mass:9.11x10-28g (nearly equal to 1/1837th of mass of hydrogen atom).
Specific charge:e/m ratio is called specific charge & is equal to 1.76x108 coulombs/gm.
Mass of one mole of electrons: It is 0.55 mg.
Charge on one mole of electron is 96500 coulombs or 1 faraday.
Density: 2.17x1017 g/cc.
3. Neutron (0n1)
* It was discovered by Chadwick by bombarding Be atom with high speed -particles.
𝟒𝐁𝐞𝟗 + 𝟐 𝐇𝐞𝟒 → 𝟔𝐂
𝟏𝟐
+𝟎 𝐧𝟏
* Charge: Charge less or neutral particle.
* Mass:1.675x10-24 g or 1.675x10-27 kg.
* Density:1.5x1014 g/cm3 and is heavier than proton by 0.18%.
* Specific charge: It is zero.
* Among all the elementary particles neutron is the heaviest and least stable.
Properties of Electron, Proton and Neutron
Limitation: It is failed explain the results of scattering experiment of Rutherford and the
stability of atom.
Beam of
particles + Nucleus
i. Most of the -particles passed through the gold foil without any deflection from
their original path.
Bcz atom has largely empty space as most of the -particles passed through
the foil undeflected.
ii. A few of the alpha particles are deflected fairly at large angles while some are
deflected through small angles.
Bcz there is heavy positive charge at the center of the atom which causes
repulsions.
The entire mass of the atom is concentrated in the nucleus.
iii. A very few -particles are deflected back along their path.
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According to Rutherford,
1. Atom is spherical & mostly hollow with lot of
empty space in it.
2. It has a small +ly charged part at its center
known as nucleus.
3. The nucleus is surrounded by electrons.
Electrons revolve round the nucleus with very
high speeds in circular paths called orbits.
4. The number of extra nuclear electrons is equal to the number of units of positive
charge in the nucleus. Therefore, the atom is electrically neutral. Electrons and the
nucleus are held together by electrostatic forces of attraction.
5. Rutherford’s model has resemblances with solar system. Hence, it’s also known as
planetary model of the atom.
6. There is an empty space around the nucleus called extra nuclear part. In this part
electrons are present. As the nucleus of the atom is responsible for the mass of the
atom, the extra nuclear part is responsible for its volume.
Drawbacks:
1. According to the electromagnetic theory of Maxwell, when a
charged particle moves under the influence of attractive force it
loses energy continuously in the form of electromagnetic
radiation. Therefore, an electron in an orbit will emit radiation.
As a result of this, the electron should lose energy at every
turn and move closer and closer to the nucleus following a spiral path.
Ultimate result is that it will fall into the nucleus thereby making the atom unstable.
i.e., Rutherford’s model cannot explain the stability of the atom.
Atomic number(Z): Atomic number denotes the number of protons or the number of
electrons in the neutral atom.
Remember!
In an atom… APE!
A= P= E
Atomic number = number of protons = number of electrons
Mass number (A): The mass number is the total number of protons and neutrons
present in the nucleus of an atom of an element and indicated as A.
Protons and neutrons present in the nucleus of an atom are collectively known as nucleons.
Therefore, the mass number is also known as nucleon number.
Mass number (A) = Number of protons (Z) + Number of neutrons (n)
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The number of neutrons (n) in an atom is equal to the difference between the mass
number and the atomic number.
n = A – Z
Mass Number
A A
Atomic Number Z X OR
Z X
Symbol of Element
1 electron 1 electron
1 electron
Isotopes of an element differ in the number of neutrons present in the nucleus. But they
have the same number of protons and electrons.
Bcz of same number of electrons they show same chemical properties. They, have
different number of neutrons, so they will have different masses and hence different
physical properties.
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Isobars: The atoms of different elements which have the same mass number but
different atomic numbers are called isobars.
Exp: 18 Ar 40 , 19 K 40 , 20 Ca40
They have same number of nucleons. But they are differed chemically because the chemical
characteristics depend upon the number of electrons which is determined by the atomic
number.
Isotones: Isotones are the atoms of different elements which have the same number of
neutrons.
Eg: 6 C14 , 7 N15 , 8 O16 (n = 8)
radiation.
1. Wave length:
The distance between two successive crests, troughs or between any two consecutive
identical points in the same phase of a wave is called wave length. It is denoted by the
letter (lambda).
The wave length is measured in terms of meters (m), centimeters (cm), angstrom units
(A0) nanometers (nm), picometers (pm) and also in millimicrons (m).
The S.I. unit of wavelength is meter, m
2.Frequency:
The number of waves that pass-through a given point in one second is known as
frequency of radiation. It is denoted by the ‘v’ (nue).
Crest Crest
a
a
Trough Trough
SI unit of frequency is per second(s–1) or Hertz (Hz). A cycle is said to be completed when
a wave consisting of a crest and a trough passes through a point.
3.Velocity:
The distance travelled by the wave in one second is called velocity or speed of the wave
(C).
4.Wave number:
The number of waves that can be present at any time in unit length is called wave
number.
It is denoted by (nue bar).
It is the reciprocal of wave length.
1
Wave number = =
5.Amplitude:
The height of the crest or the depth of the trough of the wave is called amplitude of
the wave. It is denoted by A.
The amplitude determines the strength or intensity or brightness of radiation.
6.Time period:
It is the time taken by the wave for one complete cycle or vibrations. It is denoted by
T. It is expressed in second per cycle.
1 1
T= ( where = frequency)
𝑉
Electromagnetic spectrum:
The arrangement of different types of electromagnetic radiations in the order of
increasing wavelengths or decreasing frequencies is known as electromagnetic spectrum.
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increases
10-16 10-12 10-10 10-8 10-7 10-6 10-4 10-2 101 106
decreases
Rays Cosmic - x- Ultra Visible Near Far Micro Radio Long E decreases
rays rays rays violet IR IR wave waves RW
V I B G Y O R
Photoelectric Effect:
When radiations with certain minimum frequency (ν0 ) strike the surface of a metal, the
electrons are ejected from the surface of the metal. It is called photoelectric
effect,electrons emitted are called photoelectron.
For each metal a certain minimum frequency is needed to eject the electrons called as
K.E. constant
o
metal surface by absorbing this energy. The minimum energy of a photon required to
eject an electron from a metal is called work function () of the metal. The remaining
part of the energy (h - ) of photon is used to increase the kinetic energy of the ejected
electron. If o is the threshold frequency and , the frequency of incident light then
Work function, = h o .
According to Einstein, E = h
ATOMIC SPECTRA
Spectrum is the impression produced on a screen when radiations of a particular
wavelengths are analyzed through a prism or diffraction grating. Spectra are broadly
classified into two.
(i) Emission Spectrum.
(ii) Absorption Spectrum.
1. Emission Spectrum: When the radiation emitted from some source, e.g., from the
sun or by-passing electric discharge through a gas at low pressure or by heating some
substance to high temperature etc. is passed directly through the prism and then
received on the photographic plate, the spectrum obtained is called ‘Emission
spectrum’.
Spectrum of a radiation emitted by a substance in its excited state is an emission
spectrum.
Emission Spectrum is of two types:
a. Continuous Spectrum: When white light from any source such as sun, a bulb or any
hot glowing body is analyzed by passing through a prism, it is observed that it splits
up into seven different colors from violet to red, (like rainbow), as shown in fig.
These colors are so continuous that each of them merges into the next. Hence, the
spectrum is called continuous spectrum.
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It may be noted that on passing through the prism, red colour with the longest wavelength
is dedicated least while violet colour with shortest wavelength is deviated the most.
b. Discontinuous Spectrum: When gases or vapours of a chemical substance are heated
in an electric Arc or in a Bunsen flame, light is emitted. If the ray of this light is
passed through a prism, a line spectrum is produced.
• A discontinuous spectrum consisting of distinct and well-defined lines with dark
areas in between is called line spectrum. It is also called atomic spectrum.
• The emission spectrum consisting of a series of very closely spaced lines is called
band spectrum.
1. The line spectrum has sharp, 1. The band spectrum has many closed lines.
distinct well-defined lines.
3. The line spectrum is due to transition 3. The band spectrum is due to vibrations and
of electrons in an atom. rotations of atoms in a molecule
4. The line spectrum is given by inert 4. The band spectrum is given by hot metals
gases, metal vapors and atomized and molecular nonmetals.
nonmetals.
2. Absorption spectra: When white light from any source is first passed through the
solution or vapours of a chemical substance and then analyzed by the spectroscope, it is
observed that some dark lines are obtained. Further, it is observed that the dark lines are
at the same place where coloured lines are obtained in the emission spectra for the same
substance.
The wave numbers of all the lines in all the series can be calculated by the Rydberg
equation.
1 1 1
ν̅ = = RZ2 ( 2 − 2 )
λ n1 n2
Where n1 and n2 are whole numbers, n2> n1.
For one electron species like He+, Li2+ and Be3+, the value of R is 109677 cm–1× Z2, where
Z is the atomic number of the species.
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ELECTRONIC TRANSITIONS
Infra-red region
n1=2, n2=3,4,5,6----
υ
n=2
Balmer series Visible region
n1=1, n2=2,3,4,5----
n=1 Lyman series U.V region
The wave number for any single electron species like He+, Li2+ and Be3+ can be calculated
1 1
from the equation ν̅ = Z 2 R H (n2 − n2 )
1 2
Here E1 and E2 are the lower and higher allowed energy states.
For the atom to be stable an equal centrifugal force must act away from the nucleus. This
centrifugal force is equal to –mv2/r, where ‘m’ is the mass of electron and ‘r’ is the radius
of the orbit.
In a stationary orbit
–Ze2 −mv2 Ze2
= or = mv2
r2 r r
𝑛ℎ
As per Bohr’s quantum condition, mvr = 2𝜋
nh 2 𝑛2 ℎ 2
∴v= 2πmror v = 4𝜋2𝑚2 𝑟 2
The radius of the first orbit of hydrogen is 0.529 A0 or 0.0529 nm or 52.9 pm. This value
is known as Bohr’s radius. As the value of n increases, the radius of the orbit will increase.
n 2 h2
In S.I units, rn = 4π2mKZe2
1
Where,K = 4π∈ (ϵ0 = permitivity of air = 8.854 × 10−12 Farad Metre)
0
Ze2 Ze2
K.E = 2mv2 =
1
∵ mv 2 =
2r 2r
−Ze2
P.E of electron = 𝑟
−2.18×10−18 𝑍 2
orEn = j/atom
𝑛2
2π2 mK2 Z2 e4
In S.I units: En = − n2 h2
–1
WhereK = 4𝜋𝜖 and 𝜀𝑜 beingpermittivity of air and is equal to 8.854 × 10–12 Farad metre
1
0
If the numbers of the higher and lower energy states are n2 and n1 respectively, En2 =
−2π2 mZe4 1
. n2
h2 2
−2π2 mZe4 1
En1 = . n2
h2 1
−2π2 mZe4 1 1
En2 − En1 = [n2 − n2 ]
h2 1 2
En2 − En1
But En2 − En1 = hcν̅ and ν̅ = ch
1 −2π2 mZe4 1 1
ν̅ = = [ − ]
λ ch2 n21 n22
Substituting the values, we get RH= 1,09,681cm-1.This value is almost equal to Rydberg’s
2πZe2
v= cms−1
n
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Minor axis
n=4,k=4
n=4,k=3
n=4,k=2
• n=4, k=1, k 0
Possible values of k for n = 4 are 1, 2, 3, 4 respectively. For any given value of n, k cannot
be zero as in that case, the ellipse would degenerate into a straight line passing through
the nucleus. When n = k, path becomes circular.
“It is impossible to determine simultaneously and accurately the exact position and
momentum or velocity of a sub-atomic particle like electron in an atom”.
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One can determine the position of a particle very accurately, and then the determination
of its velocity becomes less accurate. Similarly, one can determine the velocity of a particle
very accurately, and then the determination of its position becomes less accurate. The
certainty in one factor introduces the uncertainty in another factor.
If the uncertainty in the determination of the position of a small particle is given by Δx
and uncertainty in its momentum is Δp, then
ℎ
(Δx) (Δp) ≥ 𝑛𝜋
Where n = 1,2,3,4.........
For an electron revolving around the nucleus in an atom the value of n is nearly 4.
Thus Heisenberg’s principle can also be stated as the product of uncertainty in position and
momentum of an electron like micro particle moving with high speed cannot be less than
h/4.
Heisenberg’s equation can also be written as,
ℎ
(Δx) (Δv) ≥ 4𝜋𝑚
Thus, the product of Δx and Δ𝜐 is extremely small. For particles of mass greater than 1 mg,
the product will still smaller. Hence, these values are negligible.
For a microscopic particle like an electron, we have
ℎ 6.625×10−34 𝑘𝑔𝑚2 𝑠−1
Δx.Δ𝜐 = 4𝜋𝑚 = 4×3.1416×(9×10−31 𝑘𝑔) ≈ 10−4 𝑚2 𝑠 −1
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Classical mechanics, based on Newton’s laws of motion, was successful in explaining the
motion of macroscopic bodies like falling stones or motion of planets around the sun etc.
But it failed when applied to microscopic particles like electrons, atoms, molecules etc.
Hence, new branch introduced called as ‘Quantum mechanics.
m = mass of electron
h = Planck’s constant
The intensity of light is proportional to the square of amplitude (ψ2). Just as 𝛙2 indicates
the density of photons in space, 𝛙2 in case of electron wave denotes the probability
of finding an electron in the space or probability of finding the electron is also maximum.
• Principal Quantum no. indicates the main energy level to which the electron belongs.
It also indicates the average distance of an electron from nucleus and also the
speed of the atomic electron.
• As the ‘n’ value increases the distance of electron from the nucleus increases and its
energy also increases.
• The maximum no. of electrons that can be present in an orbit is given by 2𝑛2 . The
maximum no. of electron in K, L, M, and N shells are 2,8,18 and 32 respectively.
0.529×𝑛2
• The radius of the orbit is given by the expression: rn = Ao.
𝑍
• The energy of the electron/orbit is given by the expression.
−13.6×𝑍 2
En= cm/sec
𝑛
2.18×108 ×𝑍
• The velocity of the electron is given by the expression. Vn= cm /sec.
𝑛
1 0 (1s)
2 0 (2s), 1 (2p)
• It is denoted by m or ml.
• This quantum number refers to different orientations of electron could in a
particular subshell. These orientations are called the orbitals.
• An electron due to its orbital motion around the nucleus generates an electric .This
electric field in turn produces a magnetic field which can interact with the external
magnetic field. Thus, under the influence of the external magnetic field, the
electrons of a subshell can orient themselves in certain preferred regions of space
around the nucleus called orbitals. The magnetic quantum number determines the
number of preferred orientations of the electron present in a subshell.
Since each orientation corresponds to an orbital, therefore, the magnetic quantum
number determines the number of orbitals present in any subshell.
• ‘m’ can have values from – 𝑙 to +𝑙 including zero, a total (2 𝑙+1) values.
Subshell 𝒍 m values No. of orientations (Orbitals)
s 0 0 1
p 1 -1, 0, +1 3
d 2 -2, -1, 0, +1, +2 5
F 3 -3, -2, -1, 0, +1, +2, +3 7
• When l = 0, m has only one value, m = 0. The sub-level‘s’ has one orbital called s orbital.
• When l =1, m can have 3 values m = –1, 0, +1. The sub-level ‘p’ has three space
orientations or three orbitals. The three orbitals are designated as px, py and pz.
• When l = 2, m can have 5 values m = –2,–1, 0, +1, +2. The sub-level ‘d’ has five space
orientations or five orbitals. The five orbitals are designated as d xy, dyz, dzx,
dx2 −y2 and dz2 .
• When l = 3, m can have 7 values m = –3,–2,–1,0,+1,+2,+3. The sub-level ‘f’ has seven
space orientations or seven orbitals.
The magnetic quantum number gives orientation of orbitals in space. All the orbitals
present in a sublevel have same energy and shape. They are called ‘degenerate
orbitals’, which differ in their spatial orientation.
• Each value of ‘m’ constitutes an orbital in the sublevel.
• Maximum no. of electrons in subshell : 2(2𝑙+1) or (4 𝑙+2).
and -1/2 or these are very often represented by two arrows pointing in the opposite
direction, i.e.,↑and ↓.
If an orbital contains 2 electrons, the two magnetic moments oppose and cancel each other.
Thus, in an atom, if all the orbitals are fully filled, net magnetic moment is zero and the
substance is diamagnetic (i.e., repelled by the external magnetic field). However, if some
half-filled orbitals are present, the substance has a net magnetic moment and is
paramagnetic (i.e., attracted by the external magnetic field).
• The spin angular momentum (𝜇 s) of an electron is given by
h
μs = √s(s + 1) 2π
Atomic Orbital:
The three-dimensional space around the nucleus where the probability of finding the
electron is maximum is called an atomic orbital.
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Node- The three-dimensional space around the nucleus where the probability of
finding the electron is minimum or zero.
Types of Nodes:
Nodes are of two types: a) Radial Node b) Angular Node
A radial node is the spherical region around then nucleus, where the probability if finding
the electron is zero (Ψ2 = 0).
Similarly,nodal plane(angular plane) have zero probability of finding electron.
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Shapes of Orbitals:
• s –Orbitals: s- Orbital can accommodate electrons with l = 0 and these orbitals are
present in every orbit starting from 1st orbit.
The three orbitals present in a given p - sublevel will have same shape, size and energy but
different orientations (differ in m value). These three orbitals are perpendicular to each
other and the angle between any two p - orbitals is 90o.
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• d - Orbitals:begins from 3rd orbit (n = 3). For d- sub level l= 2, indicates that each
d - sublevel contains five orbitals with ‘m’ values –2, –1, 0, +1, +2. These are designated
as dxy,dyz,dzx, 𝑑𝑥 2−𝑦 2 and d𝑧 2 .
All the d-orbitals (except d𝑧 2 ) have double dumb-bell shape. Each d-orbital has four lobes
separated by two nodal planes.
In case of dxy, dyz and dzxorbitals, lobes are present in between the corresponding axes.
i.e.,between x and yaxis in case of dxy orbital. Whereasin d𝑥 2 −𝑦 2 and d𝑧 2 orbitals lobes are
present along the axes. dxy Orbital contains yz and zx as nodal planes. dyz and dzx contain
(xy,zx) and (xy,yz) planes respectively. d𝑥 2 −𝑦 2 orbitalcontains two nodal planes perpendicular
to each other and which make an angle of 45o with respect to x and y axes. 𝑑𝑧 2 orbital does
not contain nodal planes.
5 dorbitals present in a given d- sublevel will have same energy in the ground state.
ENERGY OF ORBITALS
The energy of an electron in a hydrogen atom is determined only by the principal quantum
number. Within a shell, all hydrogen orbitals have the same energy, independent of the
other quantum numbers.
1s < 2s = 2p < 3s = 3p = 3d < 4s = 4p = 4d = 4f
Although the shapes of 2s and 2p orbitals are different, an electron has the same energy
when it is in 2s orbital or 2p orbital. The energy of an electron in a multielectron atom
depends, not only on its principal quantum number, but also on its azimuthal quantum number.
The s, p, d and f orbitals within a given shell have slightly different energies in a multi
electron atom.
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• Aufbau Principle:
“In the ground state of the atoms, the orbitals are filled in order of their increasing
energies”.
In other words electrons first occupy the lowest energy orbital available to them and enter
into higher energy orbitals only after the lower energy orbitals are filled.
The relative energy of an orbital is given by
(n + l ) rule. As (n + l) value increases, the energy of orbital increases.
• The orbital with the lowest (n + l) value is filled first.
• When two or more orbitals have the same (n +l) value, the one with the lowest
‘n’ value (or) highest ‘l ’ value is preferred in filling.
Exp- Consider two orbitals 3d and 4s.
n+l value of 3d = 3 + 2 = 5 and of 4s = 4 + 0 = 4. Since 4s has lowest(n +l) value, it is filled
first before filling taking place in 3d.
Consider the orbitals 3d, 4p and 5s
The (n + l) value of 3d = 3 + 2 = 5
The (n +l) value of 4p = 4 + 1 = 5
The (n +l) value of 5s = 5 + 0 = 5
These three values are same. Since the ‘n’ value is lower to 3d orbitals, the electrons prefer
to enter in 3d, then 4p and 5s.
The order of increasing energy of atomic orbitals is:
1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d <
6p < 7s and so on.
The sequence in which the electrons occupy various orbitals can
be easily remembered with the help of Moeller’s diagram as
shown in Fig
spin. It follows that an orbital can hold a maximum of two electrons with opposite
spins.
Exp- helium atom has two electrons in its 1s orbital. Quantum numbers for first electron
are n =1, l = 0, m = 0 and s = +1/2. Quantum numbers for second electron are:
n =1, l = 0, m =0, s = –1/2.
The two electrons have the same value for n, same value for l and same value for m but
differ in s.
24 Cr 1s2 2s2 2p6 3s2 3p6 3d5 4s1 [Ar] 3d5 4s1
25 Mn 1s2 2s2 2p6 3s2 3p6 3d5 4s2 [Ar] 3d5 4s2
26 Fe 1s2 2s2 2p6 3s2 3p6 3d6 4s2 [Ar] 3d6 4s2
27 Co 1s2 2s2 2p6 3s2 3p6 3d7 4s2 [Ar] 3d7 4s2
28 Ni 1s2 2s2 2p6 3s2 3p6 3d8 4s2 [Ar] 3d8 4s2
29 Cu 1s2 2s2 2p6 3s2 3p6 3d10 4s1 [Ar] 3d10 4s1
30 Zn 1s2 2s2 2p6 3s2 3p6 3d10 4s2 [Ar] 3d10 4s2
Stability of atoms
Extra stability is associated with atoms in which degenerate orbitals are either half-filled
or completely filled due to
(1) Symmetrical distribution of electrons
(2) Exchange energy. Greater the exchange energy greater is the stability.
The presence of half-filled and completely filled degenerate orbitals gives greater
stability to atoms.
1
It is for this reason the electronic configurations of Cr and Cu are represented as [Ar] 4s
5 1 10
3d and [Ar] 4s 3d respectively.
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SELF ASSESSMENT
1.1 : Introduction :
Q.1. Who introduced the term 'atom'?
Ans: i. A Greek Philosopher Democritus introduced the term atom.
ii. The word 'atom' was derived from Greek word 'a-tomic' meaning indivisible.
Note: Maharshi Kanad, an Indian Saint and Philosopher, first used the term 'Permanu'
(Sanskrit, meaning atom) to describe the ultimate particle of matter.
Q.2. State the postulates of Dalton's atomic theory.
Ans: Postulates of Dalton's atomic theory:
i. Matter is composed of indivisible atoms.
ii. All the atoms of a given element have identical properties. They have identical mass. Atoms
of different elements have different masses.
iii. Atoms of different elements combine in a fixed ratio of whole numbers to form compounds
of different elements.
iv. Chemical reactions involve reorganization of atoms. They are neither created nor
destroyed during chemical reaction.
Q.3. What are fundamental particles?
Ans: i. Sub-atomic particles which are the constituents of an atom are called fundamental particles.
ii. Electron, proton and neutron are the most important fundamental particles of an atom.
Q.4. Explain the discovery of electrical nature of matter.
Ans: i. It is observed that when the substances like glass or ebonite are rubbed with silk or fur,
electricity is produced indicating their electrical nature.
ii. Michael Faraday showed that electricity could be passed through the solution of certain
substances (electrolytes).
iii. When electric current is passed through the solution of an electrolyte, chemical changes
occur in the solution. He called these changes as electrolysis.
iv. During electrolysis, the charged particles migrate towards oppositely charged electrodes
and either accumulate on them or escape as a gas.
v. Thus, matter is electrical in nature.
Note: Faraday surmised his finding in the form of Faraday's laws of Electrolysis. They give a
quantitative relationship between amount of electricity and mass of substance. They mean that
electricity is discrete in nature. Later on, the discrete particles of electricity were called as
electrons.
Ans: In discharge tube experiments the electricity is passed through gases at low pressure.
Q.7. Describe the discharge tube experiment of J.J. Thomson.
OR
How are cathode rays produced in a discharge tube?
Ans: Discharge tube experiment of J.J. Thomson:
J.J. Thomson studied the properties of cathode rays through a simple discharge tube
experiment. It can be described as follows:
Gas at low
Apparatus: Pressure Discharge tube
Procedure:
i. The glass tube is evacuated using a vacuum pump.
ii. It is filled with a gas at a very low pressure (10–2 to 10–3 mm Hg.)
iii. A very high voltage of about 5000 V to 10,000 V is applied between the two electrodes in
the tube, which results in the electric discharge between the two electrodes and the gas
in the tube begins to glow.
iv. A high vaccum is created within the tube, the glow is replaced by faint luminous rays from
the cathode. These rays produce fluorescence on the glass opposite to the cathode.
v. The rays start from the cathode and move away from it at right angles in straight lines.
These rays are known as cathode rays.
Q.10. Explain the experiment carried out by Sir J.J. Thomson to determine the charge to m
cathode ray particles.
Ans: i. Sir J.J. Thomson determined the ratio of electrical charge (e) to the mass (m) of Cathode
ray particle. He used a specially designed cathode ray tube. The method is described below.
ii. Electrical and magnetic fields are applied. Initially, the cathode rays were allowed to travel
through the tube in the absence of electric and magnetic field. It was observed that
cathode rays originated at cathode, passed through the hole in anode and striked the ZnS
fluorescent screen at point Y.
iii. When electric field of fixed strength was applied, deflection of cathode rays towards
positive electrode was observed and they striked the screen at point X.
iv. When instead of electric field, magnetic field was applied at right angles to the electric
field, deflection of cathode rays in opposite direction was observed and they striked the
screen at point Z as shown in the adjacent diagram.
v. Thomson then subjected the cathode rays to electric field of appropriate voltage such
that they striked at point X on the screen. Now along with the electric field, he subjected
the cathode rays to the magnetic field of field strength H such that the effect due to
electric field is compensated by magnetic field and cathode rays were once again brought
back to the original point Y. The electric and magnetic fields were applied perpendicular
to each other as well as to the path of rays.
vi. Thomson carried out the experiment at different strengths of electric and magnetic fields
and different energies of cathode rays. He observed that the extent of deviation of the
particles from their path in the presence of electric or magnetic field was dependent on
the voltage applied across the electrodes and opposing magnetic field strength
respectively. He accurately measured the magnitude of deflection and determined the
charge to mass ratio (elm) of cathode ray particles as,
𝒆
= 𝟏. 𝟕𝟓𝟖𝟖𝟐𝟎 × 𝟏𝟎𝟏𝟏 𝑪𝒌𝒈−𝟏
𝒎
where m = mass of particle of cathode rays in kg.
e = charge on particle of cathode rays in coulomb (C).
Note:
Cathode ray particles are negatively charged and therefore, this charge is represented as –e.
Q.11. What were the conclusions of cathode ray tube experiments made by Sir J.J. Thomson?
Explain the importance of these conclusions.
Ans: i. After conducting several experiments using specially designed cathode ray tube, Sir J.J.
Thomson concluded that irrespective of the nature of gas used in the discharge tube and
the nature of material of which the cathode was made; the value of elm for a cathode ray
particle was the same.
ii. These conclusions proved that
a. all the constituent particles of cathode rays are identical.
b. the cathode ray particles are the universal constituents of all the atoms of all matter.
Note: A Dutch physicist H.A. Lorenz named the cathode ray particles as electrons.
Q.12. Explain how the mass of electron was determined?
Ans: i. From oil drop experiment, Millikan determined the value of charge present on an electron.
ii. He found that the charge on the electron (e) is equal to – 1.6 × 10–19C. The accepted value
of electrical charge is – 1.6022 × 10-19C.
𝒆
iii. The value of the ratio of charge to mass of electrons = = 𝟏. 𝟕𝟓𝟖𝟖𝟐𝟎 × 𝟏𝟎𝟏𝟏 𝑪𝒌𝒈−𝟏
𝒎
iv. By knowing the charge on the electron (by Millikan method) and elm value (by Sir J.J.
Thomson's experiment) it was possible to determine the mass of electron(m) as follows:
ACTIVE SITE EDUTECH - 9844532971
–
𝒆 𝟏.𝟔𝟎𝟐 × 𝟏𝟎 𝟏𝟗 𝐂
m= = = 9.1094 × 10–31 kg
𝒆/𝒎 𝟏.𝟕𝟓𝟖𝟖𝟐𝟎×𝟏𝟎𝟏𝟏 𝑪𝒌𝒈−𝟏
Note: Mass of electron is the mass of hydrogen atom.
Q.13. Define electron.
Ans: An electron is a subatomic particle which bears unit negative charge i.e. 1.6022 × 10–19 C and
has a mass of 9.1094 × 10–31 kg
1.3 : Discovery of proton :
Q.14. What are canal rays or anode rays or positive rays?
Ans: The rays consisting of positively charged particles produced in a discharge tube by the removal
of electrons from the gaseous atoms and which move away from anode towards cathode in
straight lines are called canal rays or anode rays or positive rays. The canal rays produced from
gaseous hydrogen atoms are protons.
Q.15. How were canal rays or anode rays or positive rays discovered?
Ans: i. E. Goldstein used a modified cathode ray tube for the electrical discharge experiment.
ii. In this method, a perforated disc cathode was used in place of disc cathode. When the gas
pressure was not too low, in addition to
Perforated cathode
cathode rays, a new kind of rays were also
H gas at low pressure
found streaming behind the cathode.
2
Anode rays
iii. These particles of hydrogen gas were found to possess minimum mass and a unit positive
charge. Hence, their value of elm was found to be maximum.
iv. On determining the mass of these particles, it was found that the mass of each particle
was 1837 times the mass of an electron. This particle was called proton.
Note:
i. E. Goldstein (1896) discovered protons in the discharge tube containing hydrogen gas.
𝐻2 → 2𝐻 + + 2 𝑒 −
Protons
ii. The presence of proton was further confirmed by radioactive disintegration.
Q.18. How are positive rays or canal rays produced in the discharge tube?
Ans: i. When high speed electrons (cathode rays) strike neutral atoms or molecules of the gas
contained in the discharge tube, formation of positively charged ions takes place by
removal of one or more electrons from the neutral atoms or molecules of the gas.
𝑀 + 𝑒− → 𝑀+ + 2 𝑒 −
−
𝑀 + 𝑛𝑒 → 𝑀𝑛+ + (𝑛 + 𝑙) 𝑒 −
ii. These positively charged ions move towards perforated cathode and constitute the beam
of positive rays or canal rays coming through the holes of the cathode.
iii. Positive ions that constitute the positive rays can also be produced by passing the electric
discharge through a gas under high electric potential.
Note: Depending upon the number of electrons lost by the atoms or molecules of a gas, the
positively charged ions thus formed carry corresponding amounts of positive charge.
Q.19. Describe the nature of protons as studied by Sir J.J. Thomson.
Ans: Sir J.J. Thomson studied the nature of positive rays. He proposed the following facts about
protons:
i. The actual mass of a proton is 1.672 × 10–24 gram. On the relative scale, a proton has the
mass of approximately 1.00727 atomic mass unit (amu).
ii. Electrical charge of a proton is equal in magnitude & opposite in sign to that of the electron.
A proton carries a charge of + 1.60 × 10–19 Coulombs or +1 elementary charge unit.
iii. Proton was the lightest positive particle found in atomic beams in the discharge tube. It
was considered a unit present in all other atoms.
Q.20. How was it confirmed that all atoms contain proton?
Ans: i. Proton was the lightest positive particle found in atomic beams in the discharge tube
experiments. It was considered a unit present in all other atoms.
ii. Earnest Rutherford (in 1919) proved the presence of proton in the nucleus. He bombarded
nitrogen and aluminium atoms with a particles. Protons were ejected. As neutrons are unstable
outside the nucleus, they disintegrate into proton and electron.
iii. Protons were obtained in numerous nuclear reactions. This confirms that all atoms contain
protons.
Q.21. Define a proton.
Ans: i. A proton is defined as a subatomic particle which has a mass of 1.00727 amu and a charge
of +1 elementary charge unit.
ii. It has unit mass and unit positive charge.
Ans: i. Earlier only protons and electrons were 'known as constituent particles of an atom. They
were called subatomic particles.
ii. William Prout proposed that the atoms of the elements contain requisite number of
hydrogen atom units.
iii. Taking the atomic mass of hydrogen atom as 1.000, the atomic masses of all elements were
assumed to be whole numbers. Chlorine and copper had atomic masses 35.5 and 63.5
respectively. Hence Prout's theory was rejected.
Note:
Prout's theory was wrongly rejected as there was no knowledge of presence of two natural
isotopes of chlorine and copper at the time of rejection.
Q.23. Give an account of proton-electron theory? Why was it rejected?
Ans: i. According to Prout's theory, the nucleus of oxygen (atomic mass 16), should contain 16
protons and there should be 16 extranuclear electrons. Similarly, helium should contain 4
protons in the nucleus and 4 extranuclear electrons.
ii. However, oxygen, helium and almost all atoms of the elements contained almost half the
number of extranuclear electrons than the number predicted by Prout's theory.
iii. To account for the discrepancy, a new theory i.e., the proton-electron theory was
proposed. As per this theory, apart from extranuclear electrons, some electrons are also
present inside the nucleus.
iv. This was supported by the observed emission of P particle, i.e. electron from the nucleus.
v. Fermi rejected this theory, as it could not explain spin of some nuclei and energies of P
particles emitted by radioactive nuclei. Also electron cannot be accommodated in the small
space of atomic nucleus of size 10–15 due to its large size.
Q.24. Describe in brief the proposal of existence of the neutron in atoms.
Ans: i. Failure of Prout's theory, proton-electron theory in an attempt to suggest constituents of
an atom led to the proposal of the existence of the neutron.
ii. In order to overcome the failure of the proton-electron theory, Rutherford, in 1920,
proposed the existence of a neutral particle made from a combination of proton and
electron. He named it neutron. It has no charge and has mass almost equal to the mass of
the proton.
iii. As it satisfied all characteristics of atomic nucleus like mass, charge, spin it was accepted
by all.
iv. Neutron remained a hypothetical particle for sometime, as it could not be deflected in
electric and magnetic field.