Important Practicals
Chemistry F.Sc
Paper pattern
Practical pattern 2025 Total marks:30
Q#01: Salt Analysis (10)
Q#02 :Volumetric analysis (10)
Q#3: General experiments
Crystallization ,Chromatography,Common Ion Effect,Organic
Preparation,Functional Group And Elemental Analysis (05)
Q#4:Viva. (03)
Q#5: Copy. (02)
Note
Question No. 3 General experiments
Exp no. 1To prepare a pure sample of aspirin.
Result: Pure and dried sample of aspirin is prepared and show to examiner.
EXP 2…To prepare a pure sample of Glucosazone.
Result: Pure and dried sample of aspirin is prepared and show to examiner
Result: Pure and
Result: Pure and
dried sample of
glucosazone is
prepared and show
to examiner
EXP 3…To prepare a pure sample of Copper amine complex.
Result: Pure and dried crystals of copper amine complex is prepared and show to
examiner
EXP 4…To prepare a pure sample of iodoform.
Result: Pure and
EXP 1
dried sample of
iodpfrom is prepared
and show to
examiner
EXP :Identify the funtional group in following organic compound
‘A’
EXP 2
Identify the funtional group in following organic compound ‘A
EXP 3
Identify the funtional group in following organic compound ‘A’
Experiment: To purify the given sample of commercial
NaCl by passing HCl gas
Acid -Base Titration
General Information
Reagents used: 0.1 M HCl ,0.05M H2SO4 , 0.05 M (H2C2O4)/ oxalic acid, 0.1M CH3COOH
0.1M NaOH, 0.1M KOH, 0.05 M Na2CO3 , 0.1 M NaHCO3
Principle: It is an acid base titration.
Indicator: Phenolphthalein (NaOH, KOH) End point: Pink to colourless
Indicator: Methyl orange (Na2CO3 , NaHCO3) End point: Yellow to orange red
Equation:
NaOH + HCl → NaCl + H2O Na2CO3 + H2SO4 → Na2SO4 + H2O+CO2
KOH + HCl → KCl + H2O NaHCO3 + HCl → NaCl + H2O+CO2
2NaOH + H2SO4 → Na2SO4 + 2H2O Na2CO3 + 2HCl → 2NaCl + H2O+CO2
NaOH + CH3COOH → CH3COONa + H2O
2NaOH + H2C2O4 . 2H2O → Na2C2O4+ 4H2O
Procedure: Take acid solution in the burette and note the initial reading. Then pipette out 10
cm3 of base solution in titration flask and add one to two drops of indicator in it. Add drop
wise acid solution from the burette into the titration flask till end point. Note the final
reading. Repeat the experiment for three concordant readings and find out the mean volume
of the acid solution used.
Important experiments
Acid base titrations
Exp 1
Volume of acid used
Mean volume=
Exp .2
Exp 3
Exp 4
Exp 5
250 cm3 solution contains impure sample=2.5g
1000 cm3 solution contains impure sample=2.5/250x1000=10g
Result
The given impure sample contains pure NaHCO3= 84%
Redox Titration
Reagents used: 0.1 M FeSO4.7H2O, 0.05M H2C2O4. 2H2O, 0.1 M FeSO4.(NH4 )2 SO4.6H2O
0.02 M KMnO4 .
Principle: It is a type of redox titration.
Indicator: KMnO4 itself End point: Appearance of light pink colour
Equation:
Procedure:
Take KMnO4 solution in the burette and note the initial reading. Then pipette out 10 cm3 of
………solution in titration flask and add half test tube of dilute H2SO4 in it. Add drop wise
KMnO4 solution from the burette into the titration flask till light pink colour appear. Note the
final reading. Repeat the experiment for three concordant readings and find out the mean
volume of the KMnO4 solution used.
EXP 6
Volume of KMnO4 used
Exp 7
Mean volume =
Exp 8
Iodimetric Titration
Reagents used: 0.1 M Na2S2O3.5H2O, 0.05 M I2
Principle: It is an iodimetric redox titration.
Indicator: Starch solution End point: Deep blue colour
Equation:
2 Na2S2O3.5H2O + I2 → Na2S4O6 +2NaI + 10H2O
2 Na2S2O3 + I2 → Na2S4O6 +2NaI
2 Na2S2O3.XH2O + I2 → Na2S4O6 +2NaI + XH2O
Procedure:
Take I2 solution in the burette and note the initial reading. Then pipette out 10 cm3 of
Na2S2O3 solution in titration flask and add 1 cm3 of freshly prepared starch solution in it. Add
drop wise I2 solution from the burette into the titration flask with constant shaking the flask
until deep blue colour appear and remain stable for 5 minutes. Note the final reading. Repeat
the experiment for three concordant readings and find out the mean volume of the I2 solution
used.
EXP 9
Exp 10
Salt Analysis
Salt no. 1
Salt no.2
Salt no.3
Salt no. 4
RESULT: Acid Radical = CO3-2 (Carbonate insoluble)
Basic Radical=Pb 2+(Lead)
RESULT: The given unknown salt is PbCO3 (Lead carbonate)
Salt no.5
5 5
6
7
8
10
11
12
RESULT: Acid Radical = Br- (Bromide)
Basic Radical=Ni 2+(Nickel)
RESULT: The given unknown salt is NiBr2 (Nickel bromide)
Salt no. 6
RESULT: Acid Radical = Cl- (chloride)
Basic Radical=Cu 2+(Copper)
RESULT: The given unknown salt is CuCl2 (Copper chloride)
Salt no. 7
RESULT: Acid Radical = NO3- (Nitrate)
Basic Radical=Al 3+(Aluminium)
RESULT: The given unknown salt is Al(NO3)3 (Aluminium nitrate)
Salt 8
RESULT: Acid Radical = I - (Iodide)
Basic Radical= Zn2+ (Zinc)
RESULT: The given unknown salt is ZnI2 (Zinc iodide)
Salt 9
Distilled water
RESULT: Acid Radical = PO4 3- (Phosphate)
Basic Radical= Mg2+ (Magnesium )
RESULT: The given unknown salt is Mg 3 (PO4 )2 (Magnesium phosphate)
Salt 10
RESULT: Acid Radical = CO3 2- (Carbonate)
Basic Radical= Na+ (Sodium )
RESULT: The given unknown salt is Na2CO3 (Sodium carbonate)
