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R Beam

The document contains calculations related to structural engineering, specifically focusing on the design of reinforced concrete elements. It provides values for gross and net stress, required and provided reinforcement areas, and checks for permissible limits on span-to-depth ratios. The results indicate the necessary specifications for tension and compression steel reinforcement in a simply supported span and continuous span scenarios.

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manhbook23
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28 views2 pages

R Beam

The document contains calculations related to structural engineering, specifically focusing on the design of reinforced concrete elements. It provides values for gross and net stress, required and provided reinforcement areas, and checks for permissible limits on span-to-depth ratios. The results indicate the necessary specifications for tension and compression steel reinforcement in a simply supported span and continuous span scenarios.

Uploaded by

manhbook23
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Download as XLSX, PDF, TXT or read online on Scribd
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T PROVIDE SIMPLY SUPPORTED SPAN

Gross fsc = CONTINUOUS SPAN


As' = SUPPORT
Permissible L/d = CANTILEVER
d= 344 Actual L/d =
K' = 0.1558
K= 0.0582 > K =
z= 320.09 < 326.8 x = (344.0 - 320.1) /0.45 = 53.1 mm
x= 53.141 d' = 40 + 16/2 = 48.0 mm
d' = 48 Gross fsc = 67.7 N/mm² from strain diagram
net fsc = 54.315 67.71513 net fsc = 67.7 - 0.67 x 30 /1.5 = 54.3 > 0 N/mm²
Excess M = 0 Excess M = M - Mu = 62.0(0.058 - 0.156) /0.058 = 0.0 kNm
As' req = 0 As' = 0.0E6 /54.3 /(344.0 - 48.0) = 0 mm²
Provide 0.00%
No = 2
As' prov = 402.12 PROVIDE 2 T16 compression steel = 402 mm²
=% 0.3897
fst = 438.1 fst = 438.1 N/mm²
As = 442.14 296 As = 1E6 x 62 /320.1 /438.1 = 442 mm²
min As = 0.13% As = 1E6 x 62 /320.1 /438.1 = 442 mm²
Provide 442.14 As = (0.0E6 /296.0 + 62.0E6 /320.1) /438.1 = 442 mm²
No = 3
As prov = 603.19 PROVIDE 3 T16 tension steel = 603 mm²
fs = 224.79 fs = 2/3 x 460 x 442 /603 = 224.8 N/mm²
Base ratio 26
Comp mod f 1.115 Comp mod factor = 1 + 0.390 /(3 + 0.390) = 1.115 < 1.5
Strain diagram
Tens mod f 1.3442 Tens mod factor = 0.55Stress
+ (477diagram
- 224.8) /120 /(0.9 + 1.746) = 1.344 < 2
L/d (p) = 38.966 Permissible L/d = 26.0 x 1.115 x 1.344 = 38.966
L/d (a) = 8.7209 ok Actual L/d = 3000 /344.0 = 8.721 ok
As enhance 1 0.00% .

St = 198
Sb = 91 0
Max S 209.09 0
Min Sb 25 0
Min St 25 0
0 0
746) = 1.344 < 2

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