d i dc ( t ) 0.
8 udc ( t )
i dc ( t+ ∆ t )=i dc ( t )+ ∆ t+ 2C oss
dt tf
u dc ( t ) 0.8 udc ( t )
i dc ( t+ ∆ t )=i dc ( t )+ ∆ t +2 Coss
3 3 tf
Ldc + Ls + Ll s
2 2
udc ( t ) 0.8 udc ( t )
i dc ( t )+ ∆ t+C oss
3 3 tf
Ldc + Ls + Lls
2 2
uce ( t +∆ t )=¿ ¿