7
5 f : x 7 (2x + 3) 2 for x 2 0
(a) Find the range of f. [1]
(b) Explain why f has an inverse. [1]
(c) Find f -1. [3]
(d) State the domain of f -1. [1]
(e) Given that g : x 7 ln (x + 4) for x 2 0, find the exact solution of fg (x) = 49 . [3]
© UCLES 2020 0606/12/M/J/20 [Turn over
10
1
10 (a) g (x) = 3 + for x H 1.
x
(i) Find an expression for g -1 (x) . [2]
(ii) Write down the range of g -1 . [1]
(iii) Find the domain of g -1 . [2]
© UCLES 2020 0606/22/F/M/20
10
10 (a) The function f is defined by f (x) = 1 + x 2 , for all real values of x. The graph of y = f(x) is
given below.
y = 1 + x2
O x
(i) Explain, with reference to the graph, why f does not have an inverse. [1]
(ii) Find f 2 (x) . [2]
(b) The function g is defined, for x > k, by g (x) = 1 + x 2 and g has an inverse.
(i) Write down a possible value for k. [1]
(ii) Find g -1 (x) . [2]
© UCLES 2018 0606/22/F/M/18
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11 The functions f and g are defined by
x2 - 2
f (x) = for x H 2 ,
x
x2 - 1
g (x) = for x H 0 .
2
(i) State the range of g. [1]
(ii) Explain why fg(1) does not exist. [2]
c
(iii) Show that gf (x) = ax 2 + b + , where a, b and c are constants to be found. [3]
x2
© UCLES 2017 0606/22/F/M/17
13
(iv) State the domain of gf. [1]
x+ x2 + 8
(v) Show that f -1 (x) = . [4]
2
© UCLES 2017 0606/22/F/M/17 [Turn over
7
6 The function f is defined by f (x) = 2 - x + 5 for - 5 G x 1 0 .
(i) Write down the range of f. [2]
(ii) Find f -1 (x) and state its domain and range. [4]
4
The function g is defined by g (x) = for - 5 G x 1 - 1 .
x
(iii) Solve fg (x) = 0 . [3]
© UCLES 2016 0606/13/M/J/16 [Turn over
10
9 (a) It is given that g (x) = 6x 4 + 5 for all real x.
(i) Explain why g is a function but does not have an inverse. [2]
(ii) Find g 2 (x) and state its domain. [2]
It is given that h (x) = 6x 4 + 5 for x G k .
(iii) State the greatest value of k such that h-1 exists. [1]
(iv) For this value of k, find h-1(x). [3]
© UCLES 2019 0606/22/F/M/19