Mathematics: Quarter 2
Mathematics: Quarter 2
8
MATHEMATICS
Quarter 2
S.Y. 2021-2022
NAVOTAS CITY PHILIPPINES
Mathematics – Grade 8
Alternative Delivery Mode
Quarter 2
Second Edition, 2021
Republic Act 8293, section 176 states that: No copyright shall subsist in any
work of the Government of the Philippines. However, prior approval of the
government agency or office wherein the work is created shall be necessary for
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impose as a condition the payment of royalties.
Module 1 ............................................................................... 3
Module 2 ............................................................................... 8
Module 3 ............................................................................... 11
Module 4 ............................................................................... 17
Module 5 ............................................................................... 19
Module 6 ............................................................................... 21
Module 7 ............................................................................... 24
Module 8 ............................................................................... 28
Module 9 ............................................................................... 31
Assessment ........................................................................... 36
Reference …………………………………………………………………46
Read and analyze each question carefully. Choose the letter of the correct
answer.
A. 4a – 3b = 9
B. 8f + 4 < 12
C. 3x < 16
D. 11 + 2t ≥ 3k
2. Which among the mathematical symbols best translate the verbal statement
Twice a number x and y is at most 24?
A. 2x + y < 24
B. 2x + y > 24
C. 2x + y ≥ 24
D. 2x + y ≤ 24
A. infinite
B. 2
C. 1
D. zero
1
6. Find the value of y if f(x) = 3x-2 and the value of x = 4.
A. -10
B. 10
C. 16
D. -16
7. Which of the following is the if-then form of the statement: “A prime number
has one and itself as factors.”?
8. Which of the following is the contrapositive of the statement, “If two angles
are vertical, then they are congruent.”?
A. If two angles are not vertical, then they are not congruent.
B. If two angles are congruent, then they are vertical.
C. If two angles are vertical, then they are congruent.
D. If two angles are not congruent, then they are not vertical.
9. The statement If <A and <B are supplementary, then the sum of their
measure is 180° is translated into If the sum of the measure of <A and <B is
180°, then they are supplementary. Which symbolization illustrates the
second statement?
A. p→q
B. q→p
C. ~p→~q
D. ~q→~p
10. Which appropriate conclusion can be drawn from the statement m∠J +
m∠S = 90?
A. ∠J≅∠S
B. ∠J and ∠S are right angles
C. ∠J and ∠S are complementary
D. ∠J and ∠S are supplementary
2
MODULE 1
This module was designed and written with you in mind. It is here to help you
master illustrating linear inequalities in two variables. The scope of this module
permits it to be used in many different learning situations. The language used
recognizes the diverse vocabulary level of students. The lessons are arranged to
follow the standard sequence of the course. But the order in which you read them
can be changed to correspond with the textbook you are now using.
The module is divided into two lessons, namely:
Lesson 1.1 – Linear Inequalities in Two Variables
Lesson 1.2- Graph of Linear Inequalities in Two Variables
After going through this module, you are expected to:
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Linear equalities in two variables have a highest degree of 1. The solution can be
represented by sets of possible value that satisfies the given inequalities. The
solution of a linear inequality in two variables like Ax + By > C is an ordered pair (x,
y) that produces a true statement when the values of x and y are substituted into
the inequality.
To find the linear inequalities suited for the solution, let us substitute each ordered
pair to each inequality and check which one gives a true statement.
Examples:
Is the solution suited to x – 2y > -2?
x – 2y > -2 Given
(1) - 2(1) > -2 Substitution
1 - 2 > -2 Simplify
-1 > -2 True statement
Therefore, (1, 1) is a solution.
Activity 1: Write "Inequality "if the given shows linear inequality in two
variables and "Not Inequality" if otherwise.
1. 3x – y ≥ 12 ________________________
2. 19 < y ________________________
3. y = 2/5 x ________________________
4. x ≤ 2y + 5 ________________________
5. 7(x – 3 ) < 4y ________________________
Activity 2: Encircle the point/s that represents as the solution/s of the given
linear inequalities in two variables.
1. x + y > 14 (10, 10) (-10, 10)
2. y – 2x < -1 (4, 9) (8, 9)
3. 2x + y ≥ 10 (-3, 1) (8, 10)
4. 4x + y < 11 (1,11) (1, -11)
5. 3x – y < 8 (-1, -2) (10, 2)
4
Read and analyze problem. Write an inequality statement about it.
1. Jazmine allowance for an online class is at most P200 a week. She bought
some school supplies in preparation for her portfolio. The price of a big
notebook is P30, while a long ordinary folder is P15.What are the possible
number of long folder and big notebook can she buy from her weekly
allowance?
1. Change the linear inequality to linear equation by changing the symbol >, <,
≥, ≤ to =.
2. Arranged the linear equation in the form y= mx + b.
3. Graph the linear equation. Use a broken line (dashed line) for > or < and a
solid line (heavy line) for ≥ or ≤. This will serve as the boundary line. This
line separates the Cartesian plane into two half-plane or region.
4. Use a test point like (0,0) to determine the half-plane. Use the original linear
inequality.
5. Shade the half-plane or region that contains the solution.
6.
Example 1: Graph x + y > 2
Step 1: x + y = 2
x 0 2
Step 2: y = -x + 2
y 2 0
Step 3: table of values
Step 4: Test for (0,0)
x + y> 2
0+0>2
0>2 (not true)
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Step 5:
Use broken line
Therefore, any point that lies in the shaded part is a solution such as
(4,2), (0,6), and (3,1).
Slope: __________________
y-intercept: __________________
Plane divider: __________________
Shaded region: __________________
6
Read and analyze each problem. Write an inequality statement and solve it
using graphical method.
1. Emily bought two blouse and a pair of pants. The total amount she paid for
the items is not more than Php 980. How much is the possible cost of the
blouse and pants?
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MODULE 2
This module was designed and written with you in mind. It is here to help you
master system of linear inequalities in two variables. The scope of this module
permits it to be used in many different learning situations. The language used
recognizes the diverse vocabulary level of students. The lessons are arranged to
follow the standard sequence of the course. But the order in which you read them
can be changed to correspond with the textbook you are now using.
To check if (3, -1) is a solution, just substitute the value to the given
inequalities.
x+y≤6 2x - y > 4
3 + (-1) ≤ 6 2(3) – (-1) > 4
2 ≤ 6 TRUE 6+1>4
7 > 4 TRUE
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The graph of a system of linear inequalities is the graph of all solutions of the
system.
Example: x + y ≤ 6 Inequality 1
2x - y > 4 Inequality 2
The solution set of a system of linear inequalities in two variables is the set
of all ordered pairs of real numbers (x, y) that simultaneously satisfy all the
inequalities in the system.
S = {(5, 1), (3, - 8), (4, -6), (5, -10)}. Example of solutions that satisfies the
inequalities x + y ≤ 6 and 2x - y > 4
A graph of all such ordered pairs is called the solution region for the
system. To solve a system of inequalities, graphically means to graph its solution
region.
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Activity 1: Graph the given system of inequalities below. Determine five (5) ordered
pairs that are solution to the given system of linear inequalities.
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MODULE 3
This module was designed and written with you in mind. It is here to help you
master illustrating relation and function. The scope of this module permits it to be
used in many different learning situations. The language used recognizes the
diverse vocabulary level of students. The lessons are arranged to follow the
standard sequence of the course. But the order in which you read them can be
changed to correspond with the textbook you are now using.
Lesson
Function and Relation
3.1
A relation is a set of ordered pairs (x, y), and { } is the symbol for a set. The
first coordinate set is the domain (x – values or the abscissas) of the relation, and
the second coordinates is the range (y – values or the ordinates) of the relation.
A function is a special type of a relation. It is a relation in which every
element in the domain is mapped to exactly one element in the range. Thus, a set
of ordered pairs is a function if no two distinct ordered pairs have equal abscissas.
All functions are relations, but not all relations are functions.
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Ordered pairs Graph
1. {(1,5), (2, 10), (3,15), (4, 20)}
Correspondence of Relation
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2. Many-to-one – If any two or more elements of the domain are mapped to the
same element in the range.
Example:
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Activity 2: Determine the correspondence of the relation. Write one-to-one, many-
to-one, or one-to-many, then identify if it is a FUNCTION or NOT FUNCTION. Write
the correct answer inside the box.
Questions:
1. Describe the relation that shows in
the mapping diagram.
_______________________________
3. From the diagram above, find the domain and range of the relation linking
the city and its zip code.
Domain : (_______, ________, ______, ________,)
Range: ( ________, _______, _______,________)
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4. Is the given relation between the city and its zip code illustrates a function
or not? Why? ____________________________________________________
______________________________________________________________
Independent variable – It is a variable that stands alone and is not changed by the
other variables you are trying to measure. (CAUSE)
It is not possible that Test Score could cause a change in time spent studying
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3. The number of bikes sold and the price of the bike.
Independent Variable: ___________________________________
Dependent Variable: _____________________________________
Write three (3) examples of dependent and independent variables. Write your
answer in the table below.
Independent Variable Dependent Variable
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MODULE 4
This module was designed and written with you in mind. It is here to help you
master graphing and illustrating a linear function. The scope of this module
permits it to be used in many different learning situations. The language used
recognizes the diverse vocabulary level of students. The lessons are arranged to
follow the standard sequence of the course. But the order in which you read them
can be changed to correspond with the textbook you are now using.
Lesson Representation of
4 Function and Relation
Example 1:
Determine whether the following relations are function or not
a. {(1, 4), (2, 5), (3, 6), (4,7)} b. {(1, 2), (2, 5), (2, 0),(3,7)}
Solutions:
a. Each element in the domain, {(1), (2), (3), (4)} is assigned to no more than one
value in the range. 1 is assigned to 4, 2 is assigned to 5, 3 is assigned to 6
and 4 is assigned to 7. therefore, it is a function
b. Since the domain in element 2 is assigned to two different values in the
range, 5 and 0, it is not a function.
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Example 2:
Solve for x and y intercepts
3x - 5y =15 3x - 5y =15
3(0) -5y = 15 3x - 5(0) =15
-5y= 15 3x = 15
-5 = -5 3 3
y = -3 x= 5
Activity 1: Determine the domain and the range of the relation given the set of
ordered pairs.
1. {(0, 2), (1, 3), (2, 4), (3, 5), (4, 6)}
2. {(0, 2), (0, 4), (0, 6), (0, 8), (0, 10)}
3. {(-5, -2), (-2, -2), (1, 0), (4, 2), (7, 2)}
4. {(0, 2), (-1, 3), (-2, 4), (-3, 5), (-4, 6)}
5. {(0, -2), (1, -3), (2, -4), (3, -5), (4, -6)}
x -3 -2 -1 0 1 2 3
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MODULE 5
This module was designed and written with you in mind. It is here to help
you master on solving problems involving linear function. The scope of this
module permits it to be used in many different learning situations. The
language used recognizes the diverse vocabulary level of students. The
lessons are arranged to follow the standard sequence of the course. But the
order in which you read them can be changed to correspond with the
textbook you are now using.
Lesson
Linear Function
5
Linear functions are those whose graph is a straight line. A linear function
has the following form. y = f(x) = a + bx. A linear function has one independent
variable and one dependent variable.
Example:
Determine the values of the function f if f(x) = 2x – 1 at x = -3, 0, and 2. Give
their meanings and ordered pairs.
Solution: If x = -3, then f(x) = 2x – 1 becomes f(-3) = 2(-3) – 1
f(-3) = -6 – 1
f(-3) = -7
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which means the value of f at x = -3 is -7. or, if x = -3, then y = -7. This gives the
ordered pair (-3, -7).
Recall that an ordered pair can be written (x, y).
If x = 0, then f(x) = 2x – 1 becomes f(0) = 2(0) – 1
f(0) = 0 – 1
f(0) = -1
which means the value of f at x = 0 is -1. Or, if x = 0, then y = -1. This gives
another ordered pair (0, -1). If x = 2, then f(x) = 2x – 1 becomes f(2) = 2(2) – 1 f(2)
= 4 – 1 f(2) = 3, which means the value of f at x = 2 is 3. Or, if x = 2, then y = 3.
This gives the ordered pair (2, 3).
This implies that the graph of the function f will pass through the points (-3,
-7), (0, -1), and (2, 3).
Activity 1: Evaluate the following algebraic expressions. Match Column A with the
correct answer with Column B.
If x=2 y= -3 z=5
Column A Column B
1. 2xy A. 1
2. x-4y B. -37
3. x2+y C. -12
4. 4y-5z D. 27
5. 3x-7y E. 14
f(x)= 2-3x -6 -3 0 3 6
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MODULE 6
This module was designed and written with you in mind. It is here to help you
master on determining the relationship of between the hypothesis and conclusion
of an if -then statement. The scope of this module permits it to be used in many
different learning situations. The language used recognizes the diverse vocabulary
level of students. The lessons are arranged to follow the standard sequence of the
course. But the order in which you read them can be changed to correspond with
the textbook you are now using.
Lesson
If-Then Statement
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1. If students accomplish their homework on time, then they will get good
grades. Diane accomplished her homework on time; therefore, she got a good
grade.
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4. If two angles form a linear pair, then they are supplementary.
∠A and ∠B are supplementary; therefore, they form a linear pair.
If you will notice, the second statement is a valid consequence of the first
statement.
Examples:
If students accomplish their homework on time, then they will get good
grades. (hypothesis) (conclusion)
Activity 1: Identify the hypothesis and the conclusion for each of the following
conditional statements.
1. If you are kind and helpful, then you will have more friends.
Hypothesis: ___________________________________________
Conclusion: ___________________________________________
2. If you live your life to the fullest, then you will have no regrets.
Hypothesis: ___________________________________________
Conclusion: ___________________________________________
3. If you exercise regularly, then you will have a healthy mind and body.
Hypothesis: ___________________________________________
Conclusion: ___________________________________________
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Convert each statement to an if-then statement, then identify the hypothesis
and the conclusion.
1. Filipinos are God-fearing people.
If-Then Form: _____________________________________________________
Hypothesis: _______________________________________________________
Conclusion: _______________________________________________________
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MODULE 7
This module was designed and written with you in mind. It is here to help you
master on determining the inverse, converse, and contrapositive of n if-then
statement. The scope of this module permits it to be used in many different
learning situations. The language used recognizes the diverse vocabulary level of
students. The lessons are arranged to follow the standard sequence of the course.
But the order in which you read them can be changed to correspond with the
textbook you are now using.
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The inverse of a statement is formed by negating both the hypothesis and the
conclusion.
Statement If p, then q
(p → q)
Converse If q, then p
(q → p)
Inverse If not p, then not q
(~p → ~q)
Contrapositive If not q, then not p
(~q → ~ p)
Converse: __________________________________________________________
Inverse: ____________________________________________________________
Contrapositive: _____________________________________________________
Converse: __________________________________________________________
Inverse: ____________________________________________________________
Contrapositive: _____________________________________________________
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3. If a number is even, then it ends in the digit 0, 2, 4, 6, or 8.
Converse: __________________________________________________________
Inverse: ____________________________________________________________
Contrapositive: _____________________________________________________
Converse: __________________________________________________________
Inverse: ____________________________________________________________
Contrapositive: _____________________________________________________
Converse: __________________________________________________________
Inverse: ____________________________________________________________
Contrapositive: _____________________________________________________
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Conditional Converse Inverse Contrapositive
If two points are
collinear, then they
lie on the same
line.
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MODULE 8
This module was designed and written with you in mind. It is here to help
you master on illustrating the equivalences of a) the statement and its
contrapositive, and (b) the converse and inverse of a statement. The scope of
this module permits it to be used in many different learning situations. The
language used recognizes the diverse vocabulary level of students. The
lessons are arranged to follow the standard sequence of the course. But the
order in which you read them can be changed to correspond with the
textbook you are now using.
Two statements are logically equivalent if they have the same truth value for
all possible combinations of variables appearing in the two expressions. A
convenient and helpful way to organize truth values of various statements is in a
truth table. A truth table is a table whose columns are statements and whose rows
are possible scenarios. The table contains every possible scenario and the truth
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values that would occur. The table below summarizes a conditional statement's
truth value, its converse, inverse, and contrapositive.
T T F F T T T T
T F F T F T T F
F T T F T F F T
F F T T T T T T
Activity 1: Rewrite the conditional statement into its contrapositive, converse and
inverse.
s = 4units
Conclusion (q):____________________________________________________
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Directions: Write the converse, inverse, and contrapositive of the statement.
Identify the truth value of the given statements. If the statement is false, provide a
counterexample.
If x = 3, then 𝐱 𝟐 = 9.
Inverse
Contrapositive
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MODULE 9
This module was designed and written with you in mind. It is here to help you
master on using inductive and deductive reasoning, and writing direct and indirect
proof. The scope of this module permits it to be used in many different learning
situations. The language used recognizes the diverse vocabulary level of students.
The lessons are arranged to follow the standard sequence of the course. But the
order in which you read them can be changed to correspond with the textbook you
are now using.
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Examples:
1.
2. 1 + 100 = 101
2 + 99 = 101
3 + 98 = 101
4 + 97 = 101
5 + 96 = 101
Deductive reasoning requires one to start with a few general ideas, called
premises, and apply them to a specific situation. Recognized rules, laws, theories,
and other widely accepted truths are used to prove that a conclusion is right.
Examples:
Deductive
Inductive
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Activity 1: Observe the given statements. Provide a conclusion using the patterns
that you derived from the given statements.
1. Al got a high score in his Math test. He also loves to solve and compute. With
this, we can say that Al is _________________________________.
Draw a conclusion from the given situation and identify the reasoning being
used.
1. Acute angles measure less than 90. ∠ABC is an acute angle.
________________________________________________________________
3. Collinear points are points in the same line. Points X, Y and Z are on the
same line. ____________________________________________________________.
4. Filipinos are hospitable. Juan is a Filipino.
________________________________________________________________.
5. Every time I study hard, I get good grades. I believe that ___________________.
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Lesson
Direct and Indirect Proofs
9.2
34
The given statements show the differences between direct and indirect proof.
Direct proof is a sequence of statements that are either givens or deductions from
previous statements and whose last statement is the conclusion to be proved. At
the same time, the indirect proof is a method of reasoning where the opposite of the
statement to be proven is assumed true until the assumption leads to a
contradiction.
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Directions: Read and analyze ach question carefully. Choose the letter of the
correct answer.
A. 4a – 3b = 9
B. 8f + 4 < 12
C. 3x < 16
D. 11 + 2t ≥ 3k
2. Which among the mathematical symbols best translate the verbal statement
Twice a number x and y is at most 25?
A. 2x + y < 24
B. 2x + y > 24
C. 2x + y ≥ 24
D. 2x + y ≤ 24
A. infinite
B. 2
C. 1
D. zero
A. All real
B. [3, )
C. (3, )
D. All of the above
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6. Find the value of y if f(x) = 3x-2 and the value of x = 4.
A. -10
B. 10
C. 16
D. -16
7. Which of the following is the if-then form of the statement: “A prime number
has one and itself as factors.”?
8. Which of the following is the contrapositive of the statement, “If two angles
are vertical, then they are congruent.”?
A. If two angles are not vertical, then they are not congruent.
B. If two angles are congruent, then they are vertical.
C. If two angles are vertical, then they are congruent.
D. If two angles are not congruent, then they are not vertical.
9. The statement If <A and <B are supplementary, then the sum of their
measure is 180° is translated into If the sum of the measure of <A and <B is
180°, then they are supplementary. Which symbolization illustrates the
second statement?
A. p→q
B. q→p
C. ~p→~q
D. ~q→~p
10. Which appropriate conclusion can be drawn from the statement m∠J + m∠S
= 90?
A. ∠J≅∠S
B. ∠J and ∠S are right angles
C. ∠J and ∠S are complementary
D. ∠J and ∠S are supplementary
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What I can Do What's More
Slope: 2
y-intercept: -
5
Plane Divider:
Solid Line
Shaded
Region: Lower
Region
Module 1
Module 2
Module 3
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What I can Do What’s More
x -3 -2 -1 0 1 2 3
y -5 -3 -1 1 3 5 7 1. Domain: {0, 1, 2, 3, 4}
Range: {2, 3, 4, 5, 6}
2. Domain: {0}
Range: {2, 4, 6, 8, 10}
3. Domain: {-5, -2, 1, 4,
7}
Range: {-2, 0, 2}
4. Domain: {0, -1, -2, -3,
-4}
Range: {2, 3, 4, 5, 6}
5. Domain: {0, 1, 2, 3, 4}
Range: {-2, -3, -4, -5, -
6}
Module 4
What I can Do
Note: Assist the students in
checking this part
Module 5
Module 6
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Module 7
42
43
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What’s More
Conditional Statement: If the sides of the square measure 4 units,
then its area is 16 square units.
Premise: The sides of the square measures 4 units
Conclusion: The area of a square is 16 square units.
Converse: If the area of a square is 16 square units, then its sides
measure 4 units.
Inverse: If the sides of a square do not measure 4 units, then its area
is not 16 square units.
Contrapositive: If the are of the square in not 16 square units, then
its sides do not measure 4 units.
Module 8
Module 9
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References
Antonio C. Coronel and Sr. Iluminada C. Coronel. (2013). Growing Up with Math 8.
Quezon City: FNB Educational, Inc.
Orlando A. Oronce and Marilyn O. Mendoza. (2013). E-Math 8. Quezon City: Rex
Book Store, Inc.
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For inquiries or feedback, please write or call:
Telefax: 02-8332-77-64
Email Address: navotas.city@deped.gov.ph