INDIAN INSTITUTE OF TECHNOLOGY ROORKEE
LNA Design
Prof. Darshak Bhatt
unilateral figure of merit
• For many transistors |S12| is small enough to be ignored,
and the device can be assumed to be unilateral.
• The error in the transducer gain caused by approximating
|S12| as zero is given by the ratio GT/GTU.
• U is defined as the unilateral figure of merit,
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Expression for Gs and Gl
• For Bilateral case:
• For Matched conditions:
• Define normalized gain factors 𝑔𝑠 and 𝑔𝐿 as:
• Then we have that 0 ≤ gS ≤ 1 and 0 ≤ gL ≤ 1.
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• Constant gain circles for input section:
• Constant gain circles for output section:
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Attributes
∗ ∗
• Angle of circles are defined by 𝑆11 and 𝑆22
• when gS (or gL) = 1 (maximum gain)
-> The radius RS (or RL) = 0,
∗ ∗
-> The center reduces to 𝑆11 and 𝑆22
• The 0 dB gain circles where will always pass through the
center of the Smith chart.
• Example: Gain=11 dB, freq= 4.0 GHz,
• Plot constant-gain circles for 𝐺𝑆 = 2 and 3 dB, and 𝐺𝐿 = 0 and
1 dB.
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• Ans: 1) Find stability. K>1, Δ < 1,
• 2) Find Maximum gain
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• We choose G S = 2 dB and G L = 1 dB, for an overall
amplifier gain of 11 dB.
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Low noise amplifier design
• NF of two-port amplifier can be expressed as:
• 𝑌𝑆 = 𝐺𝑆 + 𝑗 𝐵𝑆 = source admittance presented to transistor.
• 𝑌𝑜𝑝𝑡 = optimum source admittance that results in minimum
noise figure.
• 𝐹𝑚𝑖𝑛 = minimum noise figure of transistor, attained when YS
= Yopt.
• 𝑅𝑁 = equivalent noise resistance of transistor.
• 𝐺𝑆 = real part of source admittance.
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• Converting admittance to reflection coefficient.
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• For fix value of the NF this equation will represent the circles
in 𝝘𝑆 plane.
• Noise figure parameter N is given by:
• The circle equation is given by:
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Examples
• S-parameters at 4 GHz. 𝑆11 = 0.6∠ − 60 ◦,
𝑆12 = 0.05∠26 ◦,
𝑆21 = 1.9∠81 ◦,
𝑆22 = 0.5∠ − 60 ◦,
𝐹𝑚𝑖𝑛 = 1.6 𝑑𝐵,
𝝘𝑜𝑝𝑡 = 0.62∠100 ◦,
𝑎𝑛𝑑 𝑅𝑁 = 20 .
• Assume device is unilateral, find error in GT.
• Design an amplifier with 2 dB of NF.
• Ans: 1) Find stability. K = 2.78 and Δ = 0.37
• 2) Calculate Unilateral Figure of merit
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