a
QUESTION 3
b
d'
c' c
16
b' d
,0 °
e' a' e
4,4
°
f'
g' f
150
h'
2,1°
θ=(R/L)*360
4,5°
=(25/(√(150²+((100
2 )²))*360
=113.9°
h' 7
°
113,9
g' 6
f' 5
e' 4 360:113.9
50.7:ab =>16.0°
d' 3 13.9:bc =>4.4°
4.6 :cd =>1.5°
2
16
c' 6.5:de =>2.1°
b' 1
14.2:ef =>4.5°
a'
14,2°
e f
d
c
6,5°
b
h'
4,6°
9°
13,
Ø100
7°
50,
7
a
6 d'
5 DEPARTMENT: FACULTY: DRAWN BY: TITLE:
4 MECHANICAL ENGINEERING
TUTORIAL 5
3
2 NAMIBIA UNIVERSITY APPROVED BY: PROJECTION DRAWING NR:
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