Phenols Worksheet Year 13
Phenols Worksheet Year 13
Phenols WS 1
PHENOLS
14 WS 1
1 7 (a) (i) State and explain the relative acidities of ethanol and phenol.
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(ii) In the table below, give the reaction conditions for the formation of organic products D and
E and draw their structures.
OH
HNO3 Br2
D E
phenol
HNO3 dilute, 5 C
Br2
[3]
....................................................................................................................................... [1]
....................................................................................................................................... [1]
....................................................................................................................................... [1]
62 Oleocanthal, Q, is a natural compound found in olive oil. It has antioxidant and anti-inflammatory
properties and is thought to have a protective effect against Alzheimer’s disease.
O
HO
O
Q
On the structure of Q above, circle the functional group that shows cis-trans isomerism and
indicate with an asterisk (*) the chiral carbon atom. [1]
(b) Q can be isolated from olive oil by partitioning between two solvents.
.............................................................................................................................................
.............................................................................................................................................
....................................................................................................................................... [2]
(ii) When 40.0 cm3 of hexane was shaken with 10.0 cm3 of a solution containing 0.25 g of Q in
10.0 cm3 of methanol, it was found that 0.060 g of Q was extracted into the hexane.
(c) Complete the following table to show the structures of the products formed when Q reacts with
the three reagents.
excess
Br2(aq)
NaBH4
excess hot
NaOH(aq)
[6]
(d) When a sample of Q synthesised in a laboratory was compared to a natural sample from olive
oil, it was found that the therapeutic activity of the synthetic sample was lower.
....................................................................................................................................................
.............................................................................................................................................. [1]
[Total:
[N’16 P4212]
Q6]
Phenols 1
74
11
OH
NO2
2-nitrophenol
The nitration reaction of phenol to form 2-nitrophenol shows that phenol is more reactive than
benzene.
Explain how these conditions show phenol to be more reactive than benzene.
conditions ...........................................................................................................................
explanation .........................................................................................................................
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[2]
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....................................................................................................................................... [1]
(iii) Complete the mechanism for the nitration of phenol to form 2-nitrophenol. You should
assume that the mechanism is the same as that for the nitration of benzene.
OH
+
NO2
products
phenol intermediate
[3]
(iv) Name the isomer of 2-nitrophenol which is also a major product of this reaction.
....................................................................................................................................... [1]
[Total:
[J’18 P4214]
Q6]
Phenols 1
75
16
74 (a) Chlorobenzene and phenol both show a lack of reactivity towards reactants that cause the
breaking of the C–X bond (X = Cl or OH).
Explain why.
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.............................................................................................................................................. [3]
(b) When phenol is reacted with bromine dissolved in an inert solvent, two isomeric bromophenols,
C6H4BrOH, are formed.
name: ..................................................................
name: ..................................................................
[2]
Phenols 1
76
Phenols10 WS 2
14 Cyclohexanol and phenol are both solids with low melting points that are fairly soluble in For
water. Examiner’s
Use
OH OH
cyclohexanol phenol
(a) Explain why these compounds are more soluble in water than their parent hydrocarbons
cyclohexane and benzene.
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..................................................................................................................................... [2]
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Phenols 2
(c) For each of the following reagents, draw the structural formula of the product obtained For
for each of the two compounds. If no reaction occurs write no reaction in the box. Examiner’s
Use
Na(s)
NaOH(aq)
Br2(aq)
I2(aq) + OH–(aq)
an excess of
acidified Cr2O 27 –(aq)
[7]
(d) Choose one of the above five reagents that could be used to distinguish between
cyclohexanol and phenol. Describe the observations you would make with each compound.
reagent ........................................................................................
Phenols 2
78
5
23 Menthol and menthone, the main constituents of oil of peppermint, can be made synthetically For
from thymol by the following route. Examiner’s
Use
I II
OH OH O
• reaction I, ..........................................................................................................
(b) Suggest one test for each of the three compounds that would give a positive result with
the stated compound but a negative result with both the other two compounds.
thymol
test ...................................................................................................................................
observation ......................................................................................................................
menthol
test ...................................................................................................................................
observation ......................................................................................................................
menthone
test ...................................................................................................................................
HO CO2C2H5
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(b) Draw the structures of the compounds formed when E reacts with
(iii) Br2(aq).
[4]
9701/4/O/N/03
Phenols 2
80 9 For
Examiner’s
Use
(c) Compounds F and G are isomers of E.
F G
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...................................................................................................................................
(ii) Based on their relative acidities, suggest how samples of E, F and G could be
distinguished from each other by the use of NaOH(aq) and Na2CO3(aq).
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[3]
[N'03 P4 Q4]
[Total : 9]
CH3 OH
CH2 H
C
H2C C
CH2
H2C CH
CH2
CH2
OH
CH3 H
Oestradiol is one of the hormones that controls the reproductive cycle in female mammals.
HO
CH3 H
H
H H
HO
oestradiol
(a) (i) On the above structure of oestradiol, circle one chiral centre.
(ii) What is the total number of chiral centres in the oestradiol molecule? .....................
[2]
(b) Complete the following part-structures (which have the -OH groups removed) to show
the products obtained when oestradiol (above) is reacted with the stated reagents.
CH3
H
H H
CH3
H
H H
(iii) NaOH(aq)
CH3
H
H H
(iv) CH3COCl
CH3
H
H H
CH3
H
H H
[7]
[J'07 P4 Q6]
[Total: 9]
© UCLES22007
Phenols 9701/04/M/J/07 [Turn over
83
10
55 (a) A series of experiments is carried out in which the reagent shown at the top of the column
For
Examiner’s
of the table is mixed, in turn, with each of the reagents at the side. Use
Complete the following table by writing in each box the formula of any gas produced.
Write x in the box if no gas is produced.
The first column has been completed as an illustration.
OH CO2H OH
H 2O
Na H2
KOH(aq) x
Na2CO3(aq) x
[5]
(b) Compound C is responsible for the pleasant aroma of apples. It can be prepared from
phenol by the following 3-step synthesis.
OH OH OH O CH3
step step step
1 2 3
C C C
H 3C CH3 H 3C CH3 H 3C CH3
CH3 CH3 CH3
A B C
(i) The only by-product of step 1 is HCl. Suggest the reagent that was used to react
with phenol to produce compound A.
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(iv) State the reagent and conditions needed to convert C back to B, the reverse of
step 3.
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[5]
an excess of Br2(aq)
(ii) Choose one of the above reactions to enable you to distinguish between A and B.
State below the observations you would make with each compound.
[7]
[J'13 P41 Q5]
[Total: 17]
O O OH
OH
O
HO OH
HO
chlorogenic acid
(a) (i) Draw circles around any chiral centres in the above structure.
....................................................................................................................................
(iii) How many moles of H2(g) will be evolved when 1 mol of chlorogenic acid reacts with
an excess of sodium metal?
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(iv) How many moles of NaOH(aq) will react with 1 mol of chlorogenic acid under each
of the following conditions?
on heating ...............................................
[6]
OH
OH OH
O
dil. H+(aq) +
chlorogenic acid
heat HO O OH
HO OH
HO
D E
conc.
H2SO4 Br2(aq)
heat in excess
C7H6O3
F G
(i) What type of reaction is chlorogenic acid undergoing when D and E are formed?
....................................................................................................................................
Compound F evolves CO2(g) when treated with Na2CO3(aq), and decolourises Br2(aq),
giving a white precipitate. It does not, however, decolourise cold dilute acidified KMnO4.
(ii) If the test with cold dilute acidified KMnO4 had been positive, which functional group
would this have shown to be present in F?
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(iii) Name the functional groups in compound F that would react with the following.
(iv) Suggest structures for compounds F and G and draw them in the relevant boxes
above.
Phenols 2
7
87
11
For
(d) Propanoic acid, CH3CH2CO2H, is a weak acid with Ka = 1.34 10–5 mol dm–3. Examiner’s
For
7
(v) Compound E is one of a pair of stereoisomers. Use
Examiner’s
(i) Calculate the pH of a 0.500 mol dm–3 solution of propanoic acid. –5 Use
For
(d) Propanoic
What typeacid, CH3CH2CO2H, isisa shown
of stereoisomerism weak acid with Ka = 1.34
by compound E? 10 mol dm .
–3
Examiner’s
Use
(i) Calculate the pH of a 0.500 mol dm–3 solution of propanoic acid.
....................................................................................................................................
(vi) Draw the structure of the other stereoisomer in the box below.
Buffer solution F was prepared by adding 0.0300 mol of sodium hydroxide to 100 cm3 of
a 0.500 mol dm–3 solution of propanoic acid.
Buffer solution F was prepared by adding 0.0300 mol of sodium hydroxide to 100 cm3 of
(ii) Write an equation
a 0.500 mol dm–3for the reaction
solution between
of propanoic sodium hydroxide and propanoic acid.
acid.
(ii) Write an equation for the reaction between sodium hydroxide and propanoic acid.
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(iii) Calculate the concentrations of propanoic acid and sodium propanoate in buffer
solution F.
(iii) Calculate the concentrations of propanoic acid and sodium propanoate in buffer
solution F.
H O O
H
CH3CH2CH
CO2CH
H CO H G G + +J J
3 2 2
O O
G is ..........................................................
G is ..........................................................
H is ..........................................................
H is ..........................................................
J is ..........................................................
J is ..........................................................
[2] [2]
[N'13 P41 Q3]
[Total:
[Total: 18] 18]
© UCLES 20132013
© UCLES 9701/42/M/J/13
9701/41/O/N/13 [Turn
[Turn over
over
© UCLES 2013 9701/41/O/N/13 [Turn over
Phenols 2
888
For
85 (a) Bromine reacts with a variety of organic compounds. Examiner’s
For each of the following reactions, Use
complete and balance the equation, including the structural formula of the organic
product,
state the specific conditions (if any) under which the reaction takes place and the
type of reaction that occurs.
OH
(i) ............Br2 +
(ii) ............Br2 +
(iii) ............Br2 +
hot MnO4–
D
B
(i) Suggest the identities of compounds C, D and E, drawing their structures in the
boxes above.
(ii) Use the relevant letter, C, D or E, to identify which of your compounds will react with
each of the following reagents.
Each reagent may react with more than one of C, D and E, in which case state all
the compounds that may react with each reagent.
2,4-dinitrophenylhydrazine ..............................
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[4]
(b) (b)
Complete the the
Complete following equations
following showing
equations showing allall
the products
the productsofofeach
eachofofthese
thesereactions
reactions of
of
phenol.
phenol. Include reaction conditions where appropriate in the boxes over the arrows.IfIf no
Include reaction conditions where appropriate in the boxes over the arrows. no
reaction occurs
reaction write
occurs no no
write reaction in in
reaction thethe
products
products box.
box.
OH OH
+ Na
+ Na
OH OH
+ NaOH
+ NaOH
OH
OH
+ CH3CO2H
+ CH3CO2H
OH
OH
+ Br2
+ Br2
[5]
[5]Q5]
[J'11 P42
Phenols 2
91
10
10
5 L-DOPA is used in the treatment of Parkinson's disease. It can be prepared from vanillin.
HO HO
NH2
H
HO CO2H CH3O
O
L-DOPA vanillin
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.............................................................................................................................................. [5]
Phenols 2
92
11
(b) A student carried out some reactions with samples of L-DOPA and vanillin using reagents X, Y
and Z.
Reagent X ..................................................................................................................................
Reagent Y ..................................................................................................................................
Reagent Z ..................................................................................................................................
Phenols 2
93
10
126 Oleocanthal, Q, is a natural compound found in olive oil. It has antioxidant and anti-inflammatory
properties and is thought to have a protective effect against Alzheimer’s disease.
O
HO
O
Q
On the structure of Q above, circle the functional group that shows cis-trans isomerism and
indicate with an asterisk (*) the chiral carbon atom. [1]
(b) Q can be isolated from olive oil by partitioning between two solvents.
.............................................................................................................................................
.............................................................................................................................................
....................................................................................................................................... [2]
(ii) When 40.0 cm3 of hexane was shaken with 10.0 cm3 of a solution containing 0.25 g of Q in
10.0 cm3 of methanol, it was found that 0.060 g of Q was extracted into the hexane.
Phenols 2
94
11
(c) Complete the following table to show the structures of the products formed when Q reacts with
the three reagents.
excess
Br2(aq)
NaBH4
excess hot
NaOH(aq)
[6]
(d) When a sample of Q synthesised in a laboratory was compared to a natural sample from olive
oil, it was found that the therapeutic activity of the synthetic sample was lower.
....................................................................................................................................................
.............................................................................................................................................. [1]
[N'1612]
[Total: P42 Q6]
Phenols 2