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Hamiltonian1 MTA

The document discusses the existence of periodic solutions for a class of Hamiltonian systems characterized by super quadratic and sign-indefinite potentials. It presents a variant existence result and outlines the conditions necessary for these solutions to exist, relying on mathematical frameworks such as the Cerami–Palais–Smale condition. The author, Leonard Shilgba, provides a detailed analysis of the assumptions and methodologies used to derive these results.

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0% found this document useful (0 votes)
27 views11 pages

Hamiltonian1 MTA

The document discusses the existence of periodic solutions for a class of Hamiltonian systems characterized by super quadratic and sign-indefinite potentials. It presents a variant existence result and outlines the conditions necessary for these solutions to exist, relying on mathematical frameworks such as the Cerami–Palais–Smale condition. The author, Leonard Shilgba, provides a detailed analysis of the assumptions and methodologies used to derive these results.

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traore.arouna
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© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
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Existence result for periodic solutions of a class of


Hamiltonian systems with super quadratic potential

Article in Nonlinear Analysis · November 2005


DOI: 10.1016/j.na.2005.05.018

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Nonlinear Analysis 63 (2005) 565 – 574
www.elsevier.com/locate/na

Existence result for periodic solutions of a class of


Hamiltonian systems with super quadratic potential
Leonard Karshima Shilgba∗
Hirano Laboratory, Division of Information Media and Environment Sciences, Graduate School of Environment
and Information Sciences, Yokohama National University, 79-5, Tokiwadai, Hodogaya-Ku, Yokohama-shi,
Kanagawa 240-8501, Japan
Received 27 May 2003; accepted 18 May 2005

Abstract
We have presented a variant existence result for periodic solutions to a class of Hamiltonian systems
with a potential which is both super quadratic and sign-indefinite.
䉷 2005 Elsevier Ltd. All rights reserved.
MSC: 34B15

Keywords: Periodic solutions; Hamiltonian systems; Potential; Linking

1. Introduction

Our objective is to investigate the existence of periodic solutions to the class of Hamil-
tonian systems:

ẍ + A(t)x + b(t)V  (x) = 0 on [0, T ],


x(0) = x(T ),

ẋ(0) = ẋ(T ), (P)

∗ Tel.: +81 45 50 24 115; fax: +81 45 33 94 207.


E-mail address: shilgba@yahoo.com.

0362-546X/$ - see front matter 䉷 2005 Elsevier Ltd. All rights reserved.
doi:10.1016/j.na.2005.05.018
566 L.K. Shilgba / Nonlinear Analysis 63 (2005) 565 – 574

where

1.1 A ∈ C 0 (R, RN×N ) is a symmetric T -periodic matrix function that is not sign-definite
on [0, T ];
1.2 b ∈ C 0 (R, R) is T -periodic and hanges sign on [0, T ];
1.3 V ∈ C 2 (RN , R) with V (x)  V (0) = 0 for all x ∈ RN , and has super quadratic
behaviour.

The above problem has been studied by several authors:


Case A: A ≡ 0.
While Lassoued [14] obtained existence of T -periodic solutions when V is strictly convex
and homogeneous, Ben Naoum et al. [7] provided existence results by relaxing condition
on V to only homogeneity.
Girardi and Matzeu [13] used the Alama–Tarantello condition in [1] and proved some
existence and multiplicity results for T -periodic and subharmonic solutions. The condition
is given by:
There exist c > 0,  > 2 : |V  (x)x − V (x)|  c|x|2 for all x ∈ RN . (1.4)
Case B: A  = 0.
In this case, when b(.) > 0, refer to [3,2,10] (with the references contained therein),
severally for existence of periodic, homoclinic, and subharmonic solutions. Besides, when
we assume b changes sign and A is a negative definite matrix, there are some existence and
multiplicity results of periodic, subharmonic, and homoclinic solutions (refer to [12,8,4]).
When b(.) changes sign and A is sign-indefinite, the author is aware of only the results of
Antonacci [5], Xu and Guo [19], and the author in [18].
Antonacci proved the existence of non-trivial periodic solutions under the assumption
that
 T
(A(t), ) dt > 0 for all  ∈ RN , || = 1. (1.5)
0
Antonacci observed the vital role played by assumption (1.5) as he posed two open problems:
Given that A(.) is not negative-definite, to

1. study the existence of T -periodic solutions of (P) in the case (1.5) holds and A(.) is
sign-indefinite in any interval [0, T ];
2. find some existence results in the case that A does not satisfy (1.5).

As mentioned above, Antonnaci attempted an elegant solution of problem 1 in [5]. Xu and


Guo, in attempting the solution of open problem 2 in [18], relied, among other assumptions,
on the glooseh or weaker version of (1.5), that:
T
There exist  > 0,  > 2,  > 0,  : 0 <  < ( 0 b(t) dt) such that
 T
(A(t), ) dt  −  for all  ∈ RN , || = 1, (1.6)
0

where V (x) |x| −  for all sufficiently large x ∈ RN .


L.K. Shilgba / Nonlinear Analysis 63 (2005) 565 – 574 567

T
It is clear from (1.6) that 0 (A(t), ) dt,  ∈ RN , || = 1, is neither assumed to be
definitely positive nor negative, which is a relaxation on condition (1.5.); however, it is only
T
valid when 0 b(t) dt > 0. In [18] we resolved the open problem 2 posed by Antonnaci by
assuming some super-convex quadratic condition on the potential V :
There exist real numbers, R > 0, ,  :  >  > 1 such that
 
 b(t) dt + b(t) dt > 0,
I I¯

and for all z1 , z2 ∈ RN , z1  = z2 , and |z1 + z2 | > R, we have

V (z1 + z2 ) (V (z1 ) + V (z2 )) − |z1 − z2 |2 . (V∗ )

In this paper we drop the super-convex quadratic condition (V∗ ).

2. Existence results

We shall investigate the periodic solutions of (P) in the Sobolev space HT1 = H 1 ([0, T ],
RN ) = {u : [0, T ] → RN is absolutely continuous, u(0) = u(T ), u̇ ∈ L2 (0, T ; RN )} with
the norm
 T  T 1/2
u = |u̇| +
2
|u| 2
for all u ∈ HT1 ,
0 0

assuming conditions 1.1–1.3 are verified in addition to the following assumptions:

a.1 0 < l = max |A(t)| < (1+442 )T 2 : (A(t)x, x)  l|x|2 , for all x ∈ RN , t ∈ [0, T ]
2

t∈[0,T ]
T
b.1 0 b(t) dt = 0.
m.1 There exist  > 0,  : 0 <  < l, t0 ∈ [0, T ], R1 > 0:
(i) b(t) > 0 for all t ∈ I , I = [t0 − , t0 + ] ⊂ [0, T ].
(ii) I (A(t)x, x) dt  I |x|2 dt for all x ∈ HT1 .
 
(iii)  I¯ (A(t), ) dt  T for all  ∈ RN , || = 1, (I¯ = [0, T ]\I ).
V .1 There exist  > 2, a1 > 0, R2 > 0:
(i) V (x)  V  (x)x for all x ∈ RN , |x|  R2 ,
(ii) V (x)  a1 |x| for all x ∈ RN , |x|  R2 .
V .2 There exist , R3 > 0 : V (x)  |V  (x)||x| for all x ∈ RN , |x|  R3 (xy denotes
the inner product of the pair of vectors x, y ∈ RN ).
V .3 There exists R4 > 0 : V (x) − (V  (x), x)  c|x|2 for all x ∈ RN , |x|  R4 where
 
−2 4 2
c< − l , m = max b(t).
2m (1 + 42 )T 2 t∈[0,T ]

V (x)
V .4 lim = 0.
|x|→0 |x|
2
568 L.K. Shilgba / Nonlinear Analysis 63 (2005) 565 – 574

Remark. Assumption m.1 indicates that


 T
(A(t), ) dt (2 − T ) for all  ∈ RN , || = 1; 2 − T < 0.
0

This is an improvement on condition (0.2) in [5].

Hamiltonian action: We reduce problem (P) to finding critical points of the functional:
 T  T   T
1
I (x) = |ẋ|2 − A(t)x.x − b(t)V (x) x ∈ HT1 (∗ )
2 0 0 0

associated with (P). We note that the critical points of this functional correspond to periodic
solutions of (P).

Definition 2.1 (Cerami–Palais–Smale condition). Given a real Banach space X, we say


that I ∈ C 1 (X, R) satisfies the Cerami–Palais–Smale condition at level d ∈ R (i.e
condition (CP S)d for short) if for any sequence (xn ) ∈ X such that I (xn ) → d and
(1 + xn )I  (xn ) → 0 it implies that (xn ) contains a strongly convergent subsequence
in X.

Remark. The Cerami–Palais–Smale condition was introduced by Cerami [9] as a weaker


variant of the classical Palais–Smale condition. We shall rely on the following linking
theorem of Benci–Rabinowitz (see [17,6]).

Theorem 2.2 (Linking theorem). Let E be a Banach space and I ∈ C 1 (E, R) such that

(a) E = E− ⊕ E+ , dim E− < ∞ and E+ is closed in E.


(b) There exist r, R : 0 < r < R, and ∈ E+ with  =1 : sup{I (x) : x ∈ jQ}  inf{I (x) :
x ∈ D} where
Q = {u + :  0, u ∈ E− , u +   R} ⊂ E− ⊕ R ;
D = {x ∈ E+ : x = r}.

(c) I satisfies the Cerami–Palais–Smale condition (CP S)d ,

d = inf sup I (g(y)), = {g ∈ C(Q, E) : g(y) = y for all y ∈ jQ}.


g∈ y∈Q

Then d  inf D I and d is a critical value of I. Moreover, if d = inf D I , there is a critical


point xd ∈ D : I (xd ) = d.

Lemma 2.3. Let conditions 1.1–1.3, a.1, b.1, V .1–V .3 be verified. Then I ∈ C 1 (HT1 , R)
given as in (∗) satisfies the Cerami–Palais–Smale condition for all real d.

Proof. We only need to show that given any sequence (xn ) ∈ HT1 such that I (xn ) is bounded
and (1 + xn )I  (xn ) → 0 as n → ∞ i.e sup{(1 + xn )I  (xn ) : ∈ HT1 ,   = 1} → 0
L.K. Shilgba / Nonlinear Analysis 63 (2005) 565 – 574 569

as n → ∞), then (xn ) contains a strongly convergent subsequence in HT1 . Boundedness of


I (xn ) implies that there exists k > 0 such that
   T
1 T 1 T
|ẋn |2  (A(t)xn , xn ) + b(t)V (xn ) + k. (2.1)
2 0 2 0 0

Since (1 + xn )I  (xn ) is linear, it follows from Riesz’s representation theorem that there
exists a sequence (zn ) ∈ HT1 such that
(1 + xn )I  (xn )H −1 = zn  = n →0 as n → +∞ and
T

(1 + xn )I  (xn ) = zn , H 1 for all  ∈ HT1 .


T

Thus, we have from Cauchy–Schwartz inequality that


 T  T  T
|ẋn |2  (A(t)xn , xn ) + b+ (t)(V  (xn ), xn )
0 0 0
 T
− 
− b (t)(V (xn ), xn ) − n ,
0

where b+ (t) = max{0, b(t)} and b− (t) = − min{0, b(t)}, t ∈ [0, T ].


Clearly, b(t) = b+ (t) − b− (t) for all t ∈ [0, T ].
Hence,
 T  T  T  T
|ẋn | 
2
(A(t)xn , xn ) +  b(t)V (xn ) − mc |xn |2 − n.
0 0 0 0
Therefore,
 T  T  T  T
1 1 mc n
− |ẋn |2  − (A(t)xn , xn ) − b(t)V (xn ) + |xn |2 + .
 0  0 0  0 
(2.2)
Combining (2.1) and (2.2) results
 
−2 T ( − 2)l + 2mc T n
|ẋn |2  |xn |2 + + k.
2 0 2 0 
That is,
 T  T
( − 2) |ẋn |2  [( − 2)l + 2mc] |xn |2 + k̄, (0 < k̄ < ∞).
0 0
Or, according to Wirtinger’s inequality, we have that
  T
T2
( − 2) − [( − 2)l + 2mc] 2 |ẋn |2  T [( − 2)l + 2mc]|x̄n |2 + k̄,
4 0

where
 T
1
x̄n = xn (t) dt, n ∈ N.
T 0
570 L.K. Shilgba / Nonlinear Analysis 63 (2005) 565 – 574

Clearly from condition V .3,

T2
d̄ = ( − 2) − [( − 2)l + 2mc] > 0.
42
Thus, setting

T [( − 2)l + 2mc] k̄


d1 = (> 0) and d2 = (> 0),
d̄ d̄
we obtain
 T
|ẋn |2  d1 |x̄n |2 + d2 . (2.3)
0

Moreover, applying Sobolev inequality and from (2.3), it is not difficult to verify that

min |xn (t)|  d3 |x̄n | − d4 , (d3 = 1 − (T d 1 )1/2 , d4 = (T d 2 )1/2 ).


t∈[0,T ]

We claim that 1 − T d 1 > 0. Suppose the contrary, that 1 − T d 1  0, i.e if and only if
 
42
2mc  ( − 2) −l .
(1 + 42 )T 2
This is a contradiction. Hence, we have,

min |xn (t)|  d3 |x̄n | − d4 , (d3 , d4 > 0). (2.4)


t∈[0,T ]

Clearly, if the sequence (|x̄n |) of real numbers is bounded, then so is (xn ) in HT1 . Suppose
|x̄n | → +∞ as n → +∞. Then V (xn )  a1 |xn | → +∞. So, we can define a sequence
in HT1 :

xn (t)
n (t) = , t ∈ [0, T ]
(1 + xn )V (xn (t))
which is well defined at infinity. Furthermore,
V (xn )ẋn − xn [V  (xn )ẋn ]
˙ n = .
(1 + xn )(V (xn ))2
So,

( + 1)2 |ẋn |2
|˙n |2 
[(1 + xn )V (xn )]2
for sufficiently large n, and

[{T 2 /42 + ( + 1)2 }d1 + T ]|x̄n |2 + const.


n 2  →0 as n → +∞.
a12 (1 + xn )2 (d3 |x̄n | − d4 )2
L.K. Shilgba / Nonlinear Analysis 63 (2005) 565 – 574 571

Hence,
(1 + xn )I  (xn )n → 0 as n → +∞.
It is clear that
 
 T ˙  → 0 as n → +∞.
(i) (1 + xn )  0 ẋn n
 
 T 
(ii) (1 + xn )  0 A(t)xn n  → 0 as n → +∞.

Now,
 T  T  T
 |xn |2
(1 + xn ) b(t)V (xn )n  b(t) dt − b+ (t) dt.
0 0 0 V (xn )
Thus,
 T  T
(1 + xn ) b(t)V  (xn )n →  b(t) dt  = 0 as n → +∞
0 0
since
 
 T |xn |2  m(T 2 /42 )d1 + T )|x̄n |2 + const.
 +
b (t) dt < →0 as n → +∞.
 V (xn ) 
0 a1 (d3 |x̄n | − d4 )
This contradicts our supposition. Therefore, (xn ) is bounded, and so by a similar proof in
[4], admits a strongly convergent subsequence. 

Theorem 2.4 (Main result). Given that assumptions 1.1–1.3 and a.1–V .4 hold, then (P )
has at least one periodic solution.
T
Proof. HT1 = H ⊕ RN , H = {x ∈ HT1 : 0 x(t) dt = 0}.
Let x ∈ H . Then,
   T
1 T 2 1 T
I (x) = |ẋ| − (A(t)x, x) − b(t)V (x)
2 0 2 0 0
  T  T
1 4 2
 − l |x| 2
− m V (x).
2 T2 0 0

According to V .4, we can choose


1
,0< < (42 /T 2 − l) such that there exists r  ( ) > 0 (sufficiently small):
2m
  T
1 4 2
I (x)  − l − m |x|2 > 0 for all x ∈ H , x∞ = r  . (1)
2 T2 0

Clearly, there exists c1 , c2 > 0 such that


 T  T
I (x)  c1 |ẋ|2 and I (x)  c2 |x|2 for all x ∈ H , x∞ = r  .
0 0
572 L.K. Shilgba / Nonlinear Analysis 63 (2005) 565 – 574

So,
I (x)  cm x2 , cm = min{c1 , c2 } for all x ∈ H , x∞ = r  .
Thus, we can find r(r  ) > 0 : I (x) > 0 for all x ∈ H , x = r.
Furthermore, choose a constant vector 0 ∈ RN : |0 |2 = /(2 + 2 ).
Define,

0 cos (t +  − t0 ) t ∈ I ,
(t) = 
0 t ∈ I¯ = [0, T ]\I .

So, we have (t) ∈ HT1 ,   = 1.(Particularly, (t) ∈ H .) Besides, Supp{ } ⊂ I .


Let H̄ = + z :  0, z ∈ RN . Thus, for every + z ∈ H̄ , we have
 T  
2
|z|2 
I( + z)  |˙ |2 − (A(t), ) − | + z|2
2 0 2 I¯ 2 I
 
− b(t)V ( + z) − V (z) b(t)
I I¯
 
2
|z|2 
 |˙ |2 + T − | + z|2
2 I 2 2 I
 
− a1 ˜ | + z| − V (z) b(t),
I I¯

where ˜ = minI b(t) > 0 and  ∈ RN ,  = z/|z|(|| = 1).


Now, defining some two norms on H̄ :
 1/2  1/

 + z1 = | + z| 2
,  + z2 = | + z| ,  2,
I I

it is clear that they are equivalent since dim H̄ < ∞. Therefore, for our fixed  > 2, we
have that there exists k1 () > 0 such that  + z2  k1  + z1 for all  0, z ∈ RN .
Besides, we can find some constant k2 > 0 (independent of z ∈ RN ,  0):
 
  
I ( + z)  k2 −  + z21 − k1 a1 ˜  + z − V (z) b(t). (2.5)
2 I¯
1

We have two cases, namely,


   T 
Case 1 : b(t) > 0 i.e b(t) > 0 .
I¯ 0
   
Case 2 : b(t) < 0 if and only if − b(t) > 0 .
I¯ I¯

Case 1: We have from (2.5) that


  
I( + z)  k2  + z21 −  + z21 − k1 a1 ˜  + z .
2 1
L.K. Shilgba / Nonlinear Analysis 63 (2005) 565 – 574 573

Clearly, we can find R > r (sufficiently large) such that

I( + z)  0 for all + z ∈ H̄ :  + z = R.

Therefore,

sup{I ( + z) :  0 z ∈ RN ,  + z = R}  inf{I (x) : x ∈ H , x = r}.

Hence the conditions of the linking theorem are satisfied. Consequently, I has a non-constant
critical point in HT1 which is a solution of (P).
Case 2: Without loss of generality, we assume that:
 > r, a2 > a1 : V (z)  a1 |z| + a2 |z|2 for all z ∈ RN , |z|  R.
1. There exists R 
 2
¯ 2 /(2) ˜ .
2
2. There exists ¯ > 0 : −
¯ I¯ b(t) < 0 and k1 > 
Then, we have

2  T 2
I( + z)  2
− | + z|2 +
|z|
 2
+ 2 2 I 2
   
− a1 ˜ | + z| + V (z) − b(t)
I I¯

2 2 
 2
− 2
+ (T − 2)|z|2
2 + 2 2(2 + 2 ) 2

 
− k1 a1 ˜ 
+ (2)/2 |z| + 
¯ a1 |z| + 
¯ a2 |z|2
( 2
+ 2 )/2

22 − 2 1
 2
+ (T − 2 + 2
¯ a2 )|z|2
2( 2
+ 2 ) 2

˜ 
k1  
− a1 
− a1 [k1 ˜ (2)/2 − 
¯ ]|z|
(2 + 2 )/2

 D1 2
+ D2 |z|2 − D3  − D4 |z| ,

where D1 , D2 , D3 , D4 ∈ R+ .

 + z2 = 2
+ T |z|2 for all  0, z ∈ RN .

Thus, as  + z → +∞, I ( + z) → −∞.


Therefore, we can find R > r (sufficiently large) such that

I( + z) < 0 for all + z ∈ H̄ :  + z = R.

This verifies the Linking theorem and hence completes proof of Theorem 2.4. 
574 L.K. Shilgba / Nonlinear Analysis 63 (2005) 565 – 574

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Further reading

[11] M. Degiovani, Basic tools of critical point theory, 2002.


[15] J. Mawhin, M. Willem, Critical Point Theory and Hamiltonian Systems, Springer, New York, 1989.
[16] P.H. Rabinowitz, Periodic solutions of Hamiltonian systems, Comm. Pure. Appl. Math. 31 (1978) 157–184.

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