Name: Max Song
Student Exploration: Advanced Circuits
[Note to teachers and students: This Gizmo was designed as a follow-up to the Gizmo.
                                                                        Circuits
We recommend doing that activity before trying this one.]
Vocabulary: circuit breaker, equivalent resistance,fuse, Ohm’s law, parallel circuit, series circuit
Prior Knowledge Questions (Do these BEFORE using theGizmo.)
                             1.What is the mathematical relationship between current,
                                resistance, and voltage?
                                V=IR
                             2.What is the   equivalent resistance (total resistance)of the
                                series circuit shown at left? 130 ohms
Gizmo Warm-up
In theCircuitsGizmo, you learned how to useOhm’slaw:
I=V/R, to determine the current in parallel andseries
circuits. But how do you find the resistance and current in a
complex circuit that has both series and parallel elements?
First, review how to find the equivalent resistance of a
parallel circuit. Use theAdvanced CircuitsGizmoto
construct the parallel circuit shown at right, using a 10-ohm
and a 20-ohm resistor. Set theSelected battery voltage
to 20 volts.
1.Move theAmmeternext to the battery. What is thecurrent? 3A
2. Based on Ohm’s law, what is the equivalent resistance in the circuit? 6.67 ohms
3. You can calculate the equivalent resistance of a parallel circuit using the following equation:
   Based on this equation, what is the equivalent resistance of the circuit? 6.67 ohms
Activity A:            Get the Gizmo ready:
Solving complex           ●ClickClearto remove all components from the
circuits                   CIRCUIT BOARD.
Introduction:Solving a complex circuit may look difficult,but all you have to do is be patient
and solve one part of the circuit at a time. Use these two rules to find the resistance of a part of
a circuit:
   ● For components connected in series, the equivalent resistance is the sum of the
       resistance of each component:Rt=R1+R2+ … +Rn.
  ● For resistors connected in parallel, use the equivalent resistance equation:
Goal: Determine the resistance and current in a
circuit with parallel and series elements.
1. Calculate: Use the Gizmo to create the circuit
   shown at right. Next, find the equivalent
   resistance of the outlined parallel component of
   the circuit. Show your work. (Hint: The lowest
   common denominator of the three fractions is 60.)
   Equivalent resistance of parallel component: 4.615 ohms
2. Interpret: Now that you found the resistance of theparallel part of the circuit, what do you
   think you will do next?I will find the resistanceof the entire series.
3. Calculate: Add up the resistance of each part of thecircuit to find the equivalent resistance
   of the whole circuit. What do you get? 29.615 ohms
4. Check: Remove the battery from the circuit. Connectthe two parts of theOhmmeterto the
   ends of the circuit, where the battery was attached. What is the resistance? 29.62 ohms
(Activity A continued on next page)
Activity A (continued from previous page)
5. Apply: Remove the ohmmeter and reattach the battery.Set the Selected battery voltage to
   10 volts. What do you expect the total current to be through this circuit? .338 A
    Check your answer by placing theAmmeteron the circuitnear the battery.
6. Analyze: You can use Ohm’s law (I=V/R) to calculatethe current and voltage through each
   component of the circuit. Recall that the current is the same through each series component
   but gets split up in the parallel section of the circuit.
       A.What is the voltage across the first 10-ohm resistor? 3.38 V
       B.What is the voltage across the middle, parallel section of the circuit? 1.56 V
       C.What is the current in each branch of the parallel section?
           Light bulb: 0.104     20-ohm resistor: 0.078     10-ohm resistor: 0.156
       D.What is the voltage across the last 15-ohm light bulb? 5.07 V
   Use theVoltmeterand theAmmeterto check your answers.
7. Practice: ClickClear. Use what
   you have learned to find the
   equivalent resistance of the circuit
   shown at right. Show your work in
   the space below. Use the Gizmo to
   check your answers.
   Equivalent resistance: 19.67 ohms
Activity B:            Get the Gizmo ready:
Fuses                     ● ClickClear.
Introduction:Have you ever touched an incandescentlight bulb that has been on for a while?
Ouch! What you feel is frictional heat produced by the current moving through the light’s resistor.
The high heat produced in electric circuits leads to the danger of electrical fires.
Afuseis a safety device that prevents a circuitfrom overloading and starting a fire. A fuse is
usually a thin piece of metal with low resistance. If too much current flows through the fuse, the
metal melts and the circuit is broken. The blown fuse will have to be replaced before the circuit
can be used again.
Question: How do fuses help to prevent electrical fires?
1. Predict: Build the circuit shown at right, using a0.30 A fuse. Make
   sure the switch is turned off as you build the circuit. Set the
   Selected battery voltageto 10 volts.
        A.Based on the number on the fuse, what do you think is the maximum current allowed
           in this circuit? .3 A
        B.What is the maximum battery voltage you could use in this circuit? 30 V
           (Hint: Use Ohm’s law.) Show your work:
                              V= I*R = 0.30A *100Ohm
2. Check: Click the switch to turn it on, and then graduallyincrease the Selected battery
   voltageto the amount you calculated.
   What is the current reading on theAmmeter? .3 A
3. Test: Increase the voltage so the current exceeds0.30 amps. What happens?
   The fuse burns
4. Calculate: Turn the switch off, replace the blownfuse with a new 0.30 A-fuse, and replace
   the 100-ohm resistor in the circuit with a 20-ohm resistor. Change the battery voltage to 1 V.
   What is the maximum allowed voltage now? 6 V
   Use the Gizmo to test your answer. At what voltage did the fuse blow? 7 V
(Activity B continued on next page)
Activity B (continued from previous page)
5. Apply: Click Clear. Build a parallel circuit as
   shown at right, using a 0.30 A fuse and a
   12-volt battery. Be sure all the switches are
   off before adding the fuse. This circuit is
   similar to what you might find in a house,
   with three appliances connected in parallel
   to a single circuit.
       A.Click the first switch to turn on the
          first appliance.
          What is the total current now? .12 A
       B.Turn on the second switch. What is the total current now? .24 A
       C.What do you think will happen when you turn on the third switch?
               The fuse will blow when the 3rd switch is turned on since the total current will be
.36 A which is greater than .3 A
       D.Turn on the third switch. What happens? The fuse blew
       E.Why might it be a problem if too many large appliances are connected to the same
           parallel circuit? There would be too much current flowing through a single circuit
           which could cause fires and many other problems to the appliances
6. Summarize: In your house, a device called acircuitbreakerserves the same purpose as a
   fuse. When the current exceeds the limit, the circuit breaker trips, stopping the current.
   Unlike a fuse, the circuit breaker does not need to be replaced each time it trips. Instead, it
   can simply be reset.
   Why are fuses and circuit breakers important safety features for any circuit?
   They prevent electrical fires by limiting the current that flows through a circuit.