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Material Properties:: Design of Concrete Beam

The document outlines the design specifications for a 3-storey commercial building's concrete beam, including material properties, dimensions, and reinforcement details. It provides stress results, calculations for flexural reinforcement, stirrups, torsion, and crack control, confirming that the beam design is adequate and meets safety standards. The analysis indicates that the beam is not cracking and adheres to specified guidelines for structural integrity.
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0% found this document useful (0 votes)
29 views1 page

Material Properties:: Design of Concrete Beam

The document outlines the design specifications for a 3-storey commercial building's concrete beam, including material properties, dimensions, and reinforcement details. It provides stress results, calculations for flexural reinforcement, stirrups, torsion, and crack control, confirming that the beam design is adequate and meets safety standards. The analysis indicates that the beam is not cracking and adheres to specified guidelines for structural integrity.
Copyright
© © All Rights Reserved
We take content rights seriously. If you suspect this is your content, claim it here.
Available Formats
Download as PDF, TXT or read online on Scribd
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Project Name: 3-Storey Commercial BLDG Design by:

Owner: Mark: B1
Location: Daan Sarile Cabanatuan City N.E. Date: 06/29/2022
Check by: Mark Christian D. Esguerra

DESIGN OF CONCRETE BEAM Structural Excell Program

Material Properties: Left Mid Right


Concrete f'c = 20.7 MPa
Reinforcing fy = 414 MPa
Stirrup fy = 276 MPa

Beam Data
Span type = Simply supported
Span Length = 3.25 m
width, b = 0.2 m
height, h = 0.4 m
flexure bar Ø = 16 mm
shear bar Ø = 10 mm Layer 1 = 3 Layer 1 = 3 Layer 1 = 3
Torsion bar Ø = 16 mm Layer 2 = 0 3 pcs Layer 2 = 0 3 pcs Layer 2 = 0 3 pcs

Top

Top

Top
Layer 3 = 0 Layer 3 = 0 Layer 3 = 0
Stress Result (Any FEA or Frame Analysis)
Ratio = 0 Ratio = 0 Ratio = 0.411
Moment Left Mid Right
Layer 1 = 3 Layer 1 = 3 Layer 1 = 3
TB [kN-m] 0 0 28.44
Layer 2 = 0 3 pcs Layer 2 = 0 3 pcs Layer 2 = 0 3 pcs

Bot

Bot

Bot
BB [kN-m] 0 14.99 0
Layer 3 = 0 Layer 3 = 0 Layer 3 = 0
Left Mid Right Ratio = 0 Ratio = 0.217 Ratio = 0
Shear 16.4 0 28.13 ● Check Minimum Depth of Beam
Torsion 1.57 0 1.57 Depth = 0.2 Depth use is ok Table 9.3.1.1
4xDepth = 1.36 Depth use is ok Sec. 18.6.2.1a
ServiceMoment 0 12.13 20.65 Width (200 or 0.3h) = 0.2 Width use is ok Sec. 18.6.2.1b

SUMMARY CALCULATIONS
Design for Flexural Reinforcement Design for Stirrups
Used Maximum Vu = 28.13 kN Legs = 2
Top Moment Left Mid Right
The Beam Section is Adequate
Mu (kN.m) = 0 0 28.44
Distance = @50mm @2●Height
β1 value = 0.85 0.85 0.85
Applied Force, Vu = 26.83 kN 13.62 kN
Remarks = Doubly! Doubly! Doubly! Sec. 9.6.3.1
Concrete Strength, φVc= 38.67 kN 38.67 kN
ρmax = 0.01282 0.01282 0.01282
Concrete Strength, Vs max= 154.69 kN 154.69 kN
ρmin = 0 0 0.00338
Vmax = 193.36 kN 193.36 kN
ρused = 0.00882 0.00882 0.00882
● Compute Area Reinforcement 150 mm
Reduction Fac = 0.9 0.9 0.9
Vs = 0 kN
Neutral Axis = 67.2 67.2 67.2
Vs = 103.13 kN
a= 57.12 57.12 57.12 Table 9.7.6.2.2
Spacing_max = 170 mm Table 9.7.6.2.2
Tensile Strain = 0.0123 0.0123 0.0123
Av_used = 157.08 mm²
ΦMn (kN.m) = 69.14 69.14 69.14
Av/S_req = 0 mm²/m
Av/S_min1 = 204.41 mm²/m
Table 9.6.3.3a
Bot Moment Left Mid Right Av/S_min2 = 253.62 mm²/m
Table 9.6.3.3b
Mu (kN.m) = 0 14.99 0 Av/S_used = 253.62 mm²/m
β1 value = 0.85 0.85 0.85 S_req = 619.34 mm
Remarks = Doubly! Doubly! Doubly! S_used = 100 mm
ρmax = 0.01282 0.01282 0.01282 10mm : 1@50mm 10@100mm 5@150mm REST @ 250mm O.C. TO C.L.
ρmin = 0 0.0025 0
Design for Torsion Reinforcements
ρused = 0.00882 0.00882 0.00882
Tc = 1.52 < 1.57 kN-m, must consider torsion!
Reduction Fac = 0.9 0.9 0.9
Tumax = 7.55 >= Tu = 1.57 kN-m, O.K.
Neutral Axis = 67.2 67.2 67.2
Atprov = 78.54 (Av+t(used)-Av(req'd))/2
a= 57.12 57.12 57.12
Atreq'd = 0.01 <= At(prov) = 78.35 mm², O.K.
Tensile Strain = 0.0123 0.0123 0.0123
Atreq'd = 15.33 <= At(prov) = 78.35 mm², O.K.
ΦMn (kN.m) = 69.14 69.14 69.14
Alreq'd = 0.04 < Al(min) = 294.86 mm², thus use Al(min)
Almin = 294.86 >= Al(req'd) = 0.04 mm², thus use Al(min)
● Check Minimum according to Sec. 18.6.3
a.) 1. Least 2 at both top and bot Alprov = 804.25 add'l web bars are not required!
Total(Av+t)= 0.4 <= Av+t(prov) = 157.08 mm², O.K.
2. Min bar 1 (0.25*√fc)*bd/fy
Total(Av+t)min= 38.04 <= Av+t(prov) = 157.08 mm², O.K.
2 1.4*bd/fy
3. Max bar 9 0.025*bd

b.) Positive moment at joint face shall be at least one half the negative ...

Design for Crack Control Exposure Condition = Dry Air or with Protective Membrane/ Coating
Left Mid Right
Mcr = 15.04 kN-m 15.04 kN-m 15.04 kN-m
Remark = Beam is not cracking! Beam is not cracking! Beam is not cracking!
Crack Width = 0 mm 0 mm 0.005 mm
Table 4.1 = Crack width is ok Crack width is ok Crack width is ok
Table 4.2 = Since dt = 16mm < 32mm, ok! Since dt = 16mm < 32mm, ok! Since dt = 16mm < 32mm, ok!
Table 4.3 = Since S = 100mm < 300mm, ok! Since S = 100mm < 300mm, ok! Since S = 100mm < 300mm, ok!

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