ARP-7

JEE (Main + Adv.) Division

Chemistry

TOPIC COVERED
 Alkyl Halide, Purification

 Solid State

Motion Education, 394 - Rajeev Gandhi Nagar, Kota-5 (Raj.)

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ARP [ALKYL HALIDE,

PURIFICATION]
JEE MAIN TO ADVANCED

SECTION - A
[STRAIGHT OBJECTIVE TYPE]
Q.1 to Q.5 has four choices (A), (B), (C), (D) out of which ONLY ONE is correct & carry 3 marks each. -
1 Negative marking for each wrong Answer.
1. Which of the following reaction follow E1cb mechanism.

alcKOH
(i) CH3  CH  CH2CH3 

CH2  CH  CH2CH3
|
F

CH3

CH3 –N CH– CH3
(ii) OH 

 CH2  CH2 + 3o amine
 t amine
CH2CH3 CH3

alc KOH
(iii) CH3  CH2  Br  CH2  CH2

NaOH
(iv) CH3  CH  CH2  CHO 

 CH3  CH  CH  CHO
|
OH

Select the correct option

(A) All of these (B) ii, iii & iv
(C) ii & iv (D) only iv

2. 
 major product of the reaction is

(A) (B)

(C) (D)

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3. Match the reaction in List-I with the mechanisms and characteristicin List-II
List-I List-II

Me – C – O – CH2 – CH3 
(A) |
| (P) E1
O

OH
|
H
CH3 – C – CH2 – CH3 


(B) | (Q) E2 / E1CB
CH3

Br
(C) | (R) Ei
alc
CH3 – CH2 – CH – CH3 
KOH


F
|
(D) RO– (S) Say0tzeff product
CH3  CH2  CH  CH3 




(T) Hoffmann product

Select the correct option

(A) A-RT, B-PS, C-QS, D-QT (B) A-RT, B-QS, C-QT, D-PS
(C) A-PT, B-QT, C-PS, D-QT (D) A-PS, B-RT, C-QS, D-QT

4. Consider the following reaction sequence

HBr
P Q + R
(C7H 11Br) (opt. active) (opt. inactive)
t-BuOK
O
(i) O3
S 2 +
(ii) Me2S H H O O
Correct option is
(A) (P) is
Br

H
Br
(B) (R) is Br
H

(C) (R) is optically inactive due to external compensation

H2C CH2
(D)(S) is

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5. Match List-I with List-II (no. of isomers produced in  -E2 elimination) and select the correct
answer.
List-I List-II

(a) (i) Four

(b) (ii) Zero

(c) (iii) One

(d) (iv) Three

Select the correct option

(a) (b) (c) (d) (a) (b) (c) (d)
(A) (i) (ii) (iv) (iii) (B) (iv) (iii) (i) (ii)
(C) (iv) (iii) (ii) (i) (D) (i) (iii) (iv) (ii)

[MULTIPLE OBJECTIVE TYPE]

Q.6 to Q.9 has four choices (A), (B), (C), (D) out of which ONE OR MORE THAN ONE is correct & carry
3 marks each.
6. Select the incorrect statement(s) from the following:
(A) Rate of sulphonation of C6H6 & C6D6 will be equal

(B) On treatment of salicylic acid with Br2 / water (in excess) it results in a dibromo product.

(C) When HCOOEt is treated with MeMgBr in excess followed by hydrolysis it will results in the
formation of tertiary alcohol.

(D) Product. Product is enantiomer of the reactant.

7. Which of the following order is/are correct for the rate of E2 reaction ?
(A) 5-Bromocycloheptene > 4-Bromocycloheptene

(B) 2-Bromo-1-phenylbutane > 3-Bromo-1-phenylbutane

(C) 3-Bromocyclohexene > Bromocyclohexane

(D) 3-Bromo-2-methylpentane > 2-Bromo-4-methylpentane

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8. All the possible product of the reaction is/are.

CH 3  CH  CH  CH 2  C  O  H ( i ) AgOH
 Products
|| (ii ) Br2 / CCl 4 ,
O
Br
(A)

(B)
Br

Br
(C)

(D) CH 3  CH  CH  CH 2  C  O  CH 2  CH  CH  CH 3
||
O
9. Which reaction sequence is/are incorrect.

+
NH2 NC¯
(A) CHCl
 3 /
KOH
 H3 O
 

NH2 + HCHO

CH3 CH3 CH3

–
CN HOOC D
(B) H OTs   D CN 
HO
 3


H
D H

–
OCH3
Cl  OCH 3
(C)  Conc.HI
   I + CH3 OH

Ph Ph Ph
H3C Br H3CO CH3 H3C OCH3
(D) CH
3OH

H D H D H D

CH3 CH3 CH3

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[COMPREHENSION TYPE]
Q.10 to Q.13 are based upon a paragraph. Each questions has four choice (A), (B), (C), (D) out of which
ONLY ONE is correct

Paragraph for question nos. 10 to 11

Me
I
(i ) Moist Ag 2 O
Et
 3N
 (P)      ( A) Major  (B)
SN 2 (ii ) 
Hydrocarbo n

O
CH 3–C–OAg , SN2 Ester 
 (C) Major  ( D)
–AgI Hydrocarbo n

10. Hydrocarbon A & the product C is

Me

(A) & Enantiomeric products

(B) & Diastereomeric products

(C) H2C = CH2 & Optically pure product

(D) & Positional isomeric product

11. Which statement is correct about C.

(A) It is and formed by Ei mechanism

Me

(B) It is and formed by Ei mechanism

(C) It is H2C = CH2 and formed by Ei mechanism

(D) It is and formed by E1cb mechanism

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Paragraph for question nos. 12 to 13

Column 1 Column 2 Column 3
(Reactions) (Intermediate/ (Mechanism
Transition state) for Major product)
OH
(I) conc.H SO (i) Carbocation (P) SN1
 24 

Cl
(II) NaNH2 (ii) Carbonanion (Q) SN2

(III)
PCl5 (iii) Alkene like transition state (R) E1
OH
H3O
(IV) O–Me (iv) Trigonal bipyramidal (S) E2

transition state

12. Select the correct combination of reaction which has same mechanism in column 1,2,3 as this
reaction occur.
Cl NaI
Acetone
(A) (I), (i), (P) (B) (II), (ii), (S) (C) (III), (iv), (Q) (D) (IV), (iii), (R)

13. Select the correct combination of reaction which has same mechanism in column 1,2,3 as
following reaction occur.
CH3
Alc. KOH
CH3 – CH
Cl
(A) (I), (i), (Q) (B) (II), (iii), (S) (C) (IV), (ii), (R) (D) (IV), (iv), (P)

[MATCH THE COLUMN TYPE ]

Q.14 to Q. 17 contains 4 multiple choice questions. Each question has matching list. The codes of list
have choices (A), (B), (C) & (D) out of which only & carry 4 marks each. -1 negative marking for
each wrong Answer.
14. Column-I Column-II
CH
Cl 3
HBr
I
(A) (P) I and II are identical
HBr
II
Perdoxide
Anhydrous
I
HI
(B) O conc. (Q) I and II are different
II
HI
O
|| SOCl2
(C) CH3 – C – OH I (R) Mechanism of formation of I & II are same
Red P,Catalytic
II
CH3 Cl2
Na
H OH a Me – Cl I
(D) 14CH Red P MeONa (S) Mechanism of formation of I & II are different
3 b II
II22

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Select the correct option below

(A) (A) R,S; (B) P; (C) P,R; (D) P,Q
(B) (A) P,S; (B) Q,R; (C) R,S; (D) P,Q
(C) (A) Q,S; (B) P,S; (C) Q,S; (D) P,R
(D) (A) Q,S; (B) P,R; (C) P,R; (D) Q,S

15. Column I Column II

Cl

(A) (P) Product of both SN1 & SN2 reaction are same

(B) (Q) Can give ppt. of AgCl with alcoholic AgNO3

Cl
Cl
(C) (R) Gives SN1 reaction most readily

Cl
(D) (S) Can give Belstein's test

16. Match List I with List II:

List I (Mixture) List II (Separation Technique)
A. CHCl3 + C6H5NH2 I. Steam distillation
B. C6H14 + C5H12 II. Differential extraction
C. C6H5NH2 + H2O III. Distillation
D. Organic compound in H2O IV. Fractional distillation
Select the correct option
(A) A-IV, B-I, C-III, D-II (B) A-III, B-IV, C-I, D-II
(C) A-III, B-I, C-IV, D-II (D) A-II, B-I, C-III, D-IV

17. Match items of column I and II

Column I Column II
(Mixture of compounds) (Separation Technique)
A. H2O/CH2Cl2 i. Crystallization
O OH
ii. Differential solvent
B. extraction

NO2

C. Kerosene / Naphthalene iii. Column

chromatography

D.C6H12O6/NaCl iv. Fractional Distillation

Select the correct option
(A) A-(ii), B-(iii), C-(iv), D-(i) (B) A-(i), B-(iii), C-(ii), D-(iv)
(C) A-(ii), B-(iv), C-(i), D-(iii) (D) A-(iii), B-(iv), C-(ii), D-(i)

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SECTION - B
[NUMERIC VALUE TYPE]
Q.18 to Q.21 are NUMERIC VALUE TYPE Questions. (The answer of each of the questions is carry 5
marks each.
18. Consider following compounds.
Br Br
I
Br NH Br
O Br
CH3
CH2 – Br

H3 C – Br O
Br
Br OCH3
Cl
Number of compounds which are more reactive than for SN1 mechanism are ________.

Cl

O Ag(NH ) HO end product
19. Me 3N
 moist
 Ag2O
      
3 3 2
  Zn  H O 2

What is the molecular weight of end product.

KOH
conc.H 2SO4

20. 
OH
Br

(a) Above reaction can produce how many alkenes.

(b) Out of all the alkenes how many will show geometrical isomerism

(c) Out of all the alkenes how many will show optical isomerism.

(d) How many organic products are obtained when major product of above reaction is treated with
N2H4 / H2O2.

Write answer of part (a), (b), (c) & (d) in the order V X Y Z and present the four digit
number as answer. For example : If all these answer are 9 then write 9999.

(1) + H2 SO4

21. (2) Ni + H2 (ex)

(3) Cl 2 + hv

How many monochloroderivative are possible of end product ?

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ARP [SOLID STATE]

JEE MAIN TO ADVANCED

SECTION - A
[STRAIGHT OBJECTIVE TYPE]
Q.1 to Q.6 has four choices (A), (B), (C), (D) out of which ONLY ONE is correct & carry 3 marks each.
-1 Negative marking for each wrong Answer.
1. Select the correct statement(s) about FCC (ABCAB...) structure.

a
(A) Distance between nearest octahedral void and tetrahedral void is
4

a
(B) Distance between two nearest octahedral void is
2

3a
(C) Distance between two nearest tetrahedral void is
2

2
(D) Distance between layer A and B is 2r
3

2. 4.2 gm of carbonate of an alkaline earth metal is dissolved in excess of HCl solution by which 1.12
L CO2 gas (measured at 273 K and 1 atm) is evolved. If the pure metal crystallises as BCC crystal,
then the only correct statement regarding the metal is [NA = 6 × 1023]
(A) The metal is calcium
(B) There are 3×1022 unit cell in 1.2 gm metal.
(C) The density of metal is 1.25 gm/cm3, if the edge-length of unit cell is 4Å.
(D) The metal forms amphoteric oxide.

3. In a fcc crystal, calculate fraction of body diagonal unoccupied if all its tetrahedral & octahedral
voids are occupied without causing any distortion in the cube.
(A) 0 (B) 0.24 (C) 0.36 (D) 0.48

4. The minimum inter-nuclear distance between carbon atoms in diamond is 150 pm. The density of
diamond is [NA = 6 × 1023]

20 20 20 10 3
(A) gm/cm3 (B) gm/cm3 (C) gm/cm3 (D) gm/cm3
3 3 3 9 3 9

5. If all atoms along a body diagonal length are absent then Packing fraction of diamond (Assume
closest packing) is :

5 3 9 3 5 3 27 3
(A) (B) (C)  (D)
512 512 512 512

6. An ionic solid 'AB' (Mw = 120 g/mol) has NaCl type structure. The shortest distance between cation
and anion is 500 pm. If there is a schottky defect of 2% then the density of crystal in g / cm3 will
be :
(NA = 6 × 1023)
(A) 0.80 (B) 0.784 (C) 0.016 (D) None of these

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[MULTIPLE OBJECTIVE TYPE]

Q.7 to Q.8 has four choices (A), (B), (C), (D) out of which ONE OR MORE THAN ONE is correct & carry
3 marks each.
7. 80.0 gm salt of weak base & strong acid XY is dissolved in water and formed 2 litre of aqueous
solution. The pH of the resultant solution was found to be 5 at 298 K. If XY forms CsCl type crystal

having rX  (radius of X+) = 1.6 Å & rY – (radius of Y¯) = 1.864 Å then select write statement(s).
(Given : Kb (XOH) = 4 × 10–5 ; NA = 6 × 1023)
(A) Molar mass of salt is 100 g/mol

(B) % Degree of dissociation of salt is 0.25

(C) Edge length of AB is 4Å

(D) Density of solid salt XY is 2 in gm/cc

8. Select the correct statements among following :

a
(A) Nearest neighbour distance in NaCl =
2

3a
(B) Nearest neighbour distance in CaF2 =
4

3a
(C) Nearest neighbour distance in Na2O =
4

3a
(D) Nearest neighbour distance in CsCl =
2
[COMPREHENSION TYPE]
Q.9 to Q.10 are based upon a paragraph. Each questions has four choice (A), (B), (C), (D) out of which
ONLY ONE is correct
Paragraph for question nos. 9 to 10
An ideal solution is prepared at 25°C by dissolving 0.4 kg of solid AB (having rock-salt structure,
B– ions at corner) and 5 moles liquid 'A' in 20 moles liquid 'B'. The solid is nonvolatile and nonelec-
trolyte in the solution. At 25°C, The vapour pressures of pure liquids 'A' and 'B' are 100 torr and
200 torr respectively and the vapour pressure of solution is 150 torr. The shortest distance be-
tween two A+ ions in the solid is 200 2 pm.(NA = 6 × 1023)
9. The molar mass of solid AB is :
(A) 100 gm/mol (B) 80 gm/mol
(C) 40 gm/mol (D) 160 gm/mol

10. The density of solid AB is :

25 50
(A) gm/cm3 (B) gm/cm3
3 3
25 25
(C) gm/cm3 (D) gm/cm3
6 8

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[MATCH THE COLUMN TYPE ]

Q.11 contains 4 multiple choice questions. Each question has matching list. The codes of list have
choices (A), (B), (C) & (D) out of which only & carry 4 marks each. -1 negative marking for each
wrong Answer.
11. Column I Column II
(A) ZnS (zinc blende) (p) fcc

(B) CaF2 crystal (q) hcp

3
(C) NaCl crystal (r) Distance between closest particles is a.
4

(D) Diamond crystal (s) Only one type of voids are occupied

SECTION - B
[NUMERIC VALUE TYPE]
Q.12 to Q.18 are NUMERIC VALUE TYPE Questions. (The answer of each of the questions is carry 5
marks each.

12. A metal M has an atomic mass of 60. If atomic radius of metal is 7.5 3 Å & density of

1
metal = gm/ml then what will be the edge length of the cubic crystal unit cell obtained using
135
metal M.
Express answer in nm. [NA = 6 × 1023]

13. An element X (atomic wt. =125) crystallises is simple cubic structure. If diameter of the largest
atom which can be placed without disturbing unit cell is 366 pm. Find the density of pure element
X in gm/cm3.
[Given : 3  1.732 , NA = 6 × 1023 ]
[Fill your answer by multiplying it with 300.]

14. The structure of diamond and silicon is same and can be described as atoms taking corners and
faces of a cube and also taking positions of alternate tetrahedral voids. What is the value of

 density (diamond ) 
 density (silicon )  100 .
 

At. mass (g / mol) Covalent Bond Length ( Å)

Carbon :12 C – C  1.50
Silicon : 28 Si – Si  2.25

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15. A metal 'M' having atomic mass 31.25 crystallizes in cubic close packing and it shows "Schottky
defects". If the edge length of the cubic lattice is 500 pm and density of the metal is 1.6075 gm/
ml then calculate number of moles of metal atom 'M' missing per litre of the crystal.
Given : 1amu = 1.67 × 10–24 gm

16. A metal 'A' exists in the bcc structure having uncovered length between the atoms along the edge
equal to 1.2 Å. If molar mass of the metal is 307.2 gm/mole then calculate density of the crystal
in gm/ml.
[Use : NA = 6 × 1023 and 3 = 1.7]

17. 21.4 mg of salt XCl is completely dissolved in some amount of water to form 2 litre of a solution.
If pH of the solution is observed to be 5 & the salt in solid state forms rock salt structure with ionic
radii of X+ = 0.8Å & Cl¯ = 1.7 Å then calculate density of the solid crystal in terms of gm/cm3.
[Divide your answer by 10 & give answer in nearest integer]
[Data : NA = 6 × 1023, Kb (XOH) = 10–9]

18. An ideal ionic crystal is having rock salt structure (A+B¯) such that A+ is occupying octahedral
void. The crystal is doped with atoms of C which occupy all the tetrahedral voids without distorting
the lattice. If the crystal shows defect such that the body centered atom is missing then calculate

fraction of body diagonal covered by species in the defective crystal. [Use : 1.5  1.2 ]
[Express your answer by multiplying the fraction by 10]

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ALKYL HALIDE, PURIFICATION

1. D 2. B 3. A 4. A 5. B

6. ABCD 7. BCD 8. ABCD 9. ABC 10. C

11. B 12. C 13. B 14. C

15. (A) S (B) P,Q,S (C) Q,R,S (D) Q,S 16. B 17. A

18. 5 19. 146 20. 6222 21. 14

SOLID STATE

1. D 2. C 3. B 4. B 5. D

6. B 7. AC 8. ABCD 9. B 10. A

11. (A - p,r,s); (B - p,r,s); (C - p,s); (D - p,r,s) 12. 3 13. 500

14. 145 15.  16. 2 17. 3 18. 6

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“ANALYZE past trends to estimate your FUTURE RANK!”

"JEE Advanced RANK vs MARKS (Last 8 Years)"
JEE ADVANCED-RANKS VS MARKS (%) ANALYSIS- PAST 8 YEARS
2024(360) 2023 (360) 2022 (360) 2021 (360)
Rank Mraks % Rank Mraks % Rank Mraks % Rank Mraks %
1 355 98.61% 1 341 94.72% 1 314 87.22% 1 348 96.67%
101 300 83.33% 101 284 78.89% 101 236 65.56% 101 285 79.17%
501 258 71.67% 501 242 67.22% 501 192 53.33% 501 237 65.83%
1001 233 64.72% 1001 219 60.83% 1001 170 47.22% 1001 212 58.89%
2001 207 57.50% 2001 191 53.06% 2001 146 40.56% 2001 186 51.67%
3001 192 53.33% 3001 174 48.33% 3001 132 36.67% 3001 168 46.67%
4001 181 50.28% 4001 162 45.00% 4001 122 33.89% 4001 155 43.06%
5001 172 47.78% 5001 153 42.50% 5001 115 31.94% 5001 145 40.28%
6001 165 45.83% 6001 146 40.56% 6001 109 30.28% 6001 136 37.78%
7001 159 44.17% 7001 140 38.89% 7001 104 28.89% 7001 130 36.11%
8001 154 42.78% 8001 134 37.22% 8001 100 27.78% 8001 123 34.17%
9001 149 41.39% 9001 130 36.11% 9001 96 26.67% 9001 118 32.78%
10001 146 40.56% 10001 125 34.72% 10001 92 25.56% 10001 113 31.39%
2020 (396) 2019 (372) 2018 (360) 2017 (366)
Rank Mraks % Rank Mraks % Rank Mraks % Rank Mraks %
1 352 88.89% 1 346 93.01% 1 337 93.61% 1 339 92.62%
101 279 70.45% 101 270 72.58% 101 272 75.56% 101 305 83.33%
501 235 59.34% 501 227 61.02% 501 233 64.72% 501 279 76.23%
1001 210 53.03% 1001 206 55.38% 1001 213 59.17% 1001 264 72.13%
2001 184 46.46% 2001 186 50.00% 2001 191 53.06% 2001 244 66.67%
3001 168 42.42% 3001 174 46.77% 3001 177 49.17% 3001 231 63.11%
4001 156 39.39% 4001 164 44.09% 4001 167 46.39% 4001 219 59.84%
5001 147 37.12% 5001 157 42.20% 5001 158 43.89% 5001 211 57.65%
6001 139 35.10% 6001 150 40.32% 6001 151 41.94% 6001 204 55.74%
7001 138 33.59% 7001 144 38.71% 7001 145 40.28% 7001 197 53.83%
8001 127 32.07% 8001 139 37.37% 8001 139 38.61% 8001 191 52.19%
9001 122 30.81% 9001 135 36.29% 9001 135 37.50% 9001 186 50.82%
10001 118 29.80% 10001 131 35.22% 10001 130 36.11% 10001 182 49.73%

Motion Education | 394 - Rajeev Gandhi Nagar | : 1800-212-1799 | url : www.motion.ac.in | Page No. # 16