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The document consists of a series of questions and answers related to the concepts of Raoult's law, ideal and non-ideal solutions, and azeotropes in chemistry. It includes multiple-choice questions, assertions with reasoning, and definitions, focusing on the behavior of liquid mixtures and their vapor pressures. The content is structured for educational purposes, likely for exam preparation in a chemistry curriculum.
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1 Mark Questions
Multiple Choice Questions
yo Ti iting point
tropic mixture of two liquids has a boiling
tater tha either ofthe two Tiquids when it CRSE 2023
(@) shows large negative deviation from Raoult’ law
(b)shows no deviation from Raoutt’s law
(6) shows large positive deviation from Raoult's law
(@obeys Raoult's law
2. 1 mole of liquid A and 2 moles of liquid B make a
solution having a total vapour pressure 40 torr. The
vapour pressure of pure A and pure B are 45 torr and
30 torr respectively. The above solution CBSE 2023
(a) is an ideal solution
() shows positive deviation
(©) shows negative deviation
(@ is a maximum boiling azeotrope
3. Identify the law which is stated as
(CBSE SQP 2021-22 (Term-t)
“For any solution, the partial vapour pressure of each
‘volatile component is directly proportional to its mole
fraction."
(a) Henry's law
(©) Dalton's law
(&) Raoult's law
(@) Gay-Lussac’s law
4, An azeotropic solution of two liquids has a boiling
point higher than either of the two when, it
(CBSE 2021-22 (Term:
(a) shows a negative deviation from Raoult's law
(b) shows a positive deviation from Raoult's law
(©)is saturated
(d) shows no deviation from Raoult's law
5. When | mole of benzene is mixed with I mole of
toluene. The vapours will contain (Given : Vapour of
benzene = 12.8 kPa and vapour pressure of toluene
=3.85 kPa). CBSE SQP 2021
(@) equal amount of benzene and toluene as it forms an
ideal solution
(b)unequal amount of benzene and toluene as it forms a
non-ideal solution
(higher percentage of benzene
(@)higher percentage of toluene
Assertion-Reason
6. Assertion (A) Nitric acid and water form, maximum
boiling azeotrope, CBSE SQP 2021,
13, Define azeotropes,
Reason (R) Azcotropes are binary mixture havi
same composition in liquid and vapour phase.
(a) Both (A) and (R) are correct and (R) is the correct
explanation of (A).
(b) Both (A) and (R) are correct but (R) is not the correct
‘ing the
explanation of (A).
(©) (A) is correct and (R) is incorrect.
(@) (A) is incorrect and (R) is correct.
Very Short Questions
7. Define an ideal solution and write one of
characteristics. CBSE 2024, 2014
Or Define ideal solution. Ail India 2013, 2012; Del
i 2010C
8. Some liquids on mixing form azeotropes. What are
azeotropes? Delhi 2014
Or Define the term azeotrope. All india 2013
9. State Raoult’s law. Foreign 2012
Or Define Raoult’s law in its’ general form in reference to
solutions. Delhi 2011; All India 2011
Or State Raoult’s law for a solution of volatile liquids.
Delhi 2010¢
2 Marks Questions
10. What type of deviation from Raoult's law is shown by
a
ture of ethanol and acetone ? Give reason.
‘CBSE 2024, 2023
11. The vapour pressure of pure liquid X’ and pure liquid Y
at 25°C are 120 mm Hg and 160 mm Hg respectively. If
equal moles of X and Y are mixed to form an ideal
solution, calculate the vapour pressure of the solution.
CBSE 2023
12. On mixing liquid X and liquid Y, volume of the
resulting solution decreases. What type of deviation
from Raoult’s law is shown by the resulting solution ?
‘What change in temperature would you observe after
mixing liquids X and ¥? CBSE 2023
What type of azeotrope is formed
ion from Raoult’s law? Give an
Foreign 2015, 2023
Or Define azeotropes. What type of azeotrope is formed
by positive deviation from Raoult’s law? Give an
example, Delhi 2015
by negative deviati
example,solutions
14 State Raoul’s law fora solution containing volatile
components: What is the similarity between Raoult’
y's law? Dethi 2020, Dethi 2014
45, What type of azcotropic mixture will be formed by a
solution of acetone and chloroform? Justify on the
basis of strength of intermolecular interactions that
develop in the solution, ‘All india 2019
46, State Raoult’s law for a solution containing
volatile components, Write two characteristics
of the solution which obeys Raoult’s law at all
concentrations. Delhi 2019
417, Write two differences between an i i
non-ideal solution. Reeere tana
48, Why a mixture of carbon disulphid tone st
positive deviation from Raoult’ Taw? What ype .
azeotrope is formed by this mixture? CBSE 2018 ¢
419, Define the following.
(Ideal solution
i) Molarity (4) Dethi 2017
20. (i) Gas (A) is more soluble in water than gas (B) at
the same temperature. Which one of the two gases
will have the higher value of Ky, (Henry's
constant) and why?
(ii) In non-ideal solution, what type of deviation
shows the formation of maximum boiling
azeotropes? All India 2016
21, What is meant by negative deviation from Raoult’s
law? Give an example. What is the sign of A pax 7 for
negative deviation? Foreign 2015
22, What is meant by positive deviation from Raoult’s
law? Give an example. What is the sign of A yay 1 for
positive deviation? Dethi 2015
23, Non-ideal solutions exhibit either positive or negative
deviations from Raoult’s law. What are these deviations
and why are they caused? Explain with one example for each
type. "Al India 2011, 2010; Delhi 2010; Foreign 2010
24, State Raoult’s law for a solution containing volatile
components. How does Raoult’s law become a special
cease of Henry's law? All india 2013
25. Explain why a solution of chloroform and acetone shows
negative deviation from Raoult’s law? ———_Dethi 2011
3 Marks Question
26, The vapour pressure of pure liquids A and B are 450
mm and 700 mm of Hg respectively at 350K. Find out
the composition of the liquid mixture if total vapour
pressure is 600 mm of Hg. Also, find the composition
in the vapour phase. {At india 20136
5 Marks Question
27. (i) What type of deviation from Raoult's law is
expected when phenol and aniline are mixed with
‘each other? What change in the net volume of the
mixture is expected? Graphically represent the
deviation.
(i) The vapour pressure of pure water at a certain
temperature is 23.80 mm Hg. If | mole of a
non-volatile non-electrolytic solute is dissolved in
100 g water, calculate the resultant vapour pressure
of the solution. ese Sar 2024
4. (a) Shows large negative deviation from Raoutt's law.
1
2. (c) The mole fraction of ACY 4)= 755-053
2 0.66
Mole fraction of BG 2)
3
ita + Poke
(45 x0.03) +30% 0.66
33 +19.8= 21.13 torr
Pr=
But the total pressure py=30 torr
pr (caleulated) < pr (given)
Thus, it shows negative deviation.
3. (b) Given law is Raoult’s law. According to the
statement,
PEL
p°= partial vapour pressure of component in pure state.
4. (a) The solution which shows a large negative
deviation from Raoult’s law has lower vapour pressure
of each component than the predicted vapour pressure.
‘Also, the total vapour pressure of solution is lower than
the total vapour pressure of ideal solution. Hence, theye moos se scantsty
two liquids boils at a higher 12, On mixing liquids X and Y, the volume of
resulting solution decreases means itis negative
deviation from Raoult's law.
In this case, the temperature of the solution.
tropic mixture of
fenparttze than cither of them,
is with | mole of
‘hen 1 male of benzene is mixed with
Seance vapours wll contain higher percentage of fie co te team
Vapo sssure of benzene is greater than Is a
rere of te 13, Azcotropes Refer to solution 8. "
a, ‘ is Azeotropes showing negative de fr "
; he solution majorly consist of zeotropes showing negative deviation from Rao
Soe eae ane law form maximum boiling zeotropes ata speci *
palais composition. e.g, Azeotrope formed from nitric ns
6. (b) Nitric acid and water form maximum boiling, rae aaa 8 Pe tic acid
azeotropes This solution shows large negative Azstopes shoving postv eit fom Ray
— Jaw form minimum boiling azeotropes at a specific
Thus, both (A) and (R) are correct and (R) is not the composition, e.g, Ethanolewater mittee.
Saale 14, Refer to text on page 7.
15, The mixture of acetone and chloroform is an example
of maximum boiling azeotrope. It shows negative
deviation from Raoult’s law because of increas
increases
0
7. The solutions which obey Raoult’s law over the entire
range of concentration are known as ideal solutions.
For ideal solutions, AH (mixing) =Oand AV (mixing)
=0, e.g. solution of n-hexane and mheptane, intermolecular forces of attraction between acetone
bromoethane and chlorocthane, etc. and chloroform, since they form hydrogen bonds
In these solutions (binary solutions), A—B_ type (ie. between them.
solut-solvent) interactions are nearly equal o the Rei :
. Raoull’s law states that, “at a given temperature,
4—A (solute-solute) and B—B type ne een si per
: for a solution of volatile liquids, the partial vapour
. (solvent-solvent) interactions. pressure of each component of the solution is directly
8. Azeotropes are binary mixtures having the same proportional to its mole fraction present in the
composition in liquid and vapour phase and boil at solution”,
constant temperatures,
@
The solutions which obey Raoult’s law over the entire
9. Raoult’s law For a solution of volatile liquids, the Tange of concentration are known as ideal solutions. (1)
Partial vapour pressure of each component of the The important properties of these solutions are
solution is directly proportional to its mole fraction
present in solution. Thus, for any component, partial * the enthalpy of mixing of pure components to form
ba ao the solution is zero, ie. A nig H
pet 2+ pay * the volume of mixing is also zero, ie. A mi,¥ =0. (1)
where, p°is the vapour pressure of pure component 17. —_____
and 7 is the mole fraction of that component. Heal sotation aca soit
10. The mixture of ethanol and acetone shows positive ces ofthis The components ofthis e
deviation from Raoult's law. As in ethanol the Taw ataltenperatuce eqn ion noob Rac
imolecules are hydrogen bonded and concentration, pegave devas fos
Thus, when acetone is added then its molecule get in Raoult’ aw.
between the molecule of ethanol by breaking the ie. Pa # PLA
hydrogen bonds, WP #73 o
iy droge a aetes_
11. Given, vapour pressure of pure liquid X = 120 mm Hg (On mixing, there is no On mixing, there is enthalpy
a enthalpy and volume and volume change, ie.
Narita a Y =160 mm Hg. change. hednie =O ApH #0and dpi #0 (0)
foles and Y are equal, And Aix
1 1 — —
Pr =5*1204> x160=60+80 18. Refer to text on page 7, o
=140mm Hg Carbon disulphide and acetone form minimum boiling
azeotropes, oSolutions
19. (i) Ideal solution Refer to solution 7, o
Gi) Molarity (Af) Molarity is defined as the number of
moles of solute dissolved in one litre or one cubic
decimetre of the solution.
Moles of solute
Volume of solution in Titres
€-8. 0.25 mol L~ (or 0.25 M) soluti
. ion of NaOH
means that 0.25 mole of NaOH has been dissolved
in one litre (or one cubic decimetre) of solution. (1)
20. Solubility is inversely proportional i i
See amversely proportional to Ky, i Henry's
(@ Greater the value of Ky, lower is the solubility of
the gas. As gas (4) is more soluble in water than
gas (B) at the same temperature, hence the gas (A)
has lower value of Ky. In other words, gas (B) has
higher value of Ky, than gas (4) at the same
temperature. o
Gi) In non-ideal solutions, the solutions that show
Motatity =
large negative deviation from Raoult’s law form
maximum boiling azeotropes. e.g. Mixture of
nitric acid and water. o
21, Negative deviation Refer to sol. 23. o
The plot showing negative deviatior
Vapour pressure of solution
Vapour —+
preseure
noe0. Nolo tigcion t=!
mie 2-0
plot for nomial soko showing negthe devon «t)
22. Positive deviation Refer to sol. 23. w
‘The plot for non-ideal solution showing positive
deviation is
Vapour pressure of solution
popitP2
Pt for non-idea! solution showing positive deviation (4)
23, For non-ideal solutions, vapour pressure is either
higher or lower than that predicted by Raoult’s law. If
it is higher, the solution exhibits positive deviation and
if itis lower, it exhibits negative deviation from
Raoult’s law.
In case of positive deviation, A—B interactions are
weaker than A—A and B—B interactions. Due to this,
‘vapour pressure inereases which results in positive
deviation,
e.g. Ethanol ~ Acetone and Carbon disulphide —
Acetone show positive deviation.
For positive deviation, AH (mixing) = Positive
In case of negative deviation, A—B interactions are
stronger than A—A and B—B interactions. Due to
this, vapour pressure decreases which results in
negative deviation.
e.g. Phenol + Aniline and Chloroform + Acetone show
negative deviation.
For negative deviation, AM (iit
24, Raoult’s law Refer to solution 14. o
Raoult’s law as a special case of Henry’s law In the
solution of a gas in a liquid, one of the components
is so volatile that it exists as a gas and its
solubility is given by Henry’s law, which states that,
paKyh.
partial pressure of the volatile component (gas) is,
directly proportional to the mole fraction of that
component (gas) in the solution.
‘When the equations of Raoult’s law and Henry's law
are compared, it can be seen that the partial pressure of
the volatile component or gas is directly proportional
to its mole fraction in solution. Only the
proportionality constant K,, differs from p®
Hence, Raoult’s law and Henry's law has been
{identical except that their proportionality constants are
different.
Therefore, Raoult’s law becomes a special case of
Henry’s law in which Ky, becomes equal to vapour
pressure of pure component p®. w
25. Negative deviation means A—B interactions are
stronger than A—A and B—B interactions.
‘A mixture of chloroform and acetone forms a solution
which shows negative deviation from Raoult’s law
because chloroform molecule forms H-bonding with
acetone molecule.
ing) =Negative12>
26.
is chloroform and solvent is acetone. Asa
Heres ig nteractons becomes stronger than
A—Aand B—B interactions, This decreases the
Excaning tendency of molecules for each component
‘which leads to the decrease in vapour pressure and
Tesulting in negative deviation from Raoult’s law.
5
HCL we
* Sto. HC ge
HC i, ae
SC doen toning
Given, p? = 450mm of Hg
pep =700 mm of Hg ; Pita: =600mm of Hex « =?
According to Raoult’s law,
Parta* Pa
Pa =Xe* Pe =O-2a)PS
Prat = Pa * Pa =Ka* PULA Ps
Pat(P'4- P's ha wo
(On substituting the given values into the above
equation, we get
600 = 700+ (450-700), ,
100=250%, => %4 = 040
Thus, the composition of the liquid mixture will be
2X4 =040
Xp =1-040=060 o
Calculation of composition in the vapour phase,
Pa =%4% p% =040% 450 mm of Hg
=180mm of Hg
060 700 mm of Hg
= 420mm of Hg
Mole fraction of 4 in the vapour phase
Pa
Pa*Po
__180
“180+ 420
Pe =XeP
27. (i) The negative deviation is expected when phenol
vw
____— Chopterwise CBSE Question Bonk: CHEMISty
Mole fraction of & in the vapour phase
=1-030=070
7
and aniline are mixed with each other. The net
volume of the mixture will decrease, (AV =0) dye
to stronger intermolecular interactions,
'P.1.dlagram for solutions showing negate
deviation from Raoutt's low
a»
Gi) Vapour pressure of pure water =2380 mmHg
Amount of non-volatile electrolyte solute =1 mol
Amount of water = 100g
‘We know, relative lowering of vapour pressure
°—p)
=P wy =
P *
and =n, =01
nm, =100/18=555
i #4
fe ] mtn
OL
=—— =0018
365,
p°=238mmHg
Relative lowering of vapour pressure
23.8-p
= =0018
238
2380- p=0428
p=238-0.428 =2337 mmHg aw