AUDISANKARA COLLEGE

OF
ENGINEERING AND TECHNOLOGY
(AUTONOMOUS)
NH5,BYPASS ROAD,GUDUR.

DEPARTMENT
OF
COMPUTER SCIENCE AND ENGINEERING
LAB MANUAL
OF
C PROGRAMMING LAB
20CS102
 AUDISANKARA COLLEGE
OF
ENGINEERING AND TECHNOLOGY
NH5,BYPASS ROAD,GUDUR.

AUDISANKARA
DEPARTMENT
OF
COMPUTER SCIENCE AND ENGINEERING

C PROGRAMMING LAB
LAB MANUAL

Prepared by: Verified by:

 C PPRRO
OGGR
RAAM
MMMIIN
NGG LLA
ABB

INDEX

S .No Name of the Experiments

1 Programs on Expressions

2 Programs on Operators.

3 Programs on decision control statements

4 Programs on loop statements.

5 Programs on Nested Loops.

6 Programs using arrays.

7 Programs to implement on functions.

8 Programs using recursion.

9 Programs to implement string handling functions.

10 Programs to implement on pointers.

11 Programs to implement on structures.

12 Programs on files.
C PROGRAMMING LAB MANUAL

Exercise-1

1(A).Write a C program to evaluate the algebraic expression (ax+b)/(ax-b)

AIM: To evaluate algebraic exp (ax+b)/(ax-b)

ALGORITHM:
Step1: start

Step2: input a,b,x,s

Step3: s= (a*x+b)/(a*x-b)

Step4: Result s

Step 5: stop

FLOW CHART:
STOP
To evaluate algebraic exp (ax+b)/ (ax-b)

take a,b,x,S

a=5,b=4,x=3

S=(ax+b)/(ax-b)

Display S

STOP
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PROGRAM:
To evaluate algebraic exp(ax+b)/(ax-b)
#include<stdio.h>
#include<conio.h>
void main()

int a,b,x;

float s;

clrscr();

printf("enter the values of a,b,x...");

scanf("%d%d%d",&a,&b,&x);

s=(a*x+b)/(a*x-b);

printf("the value of s=%f",s);

getch();

}
Input & Output:
Enter the values of a,b,x… 2 4 6

The value of s = 2.000000

1(B).Write a C program to evaluate algebraic expression

x power5 +10 x power 4+8 x power3+4x+2

AIM: To evaluate algebraic exp x power5 +10 x power 4+8 x power3+4x+2

ALGORITHM:

Step1: start

Step2: input x,s

Step3: s=pow(x,s)+10*pow(x,4)+8*pow(x,3)+4*x+2

Step4: Result s

Step 5: stop

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FLOWCHART:

To evaluate algebraic exp x power5 +10 x power 4+8 x power3+4x+2

start

take x

x=6

S=pow(x,s)+10*pow(x,4)+8*pow(x,3)+4*x+2

Display S

stop

PROGRAM:

To evaluate algebraic exp x power5 +10 x power 4+8 x power3+4x+2

#include<stdio.h>
#include<math.h>
Void main ()
{
float x,s;
printf("enter the values of x:");
scanf("%f",&x);
s=pow(x,5)+10*pow(x,4)+8*pow(x,3)+4*x+2;
printf("the value of s=%f",s);
getch();
}

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Input & Output:

Enter the values of x:1

The value of s = 25

1(C). Write a C program to Evaluate Area of triangle (sqrt(s(s-a)(s-b)(s-c)))

AIM: To evaluate area of triangle (sqrt(s(s-a)(s-b)(s-c)))

ALGORITHM:

Step1: start

Step2: input a,r,t,s;

Step3 area=sqrt(s*(s-a)*(s-b)*(s-c));
Step4: Result s

Step 5: stop
FLOWCHART:
To evaluate area of triangle (sqrt(s(s-a)(s-b)(s-c)))

Start

take a,b,c,s,a

a=5,b=4,c=2

s=(a+b+c)/2

area=sqrt(s-a)(s-b)(s-c)

Print Area

Stop

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PROGRAM:

To evaluate area of triangle (sqrt(s(s-a)(s-b)(s-c)))

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int a,b,c;
float s,area;
clrscr();
printf("enter the values of a,b,c\n");
scanf("%d%d%d",&a,&b,&c);
s=(a+b+c)/2;
area=sqrt(s*(s-a)*(s-b)*(s-c));
printf("the area of a trangle is =%f",area);
getch();
}

Input & Output:

enter the values of a,b,c
5
6
7
The area of a trangle is = 14.696939

1(D). Write a C program to Swapping of given two numbers

AIM: Program to swap two numbers

ALGORITHM:

Step1: start

Step2: input a,b

Step3: a=a+b

Step4: b=a-b

Step 5: a=a-b

Step6: Result a,b

Step7: stop

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FLOWCHART:
Program to swap two numbers

start

take a,b

a=1,b=10

a=a+b;b=a-b;a=a-b

Print a,b

stop

PROGRAM: Program to swap two numbers

void main()
{
int a,b;
clrscr();
printf("enter the values of a,b\n");
scanf("%d%d",&a,&b);
a=a+b;
b=a-b;
a=a-b;
printf("the values of a,b are: %d %d",a,b);
getch();
}
Input & Output:

Enter the values of a,b

10
20
The values of a, b are: 20 10

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Exercise-2

2(A). Write a C program to Find greatest number in given two numbers

using conditional operator

AIM: Program to find greatest of 2 numbers using conditional operator

ALGORITHM:

Step1: start

Step2: input a,b,c

Step3: c=(a>b)?a:b

Step4: Result c

Step 5: stop

FLOWCHART:

To Find Greatest of Two numbers.

Start

Take a,b

C= (a>b)? a:b

Print c

Stop

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PROGRAM: Program to find greatest of 2 numbers

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int a,b,c;
clrscr();
printf("enter the values of a,b\n");
scanf("%d%d",&a,&b);
c=(a>b)?a:b;
printf("the biggest no is %d",c);
getch();
}

Result:

Enter the values of a,b

5
8
The biggest number is : 8

2(B). Write a program to find greatest among 3 numbers

AIM: Program to find greatest among 3 numbers

ALGORITHM:

Step 1: start

Step 2: input a,b,c

Step 3: if(a>b) &&(a>c)

Step 4: display a is greater

Step 5: else

Step 6: if(b>c)

Step 7: display b is greater

Step 8: else

Step 9: display c is greater

Step10: stop

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FLOWCHART: To find greatest among 3 numbers

Start

Take a,b,c

If
(a>b)&&(a>c)

Display a

If (b>c)

Display b
Display c

Stop

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PROGRAM: Program to find greatest among 3 numbers

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int a,b,c;
clrscr();
printf("enter the values of a,b and c\n");
scanf("%d%d%d",&a,&b,&c);
if(a>b && a>c)
printf("a is greatest of %d %d %d", a,b,c);
else
if(b>c)
printf("b is greatest of %d %d %d",a,b,c);
else
printf("c is greatest of %d %d %d",a,b,c);
getch();
}

Input & Output:

Enter the values of a,b and c

10

30

20

30 is greatest of 10 30 20

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2(C). Write a Program to perform the arithmetic expression using switch

statement

AIM: Program to perform the arithmetic expression using switch statement

ALGORITHM:

Step1: start

Step2: input a,b

Step3: switch(result)

Step4: case 1: print num of a& b is a+b

Step5: case 2: print num of a& b is a-b

Step6: case 3: print num of a& b is a*b

Step7: case 4: print num of a& b is a/b

Step8: case 5: print num of a& b is a%b

Step9: default: invalid option

Step10: stop
PROGRAM: Program to perform the arithmetic expression using switch statement

#include<stdio.h>
#include<conio.h>
void main()
{
int a,b;
int op;
clrscr();
printf(" 1.addition\n 2.subtraction\n 3.multiplication\n 4.division\n");
printf("enter the values of a & b:");
scanf("%d%d",&a,&b);
printf("enter your choice : ");
scanf("%d",&op);
switch(op)
{
case 1:printf("sum of %d and %d=%d",a,b,a+b);
break;
case 2:printf("difference of %d and %d=%d",a,b,a-b);
break;
case 3:printf("multiplication of %d and %d=%d",a,b,a*b);
break;

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case 4:printf("Divisionn of two numbers is %d=",a/b);

break;
default: printf(" Enter Your Correct Choice.");
break;
}
getch();
}

Input & Output:

1. Addition

2. Substraction

3. Multiplication

4. Division

Enter your choice : 1

Enter a and b values 10 20

Sum of 10 and 20 = 30

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Exercise-3
3(A).Write a Program to find the factorial of a given number

AIM: Program to find the factorial of a given number

ALGORITHM:

Step1: start

Step2: input n,i,fact

Step3: fact=i=1

Step4: if(i<=n)

Step5: fact=fact*i

Step6: i=i+1

Step7: repeat from step5 to step6 till steps true

Step8: print fact

Step9: stop

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FLOWCHART:

Program to find the factorial of a given number

Start

Take n

Fact=i=1

If
(i<=n)

fact=fact*i; i=i+1

Display fact

Stop

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PROGRAM:

Program to find the factorial of a given number

// FACTORIAL(using FOR LOOP)

#include<stdio.h>
#include<conio.h>
void main()
{
int n,fact=1,i=1;
clrscr();
printf("Enter a number:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
fact=fact*i;
}
printf("Factorial value of %d is :%d",n,fact);
getch();
}

//FACTORIAL(using WHILE LOOP)

#include<stdio.h>
#include<conio.h>
void main()
{
int i=1,n,fact=1;
clrscr();
printf("Enter a number: ");
scanf("%d",&n);
while(i<=n)
{
fact=fact*i;
i++;
}
printf("Factorial value of %d is :%d",n,fact);
getch();
}

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// FACTORIAL (using DO WHILE LOOP)

#include<stdio.h>
#include<conio.h>
void main()
{
int n,i=1,fact=1;
clrscr();
printf("Enter the value of n:");
scanf("%d",&n);
do
{
fact=fact*i;
i++;
}
while(i<=n);
printf("Factorial value of %d is :%d",n,fact);
getch();
}

Input & Output:

Enter a number :5

Factorial value of 5 is : 120

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3(B). Write a program to generate all prime numbers up to nth number

AIM: Program to generate prime number till nth number

PROGRAM:

Program to generate prime number till nth number

#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,k,r;
clrscr();
printf("enter the range:");
scanf("%d",&r);
for(i=2;i<=r;i++)
{
k=1;
for(j=2;j<=i-1;j++)
{
if(i%j==0)
{
k=0;
}
}
if(k!=0)
printf("%d\n",i);
}
getch();
}
Input & Output:

Enter the range: 10

Prime numbers are
2 3 5 7

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3(C).Write a program to find total of first n natural numbers

AIM: Program to find sum of n natural numbers

Algorithm:

Step1: start
Step2: read n
Step3: i=0,sum=0
Step4: perform from step 5 to step 6 until i<=n
Step5: sum=sum+i;
Step6: i++;
Step7: write sum
Step8: stop

Flow chart: start

Read n

i=0;sum=0

F
While(i<=n)
T

Sum=sum+i;

i++

PRINT sum

stop

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Program:

#include<stdio.h>
#include<conio.h>
void main()
{
int n,i=0,sum=0;
clrscr( );
printf("Enter Limit : ");
scanf("%d",&n);
while(i<=n)
{
sum=sum+i;
i++;
}
printf("Sum of %d natural numbers = %d",n,sum);
getch();
}

Result:
Enter Limit : 10
Sum of 10 natural numbers = 55
OR
Sum of N natural numbers. n*(n+1)/2

#include<stdio.h>
#include<conio.h>
void main()
{
int n,sum=0;
clrscr();
printf("Enter the n value:");
scanf("%d",&n);
sum=n*(n+1)/2;
printf("sum=%d",sum);
getch();
}
Result:
Input & output:
Enter the n value:5
Sum:=15

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Exercise-4
4(A).Write a program to find the given number is Palindrome or not
PROGRAM // Given number is Palindrome or not
#include<stdio.h>
#include<conio.h>
void main()
{
int n,num,s=0,r;
clrscr();
printf("enter n value:");
scanf("%d",&n);
num=n;
while(n!=0)
{
r=n%10;
s=s*10+r;
n=n/10;
}
if(s==num)
{
printf("%d is a palindrome number",num);
}
else
{
printf("%d is not a palindrome number",num);
}
getch();
}
Input & Output:
Enter n value : 121

121 is a Palindrome number.

Enter n value :123

123 is not a palindrome number.

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4(B).Write a program to find the given number is Armstrong or not

PROGRAM // Given number is Armstrong number or not

#include<stdio.h>
#include<conio.h>
void main()
{
int r,n,s,num;
clrscr();
printf("enter n value: ");
scanf("%d",&n);
num=n;
s=0;
do {
r=n%10;
s=s+r*r*r;
n=n/10;
}
while(n!=0);

if(s==num)
{
printf("%d is an armstrong number\n",num);
}
else
{
printf("%d is not an armstrong number",num);
}
getch();
}
Input & Output:
Enter n value : 153

153 is an Armstrong number.

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4(C).Write a program to find Roots of a Quadratic Equation

PROGRAM //ROOTS OF QUADRATIC EQUATION//

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int a,b,c,d;
float x1,x2;
clrscr();
printf("Enter a,b,c values\n");
scanf("%d %d%d",&a,&b,&c);
d=b*b-4*a*c;
if(d<0)
printf("\nroots are imaginary");
else if(d>0)
{
printf("roots are real & un equal\n");
x1=(-b+sqrt(d))/(2*a);
x2=(-b-sqrt(d))/(2*a);
printf("x1=%f\nx2=%f\n",x1,x2);
}
else
{
printf("\nroots are real & equal\n");
x1=x2=-b/(2*a);
printf("x1=%f\nx2=%f\n",x1,x2);
}
getch();
}
Result:
1.Enter a,b,c values: 1 2 3
Roots are imaginary.
2.Enter a,b,c values: 1 2 1
Roots are real & equal. x1=-1.000000 x2=-1.000000

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4(D). Write a program to find the Summation of given Digits

PROGRAM // Summation of digits

#include<stdio.h>
#include<conio.h>
void main()
{
int sum=0,i,t;
long int n;
clrscr();
printf("Enter n value:");
scanf("%ld",&n);
do
{
sum=0;
do
{
t=n%10;
sum=sum+t;
n=n/10;
}while(n>0);
n=SUM;
}while(n>9);
printf("Sum=%d",sum);
getch();
}

Input & Output:

Enter n value:138

Sum=3

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Exercise-5

PROGRAM
5. Write a program to find the Max and Min number by using functions.

#include<stdio.h>
#include<conio.h>
int big(int[],int);
int small(int[],int);
void main()
{
int a[10],i,n,max,min;
clrscr();
printf("Enter size of an array:");
scanf("%d",&n);
printf("Enter the elements:");
for(i=0;i<n;i++)
scanf("%d",&a[i]);
max=big(a,n);
min=small(a,n);
printf("max=%d",max);
printf("min=%d",min);
getch();
}

int big(int a[],int n)

{
int max,i;
max = a[0];
for(i=1;i<n;i++)
{
if(max<a[i])
max=a[i];
}
return max;
}

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int small(int a[],int n)

{
int min,i;
min=a[0];
for(i=1;i<=n;i++)
{
if(min>a[i])
min=a[i];
}
return min;
}

Input & Output:

Enter size of an Array:6

Enter the elements: 55 98 47 21 64 34

Max=98
Min=21

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Exercise-6

6(A).Swapping of two numbers by using call by value

PROGRAM

#include<stdio.h>
#include<conio.h>
void swap(int,int);
void main()
{
int x,y;
clrscr();
printf("enter the values of x, y:\n");
scanf("%d %d",&x,&y);
swap(x,y);
printf("in the main function\n");
printf("x=%d\ny=%d\n",x,y);
getch();
}
void swap (int a,int b)
{
int t;
printf("before swapping\n");
printf("x=a=%d\n",a);
printf("y=b=%d\n",b);
t=a;
a=b;
b=t;
printf("after swapping\n");
printf("x=a=%d\n",a);
printf("y=b=%d\n",b);
}

INPUT AND OUTPUT

Enter the values of x,y:
50
60
before swapping
x=a=50
y=b=60
after swapping

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x=a=60
y=b=50
in the main function
x=50
y=60

6(B). Swapping of two numbers by using call by reference

#include<stdio.h>
#include<conio.h>
void swap(int *,int *);
void main()
{
int x,y;
clrscr();
printf("enter the values of x,y:\n");
scanf("%d %d",&x,&y);
swap(&x,&y);
printf("in the main function\n");
printf("x=%d\n",x);
printf("y=%d\n",y);
getch();
}
void swap (int *a,int *b)
{
int t;
printf("before swapping\n");
printf("x=a=%d\n",*a);
printf("y=b=%d\n",*b);
t=*a;
*a=*b;
*b=t;
printf("after swapping\n");
printf("x=a=%d\n",*a);
printf("y=b=%d\n",*b);
}

INPUT AND OUTPUT

Enter the values of x,y:
50
60
before swapping

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x=a=50
y=b=60
after swapping
x=a=60
y=b=50
in the main function
x=60
y=50

Exercise-7

7(A).Write a program to find the Factorial number by using Recursion.

PROGRAM

#include<stdio.h>
#include<conio.h>
void main()
{
int n,fact;
int fact1(int);
clrscr();
printf("Enter n value:");
scanf("%d",&n);
fact=fact1(n);
printf("Factorial value is:%d",fact);
getch();
}

int fact1(int n)
{
if(n==1 || n==0)
return(1);
else
return n*fact1(n-1);
}

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Input & Output:

Enter n value:5

Factorial value is:120

7(B).Write a program to find the Fibonacci number by using Recursion

PROGRAM

#include<stdio.h>
#include<conio.h>
void main()
{
int n,f;
int fibo(int);
clrscr();
printf("Enter any number:");
scanf("%d",&n);
f=fibo(n);
printf("The %dth fibonoci number is:%d",n,f);
getch();
}

int fibo(int x)
{
if(x==1)
return(0);
else if(x==2)
return(1);
else
return(fibo(x-1)+fibo(x-2));
}

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Input & Output:

Enter any number:8

The 5th Fibonacci number is :13

// Fibonacci series
#include<stdio.h>
#include<conio.h>
void main()
{
int a=0,b=1,n,c,i=2;
clrscr();
printf("enter how many fibonacci numbers u want :");
scanf("%d",&n);
printf("Fibonacci numbers are...");
printf("\n%d %d",a,b);
c=a+b;
do
{
printf("%5d",c);
a=b;
b=c;
c=a+b;
i++;
}while(i<n);
printf("\n");
getch();
}
INPUT AND OUTPUT
Enter how many fibonacci numbers u want :6
Fibonacci numbers are: 0 1 1 2 3 5
Enter how many fibonacci numbers u want :8
Fibonacci numbers are: 0 1 1 2 3 5 8 13
Result:

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Exercise-8
8(A). Matrix Addition
#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
void main()
{
int a[10][10],b[10][10],c[10][10],i,j,m,n,p,q;
clrscr();
printf("enter the 1st matrix size\n");
scanf("%d%d",&m,&n);
printf("enter the 2nd matrix size\n");
scanf("%d%d",&p,&q);
if(m!=p||n!=q)
{
printf("matrix Addition is not possible");
getch();
exit(0);
}
printf("enter 1st matrix elements\n");
for(i=0;i<m;i++)
for(j=0;j<n;j++)
scanf("%d",&a[i][j]);
printf("enter 2nd matrix elements\n");
for(i=0;i<p;i++)
for(j=0;j<q;j++)
scanf("%d",&b[i][j]);
for(i=0;i<m;i++)
for(j=0;j<n;j++)
{
c[i][j]=0;
c[i][j]=a[i][j]+b[i][j];
}
printf("Matrix Addition is:");
for(i=0;i<m;i++)
{
printf("\n");
for(j=0;j<n;j++)
{
printf("%5d\t",c[i][j]);
}

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}
getch();
}
INPUT AND OUTPUT
enter the 1st matrix size
2
2
enter the 2nd matrix size
2
2
enter 1st matrix elements
2
2
2
2
enter 2nd matrix elements
2
2
2
2
Matrix Addition is:
4 4
4 4

8(B). Matrix multiplication

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
void main()
{
int a[10][10],b[10][10],c[10][10],i,j,k,m,n,p,q;
clrscr();
printf("enter the 1st matrix size\n");
scanf("%d%d",&m,&n);
printf("enter the 2nd matrix size\n");
scanf("%d%d",&p,&q);
if(n!=p)
{
printf("matrix multiplication is not possible");
getch();
exit(0);
}

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printf("enter 1st matrix elements\n");

for(i=0;i<m;i++)
for(j=0;j<n;j++)
scanf("%d",&a[i][j]);
printf("enter 2nd matrix elements\n");
for(i=0;i<p;i++)
for(j=0;j<q;j++)
scanf("%d",&b[i][j]);
for(i=0;i<m;i++)
for(j=0;j<q;j++)
{
c[i][j]=0;
for(k=0;k<n;k++)
c[i][j]+=a[i][k]*b[k][j];
}
printf("Matrix Multiplication is:");
for(i=0;i<m;i++)
{
printf("\n");
for(j=0;j<q;j++)
{
printf("%5d\t",c[i][j]);
}
}
getch();
}
INPUT AND OUTPUT
Enter the 1st matrix size : 2 2
Enter the 2nd matrix size : 3 3
Matrix multiplication is not possible.
Case2:
Enter the 1st matrix size : 2 2
Enter the 2nd matrix size : 2 2
Enter the 1st matrix elements: 2 2 2 2
Enter the 2nd matrix elements: 2 2 2 2
Matrix multiplication is :
8 8
8 8

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8(C). Transpose of a matrix

#include <stdio.h>
#include<conio.h>
void main()
{
int a[10][10];
int i, j, m, n;
clrscr();
printf("Enter the order of the matrix \n");
scanf("%d %d", &m, &n);
printf("Enter the elements of the matrix\n");
for(i=0;i<m;i++)
{
for (j=0;j<n;j++)
{
scanf("%d",&a[i][j]);
}
}
printf("The given matrix is \n");
for(i=0;i<m;i++)
{
for(j=0;j<n;j++)
{
printf(" %d", a[i][j]);
}
printf("\n");
}
printf("Transpose of matrix is \n");
for(j=0;j<n;j++)
{
for(i=0;i<m;i++)
{
printf(" %d", a[i][j]);
}
printf("\n");
}
getch();
}

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Input & output:

Enter the order of the matrix :3 3
Enter the elements of the matrix:
1 2 3 4 5 6 7 8 9
The given matrix is
1 2 3
4 5 6
7 8 9
Transpose of the matrix is:
1 4 7
2 5 8
3 6 9

Exercise-9

9(A). Write a program to sort 5 city names in alphabetical order

AIM: Program to read five cities and sort them and print sorted list of
citied in alphabetical order

ALGORITHM:

Step1:start
Step2:enter 5 city names

Step3:take I and j loop variables

For(i=65;i<122;i++)

for(j=0;j<5;j++)

if(city[j][0]==i)

printf(”\n%s”,city[j]);

Step4:stop

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PROGRAM:

A program to read five cities and sort them and print sorted list of citied in
alphabetical order

#include<stdio.h>
#include<conio.h>
void main()
{
char city[5][20];
int i,j;
clrscr();
printf("enter the names of cities...\n");
for(i=0;i<5;i++)
scanf("%s",&city[i]);
printf("\nsorted list of cities...\n\n");
for(i=65;i<122;i++)
{
for(j=0;j<5;j++)
{
if(city[j][0]==i)
printf("\n%s",city[j]);
}
}
getch();
}

Result:

Enter the names of cities…

Hyd
Chennai
Bombay
goa
vizag

Sorted list of cities….

Bombay
Chennai
Goa
Hyd
vizag

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9(B). String operations using built-in (pre-defined) functions

#include<stdio.h>
#include<conio.h>
#include<string.h>
#include<process.h>
void main()
{
int choice,i,j,l;
char s[50],s1[50],ch;
clrscr();
printf("Enter the String:");
gets(s);
do
{
printf("\n MENU");
printf("\n1.Length of the string");
printf("\n2.Reverse of a string");
printf("\n3.Copying of string");
printf("\n4.Comparison of string");
printf("\n5.Concatenation of string");
printf("\n6.Exit");
printf("\nEnter your choice:");
scanf("%d",&choice);
switch(choice)
{
case 1:printf(" The string length is %d",strlen(s));
break;
case 2:printf("Reverse of the string is %s",strrev(s));
break;
case 3:printf("Copied string is %s",strcpy(s1,s));
break;
case 4:printf("Enter the string to be compared:");
scanf("%s",s1);
if(strcmp(s,s1)==0)
printf("The given strings are equal");
else
printf("The given strings are unequal");
break;
case 5:printf("Enter the other string:");
scanf("%s",s1);
printf("The Concatenated string is %s",strcat(s,s1));
break;

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case 6:exit(0);
default:printf("You Entered Wrong choice");
}
printf("\n Do you want to continue(y or n)");
ch=getch();
}
while(ch=='Y'|| ch=='y');
getch();
}

INPUT AND OUTPUT

Enter the String:RAJESH
MENU
1.Length of the string
2.Reverse of a string
3.Copying of string
4.Comparison of string
5.Concatenation of string
6.Exit
Enter your choice:1
The string length is :6

Exercise-10
10(A). // Print Address of a Variable

#include<stdio.h>
#include<conio.h>
void main()
{
int *m,n=20;
clrscr();
m=&n;
printf("Address of n is =%u\n",&n);
printf("value of n is =%d\n",*(&n));
printf("value of m is =%d\n",*m);
printf("address m is =%u\n",&m);
getch();
}

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INPUT AND OUTPUT

Address of n is=65522
value of n is =20
value of m is =20
Address of m is=65524

10(B). // Print the element of array using pointers

#include<stdio.h>
#include<conio.h>
void main()
{
int a[]={20,30,40,50,60};
int i;
clrscr();
for(i=0;i<5;i++)
{
printf("a[%d]=value of address %u=%d\n",i,&a[i],i[a]);
}
printf("Third element value is:%d",a[3]);
getch();
}

INPUT AND OUTPUT

a[0]=value of address 65516=20

a[1]=value of address 65518=30
a[2]=value of address 65520=40
a[3]=value of address 65522=50
a[4]=value of address 65524=60
Third element value is : 50

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Exercise-11

11(A). /* EMPLOYEE RECORD USING STRUCTURES */

#include<stdio.h>
#include<conio.h>
struct emp
{
int dep;
char name[50];
int basic;
}a[10];
void main()
{
float da,hra,pf,sal;
int i,n;
clrscr();
printf("enter how many employees\n");
scanf("%d",&n);
printf("enter deptcode name and basic of employee..\n");
for(i=0;i<n;i++)
{
scanf("%d%s%d",&a[i].dep,a[i].name,&a[i].basic);
}
for(i=0;i<n;i++)
{
da=a[i].basic*0.20;
hra=a[i].basic*0.5;
pf=a[i].basic*0.10;
sal=a[i].basic+da+hra-pf;
printf("\ndept\t name basic \tda \t hra\t pf\t sal\n ");
printf("%d\t%s %d %f %f %f
%f\n",a[i].dep,a[i].name,a[i].basic,da,hra,pf,sal);
}
getch();
}

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INPUT AND OUTPUT

Enter how many employees: 1
enter deptcode name and basic of employee..
10
rajesh
5000
dept name basic da hra pf sal
10 rajesh 5000 1000.000000 2500.000000 500.000000 8000

11(B). // passing Structure as an arguments

#include<stdio.h>
#include<conio.h>
struct student
{
char name[50];
int roll;
};
void Display(struct student stu);
void main()
{
struct student s1;
clrscr();
printf("Enter student's name: ");
scanf("%s",&s1.name);
printf("Enter roll number:");
scanf("%d",&s1.roll);
Display(s1); // passing structure variable s1 as argument
getch();
}
void Display(struct student stu){
printf("Output\nName: %s",stu.name);
printf("\nRoll: %d",stu.roll);
}

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INPUT AND OUTPUT

Enter student's name:RAJESH
Enter roll number:123
OUTPUT:
Name:RAJESH
Roll:123

Exercise-12

12(A). // Write on Data File and Read From Data File

#include<stdio.h>
struct Student
{
int roll;
char name[12];
int percent;
} s1 = { 10, "RAJESH", 80 };
Void main()
{
FILE *fp;
struct Student s2;
//Write details of s1 to file
fp = fopen("ip.txt", "w");
fwrite(&s1, sizeof(s1), 1, fp);
fclose(fp);
fp = fopen("ip.txt", "r");
fread(&s2, sizeof(s2), 1, fp);
fclose(fp);
printf("\nRoll : %d", s2.roll);
printf("\nName : %s", s2.name);
printf("\nPercent : %d", s2.percent);
getch();
}
INPUT AND OUTPUT
Roll :10
Name:RAJESH
Percent:80

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12(B). /* Program to copy the data one file in to another file */

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
void main()
{
FILE *fs,*ft;
char ch;
clrscr();
fs=fopen("raja.txt","r");
if(fs==NULL)
{
printf("file cannot open");
exit(0);
}
ft=fopen("raja1.txt","w");
while(1)
{
ch=fgetc(fs);
if(ch==EOF)
break;
fputc(ch,ft);
}
fclose(ft);
fclose(fs);
}

INPUT AND OUTPUT

Raja.txt
Hai how r u.

Raja1.txt
Hai how r u.

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12(B). COMMAND LINE ARGUMENTS

Write a C Program to print Command line arguments

Aim: To design and develop a C Program to print Command line arguments

Source Code:

/*To Print Command line arguments*/

#include<stdio.h>
#include<conio.h>
void main(int argc,char *argv[])
{
int i;
clrscr();
printf("Display Command line arguments\n");
printf("\n********************************\n");
for(i=0;i<argc;i++)
printf("argv[%d]=%s\n",i,argv[i]);
getch();
}
SYSTEM INPUT AND OUTPUT:
Display Command line arguments
argv[0]=C:\TC\COMMANDL.EXE
argv[1]=welcome
argv[2]=s
argv[3]=50
argv[4]=8.3

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