Minor Test 2 Class 12
Minor Test 2 Class 12
3010CMD303021250008 MD
PHYSICS
1) A body has –80 micro coulomb of charge. Number of additional electrons in it will be :-
(1) 8 × 10–5
(2) 80 × 10–17
(3) 5 × 1014
(4) 1.28 × 10–17
2) Two charge particles are shown in the diagram. Where should a third charge particle q0 be placed
so q0 will be in equilibrium :-
(1) x = 10 a
(2) x = 8 a
(3) x = 11 a
(4) x = 12 a
3) Consider the following charged suspended ball system. If α < β, then the statements which can be
true at equillibrium out of followings are :- (a) Q1 > Q2 , m1 < m2 (b) Q1 > Q2 ,
m 1 > m2
(c) Q1 < Q2 , m1 = m2 (d) Q1 < Q2 , m1 > m2
(1) Only d
(2) Only c
(3) (c, d)
(4) (b, d)
4) Four charges each equal to – Q are placed at the four corners of a square and a charge q at its
centre. If the system is in equilibrium the value of q is :-
(1)
–
(2)
(3)
–
(4)
5) Three point charges lie at the vertices of an equilateral triangle as shown. All three charges have
the same magnitude, but charge A and B are positive and charge C is negative. The net electric force
7) 8 charged drops of mercury each of same radius and surface charge density σ are combined to
form a new drop. The new surface charge density becomes :-
(1) 8 σ
(2) 4 σ
(3) 2 σ
(4) σ
8) In the figure, point A is a distance L away from a point charge Q. Point B is a distance 4L away
from Q. What is the ratio of the electric field at B to that at A, EB/EA?
(1) 1/16
(2) 16
(3) zero
(4) This cannot be determined since neither the value of Q nor the length L is specified.
9) An infinite number of charges, each of charge 1 µC, are placed on the x-axis with co-ordinates x =
1, 2, 4, 8, ...∞. If a charge of 1 C is kept atthe origin, then what is the net force acting on 1 C charge
:-
(1) 9000 N
(2) 12000 N
(3) 24000 N
(4) 36000 N
11) Two point charges are placed at face centre and side centre then flux of cube will be :-
(1)
(2)
(3)
(4)
12)
Five point charges are fixed at their position as shown in figure. The Gauss law is given by
on LHS of above equation will have a contribution from q1, q5, q3 while qnet on RHS will have
(1)
contribution from q1 and q4
on LHS of above equation will have a contribution from all charges while qnet on RHS will have
(2)
contribution from q2 and q4
on LHS of above equation will have a contribution from all charges while qnet on the RHS will
(3)
have a contribution from q1, q3 and q5
(4) Both on LHS and qnet on the RHS will have contribution from q2 and q4 only
13) A point charge is placed at origin. are electric field due to it, at point (2, 0)m and (0,
2)m respectively. Which of the following options is correct ?
(1)
(2)
(3)
(4)
14)
(1) Zero
(2) Non zero
(3) Positive
(4) Negative
15) A sheet of uniform charge density σ is passed through an imginary spherical surface of radius R
(1)
(2)
(3)
(4) zero
16) A charged arc of linear charge density λ has radius a. What will be electric field at centre of arc
:-
(1)
(2)
(3)
(4)
17) Six charges are placed at the vertices of a regular hexagon as shown in the figure. The electric
(1)
(2)
(3) O
(4)
18) The |E|–x graph due to the field of two equal and opposite charges is :
(1)
(2)
(3)
(4)
19) Two uniformly charged rings of radius R and 2R placed coaxially as in figure. If net electric field
at point P, which is x (x <<< R) distance away from common centre O is zero then which is correct
for charge on rings:-
(1) Q1 = –8Q2
(2) Q2 = –8Q1
(3) Q1 = –4Q2
(4) Q2 = –4Q1
20) A prism shaped imaginary structure is given. A point charge is kept as given in figure. Calculate
(1)
(2)
(3)
(4)
21) A disc of radius R is charged on its surface with surface charged density σ = σ0r3. Here σ0 is a
constant and r is distance from its centre. Total charge on the disc is :-
(1)
(2) 2πσ0R
5
(3)
(4)
22) Three positive charges of equal value q are placed at vertices of an equilateral triangle. The
resulting lines of force should be sketched as in :-
(1)
(2)
(3)
(4)
0
23) The electric field in a region is given by where E = 2 × 103 NC–1. Find the flux
2
due to this field through a rectangular surface of area 0.2 m parallel to the Y–Z plane.
(1) 24 Nm2/C
(2) 120 Nm2/C
(3) 480 Nm2/C
(4) 240 Nm2/C
24) Five point charges, each of value +q, are placed on five vertices of a regular hexagon of side L.
The magnitude of the force on a point charge of value –q coulomb placed at the center of the
hexagon is
(1)
(2)
(3)
(4)
25) The electric flux through a spherical Gaussian surface is zero. If E be the electric field intensity
at any point on the surface and q be the net charge enclosed, then
26) A disk of radius having a uniformly distributed charge 6 C is placed in the X-Y plane with its
centre at (–a/2, 0, 0). A rod of length a carrying a uniformly distributed charge 8 C is placed on the x-
(1)
(2)
(3)
(4)
27) Consider three neutral balls A, B, C. If N1 electrons are transferred from A to B then N2 electrons
from B to C and finaly N3 electrons from C to A. If N1, N2, N3 are positive integers with N1 > N2 > N3
then sign of final charges of A, B, C in sequence is :-
(1) +, –, +
(2) +, –, –
(3) –, +, –
(4) +, +, –
28) Two identical charged spheres of material density , suspended from the same point by
inextensible strings of equal length make an angle between the strings. When suspended in a
liquid of density and the angle remains the same. The dielectric constant K of the liquid is
(1)
(2)
(3)
(4)
29) What is electric field at distance away from centre of charged ring (Q, R) :-
(1)
(2)
(3)
(4)
30) Two point charges placed at a certain distance r in a medium of dielectric constant k, exert a
force F on each other. Then the distance r' at which these charges will exert the same force in air is
given by :-
(1) r
(2) r/k
(3)
(4)
31)
In the given diagrams the direction of electric field at point O is given in list-II (O is circumcenter of
the given regular polygon). Charge Q is positive. Match the direction of electric field for the given
arrangement:-
List-I List-II
(P) (1)
(Q) (2)
(R) (3)
(S) (4)
Code :-
P Q R S
(1) 2 1 4 3
(2) 3 1 2 4
(3) 3 2 1 4
(4) 1 4 3 2
(1) 1
(2) 2
(3) 3
(4) 4
32) Two semicircular rings lying in same plane, of uniform linear charge density λ have radius r and
2r. They are joined using two straight uniformly charged wires of linear charge density λ and length
r as shown in figure. The magnitude of electric field at common centre of semi circular rings is-
(1)
(2)
(3)
(4)
33) When a point charge is placed at h (h < r) height above the centre, the flux passed through
curved surface of hemisphere is ϕ. If same point charge is placed below the plane surface at same
distance h from the centre, then what will be flux passed through the curved surface :-
(1) ϕ
(2)
(3)
(4)
34) A hollow non conducting sphere is filled by positive charge whose volume charge density is ρ =
. Where ρ0 is constant and r distance from centre of sphere. Find charge contained in sphere :-
(1) 8πρ0 (b – a )
2 2
(2) 4πρ0 (b – a )
2 2
(3) 2πρ0(b – a )
2 2
(4) 2πρ0b
2
35) A square is kept in X-Y palne. Its coordinate at vertices are (0, 0) (0, a), (a, 0), (a, a). If a point
charge q is kept at position (a, a, a) then flux from the square will be -
(1)
(2)
(3)
(4)
36) Two small conducting spheres of equal radius have charges +10μC and –20μC respectively &
when placed at a distance R from each other experience force . If they are brought in contact and
separated to the same distance, they experience force . The ratio of | | to | | is :-
(1) 1 : 8
(2) 8 : 1
(3) 1 : 2
(4) 2 : 1
37) If a glass rod is rubbed with silk it acquires a positive charge because :-
39) If q1 + q2 = 8q then which of the following force between q1 and q2 is not possible :-
(1)
(2)
(3)
(4)
40) Two point charges q1 = 2µC and q2 = 1µC are placed at distances b = 1 cm and a = 2 cm from
the origin of the y and x axes as shown in figure. The electric field vector at point P(a, b) will
subtend an angle θ with the x–axis given by :-
(1) tan θ = 1
(2) tan θ = 2
(3) tan θ = 3
(4) tan θ = 4
41) A point charge q is situated at a distance d from one end of a thin non - conducting rod of length
L having a charge Q(uniformly distributed along its length) as shown in fig.Then the magnitude of
(1)
(2)
(3)
(4)
0
(2) [M L–3 T2 A3]
(3) [M–1 L–3 T3 A]
(4) [M–1 L–3 TA2]
43) A point charge q and mass m is in equilibrium due to the electric field produced by a
uniformely charged Ring of radius R and charge Q as shown. Identify the type of Equilibrium if
44) An electric field line emerges from a positive charge + q1 at an angle α and will enter to the
(1)
(2)
(3)
(4)
45) Linear charge density of a half ring varies with θ as . then find the total charge of
ring
(1)
(2) zero
(3)
(4)
CHEMISTRY
1) Van't Hoff factor of Na2SO4 in its aqueous solution will be (Na2SO4 is 80% ionised in the solution)
(1) 1.6
(2) 2.6
(3) 3.6
(4) 4.6
2) Moles of K2SO4 to be dissolved in 12 mol water to lower its vapour pressure by 10 mmHg at a
temperature at which vapour pressure of pure water is 50 mm Hg is :-
(1) 3 mol
(2) 2 mol
(3) 1 mol
(4) 0.5 mol
3) What is the normal boiling point of the solution represented by the phase diagram
(1) A
(2) B
(3) C
(4) D
4) What is molecular weight of a substance whose 7.0% by mass solution in water freezes at –0.93°C.
Kf for water is 1.86 K kg mol–1 :
(1) 10
(2) 4
(3) 5
(4) 0.25
7) If observed molar mass of acetic acid is more than calculated molar mass then :-
(1) i = 2
(2) i = 1
(3) i > 2
(4) i < 1
8) Which one of the following pairs of solution can we expect to be isotonic at the same
temperature?
(1) 1.01
(2) 10
(3) 10.1
(4) 100
(1) 4 atm
(2) 3.4 atm
(3) 5.078 atm
(4) 2.45 atm
11) Which of the following solution will have the minimum freezing point :-
13) Aqueous solution of 0.004 M Na2SO4 and 0.01M glucose solution are isotonic. The degree of
dissociation of Na2SO4 is :-
(1) 25%
(2) 60%
(3) 75%
(4) 85%
15) Calculate mole fractions of urea and water if 2.0 gm of urea is dissolved in 31.4 gm of aqueous
solution.
16)
17) The degree of dissociation of an electrolyte is α and its van't Hoff factor is i. The number of ions
obtained by complete dissociation of 1 molecule of the electrolyte is :-
(1)
(2) i – α – 1
(3)
(4)
18) Consider a binary mixture of volatile liquids. If at XA = 0.4 the vapour pressure of solution is 580
torr then the mixture could be (pA° = 300 torr, pB° = 800 torr) :-
(1) CHCl3–CH3COCH3
(2) C6H5Cl–C6H5Br
(3) C2H5OH–H2O
(4) nC6H14 – n C7H16
19) Henry's law constants for gases are given below at 293 K. Which one is more soluble in water at
that temp. and same pressure:-
20) 1 mol each of the following solutes are taken in 5 moles water –
(A) NaCl (B) K2SO4
(C) Na3PO4 (D) Glucose
Assuming 100% ionisation of the electrolyte relative decrease in vapour pressure will be in order :–
21) Which of the following will have the highest freezing point at one atmosphere ?
22) The vapour pressure of a solution is 3.7 atm. This solutions has been separated from the solvent
by semipermeable membrane. If 4.0 atmosphere external pressure is applied over the solution then:
(1) 0.17m
(2) 0.7m
(3) 1m
(4) 0.34
25) The substance A when dissolved in solvent B shows the molecular mass corresponding to A4. The
van't hoff factor will be
(1) 1
(2) 2
(3) 2.5
(4)
26) The lowering of vapour pressure due to a solute in 1 m aqueous solution at 100°C is :-
29)
The molarity of SO42- ion in an aqueous solution that contain 34.2 ppm of Al2(SO4)3.
30) According to Henry’s law, the solubility of a gas in a given volume of liquid increases with
increase in:
(1) Temperature
(2) Pressure
(3) Both (1) and (2)
(4) Can not predict
31) Which of the following solutions (each 1 molal) will have the maximum freezing point (assuming
equal ionisation in each case) :-
(1) [Fe(H2O)6]Cl3
(2) [Fe(H2O)5Cl]Cl2.H2O
(3) [Fe(H2O)4Cl2]Cl2.H2O
(4) [Fe(H2O)3Cl3].3H2O
32) The Van't Hoff factor for 0.1 M Ba(NO3)2 Solution is 2.74. The degree of dissociation is :-
(1) 91.3%
(2) 87%
(3) 100%
(4) 74%
33) The mass of solute ‘A’(mol mass=75gm mol–1) that should be added to 180 gm of pure water in
order to lower its vapour pressure to 4/5th of its original value :-
(1) 187.5 gm
(2) 90 gm
(3) 150 gm
(4) 75 gm
34) The relationship between osmotic pressure at 273 K when 10g glucose (P1) 10g urea (P2) and 10g
sucrose (P3) are dissolved in 250 ml of water is:-
35)
36) The molarity of a 24.5% solution (by weight) of sulphuric acid (Density = 2 gm cm–3) is :-
(1) 5
(2) 10
(3) 20
(4) 0.5
37) An azeotropic mixture of two liquids boil at a lower temperature than boiling point either of
them when :-
(1) It is saturated
(2) It does not deviate from Raoult's law
(3) It show negative deviation from Raoult's law
(4) It show positive deviation from Raoult's law
38) X3Y2 (i = 5) when reacted with A2B3 (i = 5) in aqueous solution gives brown colour. These are
separated by a semipermeable membrane. Due to osmosis there is :-
39) Van't Hoff factors of aqueous solutions of X,Y,Z are 1.8, 0.8 and 2.5. Hence, their correct order is
(assume equal concentrations in all three cases ):-
(1) 50
(2) 25
(3) 37.5
(4) 53.5
42) 12.5g of H2SO4 is present in 87.5 g of water. What is the % w/w of H2SO4 ?
(1) 25%
(2) 50%
(3) 75%
(4) 12.5%
43) Which salt may show the same value of Vant Hoff factor (i) as that of K4[Fe(CN)6] in very dilute
solution state :-
(1) Al2(SO4)3
(2) NaCl
(3) Al(NO3)3
(4) Na2SO4
44) On mixing 30 mL CCl4 and 10 mL C6H6, the total volume of the solution will be :-
(1) > 40 mL
(2) < 40 mL
(3) = 40 mL
(4) Can't be predicted
45) The Cl– concentration in solution which is obtained by mixing one mole each of BaCl2, NaCl and
HCl in 500 ml water is :-
(1) 8 M
(2) 6 M
(3) 4 M
(4) 2 M
BIOLOGY
(1) It has more cytoplasm and more DNA than an uncleaved zygote
(2) It has almost equal quantity of cytoplasm as an uncleaved zygote but much more DNA
(3) It has far less cytoplasm as well as less DNA than in an uncleaved zygote
(4) It has more or less equal quantity of cytoplasm and DNA as in uncleaved zygote
3) Select the correct option describing gonadotropin activity in a normal pregnant female :-
(1) the sperms are transported into vagina just after the release of primary oocyte fallopian tube
(2) the ovum and sperms are transported simultaneously to ampulla of the fallopian tube
the ovum and sperms are transported simultaneously to ampullary - isthmic junction of the
(3)
cervix
(4) the sperms are transported into cervix within 48 hrs of release of ovum in uterus
6) Match Column-I with Column-II and select the correct option using the codes given below :-
Column I Column II
b Antrum ii Sperm
Female external
c cleavage iii
genitalia
(1) iii i iv ii
(2) i iv iii ii
(3) iii iv ii i
(4) iii iv i ii
(1) 1
(2) 2
(3) 3
(4) 4
8) No new follicles develop in the luteal phase of the menstrual cycle because
Column-I Column-II
Bulbo-urethral
(c) (iii) Layer of the ovum
glands
Lubrication of
(d) Leydig cells (iv)
the Penis
13) Which of the following statements are correct regarding female reproductive cycle ?
A. In primate female mammals cyclical changes during reproduction is called menstrual cycle.
B. First menstrual cycle begins at puberty and is called menopause.
C. Lack of menstruation may be indicative of pregnancy.
D. Cyclic menstruation extends between menarche and menopause.
Choose the most appropriate answer from the options given below :
15) Ovulation is :-
16) When do both LH & FSH attain a peak level in a menstrual cycle ?
17) The correct chronological order of the following events during embryonic development is :
(1) FSH
(2) Androgen
(3) Progesterone
(4) oxytocin
20) The principal hormone responsible for contraction in uterus and expulsion of baby is:
(1) Progesterone
(2) Prolactin
(3) Oxytocin
(4) hCG
21) Insemination is the process by which
23)
(1) Oviduct
(2) Labia majora
(3) Labia minora
(4) Mons pubis
(1) FSH
(2) Thymus hormones
(3) Cortisol
(4) Oxytocin
Structure Function
(1) 1
(2) 2
(3) 3
(4) 4
28) Which one of the following statements is incorrect about menstrual cycle ?
(1) 46
(2) 23 + 23
(3) 45
(4) 23
30) Spot the odd one out from the following structure with reference to the male reproductive
system.
32) Choose the correct option for the components of various parts of sperms
(1) Head: Golgi bodies, nucleus and centrioles without plasma membrane
(2) Neck: Golgi bodies and centrioles covered with plasma membrane
(3) Middle piece: Mitochondria and Axial filament
(4) Tail: Mitochondria and flagellum covered with plasma membrane
(1) Estrogen
(2) Progesterone
(3) hCG
(4) LH
Vasa efferentia leaves testis and opens into vas deferens located on anterior surface of each
(1)
testis
(2) In males glans penis has urethral meatus.
(3) Male accessory gland helps in reproduction
(4) Both haploid and diploid cells are present in seminiferous tubule.
38)
See the diagram carefully and find out correct option:
(1) 1
(2) 2
(3) 3
(4) 4
39) Which hormone maintains the pregnancy and makes the wall of uterus adhesive for implantation
?
(1) FSH
(2) LH
(3) Estrogen
(4) Progesterone
40) Which is the correct option regarding size of blastomeres during clevage ?
(1) Increasing
(2) Decreasing
(3) Remain constant
(4) Some times increase & some time decrease
41) Which of the following is incorrect for vas deferens ?
42) The figure below shows development of follicles (A, B, C, D). Select the option giving correct
(1) Puberty
(2) Embryo stage
(3) After birth
(4) Life time
44) How many of the following structures are found in abdomen of adult male.
Vasa–efferentia, Rete testis, Epididymis, Prostate, Seminal vesicle, Ampulla of vas deferens.
(1) One
(2) Two
(3) Three
(4) Four
45) Corona radiata & zona pellucida are coverings of secondary oocytes :
(1) Corona radiata is primary & zona pellucida is secondary egg membrane
(2) Corona radiata is secondary & zona pellucida is primary egg membrane
(3) Both are primary egg membrane
(4) Both are secondary egg membrane
46) Which is not correct about secondary sexual characters of female ?
(1) One
(2) Two
(3) Three
(4) Four
(1) 40 – 50 eggs
(2) 250 – 300 eggs
(3) 400 – 500 eggs
(4) 750 – 850 eggs
Column I Column II
I Acrosome A erectile tissue
II Endometrium B Uterus
III Polar body C Oogenesis
IV Clitoris D Spermatozoan
(1) I – B, II – A, III – D, IV – C
(2) I – D, II – B, III – C, IV – A
(3) I – D, II – C, III – B, IV – A
(4) I – D, II – C, III – A, IV – B
50) The opening of the vagina is often covered partially by a membrane called as:
(1) Hymen
(2) Clitoris
(3) Foreskin
(4) Mons pubis
52) Fill in the blanks in the following statements The human male ejaculates about ........ million
sperms during a coitus of which, for normal fertility, at least ........... percent sperms must have
normal shape and size and at least ........ percent of them must show vigorous motility.
53) Which of the following entry induce the completion of the meiotic division of the secondary
oocyte
(1) Sperm
(2) Progesterone
(3) Estrogen
(4) Oxytocin
(1) At ovulation
(2) During fertilization
(3) Menopause
(4) Tertiary follicle
(1) Polylecithal
(2) Mesolecithal
(3) Alecithal
(4) Centrolecithal
56) At puberty only ........... primary follicles are left in each ovary
(1) 6000-8000
(2) 8000-10000
(3) 60000-80000
(4) 400-500
(1) ligase
(2) estrogenase
(3) androgenase
(4) hyaluronidase
(1) Urethra
(2) Cervix
(3) Clitoris
(4) Vulva
60) Mature Graafian follicle is generally present in the ovary of a healthy human female around the :
61) Read the enclosed Diagram and answer the question. Which of
the following constitute minimum volume Secretion of the seminal plasma.
(1) e
(2) f
(3) i
(4) d
62)
(1) Oogonia
(2) Primary oocyte
(3) Secondary oocyte
(4) Atretic follicle
63) In a normal menstrual cycle of 28 days, the progesterone surge is likely to be observed at:
(1) Menses
(2) Follicular phase
(3) Luteal phase
(4) Ovulation
65)
66) Morula is :-
68)
After ovulation, in humans the secondary oocyte is released in
69) Which hormone helps in the movement of sperm from uterus to fallopian tube ?
(1) Prostaglandin
(2) Oestrogen
(3) Progesterone and oestrogen
(4) Cortisol and oestrogen
70) The middle piece of sperm possesses many mitochondria which produces energy for movement
of tail. This layer of mitochondria is known as:
(1) Acrosome
(2) Zona pellucida
(3) Manchette
(4) Nebenkern sheath
71) If mammalian ovum fails to get fertilized, which one of the following is unlikely in luteal phase ?
(1) Part-A
(2) Part-B
(3) Part-C
(4) Part-D
75) It is a diagrammatic presentation of ovum which is surrounded by few sperm. Choose the correct
(1) Progesterone
(2) Inhibin
(3) hCG
(4) Estrogen
77)
Find correct option related with above figure :
79) The Anterior portion of sperm is covered by ............ like structure called ............ .
80) Which of the following hormones released from the pituitary is actually synthesized in the
hypothalamus ?
81) The acrosome is filled with enzymes that help in fertilisation of the ovum. These enzymes are-
82) Semen profile of four men are studied. Which of the following man will have a maximum capacity
of fertility ?
83) How many primary spermatocytes and primary oocytes are required to form 100 zygotes ?
(1) Birth
(2) Puberty
(3) Fertilization
(4) Uterine implantation
85) The spermatid are transformed into spermatozoa by the some factors of.
88) After ovulation the remaining parts of graafian follicle transform as the
89) The glandular tissue of each breast is divided into .......... A.......... mammary lobes containing
clusters of cells called .......... B ............ Identify A & B
(1) Both (A) and (R) are correct and (R) is the correct explanation of (A)
(2) Both (A) and (R) are correct but (R) is not the correct explanation of (A)
(3) (A) is true but (R) is false
(4) (A) is false but (R) is true
ANSWER KEYS
PHYSICS
Q. 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
A. 3 1 4 2 4 2 3 1 2 2 2 2 3 1 1 1 1 2 2 3
Q. 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40
A. 1 1 4 4 2 1 2 1 3 4 2 4 2 3 2 2 4 4 3 2
Q. 41 42 43 44 45
A. 4 1 2 3 2
CHEMISTRY
Q. 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65
A. 2 3 4 2 4 2 4 4 4 3 4 4 3 1 1 3 1 1 1 3
Q. 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85
A. 2 2 3 4 4 1 2 3 1 2 4 2 1 3 3 1 4 4 2 1
Q. 86 87 88 89 90
A. 1 4 1 1 1
BIOLOGY
Q. 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110
A. 2 4 3 3 2 4 1 4 1 4 4 4 3 2 1 2 3 1 2 3
Q. 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130
A. 1 3 4 4 1 2 3 4 4 4 3 3 1 3 1 4 1 3 4 2
Q. 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150
A. 4 4 1 3 2 3 3 3 2 1 3 3 1 4 3 3 3 4 2 2
Q. 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170
A. 3 3 3 1 4 2 4 1 1 4 4 3 2 4 1 3 1 4 2 2
Q. 171 172 173 174 175 176 177 178 179 180
A. 3 3 1 3 4 1 2 2 4 3
SOLUTIONS
PHYSICS
Formula : q = ne
n → no. of electron
q → total charge
So , n = = 5 × 1014
Final Answer : (3) 5 × 1014
2)
For q0 to be in equilibrium
72a – 4r = 5r
8a = r
x = 10a
3)
as α < β
m 1 > m2
4)
5)
The component of forces will be in -y direction only So, answer is (4).
6)
7)
8)
9)
Concept:
Coulomb's law
progression.
Formula:
The force F due to a charge at position x = 2n is calculated using Coulomb's law:
Fn =
F=
Sum of ∝ G.P. =
Calculation:
13)
so,
15)
Radius of circular sheet present inside spherical surface
So,
By Gauss law
Concept Based:
Use integration to calculate the net electric field at the center due to small charge elements on
the arc. Symmetry causes vertical components to cancel, leaving only horizontal contribution.
Formula Used:
dq = λadθ
Total Ex =
Calculation:
17) This is basically a problem of finding the electric field due to three dipoles. The dipole
moment of each dipole is,
p = Q (2a) Electric field due to each dipole will be,
=2×
Concept:
Electric field due to point charges and variation of field strength with distance.
Formulas Used :
Visual Aid:
Solution:
A decrease in the electric field as you move away from the charge.
At the origin field intensity will be minimum.
19) =0
⇒ Q2 = –8 Q1
=
21)
22)
Option - (1)
Cal:- electric field does not make close toop so option (2), (3), (4) are incorrect electric filed
start from positive charge and ends at infinites so option (1) in correct
Level - Easy
23)
Flux
25) The flux due to a dipole inside the closed surface is zero but field at surface is not zero.
26)
charge enclosed by cubical surface is
27)
Because, N1 > N2 > N3
Hence, for A → Deficiency of e = (N1–N3) → (+ve) charge
B → Excess of e = (N1–N2) → (–ve charge)
C → Excess of e = (N2–N3) → (–ve charge)
A. In the liquid: The electrostatic force is reduced by the factor of K (the dielectric constant of
the liquid), so:
where σ is the density of the liquid, V is the volume of the sphere, and g is the acceleration due to
gravity.
4. Calculation (In Brief):
A. For the case in air, the forces acting on the spheres result in the following equilibrium:
A. For the case in the liquid: the equilibrium condition is modified by the buoyant force:
A. Equating the two expressions for (since 0 remains the same) leads to:
5. Answer:
Option 1: .
29)
30) 1. Explanation:
Two point charges in a medium with dielectric constant k exert a force F. We are asked to find
the distance r' at which the charges will exert the same force in air.
2. Concept:
The force between two point charges in a medium is given by Coulomb's law modified by the
dielectric constant k:
Thus:
r'2 = k.r2 ⇒
4. Calculation:
Given that the force is the same, we find that:
Answer: 4)
31) Apply superposition of electric field using the fact that electric field is radially outwards.
Final Answer
33)
In case - 1 - ϕ = ϕentre
In case - 2-ϕ1 = ϕout
= –ϕ
34)
For intermediate shell
dQ =ρdV = (4ρr2)dr
35)
ϕ= =
36)
40) E ∝
tanθ =
41)
CHEMISTRY
Nw = 150.5 g mol–1
2. Given:
All solutions are 1 molal in water:
1. Glucose (non-electrolyte)
2. Sucrose (non-electrolyte)
3. NaCl (dissociates into 2 ions: Na+, Cl– → i = 2 )
4. CaCl₂ (dissociates into 3 ions: C a2+ , 2Cl– → i = 3)
3. Concept:
Freezing point depression formula:
ΔTf = i . Kf . m
Same Kf and m for all, so the one with highest i will have the maximum ΔTf → hence lowest
freezing point.
4. Calculation:
Van't Hoff factors (i):
• Glucose: i = 1
• Sucrose: i = 1
• NaCl: i = 2
• CaCl₂: i = 3
So, CaCl2 causes the most freezing point depression.
5. Final Answer: 1 molal CaCl₂ in water (Option 4)
62) i = 1 + (n – 1) α so n =
75) Acc. to Henry's law on increasing pressure solubility of gas in liquid increases.
77)
80) π = CRT
89) CCl4 and C6H6 form solution which slow +ve deviation.
BIOLOGY
149)
173)
Here's how to calculate the number of primary spermatocytes and primary oocytes
needed to form 100 zygotes:
2. Calculation